Drag the tiles to the correct boxes to compete the pairs. identify the types of chemical reactions occurring in the chemical equations. respiration photosynthesis combustion reaction of fossil fuels methane oxygen → water carbon dioxide heat arrowright glucose oxygen → carbon dioxide water energy arrowright water carbon dioxide sunlight → oxygen glucose arrowright

Answer:

765.0 grams CuS

Explanation:

The limiting reagent is the reactant which completely reacts before the other reactant(s) is used up. When 9.0 moles Na₂S and 8.0 moles CuSO₄ react, it appears that CuSO₄ is the limiting reagent. You can tell because it results in the production of less product.

You can determine the mass of CuS by multiplying the moles by the molar mass. It is important to arrange the ratio in a way that allows for the cancellation of units.

Molar Mass (CuS): 95.62 g/mol

8.0 moles CuS               95.62 g
-------------------------  x  -----------------------  =  765.0 grams CuS
                                         1 mole

The hydrolysis of esters in base is called saponification .

So, option C is correct one.

The saponification is the process that involves conversion of fats , oils , lipids into soap and water in the presence of alkaline medium. Saponification is the process of making soap.

During the saponification process, the mixture has an acidity, which tells that it's not safe for usage. After the saponification process is complete, the pH should be a base.The process of formation of carboxylic salt and water by hydrolysis of ester in base is called saponification.

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option (A) Adding heat to the product mixture is the right answer.

As the reactant side has more moles than the product side, the equilibrium of the reaction shifts to the left to decrease pressure by increasing volume.

If the temperature drops, equilibrium also moves to the left.

Given equation is co+ 3h2 ⇌ ch4+ h2o

When heat is added to the product mixture in this situation, equilibrium moves to the left.

A condition where opposing forces or actions are in balance is known as equilibrium.

Equilibrium is of two types:

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Answer:

19 hydrogen bonds

Explanation:

Between every thymine and adenine, there are 2 hydrogen bonds.

Between every guanine and cytosine, there are 3 hydrogen bonds.

Since there are 2 total thymines and adenines, they contribute 4 hydrogen bonds overall.

-----> 2 H bonds x 2 nucleotides = 4 H bonds

Since there are 5 total cytosines and guanines, they contribute 15 hydrogen bonds overall.

-----> 3 H bonds x 5 nucleotides = 15 H bonds

Therefore, there are 19 hydrogen bonds between the complementary strands.

The molecular formula of the given compound is [tex]$\mathrm{H}_{2} \mathrm{CO}_{3}$[/tex] also known as  Carbonic acid.

The simplest whole-number ratio of the various atoms in a compound is represented by an empirical formula.

The precise number of various atom types present in a compound's molecule is indicated by the molecular formula.

Given that,

H = 3.3%

C = 19.3%

O = 77.4%

No. of moles of H = 3.3/1

No. of moles of H = 3.3

No. of moles of C = 19.3 / 12

No. of moles of C = 1.60

No. of moles of O = 77.4/16

No. of moles of O = 4.83

Therefore, the ratio of the atoms of C, H and O = 3.3 : 1.60 : 4.83

Divide by smallest value which you get =3.3 / 1.60 : 1.60 / 1.60 : 4.83 / 1.60

The ratio of the atoms of C, H and O = 2 : 1 : 3

So, the empirical formula is [tex]$\mathrm{H}_{2} \mathrm{CO}_{2}$[/tex]

Let the molecular formula is [tex]$\left(\mathrm{H}_{2} \mathrm{CO}_{3}\right) \mathrm{n}$[/tex]

Then, molar mass [tex]$=(2 \times 1+1 \times 12+3 \times 16) n\\[/tex]

Molar mass = 62n

As the question, 62 n = 60

n = 0.96 or n = 1 (rounded off to nearest ones)

So, the molecular formula is [tex]$\left(\mathrm{H}_{2} \mathrm{CO}_{3}\right) 1=\mathrm{H}_{2} \mathrm{CO}_{3}$[/tex] i.e., the compound is Carbonic acid.

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mass of Liquid 1 + mass of solid = mass of Liquid 2 + mass of gas mass of Liquid

The law of conservation of mass or principle of mass conservation states that for any system closed to all transfers of matter and energy, the mass of the system must remain constant over time, as system's mass cannot change, so quantity cannot be added nor removed. Hence, the quantity of mass is conserved over time.

According to the rule of conservation of mass, mass is neither generated nor destroyed during a chemical process. For instance, when coal is burned, the carbon atom in it transforms into carbon dioxide. The carbon atom transforms from a solid to a gas, yet its mass remains constant.

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If 20. 3 grams of an aqueous solution of iron(ii) chloride contains 2. 71 grams of iron(ii) chloride, then percentage by mass of  iron(ii) chloride in the solution is 13.34%

Calculation,

Given:

mass of an aqueous solution of iron(ii) chloride = 20. 3 grams

mass of iron(ii) chloride = 2. 71 grams

The percentage by Mass is equal to percentage of mass of solute present in total mass of solution. It is also known as Mass percentage.

percentage by Mass = 100× 2. 71 grams/20. 3 grams = 13.34%

Hence, the percentage by mass of  iron(ii) chloride in the solution is 13.34% .

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body structure: the shape of specific organs/attributes of an organism. This includes cells, tissues, organs, and systems.

function: the action or purpose an organ or attribute has.

Body structure

Function

What is a body structure of the Spiny Katydid?

Spines on the body

What is the function of this structure?

The spines on the Spiny Katydid's body prevent predators from having an easy time eating them

Further Notes:

Without the spines on their body, Spiny katydids would be more vulnerable to being eaten. The spines help them survive

What is a body structure of the Longhorn Cowfish?

puckered mouth

What is the function of this structure?

The puckered mouth allows the Longhorn Cowfish to blow jets of water.

Further Notes:

The jets of water the Longhorn Cowfish blows move the sand, exposing the organisms it eats. Without the puckered mouth, the Longhorn Cowfish would have difficulty finding food.

What is the body structure of the Tarsier?

Huge eyes

What is the function of this structure?

The Tarsier's huge eyes allow it to see well.

Further Notes:

It's excellent vision helps it see and hunt for prey

body structure

function

Catalysis is the process of boosting the pace of a chemical reaction by using a catalyst. Catalysts are not consumed in the reaction and so survive it.

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pH of the solution after 24. 00 ml of the hcl has been added is 12.87

millimoles NaOH = mL x M = 24.00 mL x 0.25 M = 6.00

millimoles HCl = 24.00 mL x 0.10 M = 2.40

total volume = 48.00 mL

.................................NaOH + HCl ==>NaCl + H2O

initial.........................6.00.........0............0.........0

added.....................................2.40............................

change.................... -2.40......-2.40.........+2.40.... +2.40

equilibrium.................3.60.........0..............2.40.......2.40

The NaCl contributes nothing to the pH of the final solution. The pH is determined by the excess of NaOH present. (NaOH) = millimoles/mL = 3.60/48.00 = 0.075 M = (OH^-)

pOH = -log (OH^-). Then

pOH = -log (0.075)

pOH =1.1249

As we know,

pH + pOH = pKw = 14.00

pH=14-pOH

pH=14-1.1249

pH=12.87

pH is a logarithmic measure of an aqueous solution's hydrogen ion concentration. pH = -log[H+], where log is the base 10 logarithm and [H+] is the concentration of hydrogen ions in moles per liter.

The pH of an aqueous solution describes how acidic or basic it is, with a pH less than 7 being acidic and a pH greater than 7 being basic. A pH of 7 is regarded as neutral (e.g., pure water). pH values typically range from 0 to 14, though very strong acids may have a negative pH and very strong bases may have a pH greater than 14.

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During transpeptidation, nucleophilic attack occurs between the α-amine group in the A site and the esterified carbon in the P site

A chemical process in which an amino acid residue or peptide residue is transferred from one amino compound to another. This process occurs when a protease reversibly converts one peptide to another.

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There are some types of properties about the substance that you tested did you use to determine whether you thought it was an acid or base. Some are given below.

Substances that are used to determine whether a particular substance is an acid or  base are called indicator. The indicator is a dye that is weak an organic acid or base that changes color when it is added to an acid and base.

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4.8 × 10^9 M  is the concentration of n2 gas at equilibrium when the concentration of no2 is twice the concentration of o2 gas.

In some gas-producing fields, such as those in the US Midwest, North Sea, Eastern Europe, and South East Asia, nitrogen (N2) may naturally present in significant concentrations. Around 15% of the world's non-associated gas deposits have nitrogen content levels that are too high to be considered pipeline-quality gas (usually 3–4 mol%). Because it is an inert gas, nitrogen cannot support burning. Consequently, unstable combustion could result from burning a gas that contains too much nitrogen. The recovery of NGL content will be lowered when high nitrogen gas is treated in a gas plant because nitrogen acts as stripping gas. The compression technology and size of the transmission pipeline will rise with increased nitrogen concentration. High nitrogen levels are undesirable in an LNG plant because they lower the LNG temperature, which increases the energy required to liquefy natural gas and also increases the amount of boil-off gas from the LNG storage tanks.

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Molecules having all atoms lying in the same plane is c) HCN

HCN is a molecule in which all the atoms in the same plane i.e. it is a Planar molecule.

A Planar molecule is the one in which atoms are arranged in same plane i.e. atoms arrange themselves to exist in a two dimensional plane around the central atom.

The presence of double bond or triple bond in a molecule allows the molecule to get arranged in a plane.

The presence of triple bond in HCN allows it to be arranged in a plane.

HCN to be specific is a Linear molecule in which the angle between H and CN is 180.

The bond between C and N atom is a triple bond containing two pie bonds and one sigma bond.

Hence c) HCN is a planar molecule.

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Root mean square speed is the estimation of the effect of temperature and weight on kinetic energy. The root means square speed for a mixture of helium and methane is 2. Thus, option d is correct.

Root mean square speed is the estimation of the square root of the mean value of the squared speeds of the individual gas particles in the mixture.

As it is known that,

Root mean square speed = √{3RT/M}

Where T is constant temperature and R is gas constant. The molecular mass of helium gas is 4 g/mol and of methane is 16 g/mol.

Vrms = √{3RT/M}

For helium, Vrms = √{3RT/4}

And, for methane = Vrms = √{3RT/16}

So, (Vrms,helium) / (Vrms,methane) = 4 / 2 = 2

Therefore, option d. 2 is the root-mean-square speed for the mixture.

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Your question is incomplete, but most probably your full question was, Helium and methane gases are mixed together in a container. what is the ratio of their root-mean-square speeds, i. e. (Vrms, helium) / (Vrms, methane)?

The pH= 7.57 ,  pOH = 6.86, and  [OH-] = 1.58 x 10⁻⁴ M M of the given solution.

pH is a scale that measures the acidity and basicity of a solution. Its ranges from 1 to 14. Seven is neutral.

The H given is 7. 2 × 10⁻⁸ m

Calculating the pOH

[H⁺] = 10^(-7.20)

[H⁺] = 6.31 x 10⁻⁹ M

pOH = 14 - 7.2

pOH = 6.8

Calculating the [oh−]

[OH⁻] = 1 x 10⁻¹⁴ / 6.31 x 10⁻⁹

[OH⁻] = 1.58 x 10⁻⁴ M

Calculating the pH

pH = 14 - 6.43

pH = 7.57

Thus, the pH= 7.57 , pOH = 6.86, and  [OH-] = 1.58 x 10⁻⁴ M.

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The molar solubility of the substance is  1.2 × [tex]10^{-10}[/tex]  M if a substance x has a solubility of 2. 4 × [tex]10^{-5}[/tex]  mg/l, and a molar mass of 188 g/mol.

Calculation ,

The number of moles dissolve in one liter of solution is called molar solubility.

Given Solubility = 2.4 × [tex]10^{-5}[/tex] mg/L

Solubility = 2.4 × [tex]10^{-5}[/tex]  × [tex]10^{-3}[/tex]   g/L = 2.4 × [tex]10^{-8}[/tex]   g/L

Molar mass = 188 g/mol

Molar Solubility = 2.4 × [tex]10^{-8}[/tex]   g/L / 188 g/mol = 0.012 × [tex]10^{-8}[/tex]   mol/L

Molar Solubility = 1.2 × [tex]10^{-10}[/tex]  M

Therefore ,  the molar solubility of the substance is 1.2 × [tex]10^{-10}[/tex]  M

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Cis-platin is a chemotherapy agent used to treat and kill cancerous cells in patients. One mole of cis-platin has a mass of 300.06 grams/mol. Thus, option B is correct.

A chemotherapy agent is an alkylating agent that is used to treat cancer and is given to reduce the infection or to relieve the symptoms. Cis-platin (Pt(NH₃)₂Cl₂) is one of the chemotherapy agents that treat lung, ovarian, and neck cancer, etc.

The mass of one mole of Cis-platin is calculated as,

Moles = mass ÷ molar mass

Where,

Moles = 1 mole

The molar mass of (Pt(NH₃)₂Cl₂) is calculated as,

195.06 g/mole + 2(17g/mole) + (35.5)2 = 300.06 grams

Substituting values to calculate mass:

Mass = Molar mass × moles

= 300. 06  × 1

= 300.06 grams/mol

Therefore, option B. 300.06 gm/mol is the mass of Cis-platin.

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Your question is incomplete, but most probably your full question was, Cis-platin is a chlorine-containing chemotherapy agent with the formula pt(nh3)2cl2. What is the mass of one mole of cis-platin?

Answer:

decreased by a factor of 10

Explanation:

pH is defined in such a way that;

pH= −log10(H)

Where H represents the concentration of Hydronium or Hydrogen ions

Given that pH is changed from 1 to 2,

By rearranging the above formula , we get 10−pH = H

Therefore,  0.1/0.01 = 10 and 0.1 > 0.01

Hence, the concentration of hydronium ions in the solution is decreased by a factor of 10

In lewis structure of HCN, we can observe one lone pair of electron.

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Answer:

Percent Yield K₂O  =  59.2%

Explanation:

Before you can calculate the percent yield, you need to find the theoretical yield. This value is the amount of product produced using the balanced chemical equation and molar masses. However, the question does not specify which reactant is the limiting reagent. Therefore, you have to calculate the mass of the product starting from both values.

To find the theoretical yield, you need to (1) convert grams K/O₂ to moles K/O₂ (via molar masses), then (2) convert moles K/O₂ to moles K₂O (via mole-to-mole ratio from balanced equation coefficients), and then (3) convert moles K₂O to grams K₂O (via molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given values.

Molar Mass (K): 39.098 g/mol

Molar Mass (O₂): 2(15.998 g/mol)

Molar Mass (O₂): 31.996 g/mol

Molar Mass (K₂O): 2(39.098 g/mol) + 15.998 g/mol

Molar Mass (K₂O): 94.194 g/mol

The balanced equation:

4 K + O₂ -----> 2 K₂O

8.92 g K          1 mole             2 moles K₂O         94.194 g
--------------  x  -----------------  x  --------------------  x  ----------------  =  10.7 g K₂O
                       39.098 g           4 moles K             1 mole

3.28 g O₂          1 mole           2 moles K₂O         94.194 g
----------------  x  ---------------  x  ---------------------  x  --------------  =  19.3 g K₂O
                         31.996 g           1 mole O₂              1 mole

Because potassium produces the smaller amount of product, it is the limiting reagent. This means that all the potassium reactant is used up before the oxygen gas runs out. So, the theoretical yield of potassium oxide is 10.7 grams.

Now, you can use the theoretical yield and actual yield to determine the percent yield.

                                   Actual Yield
Percent Yield  =  ------------------------------  x  100%
                               Theoretical Yield

                                 6.36 g K₂O
Percent Yield  =  ------------------------  x  100%
                                 10.7 g K₂O

Percent Yield  =  59.2%

Answer:

This substance would cause cause an extensive cellular damage to Anil.

When pcl5 solidifies it forms pcl4 cations and pcl6–anions. according to valence bond theory, hybrid orbitals that  are used by phosphorus in the pcl4 cations are one orbital of s and three orbital of p as it is sp³hydridised.

Hybridization is a process or system which specifies the shape and geometry of any element or molecule with bond angles too.

The pcl4 cation is sp³ hybridized because of the phosphorus behave as a central atom here and the 4 chloride molecules are attached with the p- orbitals to the phosphorus molecule.

Therefore, pcl4 cation  is sp³ hybridized.

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A mixture of three gases containing an equal number of moles of each gas has a total pressure of 12. 0 atm then partial pressure of each gas is 4 atm .

Calculation ,

According to Dalton law the total gas of the container is equal to the sum of partial pressure of each gas .

[tex]P_{t}[/tex] = [tex]P_{1}[/tex] +[tex]P_{2}[/tex]+ [tex]P_{3}[/tex]

Partial pressure = total pressure × mole fraction

mole of each gas is equal . So, mole fraction is also equal for each gas.

Let the number of  mole = x

mole fraction = x/3x =1/3

[tex]P_{1}[/tex] = 12. 0 atm/3 = 4 atm

[tex]P_{2}[/tex] = 12. 0 atm/3 = 4 atm

[tex]P_{3}[/tex] = 12. 0 atm/3 = 4 atm

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There are 17.97 moles of calcium chloride would react with 5. 99 moles of aluminum oxide .

The balanced chemical equation between  reaction between calcium chloride and aluminum oxide is given as,

[tex]3CaCl_{2} (aq)+Al_{2} O_{3} (s)[/tex] → [tex]3CaO_{2} (s)+2Al Cl_{3} (aq)[/tex]

The molar ratio of above reaction is  3:1

It means 3 moles of calcium chloride is require to react one mole of aluminum oxide.

The number of moles of calcium chloride requires to react with  5. 99 moles of  aluminum oxide  = 3 × 5. 99 = 17.97 moles

The equation in which number of atoms of elements in reactant side is equal to the number of atoms of elements in product side is called balanced chemical equation .

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The pH of the monoprotic weak acid is 2.79.

The weak acids are the acids that do not fully dissociate into ions in the solution. Strong acids fully dissociate into ions.

The chemical reaction is HA(aq) ⇄ A⁻(aq) + H⁺(aq).

c (monoprotic acid) = 0.33 M.

Ka = 1.2·10⁻⁶

[A⁻] = [H⁺] = x

[HA] = 0.33 M - x

Ka = [A⁻]·[H⁺] / [HA]

2. 6 × 10⁻⁶ = x² / (0.33 M - x)

Solve quadratic equation: [H⁺] = 0.000524 M.

pH = -log[H⁺]

pH = -log(0.000524 M)

pH = 2.79

Thus,  the pH of the monoprotic weak acid is 2.79

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0.0102 moles Na₂CO₃ = 1.08g of Na₂CO₃ is necessary  to reach stoichiometric quantities with cacl2.

Based on the reaction

CaCl₂ + Na₂CO₃ → 2NaCl + CaCO₃

1 mole of CaCl₂ reacts per mole of Na₂CO₃

we have to calculate how many moles of CaCl2•2H2O are present in 1.50 g

1.50g * (1mol / 147.0146g) = 0.0102 moles CaCl₂.2H₂O = 0.0102moles CaCl₂

Moles Na₂CO₃:

0.0102 moles Na₂CO₃

Mass Na₂CO₃:

0.0102 moles * (105.99g / mol) = 1.08g of Na₂CO₃ are present

Therefore, we can conclude that 0.0102 moles Na₂CO₃  is necessary.to reach stoichiometric quantities with cacl2.

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Answer:

butanal

Explanation:

It's not 1-propanone because otherwise you have OH bonded to C not O and H bonded to C separately. 2-butanol means that the O and H would be bonded to a different C atom, and it's not propyl hydrogen ether because the O would be in the chain of bonded Cs.
Hope this helps :)

Answer:

Butanal

Explanation:

trust

Answer:The particles move faster, and their average kinetic energy decreases.

Explanation:

According to the given equation ,if 2Mg(s) O2(g) → 2MgO(s), δh° = –1203. 6

k j/m o l, then form g(s) (1/2)O2(g) → Mg O(s), the enthalpy change is δh = –601. 8 k j /m o l, hence the given statement is true.

An enthalpy change is roughly equivalent to the energy gained through the production of new chemical bonds in a reaction minus the energy required to break existing chemical bonds.

It describes how a system changes in terms of energy while pressure is constant.

The symbol ΔH stands for enthalpy change. At constant pressure, ΔH is equal to the sum of the system's internal energy and the pressure-volume work it performs on its surroundings.

It  is expressed in units of joules per mole.

If 2Mg(s) O2(g) → 2MgO(s), δh° = –1203. 6

k j/m o l, then form g(s) (1/2)O2(g) → Mg O(s), the enthalpy change is δh = –601. 8 k j /m o l, therefore the above given statement is true.

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