The null hypothesis and conclude that the average number of months looking for jobs after graduation is different for GMU and University of Alaska students with 95% confidence.
H0: The average number of months looking for jobs after graduation is the same for GMU and University of Alaska students. Ha: The average number of months looking for jobs after graduation is different for GMU and University of Alaska students.
alpha = 0.05
df = ngmu + nua - 2 = 198 (degrees of freedom)
t* = t(0.025, 198) = 1.972 (from t-distribution table)
SE = sqrt[(sgmu^2/ngmu) + (sua^2/nua)] = sqrt[(2.1^2/100) + (2.3^2/100)] = 0.324
tobt = (xgmu - xua) / SE = (3.6 - 2.7) / 0.324 = 2.77
Since tobt (2.77) > t* (1.972), we reject the null hypothesis and conclude that the average number of months looking for jobs after graduation is different for GMU and University of Alaska students with 95% confidence.
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2) A gho with a cost price of Nu 750 was sold for Nu 900. What was the percent markup?
The percent markup is 20%
The selling price of the Nu is 900
The cost price of the Nu is 750
The percent markup can be calculated as follows
= 900-750/750 × 100
= 150/750 × 100
= 0.2 × 100
= 20%
Hence the percent markup is 20%
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if 15 cans of food are needed for 7 adults for 2 days, the number of cans needed for 4 adults for 7 days is
More than 30 cans of food will be needed for 4 adults for 7 days. To find the number of cans needed for 4 adults for 7 days, given that 15 cans of food are needed for 7 adults for 2 days, we can follow these steps:
1. Determine the number of cans needed for 1 adult for 2 days: Divide the total number of cans (15) by the number of adults (7).
15 cans / 7 adults = 2.14 cans per adult for 2 days (approximately)
2. Determine the number of cans needed for 1 adult for 7 days: Multiply the cans needed for 1 adult for 2 days by 3.5 (since 7 days is 3.5 times longer than 2 days).
2.14 cans * 3.5 = 7.49 cans per adult for 7 days (approximately)
3. Determine the number of cans needed for 4 adults for 7 days: Multiply the cans needed for 1 adult for 7 days by the number of adults (4).
7.49 cans * 4 adults = 29.96 cans
Since you cannot have a fraction of a can, round up to the nearest whole number. Thus, you would need 30 cans of food for 4 adults for 7 days.
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2. An organization has 20 male and 18 female members. In how many ways can five male and five female members be selected to sit on the board of directors? Explain your solution (12)
To determine the number of ways to select five male and five female members for the organization's board of directors, we'll use the combination formula C(n, r) = n! / (r! * (n-r)!). So, there are 132,819,072 ways to select five male and five female members for the organization's board of directors.
For the male members, n = 20 and r = 5. So, we'll calculate C(20, 5):C(20, 5) = 20! / (5! * (20-5)!)
C(20, 5) = 20! / (5! * 15!)
C(20, 5) = 15,504
For the female members, n = 18 and r = 5. So, we'll calculate C(18, 5):C(18, 5) = 18! / (5! * (18-5)!)C(18, 5) = 18! / (5! * 13!)C(18, 5) = 8,568Now, we'll multiply the number of ways to choose male and female members to get the total number of ways to form the board of directors:Total ways = 15,504 (male) * 8,568 (female)Total ways = 132,819,072know more about combination formula here: https://brainly.com/question/28065038
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If k is a positive integer, then 20k is divisible by how many different positive integers? (1) k is prime. (2) k = 7
If k is the prime number, then the expression 20k is divisible by 2, 5, and k.
If k = 7, then the expression 20k is divisible by 2, 5, and 7.
Given that:
Expression, 20k
The factor of the expression 20k is given as,
20k = 2 x 2 x 5 x k
20k = 2² x 5 x k
If k is the prime number, then the expression 20k is divisible by 2, 5, and k.
If k = 7, then the expression 20k is divisible by 2, 5, and 7.
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On the same coordinate plane mark all points (x,y) that satisfy the rule y=-3x+2
Answer:
see attached
Step-by-step explanation:
You want a graph of the line y = -3x +2.
GraphThe infinite number of points that satisfy the equation y = -3x +2 will form a line on the coordinate plane. It will cross the y-axis at y = 2, and will have a slope (rise/run) of -3 units for each unit to the right. The attachment shows the graph.
<95141404393>
Econ112 (Stats for Econ & Bus) - Tutorial 4 Assessment To be submitted to on CANVAS, 9am Monday 25th April. Standard late penalties apply. However, any work received after the tutorial seminar starts will receive a mark of zero as solutions are discussed here. [Any technical problems hard copy submissions must be resolved via help-ticket to CSD] ALL questions are worth 1 Mark. SECTION A (C.I. & Hypothesis-Test with known 0 - see lectures week 8) [6 Marks] Question 1 The business model for flying in the USA tends to be towards a 'base' pricing model with additional ch arges for flight options, including baggage checking(!) Nine American airlines were selected at rando m. For each airline, the current fee for checking a single bag was recorded. The average for these 9 airlines is x = $25. Assume that the current fee follows a normal distribution with unknown mean u an d standard deviation o = - $6. = A 90% confidence interval for p is: A) $25 + $6.00 B) $25 + $3.29 C) $25 + $3.92
D) $25 + $9.87 E) $25 + $11.76
The 90% confidence interval for the average fee for checking a single bag is $21.71 to $28.29, which corresponds to option B) $25 + $3.29
To calculate a 90% confidence interval for the average fee for checking a single bag.
To calculate a 90% confidence interval, we need the sample mean (X), the standard deviation (σ), and the sample size (n). From your question, we have:
X = $25
σ = $6
n = 9
Since we know the standard deviation, we can use the z-score for a 90% confidence interval, which is 1.645 (you can find this in a standard z-table).
Next, we need to calculate the standard error (SE), which is the standard deviation divided by the square root of the sample size:
[tex]SE=\frac{σ}{\sqrt{n} }[/tex]
[tex]SE= \frac{ 6}{\sqrt{9} }[/tex]
[tex]SE= \frac{ 6}{3 }[/tex]
SE = $2
Now, multiply the z-score by the standard error:
Margin of Error (ME) = 1.645 × SE
ME = 1.645 × $2
ME = $3.29
Finally, construct the 90% confidence interval by adding and subtracting the margin of error from the sample mean:
Lower Limit: X - ME = $25 - $3.29 = $21.71
Upper Limit: X + ME = $25 + $3.29 = $28.29
Thus, the 90% confidence interval for the average fee for checking a single bag is $21.71 to $28.29, which corresponds to option B) $25 + $3.29.
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#8 Which statement about the two triangles is true?
The true statement about the two triangles is ΔDEF is not congruent to ΔTUV because ΔTUV cannot be mapped to ΔDEF by a single rotation, translation, or reflection. (option a).
Triangles are fundamental shapes in geometry that play a crucial role in various mathematical concepts.
When studying triangles, it is essential to understand their properties, such as congruence and similarity, and how they can be transformed through translations, rotations, and reflections. In this context, we can analyze the given statements about two triangles ADEF and ATUV.
The first statement says that ΔDEF is not congruent to ΔTUV because ΔTUV cannot be mapped to ΔDEF by a single rotation, translation, or reflection. Congruent triangles have the same size and shape, and can be transformed into one another through a combination of rotations, translations, and reflections.
Therefore, if ΔTUV cannot be transformed into ΔDEF through a single transformation, then they cannot be congruent. Hence, this statement is true.
Hence the correct option is (a).
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HELPP I HAVe TO SUbMIT THIS NOWWW
Is each point a solution to the given system of equations;
(-2, 3): Yes.
(2, 5): No.
(0, 2): Yes.
(1, 0): No.
How to determine and graph the solution for this system of inequalities?In order to graph the solution for the given system of linear inequalities on a coordinate plane, we would use an online graphing calculator to plot the given system of linear inequalities and then check the point of intersection;
y > x + 1 .....equation 1.
y < -2x + 6 .....equation 2.
Based on the graph (see attachment), we can logically deduce that the solution to the given system of linear inequalities is the shaded region behind the dashed lines, and the point of intersection of the lines on the graph representing each, which is given by the ordered pairs (-2, 3) and (0, 2).
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a large sports supplier has many stores located world wide. a regression model is to be constructed to predict the annual revenue of a particular store based upon the population of the city or town where the store is located, the annual expenditure on promotion for the store and the distance of the store to the center of the city.
The use of regression modeling in retail analytics can help businesses make data-driven decisions that ultimately lead to increased profits and growth.
Based on the information given, it seems that the large sports supplier is interested in predicting the annual revenue of a particular store based on various factors, such as population, promotion expenditure, and distance from the city center. This is a common approach in retail analytics, where regression models are often used to predict sales or revenue based on different variables.
By constructing a regression model, the sports supplier can gain valuable insights into which factors are most strongly associated with revenue, and how they can optimize their operations to increase sales. For example, they may find that stores located closer to the city center tend to have higher revenue, or that increased promotion expenditure leads to a greater increase in revenue in smaller towns.
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whats the answer to 12ab x 3cd
Suppose that it is known that on any given day in the month ofmarch there is a 0.3 probability of rain. Find the standarddeviation of rainy days in March.
The standard deviation of rainy days in March is approximately 2.55 days.
To find the standard deviation of rainy days in March, we first need to determine the expected value or the mean number of rainy days in March.
The expected value of a binomial distribution can be found using the formula: E(X) = np, where X is the random variable representing the number of rainy days in March, n is the number of trials (days in March), and p is the probability of success (rain) on a given day.
In this case, n = 31 (number of days in March) and p = 0.3 (probability of rain on any given day in March). Therefore, the expected value of rainy days in March is
E(X) = np = 31 × 0.3 = 9.3
Next, we need to find the variance of the binomial distribution, which is given by the formula: Var(X) = np(1 - p).
Var(X) = 31 × 0.3 × (1 - 0.3) = 6.51
Finally, the standard deviation of rainy days in March is the square root of the variance:
SD(X) = √Var(X) = √6.51 ≈ 2.55
Therefore, the standard deviation of rainy days in March is approximately 2.55 days.
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(Similar to an old final) Let X and Y be independent random variables with X = N(0,1) and Y = exp(1). Find E([[X|(Y+1)-1). Point/Hint: Use the concept in Lecture 13, slide 15. One of the most powerful
When X and Y be independent random variables with X = N(0,1) and Y = exp(1) then E([[X|(Y+1)-1)=0.
To find the expected value E([X|(Y+1)-1]), we first need to clarify the expression inside the brackets. Since Y+1-1 = Y, the expression becomes E([X|Y]). Now, let's proceed to find E(X|Y):
1. X and Y are independent random variables, with X following a normal distribution N(0, 1) and Y following an exponential distribution with a rate parameter of 1.
2. To find the expected value of X given Y, we can use the property of independent random variables:
E(X|Y) = E(X), since Y's value does not affect X's expected value X.
3. Given that X follows a normal distribution with a mean of 0 and a variance of 1, the expected value E(X) is equal to its mean, which is 0.
So, E([X|Y]) = E(X) = 0.
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The question and answer are in the picture
Answer:
15.8
Step-by-step explanation:
mean is the average in math so 9 + 14 + 11 + 31 + 14 =79 then you have to count how many numbers there is and minus it from the total which there is 5 numbers so 79 divided by 5 = 15.8
A student randomly draws a card from a standard deck of 52 cards. He records the type of card drawn and places it back in the deck. This is repeated 20 times. The table below shows the frequency of each outcome.
Outcome Frequency
Heart 7
Spade 3
Club 6
Diamond 4
Determine the experimental probability of drawing a diamond.
0.13
0.20
0.35
0.70
The experimental probability of drawing a diamond is 0.20
Determining the experimental probability of drawing a diamond.From the question, we have the following parameters that can be used in our computation:
Outcome Frequency
Heart 7
Spade 3
Club 6
Diamond 4
For diamond, we have
P(Diamond) = Diamond/Total
So, we have
P(Diamond) = 4/20
Evaluate
P(Diamond) = 0.20
Hence, the value is 0.20
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Use truth tables to determine whether the following pairs of symbolized statements are logically equivalent, contradictory, consistent, or inconsistent. First, determine whether the pairs of propositions are logically equivalent or contradictory; then, if these relations do not apply, determine if they are consistent or inconsistent.
â¼D ⨠B â¼ (D ·â¼B)
We can see that there are two combinations (D=T, B=F and D=F, B=T) for which both statements are true. Therefore, the given statements are consistent.
The statement given is:
¬D ∨ B ≡ ¬(D ∧ ¬B)
To show whether the given statements are logically equivalent, we can create a truth table and check if the two statements have the same truth values for all possible combinations of the propositions.
Let's start with the truth table for the left-hand side of the given statement:
D B ¬D ∨ B
----------------------
T T T
T F T
F T T
F F F
Next, let's create the truth table for the right-hand side of the given statement:
D B D ∧ ¬B ¬(D ∧ ¬B)
----------------------------------
T T F T
T F T F
F T F T
F F F T
Comparing the truth tables for both sides of the statement, we can see that they have different truth values for some combinations of D and B. Therefore, the given statements are not logically equivalent.
To determine if the given statements are contradictory or consistent, we can check if there is any combination of D and B for which both statements are true (consistent) or if there is no combination for which both statements are true (contradictory).
From the truth tables, we can see that there are two combinations (D=T, B=F and D=F, B=T) for which both statements are true. Therefore, the given statements are consistent.
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please answer i will give brainlest
The probability of puling out
a Triangle is 1/8,a Circle is 1/2, a Square is 3/8.How to find the probabilityIn order to calculate the probability of extracting each shape from the bag, a formula can be employed:
Probability = Number of times the shape was taken out / Total number of times shapes were taken out
Given below are the frequency of each shape:
Triangle: 3 times
Circle: 12 times
Square: 9 times
Total number of times shapes were taken out = 3 + 12 + 9 = 24
Probability of taking out a Triangle
= 3 / 24
= 1/8
Probability of taking out a Circle
= 12/24
= 1/2
Probability of taking out a Square
= 9/24
= 3/8
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14 1 point If two parents are homozygous for a genetically inherited recessive trait, what is the probability that they will have a child who does not have this trait in his or her phenotype?
The child will always have the recessive trait in their phenotype.
If both parents are homozygous for a recessive trait, it means they both carry two copies of the recessive allele. Let's assume that the dominant allele is represented by 'A' and the recessive allele by 'a'. Since both parents are homozygous for the recessive trait, their genotype must be 'aa'.
When these parents have children, they will each contribute one 'a' allele, resulting in all of their children inheriting the recessive allele. The probability that their child will have the trait is therefore 100%. The probability of not inheriting the trait is 0%.
Therefore, the answer to the question is 0%. The child will always have the recessive trait in their phenotype.
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Jaxon bought two boxes of eggs at a market and recorded the mass of each egg
in the stem-and-leaf diagram below.
a) Which of the boxes has the smaller range of masses?
b) What is the value of this range? Give your answer in grams (g).
Box A
9865 4 39
2 5
84 6
65321 7
Box A
Box B
Box B
4679
157
258
Key
25 represents a mass of 52 g
5/4 represents a mass of 54 g
The range of Box A is 31 grams which is smaller.
Given that, Jaxon bought two boxes of eggs at a market and recorded the mass of each egg in the stem-and-leaf diagram,
So, the ranges are ;
Box A = 76 - 45 = 31 grams
Box B = 78 - 43 = 35 grams
Therefore, we see that the range of the box A is smaller than the range of the box B.
Hence, the range of Box A is 31 grams which is smaller.
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The sum of two numbers is 47. If their difference is 21, find the smaller number
The smaller number is 13
Let x and y represent the unknown number
x + y= 47........equation 1
x - y= 21.........equation 2
From equation 1
x + y= 47
x= 47-y
Substitute 47-y for x in equation 2
(47-y)-y= 21
47-y-y= 21
47-2y= 21
-2y= 21-47
-2y= -26
y= 26/2
y= 13
Substitute 13 for y in equation 1
x + y= 47
x + 13= 47
x= 47-13
x= 34
Hence the smaller number is 13
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(5) Let р and q be two distinct primes. Show that p9-1+qp-1 is congruent to 1 (mod pq).
By using the Chinese Remainder Theorem separate the statement into two congruences we have x(p-1)(q−1)+1 (mod pq) for all x € Z.
Under the condition that the divisors are pairwise coprime (no two divisors share a common factor other than 1), the Chinese remainder theorem states that if one knows the remainders of the Euclidean division of an integer n by several integers, then one can uniquely determine the remainder of the division of n by the product of these integers.
It suffices to show pq divides x(x(p-1)(q-1) - 1) for all x e Z. We consider three cases. Consider gcd (x, pq). It has 3 possibilities.
Case 1: If gcd(x, pq) 1. Then applying using Euler's Theorem we have
= x(pq) = 1 (mod pq)
= x(p-1)(−1) = 1 (mod pq)
= x(p-1)(q-1)+1 (mod pq)
and so the result holds if gcd(x, pq) = 1. EX
Case 2: If gcd(x, pq) p. This means x = 0 (mod p). In this case we have
= 0 = x (mod p).
Since gcd(x, pq) = p therefore qx and = 1 (mod q) by Fermat's Little Theorem. This gives us that x(p-1)(q-1)+1 so we have x9-1 x(p−1)(q−1) = 1 (mod q) = x(p-1)(q-1)+1 = x (mod q).
We have shown that x(p-1)(q-1)+1 = x (mod p) and x(p-1)(q-1)+1 = x (mod q). Using the Chinese Remainder Theorem we get x(p-1)(q−1)+1 = x (mod pq).
Case 3: If gcd(x, pq) = q. This case is same as Case 2, with p being replaced by q.
Thus we have extinguished all cases and we have shown x(p-1)(q−1)+1 (mod pq) for all x € Z.
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Complete question:
Let р and q be distinct primes. Show that for all x € Z, we have the congruence x(p-1)(9–1)+1 x (mod pq). (Hint: Use the Chinese Remainder Theorem/Sun Ze's Theorem to separate the statement into two congruences.)
If we assume 25% of wild type mice will develop cancer, and 75% of mutant mice will develop cancer. What is the sample size we will need (per group) to obtain an 80% power to detect the proportion difference at the 0.05 significance level, two tailed?
We would need a sample size of at least 17 mice per group to detect a difference in proportions with a power of 0.8 and a significance level of 0.05.
To determine the sample size needed for a study, we can use power analysis. In this case, we want to detect a difference in proportions between two groups with a significance level of 0.05 and a power of 0.8.
We can use the following formula to calculate the sample size per group:
n = (Z_1-α/2 + Z_1-β)² × (p_1(1-p_1) + p_2(1-p_2)) / (p_1 - p_2)²
where:
Z_1-α/2 is the z-score corresponding to the chosen significance level (0.05/2 = 0.025 for a two-tailed test)
Z_1-β is the z-score corresponding to the chosen power (0.8 in this case)
p_1 is the proportion of wild type mice that develop cancer (0.25)
p_2 is the proportion of mutant mice that develop cancer (0.75)
Plugging in the values, we get:
n = (1.96 + 0.84)² × (0.25(1-0.25) + 0.75(1-0.75)) / (0.75 - 0.25)²
n = 16.48
Therefore, we would need a sample size of at least 17 mice per group to detect a difference in proportions with a power of 0.8 and a significance level of 0.05.
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Jim made some pancakes. For every 5 cups of flour, he added 9 cups of milk. The ratio of flour to milk in jim's pancakes is ____
Jim prepared a few pancakes. He used 9 cups of milk for every 5 cups of flour. Jim's pancakes have a flour-to-milk ratio of 5:9.
To see why, let's break down what this ratio means. The colon in the ratio notation indicates a comparison between two quantities, in this case, flour and milk. The first number before the colon (5) represents the amount of flour, while the second number after the colon (9) represents the amount of milk. So the ratio 5:9 tells us that for every 5 cups of flour Jim used, he added 9 cups of milk.
We can also express this ratio as a fraction, by dividing the amount of flour by the amount of milk. Using Jim's recipe, this would be:
5 cups of flour / 9 cups of milk
Simplifying this fraction by dividing both the numerator and denominator by 5 gives:
1 cup of flour / (9/5) cups of milk
Multiplying the denominator by 5/5 to get a common denominator gives:
1 cup of flour / 45/5 cups of milk
Simplifying again by dividing both the numerator and denominator by 5 gives:
1/9 cup of flour / 1 cup of milk
So we can see that the ratio of flour to milk in Jim's pancakes is indeed 5:9, or equivalently 1/9 cup of flour to 1 cup of milk.
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Use upper and lower sums to approximate the area of the region using the given number of subintervals (of equal width). (Round your answers to three decimal places. ) y = V 3x upper sum lower sum у 1
To approximate the area of the region defined by[tex]y = √(3x)[/tex] using upper and lower sums, we first divide the interval [0,1] into n subintervals of equal width [tex]Δx = 1/n[/tex]. We then compute the upper and lower sums using the formulae above, and take their average to obtain the approximate area.
To approximate the area of the region defined by the function [tex]y = √(3x)[/tex]using upper and lower sums, we first need to divide the interval of integration [0,1] into subintervals of equal width. Let n be the number of subintervals, then the width of each subinterval is[tex]Δx = 1/n[/tex].
The upper sum is the sum of the areas of rectangles whose heights are taken from the upper endpoints of each subinterval. Specifically, for each i from 1 to n, we compute the height of the rectangle as f(xi), where xi is the upper endpoint of the i-th subinterval.
Upper sum =[tex]Δx [f(x1) + f(x2) + ... + f(xn)], where x1 = 0, x2 = Δx, x3 = 2Δx, ..., xn = (n-1)Δx.[/tex]Similarly, the lower sum is the sum of the areas of rectangles whose heights are taken from the lower endpoints of each subinterval.
Lower sum = [tex]Δx [f(x0) + f(x1) + ... + f(xn-1)][/tex], where[tex]x0 = 0, x1 = Δx, x2 = 2Δx, ..., xn-1 = (n-1)Δx.[/tex] To find the approximate area of the region using upper and lower sums, we simply compute the upper and lower sums using the given number of subintervals, and take their average: Approximate area = (Upper sum + Lower sum)/2.
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In ΔNOP,
m
∠
N
=
(
5
x
−
8
)
∘
m∠N=(5x−8)
∘
,
m
∠
O
=
(
x
−
5
)
∘
m∠O=(x−5)
∘
, and
m
∠
P
=
(
6
x
+
1
)
∘
m∠P=(6x+1)
∘
. Find
m
∠
O
.
m∠O.
The value of angle O is 11 degrees
How to determine the valueIt is important to note that the properties of a triangle are;
A triangle has 3 sidesA triangle has 3 verticesA triangle has 3 anglesFrom the information given, we have the angles;
m<N = 5x - 8
m<O = x - 5
m<P = 6x + 1
Also, the sum of the angles in a triangle is 180 degrees
Now, substitute the angles
m<O + m<P + m<O = 180
5x - 8 + x - 5 + 6x + 1 = 180
collect the like terms
5x + x + 6x = 180 + 12
add the terms
12x = 192
x = 16
For the angle, m<O = x - 5 = 16 -5 = 11 degrees
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Can someone please pretty please help me with this!!!
Answer:
1)1) 90
1)2)30
1)3)60
2)1)90
2)2)15
2)3)20
2)4)70
Emily recorded the test scores of the students in her class
in the dot plot below. Which measure of center would be best
to use for this distribution?
The measure of center that would be best to use for this distribution is the median
How to explain the measure of centerIf the distribution is generally symmetric, the mean is the appropriate measure of center to use. This is because the mean considers every value in the distribution and is affected equally by each value.
As a result, if the dot plot has a skewed distribution, the median is the best measure of center to employ, whereas the mean is the best measure of center to use if the distribution is nearly symmetric.
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PLS HELP ASAP THANKS
The given quadratic equation is in vertex form.
option B.
What is the form of the quadratic equation?The form of the given quadratic equation is calculated as follows;
The general form of a parabola given as;
y = a(x - h)² + k
Where;
h, k is the vertex of the parabolaThe given quadratic equation is, y = ¹/₂(x - 2)² + 4, the vertex of this equation is;
a = 1/2
h = 2
k = 4
Therefore, the vertex of the parabola is (2, 4), and we can conclude that the equation is in vertex form.
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From a random sample of 1,005 adults in the United States, it was found that 32 percent own an e-reader. Which of the following is the appropriate 90 percent confidence interval to estimate the proportion of all adults in the United States who own an e-reader? (A) 0.32 1.960 (0.32 0.68) 1.005 (B) 0.32 1.645/(0.32 0.68) (C) 0.32 +2575, 10.320.68) 105 (D) 0.32 1.960, 032068) (E) 0.32 +1.645,10.3270.68)
The 90% confidence interval for the proportion of all adults in the United States who own an e-reader is 0.32 ± 1.645 * √(0.32 * 0.68 / 1,005). This corresponds to option (B) in your list of choices.
The appropriate formula for calculating the confidence interval for a proportion is:
sample proportion ± z*standard error
where z is the z-score corresponding to the desired level of confidence (90% in this case) and the standard error is:
sqrt((sample proportion*(1-sample proportion))/sample size)
Plugging in the values given in the question, we get:
sample proportion = 0.32
sample size = 1005
z-score for 90% confidence = 1.645 (option B)
standard error = sqrt((0.32*(1-0.32))/1005) = 0.015
So the appropriate 90% confidence interval is:
0.32 ± 1.645(0.015)
= 0.32 ± 0.025
= (0.295, 0.345)
Therefore, the correct answer is option B: 0.32 +1.645,10.3270.68
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Which expressions have a value greater than 1? Choose all the correct answers.
Answer:
A, C, E
Step-by-step explanation:
To determine which expressions have a value greater than 1, evaluate the expressions following the order of operations (PEMDAS) and remembering the following:
The quotient of two negative numbers is always positive.The product of two negative numbers is always positive.The product of a negative and positive number is always negative.Expression A[tex]\;\;\;\:-\frac{1}{3} \div (-2)+4\\\\= -\frac{1}{3} \cdot \left(-\frac{1}{2}\right)+4\\\\=\frac{(-1) \cdot (-1)}{3 \cdot 2}+4\\\\= \frac{1}{6}+4\\\\= 4\frac{1}{6}[/tex]
Expression B[tex]\;\;\;-\frac{1}{3} \cdot (-2)-4\\\\= \frac{2}{3} -4\\\\= \frac{2}{3} -\frac{12}{3}\\\\= \frac{2-12}{3}\\\\= -\frac{10}{3}\\\\=-3\frac{1}{3}[/tex]
Expression C[tex]\;\;\:\:-\frac{1}{3} \cdot (-2-4)\\\\= -\frac{1}{3} \cdot (-6)\\\\=\frac{(-1)\cdot (-6)}3{}\\\\= \frac{6}{3} \\\\= 2[/tex]
Expression D[tex]\;\;\:\:-\frac{1}{3} \cdot (-2)(-4)\\\\= -\frac{1}{3} \cdot (8)\\\\=\frac{(-1) \cdot 8}{3}\\\\= -\frac{8}{3} \\\\= -2\frac{2}{3}[/tex]
Expression E[tex]\;\;\:\:-\frac{1}{3} + (-2)-(-4)\\\\= -\frac{1}{3} -2+ 4\\\\= -2\frac{1}{3} + 4\\\\=4 -2\frac{1}{3}\\\\= 1\frac{2}{3}[/tex]
Therefore, the expressions that have a value greater than 1 are:
A, C and E.(a) Calculate the matrix elements of (n + apn) and (np¹ + Bpan) using the creation and annihilation operators â+ and â re- spectively, where [n) is an eigenket. Here a and ẞ are constants with appropriate dimensions.
The action of the annihilation operator â on an eigenket [n) is given by:
â[n) = √n [n-1)
Similarly, the action of the creation operator â+ on an eigenket [n) is given by:
â+[n) = √(n+1) [n+1)
Using these relations, we can express the operator (n + apn) in terms of the creation and annihilation operators as:
n + apn = â+n â + a â
Similarly, we can express the operator (np¹ + Bpan) as:
np¹ + Bpan = â+n â + B â
Now, we can use the relations between the operators and the eigenkets to calculate the matrix elements of these operators. Specifically, we need to calculate the inner products and , where |n> and |m> are arbitrary eigenkets.
Using the relations between the operators and the eigenkets, we can express these matrix elements as:
= √(n+1) + a√n
= √(n+1) + B
Here, we have used the fact that the eigenkets [n+1) and [n-1) are orthogonal to [n), and that the inner product is zero unless m = n.
Therefore, we have calculated the matrix elements of (n + apn) and (np¹ + Bpan) using the creation and annihilation operators â+ and â, and the eigenkets [n) and [n+1).
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