Explain the relationships you see in your data tables, and whether they agree with Newton’s Second Law of Motion (Fnet=ma).

The coefficient of the kinetic friction between the box and the floor is μk 0.21.

Friction is the force resisting the relative motion of strong surfaces, fluid layers, and fabric elements sliding against every different. There are several sorts of friction: Dry friction is a pressure that opposes the relative lateral movement of two solid surfaces in touch.

Calculation:-

Given,

mass = 40 Kg

Applied force F = 85 N

initial velocity u = 0 (rest)

distance moved = 1.4 meter

Final velocity = 1 m/s

coefficient of kinetic friction =?

Normal force = N = mg = 400 N

v² = u² +2as

a = v²/2s

  = 1/2×1.4

 = 0.36 m/s²

F = μkN

μk = F/N

     = 85/400

     0.21

Friction is a shape of touch pressure. It exists between the surfaces which are in touch. The frictional force relies upon on the person of the surface in contact. The rougher the floor, the greater the friction is involved. The frictional force is proportional to the urgent pressure, this is the weight of the body. it's far impartial of the place of the touch.

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The velocity of an object is the ratio of distance to the time. The graph shows, an increase in distance with the increase in time. This linearity make the velocity constant. Hence, the option D is correct.

Velocity of a substance is the measure of distance travelled per unit time. Thus it is the ratio of distance to time.In physics, velocity is the rate of speed.

Velocity = distance/time.

Hence, as the time taken for the travel increases velocity will decreases. In the given graph at each point distance shows linear relation with the time and it obtains a straight line.

Therefore, the distance is increasing with increase in time means the velocity is not changing and it remains constant. Hence, option D is correct.

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solid particles vibrate and slip past each other when they become liquid.

Answer:Blood type AB Rh+

Explanation:

Displacement from the center line for minimum intensity is 1.35 mm , width of the slit  is 0.75 so  Wavelength of the light  is 506.25.

When a wave is bent by an obstruction whose dimensions are similar to the wavelength, diffraction is observed. We can disregard the effects of extremes because the Fraunhofer diffraction is the most straightforward scenario and the obstacle is a long, narrow slit.

This is a straightforward situation in which we can apply the

Fraunhofer single slit diffraction equation:

y = mλD/a

Where:

y = Displacement from the center line for minimum intensity =  1.35 mm

λ =  wavelength of the light.

D = distance

a = width of the slit = 0.75

m = order number = 1

Solving for λ

λ = y + a/ mD

Changing the information that the issue has provided:

λ = 1.35 * 10^-3 + 0.75 * 10^-3 / 1*2  

=5.0625 *10^-7 = 506.25

so

Wavelength of the light 506.25.

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The technique that was used to release the "evil" that caused disease is Trepanning.

Option D is correct.

René Descartes would likely agree with the statement that The mind and body cannot be separated, therefore physical illness and mental illness cannot be separated. So option B is correct.

One of the negative consequence of deinstitutionalization was Many people with mental illness did not continue treatment once released.

So option C is correct.

Trepanning, also known as trepanation, trephination, trephining or making a burr hole, is described as a surgical intervention in which a hole is drilled or scraped into the human skull.

Deinstitutionalization well-intended move was predicated on the development of a community mental health center network. But it had unintended consequences, which is that many deinstitutionalized mentally ill clients have been forced onto the street with little or no treatment.

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Answer:

A

Explanation:

The ratio of I sub A to I sub B is 4.

How can you calculate the ratio of A to B?

A/B would be your formula if you were comparing one data point (A) to another data point (B). This indicates that you are multiplying information A by information B. For instance, your ratio will be 5/10 if A is 5 and B is 10. How do we determine each wheel's moments of inertia (around the axis of symmetry) I is equal to 1 over 2 times m times R squared is used to compute the moments of inertia for both masses and radii. We simply use a common factor to cancel. So 4:2=2:1 . The simplest representation of the ratio 4 to 2 is the ratio 2 to 1. Additionally, since each pair of numbers has the same relationship, the ratios are equivalent.

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12.5kg is the mass that would result in critical damping.

The ability of a damper to resist motion is shown by its damping coefficient, which measures the effectiveness of the damper. where c is the damping coefficient and is expressed in newton seconds per meter.

The damping coefficient is a term that has the formula where is a constant. This damping is equivalent to the kind of motion resistance and energy loss experienced when a piston with perforations is moved through a cylinder filled with a viscous fluid, like oil.

Force F = Kx

K = F/x

K = 3/1.5

K = 2N/m.

c² - 4mk = 0

m = c²/4k

m = 10²/4×2

m = 100/8

m = 12.5kg.

12.5kg is the mass that would result in critical damping.
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The movement of the beam of light is an illustration of distance and rates

The beam of light along the shoreline is moving at 261.5 km per minute when it is 1 km from P

The ratio of the distance traveled to the time required is used to compute average speed, which is the rate at which distance changes in relation to time.

[tex]\frac{d\theta}{dt}[/tex] = 8 rev min⁻¹ = 16 [tex]\pi[/tex] rad min⁻¹

tan [tex]\theta[/tex] = [tex]\frac{x}{5}[/tex]

Differentiate both sides with respect to t

[tex]sec^2 (\theta) \frac{d\theta}{dt} = \frac{1}{5} \frac{dx}{dt}[/tex]

[tex]\frac{d\theta}{dt}[/tex] = 16 [tex]\pi[/tex]

Then,

[tex]\frac{dx}{dt}[/tex] =  [tex]sec^2 (\theta) X 80\pi[/tex]

From the question, x = 1. calculate the hypotenuse (h) side of the triangle, using the following Pythagoras theorem.

[tex]h^2 = 1+ 5^2\\[/tex]

h =[tex]\sqrt{26}[/tex]

sec ([tex]\theta[/tex]) = [tex]\frac{\sqrt{26} }{5}[/tex]

Substitute sec ([tex]\theta[/tex]) = [tex]\frac{\sqrt{26} }{5}[/tex] in [tex]\frac{dx}{dt}[/tex] =  [tex]sec^2 (\theta) X 80\pi[/tex].

[tex]\frac{dx}{dt} = (\frac{\sqrt{26} }{5} )^2 . 80\pi[/tex]

= 83.2 [tex]\pi[/tex] = 261.48

Hence, the beam of light along the shoreline is moving at 261.5 km per minute when it is 1 km from P.

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The semi-infinite body shall be considered as a system that is bounded by one surface and that extends to infinity in other directions.

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The second coil's induced emf is 13,652.8 V.Therefore, if current varying at a rate of 1 ampere/second in one coil produces an e.m.f. of 1 volt, two coils are said to have a mutual inductance of 1 henry.

Therefore, if current varying at a rate of 1 ampere/second in one coil produces an e.m.f. of 1 volt, two coils are said to have a mutual inductance of 1 henry.

given,

I(t) = I₀ sin(ωt),  

M = 184 H, I₀ = 1.4 A,  ω = 53 rad/s.

a) magnitude of induced emf in terms of M and I

ε₂ = - M di/dt

The induced emf in the second coil is,

184 * 1.4 * 53 = 13,652.8 V.

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The induced emf in the second coil is 13,652.8 V.

Therefore, if current varying at a rate of 1 ampere/second in one coil produces an e.m.f. of 1 volt, two coils are said to have a mutual inductance of 1 henry.

given,

I(t) = I₀ sin(ωt),  

M = 184 H, I₀ = 1.4 A,  ω = 53 rad/s.

a) magnitude of induced emf in terms of M and I

ε₂ = - M di/dt

The induced emf in the second coil is,

184 * 1.4 * 53 = 13,652.8 V.

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dT = -T^4/(2mD^2)dP

P = W/T = FD/T = (m a)D/T

dP = -maD/T^2 dT

dT = -T^2/(maD)dP

V = aT

D = 1/2 a T^2

a = 2D/T^2

dT = -T^4/(2mD^2)dP

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Considering a quadratic equation to model the height of the car, we have that:

Considering an acceleration = gravity of -9.8m/s², the equation for the height is given as follows:

h(t) = -4.9t² + v(0)t + h(0).

In which:

Considering the values of these parameters for this problem, of v(0) = 20, h(0) = 115, the equation is:

h(t) = -4.9t² + 20t + 115.

At the maximum height point, we have that:

The velocity function is:

v(t) = v(0) - gt

v(t) = 20 - 9.8t.

Which is the linear function graphed at the end of the answer.

The cat hits the ground at t > 0 for which h(t) = 0, hence:

-4.9t² + 20t + 115 = 0.

Which is a quadratic equation with coefficients given by:

a = -4.9, b = 20, c = 115.

Using a calculator, the positive solution for this equation is:

t = 7.30s.

At this instant, the velocity is:

v(t) = 20 - 9.8(7.3) = -51.54 m/s.

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The work done by the constant force to pulled the elevator upward is 275000 Joules.

The work done by any force is given by,

W = Fa

Where,

W is the work done,

F is the force applied,

s is the displacement along the direction of the force,

The force applied on the elevator to pull it upward is 5500N and the distance to which the elevator is pulled is 50 m.

Now, putting values,

W = 5500(50)

W = 275000 Joules.

So, the work done by the force to pull the elevator upward is 275000 Joules.

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The magnitude of the acceleration of the boy toward the girl was 0.82 m/s².

Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.

Calculation:-

mass of girl = 45 kg

acceleration of girl = 3 m/s²

F = ma

   = 45 × 3

  = 135 N

According to newton's third law equal but the opposite force is applied to the boy towards the girl.

135 = 65 × a

a = 135/165

  = 0.82 m/s²

Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. Movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.

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The car speeds remains constant.

Using the following equation for momentum:

Pi=Pf

(c=car and r=rock)
              McVc + MrVr = McV'c + MrV'r

Initially
                         Vc=Vr=Vi
and since rocks are being dropped directly downward, final momentum of the rocks (being dropped one at a time) should be zero because their falling down, out of the railroad car.
So:
Vi( Mc+Mr) = McV'c V'c = [Vi(Mr+Mc)] / Mc

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The equal and opposite force for the force of the elevator floor pushing up on the person as described by Newton's third law is the weight and the reaction force from its effect.

This is referred to as a device which is used in the vertical transportation of goods and people among the floors in a buildings.

When an individual steps into the elevator, the weight acts on it and it is known as a downward force while the reaction acts upward in an opposite reaction as described by Newton's third law in this scenario.

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By analyzing the Sun's position information at two separate sites on the earth's surface, Eratosthenes, a Greek library in Alexandria, Egypt, discovered the moon's gravity in the third century BCE.

The solstice marks the time of year when the Sun appears to be at either its lowest or highest point in the sky. Because of this, ancients came to refer to this day as one when the Sun popped up to stand still. The word solstice is derived from the Latin words sol, which means "Sun," and sistere, which means "To Stand Still."

The Earth's axis tilts most nearly toward the sun twice a year during what are known as the solstices. The longest day is experienced in the hemisphere that is inclined closest toward our star.

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R0 is the original resistance. Thus, R = 9(6.0Ω) = 54 Ω.

Electric current flowing through and potential difference across an electrical component can be used to determine its resistance.

Ohm's Law, which depicts the connection between potential difference, current, and resistance:

V = I R, where V is the potential difference (in volts), V I is the current (in amps), A R is the resistance (in ohms), and

The following equation can be changed to determine the resistance:

R = V ÷ I

According to Ohm's equation, I = V/R, the behaviour of the material may be predicted if the resistance remains constant over a significant range of voltage. The definition above applies to both AC and DC applications of resistors, despite the fact that it deals with DC current and voltage.

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the maximum velocity of movement of any particle of the wire is 3.87 m/s

AND)

and)

L = wire length = 25 m

m = weight of wire = 100 g = 0.1 kg

The linear mass density of the wire is given as

μ = m/L = 0.1/25 = 0.004 kg/m

T = tensile force in the wire = 10 N

the speed of the wave along the wire is given as

v =√(T/μ)

v = √ (10/0.004)

v = 50 m/s

(ii)

A = amplitude = 15 mm = 0.015 m

f = frequency = 25 Hz

the maximum lateral velocity is given as

Vmax = 2πfA

Vmax = 2(3.14)(25)(0.015)

Vmax = 2.4 m/s

b)

F = force acting on each edge = 2.5 N

L = length of each edge = 0.75 m

m = weight of each edge = 125 g = 0.125 kg

the speed of the waves on the sheet is given as

v = √(FL/m) = √(2.5 x 0.75/0.125) = 3.87 m/s

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The magnitude and direction of the sum of vectors will be 4.15 m aligned in  50° in north west direction.

Both the vectors are making angle in a way that it will add up to 90° , hence a right angles triangle will be formed .

using Pythagoras theorem

[tex]H^{2} = P^{2} + B^{2}[/tex]

sum of vector = [tex]H^{2} = P^{2} + B^{2}[/tex]

H = [tex]\sqrt{P^{2} + B^{2} }[/tex]

   = [tex]\sqrt{3.14^{2} + 2.71^{2} }[/tex]

   = 4.15  m

let theta is the angle along the base vector 2

tan (theta ) = P/B = 3.14 / 2.71 = 1.16 °

theta = [tex]tan^{-1}[/tex] ( 1.16 )

         ≈ 50°

hence , The magnitude and direction of the sum of vectors will be 4.15 m aligned in  50° in north west direction.

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Using the range of projectile motion principle, it is determined that the angle at which the information disc is launched must be increased in order for it to reach the stationary spacecraft.

This expression makes it evident that if they want to extend the range of an information disc thrown at constant speed of spacecraft , they must also extend the angle at which they toss it. The horizontal distance that a projectile motion covers is known as its range. This qualifies as a projectile motion scenario for spacecraft.

An object in the air only experiences projectile motion when it is affected by gravity. A projectile motion  that is fired into the air close to the surface of the Earth and travels along a curved path, or more precisely a parabolic path, while being pulled downward by gravity, assuming that air resistance is minimal.

According to the formula of Range of projectile motion,

R = U^2*sin2[tex]\alpha[/tex]/g

therefore R is directly proportional to sin2[tex]\alpha[/tex]

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One plate of the capacitor holds a positive charge Q and the other plate holds a negative charge -Q.

When charging a capacitor, a single electron is first added to one side of the capacitor and then the charge moves so that the electron has an electric field that repels the other electrons.

This electric field penetrates space and pushes electrons into the other plate, giving that plate an induced positive charge. This will give you the same amount of charge on both plates.

So one plate of the capacitor holds a positive charge Q and the other plate holds a negative charge -Q.

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Since  Dr. Amari finds that accidents do seem to increase right after clocks are reset to an hour earlier. The research techniques that Dr. Amari using is B. archival research.

Archival research is any investigation that looks for, locates, and extracts data and proof from original archives. Archives are documents, records, and other sources pertaining to the actions and claims of people, groups, or both that are historical and not current.

Note that The term "data collection techniques" refers to procedures for gathering and analyzing various types of data. Examining papers pertaining to a topic, as well as conducting interviews and observations, are common methods of gathering data.

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The speed of the lorry 4 seconds later, given it was moving with uniform acceleration of 1.5 m/s² is 12 m/s

We'll begin by listing out the various parameters obtained from the question. This is shown below:

The final speed of the lorry can be obtained as follow:

a = (v - u) / t

1.5 = (v - 6) / 4

Cross multiply

v - 6 = 1.5 × 4

v - 6 = 6

Collect like terms

v = 6 + 6

v = 12 m/s

Thus, from the calculation made above, the final speed of the lorry is 12 m/s

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The initial speed of the particle is 15.83 km/s.

Consider a system having initial potential energy. With time as the system proceed, the potential energy gets converted to kinetic energy. The kinetic and potential energy changes individually, but the total energy is constant at every instant. This is known as the conservation of energy.

Escape velocity , v = 11.200 km/s

The radius of the earth, R = 6400 km

Let the mass of the particle be m.

Let the mass of Earth be by M.

Let the velocity of the particle be v.

By conservation of energy we have,

(1 ÷ 2)mv² - ((GMm) ÷ R) = (1 ÷ 2)m[tex]v_{e}^{2}[/tex]

where G is the gravitational constant.

The gravitational constant and the acceleration due to gravity is related:

g = GM ÷ R²

Thus equation (1 ÷ 2)mv² - ((GMm) ÷ R) = (1 ÷ 2)m[tex]v_{e}^{2}[/tex] becomes,

(1 ÷ 2)v² - gR = (1 ÷ 2)[tex]v_{e}^{2}[/tex]

v² - 2gR = [tex]v_{e}^{2}[/tex]

v² − 2 × 9.8 × [tex]10^{-3}[/tex] km/s² × 6400 km = (11.200km/s)²

v = 15.83km/s

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The question is -

What initial speed would a particle need to be given at the surface of Earth if it is to have a final speed that is equal to its escape speed when it is very far from Earth? Neglect any effects due to air resistance?

Substances in a mixture keep their separate properties, but in a compound the parts are bonded and do not keep their separate properties.

Mixtures contains elements and compounds without any fixed ratio and not by any means of chemical bonds. The elements and compounds are physically mixed and so they will be visibly distinct.

Compounds contains elements in a fixed ratio and is connected by chemical bonds. They only contain one type of molecule. Since they are chemically combined the particles appear as one and is not visibly distinct.

Therefore, substances in a mixture keep their separate properties, but in a compound the parts are bonded and do not keep their separate properties.

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If the moon orbits the Earth at a distance of 3.84 x 10⁸ on a path that takes 27.3 days to complete, its centripetal acceleration will be 2.7x 10⁻³ m/s².

A body moving in a circular path at a high rate of speed is said to be experiencing centripetal acceleration. We can calculate the moon's centripetal acceleration using the centripetal acceleration formula.

We are informed that the moon is approximately 3.84 x 10⁸ miles away from Earth and that a full rotation of the moon takes 27.3 days.

The distance traveled by the moon in 27.3 days is its velocity.

v = x/t

v = 2 πr/t

v = 2.41x10⁹/2.35x10⁶

v = 1025.5

The radius is 3.84 x 108 m and the velocity is 1,025.5 m/s. Here, we will determine the centripetal acceleration of the moon.

[tex]a_{c}[/tex] = v²/r

[tex]a_{c}[/tex] = (1025.5)²/3.84 x 10⁸

[tex]a_{c}[/tex] = 2.7 x 10⁻³

We now know the centripetal acceleration of the moon to be 2.7 103 m/s².

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The amount of constant acceleration needed to accomplish this is:

6 m/s2.

Given;

The car will drive a distance of d = 1.2 km

To convert 1.2 km to m

1.2 x 1000

= 1200 m.

beginning speed of the car, where u = 0.

Travel time, t = 20 s

To get the constant acceleration, use the following kinematic equation;

d = ut + ¹/₂at²

1200 = 0 + ¹/₂(20)²a

1200 = 400 /2

1200 = 200a

a = 1200 / 200

a = 6 m/s²

Therefore, 6 m/s² of constant acceleration is needed to accomplish this.

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The amount of constant acceleration needed to accomplish this is 6 m/s2.

A velocity change that does not alter over time is referred to as a constant acceleration. A car's average acceleration remains steady at 20 mph per minute even if it increases its speed by 20 mph in one minute and another 20 mph the next.

Given;

The car will drive a distance of d = 1.2 km

To convert 1.2 km to m

1.2 x 1000

= 1200 m.

beginning speed of the car, where u = 0.

Travel time, t = 20 s

To get the constant acceleration, use the following kinematic equation;

d = ut + ¹/₂at²

1200 = 0 + ¹/₂(20)²a

1200 = 400 /2

1200 = 200a

a = 1200 / 200

a = 6 m/s²

Therefore, 6 m/s² of constant acceleration is needed to accomplish this.

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