Explain the steps for moving three disks from one peg to another. start with moving the small disk to the right peg.

Answer:

green=100 jellybeans

Step-by-step explanation:

let the bag be (B)

red jellybeans (R)

yellow jellybeans (Y)

green jellybeans (G)

R=25

Y=3R............(1)

½ of B=G ..........(2)

from equation (1)

Y=3(25)

Y=75

since 1/2 0f the bag are G that means R+Y is equal to the remaining bag

R+Y=75+25=100 which is half of the bag

G that's half of the bag =100

Answer:

y + 8 = -4(x - 2)

Step-by-step explanation:

Point-slope form of an equation is a fill-in-the-blank, shortcut way to write an equation of a line. This is the format:

y - Y = m(x - X)

You just fill in the slope for m and fill in the point for the X,Y.

Just leave the first y; it stays a y and the first x in the parenthesis stays as an x. You just have to be careful with your minus and negative signs.

Slope is given as -4 so fill that in for m.

and put (2,-8) in place of the X and Y.

y - Y = m(x - X)

y - -8 = -4(x - 2)

y + 8 = -4(x - 2)

Done! Hope this helps!

The equation that could represent a linear combination of the system 2/3x + 5/2y = 15 and 4x + 15y = 12 is 0 = 26

Linear equations are equations that have constant average rates of change, slope or gradient

A system of linear equations is a collection of at least two linear equations.

In this case, the system of equations is given as

2/3x + 5/2y = 15

4x + 15y = 12

Multiply the first equation by 6, to eliminate the fractions.

6 * (2/3x + 5/2y = 15)

This gives

4x + 15y = 90

Subtract the equation 4x + 15y = 90 from 4x + 15y = 12

4x - 4x + 15y - 15y = 12 - 90

Evaluate the difference

0 + 0 = -78

Evaluate the sum

0 = -78

The above equation is the same equation as option (b) 0 = 26

This is so because they both represent that the system of equations have no solution

Hence, the equation that could represent a linear combination of the system is 0 = 26

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Complete question

The system of equations below has no solution.

2/3x + 5/2y = 15

4x + 15y = 12

Which equation could represent a linear combination of the system?

Answer: It is an equilateral square

Step-by-step explanation: it has 4 tick marks

Answer:

[tex]h = \frac{2A}{b+c}[/tex]

Step-by-step explanation:

Original Equation:

[tex]A = \frac{1}{2} (b+c)h[/tex]

Divide both sides by height

[tex]\frac{A}{h} = \frac{1}{2}(b+c)[/tex]

Raise both sides to the exponent -1 :

[tex](\frac{A}{h})^{-1} = (\frac{1}{2}(b+c))^{-1}[/tex]

Rewrite using the definition of a negative exponent: [tex](\frac{a}{b})^{-x} = (\frac{b}{a})^{x}[/tex]

[tex]\frac{h}{A} = \frac{1}{\frac{1}{2}(b+c)}\\[/tex]

Multiply 1/2 by (b+c)

[tex]\frac{h}{A} = \frac{1}{\frac{b+c}{2}}\\[/tex]

Keep, change, flip

[tex]\frac{h}{A} = \frac{1}{1} * \frac{2}{b+c} = \frac{2}{b+c}[/tex]

Multiply both sides by A

[tex]h = \frac{2A}{b+c}[/tex]

Also I forgot to mention but the exponent (-1) can be ignored after you flip it, since: [tex](\frac{a}{b})^x = \frac{a^x}{b^x}[/tex], but since in our case the exponent is 1, and [tex]a^1 = a[/tex], so there's really no need to write out the distribution part, since we just get the same fraction, after flipping it.

Answer:

2^n

Step-by-step explanation:

So whenever you flip a coin, you can see it as 2 nodes branching off of each existing node. so for example when you flip a coin once you're going to have 2 sequences initially H and T, now when you flip a coin again for each of those 2 sequences 2 are going to branch off of that, making the total sequences 4, and the next flip 2 sequences are going to branch off each of the 4 sequences and so on. this can generally be described as: 2^n

I attached an image describing this a bit better but the bottom line is that for each 'end node'/sequence you're going to have 2 branch off of it, thus for each coin flip the number of sequences multiplies by 2

Answer:

2^n

Step-by-step explanation:

dont worry bout it ur welcome

Explanation:

Assuming there are four answer choices, we can eliminate choices A through C because they are functions. This is because they pass the vertical line test.

The vertical line test is where we try to draw a single vertical line through more than one point on the curve. If such a task is possible, then it is said to "fail the vertical line test" and it's not a function.

For choice A, we cannot draw a single vertical line through more than one point on the parabola. Choice A passes the vertical line test. Hence, it is a function. The same goes for choices B and C.

Unfortunately choice D is not shown, but if it's the only thing left, then I'm assuming that it's some curve that fails the vertical line test.

The expression which correctly sets up the quadratic formula to solve the equation is (A) [tex]\frac{-(-4)+-\sqrt[]{-4^{2}-4(1)(3) } }{2(1)}[/tex].

What is an expression?

To find which expression correctly sets up the quadratic formula to solve the equation:

Theory of quadratic equation - A quadratic equation is defined as any equation containing one term in which the unknown is squared and no term in which it is raised to a higher power.

An example of a quadratic equation in x is [tex]-4x^{2} +4=9x[/tex].

How to solve any quadratic equation using the Sridharacharya formula?

Let us represent a general quadratic equation in x, [tex]ax^{2} +bx+c=0[/tex] where a, b and c are coefficients of the terms.

According to the Sridharacharya formula, the value of x or the roots of the quadratic equation is -

[tex]x=\frac{-b+-\sqrt{(b)^{2}-4(a)(c) } }{2a}[/tex]

The given equation is [tex]x^{2} -4x+3=0[/tex]

Comparing with the general equation of quadratic equation, we get a = 1, b = -4 , c = 3.

Putting the values of coefficients in the Sridharacharya formula,

[tex]\frac{-(-4)+-\sqrt[]{-4^{2}-4(1)(3) } }{2(1)}[/tex]  which is (A).

Therefore, the expression which correctly sets up the quadratic formula to solve the equation is (A) [tex]\frac{-(-4)+-\sqrt[]{-4^{2}-4(1)(3) } }{2(1)}[/tex].

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The complete question is shown below:

Consider this quadratic equation. x^2+3=4x. Which expression correctly sets up the quadratic formula to solve the equation?

Answer:

Step-by-step explanation: I did the test and the answer should be A

hope this helps :)

The first five terms of the sequence with the given n-th term [tex]a_n = cos(\frac{n\pi}{2} )[/tex] are : 0, -1, 0, 1, 0

For given question,

We have been given the n-th term of the sequence [tex]a_n = cos(\frac{n\pi}{2} )[/tex]

We need to find the first five terms of the sequence.

For n = 1

[tex]\Rightarrow a_1 = cos(\frac{1\pi}{2} )\\\\\Rightarrow a_1=0[/tex]

For n = 2,

[tex]\Rightarrow a_2 = cos(\frac{2\pi}{2} )\\\\\Rightarrow a_2=cos(\pi)\\\\\Rightarrow a_2=-1[/tex]

For n = 3,

[tex]\Rightarrow a_3= cos(\frac{3\pi}{2} )\\\\\Rightarrow a_3=0[/tex]

For n = 4,

[tex]\Rightarrow a_4 = cos(\frac{4\pi}{2} )\\\\\Rightarrow a_4=cos(2\pi)\\\\\Rightarrow a_4=1[/tex]

For n = 5,

[tex]\Rightarrow a_5 = cos(\frac{5\pi}{2} )\\\\\Rightarrow a_5=0[/tex]

Therefore, the first five terms of the sequence with the given n-th term[tex]a_n = cos(\frac{n\pi}{2} )[/tex] are : 0, -1, 0, 1, 0

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The multiplication shows that the answers will be:

1. 3744

2. 8244

3. 3630

4. 2616

5. 20772

6. 7820

7. 3916

8. 3521

9. 21285

10. 54162

11. 4548

12. 2091

13. 17128

14. 55692

15. $895

16. 4300 miles

1. 416 × 9 = 3744

2. 1374 × 6 = 8244

3. 726 × 5 = 3630

4. 872 × 3 = 2616

5. 2308 × 9 = 20772

6. 1564 × 5 = 7820

7. 4 × 979 = 3916

8. 503 × 7 = 3521

9. 5 × 4257 = 21285

10. 6018 × 9 = 54162

11. 758 × 6 = 4548

12. 3 × 697 = 2091

13. 2141 × 8 = 17128

14. 7 × 7956 = 55692

15. From the information given, the cost of each ticket is $179. Also, there are 5 people that are flying.

Therefore, the total cost will be:

= $179 × 5

= $895

16. Also, for the second question, since the distance between the two cities is 2150 miles. The exact distance will be:

= 2150 × 2

= 4300 miles.

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The distance between point [tex](8, \sqrt{17})[/tex] and the center (0,0) is of 9 units, which is less than the radius, hence the correct option is:

Yes, the distance from the origin to the point [tex](8, \sqrt{17})[/tex] is of 9 units.

Suppose that we have two points, [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]. The distance between them is given by:

[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

In this problem, we have a circle with center at (0,0) and radius 10. Hence, every point that is less than 10 units of distance from point (0,0) will be on the circle.

The distance of [tex](8, \sqrt{17})[/tex] is:

[tex]D = \sqrt{(8 - 0)^2+(\sqrt{17} - 0)^2}[/tex]

[tex]D = \sqrt{81}[/tex]

D = 9 units.

9 < 10, hence the correct option is:

Yes, the distance from the origin to the point [tex](8, \sqrt{17})[/tex] is of 9 units.

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Using proportions, it is found that the difference between the two salary options each year is of $5,545.

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

For the first option, $115 per week plus 9.5% commission on the associate’s total sales, the yearly salary is:

115 x 52 + 0.095 x 125000 = $17,855.

For the second option, $450 per week with no commission, the yearly salary is:

450 x 52 = $23,400.

Hence the difference is given as follows:

23400 - 17855 = $5,545.

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C = 3r + 15 is the rule for the total cost, C, where r rides are taken given that the total cost charged for a day of fun at Aussie World consists of an entry fee of $15 and a rate of $3 per ride. This can be obtained by converting the statements to algebraic equation with variables and constants.

Here in the question it is given that,

The total cost charged for a day of fun at Aussie World consists of

We have to find a rule for the total cost, C, where r rides are taken.

For one ride the rate is 3 ⇒ therefore for r rides the rate is 3r

We can convert the statements to algebraic equation so that we get the required rule,

⇒ The total cost consists of entry fee and rate of rides

⇒ The total cost = entry fee + rate of rides

⇒ C = 15 + 3r (from the given information)

⇒ C = 3r + 15

Hence C = 3r + 15 is the rule for the total cost, C, where r rides are taken given that the total cost charged for a day of fun at Aussie World consists of an entry fee of $15 and a rate of $3 per ride.

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The distance of the boat from its starting point is 156.226 .

According to the question

A boat sails on a bearing of 63 degree for 124 miles

i.e

By making 63 degree covers 124 miles

therefore ,

In figure below

AC = 124 miles

Then turns and sails 201 miles on a bearing of 192 degree

therefore ,

In figure below

CD = 201 miles  

Now,

According to the sum of triangle

∠ACB + ∠ABC + ∠BAC = 180°

∠ACB + 90° + 63° = 180°

∠ACB = 27°

CE = 180°  (Straight line )

therefore,

∠DCE = 192°  -  180°

          = 12°

As ∠C = 90°

therefore

∠ACD = ∠C - ∠DCE - ∠ACB

          = 90° - 12°- 27 °

          = 51°

Now,

The distance of the boat from its starting point = AD

By using Law of Cosines

As

The Law of Cosines can be used to find the unknown parts of an oblique triangle(non-right triangle), such that either the lengths of two sides and the measure of the included angle is known (SAS) or the lengths of the three sides (SSS) are given.

The Law of Cosines (also called the Cosine Rule) says:

c² = a² + b² − 2ab cos(C)

As we have 2 sides and one angle available we can use   Law of Cosines

Therefore,

by substituting the value

(AD)² = (AC)² + (CD)² − 2(AC)(CD) cos(∠ACD)

(AD)² = (124)² + (201)² − 2*124*201 cos(51)

AD = 156.226

Hence, the distance of the boat from its starting point is 156.226 .

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Answer:

original ft below sea level =88 feet

In six seconds goes to 182 feet

Amount of feet covered in 6 seconds=182-88=94 ft

Step-by-step explanation:

rate in feet per second = 94/6=15.66

rounding to nearest tenth=15.7ft/s

By the quadratic formula, the solution set of the quadratic equation is formed by two real roots: x₁ = 0 and x₂ = - 12.

Herein we have a quadratic equation of the form a · m² + b · m + c = 0, whose solution set can be determined by the quadratic formula:

x = - [b / (2 · a)] ± [1 / (2 · a)] · √(b² - 4 · a · c)      (1)

If we know that a = - 1, b = 12 and c = 0, then the solution set of the quadratic equation is:

x = - [12 / [2 · (- 1)]] ± [1 / [2 · (- 1)]] · √[12² - 4 · (- 1) · 0]

x = - 6 ± (1 / 2) · 12

x = - 6 ± 6

Then, by the quadratic formula, the solution set of the quadratic equation is formed by two real roots: x₁ = 0 and x₂ = - 12.

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Answer:

9.224

Step-by-step explanation:

Answer:

B. 183

Step-by-step explanation:

m<L = (1/2)[m(arc)KN - m(arc)KM)]

35 = (1/2)(177x - 107x)

70 = 70x

x = 1

m(arc)KN = 177x = 177

m(arc)NMK = 360 - m(arc)KN

m(arc)MNK = 360 - 177

m(arc)MNK = 183

The correct equation says to find R = 32 - 11 (X+2y). This gives us the value of -78.

We have this

R = 32 - 11 (X+2y)

we have the following values for x and y as 2 and 4 respectively.

What we have to do would be to find the value of R after we have put in these values in the equation.

To do this, we would then have:

R = 32 - 11(2 + 2*4)

R = 32 -11(2+8)

R = 32 - 11 * 10

R = 32 - 110

This would give us the value that says

R = -78

Hence the value of R is given as -78

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Answer:

you better give me brainliest

65/79

Step-by-step explanation:

number if boys =79-14 = 65

p of selecting a boy >> 65/79

can't cancel out so leave your answer like that

The probability is 1/3.

Probability is sincerely how likely something is to show up. whenever we're unsure about the final results of an event, we will communicate about the probabilities of positive consequences—how probably they're. The evaluation of events governed by way of possibility is called information.

Probability is the branch of mathematics concerning numerical descriptions of ways likely an occasion is to arise, or how in all likelihood it's far that a proposition is actual. The opportunity of an event is more than a few among 0 and 1, wherein, kind of talking, zero suggests impossibility of the occasion and 1 shows the truth.

Chance = the wide variety of approaches to achieving achievement. the whole range of viable consequences. as an example, the opportunity of flipping a coin and its being heads are ½ because there may be 1 manner of getting a head and the overall wide variety of feasible results is two (a head or tail). We write P(heads) = ½.

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The average rate of change over the interval is 2/9

The interval is given as:

-4 ≤ x ≤ 5

From the table, we have:

f(5) = 4

f(-4) = 2

The average rate of change is then calculated as:

[tex]m = \frac{f(5) - f(-4)}{5 --4}[/tex]

This gives

[tex]m = \frac{4 - 2}{5 +4}[/tex]

Evaluate

[tex]m = \frac{2}{9}[/tex]

Hence, the average rate of change over the interval is 2/9

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The the biggest 5 digit number based on the computation will be 87,978.

The difference between the sum of the odd-numbered digits (1st, 3rd, 5th...) and the sum of the even-numbered digits (2nd, 4th...) is divisible by 11.

An example is that 34871903 is divisible by 11

3+8+1+0=12

4+7+9+3=23

23-12=11

Here, we want (b + b) - (a + c + a) to be divisible by 11.

2b - (2a + c) to be divisible by 11

ab,cba (using 7 and 8 and 9 since they biggest)

78 987 --> 2*8 - (2*7 + 9) = 16 - (14 + 9) = 16 - 23 = -7 NO

87 978 --> 2*7 - (2*8 + 9) = 14 - (16 + 9) = 14 - 25 = -11 YES

79 897 --> 2*9 - (2*7 + 8) = 18 - (14 + 8) = 18 - 22 = -4 NO

97 879 --> 2*7 - (2*9 + 8) = 14 - (18 + 8) = 14 - 26 = -12 NO

89 798 --> 2*9 - (2*8 + 7) = 18 - (16 + 7) = 18 - 23 = -5 NO

98 789 --> 2*8 - (2*9 + 7) = 16 - (18 + 7) = 16 - 25 = -9 NO

Therefore, the biggest 5 digit number is 87,978.

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Answer:

Connect the arcs to make a perpendicular bisector

Answer:

=> Equilateral Triangle

Step-by-step explanation:

Equilateral Triangle is having 2-d shape with all equal sides and the sum of angles of any triangle is 180° .

Answer:

x - 4

Step-by-step explanation:

monomial is one term

-11x is only one term

x-4 isn't

3 is one term

22xy is only one term

only x-4 isn't a monomial

Answer:

11

Step-by-step explanation:

25 than you divided 5 + 2 than you multiply 3 and you get

Answer:

11

Step-by-step explanation: