The final answer is:
First Triangle:
B = NONE
C = NONE
c = NONE
Second Triangle:
B' = NONE
C' = NONE
c' = NONE
Using the Law of Sines, we can find the missing angles and sides of the triangles.
First Triangle:
Since A = 147°, b = 2.9 yd, and a = 1.4 yd, we can use the Law of Sines to find angle B.
sin B / 2.9 yd = sin 147° / 1.4 yd
sin B = (2.9 yd)(sin 147°) / 1.4 yd
sin B = 1.97
Since sin B is greater than 1, there is no solution for angle B. Therefore, the first triangle is not possible and we can enter NONE in each corresponding answer blank.
B = NONE
C = NONE
c = NONE
Second Triangle:
Since A = 147°, b = 2.9 yd, and a = 1.4 yd, we can use the Law of Sines to find angle B'.
sin B' / 2.9 yd = sin 147° / 1.4 yd
sin B' = (2.9 yd)(sin 147°) / 1.4 yd
sin B' = 1.97
Since sin B' is greater than 1, there is no solution for angle B'. Therefore, the second triangle is not possible and we can enter NONE in each corresponding answer blank.
B' = NONE
C' = NONE
c' = NONE
So, the final answer is:
First Triangle:
B = NONE
C = NONE
c = NONE
Second Triangle:
B' = NONE
C' = NONE
c' = NONE
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DEFG is definitely a parallelogram.
O A. True
O B. False
Answer: false
Step-by-step explanation:
since you do not know if EF and DG are the same it is not possible to know if it is true yet
Prove that any two consecutive terms in the Fibonacci sequence
are relatively prime. (The Fibonacci sequence is given by f1 = 1,
f2 = 1, fn = fn−2 + fn−1.)
They are relatively prime.
Proof: Let fn and fn-1 be any two consecutive terms in the Fibonacci sequence. By definition, fn = fn-2 + fn-1. Since both fn and fn-1 are integers,
they must have no common factors other than 1,
so they are relatively prime.
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HELP I NEED THIS ASAP 20 POINTS
PLEASE ANSWER THESE 2 MATH QUESTIONS!!!
They are not the best factors to use because 12 cannot be simplified further into a perfect square. It is better to factor 48 into perfect squares and simplify each square root separately.
What is factors?Factors can be classified as prime or composite. A prime factor is a factor that is a prime number, meaning it is only divisible by 1 and itself. For example, the prime factors of 12 are 2 and 3. A composite factor is a factor that is not a prime number, meaning it has more than two factors. For example, 4, 6, and 12 are composite factors of 12.
Let's examine the factors 4 and 12 to see if they can be used to simplify the square root of 48:
4 is a perfect square, and its square root is 2. However, 12 is not a perfect square, and its square root cannot be simplified further.
We can write 48 as 4 x 12, so the square root of 48 can be simplified as the product of the square root of 4 and the square root of 12, or 2√12.
However, this is not the simplest form of the square root of 48. We can further simplify √12 by factoring it into perfect squares: √12 = √(4 x 3) = √4 x √3 = 2√3.
Therefore, the simplest form of the square root of 48 is 2√3, not 2√12.
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Connor and Helen are playing a matching game to practice working with the laws of exponents. Connor's card has 18 . Helen has 3 cards to choose from. One card has 2−3 . Another card has (12)−2 . The final card has (22)−4 . Complete the statements below for each of Helen's cards.
The value of Connor's card is 18, so Helen must choose the card with (22)⁻⁴, since it has a value of 1/262144, which is the same as 18.
What is matching game?Matching games are a type of game often used to help develop memory skills. In a matching game, players must match objects, pictures, or words to one another. This can involve matching a picture to a word, or a word to a definition. Matching games can be used to help children learn new vocabulary or to review already learned words.
The card with 2⁻³ has a base of 2 and an exponent of -3. This means that the value of the card is 1/8, which is the same as 2⁻³.
The card with (12)⁻² has a base of 12 and an exponent of -2. This means that the value of the card is 1/144, which is the same as 12⁻².
The card with (22)⁻⁴ has a base of 22 and an exponent of -4. This means that the value of the card is 1/262144, which is the same as 22⁻⁴.
In this matching game, Connor and Helen must find the card with the same value as it is written on Connor's card.
The value of Connor's card is 18, so Helen must choose the card with (22)⁻⁴, since it has a value of 1/262144, which is the same as 18.
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A bakery makes cylindrical mini muffins that measure 2 inches in diameter and one and one fourth inches in height. If each mini muffin is completely wrapped in paper, then at least how much paper is needed to wrap 6 mini muffins? Approximate using pi equals 22 over 7.
A. 14 and 1 over 7 in2
B. 23 and 4 over 7 in2
C. 47 and 1 over 7 in2
D. 84 and 6 over 7 in2
Answer:
D. 84 and 6 over 7 in2
Step-by-step explanation:
The surface area of the cylindrical mini muffin can be calculated as follows:
Surface area = 2πr^2 + 2πrh
where r is the radius of the circular base and h is the height of the cylinder.
Given that the diameter of the mini muffin is 2 inches, the radius can be calculated as 1 inch (since radius = diameter / 2).
So, r = 1 inch and h = 1 and 1/4 inches.
Substituting these values into the surface area formula, we get:
Surface area = 2 x (22/7) x 1^2 + 2 x (22/7) x 1 x (5/4)
= (44/7) + (55/7)
= 99/7
≈ 14.14 square inches
Therefore, the surface area of 1 mini muffin is approximately 14.14 square inches.
To wrap 6 mini muffins, we need to multiply the surface area of 1 mini muffin by 6:
Surface area of 6 mini muffins = 6 x 14.14
≈ 84.84 square inches
Rounding off to one decimal place, the minimum amount of paper needed to wrap 6 mini muffins is approximately 84.8 square inches, which is closest to option D, 84 and 6/7 in^2.
emily is saving up to buy an iphone 7 that costs $850 so far she has saved $250, she would like to buy the phone in 10 weeks from now. how much must she save every week to have enough money to purchase the phone in 10 weeks
solve for x
Answer: Emily must save $60 per week.
Step-by-step explanation:
$850- $250= $600
$600/ 10= $60
Not sure where the x plays into this, but I hope this helped!
To figure out how much Emily needs to save each week in order to buy the iPhone 7 in 10 weeks, we must first figure out the amount that money she still requires to save.
The iPhone 7 costs $850, and Emily has indeed saved $250. As a result, she must proceed to save: $850 - $250 = $600 Now we need to start figuring out the amount that Emily needs to save every week in order to reach her $600 goal in 10 weeks.
To do so, simply divide amount she requires to save it by the amount of weeks she has: $600 ÷ 10 weeks = $60/week So Emily requires to save $60 a week for the next ten weeks in order to afford the iPhone 7.
To sum up, Emily must save $600 in total in order to buy the iPhone 7, and she's got 10 weeks to do so. To reach her goal, she must save $60 per week for ten weeks ($600).
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A cellular phone service provider has determined the number of devices per account has a probability distribution as follows.
X= #devices
1 2 3 4 5
Probability 0.13 0.43 0.29 ?? 0.07
Answer probabilities to 2 decimal places.
What is the probability of a randomly selected account having 4 devices?
What is the probability of a randomly selected account having at least 3 devices?
What is the probability of a randomly selected account having 2 or 4 devices?
What is the mean number of devices per account? 2 decimal places here!
What is the standard deviation of the distribution? Three decimal places here!
What is the probability that the number of devices in a randomly selected account lies within one standard deviation of the mean (inclusive) ?
Based on the probability distribution, the probability of a randomly selected account having 4 devices is 0.08. The probability of a randomly selected account having at least 3 devices is 0.44. The probability of a randomly selected account having 2 or 4 devices is 0.51. The mean number of devices per account is 2.39. The standard deviation of the distribution is 1.108. The probability that the number of devices in a randomly selected account lies within one standard deviation of the mean (inclusive) is 0.80.
For the given probability distribution, the probability of a randomly selected account having 4 devices is 0.08. This is because the total probability of all possible outcomes must equal 1. So, we can find the missing probability by subtracting the probabilities of the other outcomes from 1:
1 - 0.13 - 0.43 - 0.29 - 0.07 = 0.08
The probability of a randomly selected account having at least 3 devices is the sum of the probabilities of having 3, 4, or 5 devices:
0.29 + 0.08 + 0.07 = 0.44
The probability of a randomly selected account having 2 or 4 devices is the sum of the probabilities of having 2 and 4 devices:
0.43 + 0.08 = 0.51
The mean number of devices per account can be found by multiplying each possible outcome by its probability and summing the results:
(1)(0.13) + (2)(0.43) + (3)(0.29) + (4)(0.08) + (5)(0.07) = 2.39
The standard deviation of the distribution can be found by first calculating the variance and then taking the square root:
Variance = (1-2.39)^2(0.13) + (2-2.39)^2(0.43) + (3-2.39)^2(0.29) + (4-2.39)^2(0.08) + (5-2.39)^2(0.07) = 1.2279
Standard deviation = √1.2279 = 1.108
The probability that the number of devices in a randomly selected account lies within one standard deviation of the mean (inclusive) is the sum of the probabilities of the outcomes that fall within this range:
0.43 + 0.29 + 0.08 = 0.80
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solve the absolute value equation or indicate that the equation
has no solution.
|2x-1|=9
The equation has two solutions:[tex]x=5[/tex] and [tex]x=-4[/tex].
To solve an absolute value equation, we need to consider both the positive and negative solutions. We can do this by setting up two separate equations and solving each one individually.
The first equation is:
[tex]2x-1 = 9[/tex]
We can solve for x by isolating the variable on one side of the equation:
[tex]2x = 10[/tex]
[tex]x = 5[/tex]
The second equation is:
[tex]2x-1 = -9[/tex]
We can also solve for [tex]x[/tex] in this equation:
[tex]2x = -8[/tex]
[tex]x = -4[/tex]
Therefore, the solution to the absolute value equation[tex]|2x-1|=9[/tex] is [tex]x=5[/tex] or [tex]x=-4[/tex].
In conclusion, the equation has two solutions: [tex]x=5[/tex] and [tex]x=-4[/tex].
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En el año 2013 HUBO 1400 ALmnos que seleciona la asgnatura optativa de religion. En 2014 esta cifra bajo un 4% ¿cuantos alumnos la seleccionaran en 2014
Number of students that selected the elective subject of religion in 2014 is 1344
The problem tells us that in 2013, there were 1400 students who selected the elective subject of religion.
Then, in 2014, this figure decreased by 4%. This means that the new figure in 2014 will be 4 percentage less than the figure in 2013.
To calculate what 4% of 1400 is, we need to multiply 1400 by 4/100, which gives us 56. So, 56 students did not select the elective subject of religion in 2014 compared to 2013.
So, the number of students who selected the elective subject of religion in 2014 is
= 1400 - 56
= 1344
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please help asap and show work please o
The correct coordinates for N' after a 180° rotation about the origin are (-3, -4).
Ari's likely error was that they incorrectly flipped the signs of the coordinates independently.
How to explain the coordinatesIt should be noted that to rotate a point 180° about the origin, we need to flip the sign of both coordinates of the point. Therefore, the correct coordinates for N' after a 180° rotation about the origin are (-3, -4), not (-4, 3) as Ari claimed.
Ari's likely error was that they incorrectly flipped the signs of the coordinates independently, rather than flipping both signs together. This mistake could have arisen from a misunderstanding of the geometric concept of rotation or a simple arithmetic error.
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In the next four problems find the VOLUME of
the shapes. Label each answer correctly. Remember that volume is measured in cubic units.
5) Square prism: 4 cm x 4 cm x 8 cm
6) rectangular prism: 3 cm x 4 cm x 5 cm
7) cylinder: radius 6 cm, height 5 cm (round the answer to the nearest whole cubic centimeters.)
8) cone: radius 6 cm, height 5 cm (round the answer to the nearest whole cubic centimeter.)
Volume of square prism = 128 cm³
Volume of rectangular prism is, V = 60 cm³
Volume of cylinder is, V = 565.2 cm³
Volume of cone is, V = 188.4 cm³
What is Multiplication?To multiply means to add a number to itself a particular number of times. Multiplication can be viewed as a process of repeated addition.
Given that;
The dimensions of the shapes are,
Square prism: 4 cm x 4 cm x 8 cm
Rectangular prism: 3 cm x 4 cm x 5 cm
Cylinder: radius 6 cm, height 5 cm
Cone: radius 6 cm, height 5 cm
Now, We know that;
Volume of square = Side² × Height
Hence, We get;
Volume of square = 4² × 8
= 128
And, Volume of rectangular prism is,
V = 3 cm x 4 cm x 5 cm
V = 60 cm³
Volume of cylinder is,
V = πr²h
V = 3.14 × 6² × 5
V = 565.2 cm³
Volume of cone is,
V = πr²h/3
V = 3.14 × 6² × 5/3
V = 565.2 /3
V = 188.4 cm³
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Solve the equations. Check your solutions
Susie and Jenny are 25 miles apart. Susie sights a hot-air balloon at a 30 degree angle of elevation east of where she is standing. Jenny sights the same hot-air balloon at a 40 degree angle of elevation west of where she is standing. How far is the balloon from Jenny? (Round to the nearest thousandth.)
The distance of the hot-air balloon from Jenny is approximately 12.500 miles
To find the distance of the hot-air balloon from Jenny, we can use the Law of Sines. The Law of Sines states that the ratio of the length of a side of a triangle to the sine of the angle opposite that side is the same for all sides and angles in the triangle. In this case, the triangle is formed by Susie, Jenny, and the hot-air balloon.
Let the distance from Susie to the hot-air balloon be x, and the distance from Jenny to the hot-air balloon be y. Using the Law of Sines, we can write the following equation:
(x/sin(40)) = (y/sin(30)) = (25/sin(110))
Now, we can cross multiply and solve for y:
(y)(sin(110)) = (25)(sin(30))
y = (25)(sin(30))/(sin(110))
y = 12.500
Therefore, the distance of the hot-air balloon from Jenny is approximately 12.500 miles.
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rections: Circle the correct answer unless the problem What is the value of (mn)/(r^(2)) if m=7,n=18 and r=6 ? A. 3.5
The correct answer is A. 3.5.
The value of [tex](mn)/(r^(2))[/tex] if m=7, n=18, and r=6 can be found by plugging in the given values into the equation and simplifying.
Step 1: Plug in the given values:
[tex](mn)/(r^(2)) = (7*18)/(6^(2))[/tex]
Step 2: Simplify the equation:
[tex](7*18)/(6^(2)) = (126)/(36)[/tex]
Step 3: Simplify further:
(126)/(36) = 3.5
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According to the Funda equation of the given polynomial equatior f(x)=-3x^(2)+4x-1
The solutions to the given polynomial equation are x = 1/3 and x = 1.
According to the given polynomial equation f(x)=-3x^(2)+4x-1, we can find the values of x by using the quadratic formula, which is x = (-b ± √(b^(2)-4ac))/(2a).
In this equation, a = -3, b = 4, and c = -1.
Plugging these values into the quadratic formula, we get:
x = (-(4) ± √((4)^(2)-4(-3)(-1)))/(2(-3))
Simplifying this equation, we get:
x = (-4 ± √(16-12))/(-6)
x = (-4 ± √4)/(-6)
x = (-4 ± 2)/(-6)
Therefore, the two possible values of x are:
x = (-4 + 2)/(-6) = -2/(-6) = 1/3
x = (-4 - 2)/(-6) = -6/(-6) = 1
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What you guys are doing is not fair. Give. Me answer
Answer: stop being a brat
Step-by-step explanation:
In the diagram below, TU is parallel to
QR. If SU is 6 less than IS, QS = 55,
and SR = 44, find the length of IS.
Figures are not necessarily drawn to scale.
State your answer in simplest radical form, if necessary. In the diagram below, TU is parallel to
QR. If SU is 6 less than TS, QS = 55,
and SR = 44, find the length of TS.
Figures are not necessarily drawn to scale.
State your answer in simplest radical form, if necessary.
Consequently, IS has a 24 length as its length. SR is 44, QS is 55, and SU is 6 shorter than IS.
what is length ?A physical term known as length pertains to the measurement of an object's length or the separation of two points. Ordinarily, it is expressed in measures like metres, feet, inches, centimetres, etc. One of the basic elements of geometry is length, which is applied in many mathematical and scientific contexts.
given
TU and QR are parallel in the illustration below. Find the length of IS if SU is 6 shorter than IS, QS is 55, and SR is 44.
Since TU and QR are parallel, we have:
angle Angle = ISU QSR (matching angles) (corresponding angles)
angle Angle = SUI SRQ (alternate interior views) (alternate interior angles)
Triangles ISU and QSR are therefore comparable (by angle-angle similarity). So, here we are:
SU/QS Equals IS/SR
Inputting the numbers provided yields:
IS/44 = (IS - 6)/55
The result of multiplying both parts by 44*55 is:
55IS = 44(IS - 6) (IS - 6)
If we simplify, we get:
11IS = 264
IS = 24
Consequently, IS has a 24 length as its length. SR is 44, QS is 55, and SU is 6 shorter than IS.
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Choose the best explanation for the model described by the residual plot. The model is a bad fit ✓Comple 6 R for the data because the data are Choose
answers: part A good fit/bad fit. Part B clustered at 1., not linear, randomly distributed above below the x-axis, too far from the x-axis
The model is a good fit because the data are randomly distributed above and below the x-axis.
What is a residual value?In Mathematics, a residual value can be defined as a difference between the measured (given or observed) value from a residual plot (scatter plot) and the predicted value from a residual plot (scatter plot).
Generally speaking, the independent variable (fitted values) are generally plotted on the x-axis of a residual plot (scatter plot) while the residual value is plotted on y-axis of a residual plot (scatter plot).
Additionally, a line of best fit simply refers to a trend line on a residual plot (scatter plot) and the given model represents a good fit because the data set are randomly distributed below and above the x-axis.
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Word Bank: Parallelogram, Rectangle, Rhombus, Kite, Square, Isosceles Trapezoid.
Match the properties with the correct quadrilateral
1.
Opposite sides are congruent
Opposite angles are congruent
Consecutive angles are supplementary
Diagonals bisect each other
Diagonals are congruent
Diagonals are perpendicular
All four corner angles are 90°
Diagonals bisect angles
2.
Two pairs of consecutive congruent sides, but opposite sides are not congruent
Diagonals are perpendicular
Exactly one pair of congruent angles
Diagonals bisect one pair of angles
3.
Median = ½ (base + base)
Lower two base angles are congruent
Upper two base angles are congruent
The diagonals are congruent
Opposite angles are supplementary
4.
Opposite sides are congruent
Opposite angles are congruent
Consecutive angles are supplementary
Diagonals bisect each other
Diagonals are perpendicular
Diagonals bisect angles
All four sides are congruent.
The diagonals are NOT congruent.
5.
Opposite sides of a are congruent
Opposite angles of are congruent
Consecutive angles are supplementary
The diagonals of bisect each other
6.
Opposite sides are congruent
Opposite angles are congruent
Consecutive angles are supplementary
Diagonals bisect each other
Diagonals are congruent
All four corner angles are 90°
1. Parallelogram: Opposite sides are congruent, Opposite angles are congruent, Consecutive angles are supplementary, Diagonals bisect each other, Diagonals are congruent, Diagonals are perpendicular.
What is congruent?Congruence is a term used in mathematics to describe the relationship between two geometric figures or objects. When two geometric figures are said to be congruent, it means that the two figures have the same size and shape.
2. Rectangle: Two pairs of consecutive congruent sides, but opposite sides are not congruent, Diagonals are perpendicular, Exactly one pair of congruent angles, Diagonals bisect one pair of angles.
3. Rhombus: Opposite sides are congruent, Opposite angles are congruent, Consecutive angles are supplementary, Diagonals bisect each other, Diagonals are congruent, Diagonals are perpendicular.
4. Kite: Opposite sides are congruent, Opposite angles are congruent, Consecutive angles are supplementary, Diagonals bisect each other, Diagonals are perpendicular, Diagonals bisect angles.
5. Square: Opposite sides of a are congruent, Opposite angles of are congruent, Consecutive angles are supplementary, The diagonals of bisect each other, All four sides are congruent.
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Simplify $\frac{\sqrt{40\cdot9}}{\sqrt{49}}$.
The simplified expression of the given expression is [tex]\frac{6\sqrt{10}}{7}$.[/tex]
What is expression ?
An expression is a mathematical phrase that can contain numbers, variables, operators, and symbols. It can be a combination of terms, factors, and/or coefficients, and may involve addition, subtraction, multiplication, division, exponents, roots, and/or other mathematical operations. Expressions can be simplified, evaluated, or manipulated using algebraic rules and properties.
We can simplify the expression as follows:
[tex]\frac{\sqrt{40\cdot9}}{\sqrt{49}}=\frac{\sqrt{4\cdot10\cdot3\cdot3}}{\sqrt{7\cdot7}}\\ \\ \\=\frac{\sqrt{4}\cdot\sqrt{10}\cdot\sqrt{3}\cdot\sqrt{3}}{\sqrt{7}\cdot\sqrt{7}}\\ \\ \\=\frac{2\cdot3\sqrt{10}}{7}\\ \\ \\={\frac{6\sqrt{10}}{7}}.[/tex]
Therefore, the simplified expression of the given expression is [tex]\frac{6\sqrt{10}}{7}$.[/tex]
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(b) Now building on that, use the yp for the complex exponential forcing to find yp for the following differential equations. Warning: no credit if you are not showcasing this specific technique.
i. y′′−6y′−7y=5e2tsin(t). ii. y′′−6y′−7y=5e2tcos(t).
yp(t) = Aexp(2t) + Bexp(-2t) + Cexp(5t) + Dexp(-5t)
To find the solution to these two differential equations, we must use the technique of complex exponential forcing. The general solution for these types of equations is:
yp(t) = Aexp(2t) + Bexp(-2t) + Cexp(5t) + Dexp(-5t)
We can then use the given equations to substitute for y′ and y′′, and solve for the four constants A, B, C, and D. Doing so for equation (i), we get:
Aexp(2t) + Bexp(-2t) + Cexp(5t) + Dexp(-5t) = 5e2tsin(t) - 6[Aexp(2t) + Bexp(-2t)] - 7[Aexp(2t) + Bexp(-2t) + Cexp(5t) + Dexp(-5t)]
We can then solve this equation using algebraic manipulation to determine the four constants, and thus find the solution to this equation.
We can then use a similar method to solve equation (ii). The same general solution is used, and the constants can be determined using the same algebraic manipulation. The solution to this equation is then:
yp(t) = Aexp(2t) + Bexp(-2t) + Cexp(5t) + Dexp(-5t)
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. For each situation below, state the transformation(s) that occur between
f(x) and g(x).
(please fill out the whole thing I need it by tomorrow)
The transformations that are occurring between each of the function are given as follows:
f(x) = 14(x - 3) + 1 and g(x) = 7(x + 2) + 1: vertical compression by a factor of 1/2 and shift left 5 units.
f(x) = 6(x + 2) - 3 and g(x) = 8(x - 3) + 6: vertical stretch by a factor of 4/3, shift right 5 units and shift up 9 units.
f(x) = 3(x - 1) + 2/3 and g(x) = 3(3 - x) - 2/3: reflection over the y-axis, shift left 2 units and shift up 4/3 units.
f(x) = 1/3(x + 2) - 4 and g(x) = 1/3(-x - 2) + 6: reflection over the y-axis and shift up 10 units.
f(x) = 4/3(x - 2/3) + 1/3 and g(x) = 2/3(2/3 - x) = reflection over the y-axis, shift down of 1/3 units and vertical stretch by a factor of 2.
What are transformations?The curve of the graph "moves to the left/right/up/down," "it expands or compresses," or "it reflects" when a function is changed.
The transformation rules are defined as follows:
x -> x + a: shift left a unit.
x -> x - a: shift right a unit.
y -> y + a: shift up a unit.
y -> y - a: shift down a unit.
y -> ky, k > 1: vertical stretching by k times.
Vertical compression by a factor of k is achieved by y -> ky, k 1, horizontal compression by a factor of k is achieved by x -> kx, k > 1, and vertical stretch by a factor of k is achieved by x -> kx, k 1.
x -> -x: reflection over the y-axis.
y -> -y: reflection over the x-axis.
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There are 15 sacks of rice in a van. If each sacks weight 110kg, what is the total weight of all sacks
Answer:
Step-by-step explanation:
So all that you have to do is just multiply 15 by 110kg and you'll get a answer of 1500kg total.
HELPHELPHELPHELP!!!!!!!!!!!
The Dart Frog is a brightly colored frog. These bright colors could mean that this frog is poisonous,
warning predators to stay away. Plants in the rainforest are normally crowded and have very little
space. The big leaves of a Hosta Plant allow the plant to receive as much sunlight as possible when
the sun is out.
What type of adaptations are these? Compare and contrast the adaptations of the Dart Frog and the
Hosta Plant. Your answer should be 3–4 sentences long.
Answer:
Answer:
Most poison dart frogs are brightly colored, displaying aposematic patterns to warn potential predators. Their bright coloration is associated with their toxicity and levels of alkaloids. ... Poison dart frogs are an example of an aposematic organism.
Hostas for Full Sun
In general, yellow or gold hostas tolerate partially sunny location without losing their vibrant yellow color. About two hours of daily sun exposure will keep these yellow or golden beauties looking their best. Aim for morning sun to avoid burned leaves.
hope this helps
Step-by-step explanation:
Hope this is the right answer Have a good day!
have a good day
What is the name of the following formula : y = ax^(25) + bx^(24) + cx^(23) + dx^(22) + ex^(21) + fx^(20) + gx^(19) + hx^(18) + ix^(17) + jx^(16) + kx^(15) + lx^(14) + mx^(13) + nx^(12) + ox^(11) + px^(10) + qx^(9) + rx^(8) + sx^(7) + tx^(6) + ux^(5) + vx^(4) + wx^(3) + xx^(2) + yx + z
The name of the formula is a polynomial of degree 25 and is expressed as y = ax25 + bx24 + cx23 + dx22 + ex21 + fx20 + gx19 + hx18 + ix17 + jx16 + kx15 + lx14 + mx13 + nx12 + ox11 + px10 + qx9 + rx8 + sx7 + tx6 + ux5 + vx4 + wx3 + xx2 + yx + z
The formula you have provided is called a polynomial equation. It is a type of algebraic equation that consists of a sum of several terms, each term consisting of a constant coefficient multiplied by a variable raised to a non-negative integer power. In this case, the variable is x and the coefficients are a, b, c, d, e, f, g, h, i, j, k, l, m, n, o, p, q, r, s, t, u, v, w, x, y, and z. The highest power of the variable in this equation is 25, which means it is a 25th degree polynomial equation.
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Which shows how to multiply 2/5×4?
Responses
2×5÷4 you will be rewarded 10 points
2 times 5 divided by 4
2×4÷5
2 times 4 divided by 5
8×2÷5
8 times 2 divided by 5
4×5÷2
Answer:
i believe this is how you solve that problem... 2÷5×4
Help with this question
If there are 16 cups in one gallon how many cups are there in three gallons
Answer:
48 cups
Step-by-step explanation:
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Find general solutions of the following trigono metric equations. a. \( 4 \sin ^{2}(x)-4 \sin (x)+1=0 \) b. \( \tan (x) \sin (x)+\sin (x)=0 \) c. \( 3 \csc ^{2}(\theta)=4 \) d. \( 2 \sin (3 x)-1=0 \)
The general solutions for this equation are [tex]\( x = \frac{\pi}{18} + \frac{2n\pi}{3} \)[/tex] and [tex]\( x = \frac{5\pi}{18} + \frac{2n\pi}{3} \)[/tex].
The general solutions of the given trigonometric equations can be found by applying the basic trigonometric identities and solving for the unknown variable.
a. [tex]\( 4 \sin ^{2}(x)-4 \sin (x)+1=0 \)[/tex]
This equation can be solved by using the quadratic formula. Let \( u = \sin (x) \), then the equation becomes [tex]\( 4u^2 - 4u + 1 = 0 \)[/tex]. Using the quadratic formula, we get:
[tex]\( u = \frac{-(-4) \pm \sqrt{(-4)^2 - 4(4)(1)}}{2(4)} \)\\\( u = \frac{4 \pm \sqrt{16 - 16}}{8} \)\\\( u = \frac{4}{8} = \frac{1}{2} \)[/tex]
Now, we can substitute back \( u = \sin (x) \) and solve for x:
[tex]\( \sin (x) = \frac{1}{2} \)\\\( x = \arcsin (\frac{1}{2}) \)\\\( x = \frac{\pi}{6} + 2n\pi \) or \( x = \frac{5\pi}{6} + 2n\pi \)[/tex], where n is an integer.
The general solutions for this equation are [tex]\( x = \frac{\pi}{6} + 2n\pi \)[/tex] and[tex]\( x = \frac{5\pi}{6} + 2n\pi \)[/tex].
b. [tex]\( \tan (x) \sin (x)+\sin (x)=0 \)[/tex]
This equation can be solved by factoring out \( \sin (x) \):
[tex]\( \sin (x)(\tan (x) + 1) = 0 \)[/tex]
This equation will be true if either[tex]\( \sin (x) = 0 \) or \( \tan (x) + 1 = 0 \)[/tex].
For \( \sin (x) = 0 \), the general solutions are[tex]\( x = n\pi \)[/tex] where n is an integer.
For \( \tan (x) + 1 = 0 \), the general solutions are [tex]\( x = \frac{3\pi}{4} + n\pi \)[/tex], where n is an integer.
The general solutions for this equation are [tex]\( x = n\pi \) and \( x = \frac{3\pi}{4} + n\pi \).[/tex]
c. [tex]\( 3 \csc ^{2}(\theta)=4 \)[/tex]
This equation can be solved by isolating [tex]\( \csc ^{2}(\theta) \)[/tex] and taking the square root of both sides:
[tex]\( \csc ^{2}(\theta) = \frac{4}{3} \)[/tex]
[tex]\( \csc (\theta) = \pm \sqrt{\frac{4}{3}} \)[/tex]
Now, we can use the identity[tex]\( \csc (\theta) = \frac{1}{\sin (\theta)} \)[/tex]to solve for \( \theta \):
[tex]\( \frac{1}{\sin (\theta)} = \pm \sqrt{\frac{4}{3}} \)\( \sin (\theta) = \pm \sqrt{\frac{3}{4}} \)[/tex]
The general solutions for this equation are[tex]\( \theta = \arcsin (\pm \sqrt{\frac{3}{4}}) + 2n\pi \)[/tex], where n is an integer.
d. [tex]\( 2 \sin (3 x)-1=0 \)[/tex]
This equation can be solved by isolating[tex]\( \sin (3x) \)[/tex] and taking the inverse sine of both sides:
[tex]\( \sin (3x) = \frac{1}{2} \)\( 3x = \arcsin (\frac{1}{2}) \)\\\( 3x = \frac{\pi}{6} + 2n\pi \) or \( 3x = \frac{5\pi}{6} + 2n\pi \)[/tex], where n is an integer.
The general solutions for this equation are [tex]\( x = \frac{\pi}{18} + \frac{2n\pi}{3} \)[/tex] and [tex]\( x = \frac{5\pi}{18} + \frac{2n\pi}{3} \)[/tex].
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Employees frequently need to work in team projects. We examine the difference in the team efficiency, when employees work in teams through distance working (e.g. with online meetings) in relation to teamwork with physical presence. Data are collected from a sample of 87 employees that have worked in a team project through online meetings and 74 employees that have worked in a team with physical presence. The employees filled a questionnaire, where one question was "The teamwork was efficient", on a scale from 1-5, where 1=strongly disagree and 5=strongly agree. The mean score in this question for the team that had used online meetings was 2.63, with a standard deviation of 0.92, while for the team that had worked with physical presence the mean was 2.35, with a standard deviation of 0.81. Test if teamwork with distance meetings appears to be generally more efficient for employees, in relation to teamwork with physical presence. Use a 1% level of significance.
This hypothesis test indicates that the team efficiency when working through distance working (e.g. with online meetings) is not generally more efficient than when working with physical presence.
The research question being examined is whether teams that work through distance working (e.g. with online meetings) are generally more efficient than those that work with physical presence. To answer this question, a hypothesis test can be used with a 1% level of significance.
The null hypothesis (H0) is that there is no difference in team efficiency between those teams that work through distance working (e.g. with online meetings) and those that work with physical presence. The alternative hypothesis (H1) is that there is a difference in team efficiency between those teams that work through distance working (e.g. with online meetings) and those that work with physical presence.
To test this hypothesis, a two-tailed independent t-test was used. The mean score for the team that had used online meetings was 2.63 with a standard deviation of 0.92 and for the team that had worked with physical presence the mean was 2.35 with a standard deviation of 0.81. The t-statistic obtained was 1.71 and the corresponding p-value was 0.093.
Since the p-value (0.093) is not less than the level of significance (0.01), the null hypothesis cannot be rejected. Therefore, the data suggests that there is not a significant difference in team efficiency between those teams that work through distance working (e.g. with online meetings) and those that work with physical presence.
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