9514 1404 393
Answer:
0.5
Step-by-step explanation:
The "enclosed area" can be taken to mean different things. Here, we consider it to mean the finite area bounded between the two curves, regardless of which curve is higher value than the other.
The area is bounded on the interval [0, 2]. On half that interval y1 > y2; on the other half, y2 > y1. This means the integral of the area between the curves will be different for one part of the interval than for the other. (The curves are symmetric about the point (1, 0).)
The area on the interval [0, 1] is given by the integral ...
[tex]\displaystyle\int_0^1{(y_1-y_2)}\,dx=\int_0^1{((x-1)^3-(x-1))}\,dx\\\\=\int^1_0{(x(x-1)(x -2))}\,dx=\left.(\frac{x^4}{4}-x^3+x^2)\right|^1_0=\boxed{\frac{1}{4}}[/tex]
The area on the interval [1, 2] is the integral of the opposite integrand, but has the same value.
The positive area over the whole interval from 0 to 2 is 1/4+1/4 = 1/2.
If you simply integrate y2-y1 or y1-y2 over that interval, the result is 0.
What is the level of measurement for "year of birth"?
Answer:
interval?
Step-by-step explanation:
I'm not sure. I think so....hope its correct :)
Find the value for the side marked below.
Round your answer to the nearest tenth.
у
100
49°
y = [?]
Answer:
y = 75.5
Step-by-step explanation:
Reference angle (θ) = 49°
Hypotenuse = 100
Opposite = y
Apply trigonometric function, SOH. Which is:
Sin θ = Opp/Hyp
Plug in the values
Sin 49 = y/100
100*Sin 49 = y
y = 75.5 (nearest tenth)
Angles A and B are complementary. If sin A = 4x + 10 and cos B = 2x + 16, what is the value of x? (
Answer:
x is 10.66
Step-by-step explanation:
What are complementary angles?
They are angles that up to 90
So we have Sin A and Cos B
4x + 10+ 2x + 16= 90
collect like terms
6x+ 26= 90
6x= 90-26
6x= 64
x= 64/6
x= 10.66
Hence the value of x is 10.66
Answer:
not 10.66
Step-by-step explanation:
What is the length of an arc with a central angle of 2/3pi radians and a radius of 24 centimeters?
Use 3.14 for pi.
Enter your answer, as a decimal, in the box.
9514 1404 393
Answer:
50.24 cm
Step-by-step explanation:
Fill in the given numbers and do the arithmetic.
s = rθ
s = (24 cm)(2/3π) = (24 cm)(2/3)(3.14) = 50.24 cm
Find the solution set.
The solution set for 5v2 – 125 = 0
Answer:
5v2 – 125 = 0
5(v2−25)=0
v2−25=0
a couple more steps and the answer is...
v=-5
if x can be divide by 7 and 9 without leaving a remainder, it can also divided by which number without leaving a remainder
Answer:
all counting numbers except one
Find the length of an arc that subtends a central angle of 224° in a circle of radius 20 m
Answer:
78.2m
Step-by-step explanation:
Lenght of the arc= ( circumference) × ( fraction of the circle)
Circumference=2πr = 2×20×π
Radius=20 m
fraction of the circle can be calculated as 224°/360°= 0.662
Then substitute the values we have
Lenght of the arc=
(2×20×π) ×0.662
= 78.2,
Lenght of the arc is 78.2m
Hannah ran 12 laps for 8 days. How many laps did she run in total if she take a break of 1 complete day and 1 half day.
Answer:
The correct answer would be - 9.75 laps (if runs 12 laps in 8 days) or 78 laps (if 12 laps each day for 8 days)
Step-by-step explanation:
Given:
a) Laps covered in 8 days = 12
interval = 1 and half day
total laps = ?
Solution:
To know the total laps with intervals we need to calculate the laps run each day :
= 12/8 laps per day
= 3/2 laps per day
Now multiply the daily run with days
= (3/2)*6.5 (due to 8 - 1.5 = 6,5 days)
= 9.75 laps
B) Given:
Laps covered in 8 days = 12*8 =96
interval = 1 and half day
total laps = ?
Solution:
To know the total laps with intervals we need to calculate the laps run each day :
= 96/8 laps per day
= 12laps per day
Now multiply the daily run with days
= 12*6.5 (due to 8 - 1.5 = 6,5 days)
= 78 laps
A point is selected at random from a line segment of length l, dividing it into two line segments. What is the probability that the longer line segment is at least three times as long as the shorter segment
Answer:
3/4
Step-by-step explanation:
Let a be the length of the shorter line segment and b be the length of the longer line segment.
Since the length of the line segment is l, we have that the length of the line segment equals length of shorter line segment + length of longer line segment.
So, l = a + b
Since we require that the longer line segment be at least three times longer than the shorter line segment, we have that b = 3a
So, l = a + b
l = a + 3a
l = 4a
The probability that the shorter line segment will be a(or 3 times shorter than b) is P(a) = length of shorter line segment/length of line segment = a/l
Since l = 4a.
a/l = 1/4
So, P(a) = 1/4
The probability that a will be less than 3 times shorter that b is P(a ≤ 1) = P(0) + P(a) = 0 + 1/4 = 1/4
The probability that b will be 3 times or more greater than a is thus P(b ≥ 3) = 1 - P(a ≤ 1) = 1 - 1/4 = 3/4
A cell site is a site where electronic communications equipment is placed in a cellular network for the use of mobile phones. The numbers y of cell sites from 1985 through 2011 can be modeled byy = 269573/1+985e^-0.308t where t represents the year, with t = 5 corresponding to 1985. Use the model to find the numbers of cell sites in the years 1998, 2003, and 2006.
Answer:
(a) 3178
(b) 14231
(c) 33152
Step-by-step explanation:
Given
[tex]y = \frac{269573}{1+985e^{-0.308t}}[/tex]
Solving (a): Year = 1998
1998 means t = 8 i.e. 1998 - 1990
So:
[tex]y = \frac{269573}{1+985e^{-0.308*8}}[/tex]
[tex]y = \frac{269573}{1+985e^{-2.464}}[/tex]
[tex]y = \frac{269573}{1+985*0.08509}[/tex]
[tex]y = \frac{269573}{84.81365}[/tex]
[tex]y = 3178[/tex] --- approximated
Solving (b): Year = 2003
2003 means t = 13 i.e. 2003 - 1990
So:
[tex]y = \frac{269573}{1+985e^{-0.308*13}}[/tex]
[tex]y = \frac{269573}{1+985e^{-4.004}}[/tex]
[tex]y = \frac{269573}{1+985*0.01824}[/tex]
[tex]y = \frac{269573}{18.9664}[/tex]
[tex]y = 14213[/tex] --- approximated
Solving (c): Year = 2006
2006 means t = 16 i.e. 2006 - 1990
So:
[tex]y = \frac{269573}{1+985e^{-0.308*16}}[/tex]
[tex]y = \frac{269573}{1+985e^{-4.928}}[/tex]
[tex]y = \frac{269573}{1+985*0.00724}[/tex]
[tex]y = \frac{269573}{8.1314}[/tex]
[tex]y = 33152[/tex] --- approximated
ok i think you guys can do it
[tex] {64}^{ \frac{2}{3} } \div {27}^{ \frac{5}{3} } \times 54 \\ = > \: {({2}^{3} )}^{ \frac{2}{3} } \div ({{3}^{3}})^{ \frac{5}{3} } \times 54 \\ = > \: {2}^{2} \div {3}^{5} \times 54 \\ = > \: 4 \div 243 \times 54 \\ = > \: 4 \div 13122 \\ = > \: \frac{4}{13122} \\ = > \: \frac{2}{6561} [/tex]
Hope it helps!!!!!!!!!!
2•^2=?
A) -4
B) 1/4
C) 4
Answer:
1/4.
Step-by-step explanation:
2^-2 = 1/2^2
= 1/4.
I’m stuck please help .
Answer:
me too
Step-by-step explanation:
me too
Use the completing the square to solve x^2+6x=12.
Answer:
x= -3 ± [tex]\sqrt{21}[/tex]
Step-by-step explanation:
[tex]x^{2}[/tex]+6x=12
We add 9 [[tex](6/2)^{2}[/tex]] to both sides to complete the square as [tex]x^{2}[/tex]+6x+9 = [tex](x+3)^{2}[/tex].
[tex](x+3)^{2}[/tex]=21
Now we take the square root of both sides:
x+3=±[tex]\sqrt{21}[/tex]
x= -3 ± [tex]\sqrt{21}[/tex]
Answer:
x = -3 ± [tex]\sqrt{21}[/tex]
Step-by-step explanation:
[tex]x^2+6x=12[/tex]
[tex](\frac{b}{2} )^{2}[/tex] = 9
[tex]x^2+6x + 9 =12 + 9[/tex]
[tex](x+3)^{2} =21[/tex]
x + 3 = [tex]\sqrt{21}[/tex]
x = -3 ± [tex]\sqrt{21}[/tex]
The graph of a line goes through the points (-4,3) and (6,8). What is the equation of the line in slope-intercept form?
Enter the correct answer in the box by replacing m and b with the appropriate values.
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73°F Mostly cloudy
327 PM
7/3/2001
Answer:
[tex]y=\frac{1}{2}x+5[/tex]
Step-by-step explanation:
Hi there!
Slope intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when x is 0)
1) Determine the slope (m)
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex] where two points that lie on the line are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]
Plug the given points (-4,3) and (6,8) into the equation
[tex]m=\frac{8-3}{6-(-4)}\\m=\frac{8-3}{6+4}\\m=\frac{5}{10}\\m=\frac{1}{2}[/tex]
Therefore, the slope of the line is [tex]\frac{1}{2}[/tex]. Plug this into [tex]y=mx+b[/tex] :
[tex]y=\frac{1}{2}x+b[/tex]
2) Determine the y-intercept (b)
[tex]y=\frac{1}{2}x+b[/tex]
Plug in one of the given points and solve for b
[tex]8=\frac{1}{2}(6)+b\\8=3+b[/tex]
Subtract 3 from both sides to isolate b
[tex]8-3=3+b-3\\5=b[/tex]
Therefore, the y-intercept is 5. Plug this back into [tex]y=\frac{1}{2}x+b[/tex]:
[tex]y=\frac{1}{2}x+5[/tex]
I hope this helps!
Is −8 a solution to the equation 3x = 16 − 5x? How do you know?
Which system of equations shows a solution of (0.5, -1)?
Need answers asap plzzz
Answer:
The first graph
Step-by-step explanation:
Solve for the following equation for x. l x/4 + 3 l < 6
Answer:
this is the answer I got! i don't know if it helps, but I hope it does
What is the growth factor that corresponds to a product that increases its value first by 2%, and then increases by 5% of
its value, and finally increases by 12% of its value? Round to the tenths place.
a. 1.20
C. 1.19
b. 3.19
d. 1
Answer:
1.19
Step-by-step explanation:
1+0.02+0.05+0.12 = 1.19
Find the simplified product:
V9x* - 33x
O
V12x12
о
327x12
O
3x4
O
9.x
9514 1404 393
Answer:
(c) 3x^4
Step-by-step explanation:
The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
(a^b)^c = a^(bc)
___
[tex]\displaystyle\sqrt[3]{9x^4}\cdot\sqrt[3]{3x^8}=\sqrt[3]{9\cdot3x^4x^8}=\sqrt[3]{27x^{12}}=\sqrt[3]{(3x^4)^3}=\boxed{3x^4}[/tex]
Will give brainliest answer
Answer: 2/5x to the second.
may I have the brainiest? pls
Using a weight of 12 for the most recent observation, 13 for the second most recent observation, and 16 for third most recent observation, compute a three-week weighted moving average for the time series. (Round your answers to two decimal places.)
Answer: Hi some data is missing attached below is the missing data
answer:
WMA = 174.53
Step-by-step explanation:
Determine the three-week weighted moving average with weights
( 1/2, 1/3, 1/6 )
Weighted moving average ( WMA ) = 174.53
MSE = ∑ (xi - WMA)^2 / n
= 9.71
attached below is the detailed solution/table
If you spin two times, what is the probability of landing on
green both times? (leave answer in fraction form in lowest
terms)
Red
Green
Yellow
Red
1/9
1/30
1/6
1/360
find the value of the following 425×167+233×425 step by step explanation
Answer:
so first we start from the left
425*167=70975
but instead of adding this to 233 we use pemdas so instead we do
233*425=99025
now we add them together
70975+99025=170000
Hope This Helps!!!
Answer:
170,000
Step-by-step explanation:
425 × 167 + 233 × 425
= (425 × 167) + (233 × 425)
= 70,975 + 99,025
= 170,000
Please explain the misleading
There are more compact cars (4*10 = 40) compared to trucks (2*10 = 20); however, the pictogram might make it appear that there are more trucks because the individual truck icon is larger compared to an individual compact car icon.
To anyone giving this image a quick glance, they may erroneously conclude that there are more trucks since their eye would notice the trucks first. Also, the person might think there are more trucks because bigger sizes tend to correspond to more proportion.
In real life, a truck is larger than a compact car, but the icons need to be the same size to have the figure not be misleading.
A very similar issue happens with the mid-size cars vs the compact cars as well. The three mid-size car icons span the same total width as the compact cars do, indicating that a reader might mistakenly conclude that there are the same number of mid-size cars compared to compact ones (when that's not true either).
Mrs. Rodger got a weekly raise of $145. If she gets paid every other week, write an integer describing how the raise will affect her paycheck.
Answer:
her salary will increase by $ 145 for every week
Step-by-step explanation:
x=1st paycheck (integer).
weekly raise = $ 145.
After completing the 1st week she will get $ (x+145).
Similarly after completing the 2nd week she will get
$ (x + 145) + $ 145.
= $ (x + 145 + 145)
= $ (x + 290)
So in this way end of every week her salary will increase by $ 145.
What is the volume of a cone with a height of 27 cm
and a radius of 13 cm? Round your answer to the
nearest tenth.
Use the button on your calculator to complete this
problem.
V=
cm3
Answer:4778.3 cm^3
Step-by-step explanation: The formula for volume of a cone is V=1/3h pi r^2. By plugging in the height and the radius we get our answer.
Answer:
4778.4 :)
Step-by-step explanation:
In an international film festival, a penal of 11 judges is formed to judge the best film. At last two films FA and FB were considered to be the best where the opinion of judges got divided. Six judges where in favor of FA whereas five in favor of FB. A random sample of five judges was drawn from the panel. Find the probability that out of five judges, three are in favor of film FA.
Answer:
The answer is "0.4329 ".
Step-by-step explanation:
P( three in favor of FA)
Select 3 out of 6 FA supporters then select 2 out of 5 FB supportive judges
[tex]=\frac{^{6}_{C_{3}}\times ^{5}_{C_{2}}}{^{11}_{C_{5}}}\\\\=\frac{\frac{6!}{3!(6-3)!}\times \frac{5!}{2!(5-2)!}}{\frac{11!}{5!(11-5)!}}\\\\=\frac{\frac{6!}{3! \times 3!}\times \frac{5!}{2! \times 3!}}{\frac{11!}{5! \times 6!}}\\\\=\frac{\frac{6 \times 5 \times 4 \times 3!}{3 \times 2 \times 1\times 3!}\times \frac{5 \times 4 \times 3!}{2 \times 1 \times 3!}}{\frac{11 \times10 \times 9 \times 8 \times 7 \times 6! }{5 \times 4 \times 3 \times 2 \times 1 \times 6!}}\\\\[/tex]
[tex]=\frac{ (5 \times 4) \times(5 \times 2)}{(11 \times 3 \times 2 \times 7 )}\\\\=\frac{ 20 \times 10 }{(11 \times 42)}\\\\=\frac{ 200 }{462}\\\\=\frac{100 }{231}\\\\=0.4329[/tex]
i got some summer h.w it doesn't have a answer but like it asks for me to Create a table of x and y values that represents a proportional relationship. and i dont know how cause it wont let me draw a graph so i have to write something down apparently any help pls?
Answer:
So for example a graph in typed in word format could look like
Time Girls Boys
1 3 5
2 4 6
3 5 7
4 6 8
5 7 9
Not saying that this graph would be sufficient value wise for the answer, but this is how I would tackle it if I wasn't given the option to draw a graph.
Could someone help me
Hello,
I have only found 113 solutions (i have num 15 given)
nb= 1 ::: 27*n + 98= 30*n + 56===> n= 1 4
nb= 2 ::: 28*n + 95= 30*n + 67===> n= 1 4
nb= 3 ::: 29*n + 65= 30*n + 17===> n= 4 8
nb= 4 ::: 29*n + 65= 30*n + 18===> n= 4 7
nb= 5 ::: 29*n + 65= 30*n + 47===> n= 1 8
nb= 6 ::: 29*n + 65= 30*n + 48===> n= 1 7
nb= 7 ::: 29*n + 74= 30*n + 16===> n= 5 8
nb= 8 ::: 29*n + 74= 30*n + 18===> n= 5 6
nb= 9 ::: 29*n + 74= 30*n + 56===> n= 1 8
nb= 10 ::: 29*n + 74= 30*n + 58===> n= 1 6
nb= 11 ::: 30*n + 16= 29*n + 74===> n= 5 8
nb= 12 ::: 30*n + 17= 29*n + 65===> n= 4 8
nb= 13 ::: 30*n + 18= 29*n + 65===> n= 4 7
nb= 14 ::: 30*n + 18= 29*n + 74===> n= 5 6
nb= 15 ::: 30*n + 47= 29*n + 65===> n= 1 8
nb= 16 ::: 30*n + 48= 29*n + 65===> n= 1 7
nb= 17 ::: 30*n + 56= 27*n + 98===> n= 1 4
nb= 18 ::: 30*n + 56= 29*n + 74===> n= 1 8
nb= 19 ::: 30*n + 58= 29*n + 74===> n= 1 6
nb= 20 ::: 30*n + 67= 28*n + 95===> n= 1 4
nb= 21 ::: 36*n + 97= 40*n + 25===> n= 1 8
nb= 22 ::: 38*n + 59= 40*n + 27===> n= 1 6
nb= 23 ::: 38*n + 65= 40*n + 27===> n= 1 9
nb= 24 ::: 38*n + 69= 40*n + 15===> n= 2 7
nb= 25 ::: 39*n + 78= 45*n + 6===> n= 1 2
nb= 26 ::: 39*n + 82= 40*n + 15===> n= 6 7
nb= 27 ::: 39*n + 82= 40*n + 17===> n= 6 5
nb= 28 ::: 39*n + 82= 40*n + 65===> n= 1 7
nb= 29 ::: 39*n + 82= 40*n + 67===> n= 1 5
nb= 30 ::: 40*n + 15= 38*n + 69===> n= 2 7
nb= 31 ::: 40*n + 15= 39*n + 82===> n= 6 7
nb= 32 ::: 40*n + 17= 39*n + 82===> n= 6 5
nb= 33 ::: 40*n + 25= 36*n + 97===> n= 1 8
nb= 34 ::: 40*n + 27= 38*n + 59===> n= 1 6
nb= 35 ::: 40*n + 27= 38*n + 65===> n= 1 9
nb= 36 ::: 40*n + 65= 39*n + 82===> n= 1 7
nb= 37 ::: 40*n + 67= 39*n + 82===> n= 1 5
nb= 38 ::: 46*n + 87= 50*n + 39===> n= 1 2
nb= 39 ::: 46*n + 87= 52*n + 9===> n= 1 3
nb= 40 ::: 47*n + 68= 50*n + 29===> n= 1 3
nb= 41 ::: 47*n + 83= 50*n + 26===> n= 1 9
nb= 42 ::: 47*n + 98= 51*n + 6===> n= 2 3
nb= 43 ::: 47*n + 98= 53*n + 2===> n= 1 6
nb= 44 ::: 48*n + 63= 50*n + 29===> n= 1 7
nb= 45 ::: 48*n + 73= 52*n + 9===> n= 1 6
nb= 46 ::: 49*n + 63= 51*n + 7===> n= 2 8
nb= 47 ::: 49*n + 72= 53*n + 8===> n= 1 6
nb= 48 ::: 49*n + 78= 52*n + 30===> n= 1 6
nb= 49 ::: 49*n + 87= 56*n + 3===> n= 1 2
nb= 50 ::: 50*n + 26= 47*n + 83===> n= 1 9
nb= 51 ::: 50*n + 29= 47*n + 68===> n= 1 3
nb= 52 ::: 50*n + 29= 48*n + 63===> n= 1 7
nb= 53 ::: 50*n + 39= 46*n + 87===> n= 1 2
nb= 54 ::: 52*n + 30= 49*n + 78===> n= 1 6
nb= 55 ::: 57*n + 92= 63*n + 8===> n= 1 4
nb= 56 ::: 58*n + 72= 60*n + 34===> n= 1 9
nb= 57 ::: 58*n + 73= 60*n + 49===> n= 1 2
nb= 58 ::: 58*n + 79= 60*n + 31===> n= 2 4
nb= 59 ::: 58*n + 97= 60*n + 13===> n= 4 2
nb= 60 ::: 59*n + 47= 62*n + 8===> n= 1 3
nb= 61 ::: 59*n + 71= 60*n + 23===> n= 4 8
nb= 62 ::: 59*n + 71= 60*n + 28===> n= 4 3
nb= 63 ::: 59*n + 71= 60*n + 43===> n= 2 8
nb= 64 ::: 59*n + 71= 60*n + 48===> n= 2 3
nb= 65 ::: 59*n + 74= 63*n + 2===> n= 1 8
nb= 66 ::: 59*n + 78= 61*n + 30===> n= 2 4
nb= 67 ::: 59*n + 84= 61*n + 30===> n= 2 7
nb= 68 ::: 59*n + 87= 61*n + 3===> n= 4 2
nb= 69 ::: 60*n + 13= 58*n + 97===> n= 4 2
nb= 70 ::: 60*n + 23= 59*n + 71===> n= 4 8
nb= 71 ::: 60*n + 28= 59*n + 71===> n= 4 3
nb= 72 ::: 60*n + 31= 58*n + 79===> n= 2 4
nb= 73 ::: 60*n + 34= 58*n + 72===> n= 1 9
nb= 74 ::: 60*n + 43= 59*n + 71===> n= 2 8
nb= 75 ::: 60*n + 48= 59*n + 71===> n= 2 3
nb= 76 ::: 60*n + 49= 58*n + 73===> n= 1 2
nb= 77 ::: 61*n + 30= 59*n + 78===> n= 2 4
nb= 78 ::: 61*n + 30= 59*n + 84===> n= 2 7
nb= 79 ::: 65*n + 89= 70*n + 24===> n= 1 3
nb= 80 ::: 68*n + 59= 72*n + 3===> n= 1 4
nb= 81 ::: 68*n + 91= 70*n + 45===> n= 2 3
nb= 82 ::: 69*n + 43= 70*n + 15===> n= 2 8
nb= 83 ::: 69*n + 43= 70*n + 18===> n= 2 5
nb= 84 ::: 69*n + 43= 70*n + 25===> n= 1 8
nb= 85 ::: 69*n + 43= 70*n + 28===> n= 1 5
nb= 86 ::: 69*n + 48= 72*n + 3===> n= 1 5
nb= 87 ::: 69*n + 52= 70*n + 14===> n= 3 8
nb= 88 ::: 69*n + 52= 70*n + 18===> n= 3 4
nb= 89 ::: 69*n + 52= 70*n + 34===> n= 1 8
nb= 90 ::: 69*n + 52= 70*n + 38===> n= 1 4
nb= 91 ::: 69*n + 54= 71*n + 8===> n= 2 3
nb= 92 ::: 69*n + 58= 73*n + 2===> n= 1 4
nb= 93 ::: 69*n + 82= 75*n + 4===> n= 1 3
nb= 94 ::: 69*n + 85= 74*n + 20===> n= 1 3
nb= 95 ::: 70*n + 14= 69*n + 52===> n= 3 8
nb= 96 ::: 70*n + 15= 69*n + 43===> n= 2 8
nb= 97 ::: 70*n + 18= 69*n + 43===> n= 2 5
nb= 98 ::: 70*n + 18= 69*n + 52===> n= 3 4
nb= 99 ::: 70*n + 24= 65*n + 89===> n= 1 3
nb= 100 ::: 70*n + 25= 69*n + 43===> n= 1 8
nb= 101 ::: 70*n + 28= 69*n + 43===> n= 1 5
nb= 102 ::: 70*n + 34= 69*n + 52===> n= 1 8
nb= 103 ::: 70*n + 38= 69*n + 52===> n= 1 4
nb= 104 ::: 70*n + 45= 68*n + 91===> n= 2 3
nb= 105 ::: 74*n + 20= 69*n + 85===> n= 1 3
nb= 106 ::: 76*n + 93= 80*n + 45===> n= 1 2
nb= 107 ::: 79*n + 45= 82*n + 6===> n= 1 3
nb= 108 ::: 79*n + 54= 83*n + 6===> n= 1 2
nb= 109 ::: 80*n + 45= 76*n + 93===> n= 1 2
nb= 110 ::: 87*n + 64= 90*n + 25===> n= 1 3
nb= 111 ::: 87*n + 65= 90*n + 23===> n= 1 4
nb= 112 ::: 90*n + 23= 87*n + 65===> n= 1 4
nb= 113 ::: 90*n + 25= 87*n + 64===> n= 1 3