Find the critical point for f and then use the second derivative test to decide whether the critical point is a relative maximum or a relative minimum.f(x)=-x^2-2x-9

Answer

a) chart

Step-by-step explanation:

a) chart best represents the following information about student results from a class assignment

Answer:

Yeah the answer is n o .

Answer:

yes i do have but i dont use it

Answer:

60 miles

Step-by-step explanation:

Create an equation where y is the total cost and x is the number of miles traveled.

0.8x will represent the cost from the miles traveled. 8.5 will be added to this to represent the taxi cost and additional charge from tolls:

y = 0.8x + 8.5

Plug in 56.50 as y and solve for x, the number of miles:

y = 0.8x + 8.5

56.5 = 0.8x + 8.5

48 = 0.8x

60 = x

So, you can travel 60 miles

Answer:

Cuboid = width*height*length

Cuboid = 24 cm^2

Answer:

y-(-20)=1(x-(-10))

Step-by-step explanation:

If you're really in college you should know this, but here's the explanation:

m= -9-(-20)

      1-(-10)

  = 11

     11

m = 1

The equation is y-y^1=m(x-x^1)

Replace the y^1, m, and x^1 from the first point

You get y-(-20)=1(x-(-10))

Or simplify that into y+20=x+10

You can also simplify it more but I don't think you need that for that question

Answer:

ghthtf

Step-by-step explanation:

tygtgg

Answer:

270 plates

Step-by-step explanation:

First, you need to find how much one plate costs.

6x = 54

----    ----

6       6

x = 9

Now, multiply 30 plates with x, which is 9.

30(9) = 270

The answer is 270.

Answer:

270

Step-by-step explanation:

54($)÷6= 9 then 9×30=270

Answer:

y=4√3 units

Step-by-step explanation:

Hi there!

We are given ΔABC, which is a right triangle (m<C=90°), m<A=60°, AB=8, and BC=y

We need to find the value of y (BC)

The side AB is the hypotenuse of the  (the side opposite from the right angle).

BC is a leg, which is a side that makes up the right angle.

Now, if we have a right triangle that has one of the acute angles as 60°, the side OPPOSITE from that 60° angle (in this case, BC) is equal to [tex]\frac{a\sqrt{3}}{2}[/tex], where a is the length of the hypotenuse

Since we have the hypotenuse given as 8, the length of BC (y) is [tex]\frac{8\sqrt{3}}{2}[/tex], or 4√3

so y=4√3 units

Hope this helps!

Answer:

19219.48

Step-by-step explanation:

16540x0.162+16540

The original price would be 100%

It was marked down 16.2%

100 % - 16.2% = 83.8%

The price you paid was 83.8% of the original price.

To find the original price divide the amount you paid by the percentage of the original price:

16,540 / 0.838 = 19.737.47

Original price: $19,737.47

Answer:

AAS

Step-by-step explanation:

It will be angle angle side because you are given a side and two angles, and when you put them in the correct order, you will get AAS, or SAA (not the correct way to say it)

a hour,.....................

step by step explanation:

[tex]\mathfrak{x}^{2}+{y}^{2}+16=0[/tex]

=[x2+16=0x26]

=[2x{y}^2{16}~0]

=[4×{y}^0{16}]

=[32x{y}^x]

Answer:

f is not a function

Step-by-step explanation:

Given

Domain: Whole numbers

Range: Real numbers

Required

Is f a function

Base on the given parameters, f is not a function because:

There are more real numbers than whole numbers

And this implies that at least one element in the domain will have more than one corresponding elements in the range. i.e. one-to-many or many-to-many relationship

For a relation to be regarded as a function, the relationship has to be one-to-one or many-to-one

i.e. 1 or many domain elements to 1 element in the range.

An example is:

[tex]\begin{array}{ccccc}x & {1} & {9} & {9} & {0} \ \\ f(x) & {1.5} & {3.2} & {-3.5} & {0.1} \ \end{array}[/tex]

In the above function

The domain (i.e. x values) are whole numbers

The range (i.e. y values) are real numbers

However,

9 points to 3.2 and -3.5

So, the relation is not a function.

Answer with Step-by-step explanation:

Complete question:

The coordinates  of the vertices of the triangle are (-8,8),(-8,-4), and. Consider QR the base of the triangle. The measure of the base is b = 18 units, and the measure of the height is h = units. The area of triangle PQR is square units.

Let

P=(-8,8)

Q=(-8,-4)

QR=b=18 units

Height of triangle, h=Length of PQ

Distance formula

[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Using the formula

Height of triangle, h=[tex]\sqrt{(-8+8)^2+(-4-8)^2}=12units[/tex]

Area of triangle PQR=[tex]\frac{1}{2}\times base\times height[/tex]

Area of triangle PQR=[tex]\frac{1}{2}\times 18\times 12[/tex]

Area of triangle PQR=108 square units

Length of QR=18units

Let the coordinates of R(x,y)

[tex]\sqrt{(x+8)^2+(y+4)^2}=18[/tex]

[tex](x+8)^2+(y+4)^2=324[/tex]

[tex]x^2+64+16x+y^2+8y+16=324[/tex]

[tex]x^2+y^2+16x+8y=324-64-16[/tex]

[tex]x^2+y^2+16x+8y=244[/tex]   ......(1)

Using Pythagoras theorem

[tex]H=\sqrt{P^2+B^2}[/tex]

[tex]H=\sqrt{(18)^2+(12)^2}[/tex]

[tex]H=6\sqrt{13}[/tex]units

[tex](6\sqrt{13})^2=(x+8)^2+(y-8)^2[/tex]

[tex]x^2+64+16x+y^2+64-16y=468[/tex]

[tex]x^2+y^2+16x-16y=468-64-64=340[/tex]

[tex]x^2+y^2+16x-16y=340[/tex] .....(2)

Subtract equation (2) from (1) we get

[tex]24y=-96[/tex]

[tex]y=-96/24=-4[/tex]

Using the value of y in equation (1)

[tex]x^2+16x+16-32=244[/tex]

[tex]x^2+16x=244-16+32[/tex]

[tex]x^2+16x=260[/tex]

[tex]x^2+16x-260=0[/tex]

[tex]x^2+26x-10x-260=0[/tex]

[tex]x(x+26)-10(x+26)=0[/tex]

[tex](x+26)(x-10)=0[/tex]

[tex]x=-26, x=10[/tex]

Hence, the coordinate of R (10,-4) or (-26,-4).

Answer:

5555 Lakh rupoes maybe hope it helps

The amount Frans took as loan = R12000

"It is the interest that is only calculated on the initial amount of the loan."

[tex]SI=\frac{P\times R\times T}{100}[/tex]

where, P: principal amount

T : period

R: rate of interest

For given question,

SI = 9600

T = 5 years

R = 16%

We need to find the principal amount.

Using simple interest formula,

[tex]\Rightarrow SI=\frac{P\times R\times T}{100}\\\\\Rightarrow P=\frac{SI\times 100}{R\times T}\\\\\Rightarrow P=\frac{9600\times 100}{5\times 16}\\\\\Rightarrow P=12000[/tex]

Therefore, the amount Frans took as loan = R12000

Learn more about the simple interest here:

https://brainly.com/question/22621039

#SPJ3

Answer and explanation:

A linear problem is an equation based on known and unknown variables that follow a linear path, usually without exponents and look like this:

y=mx+b. To formulate the linear constraints of the problem above, we look at the unknown variables and known variables and define and equation using this.

From the problem, assume x and y are the prices of the different boat brands:

50x+50y=420000

Assume a and b are number of x brand boats and y brand boats supplied thus:

a+b>=200

Answer:

absolute value of the determinant, adjacent to, equal to

Step-by-step explanation:

The absolute value of a determinant  of the [tex]\text{matrix whose}[/tex] columns are the vectors and they define the [tex]\text{sides}[/tex] of a [tex]\text{parallelogram}[/tex] which is adjacent to  one another and is equal to the [tex]\text{area}[/tex] of the [tex]\text{parallelogram}[/tex].

The determinant is a real number. They are like matrices, but we use absolute value bars to show determinants whereas to represent a matric, we use square brackets.

Step-by-step explanation:

put the value of f(x)

I think that you know

hope it is helpful for you

Answer:

4x + 2h - 1

Step-by-step explanation:

[tex]\frac{f(x+h) - f(x)}{h}[/tex]

[tex]\frac{(2(x+h)^2 - (x + h) + 5) - (2x^2 - x + 5)}{h}[/tex]

[tex]\frac{2x^2 + 4xh + 2h^2 - x - h + 5 - 2x^2 + x - 5}{h}[/tex]

[tex]\frac{4xh + 2h^2 - h}{h}[/tex]

4x + 2h - 1

Answer:

x²+6x-4 is answer maybe

9514 1404 393

Answer:

  -1/3x

Step-by-step explanation:

We want to find the term 'a' such that ...

  (5/6x -4) + a = (1/2x -4)

Add 4-1/2x to both sides.

  (5/6 -1/2)x -4 +4 +a = 0

  (5/6 -3/6)x + a = 0 . . . . . . express the fractions using a common denominator

  1/3x + a = 0 . . . . . . . . . . simplify the difference

  a = -1/3x . . . . . . . . . . .subtract 1/3x

The term you can add to make the desired equivalent is -1/3x.

Answer:

0.5759

Step-by-step explanation:

Answer:

The responses to these question can be defined as follows:

Step-by-step explanation:

For point a:

[tex]\to P(1) = 0.73[/tex]

For point b:

[tex]\to P(2\ or\ 3) = P(2) + P(3)[/tex]

                    [tex]= 0.27 \times 0.73 + 0.27\times 0.27\times0.73\\\\=0.1971+0.1971\times 0.27\\\\=0.1971+0.053217\\\\=0.250317[/tex]

Answer:

15=2p+3

Step-by-step explanation:

Answer:

a) f(x,y) = - 1    minimum  at   P ( 0 ; -1 )

b) f (x,y) = 10  maximum at   P ( 3 , 1 ) and   f (x,y) = - 10 minimum at       Q ( - 3 , - 1 )

c)  Max  f ( x , y ) = 2   for points    P ( 1, 2 )  and T ( -1 , -2 )

Min  f ( x , y ) =  -2   for points   Q ( 1 , - 2 )  and R  ( -1 , 2 )

Step-by-step explanation:

A)  f(x,y) = x² - y²         subject to   x² + y² = 1      g(x,y) = x² + y²- 1

δf(x,y)/ δx  = 2*x                                                 δg(x,y)/ δx  =    2*x                      

δf(x,y)/ δy  = - 2*y                                                 δg(x,y)/ δy  =    2*y

δf(x,y)/ δx  = λ* δg(x,y)/ δx

2*x = λ*2*x

δf(x,y)/ δy  = λ* δg(x,y)/ δy

- 2*y = λ*2*y

Then, solving

2*x = λ*2*x           x = λ*x      λ = 1

- 2*y = λ*2*y         y = - 1

x² + y²- 1 = 0         x²  + ( -1)² - 1 = 0      x = 0    

Point  P ( 0 ; -1 )  ; then at that point

f(x,y) = x² - y²             f(x,y) = 0 - ( -1)²     f(x,y) = - 1    minimum

b)  f( x, y ) =  3*x  + y            g ( x , y )  = x² +  y²  = 10

  δf(x,y)/ δx  = 3                   δg(x,y)/ δx  =  2*x

 δf(x,y)/ δy   = 1                   δg(x,y)/ δy  =   2*y

δf(x,y)/ δx  =   λ * δg(x,y)/ δx      ⇒   3 = 2* λ *x    (1)

δf(x,y)/ δy   =  λ *  δg(x,y)/ δy     ⇒    1 = 2*λ * y    (2)

                                                           x² +  y²  - 10 = 0  (3)

Solving that system

From ec (1)     λ  =  3/2*x      From ec (2)     λ  = 1/2*y

Then    (3/2*x )  = 1/2*y          3*y  =  x

x²  +  y²  = 10     ⇒   9y²  + y²  = 10      10*y² = 10

y² = 1       y  ± 1       and    

y  =  1      x  = 3       P  ( 3 , 1  )       y  = - 1    x = -3    Q  ( - 3 , - 1 )

Value of  f( x , y )  at   P   f (x,y) = 3*x + y      f (x,y) =    3*(3) +1  

f (x,y) = 10  maximum at  P ( 3 , 1 )

Value of  f( x , y )  at  Q     f (x,y) = 3*x + y    f (x,y) =  3*(- 3) + ( - 1 )

f (x,y) = - 10 minimum at Q ( - 3 , - 1 )

c)  f( x, y ) =  xy                       g ( x , y )  =  4*x² + y² - 8

δf(x,y)/ δx  = y                         δg(x,y)/ δx  = 8*x

δf(x,y)/ δy = x                          δg(x,y)/ δy  =  2*y

δf(x,y)/ δx  =  λ * δg(x,y)/ δx   ⇒   y  =  λ *8*x    (1)

δf(x,y)/ δy =   λ * δg(x,y)/ δy   ⇒   x  =  λ *2*y    (2)

                                                      4*x² + y² - 8 = 0   (3)

Solving the system

From ec (1)  λ = y/8*x    and From ec (2)      λ = x/2*y        Then    y/8*x  =  x/2*y

2*y² = 8*x²       y² = 4*x²    

Plugging that value in ec (3)

4*x²  +  4*x² - 8 = 0

8*x² = 8     x² = 1        x ± 1      And y² = 4*x²

Then:

for x  = 1      y² =  4     y = ± 2

for x  = -1     y² =  4     y = ± 2

Then we get     P (  1 ; 2 )   Q  ( 1 ; - 2)

                          R ( - 1 ; 2 )  T  ( -1 ; -2)

Plugging that values in f( x , y ) = xy

P (  1 ; 2 )  f( x , y ) = 2            R ( - 1 ; 2 )  f( x , y ) = - 2

Q ( 1 ; - 2)  f( x , y ) = -2           T ( -1 ; -2 )  f( x , y ) = 2

Max  f ( x , y ) = 2   for points    P and T

Min  f ( x , y ) =  -2   for points   Q and R

Answer:

the second option : ST and WX

Step-by-step explanation:

congruent means they would completely cover each other when oriented in the same direction and positioned at the same location.

after dying the two mirroring actions we get

VS correlates to ZW

ST correlates to WX

TU correlates to XY

UV correlates to ZY

Perimeter = namely the length of outside bordering,

well, this is a PENTAgon, or PENTA=5 or namely 5 sides, is regular so each side is the same length, so we have a polygon with 5 sides each measuring 40cm, well, its perimeter is just 40+40+40+40+40 = 200.

Answer:

9262

Step-by-step explanation:

just plug in 22 for n and calculate

Answer:

This problem has not solution

Step-by-step explanation:

lets the  integers be:

x

x+1

x+2

x+3

so:

x+(x+1)+(x+2)+(x+3)=2021

x+x+x+x+1+2+3=2021

4x+6=2021

4x=2021-6=2015

x=2015/4=503.75

x is not a integer

Answer:

[tex]\boxed {\boxed {\sf \$15.06 \ billion }}[/tex]

Step-by-step explanation:

We are given the function f(x). This is the value of diamond production for the year in billions.

[tex]f(x)= 0.21x+13.8[/tex]

We want to find the value of the diamond production in 2006.

We know that x is the number of years after 2000. The year 2006 was 6 years after 2000 because 2006 - 2000 = 6. Therefore, x (years after 2000) is equal to 6. We can substitute 6 in for x.

[tex]f(6)= 0.21(6)+ 13.8[/tex]

Solve according to PEMDAS (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction).

Multiply 0.21 and 6.

[tex]f(6)= 1.26+13.8[/tex]

Add 1.26 and 13.8

[tex]f(6)=15.06[/tex]

Remember the answer is in billions of dollars.

[tex]f(6)= \$ 15.06 \ billion[/tex]

Diamond production in 2006 is expected to be worth 15.06 billion dollars.