The magnitude and direction of the sum of vectors will be 4.15 m aligned in 50° in north west direction.
Both the vectors are making angle in a way that it will add up to 90° , hence a right angles triangle will be formed .
using Pythagoras theorem
[tex]H^{2} = P^{2} + B^{2}[/tex]
sum of vector = [tex]H^{2} = P^{2} + B^{2}[/tex]
H = [tex]\sqrt{P^{2} + B^{2} }[/tex]
= [tex]\sqrt{3.14^{2} + 2.71^{2} }[/tex]
= 4.15 m
let theta is the angle along the base vector 2
tan (theta ) = P/B = 3.14 / 2.71 = 1.16 °
theta = [tex]tan^{-1}[/tex] ( 1.16 )
≈ 50°
hence , The magnitude and direction of the sum of vectors will be 4.15 m aligned in 50° in north west direction.
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Two projectiles of mass and are fired at the same speed but in opposite directions from two launch sites separated by a distance . they both reach the same spot in their highest point and strike there. as a result of the impact they stick together and move as a single body afterwards. find the place they will land.
Two projectiles of mass and are fired at the same speed but in opposite directions from two launch sites separated by a distance, will land at a place x = D/2 [ 1+{ (m₁ - m₂) / m₁ + m₂)}
This is calculated using the conservation of linear momentum in the horizontal direction as ,
(vm₁vₓ₁ - m₂vₓ₁ ) ₓî = (m₁ + m₂) vₓ₂ ₓî
vₓ₂ = {(m₁ - m₂) / m₁ + m₂)} × vₓ₁
vₓ₂ = {(m₁ - m₂) / m₁ + m₂)} × v Cos Θ
t max = vₓ₁ / g
= v Sin Θ / g
x =(D / 2) + vₓ₂t max
= (D / 2) { {(m₁ - m₂) / m₁ + m₂)} × v² Sin Cos Θ / g } ------ (1)
now,
D = 2 vₓ₁vₓ₂ / g
D / 2 = v² Sin Cos Θ / g
From equation (1) we get,
x = D/2 [ 1+{ (m₁ - m₂) / m₁ + m₂)}
Hence , D/2 [ 1+{ (m₁ - m₂) / m₁ + m₂)} is the place they will land.
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describe the rotation curve of the milky way galaxy and contrast its shape with that of the solar sysstem
Compared to the orbital speeds of the planets in our solar system, the Milky Way Galaxy's rotation curve is far more flat and steady. While there is less mass as we get farther from the sun in our solar system.
The orbital speed of an astronomical body or object (such as a planet, moon, artificial satellite, spacecraft, or star) in gravitational bound systems is its speed relative to the most massive body's centre of mass, or the barycenter, if one body is significantly more massive than the other bodies in the system put together.
The phrase can be used to describe either the mean orbital speed (i.e., the speed throughout the course of an orbit) or its instantaneous speed at a specific location in the orbit. For objects in closed orbits, the maximum (instantaneous) speed occurs at periapsis (perigee, perihelion, etc.), whereas the smallest speed occurs at apoapsis (apogee, aphelion, etc.). When two-body systems are perfect, things An astronomical body or object (such as a planet, moon, man-made satellite, spacecraft, or star) moves through space at a certain speed called its orbital speed in gravitational bound systems.
When a system closely resembles a two-body system, the object's specific orbital energy, also known as "total energy," and its distance from the central body can be used to calculate the object's instantaneous orbital speed at a specific point in the orbit. Independent of position, the specific orbital energy is constant.
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Light passes straight through two vertical polarizers. The axes of the filters are aligned parallel to each other. How does the light that passes through the second filter compare to the light that passed through the first filter?.
The direction of the polarized light after passing the first and the second filter are the same, however the intensity of the light after passing the first and second polarizer are half and fourth of its original intensity, respectively.
Light polarization is a filter of electromagnetic waves such that it propagates into one transmission axis only.
When light passes through a polarizer, its intensity will decrease by half.
Suppose the intensity of unpolarized light is I₀, after passing the first polarizer, its intensity becomes:
I₁ = 1/2 . I₀
After passing the second polarizer, the intensity will further decrease by half, or:
I₂ = 1/2 . I₁
I₂ = 1/2 .1/2 . I₀ = 1/4. I₀
Since both polarizers are vertical filters, then the direction of the polarized light after passing the first and the second filter are the same.
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The change in velocity v of an object is zero over a short time interval t. Which of the following is true? Assume quantities are instantaneous unless stated otherwise.
Answer:
2. The object must have zero average acceleration over the interval.
Explanation:
Notes:
-Velocity can have zero change if it is either at rest or moving at a constant velocity. This also means there is zero acceleration (acceleration is any change in velocity).
-Velocity is also speed and direction, so if it changes direction (for example: moving backward or in a circle) it is not constant even if it has a constant speed. It also means the object is accelerating.
1: Nothing can be determined without additional information.
Incorrect, because it is solvable by the process of elimination.
2: The object must have zero average acceleration over the interval.
Correct, because zero acceleration equals zero change in velocity.
3: The object must be changing position.
Incorrect, because you don't know whether or not the object is accelerating.
4: The object must have zero average velocity over the interval.
Incorrect, because this implies it is at rest. To have zero change, it can be at rest OR moving at a constant velocity.
5: The object must have constant velocity over the interval.
Incorrect, because zero change in velocity can mean either be at rest OR moving at a constant velocity.
6: The object must begin and end at the same position.
Incorrect, because to begin and end at the same position implies that it was at rest or it changed direction while moving to end at the same position. (see Notes above for explanation)
7: The object must have constant acceleration over the interval.
Incorrect, because you can't have zero change in velocity if there is acceleration (Acceleration is any change in velocity).
8: The object must be at rest.
Incorrect, because to have zero change, it can be at rest OR moving at a constant velocity.
A coin has a mass of 7.0g. It is made of a metal alloy of density 5.6g/cm cube. Calculate the volume of the coin.
Answer:
1.25 cm³
Explanation:
Datam = 7.0 g
d = 5.6 g/cm³
v = ?
CalculationUsing,
[tex] d \: = \frac{m}{v} [/tex]
[tex]v = \frac{m}{d} [/tex]
[tex]v = \frac{7}{5.6} [/tex]
[tex]v = 1.25 \: c {m}^{3} [/tex]
if more massive stars have more hydrogen in their cores than less massive stars, why do they have shorter lifetimes?
Thermonuclear fusion occurs faster in massive stars so larger stars use up all their fuel in less time.
The more mass a star has the faster it will exhaust its fuel supply and the shorter its lifespan. The most massive stars could burn up and explode in a supernova after just a few million years of nuclear fusion. Massive stars are the largest, hottest, and brightest main-sequence stars and are blue, blue-white, or white in color.
Massive stars run out of hydrogen fuel very quickly and therefore have short lives. This is because the more massive the star the greater the fuel consumption. Even if a high-mass star has more fuel it uses it up very quickly so it does not live as long as a low-mass star. A main-sequence star's mass determines the fundamental properties of its luminosity surface temperature radius and lifetime.
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) a 45 kg box is pulled horizontally across the floor will a force directed horizontally to the left with a magnitude of 200.0n. (a) what is the acceleration of the box if the coefficient of kinetic friction is 0.10? (b) if the box starts from rest, how fast will it be moving at 3.0 s assuming the constant force is applied for the entire 3.0s?
The acceleration of the box is 3.4m/s² and if the box starts from rest at constant force for 3 seconds, then the speed of the box will be 10.2m/sec
The frictional force (f) = μN
where μ= coefficient of kinetic friction
N = Normal force = mg
The given value for μ = 0.10
∴ f = 0.10 × 45 × 10
f = 45 N
Hence F net = applied force - frictional force
F net = 200 - 45
F net = 155N
Thus, the acceleration of box (a) will be, F = ma
where m = mass of box =45kg
a = F /m
a = 155/45
a = 3.4 m/s²
a) Hence acceleration of the box pulled horizontally is 3.4m/s²
The speed of the box pulled, if initially the box was at rest and constant force is applied for 3 seconds,
v = u + at
v = 0 + 3.4 × 3
v = 10.2 m/s
b) Hence, the speed of the box at constant force is 10.2m/s
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In which scenario below does the ball have more gravitational potential energy when sitting at the top?
Why?
A. The ball
travels up
the stairs
to a
height of
3 ft.
B. The ball
travels straight
up the column
to a height of 3
ft.
In both the cases gravitational potential energy is same.
What is gravitational potential?Gravitational potential energy is energy an object possesses because of its position in a gravitational field. The most common use of gravitational potential energy is for an object near the surface of the Earth where the gravitational acceleration can be assumed to be constant at about 9.8 m/s².
Given two cases height of the top is 3 ft so the potential energy is same as potential energy is dependent on height of the ball.
In both the cases gravitational potential energy is same.
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tarzan, who weighs 688 n, swings from a cliff at the end of a vine 18 m long (fig. 8-38). from the top of the cliff to the bottom of the swing, he descends by 3.2 m. the vine will break if the force on it exceeds 950 n. (a) does the vine break? (b) if no, what is the greatest force on it during the swing? if yes, at what angle with the vertical does it break?
Tension is defined as the pulling force transmitted axially using a string, a rope, chain, or similar object, or by each end of a rod, truss member, or similar 3-D object; tension might also be expressed as the action-reaction pair of forces acting at each end of said elements.
Maximum tension:
T - mg = mv²/L
By energy conservation:
mgh = ¹/₂ mv²
v² = 2gh
Now the tension force in the vine at this position is given as:
T = mg + mv²/L
Now substitute the values in the above equation:
T = 688 N + m(2gh)/L
T = 688 + 2×3.2(688)/18
T = 932.6 N
As the force is less than the limit of 950 N so the vine didn't break.
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A championship weight lifter did 11,000 J of work on a set of barbells weighing 3680 N. How much gravitational potential energy did the barbells have at the maximum height of the lift? (show the steps you followed to solve the problem - ie. the formula, calculations, and final answer)
The GPE that the barbells have at max height is ,
3680.h j=11,000 units
where h= maximum height the barbells were lifted
work done by the championship lifter ,W = 11,000 units
weight of the barbells, N = 3680 N
The gravitational potential energy, P.E., the barbells had at their maximum height of lift is given as follows;
P.E. = m × g × h
Where;
m = The mass of the barbells;
g = The acceleration due to gravity = 9.8 m/s^2
h = The maximum height to which the barbells are lifted
m × g = The weight of the barbells = 3680 N
∴ P.E. = 3680 N × h = 3680·h J
we know the law of conservation of energy, according to this the work done by the weight lifter is equals to the maximum gravitational potential energy gained by the barbell is equal to energy at maximium height i.e P.E
therefore, GPE = 3680.h j = W = 11,000j is your answer.
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https://brainly.com/question/20561066Which of the following describes a way that neighborhoods help children build new relationships?
OA neighborhood holds a winter festival with activities for children and families.
O Families of the neighborhood walk around the block on differing weeknights.
O Lawn crews ensure that the neighborhood is properly maintained each week.
O Members of the community form a Neighborhood Watch team.
The neighborhood can help children build new relationships by holding a winter festival with activities for children and families.
In today's world, where everyone is quite busy in their own world, children have academic pressure and many more.
They tend to detach themselves from people, and hence many relationships ruin.
Building relationship helps the children grow and makes them more sociable. It boots their intelligence and makes them aware of the importance of having a relationship and building bonds with people.
The neighborhood holds a winter festival with activities for children and families is a great way to build new relationships.
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What was the force of gravity on the ball when it was at the highest point in its flight?
when an astronomer rambles on and on about the luminosity of a star she is studying, she is talking about:
When an astronomer rambles on and on about the luminosity of a star she is studying, she is talking about the amount of energy the star gives off each second.
Luminosity and apparent brightness are about brightness, but from a different point of view. The difference between luminosity and apparent brightness is that luminosity tells us exactly how bright a star really is while apparent brightness only tells us its brightness seen from Earth.
L / Lsun = ( d / dsun )² = b / bsun
L = Luminosity of a star
Lsun = Luminosity of sun
d = Distance of star
dsun = Distance of sun
b = Brightness of star
bsun = Brightness of sun
Therefore, when an astronomer rambles on and on about the luminosity of a star she is studying, she is talking about the amount of energy the star gives off each second.
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many astronomers believe that the massive object at the center of the milky way galaxy is a black hole. if so, what must the schwarzschild radius rs of this black hole be?
The Schwarzschild Radius Rs of this black hole is 5.69 x [tex]10^{10}[/tex] m
The Schwarzschild radius or gravitational radius is a physical parameter in the Schwarzschild solution of Einstein's field equations that corresponds to the radius defining the event horizon of a Schwarzschild black hole.
Let's assume that the ring shaped disk is circular and thus, to find the mass of the object at the center of the milky way, we can use the circular orbit equation;
v = √(GM/r)
where;
G is the gravitational constant and has a value of 6.67 x 10^(-11) Nm²/kg²
R is the radius of the orbit,
M is the mass of the larger object
v = velocity = 190km/s = 190000 m/s
Also
1 light year = 9.4605 x 10^(15) m
Thus,7.5 light years = 7.5 x 9.4605 x 10^(15) m
so, M = v²r/G
Putting all the values in the equation,
M = [190000² x 7.5 x 9.4605 x 10^(15)]/6.67 x 10^(-11)
M = 3.84 x 10^(37) kg
Now, mass of the sun generally has a value of 1.9891 x 10^(30) kg
Thus, value of mass of object in solar masses = 3.84 x 10^(37)/1.9891 x 10^(30) = 1.931 x 10^(7) solar masses
The formula for Schwarzschild radius is given as;
Rs = 2GM/c²
Where c is speed of light = 3 x 10^(8) m/s
Thus,
Rs = 2 x 6.67 x 10^(-11) x 3.84 x 10^(37)/(3 x 10^(8))² = 5.69 x [tex]10^{10}[/tex] m
The Schwarzschild radius Rs of this black hole is 5.69 x [tex]10^{10}[/tex] m
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what is the average flow rate in cm3/s of gasoline to the engine of a car traveling at 104 km/h if it averages 8.0 km/l? (you do not need to enter any units.)
The average flow rate is 3.611 cm^3/s
The speed V is = 104Km/h
The velocity of vehicle z is = 8km/l
Qavg = V/Z
= 104/8 =13
= 13 (1000)/1(3600)
Qavg = 3.611 cm^3/s
The physical parameters flow rate and velocity are linked yet very distinct. Consider a river's flow rate to help you understand the difference. The flow rate of the river increases as water velocity increases. However, the size of the river also affects the flow rate. The Amazon River in Brazil, for instance, carries much more water than a swift alpine stream. When A is the cross-sectional area and v is the average velocity, the flow rate Q and velocity v are precisely related. This equation seems to make sense. According to the relationship, the size of a river, pipe, or other body of water as well as the magnitude of the average velocity (hereinafter referred to as the speed) directly affect the flow rate.
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a moving hammer hits a nail and drives it into a wall. if the hammer hits the nail with four times the speed, how much deeper will the nail be driven? (assume that all of ke goes into work)
According to the work-energy theorem, twice the speed corresponds to 4 times the energy and 4 times the driving distance.
What is energy?There are different forms of energy on earth. The sun is considered the elementary form of energy on earth. In physics, energy is considered a quantitative property that can be transferred from an object to do work. Therefore, we can define energy as the force required for any physical activity. So we can define energy in simple words as follows Energy is the ability to do work According to the laws of conservation of energy, "energy can neither be created nor destroyed, it can only be changed from one form to another". The SI unit of energy is the joule.
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the vertical deflecting plates of a typical classroom oscilloscope are a pair of parallel square metal plates carrying equal but opposite charges. the potential difference between the plates is 25.0 v. typical dimensions are about 3.9 cm on a side, with a separation of about 5.4 mm. the plates are close enough that we can ignore fringing at the ends. part a under these conditions, how much charge is on each plate?
If we keep oscilloscope plates close with potential difference 25 V , the Charge on each plate will be 4.68 *10^-11 C.
How to calculate charge ?Charged material experiences a force when it is exposed to an electromagnetic field due to the physical property of electric charge.The number of charges (electrons) that go from a higher potential to a lower potential is referred to as quantity of charge. It refers to the total amount of electricity flowing via a conductor.The capacitance of a parallel plate capacitor is given by:
C = ∈₀A / d
where
∈₀ = 8.85 *10^-12 F/m is the vacuum permittivity
A is the area of each plate
d is their separation
For the capacitor in the problem:
A= 0.033m² = 0.0011m²
d = 5.2 mm = 0.0052 m
Substituting,
C = (8.85 *10^-12) (0.0011m)/ 0.0052 = 1.87 *10^-12 F
The capacity is related to the charge on the plate by:
Q=CV
where
V = 25.0 V is the potential difference between the plates
C = 1.87 *10^-12 F
Substituting,
Q = (25.0) (1.87 *10^-12) = 4.68 *10^-11 C
Charge on each plate = 4.68 *10^-11 C
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A person standing on a hill throws a ball horizontally with a velocity of 12m / s The ball lands 10.1 m away from the hill. How tall is the hill? Assume no air resistance
A.3.5
B.6.9
C.0.84
D.0.42
The height of a hill from which the person throws a ball horizontally with a velocity of 12 m/s and the ball lands 10.1 m away from the hill is 3.47 m.
What is the height of a hill from which the person throws a ball horizontally with a velocity of 12 m/s and the ball lands 10.1 m away from the hill?The height of a hill from which the person throws a ball horizontally with a velocity of 12 m/s and the ball lands 10.1 m away from the hill is calculated as follows;
The ball was projected horizontally from the top of a hill, therefore, there is no vertical component of the velocity of projection and the object is considered to be undergoing free fall under gravity from a height, h.
The height from which an object falls freely under gravity is calculated with the formula below:
H = gt²/2
where g is the acceleration due to gravity = 9.81 m/s²
t is time.
the time taken for the fall = horizontal distance / velocity
t = 10.1 / 12
t = 0.841 s
Therefore;
h = 9.81 * (0.841)² / 2
h = 3.47 m
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you and a friend are on a swing set and her swing is slightly longer than yours. if you both start swinging at the same time, from the same height, where will she be after you have completed one complete swing back and forth?
She might be barely lower than you however shifting upward in the direction of you.
Oscillation is the repetitive or periodic variation, generally in time, of a few measures approximately a critical price or among or greater distinct states. familiar examples of oscillation consist of a swinging pendulum and alternating modern-day.
A pendulum is a weight suspended from a pivot so that it can swing freely. whilst a pendulum is displaced sideways from its resting, equilibrium position, it's miles issue to a restoring force due to gravity so one can accelerate it returned toward the equilibrium function.
Oscillation is defined as the method of repeating versions of any quantity or degree about its equilibrium price in time. Oscillation can also be defined as a periodic variant of a rely on among values or approximately its crucial price.
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A car moves at a velocity of 8.5m/s. It then accelerates at a constant rage of 2.5m/s/s for a total time of 5 second. How fast is the car moving at the end of the 5 second
The car would be moving with a velocity of 21 m/s at the end of the five seconds.
We know that the first equation of motion is ⇒ v = u + at (i)
Here, the car moves with an initial velocity, u = 8.5 m/s (ii)
The car accelerates at a constant rate, a = 2.5 m/s² (iii)
The total time during this process, t = 5 seconds (iv)
Putting the values of the initial velocity, acceleration, and time (ii, iii, and iv) in equation (i), we get ⇒ v = 8.5 + (2.5)(5)
v = 21 m/s
Therefore, the car moves with a final velocity of 21 m/s at the end of the five seconds.
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Which letter represents the normal force acting on the box?
A
B
C
D
What is the answer
Answer: (C)
Explanation: (B) is the weight of the box acting downwards
(A) is the frictional force acting on the box because of moving forward against the plane
(D) is the force that moves the box forward
( C) is perpendicular to the box which means it is at 90 degrees with the box. Normal usually means at 90 degrees
A student conducts an experiment to check how high a basketball can bounce when different volumes of air are filled inside. Which of these steps will most likely help the student get reliable results?(1 point)
Changing the ball for each trial
Doing only one trial with the ball
Doing at least three trials with the ball
Using a different watch to time each trial
How does a white dwarf differ from a neutron star? how does each form? what keeps each from collapsing under its own weight?.
An electron degenerate object is a white dwarf, whereas a neutron star is a neutron degenerate object. A white dwarf is less compact and has a larger radius than a neutron star.
How is a white dwarf transformed into a neutron star?A white dwarf would collapse into a denser entity known as a neutron star if it reached the Chandrasekhar limit and nuclear reactions were to stop. This would happen if nuclear reactions continued to occur.
How is a white dwarf prevented from exploding into a neutron star?White dwarf stars are prevented from collapsing by the fact that electrons are fermions, while neutron stars are prevented from collapsing by the fact that electrons are fermions.
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A 5 kg block is pulled across the ground to the right by a tension force of 40 N with a frictional force of 8 N opposing the motion. What is the acceleration of the object?
The Acceleration of the object = 6.4 m/s²
Mass of block (m) = 5 kg
Action force on block, (F₁) = 40 N
Frictional force opposing the motion (F₂) = 8 N
Acceleration of the object (a) = ?
⇒ Net force = Action force on block - Opposing friction force
⇒ F = F₁ - F₂
⇒ F = 40 - 8
⇒ F = 32 N
Net force of the block (F) = 32 N
Mass of block (m) = 5 kg
F is the Force in N.
m is the Mass in kg.
a is the Acceleration in m/s².
F = ma
⇛ a = F/m
⇛ a = 32/5
⇛ a = 6.4 m/s²
Please someone help!! I don’t know how to figure this out!
Answer:
relax
Explanation:
your answer is right there in front of you force = weight
area of feet = area
while your pressure = force per unit area i.e
force/area = 600/0.03
= 2 × 10⁵
joey is riding in an elevator which is accelerating upwards at 2.0 m/s2. The elevator weighs 300.0 kg, and Joey weighs 60.0 kg. What is the tension in the cable that pulls the elevator upwards?
The tension in the cable is 4248 N.
what is tension?The force transmitted through a rope, string, or wire when two opposing forces pull on it is known as tension. The tension force pulls energy equally on the bodies at the ends and is applied along the entire length of the wire.
Given parameters:
Weighs of the elevator, M = 300.0 kg.
weighs of Joey, m = 60.0 kg.
Upward acceleration of the elevator, a = 2.0 m/s².
And, acceleration due to gravity, g = 9.8 m/s².
So, net tension in the cable, T = (M + m)g + (M + m)a
= ( 300.0 + 60.0 ) × 9.8 N + (300.0 +60.0 )× 2.0 N
= 4248 N.
Hence, the tension in the cable that pulls the elevator upwards is 4248 N.
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in a double-slit experiment, the slit separation d is 2.00 times the slit width w. how many bright interference fringes are in the central diffraction envelope
The number of bright interference fringes in the central diffraction envelope is 3.
To determine the number of bright interference, we need to understand the equation of first minima in the diffraction pattern, and the equation of angular locations of the double slit interference pattern.
For the equation of first minima in the diffraction pattern is:
[tex]W[/tex]·[tex]Sin[/tex]θ = [tex]m_{1}[/tex]·λ
For the equation of angular locations of the double slit interference pattern is:
[tex]d[/tex]·[tex]Sin[/tex]θ = [tex]m_{2}[/tex]·λ..... (1)
Here, W is single slit width while d is slit separation
Next, we need to determine the number of bright interference fringes in the central diffraction envelope.
For the first minima, [tex]m_{1} = 1[/tex], then rewrite the equation (1) as follows.
=[tex]a[/tex]·[tex]Sin[/tex]θ = [tex]m_{1}[/tex]·λ
=[tex]a[/tex]·[tex]Sin[/tex]θ = [tex]1[/tex]·λ
=[tex]a[/tex]·[tex]Sin[/tex]θ = λ..... (2)
Then, from the equations (1) and (2)
[tex]=m_{2}=\frac{d}{w} \\=m_{2}=\frac{2w}{w}\\=m_{2}=2[/tex]
Therefore, there are 3 bright fingers, 1 at the centre and 2 in each side.
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what is the heaviest the book he can hold vertically before it slips out of his fingers? the coefficient of static friction between his fingers and the book cover is 0.88
Mass of the heaviest book is 0.733 kg.
Heaviest book has weight
= (6 + 6) * 0.6 N
= 7.2 N
If m = mass of the heaviest book in kg
m = 7.2/9.81 kg
= 0.733 kg.
Children often bring a well-established "life-view" of friction with them because of their experiences with slippery surfaces like frozen ponds (low friction) and "gripping" surfaces like deep pile carpets (high friction) and the effects they have on movement. This way of existence needs to be expanded and understood in the perspective of science.
The force that modifies movement as a result of surface/surface interaction is known scientifically as friction (all changes of movement require the action of a force). When using diagrams to portray forces in action, the direction of the frictional force should be depicted as being opposed to that of the movement.
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simple telescope could be made with the two converging lenses from parts 2 and 3 of this experiment. using your experimentally determined focal lengths of these two lenses what would be the magnification of this telescope? 7
The magnification of this telescope is 12.
Solution:
F = 1200 mm = 120 cm
f = 32mm, 25mm, 14 mm, 10mm
M = F/f 120/ = 3.75
M = 120/25 = 4.8
M = 120/14 = 8.57
M = 120/10 = 12.
Magnification ratio means that the ratio of subject size on the sensor plane is greater than or equal to the actual size of the subject. This allows macro lenses to capture very sharp close-ups of insects, etc. The magnification produced by a lens is equal to the ratio of image distance to object distance. Total magnification In a compound microscope the total magnification is the product of the objective and ocular lenses.
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true or false? - A ball is moving upwards and to the left. A net force that points upwards and to the left must be acting on the ball.
Answer:
false is the answer . in my point of view
