Find the equation of the line that passes through point (6, 1) with the x-intercept of 2.

[tex]30 \: percent \: alcohol \: in \: 260 \: ml \\ alcohol = 0.3 \times 26 0= 78 \: ml[/tex]

[tex]c( \gamma ) = \frac{78 + 0.95\gamma }{260 + \gamma } \times 100[/tex]

[tex]c( \gamma ) = 75[/tex]

[tex] \frac{78 + 0.95\gamma }{260 + \gamma } = 0.75[/tex]

[tex]78 + 0.95\gamma = 0.75 \gamma + 195 \\ 0.2 \gamma = 117 \\ \gamma = 585[/tex]

[tex]we \: need \: 585 \: ml \: of \: 95% \: alcohol[/tex]

Answer:

You will need 585 mL of the 95% solution.

Step-by-step explanation:

Answer:

y = -0.6x^2 + 5x + 6

Step-by-step explanation:

First, find the equation of a linear line that passes through the points (0,6) and (3, 15.6) in the slope intercept form, y = mx + b. We know that the line has a y-intercept of 6, so b = 6. Substitute 3 for x, 15.6 for y, and 6 for b to find m.

y = mx + b

15.6 = 3m + 6

9.6 = 3m

m = 3.2

y = 3.2x + 6

y = a(x - 0)(x - 3) + 3.2x + 6

y = a(x)(x - 3) + 3.2x + 6

Finally, substitute 10 for x and -4 for y in the equation above to find a.

-4 = a(10)(10 - 3) + 3.2*10 + 6

-4 = a(10)(7) + 32 + 6

-4 = 70a + 38

-42 = 70a

a = -0.6

Simplify to write in standard form.

y = -0.6(x)(x - 3) + 3.2x + 6

y = -0.6x^2 + 5x + 6

The answers to these questions are:

a. In the question we have the existence of the mean, the mode and the median hence the answer to this question is none.

b. if the measurement 14 is replaced by 2, the data that it is going to have the most effect on is going to be the mean. It would reduce the mean.

c. If the largest measurement is removed, it is going to have the most effects on the mean and the median.

d. If the data is skewed then the mean of the data set is going to be greater.

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Answer:

[tex]x=1+\sqrt[n]{y}[/tex]

Step-by-step explanation:

Since: [tex](x-1)*(x-1)*(x-1)=y[/tex]

that would imply: [tex](x-1)=\sqrt[3]{y}[/tex]

This is a bit more clear, if you write the equation as:

[tex](x-1)^3=y[/tex]

and then take the cube root of both sides

[tex]\sqrt[3]{(x-1)^3}=\sqrt[3]{y}[/tex]

Which simplifies to

[tex]x-1=\sqrt[3]{y}[/tex]

Now add 1 to both sides, and you get the equation:

[tex]x=1+\sqrt[n]{y}[/tex]

I'm tentatively changing my answer to say this kind of relies on practical knowledge of how stores tend to operate. If 20 coupons are given out, the store has sold all 500 shirts, arguably at a loss to the retailer. They have to have more shirts in stock to be sold at full price because, well, that's how they make money. It's more likely that such a store would carry more than just 500 shirts at the start of each day, so A is (probably) wrong.

Answer:

c,d

Step-by-step explanation:

Answer:

x=18

Step-by-step explanation:

[tex]\frac{4}{12} =\frac{6}{x} \\[/tex]

[tex]\frac{4}{12}[/tex] ÷ [tex]\frac{2}{2}[/tex] = [tex]\frac{2}{6}[/tex] = [tex]\frac{6}{x}[/tex]

[tex]\frac{2}{6} = \frac{6}{x}[/tex]  

2×3 =6

6×3=18

x=18

Using the relation between velocity, distance and time, it is found that the rate of the current is of 3.33 mph.

Velocity is distance divided by time, hence:

v = d/t

A small motorboat travels 12mph in still water. With the current, upstream, 46 miles are traveled in t hours, hence:

12 + r = 46/t

r = 46/t - 12

Downstream, the time is of t + 2 hours, hence:

12 - r = 46/(t + 2)

r = 12 - 46/(t + 2)

Hence, equaling the values for r:

46/t - 12 = 12 - 46/(t + 2)

46/t + 46/(t + 2) = 24

[tex]\frac{46t + 92 + 46t}{t(t + 2)} = 24[/tex]

92t + 92 = 24t² + 48t

24t² - 44t - 92 = 0

Using a quadratic equation calculator, the solution is t = 3. Hence the rate is found as follows:

r = 46/t - 12 = 46/3 - 12 = 3.33 mph.

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(8) The algebraic expression representing the given phrase is 22x ≥ 350, where x is the number of units sold by Ms. Reed.

(9) The minimum number of shares needed to achieve the required profit is 1223, using the algebraic expression 2.25x ≥ 2750, where x is the number of shares.

(10) The number of books needed to be sold for the novelist to make a profit of $10,000 is 4350, using the algebraic expression 5000 + 1.1495x ≥ 10000, where x is the number of books sold,

(8) Weekly target for Ms. Reed is $350.

The cost of each unit she sells is $22.

We assume the number of units she sold to be x.

Thus, the total sales done by Ms. Reed is $22x.

For her to remain employed, her total sales should exceed her target, which can be shown as an algebraic expression: 22x ≥ 350.

Thus, the algebraic expression representing the given phrase is 22x ≥ 350, where x is the number of units sold by Ms. Reed.

(9) Profit on each share is $2.

The additional profit is $0.25.

Thus, the total profit on each share is $2 + $0.25 = $2.25.

The required profit by the customer is $2750.

We assume the number of shares needed to be x.

Thus, the total profit made by the customer is $2.25x.

For the customer to make the required profit, we can write the algebraic expression, 2.25x ≥ 2750.

To solve this, we divide both sides by 2.25 to get:

2.25x/2.25 ≥ 2750/2.25,

or, x ≥ 1222.22.

Thus, the minimum number of shares needed to achieve the required profit is 1223.

(10) Default contract of Book Maker publisher is $5000 and 5% royalty.

The cost of the book, for which the novelist has got the contract is $22.99.

We assume the number of books sold to be x.

The royalty share on each book given to the novelist is 5% of $22.99, or, $ 5/100 * 2299/100 = $ 11495/10000 = $1.1495.

Thus, the royalty received on x number of books = $1.1495*x = $1.1495x.

Thus, the total profit to the novelist = (5000 + 1.1495x).

Since the novelist wants to make a minimum profit of $10000, we can show it as the algebraic expression:

5000 + 1.1495x ≥ 10000.

To solve this, we go as follows:

5000 + 1.1495 ≥ 10000,

or, 1.1495x ≥ 10000 - 5000,

or, 1.1495x ≥ 5000,

or, x ≥ 5000/1.1495,

or, x ≥ 4349.717.

Approximating, we get x ≥ 4350.

Thus, 4350 books need to be sold to achieve the wanted profit.

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From the given functions, of the cost, c(x) = 300 + 260•x, and revenue, r(x) = 300•x - x², we have;

First part;

The values of x to break-even are;

x = 30, or x = 10

Second part;

The profit function, P(x) is presented as follows;

P(x) = x•(40 - x) - 300

Third part;

The cost is c(x) = 300 + 260•x

Revenue is r(x) = 300•x - x²

First part;

At the break even point, we have;

Which gives;

300 + 260•x = 300•x - x²

x² + 260•x - 300•x + 300 = 0

Factoring the above quadratic equation gives;

x² - 40•x + 300 = (x - 30)•(x - 10) = 0

At the break even point, x = 30, or x = 10

The values of x at the break even point are;

Second part;

Profit = Revenue - Cost

The profit function, P(x), is therefore;

P(x) = r(x) - c(x)

Which gives;

P(x) = (300•x - x²) - (300 + 260•x)

P(x) = 300•x - x² - 300 - 260•x

P(x) = 300•x - 260•x - x² - 300

P(x) = 40•x - x² - 300

The profit function is therefore;

Third part;

When 10 more units are sold than the break even point, we have;

x = 30 + 10 = 40 or x = 10 + 10 = 20

The profit at x = 40 or x = 20 are;

P(40) = 40•(40 - 40) - 300 = -300

When the number of units sold, x = 40, the profit is, P(40) = -($300) unexpected loss

At x = 20, we have;

P(20) = 20•(40 - 20) - 300 = 100

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Answer:

5250%

Also, if you could label this brainliest that would be a great help!

Thanks xx

-Dante

Step-by-step explanation:

1) Formulate

2) Calculate

3) Transform expression

4) Calculate

5) Invert and multiply

6) Simplify

7) Calculate

8) Calculate

9) Rewrite the number

10) Calculate

11) Calculate

12) Convert the number

You’re done!

Answer:

15.2m2

Step-by-step explanation:

hope it helps.good day

The length of the apothem of the regular pentagon shown is 5.2 meters

Represent the central angle of the regular pentagon using x

The value of the central angle of the regular pentagon is then calculated as:

x = 360/n

Where n represents the number of sides

i.e n = 5

So, we have:

x = 360/5

Evaluate the quotient

x = 72

Represents the apothem with y.

The apothem is then calculated as:

tan(x/2) = (Side length/2)/Apothem

This gives

tan(72/2) = (7.6/2)/y

Evaluate the quotient

tan(36) =3.8/y

Multiply both sides by y

y tan(36) = 3.8

Divide both sides by tan(36)

y = 3.8/tan(36)

Evaluate the quotient

y = 5.2

Hence, the length of the apothem of the regular pentagon shown is 5.2 meters

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Answer:

n=11

Step-by-step explanation:

(n+4)/10 = (n-8)/2

We can solve using cross products

(n+4) * 2 = 10 * ( n-8)

Distribute

2n+8 = 10n -80

Subtract 2n from each side

2n+8-2n = 10n-80-2n

8 = 8n-80

Add 80 to each side

8+80= 8n-80+80

88 = 8n

Divide each side by 8

88/8 = 8n/8

11 = n

Answer: n=11

Step-by-step explanation:

(n+4)/10 = (n-8)/2

multiply both sides by 10

n+4 = (n-8)/2*10

cancel

n+4=(n-8)*5

n+4=5(n-8)

multiply

n+4=5n-40

subtract both sides by 5n

n-5n+4=-40

subtract both sides by 4

n-5n=-40-4

subtract the like terms

-4n=-44

cancel the negatives

4n=44

divide each side by 4

n=11

Answer:

0.524

Step-by-step explanation:

That is the answer not really sure tho

The required probabilities are:

A) P(D or 5) = 4/13

B) P(H and J) = 1/13

C) P(J or 8) = 2/13

D) P(H or S) = 1/2

E) P(R and F) = 3/26

F) P(R or Q) = 7/13

The ratio of favorable outcomes to the total outcomes of an event is said to be its probability.

P(E) = n(E)/n(S)

It is given that a single card is drawn at random from a standard deck of 52 cards.

So, the sample space consists of 52 cards in total

From those,

4 suits: Hearts, Clubs, Spades, Diamonds

Each of the suit has 13 cards: { Ace, 2,3,4,5,6,7,8,9,10, Jack, Queen, King}

There are 26 Red cards and 26 Black cards.

A) The probability of drawing a diamond or a 5:

P(D or 5) = P(D) + P(5) - P(D and 5)

               = 13/52 + 4/52 - 1/52

               = 16/52 = 4/13

B) The probability of drawing a heart and a jack:

P(H and J) = P(H) × P(J) (Since they are independent events)

                 = 13/52 × 4/13

                 = 1/13

C) The probability of drawing a jack or 8:

P(J or 8) = P(J) + P(8) - P(J and 8)

              = 4/52 + 4/52 - 0

              = 2/13

D) The probability of drawing a heart or a spade:

P(H or S) = P(H) + P(S) - P(H and S)

               = 13/52 + 13/52 - 0

               = 26/52 = 1/2

E) The probability of drawing a red and face card:

P(R and F) = P(R) × P(F) (Since they are independent)

                 = 26/52 × 12/52

                 = 1/2 × 3/13

                 = 3/26

(There are three face cards- jack, king, and queen: each of 4)

F) The probability of drawing a red card or a queen:

P(R or Q) = P(R) + P(Q) -P(R and Q)

               = 26/52 + 4/52 - 2/52

               = 28/52 = 7/13

Thus, the required probabilities are calculated.

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(i) The expanded form of (1 / 2 - 2 · x)⁵ in ascending form is 1 / 32 - (5 / 8) · x + 5 · x² - 20 · x³ + 40 · x⁴ - 32 · x⁵.

(ii) The coefficient of x³ from (1 + a · x + 3 · x²) · (1 / 2 - 2 · x)⁵ is - 265 / 8.

In this problem we must apply the concept of Pascal's triangle to expand the power of a binomial of the form (x + y)ⁿ and further algebra properties.

(i) First, we proceed to expand the power binomial (1 / 2 - 2 · x)⁵ in ascending order:

(1 / 2 - 2 · x)⁵ = (1 / 2)⁵ + 5 · (1 / 2)⁴ · (- 2 · x) + 10 · (1 / 2)³ · (- 2 · x)² + 10 · (1 / 2)² · (- 2 · x)³ + 5 · (1 / 2) · (- 2 · x)⁴ + (- 2 · x)⁵

( 1 / 2 - 2 · x)⁵ = 1 / 32 - (5 / 8) · x + 5 · x² - 20 · x³ + 40 · x⁴ - 32 · x⁵

(ii) Second, we proceed to expand the following product of polynomials by algebra properties:

(1 + a · x + 3 · x²) · (1 / 2 - 2 · x)⁵ = (1 + a · x + 3 · x²) · [1 / 32 - (5 / 8) · x + 5 · x² - 20 · x³ + 40 · x⁴ - 32 · x⁵]

(1 + a · x + 3 · x²) · (1 / 2 - 2 · x)⁵ = 1 / 32 + (a / 32 - 5 / 8) · x + (- 5 · a / 8 + 163 / 32) · x² + (- 175 / 8 + 5 · a) · x³ + (65 - 20 · a) · x⁴ + (- 92 + 40 · a) · x⁵ + (120 - 32 · a) · x⁶ - 96 · x⁷

In accordance with the statement, we find that:

- 5 · a / 8 + 163 / 32 = 13 / 2

- 5 · a / 8 = 45 / 32

a = - 9 / 4

Thus, the coefficient of x³ is:

C = - 175 / 8 + 5 · (- 9 / 4)

C = - 265 / 8

The coefficient of x³ from (1 + a · x + 3 · x²) · (1 / 2 - 2 · x)⁵ is - 265 / 8.

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Using translation concepts, the equation for function g is given by:

g(x) = 7x/3 + 1.

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.

Supposing that we have a function f(x), a horizontal compression by a factor of a is equivalent to finding f(ax).

In this problem, the function is:

f(x) = 7x + 1.

For the horizontal compression by a factor of 1/3, we have that:

g(x) = f(1/3x) = 7x/3 + 1.

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a. Central angle: Angle BAC

b. Major arc: Arc BEC

c. Minor arc: Arc BC

d. m(BEC) = 260°

e. m(BC) = 100°

A major arc can be defined as an arc that has a measure that is greater than a semicircle (half a circle) or greater than 180 degrees.

A minor arc can be defined as an arc that has a measure that is less than a semicircle (half a circle) or less than 180 degrees.

An angle whose vertex is at the center of a circle and has two radii of as its  sides is called a central angle of a circle.

a. Central angle in the image given is: Angle BAC

b. Major arc of the circle is: Arc BEC

c. Arc BC is a minor arc.

d. m(BEC) = 360 - 100 [based on the central angle theorem]

m(BEC) = 260°

e. angle BAC = 100°

m(BC) = angle BAC [based on the central angle theorem]

m(BC) = 100°

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The number of tickets sold are:

From the question, we have the following parameters:

Represent the children tickets with x and adults ticket with y.

So, we have the following system of equations

x + y = 63

6x + 8y = 444

Express the equations as a matrix

x      y

1       1       63

6      8       444

Apply the following transformation

R2 = R2 - 6R1

This gives

x      y

1       1       63

0      2       66

Apply the following transformation

R2 = 1/2R2

x      y

1       1       63

0      1       33

From the above matrix, we have the following system of equations

x + y = 63

y = 33

Substitute y = 33 in x + y = 63

x + 33 = 63

Subtract 33 from both sides of the above equation

x = 30

Hence, 30 children tickets were sold and 33 adult tickets were sold

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Answer:

[tex]\textsf{Option 3}: \quad -10 x^2y^2-16x^{-2}y^2+8x^{-1}y^3[/tex]

Step-by-step explanation:

Given expression:

[tex]-2x^{-3}y(5yx^5+8xy-4y^2x^2)[/tex]

Distribute:

[tex]\implies -2x^{-3}y(5yx^5) -2x^{-3}y(8xy)-2x^{-3}y(-4y^2x^2)[/tex]

Multiply the constants and collect like terms:

[tex]\implies -10 x^{-3}x^5yy-16x^{-3}xyy+8x^{-3}x^2yy^2[/tex]

Remember that a = a¹.

[tex]\textsf{Apply exponent rule} \quad a^b \cdot a^c=a^{b+c}:[/tex]

[tex]\implies -10 x^{(-3+5)}y^{(1+1)}-16x^{(-3+1)}y^{(1+1)}+8x^{(-3+2)}y^{(1+2)}[/tex]

[tex]\implies -10 x^2y^2-16x^{-2}y^2+8x^{-1}y^3[/tex]

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Answer:

8.16 Kg

Step-by-step explanation:

average is calculated as

average = [tex]\frac{sum}{count}[/tex]

here average = 0.17 and count = 48 , then

0.17 = [tex]\frac{sum}{48}[/tex] ( multiply both sides by 48 )

8.16 = sum

that is total mass = 8.16 Kg

Answer:

120°

Step-by-step explanation:

The angle just below 'x' is 40°    (alternate angles/parallel lines)

40 + x + 20 = 180  ( straight line)

x = 120°

Answer:

[tex]\frac{x^2}{784}+\frac{y^2}{400}=1[/tex]

Step-by-step explanation:

Horizontal Major Axis:

   [tex]\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}[/tex]

Vertical Major Axis:

   [tex]\frac{(y-k)^2}{a^2}+\frac{(x-h)^2}{b^2}+[/tex]

So these two expressions are essentially the same with the only difference being the location of "a" and "b". The length of the major axis will be "2a" and the length of the minor axis will be "2b". The way I remember this is because when you have the horizontal major axis the "a" value is in the denominator of the (x-h) and I think of "x" as a horizontal value, since it moves a point horizontally. When you have a vertical major axis the "a" value is in the denominator of (y-k) and I think of "x" as a vertical value, since it moves a point vertically.

So just by looking at the graph, you can easily determine that the eclipse has a horizontal major axis. This can be further proven, since the distance from the origin on the right side is 28, and the distance from the the top to the origin is only 20.

So you could set up an equation to solve for a, since 2a = length of major axis, but since we're given the two points, the "a" value is really just the length from the origin to the right/left side, and combining these together you get the value of 2a/major axis, but you don't have to do that. So by looking at the graph you'll see the distance from the origin to the right side is 28. This means "a=28"

You can do the same thing here for the "b" value, and since the top is 20 units away from the origin, "b = 20"

So now let's set up the equation:
[tex]\frac{x^2}{28^2} + \frac{y^2}{20^2}=1[/tex]

Square the values in the denominator

[tex]\frac{x^2}{784}+\frac{y^2}{400}=1[/tex]

Splitting up [0, 3] into [tex]n[/tex] equally-spaced subintervals of length [tex]\Delta x=\frac{3-0}n = \frac3n[/tex] gives the partition

[tex]\left[0, \dfrac3n\right] \cup \left[\dfrac3n, \dfrac6n\right] \cup \left[\dfrac6n, \dfrac9n\right] \cup \cdots \cup \left[\dfrac{3(n-1)}n, 3\right][/tex]

where the right endpoint of the [tex]i[/tex]-th subinterval is given by the sequence

[tex]r_i = \dfrac{3i}n[/tex]

for [tex]i\in\{1,2,3,\ldots,n\}[/tex].

Then the definite integral is given by the infinite Riemann sum

[tex]\displaystyle \int_0^3 2x^2 \, dx = \lim_{n\to\infty} \sum_{i=1}^n 2{r_i}^2 \Delta x \\\\ ~~~~~~~~ = \lim_{n\to\infty} \frac6n \sum_{i=1}^n \left(\frac{3i}n\right)^2 \\\\ ~~~~~~~~ = \lim_{n\to\infty} \frac{54}{n^3} \sum_{i=1}^n i^2 \\\\ ~~~~~~~~ = \lim_{n\to\infty} \frac{54}{n^3}\cdot\frac{n(n+1)(2n+1)}6 = \boxed{18}[/tex]

Using translation concepts, the trigonometric graph is given by:

y = sin(x) + 1 = 1sin(1x) + 1.

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.

The parent function given in this problem is:

y = sin(x).

The dashed line is a shift up one unit of the parent function, hence the definition is:

y = sin(x) + 1 = 1sin(1x) + 1.

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Answer:

The third one

Step-by-step explanation:

It cannot be the first 2 as the corners wouldn't line up. It cannot be the last one as B and R are not the same angles