The gradient of line A is 8, and the gradient of line B is -4.
We have,
To find the gradient of a line, we use the formula:
Gradient = (change in y) / (change in x)
For line A:
Between (1, 2) and (1.5, 6), the change in y is 6 - 2 = 4, and the change in x is 1.5 - 1 = 0.5.
So the gradient between these two points is 4 / 0.5 = 8.
Between (1.5, 6) and (2, 10), the change in y is 10 - 6 = 4, and the change in x is 2 - 1.5 = 0.5.
So the gradient between these two points is 4 / 0.5 = 8.
Since the gradient is constant for a straight line, we can conclude that the gradient of line A is also 8.
For line B:
Between (2, 0) and (1, 4), the change in y is 4 - 0 = 4, and the change in x is 1 - 2 = -1. So the gradient between these two points is 4 / (-1) = -4.
Between (1, 4) and (0, 8), the change in y is 8 - 4 = 4, and the change in x is 0 - 1 = -1. So the gradient between these two points is 4 / (-1) = -4.
Again, since the gradient is constant for a straight line, we can conclude that the gradient of line B is also -4.
Therefore,
The gradient of line A is 8, and the gradient of line B is -4.
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Golf Tournament In a golf tournament, the top 6 men's scores are 65, 68, 70, 72, 73, 75. The top women's scores are 69, 71, 73, 74, 77, 80. Compare the spread of the data for the two sets of scores using (a) the range and (b) the mean absolute deviation.
Answer:
Range: Men: 10, Women: 11
MAD: Men: 2.833333 (17/6), Women: 3
Step-by-step explanation:
The range of the men's scores is 75-65 (highest-lowest), which is 10.
The range of the woman's scores is 80-69, which is 11.
The MAD is the mean of the absolute difference between the terms and the mean, which is very painful to do, but in the sake of the problem, I will be doing.
Men's MAD:
The mean is [tex]\frac{65+68+70+72+73+75}{6}[/tex], which is 70.5.
Sigh.
Now, we find the difference of each term to the mean.
[tex]70.5-65= 5.5[/tex]
[tex]70.5-68=2.5[/tex]
[tex]70.5 - 70 = 0.5[/tex]
[tex]72-70.5=1.5[/tex]
[tex]73-70.5=2.5[/tex]
[tex]75-70.5=4.5[/tex]
wow. Now, we find the mean of these numbers.
[tex]\frac{5.5 + 2.5 + 0.5 + 1.5 + 2.5 + 4.5}{6}[/tex]= 17/6=2.8333333333 This is the MAD.
For the Women's, I'll speed over it.
The mean is 74.
The MAD is 3.
If events E and F are disjoint (mutually exclusive) and the events F and G are disjoint, must the events E and G necessarily be disjoint? Give an example to illustrate your opinion. Choose the correct answer below.A.Yes, events E and G must be disjoint. For example, E = {0,1,2}, F = {3,4,5}, and G= {6,7,8} show that E and F are disjoint events, F and G are disjoint events, and E and G are also disjoint events.B.No, events E and G are not necessarily disjoint. For example, E = {0,1,2}, F = {3,4,5}, and G = {2,6,7} show that E and F are disjoint events, F and G are disjoint events, and E and G are events that are not disjoint.C.Yes, events E and G must be disjoint. For example, E = {0,1,2}, F = {3,4,5}, and G = {2,6,7} show that E and F are disjoint events, F and G are disjoint events, and E and G are also disjoint events.D.No, events E and G are not necessarily disjoint. For example, E = {0,1,2}, F = {3,4,5}, and G = {6,7,8} show that E and F are disjoint events, F and G are disjoint events, and E and G are events that are not disjoint.
The correct answer is D. No, events E and G are not necessarily disjoint. The mutual exclusivity of events F and G does not guarantee the mutual exclusivity of events E and G.
The example provided in option D shows that events E and F are disjoint, events F and G are disjoint, but events E and G are not disjoint. This is because they share the element 2.
For example, E = {0,1,2}, F = {3,4,5}, and G = {2,6,7} .
Therefore, the mutual exclusivity of events F and G does not guarantee the mutual exclusivity of events E and G.
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The graph of f(x) and table for g(x) = f(kx) are given.
The graph shows an upward opening parabola labeled f of x that passes through a point negative 2 comma 8, a point negative 1 comma 2, a vertex 0 comma 0, a point 1 comma 2, and a point 2 comma 8.
x g(x)
−8 8
−4 2
0 0
4 2
8 8
What is the value of k?
k is equal to one fifth
k = 5
k is equal to one fourth
k = 4
Answer: C. k is equal to one fourth
Step-by-step explanation:
formula for parabola in vertex form
y= a(x-h)²+k (h, k) is vertex here it is (0,0)
f(x)=ax² another point we can plug in is (1,2)
2=a1
a= 2
so f(x)= 2x²
g(x)= f(kx) plug in kx into f(x)
g(x) = 2(kx)²
g(x) = 2(k²)(x²) plug in a point and find k (4,2)
2 = 2 k²4²
k²=1/16
k=1/4
C
John has 8 boxes of apples. Each box holds 10 apples. If 5 of the boxes are full, and 3 of the boxes are half full, how many apples does John have?
Answer:
65 apples
Step-by-step explanation:
We Know
John has 8 boxes of apples.
Each box holds 10 apples.
If 5 of the boxes are full, and 3 of the boxes are half full, how many apples does John have?
Let's solve
5 boxes are full: 5 x 10 = 50 apples
3 boxes are half full = 3(1/2 · 10) = 15 apples
50 + 15 = 65 apples
So, John has 65 apples.
5/8 - ( 3 - 1/4) + 2/3
The expression 1500 (1.085)^3 represents an account balance in dollars after three years with an initial deposit of $1,500. The account pays 8.5% interest, compounded annually for three years.
A. Explain how the expression would change if the bank had compounded the interest quarterly for the three years.
B. Write a new expression to represent the account balance, in dollars, if interest is compounded quarterly.
A. If the bank had compounded the interest quarterly for the three years, the interest rate would be divided by 4 (since there are 4 quarters in a year) and the number of compounding periods would be multiplied by 4. This is because the interest would be calculated and added to the account balance every quarter, rather than just once a year.
B. To represent the account balance if interest is compounded quarterly, we need to use the formula for compound interest with quarterly compounding:
A = P(1 + r/n)^(nt)
where A is the account balance, P is the principal (initial deposit), r is the annual interest rate (8.5%), n is the number of times the interest is compounded per year (4 for quarterly compounding), and t is the number of years (3).
Substituting the given values into the formula, we get:
A = 1500(1 + 0.085/4)^(4×3)
A = 1500(1.02125)^12
A ≈ $1,969.36
Therefore, the new expression for the account balance, in dollars, if interest is compounded quarterly is:
$1,969.36 = 1500(1 + 0.085/4)^(4×3)
It is the end of the semester and Kyle has one test left. His 5 test grades were 90, 83, 75, 84, 96. What does he need to make on the sixth test to have a mean test grade of 90
Answer:
Kyle needs 112 marks on his sixth test for the mean test grade to be 90.
Step-by-step explanation:
Let the marks Kyle needs for the sixth test be x.
The mean of all tests is given as 90. The formula for mean would be: (sum of marks obtained in each test)/(total number of tests)
which implies,
(90+83+75+84+96+x)/6 = 90,
(428+x)/6 = 90,
428+x = 540,
x = 112
Therefore, Kyle needs 112 marks on his sixth test for the mean test grade to be 90.
The sum of all values divided by the total number of values determines a dataset's mean (also known as the arithmetic mean, which differs from the geometric mean). It is the most widely applied central tendency measure and is frequently called the "average."
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There were 6 white socks and 4 black socks in a drawer. If you pick one sock without looking and then another without looking (not replacing the first), what is the probability that you pick two white socks?
Answer:
the probability of picking two white socks is 1/3, or approximately 0.333.
Step-by-step explanation:
When choosing the first sock, there are 10 socks in total, and 6 of them are white. Therefore, the chance of picking a white sock on the first try is 6/10 or 3/5.
When picking the second sock, there are only 9 socks left in the drawer, since we did not replace the first sock. Of the remaining socks, 5 are white (since we did not replace the first white sock) and 4 are black. Therefore, the probability of picking a white sock on the second try, given that we picked a white sock on the first try, is 5/9.
Answer: 1/3
Step-by-step explanation:6*5/2 is number of ways that work. This is 15. There are 10*8/2=45 total ways. 15/45=1/3.
HELPP PLEASE THIS IS TO HARD FOR ME
Using integration by part, the value of the integration over the interval is given as [(4√3 π - π + 2ln(2) - 4)] / 6
What is the the integral value of the function?In the given question, we have a function which is;
f(x) = √x tan⁻¹ √x dx over an interval of lower limit 1 and upper limit of 3
Applying integration by parts
[2/3x^3/2 arctan(√x) - ∫ x/3(x + 1) dx]^3_1
We can simplify this into;
[1/3(2x^3/2 arctan(√x) - x - 1 + ln |x + 1|)] ^3_1
Let's compute the boundaries
[(4√3 π - π + 2ln(2) - 4)] / 6
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help please will give brainliest
The minimum value of the function on the interval [2, 11] is -100,000,000,000.
What is the minimum value of the function?The function f(x) = -10ˣ is a decreasing exponential function, which means that its value decreases as x increases.
f(x) = -10ˣ on the interval [2, 11]
The minimum value of the function will be at the endpoint of the interval, which is at x=11.
f(11) = -10¹¹
f(11)= -100,000,000,000
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A canoe is approaching a lighthouse on the coastline of a lake. The front of the
canoe is 1.3 feet above the water and an observer in the lighthouse is 115 feet above the water.
At 5:00, the observer in the lighthouse measured the angle of depression to the front of the canoe to be 6.5°. Five minutes
later, the observer measured and saw the angle of depression to the front of the canoe had increased by 42.2º.
Determine to the nearest tenth of a foot per minute, the average speed at which the canoe traveled toward the lighthouse.
The average speed at which the canoe traveled toward the lighthouse is approximately 17.2 feet per minute.
How to solve for the average speedA is the front of the canoe
B is the position of the observer in the lighthouse
AB is the distance between the front of the canoe and the observer
θ1 is the angle of depression at 5:00
θ2 is the angle of depression at 5:05
h is the height of the front of the canoe above the water (1.3 feet)
We want to find the speed at which the canoe is traveling toward the lighthouse, which we'll call x feet per minute.
Using trigonometry, we can find the following relationships:
tan(θ1) = h / AB (1)
tan(θ2) = h / (AB + 5x) (2)
We can rearrange equation (1) to solve for AB:
AB = h / tan(θ1) (3)
Substituting equation (3) into equation (2), we get:
tan(θ2) = h / (h / tan(θ1) + 5x)
tan(θ2) = tan(θ1) / (1 + 5x * tan(θ1) / h) (4)
We can solve equation (4) for x:
x = (tan(θ1) / (tan(θ2) - tan(θ1))) * h / 5 (5)
Now we just need to plug in the values we know:
θ1 = 6.5°
θ2 = 48.7° (since θ2 = θ1 + 42.2°)
h = 1.3 feet
Plugging these into equation (5), we get:
x = (tan(6.5°) / (tan(48.7°) - tan(6.5°))) * 1.3 / 5
x ≈ 17.2 ft/min
Therefore, the average speed at which the canoe traveled toward the lighthouse is approximately 17.2 feet per minute.
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Solve for x to make A||B.
A = x + 12
B = x + 48
X = [?]
(Make sure to look at the pic for better understanding in the question)
Answer:
x=80
Step-by-step explanation:
x+12 and x+48 must equal 180 so 60 is the answer
60+12=72
60+48=108
72+108=180
Answer: 60
Step-by-step explanation:
When you have 2 parrallel lines the angles will either be = or =180 in this case =180
so
A+B=180
x + 12 + x + 48 = 180
2x + 60 =180
2x = 120
x=60
Alyssa is tracking the growth of a plant. The plant grows c inches in the first week and n inches in the second week. Enter an equation to show that the plant grows 2 inches more in the second week than in the first week
The equation is given as n = c + 2
How to derive the equationThe plant grows c inches in the first week.
The plant grows n inches in the second week.
mаthеmаticаlly, the equаtion requires that wea rea to to show thе relаtionship between thе growth in thе first wееk (c) and thе growth in thе seсond wееk (n).
thе growth in thе seсond wееk (n) is said to be 2 inсhes more than thе growth in thе first wееk (c) from the given question.
The equation would be
n = c + 2
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A 95% confidence interval for the mean of a population is computed to be 6 to 14. Which one of the following claims would the interval tend to support?
A. The population mean is less than 15.
B. The population mean is between 8 and 10.
C. The population mean is exactly 9.
D. The population mean is more than 17.
E. The population mean is more than 7.
Thus, option B, "The population mean is between 8 and 10," is the claim that is most supported by the interval.
Based on the given confidence interval of 6 to 14, we can say with 95% confidence that the true population mean falls between those values. Therefore, option B, "The population mean is between 8 and 10," is the claim that is most supported by the interval.
Option A, "The population mean is less than 15," and option E, "The population mean is more than 7," are also supported by the interval but are less specific than option B.
Option C, "The population mean is exactly 9," is not necessarily supported by the interval, as the true mean could be any value within the interval.
Option D, "The population mean is more than 17," is not supported by the interval, as the upper limit of the interval is only 14.
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f(x) =
=
|x|
1 x
x - 4
for a
x
for x
≤
1
1
A graph of the piecewise function is shown on the coordinate plane in the image attached below.
What is a piecewise-defined function?In Mathematics, a piecewise-defined function can be defined as a type of function that is defined by two (2) or more mathematical expressions over a specific domain.
Generally speaking, the domain of any piecewise-defined function simply refers to the union of all of its sub-domains. By critically observing the graph of the given piecewise-defined function, we can reasonably infer and logically deduce that it is decreasing over the interval x ≤ 1 and increasing over the interval x > 1.
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Test the given claim. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, and then state the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. Among 2094 passenger cars in a particular region, 227 had only rear license plates. Among 330 commercial trucks, 46 had only rear license plates. A reasonable hypothesis is that commercial trucks owners violate laws requiring front license plates at a higher rate than owners of passenger cars. Use a 0.10 significance level to test that hypothesis.a. Test the claim using a hypothesis test.b. Test the claim by constructing an appropriate confidence interval.
Since the p-value is less than the significance level of 0.10, we reject the null hypothesis. Since the confidence interval does not contain 0, it supports the alternative hypothesis that commercial trucks have a higher proportion of violations than passenger cars.
a. Hypothesis Test:
Null Hypothesis: The proportion of passenger cars with only rear license plates is equal to or greater than the proportion of commercial trucks with only rear license plates.
Alternative Hypothesis: The proportion of commercial trucks with only rear license plates is greater than the proportion of passenger cars with only rear license plates.
Let p1 be the proportion of passenger cars with only rear license plates, and p2 be the proportion of commercial trucks with only rear license plates.
The test statistic for comparing two proportions is the z-test.
z = ((p1 - p2) - 0) / √(p_hat * (1 - p_hat) * (1/n1 + 1/n2))
where p_hat = (x1 + x2) / (n1 + n2) is the pooled sample proportion, and x1 and x2 are the number of successes (only rear license plates) in the two samples, and n1 and n2 are the sample sizes.
Plugging in the values, we get:
p1 = 227/2094 = 0.1084
p2 = 46/330 = 0.1394
p_hat = (227 + 46) / (2094 + 330) = 0.1116
n1 = 2094
n2 = 330
z = ((0.1084 - 0.1394) - 0) / √(0.1116 * (1 - 0.1116) * (1/2094 + 1/330))
= -1.68
The p-value for this one-tailed test is P(Z < -1.68) = 0.0475.
Conclusion: The data provides sufficient evidence to support the claim that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars.
b. Confidence Interval:
We can also construct a confidence interval to estimate the difference in proportions with a specified level of confidence.
A 90% confidence interval for the difference in proportions can be calculated as:
(p1 - p2) ± z√(p1(1-p1)/n1 + p2*(1-p2)/n2)
Plugging in the values, we get:
(p1 - p2) ± 1.645√(0.1084(1-0.1084)/2094 + 0.1394*(1-0.1394)/330)
= (-0.0499, 0.0094)
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A cell phone that was bought for 2500 was sold at 15% calculate the selling price
Answer:
The answer to your question is $375
The selling price of the cell phone is $375.
Step-by-step explanation:
15% x 2500
100 = 375
I hope this helps and have a wonderful day!
The inverse of a function can be found by ___ the numbers in each ordered pair of the function.interchangingreflectingexponentintercept
The main answer to your question is "interchanging". To find the inverse of a function, we interchange the numbers in each ordered pair of the function. This means that we switch the x and y values of each point in the function.
For example, if we have a function f(x) = 2x + 3, the ordered pairs would be (1,5), (2,7), (3,9), etc. To find the inverse function, we would switch the x and y values of each point to get ordered pairs such as (5,1), (7,2), (9,3), etc.
The explanation for why we interchange the numbers is that the inverse function "undoes" the original function. If we apply the original function to a number, the inverse function will take us back to the original number. By switching the x and y values, we make sure that the inverse function will undo the original function.
In conclusion, to find the inverse of a function, we interchange the numbers in each ordered pair of the function. This ensures that the inverse function will undo the original function.
Hi! I'm happy to help you with your question.
Main answer: The inverse of a function can be found by interchanging the numbers in each ordered pair of the function.
Explanation: When finding the inverse of a function, you are essentially swapping the input and output values in each ordered pair (x, y) to create a new ordered pair (y, x). This process is called interchanging the numbers in the ordered pair.
Conclusion: To find the inverse of a function, you need to interchange the numbers in each ordered pair of the function, which essentially swaps the input and output values.
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One angle of an isosceles triangle measures 108°. What measures are possible for the other two angles? Choose all that apply.
The measure of the angles of the isosceles triangle is x = 36°
Given data ,
Let the measure of one angle of the isosceles triangle be = 108°
where , the isosceles triangle has three acute angles, meaning that the angles are less than 90°
So , let the measure of the unknown angle be x
And , x + x + 108 = 180
Subtracting 108 on both sides , we get
2x = 72
Divide by 2 on both sides , we get
x = 36°
Hence , the angle of isosceles triangle is x = 36°
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The complete question is attached below :
One angle of an isosceles triangle measures 108°. What measures are possible for the other two angles? Choose all that apply.
The could spring high school student government polled randomly selected seniors and asked them how much money they spent on gas in the last week. The following stem-and-leaf plot shows the data they collected
Any number above 108 will be an upper outlier. So, there is no upper outlier.
Therefore, there is 1 outlier.
How to solveMean :
For a given distribution, the mean can be calculated by dividing the sum of all quantities with the number of quantities. Sometimes it referred to as average.
Median:
The median of a given data distribution is calculated as follows:
1. First arrange all the given data in ascending order.
2. If the number of data items is odd, then the centre data represents the median.
3. If the number of data items is even, then two numbers are in the central data. The average of those two data items is a median.
Mode
In the given data, the element which occurs number of times is called the mode of the data.
Step 2/14
a.
Consider the stem and leaf plot given in the text book that represents the money spent on gas in the last week by the selected seniors.
Compute the frequency of the given stem-and-leaf plot by counting its leaves. There are 27 leaves in the given plot.
Therefore, a total 27 students were polled.
Step 3/14
b.
Add the data represented in the plot and divide it by the frequency to compute the mean.
The sum of all data points is as follows,
1662
So, the mean of the given data set will be,
1662/27
=$61.56
Step 4/14
c.
The frequency of the given data set is an odd number (27).
So, the median will be the 14th data point.
From the given data set, 14th data point is $ 64.
Therefore, the median of the given data is. $64
Step 5/14
d.
The Mode of a given data set is the most occurring item.
From the given stem and leaf plot, the leaf 3 corresponding to the stem 5 is the most occurring data point (5 times).
Therefore, the mode of the given data is. $53
Step 6/14
e.
The Range is the difference between the greatest number and the least number in the given data set.
The lowest data point is 17 $ and the greatest data point is 84 $
Therefore, the range of the given data will be,
Range = 84 -17
=$67
Step 7/14
f.
The lower quartile of the given data set will be the 7th data point.
Therefore, Q1 = $54
The second quartile of the given data set will be equal to the median.
Therefore, Q2 = $64
The upper quartile of the given data set will be the 21st data point.
Therefore, Q3 = $75
Forth quartile of the given data set will be equal to the maximum value in the data set. Therefore, Q4 =-$84
Step 8/14
g.
53 $ is the lower quartile of the given data set. So, 25% of the numbers in the data set are at or below 53 $.
Therefore, 75% of the students spent $ 53 or more on gas.
Step 9/14
h.
Inter quartile range of the given data set will be,
Q3 -Q1
=$22
Step 10/14
i.
53 $ is the lower quartile and 75 $ is the upper quartile of the given data set. 50% of the numbers in the data set lie between lower quartile and upper quartile.
Therefore, 50% of the students spent from $ 53 to $ 75 on gas.
Step 11/14
j.
The boundary for the lower outliers will be,
53- 1.5 x 22
=20
Step 12/14
k.
The boundary for the upper outliers will be,
75 + 1.5 x 22
=108
Step 13/14
l.
Any number below 20 will be a lower outlier. So, $ 17 is a lower outlier.
Any number above 108 will be an upper outlier. So, there is no upper outlier.
Therefore, there is 1 outlier.
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PLEASE ANSWER THIS QUESTION LIKE ASAP
pllss help me with this!!!
Answer:
18.3
Step-by-step explanation:
In order to convert Fahrenheit to Celsius, you need to use the formula:
[tex]C=\frac{5}{9}(F-32)[/tex]
Since F = 65, we can plug it in:
[tex]C=\frac{5}{9}(65-32)[/tex]
[tex]C=\frac{5}{9}(33)[/tex]
[tex]C=\frac{165}{3}[/tex]
[tex]C=18.33333333333333333333333333[/tex]
Rounding to the nearest tenth, we get
[tex]C = 18.3[/tex]
For which value of x is the inequality −2x≥6
true?
A. -3
B. -2
C. -1
D. 0
E. 4
Answer:
-2x > 6, so x < -3
So A is correct.
a target is 16 inches by 20 inches and the center target is 4 inches by 3 inches. what is the probability the ball will hit the center target to the nearest tenth of a percent?
The probability of hitting the center target is 3.8%.
To find the probability of hitting the center target, we need to know the total area of the larger target and the area of the center target.
The area of the larger target is:
16 inches x 20 inches = 320 square inches
The area of the center target is:
4 inches x 3 inches = 12 square inches
So, the probability of hitting the center target is:
12 square inches / 320 square inches = 0.0375 or 3.75%
Rounded to the nearest tenth of a percent, the probability of hitting the center target is 3.8%.
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I need help pls im confuzzled
Heart = 1
Water = 2
star = 4
Step-by-step explanation:
Heart x water = water, so heart is probably 1.
Water x water=star and water + water= star so water is 2. Star is 4
Answer:
heart= 1
tear= 2
star=4
leaf=2
diamond=3
circle=6
Step-by-step explanation:
if heart x tear equals tear one of those numbers has to be one.
so heart equals 1
tear + tear= star and tear x tear= star
only number that work are 2 since 2+2=4 and 2x2=4
leaf +leaf +leaf = circle
so plug in 2 for the leaves. 2+2+2=6
2x ____=6 plug in 3 so diamond is 3
3+3=6 so those are the correct choices.
A. A population of values has a normal distribution with ฮผ=208.5 and ฯ=35.4. You intend to draw a random sample of size n=236.
Find the probability that a single randomly selected value is greater than 203.4.
P(X > 203.4) =
The probability that a single randomly selected value is greater than 203.4 is approximately 0.556.
To solve this problem, we need to use the properties of the normal distribution and probability.
First, we know that the population has a normal distribution with a mean of 208.5 and a standard deviation of 35.4. This means that the distribution of sample means will also be normal with a mean of 208.5 and a standard deviation of 35.4/sqrt(236), which is approximately 2.3.
Next, we want to find the probability that a single randomly selected value is greater than 203.4. To do this, we need to standardize the value using the formula:
z = (x - μ) / σ
where x is the value we want to find the probability for, μ is the population mean, and σ is the population standard deviation.
Plugging in the values we have:
z = (203.4 - 208.5) / 35.4 = -0.144
This means that the value of 203.4 is 0.144 standard deviations below the mean.
Using a standard normal distribution table or calculator, we can find the probability of a value being less than -0.144, which is the same as the probability of a value being greater than 0.144. This probability is approximately 0.556.
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Find the limit. Use l'Hospital's Rule where appropriate. If there is a more elementary method, consider using it.
lim 1 − sin(θ)/1 + cos(2θ)
θ→π/2
The expression: lim θ→π/2 sin(θ)/(4cos(2θ)) = sin(π/2)/(4cos(2π/2)) = 1/4.
The limit is 1/4.
What is trigonometry?
Trigonometry is a branch of mathematics that deals with the relationships between the sides and angles of triangles.
We can begin by directly substituting π/2 into the expression and see that we get an indeterminate form of 0/0:
lim θ→π/2 (1 - sin(θ))/(1 + cos(2θ)) = (1 - sin(π/2))/(1 + cos(2π/2)) = 0/0.
To apply l'Hospital's Rule, we take the derivative of the numerator and denominator with respect to θ:
lim θ→π/2 (1 - sin(θ))/(1 + cos(2θ)) = lim θ→π/2 (-cos(θ))/(−2sin(2θ))
Now we can directly substitute π/2 into the expression:
lim θ→π/2 (-cos(θ))/(−2sin(2θ)) = (-cos(π/2))/(−2sin(2π/2)) = -1/0,
which is another indeterminate form. We can apply l'Hospital's Rule again by taking the derivative of the numerator and denominator with respect to θ:
lim θ→π/2 (-cos(θ))/(−2sin(2θ)) = lim θ→π/2 sin(θ)/(4cos(2θ))
Now we can substitute π/2 into the expression:
lim θ→π/2 sin(θ)/(4cos(2θ)) = sin(π/2)/(4cos(2π/2)) = 1/4.
Therefore, the limit is 1/4.
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two standard 6 sided dice are rolled. one is blue and one is red. what is the probability that sum of the two dice on a roll is 5 given that the blue die for that roll landed on 6?
The probability that sum of the two dice on a roll is 5 given that the blue die for that roll landed on 6 is 0.25 or 25%.
If we know that the blue die landed on 6, then we only need to consider the possible outcomes of the roll of the red die that would result in a sum of 5.
If red die shows 1, 2, 3 or 4, then the sum of the dice will be 6. There are a total of 6 possible outcomes for the roll of the red die (since it is a standard 6-sided die), but we can eliminate the outcomes 5 and 6 since they would result in a sum greater than 5.
So, out of the 4 possible outcomes for the roll of the red die that would result in a sum of 5, only one of them will occur if the blue die landed on 6. Therefore, the probability of getting a sum of 5 given that the blue die landed on 6 is:
1/4 = 0.25 or 25%
Hence the probability of the sum being 5 is 0.25 or 25%.
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A certain quadratic function has a graph which contains the points (1, 7), (2, 16), and (3, 29). Using a quadratic regression (or a system of linear equations), find the equation for this function in standard form. As your answer, give the coefficient on x2 (that is, a).
Group of answer choices
–2
2
–1
1
The required coefficient on x² is 2, so the answer is 2. Option B is correct.
We can start by assuming that the quadratic function has the form:
y = ax² + bx + c
where a, b, and c are unknown coefficients to be determined. We can use the three given points on the graph to set up a system of three equations in three unknowns:
7 = a(1)² + b(1) + c
16 = a(2)² + b(2) + c
29 = a(3)² + b(3) + c
Simplifying each equation, we get:
a + b + c = 7
4a + 2b + c = 16
9a + 3b + c = 29
We can solve this system of equations using any method of our choice, such as elimination or substitution. One possible approach is to subtract equation 1 from equation 2 and equation 2 from equation 3, which gives:
a + b + c = 7
3a + b = 9
5a + b = 13
a = 2; b = 3; c = 2
Therefore, the equation for the quadratic function in standard form is:
y = 2x² + 3x + 2
The coefficient on x² is 2, so the answer is 2.
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What is the length of segment AB? Round your answer to the nearest hundredth.
In the given graph, the length of the segment "AB" is 6.32units.
We have to find length of segment "AB", which means we have to find the distance between the end-points "A" and "B",
From the graph, the end-points of the segment "AB" are :
A ⇒ (-2,4) and B ⇒ (4,2),
So, the length(distance) between these two points can be calculated by the formula : √((x₂-x₁)² + (y₂-y₁)²);
Considering (-2,4) as (x₁, y₁) and (4,2) as (x₂, y₂);
We get,
Length(distance) = √((4-(-2))² + (2-4)²);
Length = √(6² + (-2)²); = √(36 + 4);
Length = √40 ≈ 6.32 units.
Therefore, the length of the segment is 6.32 unis.
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