Find the product or type impossible[5 -2 4] [2 7 -3]

Answers

Answer 1

Answer:

Step-by-step explanation:

You can only multiply matrices if the number of columns in the matrix on the left is the same exact number as the number of rows in the matrix to the right of that other matrix.

The matrix on the left, |5 -2  4| has the dimensions

                                      1 x 3 (1 row, 3 columns)

The matrix to its right, |2  7  -3| has the dimensions

                                      1 x 3 (1 row, 3 columns).

Putting those dimensions next to each other in that order:

                  1 x 3     1 x 3

The bold print 3 and 1 have to be the same number (both 3's or both 1's) in order for the multiplication to work. This doesn't work; it's impossible.

Answer 2

Answer: -16

Step-by-step explanation:

i was on a unit exam typing in random numbers since i didn't know it and -16 is the right answer.


Related Questions

I need help asap please help me

Answers

Answer:

8

Step-by-step explanation:

I belive what they mean is how many dots thier are i am not complety sure though but just by counting them up i came up with 8.

hope this helped

x2 + 6x - 7

Factor the following trinomials containing negative numbers. Follow the rules for operations with signed numbers to identify the correct binomial factors.

Answers

The factored form of the given trinomial is (x -7)(x +1)

Factoring the quadratics

From the question, we are to factor the given trinomials

The given trinomial is

x² + 6x - 7

The trinomial is a quadratic expression. The trinomial/ quadratic expression can be factored as a product of two binomial. When factored, the trinomial will take the form (x + a)(x + b)

Where are a and b are integers.

Factoring the trinomial

x² + 6x - 7

To factor the trinomial, we will find two numbers such that when added, we get the middle term; and when these numbers are multiplied we get the constant term.

The numbers that satisfy this condition are +1x and -7x

x² +x -7x - 7

x (x + 1) -7(x +1)

(x -7)(x +1)

Hence, the factored form of the given trinomial is (x -7)(x +1)

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find the missing length 25 and 65​

Answers

Answer: 60.

Step-by-step explanation:

Let in a right triangle one of the legs is 25, and the hypotenuse is 65.

Hence, the other leg is:  [tex]\sqrt{65^2-25^2}=\sqrt{4225-625}=\sqrt{3600}=60.[/tex]

The answer is 5 hope that helps I think

Is there anyone who help me in my math work

Answers

Answer:

LCM=72

Step-by-step explanation:

l.c.m by prime factorization

a)18,24

factor of 18=2*3*3

factor of 24=2*2*2*3

common and remaining factor=2*3*3*2*2= 72

What is the value of x in the equation7x+2y=48 , when y = 3?

Answers

Answer:

x = 6

Step-by-step explanation:

put '3' in where 'y' is :

7x + 2(3) = 48

7x + 6 = 48              subtract 6 from both sides of the equation

7x = 42                 divide both sides by 7

x = 6

What is the range of the data? 6 7 9 10

Answers

Answer:

4

Step-by-step explanation:

10 - 6 = 4

4.
To find range, you have to subtract the highest value of the list to the lowest value of the list.
10 - 6 = 4.

help solve math problem

Answers

Answer:

  (c)  x < -5.170

Step-by-step explanation:

The given function is an exponential function with a decay factor of 0.5 and a y-intercept of 0.5^2 = 0.25. It will be larger for more negative x-values.

Estimate

We know that 2^3 = 8, so (1/2)^-3 = 8. This means the exponent of 0.5 in the given inequality will be more negative than -3:

  x +2 < -3

  x < -5 . . . . . . . . subtract 2

The only answer choice in this range is ...

  x < -5.170

Exact solution

Taking the logarithm of both sides of the inequality, we have ...

  (x +2)log(0.5) > log(9)

  x +2 < log(9)/log(0.5) . . . . . . log(0.5) < 0, so the inequality reverses

  x < log(9)/log(0.5) -2 . . . . . . subtract 2

  x < (0.95424251)/(-0.30103000) -2 = -3.1699250 -2

  x < -5.1699250 ≈ -5.170

Elijah has a flower box in shape of a rectangular prism with injector dimensions that are 15 inches in length, 8 inches in width height. elijah will flower box 3/4 full of soil. how many cubic inches of soil will be in flower box?

Answers

720 cubic inches of soil will be in the flower box.

Cuboid Definition: Cuboid shaped objects surround us in our day-to-day life. From television sets, books, carton boxes to bricks, mattresses, and shoeboxes, cuboid objects are all around us. In Geometry, a cuboid is a three-dimensional figure with six rectangular faces, twelve edges, and eight vertices.

Volume of Cuboid = Length x Width x Height

∴ The volume of the soil box = 15 x 8 x 8 = 960 inch³

Since 3/4 is occupied by the soil, the volume of the soil becomes

= 3/4 x 960

= 720 inch³

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Select the correct answer.
Graph the following system of inequalities.
y ≥x-2
y ≤-4x - 2
y
-6-5
6
0 1 2 3 4
X
9
5
2
F
6
12 RE
NUE
F
4 5 6

Answers

Answer:

I don't understand the formatting after the first two equations.

Step-by-step explanation:

See attached graph.



Identify the inequality
that describes this graph.
y≤x + 5
y>x+5

Answers

The inequality that describes this graph is y ≥ x+5

How to determine the inequality?

From the given graph, we have the following highlights:

The line of the graph is a closed lineThe upper part is shaded

The first highlight above implies, the inequality can be any of ≥ and ≤

While the second highlight above implies, the inequality is ≥

Hence, the inequality that describes this graph is y ≥ x+5

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find the exepted value of the random varible with the following probability distribution x=2,3,4,5,6,7,8,9,10,11,12 Probability =1/36,1/18,1/12,1/9,5/36,1/6,5/36,1/9,1/12,1/18,1/36

Answers

The expected value of the random variable is 7

How to determine the expected value of the random variable?

The probability distribution is given as:

x=2,3,4,5,6,7,8,9,10,11,12

Probability =1/36,1/18,1/12,1/9,5/36,1/6,5/36,1/9,1/12,1/18,1/36

The expected value of the random variable is calculated using

E(X) = ∑xP(x)

Using the above formula, we have

E(x) = 2 * 1/36 + 3 * 1/18 + 4 * 1/12 + 5 * 1/9+ 6 * 5/36 + 7 * 1/6 + 8 * 5/36 + 9 * 1/9 + 10 * 1/12 + 11 * 1/18+ 12 * 1/36

Evaluate the sum of products

E(x) = 7

Hence, the expected value of the random variable is 7

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the sides of each square have a length of 3 inches. what is the perimeter of Edgar's check boar​

Answers

Answer:

  (b)  96 inches

Step-by-step explanation:

The perimeter of the board is the sum of its four edge lengths.

Edge length

Each edge of the board is indicated as being 8 squares long. Each square is 3 inches on a side, so the edge of the board is ...

  8 × (3 in) = 24 in . . . . board edge length

Perimeter

The perimeter of the board is 4 times the length of one edge, so is ...

  P =4s = 4(24 in) = 96 in

The perimeter of Edgar's checkerboard is 96 inches.

__

Scaled geometry (alternate solution)

The perimeter of one small square on the board is ...

  P = 4s = 4(3 in) = 12 in

The whole board is a dilation of one square by a factor of 8. Its perimeter will be ...

  P' = (scale factor) × P

  P' = 8×(12 in) = 96 in

The perimeter of Edgar's checkerboard is 96 inches.

pllllllllllllllllllllleasee one guys i neeed ur help one

Answers

[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Let's solve ~

Calculate discriminant :

[tex]\qquad \sf  \dashrightarrow \: 3 {x}^{2} + 6x - 1[/tex]

a = 3b = 6c = 1

[tex]\qquad \sf  \dashrightarrow \: discriminant = {b}^{2} - 4ac[/tex]

[tex]\qquad \sf  \dashrightarrow \: d = (6) {}^{2} - (4 \times 3 \times 1)[/tex]

[tex]\qquad \sf  \dashrightarrow \: d = 36 - 12[/tex]

[tex]\qquad \sf  \dashrightarrow \: d = 24[/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt {d} = 2 \sqrt{6} [/tex]

Now, let's calculate it's roots ( x - intercepts )

[tex]\qquad \sf  \dashrightarrow \: x = \cfrac{ - b \pm \sqrt{d} }{2a} [/tex]

[tex]\qquad \sf  \dashrightarrow \: x = \cfrac{ - 6\pm 2 \sqrt{6} }{2 \times 3} [/tex]

[tex]\qquad \sf  \dashrightarrow \: x = \cfrac{ - 6\pm 2 \sqrt{6} }{6} [/tex]

So, the intercepts are :

[tex]\qquad \sf  \dashrightarrow \: x = \cfrac{ - 6 - 2 \sqrt{6} }{6} [/tex]

and

[tex]\qquad \sf  \dashrightarrow \: x = \cfrac{ - 6 + 2 \sqrt{6} }{6} [/tex]

Answer:

[tex]\left( \dfrac{ -3 + 2\sqrt{3}}{ 3}, \ 0\right), \ \left(\dfrac{ -3 - 2\sqrt{3}}{ 3}, \ 0\right)[/tex]

Explanation:

Given expression:

f(x) = 3x² + 6x - 1

To find x intercepts, set f(x) = 0

Use quadratic formula:

[tex]\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \ where \ ax^2 + bx + c = 0[/tex]

Here after finding coefficients:

a = 3, b = 6, c = -1

Applying formula:

[tex]x = \dfrac{ -6 \pm \sqrt{6^2 - 4(3)(-1)}}{2(3)}[/tex]

[tex]x = \dfrac{ -6 \pm \sqrt{48}}{6}[/tex]

[tex]x = \dfrac{ -6 \pm 4\sqrt{3}}{6}[/tex]

[tex]x = \dfrac{ -6 \pm 4\sqrt{3}}{2 \cdot 3}[/tex]

[tex]x = \dfrac{ -3 \pm 2\sqrt{3}}{ 3}[/tex]

[tex]x = \dfrac{ -3 + 2\sqrt{3}}{ 3}, \ \dfrac{ -3 - 2\sqrt{3}}{ 3}[/tex]

solve for x in x²+8x+15=0 in factorisation method ​

Answers

Answer: [tex]x=-5, -3[/tex]

Step-by-step explanation:

[tex]x^2 +8x+15=0\\\\(x+5)(x+3)=0\\\\x=-5, -3[/tex]

While walking between gates at an airport, you notice a child running along a moving walkway. Estimating that the child runs at a constant speed of 2. 4 m/s relative to the surface of the walkway, you decide to try to determine the speed of the walkway itself. You watch the child run on the entire 18-m walkway in one direction, immediately turn around, and run back to his starting point. The entire trip takes a total elapsed time of 32 s. Given this information, what is the speed of the moving walkway relative to the airport terminal?.

Answers

The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.

How to estimate the speed of the moving walkway relative to the airport terminal?

Let x be the speed of the walkway.

(2.8 + x) = speed of child moving in direction of the walkway

(2.8 - x) =  speed of child moving against the direction of the walkway

Travel time = distance/speed

Travel time of child moving in direction of walkway = 23/(2.8+x)

Total elapsed time given = 29s

23/(2.8 + x)+ 23 / (2.8-x) = 29

LCD = (2.8 + x)(2.8 - x)

[tex]23(2.8 - x) + 23(2.8 + x) = 29(2.8 + x)(2.8 -x)[/tex]

simplifying the equation, we get

[tex]23*2.8-23x+23*2.8+23x=29(2.8^2-x^2)[/tex]

[tex]23(2.8+2.8)/29=2.8^2-x^2[/tex]

[tex]x^2=(2.8)^2-(23*5.6)/29)=3.4[/tex]

[tex]x=\sqrt{3.4}=1.84m/s[/tex]

Speed of walkway = 1.84 m/s

The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.

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When strawberry prices increase 20 percent, the quantity demanded of whipped cream falls 10 percent. what is the cross-price elasticity of demand between strawberries and whipped cream?

Answers

The cross-price elasticity of demand between strawberries and whipped cream is (C) -0.5.

What is the cross-price elasticity of demand?The cross elasticity of demand, also known as the cross-price elasticity of demand, is a measure in economics that compares the percentage change in the quantity desired for one commodity to the percentage change in the price of another good, everything else being equal. In practice, the amount desired of a thing is affected not only by its own price (price elasticity of demand) but also by the prices of other "related" products.As an example, when strawberry prices rise by 20%, demand for whipped cream falls by 10%. The cross-price elasticity of demand between strawberries and whipped cream is -0.5.

Therefore, the cross-price elasticity of demand between strawberries and whipped cream is (C) -0.5.

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The complete question is given below:

When strawberry prices increase by 20 percent, the quantity demanded of whipped cream falls by 10 percent. What is the cross-price elasticity of demand between strawberries and whipped cream?

a. -2

b. 2

c. -0.5

d. 0.5

please answer this question I f0ll0w u and mark brainiest and give many thanks​

Answers

Answer:

look above

Step-by-step explanation:

hope it helps

help me with this please

Answers

Answer:

48

Step-by-step explanation:

The area of this circle is

[tex]\pi( {4}^{2} ) = 16\pi = 50.27[/tex]

about 50.27 square centimeters. So 48 square centimeters seems reasonable here since 3 is used for π.

Marcus had $50 in the bank and deposited
$x a week. At the end of 15 weeks, he had
$1,010 in the bank. Write and solve an
equation to determine how much money he
deposited each week.
13)

Answers

Answer:

$64

Step-by-step explanation:

Equation: 50 + 15x = 1010

x = (1010 - 50) ÷ 15 = 64

Since x is the total amount of money deposited in the bank per week, the answer is $64.

which relation is a function?

Answers

The relation that is a function is:

b. y = 2x² - 3x + 7

When a relation is a function?

A relation is a function if each value of the input is mapped to only one value of the output.

Hence, when both x and y are squared, we have that [tex]x = \pm ay[/tex], hence it is not a function. This is the case for items a and c.

For item d, we have that the relation can be simplified as follows:

x = -y² + 3y

x = y(-y + 3)

The solution above, is associated to two values of y, hence it is also not a function. Then the function is given by:

b. y = 2x² - 3x + 7

In the solution, it can be seen that for each input x, only one value of y can be generated.

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60. In the given figure, PTR is tangent of a circle. If AT=PT and ZAPT=20°, what is the value of ZABT? ​

Answers

The value of angle ABT is 40 degrees if PTR is the tangent of a circle option (a) 40° is correct.

What is a circle?

It is described as a set of points, where each point is at the same distance from a fixed point (called the center of a circle)

It is given that:

A circle is shown in the picture.

PTR is the tangent of a circle.

AT=PT

Angle APT=20°

Let O is the center of the circle:

Angle BOT = 2 Angle PAT = 40 degrees

BO = TO = r

Angle BOT = Angle TBO = (1/2)(180 - 40) = 70 degrees

RTP is the tangent

OT ⊥ PTR

Angle OTA = 90 - Angle ATR = 50 degrees

Angle ABT = 180 - Angle PAT - Angle BTA

= 180 - 20 -  (170 + 50)

= 40 degrees

Thus, the value of angle ABT is 40 degrees if PTR is the tangent of a circle option (a) 40° is correct.

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Evaluate the line integral
6 integral yzcosx ds x = t, y = cost, z = sint 0 < t < pi

Answers

It looks like the integral is

[tex]\displaystyle 6 \int yz\cos(x) \, ds[/tex]

With [tex]x=t[/tex], [tex]y=\cos(t)[/tex], and [tex]z=\sin(t)[/tex], the line element is

[tex]ds = \sqrt{\left(\dfrac{dx}{dt}\right)^2 + \left(\dfrac{dy}{dt}\right)^2 + \left(\dfrac{dz}{dt}\right)^2} \, dt = \sqrt2 \, dt[/tex]

and so

[tex]\displaystyle 6 \int yz\cos(x) \, ds = 6\sqrt2 \int_0^\pi \cos^2(t) \sin(t) \, dt[/tex]

Substitute [tex]u = \cos(t)[/tex] and [tex]du=-\sin(t)\,dt[/tex], then

[tex]\displaystyle 6 \int yz\cos(x) \, ds = -6\sqrt2 \int_1^{-1} u^2 \, du = 12\sqrt2 \int_0^1 u^2 \, du = \boxed{4\sqrt2}[/tex]

where in the second-to-last equality, we have

[tex]\displaystyle -\int_1^{-1} = \int_{-1}^1[/tex]

and

[tex]\displaystyle \int_{-1}^1 u^2 \, du = 2 \int_0^1 u^2\,du[/tex]

by symmetry.

i,dk how to do this pls help :)

Answers

Given the percentage taken off and the reduced price, the original price of the item is $142.

What was the original price of the item?

Given the data in the question;

Percentage off the item = 20%Reduced price of the item = $113.60Original price of the item = ?

The original price of the item is at 100%, if the 20% is taken off. The price is now at 80%.

Hence 80% of the original price will give the reduced price.

Let the original price be represented by x

80% × x = $113.60

We solve for x

80/100 × x = $113.60

80x/100 = $113.60

Cross multiply

80x = $11360

x = $11360/80

x = $142

Given the percentage taken off and the reduced price, the original price of the item is $142.

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(6+q)-xy pllease help this question turn in words

Answers

In words (6 + q) - xy is six added to a number subtracted from the product of two numbers

The problem is a algebraic expression

What is an algebraic expression?

A algebraic expression  a mathematical expression containing one or more variables used to express a word problem

We want to convert the algebraic expression (6 + q) - xy into a word problem.

First, we have 6 + q which is six added to a number.Next, we have xy which is the product of two numbersSince (6 + q) is subtracted from xy, we have (6 + q) - xy as six added to a number subtracted from the product of two numbers

So, (6 + q) - xy in words is six added to a number subtracted from the product of two numbers

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The function f(x) = 2x 1 represents the altitude of a plane, where x is the time in minutes. the function g(x) = x2 − 10 represents the time in minutes, where x is the height in thousands of feet of the plane. what is the value of f[g(10)]? 271 181 90 21

Answers

To estimate the value for g(10), that means that you have to substitute 10 in every x of g(x), then [tex]$g(x) =x^2-10[/tex] exists g(10) = 90.

The value of g(10), we have to substitute in every x of f(x), the

[tex]f(x) = 2x + 1[/tex] exists f(90) = 181

Therefore, the value of f[g(10)] exists 181.

How to estimate the value of f[g(10)]?

To estimate the value for g(10), that means that you have to substitute 10 in every x of g(x), then

[tex]$g(x) =x^2-10[/tex]

substitute the value of x = 10

[tex]$g(10) = (10)^2-10[/tex]

simplifying the equation, we get

g(10) = 100 - 10

g(10) = 90

We have the value of g(10), we have to substitute in every x of f(x), then

f(x) = 2x + 1

substitute the value of x = 90

f(90) = 2(90) + 1

simplifying the equation, we get

f(90) = 180 + 1

f(90) = 181

The value of f[g(10)] exists 181.

Therefore, the correct answer is option b) 181.

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A video game shop is analyzing its sales performance using matrices. matrix a contains the unit sales data for each product category (horizontally) per week (vertically). matrix b contains the unit sales data for weekends for each category (horizontally) per week (vertically). to find the number of games in each product category that were sold each week only on weekdays, which matrix operation must be performed? a. add matrix a to the inverse of matrix b. b. more data is needed to calculate the sales during weekdays. c. subtract matrix b from matrix a. d. add matrix b to matrix a.

Answers

Answer:

Matrix B should be subtracted from Matrix A.

Step-by-step explanation:

Simplify (64/125)-2/3 + (256/625)-1/4 + (7/3)​

Answers

Step-by-step explanation:

part 1: 64/125 - 2/3

make the denominator ( bottom number) the same

x/125 and x/3

125×3 and 3×125

x/375 and x/375

whatever we do to the denominator we have to do to the numerator ( top number)

64/125

125 × 3

so

64 ×3

=64×3/125×3

=192/375

2/3

3 × 125

so

2 × 125

=2×125/3×125

=250/375

put together:

192/375 - 250/375

denominator is the same so we can simply take 192 from 250

192 - 250 = -58

= -58/375

part 2: + (256/625)-1/4

-58/375 + (256/625)-1/4

do the same for (256/625)-1/4 as in part 1

then add it to -58/375 by making the denominator the same

part 3: + (7/3)​

make the denominator the same and add

part 4: simplify

divide a number from both the top and bottom till there is nothing you can divide from both

How many cars can be washed with 1 gallon of soap if 100oz Can
wash 11 cars?

Answers

Answer: 14 cars.

Step-by-step explanation:

A car can be washed with : 100/11 oz.

1 gallon=128 oz.

Hence,

[tex]\displaystyle\\\frac{128}{\frac{100}{11} } =\frac{128*11}{100} =\frac{1408}{100} =14,08\ (cars).[/tex]

The total number of cars that can be washed with 1 gallon of soap if 100oz Can wash 11 cars would be given as 14 cars

How to solve for the total number

To determine how many cars can be washed with 1 gallon of soap, we need to find the ratio between the amount of soap used and the number of cars washed.

Given that 100 oz of soap can wash 11 cars, we can set up the following proportion:

100 oz soap / 11 cars = 1 gallon soap / x cars

I gallon is given as 128 OZ

Such that we have

128 x 100 / 11

= 14.08 cars

Hence the total number of cars would be given as 14 cars

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Find the ratio of 4:25​

Answers

4:25
16:100
1: 6.25

Answer: 1: 6.25

If you have 6 lessons a week in mathematics, each lesson being 38 minutes long, what is the total time spent in mathematics lessons in a ten week term?

Answers

Answer:

2280 minutes.

Step-by-step explanation:

Time spent each week in lessons = (Lessons per week)(Time per lesson)

= (6)(38)

= 228 minutes/week

Time spent in a 10-week period:

10 weeks * 228 minutes/week

= 2280 minutes

Use conversion factors to determine the time in the desired units (i.e. Hours, seconds, etc.).

Hope this helps!

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