Answer:
There are two possibilities: 1) A is the hypotenuse: [tex]C \approx 18.74[/tex], 2) A is not the hypotenuse: [tex]C \approx 21.19[/tex]
Step-by-step explanation:
Let be C the remaining side of the triangle. Given that triangle is right-angled and the remaining side can be found by Pythagorean Theorem, there are two options by using the two known sides:
1) A is the hypotenuse
[tex]20^{2} = 7^{2} + C^{2}[/tex]
[tex]C^{2} = 20^{2}-7^{2}[/tex]
[tex]C = \sqrt{20^{2}-7^{2}}[/tex]
[tex]C \approx 18.74[/tex]
2) A is not the hypotenuse
[tex]C^{2} = 20^{2} + 7^{2}[/tex]
[tex]C = \sqrt{20^{2}+7^{2}}[/tex]
[tex]C \approx 21.19[/tex]
The area of one of the smaller circles is 8/ in². Find the area of the shaded region.
A. pi in.²
B. 4 pi in.²
C. 8 pi in.²
D. 16 pi in.²
The answer is D btw i just submitted my quiz
Answer:
Area of shaded region = 16π in² (D)
Step-by-step explanation:
The question is incomplete without the diagram if the circles. Find attached the diagram used in solving the question.
Area of the smaller circle = 8π in²
Area of a circle = πr²
πr² = 8π
r² =8
r = √8 = 2√2
From the diagram, there are two smaller circles in a bigger circle.
The radius of the bigger circle (R) is 2times the radius of the smaller circle (r)
R = 2r
Area of bigger circle = πR²
= π×(2r)² = π×(2×2√2)²
= π×(4√2)² = π×16×(√2)²
Area of bigger circle = π×16×2
Area of bigger circle = 32π in²
Since there are two smaller circles in a bigger circle
Area of shaded region = Area of bigger circle -2(area of smaller circles)
Area of shaded region = 32π in² - 2(8π in²)
Area of shaded region = 32π in² - 16π in²
Area of shaded region = 16π in²
Answer:
D.
Step-by-step explanation:
May someone help me solve
g(x)=8x^2-10x-3 and find the x intercepts
X intercepts:
(-1/4,0),(3/2,0)
I need help with these problems!!!
How would I solve them, can someone explain the steps please, or check if there correct?
Answer:
Step-by-step explanation:
What is the length of the hypotenuse triangle
Answer:
The length of the hypotenuse of a right triangle can be found using the Pythagorean theorem, which states that the square of the length of the hypotenuse equals the sum of the squares of the lengths of the other two sides.
Step-by-step explanation:
Find the volume of a tennis ball with diameter of 6.7 centimeters. Round your answer to the nearest hundredth.
Answer:
157.48
Step-by-step explanation:
Heyo, I don't get where she got the 49 from, can someone help?
Answer:Instructions below
Step-by-step explanation:
This is completing the square, so what happened was that -14 was divided, then squared, to find a perfect square. To find the third term, you have to divide it by two then square it, then add it to the other side to balance the equation out.
-14/2 = -7^2 = 49 This applies to every question in which you have to complete the square
You roll two six-sided dice. What is the probability that the sum is odd or a multiple of 5? Round your answer to the nearest tenth of a percent.
Answer:
The probability that the sum is odd or a multiple of 5
P(E₁∪E₂) = 0.58 = 58%
Step-by-step explanation:
Step ( i ) :-
Given the two dice are thrown ,The total number of exhaustive cases
n(S) = 6² = 36
Let 'E₁' be the event of getting the sum is odd on two dice
E₁ = { (1,2)(1,4),(1,6),(2,1),(2,3),(2,5),(3,2)(3,4),(3,6),(4,1)(4,3),(4,5),(5,2),(5,4),(5,6),(6,1),(6,3),(6,5)}
n(E₁) = 18
Let 'E₂' be the event of getting the sum is multiple of 5 on two dice
E₂ = { (1,4),(2,3), (3,2),(4,1),(4,6),(5,5),(6,4)}
n(E₂) = 7
n(E₁∩E₂) = {(1,4),(2,3),(3,2),(4,1)} = 4
Step(ii):-
The probability that the event of getting the sum is odd on two dice
[tex]P(E_{1}) = \frac{n(E)}{n(S)} = \frac{18}{36}[/tex]
The probability that the event of getting the sum is multiple of '5' on two dice
[tex]P(E_{2}) = \frac{n(E_{2} )}{n(S)} = \frac{7}{36}[/tex]
The probability that the event of getting the sum is odd and multiple of '5' on two dice
[tex]P(E_{1} n E_{2}) = \frac{n(E_{1} n E_{2} )}{n(S)} = \frac{4}{36}[/tex]
The probability that the sum is odd or a multiple of 5
P(E₁∪E₂) = P(E₁) + p(E₂) - P(E₁ ∩ E₂)
= [tex]\frac{18}{36} + \frac{7}{36} - \frac{4}{36}[/tex]
[tex]\frac{18+7}{36} - \frac{4}{36} = \frac{25-4}{36} = \frac{21}{36}[/tex]
P(E₁∪E₂) = 0.58 = 58%
Final answer:-
The probability that the sum is odd or a multiple of 5
P(E₁∪E₂) = 0.58 = 58%
The probability that the sum is odd or a multiple of 5 is 56 %.
Probability :When two dice are rolled, then
Total number of outcomes is [tex]=6^{2}=36[/tex]
Outcomes for the sum is odd or a multiple of 5 ,
[tex](1,2),(2,1),(2,3),(3,2),(1,4),(4,1),(1,6),(6,1),(2,5),(5,2),(3,4)\\\\(4,3),(3,6),(6,3),(4,5),(5,4),(6,5),(5,6),(4,6),(6,4)[/tex]
Number of favourable outcomes are [tex]=20[/tex]
the probability that the sum is odd or a multiple of 5 is,
[tex]P(E)=\frac{20}{36} =0.56[/tex]
Learn more about the probability here:
https://brainly.com/question/24756209
Jessie installed 12 more axles than the number of engine blocks her friend Gus installed yesterday. Write an equation for g, the number of engine blocks Gus installed yesterday.
Answer:
g = j - 12
Step-by-step explanation:
Let's say Jessie installed j axles. Convert words to math:
- "12 more" = + 12
- "the number of engine blocks her friend Gus installed yesterday" = g
Put it together: g + 12. This is equal to j: j = g + 12. Solve for g:
j = g + 12
g = j - 12
Lets use the variables "a" and "g" to solve.
a = number of axles
g = number of engine blocks
If Jessie has 12 more axles than the number of engine blocks, this means we are adding (g + 12).
Now, we have the expression a = g + 12
Solve for g since we are finding the number of engine blocks Gus Installed.
a = g + 12
~Subtract 12 to both sides
a - 12 = g + 12 - 12
a - 12 = g
Therefore, the answer is [ a - 12 = g ]
Best of Luck!
Please try your best
Answer:
y= - 4/1x + 5
Step-by-step explanation:
Answer:
y=-4x+5
Step-by-step explanation:
4 equals the slope (rise over run) and 5 equals the y-intercept
How may cups are In a gallon
Answer:
I think it is 16 cups in a gallon
If f(1)=160 and f(n+1)=2(n) what is f(4)
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Cuáles de los siguientes experimentos son aleatorios. a) Número de personas que suben a un autobús en una parada. b) Aplicar el teorema de Pitágoras en un triángulo rectángulo. c) Conocer el ganador de la Liga de Campeones. D) Calcular la raíz cuadrada de un número.
Answer:
a) Número de personas que suben a un autobús en una parada.c) Conocer el ganador de la Liga de Campeones.Step-by-step explanation:
This problem is about random experiments.
Random experiments are defined as experiments where the outcome can't be predicted. To ensure that result, the subjects are selected randomly. So, in this case, the right answer must be a situation where subjects are randomly present.
People taking the bus is a random experiment, because there's no the exact subjects in a bus at any time, it happens randomly.
Also, the winner of a sport league is also a random experiment, because it happens after several games which cannot be predicted.
Therefore, the right answers are a and c.
Please help What is the value of S4 for
2.48
12.48
16
24
Answer:
B, 12.48 is the answer
Step-by-step explanation:
Just took the test
Answer:
its b just took the quiz on edge 2020
Step-by-step explanation:
What is the value of i^2
Answer: i^2 = -1
Step-by-step explanation:
NVM Ignore this answer (:::::::
Find the circumference of each circle.
Answer:The distance around a rectangle or a square is as you might remember called the perimeter. The distance around a circle on the other hand is called the circumference (c).
circle diameter radius
A line that is drawn straight through the midpoint of a circle and that has its end points on the circle border is called the diameter (d)
Half of the diameter, or the distance from the midpoint to the circle border, is called the radius of the circle (r).
The circumference of a circle is found using this formula: so the answer is B
Step-by-step explanation:
Kendra made a scaled copy of the following square. She used a scale factor less than 111. What could be the side length of the scaled copy of the square.
Answer:
B,C,E
Step-by-step explanation:
khan academy
Side length of the scaled copy of square is smaller than original.
What is scale factor?A scale factor is defined as the ratio between the scale of a given original object and a new object, which is its representation but of a different size (bigger or smaller).
Given,
Scale factor of scaled copy of square is less than 1.
Scale factor basically defines the ratio between the sides of the constructed square to that of the original square.
if scale factor is less than 1 then the sides of the constructed square is smaller than that of the original square.
Hence, side length of constructed square is smaller than the original square.
Learn more about scale factor here:
https://brainly.com/question/30215119
#SPJ2
If events A and B are independent, find P(A│B).
A. P(A)
B. 1
C. 0
D. P(A)/P(B)
Answer:
If events A and B are independent:
P(A|B) = P(A⋂B)/P(B) = (P(A) x P(B))/P(B) = P(A)
=> Option A is correct
Hope this helps!
:)
5 (3-n)=2n+1
How do I solve this problem? Please help me. Thank you very much.
Step-by-step explanation:
15 - 5n = 2n + 1
Bringing like terms on one side
15 - 1 = 2n + 5n
14 = 7n
14/ 7 = n
2 = n
Answer:
Step-by-step explanation:
First distribute. 5•3 and 5•n.
This gives you 15-5n=2n+1
Next add 5n to both sides.
This will give you 15=7n+1
Then you will subtract 1 from both sides.
14=7n
Finally you divide by 7 so you can get n by itself.
Your answer will be 2=n
You can always go back and plug your answer in to see if it works!
The given system of eqqations models the coins in a jar containing n nickels, d dimes, and a quarters. Which statement is
modeled by one of the equations in the system?
q- dun
0 250+ 0 100+ 0.05n-6.05
+0+-36
The number of nickels is equal to the total number of dimes and quarters
The total value of the coins in the jar is $36
There is a total of 36 coins in the jar
There is an equal number of nickels, dimes, and quarters
Answer:
Option (3).
Step-by-step explanation:
This question is incomplete; find the compete question in the attachment.
Equation (1): q = d + n
"Total number of quarters is equal to the sum of number of dimes and nickels."
Equation (2): 0.25q + 0.10d + 0.05n = 6.05
"Total value of the coins in the jar is $36"
Equation (3) : q + d + n = 36
"There are a total of 36 coins in the jar."
By comparing the options given, we find the third option which matches with equation (3)
Therefore, option (3) is the correct answer.
Ax +by=cz what is the answer ?
Answer:
ax=cz-by
ax then find it by taking numbersYou throw a ball up in the air.the basketball's height,in feet,is given by the function:h=-16t^2+30t+4,where t is the time in seconds after the ball leaves your hand.Find the greatest height the ball reaches(use a calculator).
Answer:
18.0625 ft
Step-by-step explanation:
Greatest height is when:
t = -b/2a
t = -30/2(-16)
t = 15/16
Greatest height is:
-16t(15/16)² + 30(15/16) + 4 = 289/16
= 18.0625m
What’s the value of the expression 16 -3/4
Answer:
15 1/4
Step-by-step explanation:
16-3/4
64/4-3/4
61/4
15 1/4
find -2-(-.7)
help me plz :(
Answer: 5
Step-by-step explanation:
two negatives equal a positive, so if you are subtracting with two negatives it just like 7-2 if that makes sense :)
Answer:
5
Step-by-step explanation:
you have to multiply the 2 negative signs in between of 2 and 7 and then you will get a positive sign
since the 2 signs are different you will need to subtract.
so 7-2 equals 5 and you put the bigger number's sign which is positive
See question above
A) 7.2 cm
B) 9 cm
C) 10.6 cm
D) 12 cm
Answer:
B) 9 cm
Step-by-step explanation:
Just look at the triangle and use Pythagoras theoreum.
a² + b² = c²
a = 9 9 - 4.9 = 5
b = ?
c = 10
5² + b² = 10²
b² = 100 - 25
b² = 75
b = + - SQRT( 75 )
{Only the positive term has a meaning here.}
b = 8.66 rounded that is 9, which is answer B.
Suppose that 15 years ago, a benefactor set up an account for your education. This benefactor made a single deposit of $20,000 that has been earning 6% interest compounded monthly. Since the deposit 15 years ago, no money has been added to or taken from the account. Will this account be sufficient to cover tuition for all four years that you will be in school? (Answer this question using the school that you chose for parts C and D and the formula given below.) Make sure that the "time in years" that you use is 15 years + the number of years you will be at school.
Answer:
No it wont
Step-by-step explanation:
A bottle contains 3 red marbles, 5 blue marbles and 2 green marbles. If a single marble is drawn from the bottle at random, what is the probability that the marble is green?
Answer:
1/5
Step-by-step explanation:
There are 3+5+2 = 10 marbles in the bottle
P(green) = number of green marbles/ total
= 2/ 10 = 1/5
Solve by factoring
6a^2=-23a-20
Answer:
x=[tex]\frac{-4}{3}[/tex] or x=[tex]\frac{-5}{2}[/tex] I suggest using the MathPapa or the Symbolab websites for more factoring problems.There is a bell at the top of a tower that is 45m high. The bell weighs 190 kg. How much potential energy does the bell have?
Answer:
83.79 kJ
Step-by-step explanation:
The potential energy is the product of weight and height, where weight is in newtons.
PE = Mgh = (190 kg)(9.8 m/s^2)(45 m) = 83,790 J
what did I do wrong? please help me.Solve the triangle. Round decimal answers to the nearest tenth. 85, 19, 47
Answer:
b is about 25.5, c is about 18.7
Step-by-step explanation:
Using the law of sines, you can find the measure of side b with the following equation:
[tex]\dfrac{\sin 48}{19}=\dfrac{\sin 85}{b}[/tex]
[tex]b\approx 25.5[/tex]
Similarly, for c, you can do the following:
[tex]\dfrac{\sin 48}{19}=\dfrac{\sin 47}{c}[/tex]
[tex]c\approx 18.7[/tex]
Hope this helps!
PQR is an isosceles triangle which PQ = PR
M and N are points on PQ and PR such that angle MRQ = angle NQR.
prove that triangles QNR and RMQ are congruent.
Answer:
∠NQR, ∠NRQ and side QR for ΔQNR is equivalent to ∠MRQ, ∠MQR and side QR, which defines the two triangles and proves that the two triangles are congruent
Step-by-step explanation:
Here, we have
ΔPQR is an isosceles triangle,
∠MRQ = ∠NQR
Therefore, since ∡R = ∡Q (Base angles of isosceles ΔPQR), then;
∠MRQ + ∡Q + ∠QMR = 180° = ∠NQR + ∡R + ∠RNQ (Sum of angles in a triangle)
Whereby ∠MRQ = ∠NQR and ∡R = ∡Q, we have;
∠MRQ + ∡Q = ∠NQR + ∡R which gives;
∠QMR = ∠RNQ
Which gives;
∠NQR, ∠NRQ and side QR for ΔQNR is equivalent to ∠MRQ, ∠MQR and side QR, which defines the two triangles and proves that the two triangles are congruent.
