Find the value of x.
Round to the nearest tenth.
A
X
29
B
50
26
C

x = [?]°

It will take 6 weeks for the number of infected people to reach 1200

The function is given as:

y equals 15 times 2 to the power of t

Rewrite the function properly as follows

y = 15 * 2^t

When the population is 1200, the equation becomes

15 * 2^t = 1200

Divide both sides by 15

2^t = 80

Take the logarithm of both sides

t * log(2) = log(80)

Divide both sides by log(2)

t = 6.3

Approximate

t = 6

Hence, it will take 6 weeks for the number of infected people to reach 1200

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The area of the small poster is 160 inches square

From the information given, we have the poster to take the form of a rectangle

The formula for area of a rectangle is;

Area = length × width

For the smaller poster created using a scale of factor 2/3

Length = 2/ 3 × 24

Length = 16 inches

Width = 2/ 3 × 15

Width = 10 inches

Substitute into the formula

Area = 16 × 10

Area = 160 inches square

Thus, the area of the small poster is 160 inches square

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Answer:

35,000 - 8000=27,000 altitude

Information : The given hyperbola is a horizontal hylerbola with its centre (3 , -5) and one of its focus at (9 , -5) and vertex at (7 , -5) and as we can see that the focus and vertex have same y - coordinates, it must have its Transverse axis on line y = - 5.

Now,

it's vertex is given, I.e (7 , -5)

so, length of semi transverse axis will be equal to distance of vertex from centre, i.e

Now, it's focus can be represented as ;

[tex]\qquad \sf  \dashrightarrow \: (3 + ae, - 5 )[/tex]

so,

and we know, a = 4

[tex]\qquad \sf  \dashrightarrow \: 4e + 3 = 9[/tex]

[tex]\qquad \sf  \dashrightarrow \: 4e = 6[/tex]

[tex]\qquad \sf  \dashrightarrow \: e = \cfrac{3}{2} [/tex]

Now, let's find the measure of semi - conjugate axis (b)

[tex]\qquad \sf  \dashrightarrow \: {b}^{2} = {a}^{2} ( {e}^{2} - 1)[/tex]

[tex]\qquad \sf  \dashrightarrow \: {b}^{2} = 16( \frac{9}{4} - 1)[/tex]

[tex]\qquad \sf  \dashrightarrow \: {b}^{2} = 16( \frac{9 - 4}{4} )[/tex]

[tex]\qquad \sf  \dashrightarrow \: {b}^{2} = 16( \frac{5}{4} )[/tex]

[tex]\qquad \sf  \dashrightarrow \: {b}^{2} = 20[/tex]

[tex]\qquad \sf  \dashrightarrow \: b = \sqrt{20} [/tex]

So, it's time to write the equation of hyperbola, as we already have the values of a and b ~

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {(x - h)}^{2} }{ {a}^{2} } - \cfrac{( {y - k)}^{2} }{ {b}^{2} } = 1[/tex]

[ plug in the values, and h = x - coordinate of centre, and k = y - coordinate of centre ]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ ({x-3)}^{2} }{ {16}^{} } - \dfrac{ {(y+5)}^{2} }{ { {20} }^{} } = 1[/tex]

Hello and Good Morning/Afternoon:

Let's solve this problem step-by-step:

Let's find the format of the standard form of hyperbole:

 [tex]\hookrightarrow \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2} =1[/tex]

Let's find the value of a, b:

             [tex]a = \sqrt{(7-3)^2+(-5--5)^2} =\sqrt{16} =4[/tex]

           ⇒value of c: distance between focus (9, -5) and center (3, -5)

                  [tex]c = \sqrt{(3-9)^2+(-5--5)^2}=\sqrt{36} =6[/tex]

            ⇒ therefore:

                  [tex]b = \sqrt{c^2-a^2} =\sqrt{6^2-4^2}=\sqrt{20}[/tex]

Let's plug everything into our standard form of the equation:

   [tex]\frac{(x-3)^2}{4^2} -\frac{(y--5)^2}{(\sqrt{20})^2 } =1\\\frac{(x-3)^2}{16} -\frac{(y+5)^2}{20 } =1[/tex] <== Answer

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Answer: tan 1 radians = 1.557, tan 1 degrees = 0.017

Answer:

b

Step-by-step explanation:

b

According to the confidence interval only persons who watch at least 9.9 hours TV per day are eligible.

According to the statement

we have given that the mean of 7 hours per day watching TV, and a standard deviation of 1.8 hours.

And we have to find that the At least how many hours of daily TV watching are necessary for a person to be eligible for the interview.

So, For this purpose,

The confidence interval is is a range of estimates for an unknown parameter. A confidence interval is computed at a designated confidence level.

Let us Assume x is the amount of hours that 5% of the persons exceeds.

Then P(z<(x-7)/1.8) = 0.95

From a standard normal table, we know that:

(x-7)/1.8 = 1.6449

x-7 = 2.9607

x = 9.9607

So, According to the confidence interval only persons who watch at least 9.9 hours TV per day are eligible.

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The pair of functions that are inverses of each other is (a) f(x) = 5x - 11 and g(x) = (x + 11)/5

The complete question is added as an attachment

Function 1

f(x) = 5x - 11 and g(x) = (x + 11)/5

Represent 5x - 11 with y in f(x) = 5x - 11

y = 5x - 11

Swap x and y

x = 5y - 11

Add 11 to both sides

x + 11 = 5y

Divide by 5

y = (x + 11)/5

Express as a function

g(x) = (x + 11)/5

From the question, we have:

f(x) = 5x - 11 and g(x) = (x + 11)/5

This means that the function g(x) is an inverse of the function f(x)

Hence, the pair of functions that are inverses of each other is (a) f(x) = 5x - 11 and g(x) = (x + 11)/5

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Answer:

There are 5 ways to find if two triangles are congruent.

SSS- {Side Side Side Congruence.}

This law of congruence states that if we have two triangles, each with the same measures on each 3 sides it deems the triangles congruent.

SAS- {Side Angle Side Congruence.}

This law of congruence states that if we have two triangles, with 2 equal sides and one angle which is common among them; the triangles are congruent.

ASA- {Angle Side Angle Congruence.}

This law of congruence states that if we have two triangles, with 2 congruent angle measures and 1 congruent side; the triangles are indeed congruent.

AAS- {Angle Angle Side Congruence.}

You may be wondering how this law of congruence differs from the previous one. ASA refers to any two angles and the included side, whereas AAS refers to the two corresponding angles and the non-included side.

HL- {Hypotenuse Leg Congruence.}

This law of congruence states that if we have two triangles, with a common (congruent) leg and hypotenuse; the triangles are congruent.

I really hoped this helped, if it didn't leave a comment I am always open to feedback. If it did let me know, brainiest is always appreciated!

Hope you have a great rest of your day.

Answer:

Step-by-step explanation:

for completeness, here is the answer again:

1 Given is correct

2 Definition of right angle is correct

3 should be sum of interior angles in a triangle

4 is substitution

5 subtracting 90degree from left and right hand side

6 is definition of complementary angles

Answer:

123 soda and 87 hot dogs

Step-by-step explanation:

Let s = # soda and h = # hot dogs

s +  h = 210         s = h + 36  Substitute the h + 36 for s into the first equation

s + h = 210

(h + 36) + h = 210  

h + 36 + h = 210  Combine the h's

2h + 36 = 210  Subtract 36 from both sides

2h = 174  Divide both sides by 2

h = 87  This is the number of hot dogs.  Substitute this into either equation above to find the sodas.        

s + h = 210

s + 87 = 210

s = 123  

OR

s = h + 36

s = 87 + 36

s = 123

Answer:

matrices can be added together if both have the same order

Addition is both commutative and associative

matrices can be multiplied together if the number of column in the right hand matrix equals the number of row in the left hand matrix

Answer:

m∠RQS = 109°

Step-by-step explanation:

Angles on a straight line sum to 180°.

Therefore:

⇒ m∠RQS + m∠SQT = 180°

⇒ (15x + 4) + (10x + 1) = 180

⇒ 15x + 4 + 10x + 1 = 180

⇒ 15x + 10x + 4 + 1 = 180

⇒ 25x + 5 = 180

⇒ 25x + 5 - 5 = 180 - 5

⇒ 25x = 175

⇒ 25x ÷ 25 = 175 ÷ 25

⇒ x = 7

Now that we have found the value of x, substitute this into the expression for m∠RQS:

⇒ m∠RQS = 15(7) + 4

                  = 105 + 4

                  = 109°

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Answer: Pr(4.19 ≤ X ≤ 4.81)

Step-by-step explanation:

First of all, let's calculate the mean;

x¯ = (4.3 + 5.1 + 3.9 + 4.5 + 4.4 + 4.9 + 5.0 + 4.7 + 4.1 + 4.6 + 4.4 + 4.3 + 4.8 + 4.4 + 4.2 + 4.5 + 4.4)/17

x¯ = 76.5/17

x¯ = 4.5

We are given standard deviation; s = 0.31

Now, z-value for a 68% Confidence interval is 1

Range in which the data falls is;

Range = x¯ ± zs

Range = 4.5 ± (1 × 0.31)

Range is;

Pr[(4.5 - 0.31) ≤ X ≤ (4.5 + 0.31)]

Pr(4.19 ≤ X ≤ 4.81)

Answer:

Pr (3.57 ≤ X ≤ 5.43)

Step-by-step explanation:

Took the quiz.

The length of the transverse axis is 8.

Given the equation of hyperbola:[tex]\frac{(y-2)^{2} }{16}[/tex][tex]-\frac{(x+1)^{2} }{144 }[/tex][tex]=1[/tex]

Rewrite this equation as [tex]\frac{(y-2)^{2} }{4^{2} }[/tex][tex]-\frac{(x+1)^{2} }{12^{2} }[/tex][tex]=1[/tex]

When comparing this equation to the common hyperbola equation with a vertical transverse axis is [tex]\frac{(y-k)^{2} }{a^{2} }[/tex][tex]-\frac{(x+h)^{2} }{b^{2} }[/tex][tex]=1[/tex]

[tex]h = -1[/tex]

[tex]k= -2[/tex]

[tex]a = 4[/tex]

[tex]b = 12[/tex]

The length of the transverse axis is[tex]2a = 2*4[/tex]

                                                               [tex]=8.[/tex]

The length of the transverse axis is 8.

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Answer:

For example, 8f + 4g is one of the most used expression

Another example is 4 (2f + g), is correct too

Answer: 2 radians

Step-by-step explanation: You welcome

The time at which the break started is 10 : 30 am.

The first step is to convert the time between  10:00 a.m. - 11:15 a.m. to minutes.

The time  between  10:00 a.m. - 11:15 a.m. is 1 hour 15 minutes

In order to convert hours to minutes, multiply hour by 60

1 x 60 = 60 minutes

60 minutes +  15 minutes =  75 minutes

The second step is to subtract the time from the break from the duration of the golf lesson

75 minutes -  15 minutes = 60 minutes

The third step is to divide 60 minutes into equal halves by dividing 60 by 2

60 / 2 = 30 minutes

The last step is to add 30 minutes to the time the lesson started : 10 : 00 am + 30 minutes = 10 : 30 am

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Step-by-step explanation:

=(7x)^2-(y)^2

=(7x+y) (7x-y)

Therefore, a^2-b^3

=(a+b) (a-b)

If the sample size is 1488 and confidence interval of 99% then the margin of error is 0.03088.

Given sample size of 1488, percentage of those polled own a home be 69% and confidence level be 99%.

We are required to find the approximate margin of error.

Margin of error is the difference between calculated values and real values.

n=1488

p=0.69

Margin of error=z*[tex]\sqrt{p(1-p)/n}[/tex]

Z score when confidence level is 99%=2.576.

Margin of error=2.576*[tex]\sqrt{0.69(1-0.69)/1488}[/tex]

=2.576*[tex]\sqrt{(0.69*0.31)/1488}[/tex]

=2.576*[tex]\sqrt{0.2139/1488}[/tex]

=2.576*[tex]\sqrt{0.0001437}[/tex]

=2.576*0.01198

=0.03088

Hence if the sample size is 1488 and confidence interval of 99% then the margin of error is 0.03088.

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Answer:

0.031

Step-by-step explanation:

Plato/Edmentum

Answer: for number 3, x= 6

Step-by-step explanation:

Answer: 425

Step-by-step explanation:

Think of this problem as 4% of a number equals 17

since in math, the word 'of' usually means multiplication, we can think of it that way.

Also, 4% = 0.04

[tex]x*0.04=17[/tex]

[tex]0.04x=17[/tex]

[tex]\frac{0.04x}{0.04} =\frac{17}{0.04}[/tex]

[tex]x=425[/tex]

Answer:

15 days

Step-by-step explanation:

5 workers times 12 days is 60 days per worker which gets reduced based on how many workers there are. 60 divide by 4 workers now brings down to 15 days. 5 workers, 12 days. 10 workers 6 days etc.

Answer:

963 hours

Step-by-step explanation:

I subtracted 20 from the 981

The correct answer for the hours elaine spend attending classes is  [tex]817.5[/tex]  hours.

Given,

The time spent doing homework was 20% less than the time she spent attending class.

Assume the time Elaine spent attending class is "x" hours.

So, the time spent on these activities is 0.2 * x hours.

Now, the total time  spent attending class, doing homework, or  in extracurricular activities is 981 hours.

The equation representing the total time is:

[tex]x + 0.2x = 981[/tex]

solve for "x":

[tex]1.2x = 981[/tex]

[tex]x= \dfrac{981}{1.2}[/tex]

[tex]x= 817.5[/tex]

Elaine spent approximately [tex]817.5[/tex] hours attending class.

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Parent function = √x

On stretching vertically by factor of 6

New function G(x) = 6√x

=============================================================

Explanation:

The probability of getting heads is 1/2 because there's one side we want out of two sides total

The probability of getting less than 3 is 2/6 = 1/3 since we have two sides we want (rolling a "1" or a "2") out of six sides total.

Multiply the two mentioned fractions: 1/2 times 1/3 = 1/6

1/6 can be written as "one sixth", but I prefer the first format better since it's shorter.

---------------

If you are a visual learner, you can make a table with 2 rows and 6 columns, or vice versa (6 rows and 2 columns). The order doesn't matter.

The two rows represent the events Heads or Tails. The 6 columns show the different outcomes on the number cube. We have 6*2 = 12 different outcomes of rolling a die and flipping a coin.

Of those 12 outcomes, shade in 2 boxes to represent getting heads and either a "1" or "2". Refer to the diagram below.

We have 2 shaded rectangles out of 12 total to get 2/12 = 1/6

The visual representation of a table like this may help show why we multiplied the fractions 1/2 and 1/3 to get the answer. Hint: think of area = length*width.

The probability of getting heads on the coin and a number less than 3 on the number cube is 1/6, Option A is correct.

It is a branch of mathematics that deals with the occurrence of a random event.

Given,

A coin is flipped, and a number cube is rolled.

We need to find the probability of getting heads on the coin and a number less than 3 on the number cube.

The probability of getting heads when flipping a coin is 1/2

The probability of getting less than 3 is 2/6 = 1/3 since we have two sides

Now  the probability of getting heads on the coin and a number less than 3 on the number cube

The product of 1/2 and 1/3

1/2×1/3

1/6

Hence, the probability of getting heads on the coin and a number less than 3 on the number cube is 1/6, Option A is correct.

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Using it's concept, the probabilities are given as follows:

a) C. 7/20.

b) D. 15/22.

A probability is given by the number of desired outcomes divided by the number of total outcomes.

For item a, we have that there are 60 students with no curfew, and of those, 21 have no chores, hence the probability is given by:

p = 21/60 = 7/20

Which means that option C is correct.

For item b, we have that there are 66 students with no shores, and of those, 45 have a curfew, hence the probability is given by:

p = 45/66 = 15/22

Which means that option D is correct.

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The correct answer which represents the quotient of 20√z⁶ ÷ √16z⁷ in simplest radical form is; (5√z)/z.

The quotient given can be evaluated by means of the laws of indices as follows;

20√z⁶ ÷ √16z⁷

= 20√z⁶ ÷ 4√z⁷

= 5 √(z⁶/z⁷)

= 5 √z^(-1)

= 5 × z^(-1/2)

= 5/√z

Hence, by rationalisation; we have;

= (5√z)/z.

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The implied enterprise value of Snap Inc., calculated using the assumptions and acquisition premium provided, is $91,669

Share Price, P = 44.29

Premium on the acquisition, p = 20%

Therefore, effective share price for acquisition, P* = P x (1 + p) = 44.29 x (1 + 20%) = $ 53.15

Number of shares outstanding, N = 1,734 MM

Equity value, E = P* x N = 53 x 1,734

= $92,158.63 MM

Net Debt, D = - 496

Hence, the implied enterprise value:

= Equity value + net debt

= 92,158.63 + (- 496)

= $$91,669

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Answer:

[tex]\textsf{A)} \quad (x-40)^2=-100(y-16)[/tex]

B)  Focus = (40, -9)

    Directrix:  y = 41

    Axis of symmetry:  x = 40

Step-by-step explanation:

The x-intercepts of a parabola are the points at which the curve intercepts the x-axis (when y = 0).

The x-coordinate of the vertex of a parabola is halfway between the x-intercepts.

The y-coordinate of the vertex if the minimum or maximum height of the parabola.

A jumping spider's movement is modeled by a parabola.

Define the variables:

From the information given:

Standard form of a parabola with a vertical axis of symmetry:

[tex](x-h)^2=4p(y-k) \quad \textsf{where}\:p\neq 0[/tex]

If p > 0, the parabola opens upwards, and if p < 0, the parabola opens downwards.

Substitute the vertex (40, 16) and one of the x-intercept points (0, 0) into the formula and solve for p:

[tex]\implies (0-40)^2=4p(0-16)[/tex]

[tex]\implies 1600=-64p[/tex]

[tex]\implies p=-25[/tex]

Substitute the vertex and the found value of p into the formula:

[tex]\implies (x-40)^2=4(-25)(y-16)[/tex]

[tex]\implies (x-40)^2=-100(y-16)[/tex]

Given:

Substitute the given values into the formulas for focus, directrix and axis of symmetry:

Focus

⇒ (h, k+p)

⇒ (40, 16 + (-25)))

⇒ (40, -9)

Directrix

⇒ y = (k-p)

⇒ y = (16 - (-25))

⇒ y = 41

Axis of symmetry

⇒ x = h  

⇒ x = 40