1. phase difference = 45.1318°
2. phase difference = 54.52°
3. phase difference = 62.153°
Case 1: C = 56.4 ₙF
V₁ = [tex]\frac{156}{\sqrt[]{2} }[/tex]
[tex]x_{c}[/tex] = [tex]\frac{1}{2\pi fc}[/tex]
[tex]x_{c}[/tex] = [tex]\frac{1}{2\pi * 60*56.4*10^{-9} }[/tex]
[tex]x_{c}[/tex] = 47.031 KΩ
here, [tex]V_{0} = V_{A}[/tex]
[tex]X_{L}[/tex] = 2πfL
[tex]X_{L}[/tex] = 2π x 60 x 125
[tex]X_{L}[/tex] = 94.247 KΩ
Apply KCV of node "A"
[tex]\frac{V_{A}-0 }{-jX_{c} +jX_{L}+R_{2} }[/tex] + [tex]\frac{V_{A} -V_{1} }{R_{1} }[/tex] = 0
[tex]V_{A}[/tex] ( [tex]\frac{1}{R_{2} +j(X_{L} -X_{C} )} + \frac{1}{R}[/tex] ) = [tex]\frac{V_{1} }{R_{1} }[/tex]
[tex]V_{A}[/tex] ( [tex]\frac{1}{47 + j(94.247 - 47.031)} + \frac{1}{67}[/tex] = [tex]\frac{156/\sqrt[]{2} }{67}[/tex]
[tex]V_{0} = V_{A} = \frac{84.227}{\sqrt{2} }[/tex]
[tex]V_{A}[/tex] = 84.227 sin (2π x 60t + 22.663) Volts
[tex]V_{R} _{1}[/tex] = [tex]V_{1}[/tex] = [tex]V_{A}[/tex] = [tex]\frac{84.706}{\sqrt{2} }[/tex]
V[tex]R_{1}[/tex] = 84.706 sin [2π x 60t + (-22.498°)] Volts
phase difference = 22.6333 - (-22.498)
phase difference = 45.1318°
Case 2: C = 100ₙF
[tex]X_{C}[/tex] = [tex]\frac{1}{2\pi * 60 * 100 * 10^{-9} }[/tex]
[tex]X_{C}[/tex] = 26.525 Ω
[tex]V_{0}[/tex] = [tex]\frac{156}{\sqrt{2} }[/tex] x [tex]\frac{R_{2} + j (X_{L} - X_{C}) }{R_{1} + R_{2} +j(X_{L} - X_{C} )}[/tex]
[tex]V_{0}[/tex] = [tex]\frac{96.98}{\sqrt{2} }[/tex] [tex]\\ 24.52[/tex]° Volts
[tex]V_{R1}[/tex] = [tex]V_{1}[/tex] - [tex]V_{0}[/tex] = [tex]\frac{78.82}{\sqrt{2} }[/tex] -30° Volts
phase difference = 24.52 - (-30)
phase difference = 54.52°
Case 3: C = 500ₙF
[tex]X_{C[/tex] = 5.305 KΩ
[tex]V_{0}[/tex] = [tex]\frac{156}{\sqrt{2} }[/tex] ([tex]\frac{47 + j 94.247 - j 5.305}{67 + j 94.247 - j 5.305 + 47}[/tex])
[tex]V_{0}[/tex] = [tex]\frac{108.533}{\sqrt{2} }[/tex] (24.186°)
[tex]V_{R1} = V_{1} - V_{0}[/tex] = [tex]\frac{72.28}{\sqrt{2} }[/tex] (-37.967°) Volts
phase difference = 24.186 - (-37.967) Volts
phase difference = 62.153°
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A man wishes to pull a crate 15m across a rough floor by exerting a force of 100 n. The coefficient of kinetic friction is 0. 25. For the man to do the least work, the angle between the force and the horizontal should be:.
For the least amount of work, the exerting a force angle from horizontal is 76 degree.
How do you compute the angle between exerting the force and the horizontal plane?Fcosθ−μN=maFcosθ−μN=ma
N+Fsinθ−mg=0N+Fsinθ−mg=0
(Unless Fsin>mgFsin>mg)
The angle is measured from the horizontal, and N is the upward normal force to the surface.
Work is defined as force times distance in the direction of motion... or a shift in energy. You want the man to do the work... guess: whole work. So attempt to accelerate the box (madmad) and against friction (NdNd).
So, how about this:
Minimizing force reduces effort for the same distance. As a result, we want the vertical component of force to be equal to and opposite to the weight. Any higher, and there is extra work propelling the box upwards.
This entirely removes friction, leaving only madness.
θ=sin−1[mg/F]
θ=sin−1[mg/F]
W=Fdcosθ+μNd
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at this solar plant, more than 1,000 freestanding computer-controlled mirrors follow the arc of the sun and focus their reflecting sunlight toward a 40-story-high tower (see photo), where water is boiled, generating steam to drive a turbine that, in turn, produces electricity.
Computer-controlled flat mirrors (called heliostats) track the sun along two axes and focus solar energy on a receiver at the top of a high power.
The focused energy is used to heat a transfer fluid (over 1,000° F) to produce steam and run a central power generator a solar power plant called Cesar 1 consisting of an 80 m high concrete tower with several receivers and a heliostat field of 300 units of 40m^2 each producing electric power of 1 MWe. From: The Institute of Energy's Second International Conference on Ceramics in Energy Applications, 1994.
Electric utility companies are using mirrors to concentrate heat from the sun to produce environmentally friendly electricity for cities, especially in the southwestern United States. The southwestern United States is focusing on concentrating solar energy because it's one of the world's best areas for sun- light.
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Please help me please I will give brainliest
A car covers the road from city A to city B, 40 km, in 30 minutes, and the road from city B to C, 30 km, in 15 minutes. find the average speed with which the car moves all the way from A to C
Answer:
0.667m/s
Explanation:
since speed(v) = d/t
average Speed(v) = d1 - d2/ t1 - t2
40-30/ 30-15
= 0.667m/s
Find the Fermi energy ef for a three-dimensional relativistic electron gas in which the energy of the electrons is given by = p?c? + m²c4. Take the non-relativistic limit of your expression for ef and comment on the result.
The non-relativistic limit of your expression for Fermi energy (ef) is shown in the figure below please convey to that figure.
The Fermi energy is the energy difference between the highest and lowest occupied single-particle states in a quantum system of non-interacting fermions at absolute zero temperature. The lowest occupied state in a Fermi gas is supposed to have no kinetic energy, in contrast to the lowest occupied state in a metal, which is frequently thought to represent the bottom of the conduction band. The term "Fermi energy" is frequently used to refer to the Fermi level, a different but closely related concept (also called electrochemical potential). At least in the context of this article, the Fermi level and Fermi energy differ significantly from one another: The Fermi level is defined at any temperature, but the Fermi energy is only stated at absolute zero. The Fermi level is a total energy level made up of both kinetic energy and potential energy (often corresponding to a kinetic energy). Even in complex interacting systems in thermodynamic equilibrium, the Fermi level is well defined, while the Fermi energy can only be specified for non-interacting fermions.
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a 6.00 gg bullet is fired horizontally into a 1.20 kgkg wooden block resting on a horizontal surface. the coefficient of kinetic friction between block and surface is 0.200. the bullet remains embedded in the block, which is observed to slide 0.200 mm along the surface before stopping. (a) What was teh initial speed of the bullet?
(b) What kind of collision took place between the bullet and the block? Explain your answer comparing the values of the kinetic energy before and after the collision.
(c) Calculate the impulse of the block from the moment just after the impact to his final position. Analyze the result.
The initial speed of the bullet should be 159.32 m/s.
What was the initial speed of the bullet?Let the initial speed of the bullet be V.
Momentum will be conserved after bullet hits the block . If v₁ be the common velocity of bullet block system
6.00 x 10⁻³ x V + 0 = ( 6 x 10⁻³ + 1.2 ) v₁
= ( 6 + 1200 ) x 10⁻³ v₁
v₁ = (6 / 1206 ) x V
1 / 201 V
Now the moving bullet - block system faces friction force and ultimately they come to rest , so
Kinetic energy of bullet block system = work done by friction
Kinetic energy of bullet block system =
1/2 x ( 6 + 1200 ) x 10⁻³ x ( 1 / 201 V )²
work done by friction
= frictional force x displacement
μ mg x d ( μ is coefficient of friction of surface , m is mass of the bullet block system and d is displacement )
0.16 x ( 6 + 1200 ) x 10⁻³ x 9.8 x .2
= 38.592 x 9.8 x 10⁻³
1/2 x ( 6 + 1200 ) x 10⁻³ x ( 1 / 201 )² V ² =
= 38.592 x 9.8 X 10⁻³
V² = 25382.65
V = 159.32 ms⁻¹
What kind of collision took place and calculate the impulse of the block?The impulse of the friction force produced by the surface during the impact is disregarded when we apply conservation of momentum to the collision. This makes sense given that the force is far less than the forces that the bullet and block will exert on one another when they collide. The block moves after the collision and is affected by this force, which removes all of the kinetic energy.
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What are the 7 stages of mitosis in order?.
There are five phases namely, prophase, prometaphase, metaphase, anaphase and telophase. Final cell division after telophase, cytokinesis is regarded as the sixth phase of mitosis.
Mitosis begins with the prophase.
Chromosomes gather and are made visible. Centrosomes are the origin of spindle fibres.Nucleolus dissolves as nuclear envelope disintegrates.
Second stage of mitosis is known as prometaphase. Chromosomes continue to compact. Centrosomes travel in the direction of their opposite poles as mitotic spindle microtubules attach to kinetochores.
Third phase is metaphase. Each chromosome is in the centre.
The fourth stage is known as anaphase. Sister chromatids which were previously bound together by cohesin proteins, separate and are drawn in opposite directions.
The fifth stage is called telophase. The nuclear envelope material that surrounds each set of chromosomes decondenses as the chromosomes arrive at opposite poles.
The last stage of mitosis is known as cytokinesis. In animal cells, the daughter cells are divided by a cleavage furrow.
The splitting of cytoplasm into two distinct daughter cells happen in plant cells.
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How will the weight and mass of a rover on Mars compare to its weight and mass on Earth?.
The mass of a frame or object on the surface of the Earth is similar to its mass on the floor of Mars. this is because the composition and the quantity of count in that body or object remain the same.
Wm=mgm=500×3.seventy one=1855 N. W m = m g m = 500 × 371 = 1855 N . Calculating R, the ratio of weights of the rover on Mars to its weight on the planet R=WmWe=18554905=0.38.
This is due to the fact weight is the dimension of the pressure of gravity on an object. although the individual could incorporate an identical quantity of depending, their weight might most effectively be 38% of their weight in the world. this is because the force of gravity is lower on Mars.
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A plant cell is no longer capable of capturing energy from sunlight and converting it into chemical energy. Which organelle is most likely damaged?.
The chloroplast of the cell is most likely damaged if the plant cell is no longer capable of capturing energy from sunlight and converting it into chemical energy.
The chloroplast is the structure inside the leaf cell that is known for capturing light energy from the sun.
This light energy is then used to make food that has chemical energy. If a plant cell has a damaged chloroplast or the chloroplast is removed, then it will no longer be able to trap the light energy. As a result, the process of photosynthesis will not occur in the plant cell. The plant cell will not be able to make the chemical energy required for functioning.
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Which of following is not a polynomial?.
Out of the following option A, option B and option D are not polynomials.
A ) x² + 1 / x,
This can be written as x² + x⁻¹.
Since the exponent of the variable in second term is negative, it is not a polynomial.
B ) 2 x² - 3 √ x + 1,
This can be written as 2 x² - 3 x ^ 1 / 2 + 1.
Since the exponent of the variable in second term is rational, it is not a polynomial.
C ) x³ - 3 x + 1.
This is a polynomial because all the exponentials are positive whole numbers.
D ) 2 x ^ 3 / 2 - 5 x.
Since the exponent of the variable in first term is rational, it is not a polynomial.
Therefore, option A, B and D are not polynomials.
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what factor(s) determine the speed of wind-blown waves in deep ocean? what factor(s) determine the speed of tsunami wave?
The speed of a tsunami depends on the depth of the water it is traveling through. The deeper the water; the faster the tsunami.
What is windspeed?
In meteorology, wind speed, also known as wind flow speed, is a fundamental atmospheric quantity brought on by air shifting from a state of high to low pressure, frequently as a result of temperature changes. Nowadays, an anemometer is frequently used to measure wind speed.
What is tsunami?
A tsunami is a set of waves brought on by a disturbance. Similar to the ripples created when a stone is thrown into a pond, a tsunami can be produced by a disturbance that moves the water vertically (a sudden drop or a sudden rise).
Three factors influence the formation
Windspeed;
Length of time the wind has blown over a given area; and
Distance of open water that the wind has blown over (called fetch).
The speed of a tsunami depends on the depth of the water it is traveling through. The deeper the water; the faster the tsunami. As the water depth decreases, the tsunami slows. The tsunami's energy flux, which is dependent on both its wave speed and wave height, remains nearly constant.
Therefore, the speed of a tsunami depends on the depth of the water it is traveling through. The deeper the water; the faster the tsunami.
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What is the primordial heat?.
The intrinsic heat energy generated via evaporation in a planet throughout its initial several million years of evolution is referred to as primordial heat.
The interior heat energy generated via dispersion in a planetary during its initial few million years of existence is known as primordial heat. The primary sources of primordial heat were accretional energy (the energy deposited based on the forecasted planetesimals) as well as differentiation energy.
The heat lost mostly by Earth as it cools from its initial formation has been referred to as primordial heat.
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how will you know that the pressure of your system is equalized and that it is okay to record an initial and/or final volume?
when the burets' and the funnel's meniscus are at a same height. The system will be under equal pressure at this moment. This will equalize the pressure in your system.
And that it is acceptable to record the first and/or last volume. In contrast to an articular disc, which completely divides a joint cavity, a meniscus is a crescent-shaped fibrocartilaginous anatomical structure. meniscus are found in the knee, wrist, sternoclavicular, acromioclavicular, and temporomandibular joints in humans; they may also be found in other joints in other animals.
The force perpendicular to an object's surface that is delivered per unit area over that force is known as pressure.
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at time t 0 a solid conducting sphere is given total charges q that is uniformly spread throughout its volume. twi students discuss whether or not this charge distribution is stable
At time t = 0 a solid conducting sphere is given total charges q that is uniformly spread throughout its volume it is a stable distribution.
Why is it stable ?Student 1 : At time t = 0 a solid conducting sphere is given total charges q that is uniformly spread throughout its volume it is a stable distribution.
Student 2 : No its a unstable distribution.
Student 1 : But when the charges are equally given in the volume of sphere the charges will also be equal and when charges are equal it is said to be stable.
Student 2 : What about the resonance, because of it the stability may not exist.
Student 1 : When we talk about resonance here we just mean the charge distribution over two different atoms in a molecule.
Student 2 : As you know, resonance structures are considered to be more stable due to charge distribution.
Student 1 : If the charge is distributed between two atoms in the molecule, there is a gap between the charges and it is less repulsive and more stable than a molecule with no charge distribution.
Student 2 : In resonance , generally the negative charge goes on most electronegative atom.
Student 1 : Yes but on the other hand, the molecule gains stability because the positive charge is transferred to the less electronegative atom.
What is stable distribution?A stable distribution is when the charges are equally given in the volume of sphere the charges will also be equal .
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a single rectangular slit of width of 50 is illuminated by red light with a wavelength of 600 nm. a screen is placed a certain distance behind the slit so that the central bright band of the diffractio pattern is 18 mm wide
A single rectangular slit of width of 50 is illuminated by red light with a wavelength of 600 nm and a screen is placed a certain distance behind the slit so that the central bright band of the diffraction pattern is 18 mm wide then the width of slit is 1.667 mm .
How is the width calculated?Given ,
λ = 600 × 10⁻⁹
D = 50
d = 18 mm
The position of central maxima in the diffraction pattern is
w = Dλ / d
∴ w = (50 × 600 × 10⁻⁹ ) / (18 × 10⁻³ )
∴ w = 30000 × 10⁻⁹ / 18 × 10⁻³
∴ w = 30 × 10⁻⁶ / 18 × 10⁻³
∴ w = 1.667 × 10⁻³
∴ w = 1.667 mm
Hence, the width of the central bright fringe of the diffraction pattern will be 1.667 mm.
What is the central bright band of diffraction?The width of the central diffraction peak is found to be inversely proportional to the slit width. Increasing the width magnitude a decreases the angle θ at which the intensity first goes to zero, narrowing the central band.Reducing the width of the slit also increases the angle θ and widens the central band. The width and spacing of the bright bands on the screen behind the slit depend on the distance between the slit and the screen.Therefore, the light intensity distribution becomes diffracted light.
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in considering the earth-moon orbital system, complete the following statements: the earth has the same strength gravitational pull on the moon than moon has on the earth, because of newton's 3rd law . the acceleration of the moon is less than the earth's acceleration.
The statement ' the earth has the same strength gravitational pull on the moon than the moon has on the earth, is because of Newton's 3rd law. The acceleration of the moon is less than the earth's acceleration' is true.
According to Newton's third law of motion, there is an equal and opposite reaction to every force. Hence, according to Newton's third law, the force with which the moon pulls the earth is equal and opposite to the force with which the earth pulls the moon. The force that is exerted by the earth on the moon will be called as the gravitational pull.
However, the acceleration of the earth is more as compared to that of the moon. This is because the earth travels a larger distance as compared to than of the moon. Hence, the statement above is true.
The question will correctly be written as:
The earth has the same strength gravitational pull on the moon than moon has on the earth, because of Newton's 3rd law. the acceleration of the moon is less than the earth's acceleration. true or false
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The following images show four identical Sun-like stars and their companion planets, all traveling in circular orbits. In each case, the mass of the planet is given in Jupiter masses and the orbital distance is given in Astronomical Units (AU). Rank each case based on the strength of the gravitational force exerted by the extrasolar planet on its central star, from weakest to strongest. If you think that two (or more) diagrams should be ranked as equal, drag one on top of the other(s) to show this equality. (Not to scale)
Weakest- one Jupiter mass and 2 Au
Same- Four Jupiter Masses 2 AU & 1 Jupiter mass 1AU
Strongest- 2 Jupiter masses 1 AU
One Jupiter mass and 2 Au are the weakest. The same: Four Jupiter masses of 2 AU and one Jupiter mass of 1 AU and Strongest: 1 AU and 2 Jupiter masses.
By far the largest planet in the solar system, Jupiter is more than twice as massive as all the other planets put together. Jupiter is the fifth planet from our Sun. The swirls and stripes of Jupiter are actually ammonia and water clouds floating in a hydrogen and helium atmosphere.Jupiter has at least 79 moons, four of which are active, planet-like worlds that range in size from just smaller than the moon of Earth to larger than Mercury. It also has a weak ring system.The astronomical unit is a measurement of length that is roughly equal to 150 million kilometers or 8.3 light-minutes, or the distance between the Earth and the Sun. As Earth orbits the Sun, its actual distance from the Sun changes by around 3%, going from its maximum to its minimum and back again once per year.To know more about Jupiter
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What is the wavelength of a wave with a speed of 12 m/s and a frequency of 3 Hz?.
Answer:
[tex] \huge{ \boxed{4 \: m}}[/tex]
Explanation:
The wavelength of the wave given it's speed and frequency can be found by using the formula
[tex] \lambda = \frac{v}{f}\\ [/tex]
where v is the speed
f is the frequency
From the question
v = 12 m/s
f = 3 Hz
We have;
[tex] \lambda = \frac{12}{3} = 4 \\ [/tex]
We have the final answer as
4 mhow far will it go, given that the coefficient of kinetic friction is 0.10 and the push imparts an initial speed of 3.6 m/s ?
Given
coefficient of kinetic Friction μ(k) = 0.1
Initial speed u = 3.6
Friction is present so it tries to stop to the object and stops it completely after moving certain displacement let say s
maximum deceleration provided by friction is
a(max) = μ(k) * g
= 0.1 * 3.6
using equation of motion
v² - u² = 2as
where,
v = final velocity
u = initial velocity
a = acceleration
s = displacement
(0)² - (3.6)² = 2 * (-0.36) * s
s = 18 m
Therefore, the displacement will be 18 m
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What is the gravitational acceleration on Planet Y if there is an increase in gravitation potential energy equal to 352 J when a 8.27 kg is lifted 15.43 m? (1 point) 0 27.6) O 188.66 ) 2.763 42.560 44917.35)
The gravitational acceleration on the planet Y will be 59.52 m/[tex]s^{2}[/tex].
Given,
Gravitational potential energy, [tex]P_{E}[/tex] = 352 J
Mass of an object, m = 8.27 kg
Lifted to the height, R = 15.43 m
Gravitational potential energy at the height R can be calculated as:
[tex]P_{E}[/tex] = - [tex]\frac{GMm}{r}[/tex]
As GM = gR^2
Potential energy will be -mgR
and for r = R, Potential energy will be - (mgR)/2
m = mass of the object (8.27 kg)
So, [tex]P_{E}[/tex] = - (mgR)/2
Now to calculate g (gravitational acceleration), g =-([tex]P_{E}[/tex]×2)/mR
=(-352×2)/8.27×1.43
g = 59.52 m/[tex]s^{2}[/tex]
Hence, gravitational acceleration on the planet Y will be 59.52 m/[tex]s^{2}[/tex].
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consider that the ball travels one revolution of its path in t second. what is the speed of the ball in terms of l, r, and t?
The speed of the ball in term of l, r, t is given as,
l = r/t
Where, l is the speed of the ball, r is the distance travel by the ball and t is the time to complete one revolution.
Every day, each of us makes a trip to a different location and covers a distance along the way. But from the perspective of physics, distance is something that takes into account a variety of things.A ball is moving consistently translationally. The ball moves down the path at a constant pace and can follow a straight or round path. The speed of the ball is constant and has the same magnitude and direction for every component.
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students are doing an experiment near an empty pool. a student of mass 40kg is standing on one end of a board as the board hangs over the pool as shown. the board is of uniform density, has a length l, and is positioned such that the pivot point is l/3 from the end of the board. the board is just about to tip over into the pool. how far from the pivot point must a 60kg student stand so that the board is just about to tip over? reddit
The correct option about his position is : At 2L/9 you will see it tip over
Why does weight change and mass does not ?Due to the fact that mass is the quantity of matter contained in an item and does not change with gravity, mass is always the same. As long as the amount of matter in an object doesn't change, its mass will remain constant. In contrast, an object's weight refers to the force of gravity acting on it.
No matter where you are in the cosmos, you have the same mass since mass is a measurement of how much matter is in an object. But because weight measures the force between an object and the body it is resting on, it fluctuates (whether that body is the Earth, the Moon, Mars, et cetera).
Given : A mass of student 40 kg
length is represented by l
Position of the pivot point from the board = l/3
The student should stand at 2L/9 you will see it tip over so as to weigh of 60kg.
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what is the angular velocity (in rad/s) of a 62.0 cm diameter tire on an automobile traveling at 90.5 km/h? (enter the magnitude.)
The angular velocity is 55.6rads/s.
What is angular velocity?
The rotation rate of an object, or how quickly it revolves or rotates in relation to another point, is measured vectorially as angular velocity. Angular velocity is simply the rate of rotation or revolving around an axis of an object.
What is magnitude?
Magnitude serves as the common denominator for both vector and scalar quantities. Their definition states that scalar quantities are those that have only magnitude.
Using the second relationship in v = r, vr = v r, and knowing v and r, we can get the angular velocity. To calculate the angular velocity, we will use the formula = vr. = v r.
If an object's radius is r, its linear speed is v, and its angular velocity is measured in radians per second, then v = r.
Substituting the values, in the formula
=62.0cm*90.5
V=55.6
Therefore, the angular velocity is 55.6rads/s.
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In the figure, a broad beam of light of wavelength 610 nm is incident at 90? on a thin, wedge-shaped film with index of refraction 1.45. An observer intercepting the light transmitted by the film sees 10.0 bright and 9.00 dark fringes along the length of the film. By how much does the film thickness change over this length?
The film thickness change over by dL = 1.99 um.
Thomas Young proposed that the superposition principle applies to light, which is a wave. His ability to demonstrate that light may interfere both positively and negatively was his biggest experimental achievement. An updated version of Young's experiment, which only differs in the source of light from the original experiment, uniformly illuminates two parallel slits in an otherwise opaque surface. The light passing through the two apertures can be seen on a distant screen. When the slit widths are substantially more than the light's wavelength, the laws of geometrical optics are upheld and the light creates two shadows and two illuminated zones on the screen.
There are 10 bright fringes
2nLa= (ma + 0.5)W
2nLb = (mb + 0.5)W
mb = ma + 9
2nLb - 2nLa = 9W
Dark fringes = 9
dL = 9 × 610nm/(2 × 1.45)
Thickness film changes by dL = 1.99 um
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a car is traveling at $$50 mi/hr when the brakes are fully applied, producing a constant deceleration of $$22 ft per sq sec. what is the distance (in feet) covered before the car comes to a stop? be mindful of the units being used in this problem
The distance (in feet) covered before the car comes to a stop is 122.2 ft
It is given that
initial speed of car = u = 50 mi/hr
deceleration = - 22 m/s^2
final speed = v = 0 m/s
We have to find the distance
Applicable kinematic equation is
v^2 - u^2 = 2as
50 mph x 1760 x 3/3600 = 73.333 fps
0^2 - (73.333)^2 = 2*(-22)*s
s = (73.333)^2/44
s = 122.2 ft
Hence, distance (in feet) covered before the car comes to a stop is 122.2 ft
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What happens to gravitational potential energy of mass increases?.
Gravitational potential energy increases as weight and height increases.
Potential energy is stored or conserved energy in a material or object. The amount of stored energy depends on the arrangement, organization, and state of the object or substance.
You might think of it as energy with the "potential" to be productive. Any changes to the object's position, configuration, or status will result in the release of any stored energy.
For instance, in order to compress a spring, energy is required, but what happens to that energy once the spring has been broken It is impossible to generate or destroy energy because it can only transform from one form to another.
The kinetic energy that was used to compress our spring has now been converted to potential energy
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What results from the human farmers visit to Animal Farm?.
The farmers worry that the livestock will also rebel. The efficiency with which the farm is operated impresses the farmers.
The farmers worry that the livestock will also rebel. The efficiency with which the farm is operated impresses the farmers. The farmers promise to put the same kinds of processes in place. The farmers make the decision to become active members of the farm. The animals' mistrust of the farmers angers the farmers.
After a two-day episode in which the farmhands neglected and malnourished the animals, the uprising begins. As soon as the cows kick down the barn door, the rest of the animals go mad. The animals run away every person from the farm as Jones tries to whip them, starting the uprising.
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a 2000 kg truck is moving eastward at 25 m/s. it collides inelastically with a 1500 kg truck traveling southward at 30 m/s. they collide at the intersection.
According to the given statement Final velocity when they stick together is 8.735i^ + 11.25j^
What is collision and momentum?The unit of momentum is kg ms -1. Momentum is a vector parameter that is influenced by the object's direction. During collisions involving objects, momentum is a relevant concept. The final velocity before a collision between two objects equals the total motion after the impact (in the absence of external forces).
Briefing:From conservation of momentum
Initial momentum = final momentum
m u +M U =(m+M) V
2000×25 i^ +1500×30 j^ =(2000+1500) V
V = 8.735i^ + 11.25j^
Final velocity when they stick together is 8.735i^ + 11.25j^
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The complete question is -
A 2000 kg truck is moving eastward at 25 m/s. it collides inelastically with a 1500 kg truck traveling southward at 30 m/s. they collide at the intersection. Find the direction and magnitude of velocity of the wreckage after the collision, assuming the vehicles stick together after the collision.
What is a substance
promotes glomerular hypertension and hyperfiltration caused by efferent arteriolar vasoconstriction and also promotes systemic hypertension.
Angiotensin II promotes glomerular hypertension and hyperfiltration caused by efferent arteriolar vasoconstriction and also promotes systemic hypertension.
What is Angiotensin II ?A drug called angiotensin II is used to treat hypotension brought on by septic shock or other types of distributive shock. It is marketed as Giapreza, a synthetic vasoconstrictor peptide that is equivalent to the human hormone angiotensin II.The muscle walls of tiny arteries contract as a result of angiotensin II, raising blood pressure. Additionally, angiotensin II causes the release of aldosterone from your adrenal glands and an antidiuretic hormone from your pituitary gland.The primary RAS effector molecule is angiotensin II. It raises blood pressure, encourages the renal tubuli to retain sodium and water, and prompts the adrenal gland to secrete aldosterone.To learn more about Angiotensin refer :
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a 10.0-kg dog is running with a speed of 5.00 m/s. what is the minimum magnitude of the work required to stop the dog in 2.40 s?
An 10.0-kg dog is moving at a pace of 5.00 meters per second. The amount of work that must be done to halt its dog in 2.40 seconds must be at least 125 joules.
What is a work?Whenever an object is transported over a length by an external force, at least a portion of that force must be applied in the plane of the displacement. In physics, this is referred to as work.
What are the three categories of physics work?The three categories below can be used to categorize the kinds of labor that are done. The three sorts are good work, negative collaborate, and zero work. The type of work that is performed depends on the connection between force and displacement. When a force is used and an item is pushed in that direction, positive work is produced.
Briefing:Work is equal to force times distance.
Work done = kinetic energy
Kinetic energy is equal to 1/2 mv2 or 1/2 10*5² or 5 *25.
= 125 joules
Hence, work done is 125 joules.
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