Find u special 4 A. 22‾√ 2 2 B. 4 C. 2 D. 2‾√

Given the length of the two diagonals of the kite, the area of kite ABDC is 33 squared centimeters.

Formular for the area of a kite is expressed as;

A = pq/2

Where p and q are the two diagonals of the kite.

Given the data in the question;

From the diagram, we can determine line AM and line MD using Pythagoras theorem.

c² = a² + b²

First, we find line AM

c² = a² + b²

5² = 3² + b²

25 = 9 + b²

b² = 25 - 9

b² = 16

b = √16

b = 4

Line AM = 4

Next, we determine Line MD

c² = a² + b²

(√58)² = 3² + b²

58 = 9 = b²

b² = 58 - 9

b² = 49

b = √49

b = 7

Line MD = 7

Now, we can find the area of the kite.

Diagonal p = BC = 6

Diagonal q = AD = AM + MD = 4 + 7 = 11

Area = pq/2

Area = [ 6 × 11 ]/2

Area = 66 / 2

Area = 33cm²

Given the length of the two diagonals of the kite, the area of kite ABDC is 33 squared centimeters.

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the vertex of the function g(x) = f(x 2) .

If a quadratic equation is expressed as the following

                          [tex]y=a(x-h)^{2}+k[/tex]

It is then said to be in vertex form. Because the vertex point (peak point) occurs on the graph of this equation, it is so named (h,k)

The parabola that the quadratic equation depicts has this point (h,k) as its vertex.

We first remove the x squared coefficient, and then inside the bracket, we strive to create a condition that resembles a perfect square.

So, this is what we have:

                         [tex]$f(x)=x^{2}+6 x+3$\\$g(x)=f(x-2)$[/tex]

Thus, we obtain:

                        [tex]\begin{aligned}&g(x)=f(x-2) \\&g(x)=(x-2)^{2}+6(x-2)+3 \\&g(x)=x^{2}-4 x+4+6 x-12+3 \\&g(x)=x^{2}+2 x-5\end{aligned}[/tex]

Vertex form transformation of g(x):

                             [tex]\begin{aligned}&g(x)=x^{2}+2 x-5 \\&g(x)=x^{2}+2 x+1-1-5 \\&g(x)=(x+1)^{2}-9 \\&g(x)=(x-(-1))^{2}-6 \\&g(x)=(x-(-1))^{2}+(-6)\end{aligned}[/tex]

By comparing this[tex]a(x-h)^{2}+k[/tex] to, we obtain the coordinates of the vertex of the graph of g(x) as (h,k) = (-1,-6), as shown below.

As a result, the vertex of the function g(x) = f(x 2) .

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Step-by-step explanation:

we have 2 blocks, as the graphic shows.

the surface areas of both blocks are the sum of their 6 sides each.

the special thing about seeing them as "composite figure" is that 2 sides (one for each block) are partly or even completely blocking each other off from being seen, so these parts and whole side are not part of the combined surface area.

let's start with the large block :

it is 5cm × 6cm × 20cm.

its surface area is the sum of

top and bottom 5×6

front and back 20×5

left 20×6

visible right (20 - 12)×6 = 8×6

it is (20-12)cm long, because the short block

is 12cm high.

so, we have

2 times 5×6 =2×30 = 60 cm²

2 times 20×5 = 2×100 = 200 cm²

20×6 = 120 cm²

8×6 = 48 cm²

in total : 428 cm²

now the small block :

it is 4cm × 6cm × 12cm.

its surface area is the sum of

top and bottom 4×6

front and back 4×12

no left (completely covered by the large block)

right 6×12

so, we have

2 times 4×6 = 2×24 = 48 cm²

2 times 4×12 = 2×48 = 96 cm²

6×12 = 72 cm²

in total : 216 cm²

the complete surface area of the composite figure is

428 + 216 = 644 cm²

Answer:

Define the variables.

Step-by-step explanation:

Define the variables, then set up the equations, and finally solve the system using graphing, substitution, or elimination method.

To set up or model a linear equation to fit a real-world application, First, we have to determine the known amounts or quantities before defining the unknown quantity as a variable.

A linear equation is defined as an equation in which the highest power of the variable is always one.

To set up a model linear equation to fit real-world applications

In the first step determine known amounts or quantities.

Then, assign the unknown amount to a variable.

Now, find a method or approach to express the second unknown in terms of the first if there are many unknown quantities.

Create an equation that translates the words into mathematical functions.

Complete the equation. Make certain that the solution, including the system of measurement, can be expressed in words.

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The true statement is (c) Amal's work is incorrect because it includes a positive two instead of a negative two in the answer

The complete question is added as an attachment

From the table, we have

Divisor = x^2 - 3x + 4

Quotient = 2x + 5

Dividend = -2x^3 + 11x^2 - 23x + 20

See that the signs of the leading coefficients of the dividend and the divisor are different

This means that the leading coefficient of the quotient must be negative

From the question, we have:

Quotient = 2x + 5

The expression 2x + 5 has a positive leading coefficient

Hence, the true statement is (c) Amal's work is incorrect because it includes a positive two instead of a negative two in the answer

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Step-by-step explanation:

Area of rectangle= length × breadth

A= a²+6a+8

= a²+4a+2a+8

= a(a+4) + 2(a+4)

= (a+4)(a+2)

length= a+4

breadth= a+2

Answer:

The graph of g(x) has a y-intercept at (0,0) and a slope of -2.

[tex]\Large\texttt{Answer}[/tex]

[tex]180^\circ=\pi\:radians}[/tex]

[tex]\overline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}[/tex]

[tex]\Large\texttt{Process}[/tex]

⇨ For converting from degrees to radians, use this conversion factor:

[tex]\bf{\cfrac{\pi}{180}}[/tex]

⇨ Convert

[tex]\bf{\cfrac{180}{1}\times\cfrac{\pi}{180}}[/tex]

⇨ The 180s cancel out, and we have:

[tex]\pi[/tex]

Hence

[tex]\bf{180^\circ=\pi\:radians}[/tex]

Hope that helped

Answer:

Step-by-step explanation:

Equation

f(x) = (8x + 1) / (2x + 9)

Notice the brackets. They are necessary to show what comes before the division sign, and what comes after.

Behavior

The best way to state the behavior is to get something like a graphing program to show you what the curve looks like -- where it's critical points are for example. I use Desmos for  this kind of question, Just do a search for Desmos and bookmark it. You will use it quite often.

So you want to know the behavior.

Right Curve

Crosses the x axis at (-0.125, 0)

Crosses the y axis at (0,0,111)

The right curve has a domain of -∞ < x < ∞

The  right curve has a range of -∞ < x < ∞

The range is going to have to go out quite a ways before you see any dramatic decrease in the way it is drawn.

Left Curve.

The right hand curve never crosses either the x or y axis.  Nor does it just touch the x or y axis.

The domain is -∞ <x < 0

The range is 0<x<∞

Answer:

9:20

Step-by-step explanation:

1kg is 1000g grams and in order to simify we need the units to be equal . 450:1000 would simplify to

45: 100 by divinding both the number by 10 then divide both number by 5 which would give 9: 20

hopefully this helped . if you need any more explanation pls ask

pls give brainliest if you like my answer :) thanks

Answer:

9: 20

Step-by-step explanation:

      1kg × 1000 = 1000g

     450 :  1000g

     450  :  1000

        9: 20

[tex](k \circ p)(x)=k(p(x))=k(x-3) \\ \\ =2(x-3)^2-5 \\ \\ =2(x^2 - 6x+9)-5 \\ \\ =\boxed{2x^2 - 12x+13}[/tex]

For instance, f[g (x)] exists the composite function of f(x) and g(x). The composite function f[g (x)] exists read as “f of g of x”.

The composite function exists [tex]$k(p(x))=2 x^{2}-12 x+13$[/tex]

Therefore, the correct answer is option b. [tex]$k(p(x))=2 x^{2}-12 x+13$[/tex].

A composite function exists generally as a function that exists written inside another function. The composition of a function exists done by replacing one function with another function.

Given function exists, [tex]$k(x)=2 x^{2}-5[/tex] and p(x) = (x - 3)

To find composite function k(p(x)).

k(p(x)) = k(x-3)

[tex]$&k(p(x))=2(x-3)^{2}-5 \\[/tex]

simplifying the above equation, we get

[tex]$&k(p(x))=2\left(x^{2}+9-6 x\right)-5 \\[/tex]

[tex]$&k(p(x))=2 x^{2}+18-12 x-5 \\[/tex]

[tex]$&k(p(x))=2 x^{2}-12 x+13[/tex]

The composite function exists [tex]$k(p(x))=2 x^{2}-12 x+13$[/tex]

Therefore, the correct answer is option b. [tex]$k(p(x))=2 x^{2}-12 x+13$[/tex].

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Answer:

  9.08

Step-by-step explanation:

To find the predicted value of y, put the x-value where x is in the equation and do the arithmetic.

  [tex]\hat{y}=134.63-2.79x\qquad\text{given}\\\\\hat{y}=134.63-2.79(45) = 134.63-125.55\qquad\text{use 45 for x}\\\\\boxed{\hat{y}=9.08}\qquad\text{simplify}[/tex]

The function can be solved as follows:

(h - g)(2.1) = 3.51

g(x) = 2x² + 3x - 9

h(x) = x² + 2x - 6

(h - g)(x) = h(x) - g(x)

(h - g)(x) = 2x² + 3x - 9 - ( x² + 2x - 6)

(h - g)(x) =  2x² + 3x - 9 - x² - 2x + 6

(h - g)(x) = 2x² - x² + 3x - 2x - 9 + 6

(h - g)(x) = x² + x - 3

Therefore,

(h - g)(2.1) = (2.1)² + (2.1) - 3

(h - g)(2.1) = 4.41 + 2.1 - 3

(h - g)(2.1) = 6.51 - 3

(h - g)(2.1) = 3.51

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Answer:

-4

Step-by-step explanation:

We are going to substitute 0 in for x and solve for y.  

-2(0)+ 8y = -32  Anything times zero is zero

0 + 8 y = -32  Anything plus zero is itself.

8y = -32 Divide both sides by 8

y = -4

Answer:

  triangle angle sum theorem

Step-by-step explanation:

The missing statement is one that justifies the sum of the angles in a triangle being 180°.

That justification is provided by the ...

  triangle angle sum theorem

Answer:

50 days

Step-by-step explanation:

40×300=1200

1200-700

500

so 1 day is 10 . 50 days is 500

The number of days he was absent from work will be 50 days

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Given that a man gets Rs. 40 for every day he works, but is fined Rs. 10 for every day he is absent If he got Rs. 700 at the end of 30 days.

The number of days he was absent from work will be calculated as below:-

40×300 = 1200

             = 1200-700

             = 500

1 day is 10 then 50 days is 500. Therefore, the number of days he was absent from work will be 50 days

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Answer:

(15,0) , (0,6)

Step-by-step explanation:

Same concept as the previous 2 questions.

x-intercept is where the line touches the x-axis, and y = 0.

when y = 0,

12x + 30(0) = 180

12x = 180

x = [tex]\frac{180}{12}[/tex]

x = 15

Therefore the coordinates of the x-intercept is (15,0)

y-intercept is where the line touches the y-axis, and x = 0.

when x = 0,

12(0) + 30y = 180

30y = 180

y = [tex]\frac{180}{30}[/tex]

y = 6

Therefore the coordinates of the y-intercept is (0,6)

The x-intercept is when y=0, but since [tex]\log_{3}(x-4) \neq 0 \text{ } \forall x[/tex], there is no x-intercept.

The asymptote is when the argument equals 0, which is at x=4.

The total volume of silo is  = 116.5[tex]{~m}^{3}[/tex]

The correct option is C

Any arrangement of points, lines, or planes constitutes a geometric figure. Depending on their dimensions, geometric figures can be categorized as either a space figure, a plane figure, a line, a line segment, a ray, or a point.

Any object's surface area is the space that the object's surface takes up on a specific area or region. Volume, however, refers to how much room a thing has.

Given data:

Radius =4.4/2

                   =2.2

height of cylinder = 6.2

to find :

total volume of silo =  volume of cylinder + volume of hemisphere

                                  [tex]\begin{aligned}&=\pi r^{2} h+\frac{2}{3} \pi r^{3} \\&=\pi r^{2}\left(h+\frac{2}{3} r\right) \\&=\frac{22}{7} \times(2.2)^{2}\left[6.2+\frac{2 \times 2.2}{3}\right]\end{aligned}[/tex]

                                   = 116.5[tex]m^2[/tex]

The total volume of silo is = 116.5[tex]m^2[/tex]

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I understand that the question you are looking for is:

A grain silo is composed of a cylinder and a What is the approximate total volume of the silo? Use hemisphere. The diameter is 4.4 meters. The height of  3.41 for [tex]\pi[/tex] and round the answer to the nearest tenth of its cylindrical portion is  6.2 meters. a cubic meter.

a. 37.1[tex]m^2[/tex]

b. 71.9 [tex]m^2[/tex]

c.116.5 [tex]m^2[/tex]

d. 130.8[tex]m^2[/tex]

Answer:

a) $20,771.76

b) $20,817.67

c) $20,484.80

d) $20,864.52

Step-by-step explanation:

Compound Interest Formula

[tex]\large \text{$ \sf A=P\left(1+\frac{r}{n}\right)^{nt} $}[/tex]

where:

Part (a): semiannually

Given:

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=15000\left(1+\frac{0.055}{2}\right)^{2 \times 6}[/tex]

[tex]\implies \sf A=15000\left(1.0275}{2}\right)^{12}[/tex]

[tex]\implies \sf A=20771.76[/tex]

Part (b): quarterly

Given:

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=15000\left(1+\frac{0.055}{4}\right)^{4 \times 6}[/tex]

[tex]\implies \sf A=15000\left(1.01375}\right)^{24}[/tex]

[tex]\implies \sf A=20817.67[/tex]

Part (c): monthly

Given:

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=15000\left(1+\frac{0.055}{12}\right)^{12 \times 6}[/tex]

[tex]\implies \sf A=15000\left(1+\frac{0.055}{12}\right)^{72}[/tex]

[tex]\implies \sf A=20484.80[/tex]

Continuous Compounding Formula

[tex]\large \text{$ \sf A=Pe^{rt} $}[/tex]

where:

Part (d): continuous

Given:

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=15000e^{0.055 \times 6}[/tex]

[tex]\implies \sf A=20864.52[/tex]

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Answer:

Step-by-step explanation:

Just multiply how much she waxes in 3/5 hour by 5/3.  Answer is 100/3 or 33.33 sq. meters per hour

The polar equation of an ellipse is [tex]r=-\frac{3}{1+2cos\theta}[/tex].

The vertices of ellipse are (−1,0) and (3,0).

The polar equation of an ellipse can be represented as

[tex]r=\frac{ep}{1+ecos\theta}[/tex]

where e is the eccentricity.

Eccentricity, e = [tex]\frac{c}{a}[/tex]

c is the distance from the center to the focus and a is the distance from the center to the vertex

[tex]c=\frac{3-(-1)}{2}[/tex]

⇒ [tex]c=\frac{4}{2}[/tex]

⇒ c = 2

[tex]a=\frac{3+(-1)}{2}[/tex]

⇒ [tex]a=\frac{2}{2}[/tex]

⇒ a = 1

Then, e = [tex]\frac{2}{1}[/tex]

⇒ e = 2

Now, the polar equation of an ellipse becomes as,

⇒ [tex]r=\frac{2p}{1+2cos\theta}[/tex] ------- (1)

Now plug in a vertex point such as (-1,0) and solve for p,

⇒ [tex]-1=\frac{2p}{1+2cos0}[/tex]

⇒ [tex]-1=\frac{2p}{1+2(1)}[/tex]               [∵ cos 0 = 1]

⇒ [tex]-1=\frac{2p}{3}[/tex]

⇒ [tex]-3=2p[/tex]

⇒ [tex]p=-\frac{3}{2}[/tex]

Thus the polar equation of an ellipse (1) becomes as,

⇒ [tex]r=\frac{2(-\frac{3}{2} )}{1+2cos\theta}[/tex]

⇒ [tex]r=-\frac{3}{1+2cos\theta}[/tex]

Hence we can conclude that the polar equation of an ellipse is [tex]r=-\frac{3}{1+2cos\theta}[/tex].

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The system of linear equations represents the situation is;

x + y = 125

x + y = 1255x + 8y = 775

Simultaneous equation is an equation in two unknown values are being solved for at the same time.

let

x + y = 125

5x + 8y = 775

From equation (1)

x = 125 - y

5x + 8y = 775

5(125 - y) + 8y = 775

625 - 5y + 8y = 775

- 5y + 8y = 775 - 625

3y = 150

y = 150/3

y = 50

x + y = 125

x + 50 = 125

x = 125 - 50

x = 75

Therefore, the number of quick washes and premium washes Monica’s school band had is 75 and 50 respectively.

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Answer:

A. 5x + 8y = 775 and x + y =125

Step-by-step explanation:

The expression, written as the sine of an angle is sin (7π/10)

From the question, we are to write the given expression as the sine or cosine of an angle.

The given expression is

sin(π/5)cos(π/2) + sin(π/2)cos(π/5)

Let A = π/5

and

B = π/2

Thus, we get

sinA cosB + sinB cosA

From the given information, we have that

sin(A ± B) = sinA cos B ± cosA sinB

∴ sin(A + B) = sinA cos B + cosA sinB

Now,

sinA cosB + sinB cosA = sinA cosB + cosA sin B

∴ sinA cosB + sinB cosA = sin (A + B)

Put A = π/5

and

B = π/2

sinπ/5 cosπ/2 + sinπ/2 cosπ/5 = sin (π/5 + π/2)

sinπ/5 cosπ/2 + sinπ/2 cosπ/5 = sin (7π/10)

Hence, the expression, written as the sine of an angle is sin (7π/10)

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Amount of money earned per number of hours of work =  [tex]f(g(x)) = 6x^{3} + 4[/tex]

To evaluate a composite function f(g(x)) at some x = a, first compute g(a) by substituting x = a in the function g(x). Then substitute g(a) into the function f(x) by substituting x = g(a). In the same way, we can calculate g(f(a)) as well.

Required calculation -

Amount of money (the earning) per unit x = [tex]f(x) = 2x^{2} + 4[/tex]

Number of gallons of ice cream that Barrett makes per hour, where x is the number of hours he works = [tex]g(x) = \sqrt{3x^{3}}[/tex]

we are to find the composite function [tex]f(g(x))[/tex]

Substituting g(x) into the x of f(x), we find:

[tex]f(g(x)) = 2(\sqrt{3x^{3} } )^{2} + 4\\\\= 2(3x^{3} ) + 4\\= 6 x^{3} + 4[/tex]

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Answer:

f(g(x)) = 6x3 + 4 dollars over hour

Step-by-step explanation:

Answer:

i think 80 copies

Step-by-step explanation:

Answer:

y = 2x - 11.

Step-by-step explanation:

Use the point-slope form of the straight line.

y - y1 = m(x - x1)   where m = slope and (x1, y1) is the given point.

Here m = 2 and (x1, y1) = (7,3) so the equation is:

y - 3 = 2(x - 7)

y - 3 = 2x - 14

y = 2x - 11

Using it's concept, we have that the probability that both the first digit and the last digit of the three-digit number are even numbers is 2/27.

A probability is given by the number of desired outcomes divided by the number of total outcomes.

Considering that there are six numbers, out of which 4 are odd and 2 are even, we have that:

Hence the desired probability is:

p = 1/3 x 2/3 x 1/3 = 2/27.

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Answer:

a) Class A has the larger interquartile range.

b) Class A has the highest test score.

c) Class B has higher median test score.

d) Class B has smaller range of test score.

Step-by-step explanation:

a) Inter quartile range (IQR) =  upper quartile - lower quartile

  Class A:  IQR = 79 - 65 = 14

  Class B: IQR = 77 - 70 = 7

Class A has larger interquartile range.

b)  Class A has the highest test score.

c) Median of class A = 70

 Median of class B   = 74

Class B has higher median test score.

d) Range is the difference between the highest and lowest score.

Range = highest score - lowest score

 Range of Class A = 85 - 62 = 23

 Range of class B  =  79 - 68 = 11

Class B has smaller range of test score.

With the aid of the attached diagrams in the question, we have;

1- Linear relation

2- W = 8•P + 80

3- Please find attached the graph created using a graphing calculator.

4- a) The initial value is the mass of the vase

b) The slope is the mass of each pebble

5- The initial value is lesser than 80

6- 1.2 kilograms

7- 53 pebbles

8- a)

b) (0, 80)

c) The masses are the same

9- Trapezoid area, A = 14•x² - 4•x

10- Tanya and Leah are 18 and 6 years old respectively

1- The relationship between two variables (x and y) is linear if the difference between the terms of the x-values and the terms of the y-values are both constant.

From the table we have;

The relationship between the x and y-values in the table is therefore;

2. The slope, m, of the linear function is found as follows;

m = (360 - 280)/(30 - 20) = 8

The equation is therefore;

W - 360 = 8•(P - 30)

W = 8•P - 240 + 360 = 8•P + 80

3. Please find attached the graph drawn with a graphing calculator.

4. The initial value is the output variable (W-value) when the input variable (P-value) is zero.

Therefore;

y = 8×0 + 80 = 80

a) The initial value indicates when the input, P-value is zero, which gives the mass of the vases

b) The slope indicates the number of times an additional pebble increases the weight of the vase and pebble, which is the mass of one pebble

5- A styrofoam cup is lighter than a glass cup, therefore, the initial value, which is the constant term, c, reduces.

6- The weight, W, of 112 pebbles is therefore;

W = 10 × 112 + 80 = 1,200

7- 504 = 8•P + 80

Which gives;

504 - 80 = 8•P

P = 424 ÷ 8 = 53

8- Wilma's equation is; W = 10•P + 80

a) Please find the second graph showing the graphs of the two equations combined.

b) The point of intersection is given by the relation 10•P + 80 = 8•P + 80

2•P = 0

P = 0

Therefore, at the point of intersection, W = 80

The coordinates of the point of intersection is therefore;

c) The point of intersection means that the weight of Wilma's vase and the vase in question 1 are the same.

9. The area of the trapezoid, A, can be expressed as follows;

A = 4•x × ((2•x + 5)+(5•x - 7))/2

A = 2•x × (7•x - 2) = 14•x² - 4•x

10. Let T represent Tanya's age now and let L represent Leah's current age, we have;

T = L + 12

T - 3 = (L - 3) × 5

Solving gives;

L + 12 - 3 = (L - 3) × 5 (Substitution property)

L + 9 = 5•L - 15

4•L = 9 + 15 = 24

L = 24 ÷ 4 = 6

T = L + 12

Therefore;

T = 6 + 12 = 18

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