for the following surface, what is the minimum number of area vectors would you need to fully describe the area?

The quadratic equation for the resistance ratio is 6E-06 t^2 + 0.00341t +1.

The temperature at which electric resistance would be double is  293.25 Fahrenheit.

Resistance predicted at 71 degrees is 1.2724.

What is resistance ratio?

The resistance ratio is the difference between the thermometer's resistance at the ice point and its resistance at a given temperature (t) (t0).

Temp t

in

degrees

(x) c(t) / c(0) (y) (x)2 (x)3 (x)4  xy x2 y

0 1 0 0 0 0 0

10 1.0393 100 1000 10000 10.393 103.93

20 1.0798 400 8000 16000 21.596 431.92

30 1.1215 900 27000 81000 33.645 1009.35

40 1.1644 1600 64000 2560000 46.576 1863.04

sum =100 5.405 3000 100000 2667000 112.21 3408.24

a. To calculate equation in the form of y = ax^2 + bx +c

Substituting the values calculated above in the formula

= 112.21 - (100*5.405) /5 =4.11

= 100000 - (3000*100)/5 =40000

= 2667000 -1800000 = 867000

a = { [ Σ x2 y * Σ xx ] - [Σ xy * Σ xx2 ] } / { [ Σ xx * Σ x2x 2] - [Σ xx2 ]2 }

= 6E-06

b = { [ Σ xy * Σ x2x2 ] - [Σ x2y * Σ xx2 ] } / { [ Σ xx * Σ x2x 2] - [Σ xx2 ]2 }

= 0.00341

c = [ Σ y / n ] - { b * [ Σ x / n ] } - { a * [ Σ x 2 / n ] } = 1.012

So the equation is c(t)/c(0) = 6E-06 t^2 + 0.00341t +1

b). c(t)/c(0) =2

Putting in the quadratic equation found above-

2 = 6E-06 t^2 + 0.00341t +1

1 = 0.00341t  (neglecting the square term)

t = 293.25 fahrenheit

c). at 71 degrees

c(t)/c(0) = 0.030246+0.24211+1.012

= 1.27235

Resistance predicted at 71 degrees = 1.2724

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If the force exerted by block b on block a has a magnitude f, the magnitude of fa is is f, because according to the newtons thied law of motion, the every force there is equal and opposite reaction.

Friction is the force resisting the relative motion of sturdy surfaces, fluid layers, and material factors sliding towards each specific. There are numerous styles of friction: Dry friction is a strain that opposes the relative lateral movement of two stable surfaces in touch.

Friction is a shape of contact pressure. It exists between the surfaces that are in touch. The frictional force relies upon on the character of the floor in contact. The rougher the ground, the extra the friction is involved. The frictional force is proportional to the urgent pressure, that is the burden of the body. it's miles impartial of the place of the touch.

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56mm is the distance of the second maximum from the center line of the central maximum. coherent light of wavelength 585 nm is incident on a pair of slits with separation 0.24 mm.

Given information

wavelength  = 585 nm

D = 1.63m

d = 0.24mm

m = 2

SinΘ = (m+ 1/2) A x wavelength x d = Sing= (2+↓ 2 X 0.24X183

SinΘ = 6·093.75×10^- = 6.09703N-3

Θ= Sin-1 ( 0·00609) = 0.34

Y= D tanΘ  is  y = (1.63) tan (0.34)

Y = 9.49 x10-3 m. = 0.056 m= 56mm.

A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in the consecutive cycles.

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The events f and s are conditional independent events given d and ~d respectively with p(D|F∩S) is 0.9529.

What is events?

An event in probability theory is a collection of experiment results to which a probability is ascribed. A single outcome might be a component of several events, and since various events in an experiment could have quite diverse groupings of outcomes, they are often not equally probable.

If F and S are conditionally independent given D and ~D, then

P(FSD)= P(D)P(F|D)P(S|D)

P(FS~D) = P(~D)P(F|~D)P(S|~D)

P(F|~D) = 1 - P(~F|~D)

P(S|~D) = 1 - P(~S|~D)

P(~D) = 1 - P(D)

P(D|FS) = P(FSD)/(P(FSD) + P(FS~D))

P(F|D) = P(S|D) = .9

P(~F|~D) = P(~S|~D) = .9

P(D = .2)

Then, P(FSD) = P(D)P(F|D)P(S|D) = .2*.9*.9 = .162

P(FS~D) = P(~D)P(F|~D)P(S|~D) = (1 - .2)(1 - .9)(1 - .9)= .008

P(D|FS) = P(FSD)/(P(FSD) + P(FS~D)) = .162/(.162+.008) = 162/170=81/85 = .9529

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The horizontal acceleration is always zero and the vertical acceleration is always a non-zero constant downward.

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Considering both the object's mass and the surface's coefficient of friction In relation to heat energy, friction is a resistive force.

According to physics, heat is a type of energy that moves from a hotter body to a cooler one or it is the movement of atoms and molecules within a substance; the faster the atoms or molecules move, the more energy the substance has. The SI unit of heat is the joule (J).

Natural gas, propane (Mp), oil, coal, firewood, electricity, water heaters, ground source heat pumps, and solar energy are just a few of your many options for heating energy sources. Offering goods that are both extremely energy-efficient and wise investments is a goal of Radiantec.

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Force is gravity and friction are Contact forces and Non-contact forces. yes, inertia and gravity are related.

According to Einstein, inertia and gravity are the same thing. The fact that two different masses fall at the same rate leads me to conclude that gravity and inertia are equivalent.

That is, whether a greater mass is dumped on the Earth or the Moon, its inertia is precisely enough to slow down its acceleration to the same level as a smaller mass.

Contrary to what some individuals in the comments claim, Einstein did assert that gravity and inertia are interchangeable concepts.

This is a typical mistake that results from Einstein's concept of equivalence, which equates gravitational mass with inertial mass, but also from the fact that acceleration and gravity appear to be two distinct phenomena.

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The greatest height that the water can depart through the two points using fluid mechanics expressions is as follows:

1) y = 0.20 m is the maximum height that the water can exit the hose at.

2) The water shoots out of the nozzle at a maximum height of 68.6 meters.

When the water exits the hose, the pressure is atmospheric, and it is the same when it reaches its greatest point. P1 = P2

12 v12 + g y1 = 12 v22 + g v2

At the highest point of  trajectory the velocity must be =zero.

 y₂- y₁ = [tex]v^{2} /2g[/tex]

Let's calculate

  Δy = 0.2 m.

Using Bernoulli's equation,  the speed of the water is the highest point=0.

 Δy = 68.6m

The law of energy conservation is the foundation of Bernoulli's principle, to the fullest extent possible. At various sites when liquid is flowing under a constant pressure differential, the whole energy of the liquid—including pressure energy, potential energy, and kinetic energy—is equalized.

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In the real scenario, the bags of food would have been dropped from the planes without parachutes, so they would have fallen to the ground under the force of gravity.

The food bags would have been dropped from the planes in the real scenario without parachutes, allowing gravity to bring them to the ground. They would have fallen faster because of the acceleration brought on by gravity. Air resistance would have caused the bags to descend a little more slowly as well. Depending on their mass and speed when they hit the ground, they would have impacted with a specific amount of kinetic energy.

The food bags would have been dropped with parachutes attached in the imagined scenario. The bags' descent would have been slowed by the parachutes, lowering the acceleration brought on by gravity. This would have decreased the bags' kinetic energy and speed before they touched the ground. The bags would have encountered air resistance as well, but due to the slower speed, this would have been less noticeable. If the bags had been dropped with parachutes, they would have landed with less force and kinetic energy overall.

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Mass of the Earth, M = 6 * 10²⁴

m = 200 kg

R = 6.4 * 10⁶

G = 6.67 * 10¹¹ Nm²/kg²

Height of the satellite, h = 300 km = 3 * 10⁵ m

Total energy of the satellite at height h = 1/2mv² + [G(M*m)/(R+h)]

Orbital velocity of the satellite, v = √[ (G*M) / (R+h) ]

Total energy at height h = 1/2[ (G*M) / (R+h) ]

The negative sign indicates that the satellite is bound to the Earth.

Energy required to send the satellite out of its orbit = – (Bound energy)

= GM*m/ 2(R+h)

= 6.67*10⁻¹¹ * 6*10²⁴* 200 / 2(6.4*10⁶ + 0.3*10⁶)

= 11.9*10⁹ J

If the satellite just escapes from the gravitational field, then total energy of the satellite is zero.

Therefore, we have to supply 11.9*10⁹ J of energy to just escape it.

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[NOTE:THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS: imagine a satellite in low-earth circular orbit, i.e., approximately 300 km above the surface of the earth. if the radius of the earth is 6.37 x 106 meters, and we assume the gravitational force on the satellite is approximately equal to mg with g. The mass of satellite is 200 kg. How much energy must be expended to rocket the satellite out of the earth's gravitational influence?]

First and Fourth option is correct

Center of mass of an object:

The centroid of a mass distribution in space (also called the equilibrium point) is the unique point where the weighted relative positions of the distribution masses sum to zero. This is the point where force can be applied to produce linear acceleration without angular acceleration. Mechanics calculations are often simplified when formulated in terms of the center of gravity. This is a virtual point at which the entire mass of the object can be assumed concentrated in order to visualize its motion. In other words, the center of mass is the particle equivalent of a particular object for which Newton's laws of motion apply.

Angular momentum:

Angular momentum is the rotational analogue of linear momentum. It is an important physical quantity because it is conserved. The total angular momentum of a closed system remains constant. Angular momentum has both direction and magnitude, both of which are conserved.

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a) The change in temperature of water is 0.0084°C.

b) The potential energy is transformed into kinetic energy, which is ultimately transformed into water heat.

c) The metal lost energy as a result of the friction created by the metal's motion inside the water, and this energy was then transformed to heat energy to raise the temperature of the water.

What is kinetic energy?

Kinetic energy is a type of energy that a moving object or particle experiences. When an item undergoes work—the transfer of energy—by being subjected to a net force, it accelerates and acquires kinetic energy. A moving object or particle's kinetic energy, which depends on both mass and speed, is one of its properties. The type of motion could be vibration, rotation on an axis, translation (or travel along a path from one place to another), or any combination of these.

Given,

Potential energy which is lost by the metal through the height, h

= 6m

We know,

PE = mgh

= 0.15 × 9.8 × 6 = 8.82 J

This is the energy used to heat up the water,

So, 8.82 = M × C × dT

Where,

M = 0.25 kg

C = 4186 J/kg/C

dT = Change in temperature of water

= T-22

So,

0.25 × 4186 × (T-22) = 8.82

T = 22.0084°C

Hence, The change in temperature is 0.0084°C.

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The calculated value of speed of sound be 400 m/s.

An echo is a sound produced when sound waves are reflected off of a surface and returned to the listener. It is the sound that has been reflected, and it reaches the listener after the original sound has passed.

Given parameters:

The student's  distance to the wall is = 300 m.

The time delay between clap an echo is 1.5 seconds.

In this time, sound waves goes to the wall and hits back to the student's ear.

So, total distance covered by the sound wave: d= 2 × 300 m = 600 m.

Hence,  the speed of sound be - 600 m/1.5s = 400 m/s.

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The construction that two concrete spans of the bridge of total length  is 2.55m.

What is Linear expansion coefficient ?

The coefficient of linear expansion may be defined as the increase in length per unit length when the temperature is raised 1°C. Thus if the temperature of a rod of length l0 is raised from 0°C to t°C, the new length, lt, will be given by. (21.1)

Linear expansion coefficient of concrete is, [tex]$\alpha=1.2 \times 10^{-5} /{ }^{\circ} \mathrm{C}$[/tex]

Final length of the bridge,

[tex]$$\begin{aligned}& L=L_i(1+\alpha \Delta T)=260 \times\left(1+\left(1.2 \times 10^{-5} \times 16\right)\right)=260.04992 \mathrm{~m} \\& y=\frac{1}{2} \sqrt{L^2-L_i^2}=\frac{1}{2} \times \sqrt{(260.04992)^2-260^2}=2.55 \mathrm{~m}\end{aligned}$$[/tex]

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The false option about a real image is that  It appears behind the mirror. Last option.

Rays merely appear to diverge in a virtual image, whereas they actually converge in a real image. Only when the item is placed farther away from the mirror/lens than the focal point and this real picture is reversed can concave mirrors and converging lenses produce genuine images.

Using a converging lens or a concave mirror, actual images can be captured. The positioning of the object affects the size of the actual image.

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The correct answer is (b) F1 does more work than F2.

The block is moving horizontally the direction is opposite to direction of motion. The two forces applied are F1 and F2.F1 is applied horizontally so its horizontal component is F1cos0 = F1

While F2 is at angle  so horizontal component of F2 is F2cos(theta) and as we know cos is a decreasing in 0 to 90 degree. Therefore F1 does more work than F2.

Work is defined as the product of the magnitude of a force and the displacement of the object it is acting upon. In this case, the forces F1 and F2 are acting on the box, causing it to move across the floor. To calculate the work done by each force, we need to calculate the magnitude of the force and the displacement of the box.

The magnitude of F1 is given in the diagram, and it is 2 N. The magnitude of F2 is also given, and it is 4 N. For the displacement of the box, we will assume it is 1 m.

Now we can use the formula W = F x d to calculate the work done by each force.

For F1: W1 = 2 N x 1 m = 2 J

For F2: W2 = 4 N x 1 m = 4 J

Since F1 does 2 J of work, and F2 does 4 J of work, F1 does more work than F2 does. Therefore, the correct answer is (b) F1 does more work than F2 does.

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The four primary forces that interact between the Earth and the Sun are gravity, electromagnetic, feeble, and strong, in order of their relative intensities.

Radio and TV waves, microwaves, visible radiation, visible light, ultraviolet rays, Cross, and gamma rays are a few examples of electrical waves that travel through space without the aid of matter.

Electromagnets are made by winding wire coils carrying electricity through them. Since moving charges create magnetic fields, the wire coils inside an electromagnet act like magnets when an electrical discharge passes through them.

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Primary motor neurons of the direct motor pathway produce impulses that cause skeletal muscles to contract voluntarily, whereas primary motor neurons of the indirect motor pathway produce impulses that cause skeletal muscles to contract involuntarily.

For higher motor neuronal signals coming from the cerebral cortex and from basic brainstem motor nuclei, the motor route, also known as the pyramidal tract or the corticospinal tract, acts as the motor pathway. In the corticospinal tract, upper and lower motor neurons are present.

The cranial nerves' higher motor neurons make up the corticobulbar tract. The corticobulbar system, which terminates on motor neurons, regulates the muscles of the face, head, and neck.

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The Rank from brightest to dimmest is A=B=C.

the word "rak"Definition: Something that is extremely unpleasant to look at, smell, taste, or think about.Origins: A really low status object.a Swedish word that implies thin and feeble and is related to.Honks, grotty, are synonyms.

adjective.having an unpleasant rotten smell.Synonyms include offensive, malodorous, stinking, and malodourous.smelling bad in some way.

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The density of her house key is 7.9 g/ml, So the metal is Bronze - lead.

Density is the substance's mass consistent with the unit of quantity. The symbol most customarily used for density is ρ, despite the fact that the Latin letter D can also be used. Density is the size of ways tightly a cloth is packed together. it's far defined as the mass consistent with unit quantity.

ρ = m/V, wherein ρ is the density, m is the mass of the item and V is the quantity of the object.

The density of a liquid is a measure of how heavy it is for the quantity measured. in case you weigh the same amounts or volumes of two one-of-a-kind beverages, the liquid that weighs extra is greater dense.

Calculation:-

Density = mass/volume

            =  39.5 / 5

            = 7.9 g/ml

The density is of two types, one is absolute density, and the alternative is relative density. Relative density is also called unique gravity, which is the ratio of the density of a material to the density of a reference material. typically, the reference fabric is water.

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Answer:

See below

Explanation:

Total distance = 300 + 100 = 400 meters in 60 + 20 = 80 seconds

   400 m / 80 s = 5 m/s

If you are using DISPLACEMENT:
 displacement =   sqrt  (  ( 300 + 100 cos 45)^2 + (100sin 45)^2 ) = 377.4 m

     in 80 seconds        377.4 / 80 = 4.7 m/s

Option (C) is correct.

The given equation   [tex]2SO_{2(g)} +O_{2(g)}[/tex]    ⇄    [tex]2SO_{3(g)}[/tex]  is at equilibrium.

Given equation,

                         [tex]2SO_{2(g)} +O_{2(g)}[/tex]    ⇄    [tex]2SO_{3(g)}[/tex]

and

                   [tex]K_{c} =5.00[/tex]   at  1300 K

To determine whether the reaction is at equilibrium or will shift to left or right, determine the Reaction Quotient, which is calculated at any instant of time,

Given,

           [tex][SO_{2} ]=2.40M[/tex]

             [tex][O_{2} ]=0.45M[/tex]

           [tex][SO_{3} ]=3.60M[/tex]

               [tex]Q_{c} =\frac{[SO_{3} ]^2}{[SO_{2} ]^2[O_{2} ]}[/tex]

               [tex]Q_{c} =\frac{(3.60)^2}{(2.40)^2(0.45)}[/tex]

               [tex]Q_{c} =5[/tex]

Since,  

           [tex]K_{c} =5.00[/tex] = [tex]Q_{c}[/tex]

The given reaction is at equilibrium.

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torque τ   = 25.24 N-m

torque  τ  = 12.68 N-m  

mass of the ball  is= 2.5 kg

arm length is  l = 70 cm = 0.7 m

mass of arm is  = 4 kg

we get here  center of mass that is

center of mass =  (m1+m2) rcm =m1 r1+m2 r2

center of mass = 0.44545 m  

and

the torque will be

torque τ   =  F × r ×sinθ  

torque τ   =  (4+2.5)9.8 × 0.4454 × sin90

torque τ   = 25.24 N-m

and now we get the magnitude of the torque  

magnitude of the torque is τ  = F × r ×sinθ

magnitude of the torque is  τ  = (4+2.5)9.8 × 0.4454 × sin60

magnitude of the torque is τ  = 12.68 N-m  

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The wave is traveling in the negative x direction.The wave speed is 12.0m/s.The frequency is 5HzThe wavelength is 2.4m.The displacement is 0.029m.

The general wave equation is given by;

y(x, t) = y cos (2(x/λ) - 2ft)    --------------------------------(i)

y(x, t) is the displacement of the wave at position x and a given time t

y(x, t) = (3.0 cm) × cos[2π(x/(2.4 m) + t/(0.20 s))]   ------------------(ii)

Which can be re-written as;

y(x, t) = (3.0 cm) × cos[2π(x/(2.4 m)) + 2π(t/(0.20 s))]  -------------(iii)

Comparing equations (i) and (iii) we have that;

=> 2π(x/(2.4 m) = 2π(x/λ)

=> λ = 2.4m

Therefore the wavelength of the wave is 2.4m

Also, still comparing the two equations;

=> 2π(t/(0.20 s) = 2πft

=> f = 1 / 0.20

=> f = 5Hz

Therefore the frequency of the wave is 5Hz

To get the wave speed (v), it is given by;

v = f x λ

Where f = 5Hz and λ = 2.4m

=> v = 5 x 2.4

=> v = 12.0m/s

Therefore, the speed of the wave is 12.0m/s

At t = 0.50s and x = 0.20m;

The displacement, y(x,t) of the string wave is given by

y(x, t) = (3.0 cm) × cos[2π(x/(2.4 m) + t/(0.20 s))]

Convert the amplitude of 3.0cm to m

=> 3.0cm = 0.03m

Carefully solve the equation

=> y(x, t) = (0.03m) × cos[2π((0.20)/(2.4 m)) + 2π(0.50/(0.20 s))]

=> y(x, t) = (0.03m) × -0.9684

=> y(x, t) = 0.029m

Therefore the displacement at those points is -0.029m

Also, the sign of the displacement shows that the direction of the wave is in the negative x direction.

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Equation gives a straight result of 8.2*10^2N for friction on each rear wheel. In a similar way, 1.4*10^2N is the result for friction on the front rear wheel. The acceleration is 4.112m.s^2 in magnitude.

We can apply Equation, as suggested in the problem statement. Taking into account the torques around the Centre of mass of the vehicle and the fact that the friction forces are exerted horizontally at the bottom of the wheels, the total friction force there is 3.92m, located 0.75 metres vertically below the centre of mass.

Equation gives the following results for friction on each rear wheel:

friction = (0.42)(3929/2), which is 8.2*10^2N.

In a similar vein, friction on the front and back wheels

friction is (0.42)(7071/2) = 1.4 * 10^2 N

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According to 802.11 comedies the frequencies suitable for the Wireless networking R 2.5 GHz and 5.75 GHz.

The electromagnetic spectrum of the wave contains many types of electromagnetic waves.

Among these waves the waves used for the Wireless networking are radio waves.

The radio waves that are suitable as per the IEEE 802.11 for Wireless networking is suggested to be 2.5 GHz and 5.75 GHz.

These two frequencies are suitable for wireless communication because with their do not harm the environment and they do not intersect with each other.

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Answer:

Below

Explanation:

You will need a hose with double the cross sectional area

 Area = pi r^2    

          pi * (1.5)^2 = 2.25 pi

  now double it to 4.5 pi and solve for r

           4.5 pi = pi r^2

             4.5 = r^2     r = 2.12 cm radius

2.12 - 1.5 = the hose radius should be increased .621 cm

                      this would be .621 * 2 = 1.24 cm wider

When white light is passed through a glass prism it splits into its spectrum of colours (in order violet, indigo, blue, green, yellow, orange and red) and this process of white light splitting into its constituent colours is termed as dispersion.

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Aluminum and silver of 5 kg mass have different thermal energies at the same temperature. Heat moves from a higher to a lower temperature.

Various materials need varying amounts of heat to have similar changes in temperature. When two items with different temperatures come in contact with one another, energy moves from the hotter (higher temperature) object to the cooler (lower temperature) object until both objects reach the same temperature. Temperature change is one of the main outcomes of heat transfer: heating raises the temperature while cooling lowers it.

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Angular Momentum = Angular velocity * Moment of Inertia

[tex](L=I\cdot \omega)[/tex]

[tex]Angular velocity = \omega = \frac{2 \pi}{T} = \frac{2 \pi}{24 \cdot 60 \cdot 60 sec}=\frac{\pi}{12\cdot 3600} rads/sec[/math][/tex]

[tex]Moment of inertia of a uniform sphere = \frac{2}{5}Mr^2\\ = \frac{2}{5}5.972 \times 10^{24} kg \cdot (6.371\times 10^6 m)^2[/tex]

Angular Momentum of Earth rotating on its axis (assuming that Earth is a solid sphere with its mass distributed evenly):

[tex]L=I\cdot \omega= \frac{\pi}{12\cdot 3600} rads/sec \cdot \frac{2}{5}5.972 \times 10^{24} kg \cdot (6.371\times 10^6 m)^2=\frac{\pi\cdot 2\cdot 5.972 \times 10^{24} \cdot(6.371\times 10^6)^2}{12\cdot 3600\cdot 5} kg m^2 / s = 7.051\times 10^{33} kg m^2 / s[/tex]

What is angular momentum?

The rotating equivalent of linear momentum in physics is called angular momentum. Because it is a conserved quantity—the total angular momentum of a closed system stays constant—it is a significant physical quantity. Both the direction and the amplitude of angular momentum are conserved.

Hence, the answer is [tex]7.051\times 10^{33} kg m^2 / s[/tex]

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