Please help pls help mEE THIS IS REALLY CONFUSING MARKING BRAINlIST AND GIvinG 50 POINTS IF CORRECT!!
The ratio of the number of cupcakes to the number of pastries in a box is 7:2. Which table shows the possible amounts of cupcakes and pastries in a box, given the ratio?
Last box
If you found this useful, please mark it as the BRAINLIEST.XDHave a nice day ツAs it's 7:2
The variation is directDifference between x and y must increase in big number as x and y increases
Option D is correct in that manner
Let's double check
7:214:428:856:16question in pictures
The derivatives of the functions are listed below:
(a) [tex]f'(x) = -7\cdot x^{-\frac{9}{2} }- 2\cdot x + 4 - \frac{1}{5} - 5\cdot x^{-2}[/tex]
(b) [tex]f'(x) = \frac{1}{3}\cdot (x + 3)^{-\frac{2}{3} }\cdot (x+ 5)^{\frac{1}{3} } + \frac{1}{3} \cdot (x + 5)^{-\frac{2}{3} } \cdot (x + 3)^{\frac{1}{3} }[/tex]
(c) f'(x) = [(cos x + sin x) · (x² - 1) - (sin x - cos x) · (2 · x)] / (x² - 1)²
(d) f'(x) = (5ˣ · ㏑ 5) · ㏒₅ x + 5ˣ · [1 / (x · ㏑ 5)]
(e) f'(x) = 45 · (x⁻⁵ + √3)⁻⁸ · x⁻⁶
(f) [tex]f'(x) = (\ln x + 1)\cdot [7^{x\cdot \ln x \cdot \ln 7}+7\cdot (x\cdot \ln x)^{6}][/tex]
(g) [tex]f'(x) = -2\cdot \arccos x \cdot \left(\frac{1}{\sqrt{1 - x^{2}}} \right) - \left(\frac{1}{1 + x} \right) \cdot \left(\frac{1}{2} \cdot x^{-\frac{1}{2} }\right)[/tex]
(h) f'(x) = cot x + cos (㏑ x) · (1 / x)
How to find the first derivative of a group of functions
In this question we must obtain the first derivatives of each expression by applying differentiation rules:
(a) [tex]f(x) = 2 \cdot x^{-\frac{7}{2} } - x^{2} + 4 \cdot x - \frac{x}{5} + \frac{5}{x} - \sqrt[11]{2022}[/tex]
[tex]f(x) = 2 \cdot x^{-\frac{7}{2} } - x^{2} + 4 \cdot x - \frac{x}{5} + \frac{5}{x} - \sqrt[11]{2022}[/tex] Given[tex]f(x) = 2 \cdot x^{-\frac{7}{2} } - x^{2} + 4\cdot x - \frac{x}{5} + 5 \cdot x^{-1} - \sqrt[11]{2022}[/tex] Definition of power[tex]f'(x) = -7\cdot x^{-\frac{9}{2} }- 2\cdot x + 4 - \frac{1}{5} - 5\cdot x^{-2}[/tex] Derivative of constant and power functions / Derivative of an addition of functions / Result(b) [tex]f(x) = \sqrt[3]{x + 3} \cdot \sqrt[3]{x + 5}[/tex]
[tex]f(x) = \sqrt[3]{x + 3} \cdot \sqrt[3]{x + 5}[/tex] Given[tex]f(x) = (x + 3)^{\frac{1}{3} }\cdot (x + 5)^{\frac{1}{3} }[/tex] Definition of power[tex]f'(x) = \frac{1}{3}\cdot (x + 3)^{-\frac{2}{3} }\cdot (x+ 5)^{\frac{1}{3} } + \frac{1}{3} \cdot (x + 5)^{-\frac{2}{3} } \cdot (x + 3)^{\frac{1}{3} }[/tex] Derivative of a product of functions / Derivative of power function / Rule of chain / Result(c) f(x) = (sin x - cos x) / (x² - 1)
f(x) = (sin x - cos x) / (x² - 1) Givenf'(x) = [(cos x + sin x) · (x² - 1) - (sin x - cos x) · (2 · x)] / (x² - 1)² Derivative of cosine / Derivative of sine / Derivative of power function / Derivative of a constant / Derivative of a division of functions / Result(d) f(x) = 5ˣ · ㏒₅ x
f(x) = 5ˣ · ㏒₅ x Givenf'(x) = (5ˣ · ㏑ 5) · ㏒₅ x + 5ˣ · [1 / (x · ㏑ 5)] Derivative of an exponential function / Derivative of a logarithmic function / Derivative of a product of functions / Result(e) f(x) = (x⁻⁵ + √3)⁻⁹
f(x) = (x⁻⁵ + √3)⁻⁹ Givenf'(x) = - 9 · (x⁻⁵ + √3)⁻⁸ · (- 5) · x⁻⁶ Rule of chain / Derivative of sum of functions / Derivative of power function / Derivative of constant functionf'(x) = 45 · (x⁻⁵ + √3)⁻⁸ · x⁻⁶ Associative and commutative properties / Definition of multiplication / Result(f) [tex]f(x) = 7^{x\cdot \ln x} + (x \cdot \ln x)^{7}[/tex]
[tex]f(x) = 7^{x\cdot \ln x} + (x \cdot \ln x)^{7}[/tex] Given[tex]f'(x) = 7^{x\cdot\ln x} \cdot \ln 7 \cdot (\ln x + 1) + 7\cdot (x\cdot \ln x)^{6}\cdot (\ln x + 1)[/tex] Rule of chain / Derivative of sum of functions / Derivative of multiplication of functions / Derivative of logarithmic functions / Derivative of potential functions [tex]f'(x) = (\ln x + 1)\cdot [7^{x\cdot \ln x \cdot \ln 7}+7\cdot (x\cdot \ln x)^{6}][/tex] Distributive property / Result(g) [tex]f(x) = \arccos^{2} x - \arctan (\sqrt{x})[/tex]
[tex]f(x) = \arccos^{2} x - \arctan (\sqrt{x})[/tex] Given[tex]f'(x) = -2\cdot \arccos x \cdot \left(\frac{1}{\sqrt{1 - x^{2}}} \right) - \left(\frac{1}{1 + x} \right) \cdot \left(\frac{1}{2} \cdot x^{-\frac{1}{2} }\right)[/tex] Derivative of the subtraction of functions / Derivative of arccosine / Derivative of arctangent / Rule of chain / Derivative of power functions / Result(h) f(x) = ㏑ (sin x) + sin (㏑ x)
f(x) = ㏑ (sin x) + sin (㏑ x) Givenf'(x) = (1 / sin x) · cos x + cos (㏑ x) · (1 / x) Rule of chain / Derivative of sine / Derivative of natural logarithm /Derivative of addition of functions f'(x) = cot x + cos (㏑ x) · (1 / x) cot x = cos x / sin x / ResultTo learn more on derivatives: https://brainly.com/question/23847661
#SPJ1
You are volunteering to help with the soccer team's Valentine's Day fundraiser. Each 16-ounce bag of nuts the team sold must include at least 60% chocolate-covered nuts inside.
However, instead of receiving a shipment of separated plain nuts and chocolate nuts, they delivered two large containers of mixed nuts. The first says it is 50/50 plain and chocolate covered. The second contains 80% chocolate-covered nuts.
The team is dismayed, but you come up with a solution. You suggest combining
ounces* of the 50/50 nuts with
ounces* of the 80% chocolate-covered nuts, to create the 60% mixture required for each bag.
*estimate
Then Bob, another student on the team says, "Wait, we promised at least 60%. So if we just do half and half, won't we be giving them at least 60%?"
Bob
correct.
Proportionately, if they do half and half of 50% and 80% of the two bags, Bob is correct.
What is a proportion?A proportion is a mathematical measure that compares two variables or numbers.
Proportions can be stated in percentages or ratios, as decimals or fractions.
Data and Calculations:Content of 16-ounce bag of nuts = 60% chocolate-covered nuts
Content of first bag = 50/50 plain and chocolate-covered nuts
Content of second bag = 80% chocolate-covered nuts
A mixture of half of 50% bag with half of 80% bag will result in 65% (50% + 80%)/2.
Thus, since the promise for each 16-ounce bag is for at least 60% chocolate-covered nuts, Bob is correct.
Learn more about proportion at https://brainly.com/question/870035
#SPJ1
Question Completion:Is Bob correct?
. Last weekend, Michael
drove to his friend's house.
When he left, he noticed
that the fuel gauge in his
car indicated that his gas
tank was 4 full. When he
returned home, the fuel
gauge in his car indicated
that his gas tank was ½ full.
If the gas tank holds 24
gallons, how many gallons
did Michael use on his
drive?
It can be said that the total amount of fuel that was used by Michael when he was away to his friends was 12 gallons.
How to solve for the quantity.The question said that the tank was full before he left to his friends. This was after he checked the gauge of the gas tank.
The question says that the required quantity needed to fill up this tank is 24 gallon. Hence if it is full, then the total gallon it had before he made this trip was 24 gallon.
Then we are told that he went ahead to check the gauge when he finished and was at home. The quantity of fuel he had at this time was 1/2 of what was there.
This would be 1/2 * 24
12
Hence he made use of 12 gallons when he was away.
Read more on quantities here:
https://brainly.com/question/809966
#SPJ1
Vanessa knows that about 20% of the students in her school are bilingual. She wants to estimate the probability that if 3 students were randomly selected, all 3 of them would be bilingual. To do so, she will use a spinner with 5 equally sized sections labeled as either "bilingual" or "monolingual". She will spin the spinner 3 times, record the results, and repeat the process 50 times.
How many of the 5 sections should she label "bilingual"?
How many of the 5 sections should she label "monolingual"?
Answer:
1 section should be labelled "bilingual".
4 sections should be labelled "monolingual".
Step-by-step explanation:
If 20% of students in the school are bilingual, then 80% of students in the school are monolingual, since 100% - 20% = 80%.
If the spinner is to be divided into 5 equally sized sections, with each section labeled as "bilingual" or "monolingual" to represent the corresponding proportion of students in the school, then:
Bilingual
20% of 5
= 20/100 × 5
= 100/100
= 1 section
Monolingual
80% of 5
= 80/100 × 5
= 400/100
= 4 sections
Therefore:
1 section should be labelled "bilingual".4 sections should be labelled "monolingual".For the equation:
y=−x^2+10x−24, the x-intercepts are already given on the graph. Now, using the parabola tool, graph rest of the equation.
The graph of the parabola can be seen in the image below.
How to graph the parabola?
We need to find some points on the parabola, and then draw a curve that connects them.
On the graph you already have the x-intercepts, so you already have two points.
Now let's get another point which is the vertex.
For our parabola:
[tex]y = -x^2 + 10x - 24[/tex]
The vertex is at:
[tex]x = -10/(2*-1) = 5[/tex]
Evaluating in x = 5 we get:
[tex]y = -5^2 + 10*5 - 24 = 1[/tex]
So we also have the point (5, 1), now we can just connect the points and get the parabola:
If you want to learn more about parabolas:
https://brainly.com/question/4061870
#SPJ1
urgently need help please help
Answer: 40
Step-by-step explanation:
Sub x=4 into 3x²-2x+1
∴ 3(4)²-2(4)+1
=3(16)-8+1
=48-8+1
=40
Answer:
41
Step-by-step explanation:
substitute the x to 4
so 3(4)² - 2(4) + 1 = 41
it took a 3D priner 10528 minutes to print 87 percent of a 3D print job. At this rate of speed how much time will take for the print to
reach 100 percent completion?
The time it would take for the print to reach 100 percent completion is 12,101 minutes 9 seconds.
What is time it would take to reach 100%?The mathematical operations that would be used to determine the required value are division and multiplication. Division is the process of grouping a number into equal parts using another number. The sign used to denote division is ÷. Multiplication is the process of determining the product of two or more numbers. The sign used to denote multiplication is ÷.
Other mathematical operations that are used to solve problems include addition and subtraction.
Time it would take to reach 100% completion = (minutes it takes to print 87% of the words x 100%) / 87%
Time it would take to reach 100% completion = (10,528 x 1) / 0.87 =
10.528 / 0.87
= 12,101. 15
= 12,101+ (0.15 x 60)
= 12,101 minutes 9 seconds
To learn more about division, please check: https://brainly.com/question/13281206
#SPJ1
Question 3 of 10
If a circle has a diameter of 24 inches, which expression gives its area in
square inches?
OA. 12. T
OB. 242. T
O C. 122. T
OD. 24. T
SUBMIT
Answer:
OB:.242.T gives it's area in square inches
HELPPPP PLSSSSSss!!!!!!!
Answer:(5-1)(7-1)
Step-by-step explanation:
We have give 4 numbers that are 1,1,5,7. we have to apply operations on it to make it 24.
Solution :» ( 7 - 1) × (5 - 1)
» (6) × (4)
» 24
Here's our answer..!!
What is the solution to this equation?
9x - 4(x - 2) = x + 20
9x - 4(x - 2) =x + 20
We move all terms to the left:
9x -4(x - 2) - (x + 20) = 0Multiply
9x - 4x -(x + 20) + 8 = 0We get rid of the parentheses.
9x - 4x - x - 20 + 8 = 0We add all the numbers and all the variables.
4x - 12 = 0We move all terms containing x to the left hand side, all other terms to the right hand side
4x=12x = 12/4x = 3Cos(11*)cos(19*) - sin(11*) sin(19*)
Write the expression as a function of one number then find it’s exact value.
Answer:
√3/2
Step-by-step explanation:
This is compound angle of cosine
cos(11+19)
=cos(30)
=√3/2
An account begins the year with a
$4000.00 balance. If the account
earns 3% simple interest, what is the
balance at the end of one year?
A. $4,120.00
C. $4,300.00
B. $4,003.00
D. $4,012.00
[tex]s = c(1 + in) \\ s = 4000(1 + 0.03 \times 1) [/tex]
[tex]s = 4120.00[/tex]
Option: AEvaluate the expression
for (2^2x2/xy^2) for x=3 and y=2
Step-by-step explanation:
(2^2x²/xy²) for x=3 and y=2
we have
2^2(3)²/((3)(2²))
2^2(9)/((3)(4))
2^18/12
262144/12
21845.3
The value of expression [tex]2^{2} x^{2}/xy^{2}[/tex] for x=3 and y=2 is, 3
What are expressions?An expression is a sentence with at least two numbers or variables having mathematical operation. Math operations can be addition, subtraction, multiplication, division.
For example, 2x+3
Given that,
The expression, [tex]2^{2} x^{2}/xy^{2}[/tex]
The value of expression when, x = 3 & y = 2
⇒ 2²×3²/3×2²
⇒ 3
Hence, The value is 3
To know more about Expressions check:
brainly.com/question/16804733
#SPJ2
A coordinate grid with 2 lines. One line, labeled f(x) passing through (negative 2, 4), (0, 2), and the point (1, 1). The other line is labeled g(x) and passes through (negative 3, negative 3), (0, 0) and the point (1, 1). Which input value produces the same output value for the two functions on the graph? x = −1 x = 0 x = 1 x = 2 Mark this and return
Answer:
Step-by-step explanation:
why is it so hard omg
Which of the following options have the same value as 5\%5%5, percent of 353535?
Answer:
[tex]\frac{5}{100}\times35[/tex]
[tex]0.05\times35[/tex]
Step-by-step explanation:
Given:
Which of the following options have the same value as 5% 35, percent of 35?
Following Options:
[tex]5 \times 35[/tex]
[tex]\frac{5}{100}\times35[/tex]
[tex]0.5\times0.35[/tex]
[tex]0.05\times35[/tex]
[tex]\frac{5}{10}\times35[/tex]
Solve:
[tex]5[/tex] % [tex]= 0.05=\frac{5}{100}[/tex]
Thus the following options:
[tex]5 \times 35[/tex] [ False x ]
5 does not equal 5%
[tex]\frac{5}{100}\times35[/tex] [True √ ]
[tex]5[/tex]% [tex]=\frac{5}{100}[/tex]
[tex]0.5\times0.35[/tex] [ False x ]
[tex]0.5 = 0.50[/tex]
[tex]0.05\times35[/tex] [True √ ]
[tex]5[/tex]% [tex]= 0.05=\frac{5}{100}[/tex]
[tex]\frac{5}{10}\times35[/tex] [ False x ]
[tex]\frac{5}{10}=0.50[/tex]
Therefore, the options [B] [tex]\frac{5}{100}\times35[/tex] and [D] [tex]0.05\times35[/tex] is True.
Kavinsky
Solve the following equation for W.
P=2L+2W
**Disclaimer** Hi there! I assumed the question is to represent W in terms of all other variables (P, L). The following answer corresponds to this understanding. If it is incorrect, please let me know and I will modify my answer.
Answer: W = (P/2) - L
Step-by-step explanation:
Given equation
P = 2L + 2W
Factorize 2 out
P = 2 (L + W)
Divide 2 on both sides
P / 2 = 2 (L + W) / 2
P / 2 = L + W
Subtract L on both sides
(P / 2) - L = L + W - L
[tex]\Large\boxed{W=\frac{P}{2} -L}[/tex]
Hope this helps!! :)
Please let me know if you have any questions
Answer:
[tex]\displaystyle{W = \dfrac{P}{2} - L}[/tex]
Step-by-step explanation:
To solve for W, we have to isolate the W-variable. First, we can factor the expression 2L + 2W to 2(L+W):
[tex]\displaystyle{P = 2(L+W)}[/tex]
Next, we'll be dividing both sides by 2:
[tex]\displaystyle{\dfrac{P}{2} = \dfrac{2(L+W)}{2}}\\\\\displaystyle{\dfrac{P}{2} = L+W}[/tex]
Then subtract both sides by L:
[tex]\displaystyle{\dfrac{P}{2} - L= L+W-L}\\\\\displaystyle{\dfrac{P}{2} - L= W}[/tex]
Therefore, we'll obtain W = P/2 - L.
Note that the given formula is perimeter formula of a rectangle where Perimeter = 2 * Length + 2 * Width.
So if we solve for W (Width) then we'll get Width = Perimeter / 2 - Length which can be useful to find width with given perimeter and length.
So I need to know what company changes more or less
In a recent year, 28.7% of all registered doctors were female. If there were 52,900 female registered doctors that year, what was the total number of registered doctors?
Step-by-step explanation:
(52900 ÷ 28.7) × 100 = 184320 ( rounded to nearest whole number, since you cannot have half humans)
Patel is solving 8x2 + 16x + 3 = 0. Which steps could he use to solve the quadratic equation? Select three options. 8(x2 + 2x + 1) = –3 + 8 x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot x = –1 Plus or minus StartRoot StartFraction 4 Over 8 EndFraction EndRoot 8(x2 + 2x + 1) = 3 + 1 8(x2 + 2x) = –3
The options Patel has to solve the quadratic equation 8x² + 16x + 3 = 0 is x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot.
Quadratic equation8x² + 16x + 3 = 0
8x² + 16x = -3
8(x² + 2x) = -3
Using completing the square8(x² + 2x + 1) = -3 + 8
factorization8(x² + 1) = 5
(x² + 1) = 5/8
Taking the square root of both sides(x + 1) = ± √5/8
x = -1 ± √5/8
Therefore,
x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot
Learn more about quadratic equation:
https://brainly.com/question/1214333
#SPJ1
If
m ≤ f(x) ≤ M
for
a ≤ x ≤ b,
where m is the absolute minimum and M is the absolute maximum of f on the interval [a, b], then
m(b − a) ≤
b
a
f(x) dx ≤ M(b − a).
Use this property to estimate the value of the integral.
⁄12 7 tan(4x) dx
It's easy to show that [tex]7\tan(4x)[/tex] is strictly increasing on [tex]x\in\left[0,\frac\pi8\right][/tex]. This means
[tex]M = \max \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/12} = 7\sqrt3[/tex]
and
[tex]m = \min \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/16} = 7[/tex]
Then the integral is bounded by
[tex]\displaystyle 7\left(\frac\pi{12} - \frac\pi{16}\right) \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le 7\sqrt3 \left(\frac\pi{12} - \frac\pi{16}\right)[/tex]
[tex]\implies \displaystyle \boxed{\frac{7\pi}{48}} \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le \boxed{\frac{7\sqrt3\,\pi}{48}}[/tex]
For a standard normal distribution, find:
P(-1.64 < z < 0.2)
For a standard normal distribution, the probability of the 2 - scores P(-1.64 < z < 0.2) is 0.52876
How to find the p-value from 2 z-scores?
We want to find the p-value between 2 z-scores expressed as;
P(-1.64 < z < 0.2)
To solve this, we will solve it as;
P(-1.64 < z < 0.2) = 1 - [P(z < -1.64) + P(z > 0.2)]
From normal distribution table, we have that;
P(x < -1.64) = 0.050503
P(x > 0.2) = 0.42074
Thus;
P(-1.64 < z < 0.2) = 1 - (0.050503 + 0.42074)
P(-1.64 < z < 0.2) = 0.52876
Thus, For a standard normal distribution, the probability of the 2 - scores P(-1.64 < z < 0.2) is 0.52876
Read more about p-value from z-score at; https://brainly.com/question/4621112
#SPJ1
If you chose an angle, how are the construction steps you completed similar to the steps you would have taken to construct and bisect a line segment? How are they different?
There are different ways to construct an angle. The steps used in making a line segment are; First, you have to put the compass at one specific end of the line segment. Then you shift the compass slowly a little bit so it will be longer than half the length of the line segment. Then you have to draw arcs up and down the line. while using the same compass width, you then draw arcs from one specific end of the line. and thereafter you put your ruler at the point where the arcs cross, and you then draw the line segment. The difference is that to bisect an angle, one has to divide the shape or angle into two congruent parts while in the construction of a line segment, there are differences in length. What is the construction process of Angles? This entails a good construction process in making angles. They are step-by-step processes used to produce detailed and exact geometric figures.
121 slabs . How many slabs will she need to lay in each row to make a square
She needs to lay 11 slabs on each row to make a square
How to determine the number of slabs in each row?The total number of slabs is given as:
Total = 121 slabs
Let this represent the area of the slab.
The area of a square is calculated as:
Area = Length^2
Substitute the known values in the above equation
Length^2 = 121
Take the square root of both sides
Length = 11
Hence, she needs to lay 11 slabs on each row to make a square
Read more about squares at:
https://brainly.com/question/24487155
#SPJ1
9) If m/1 = 45° and 21 and 22 are complementary angles. Find m22.
❄ Hi there,
keeping in mind that the sum of complementary angles is 90°,
set up an equation, letting [tex]\angle2[/tex] be x –
[tex]\triangleright \ \sf{\angle1+x=90}[/tex] {and we know that [tex]\boxed{\angle1=45}[/tex]}
[tex]\triangleright \ \sf{45+x=90}[/tex]
[tex]\triangleright \ \sf{x=90-45}[/tex]
[tex]\triangleright \ \sf{x=45}[/tex]
[tex]\triangleright \ \sf{\angle2=45\textdegree}[/tex]
__________
Keeping in mind that a right angle is 90°,
set up an equation, letting [tex]\angle1[/tex] be x:
[tex]\triangleright \ \sf{x+\angle2=90}[/tex] {and we know that [tex]\boxed{\angle2=63}[/tex]}
[tex]\triangleright \ \sf{x+63=90}[/tex]
[tex]\triangleright \ \sf{x=27}[/tex]
[tex]\triangleright \ \sf{\angle1=47\textdegree}[/tex]
❄
Let f(r) = 6,
find f-¹(r)
There is no answer because there cannot be one to one function inverse.
PLS HELP plsssssssssssssss
Answer:
a. 33
Step-by-step explanation:
a straight line is 180° so
3x = 180 - 81
3x = 99
to find x divide by 3
x = 99/3
x = 33
Craig has a watch that is losing time. For every minute that passes, his watch loses 10 seconds. If Craig set his watch correctly at 9am, what time whould it show when it is 10am on the house clock?
Answer:
9:50 am
Step-by-step explanation:
because 10 x 60 is equal to 1 hour, so you get 600 seconds subtracted from 10am. 600 seconds is equal to 10 minutes. so 10 am - 10 minutes = 9:50am
What is the equation of the line described below in slope-intercept form?
The line passing through point (-1, 5) and parallel to the line whose equation is x + y = 10
keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above
[tex]x + y = 10\implies y = -x+10\implies y=\stackrel{\stackrel{m}{\downarrow }}{-1}x+10 \leftarrow \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}[/tex]
so, we're really looking for the equation of al ine whose slope is -1 and that passes through (-1 , 5)
[tex](\stackrel{x_1}{-1}~,~\stackrel{y_1}{5})\hspace{10em} \stackrel{slope}{m} ~=~ -1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{-1}( ~~ x-\stackrel{x_1}{(-1) ~~ }) \\\\\\ y-5 = -(x+1)\implies y-5=-x-1\implies y=-x+4[/tex]
A rectangular tank 60cm long, 50cm wide and 24cm height was 1/3 filled with water at first. A tap was turned on to completely fill the tank. The rate of water flowing from the tap into the tank was 3 litre per minute. How long did it take to fill the tank completely? Give your answers in minutes.
