Given the function f(x) = -5|x + 1 + 3, for what values of x is f(x) = -12?
O x = -2x = 4
O x = -2, x = 4
O x = 2, X= 4
O x= 2 X= 4

[tex] {\bold{\red{\huge{\mathbb{QUESTION}}}}} [/tex]

what is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each

[tex]\bold{ \red{\star{\blue{GIVEN }}}}[/tex]

TOTAL NUMBER OF ARTICLE= 7

ARTICLES FOR 30K = 3

ARTICLES FOR 12.5K = 7-3= 4

[tex]\bold{\blue{\star{\red{TO \: \: FIND}}}}[/tex]

Average cost of 7 articles

[tex] \bold{ \green{ \star{ \orange{FORMULA \: USED}}}}[/tex]

[tex] \red{AVERAGE = \frac{TOTAL \: COST}{ NUMBER \: OF\: ARTICLES }}[/tex]

[tex] \huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}[/tex]

[tex]Average \: cost \: of \: 7 \: articles - > \\ \frac{(3 \times 30k) + (12 .5k \times 4)}{7} \\ \frac{90k + 50k}{7} \\ \frac{140k}{7} \\ \blue {Average \: cost \: of \: 7 \: articles - >} \\ 20k[/tex]

Answer:

x ≈ 52.1°

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan x = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{KL}{LM}[/tex] = [tex]\frac{36}{28}[/tex] , then

x = [tex]tan^{-1}[/tex] ([tex]\frac{36}{28}[/tex] ) ≈ 52.1° () to the nearest tenth )

Answer:

x = 5

Step-by-step explanation:

comment if you need explanation

Answer:

Step-by-step explanation:

It just so happens that x is the hypotenuse in the right triangle with sides 3 and 4. To find x we use Pythagorean's Theorem:

[tex]x^2=3^2+4^2[/tex] and

[tex]x^2=9+16[/tex] and

[tex]x^2=25[/tex] so

x = 5

[tex]\displaystyle\bf h(x)=-4x-7\Longrightarrow h(3)=-4\cdot3-7=-19\\\\Answer:\boxed{ h(3)=-19}[/tex]

Answer:

-19

Step-by-step explanation:

heyya, so if x = 3 you just replace the x in the calculation to 3:

-4 *3 -7

= -12 -7

= -19

Answer:

Step-by-step explanation:

[tex]Quotient \ of \ 10 \ and \ x = 10 \div x[/tex]

Answer:

90 degrees

Step-by-step explanation:

B is the corner and angle opposite of the side AC.

so, AC is becoming side c, and the other two are a and b (it does not matter which is which).

we use the enhanced Pythagoras formula for general triangles

c² = a² + b² - 2ab×cos(C)

in our example the angle C is named B.

but other than that we simply calculate

10² = 6² + 8² - 2×6×8×cos(B)

100 = 36 + 64 - 96×cos(B)

100 = 100 - 96×cos(B)

0 = -96×cos(B)

cos(B) = 0

=>

B = 90 degrees

Hello,

First, you must understand that

(f-g)(x) means f(x)-g(x) it is the difference of two functions :

f(x)=2x+4 and g(x)=3x-7

f(5)=2*5+4=10+4=14

g(5)=3*5-7=15-7=8

So, (f-g)(5)= f(5)-g(5)=14-8=6

Answer A: none of the choices are correct.

An other way to do it:

(f-g)(x)=f(x)-g(x)=2x+4-(3x-7)= 2x-3x+4+7=-x+11

if x= 5 then (f-g)(5)=-5+11=6

Answer:

Kindly check attached picture

Step-by-step explanation:

Based d on the instruction given.

1.)

-3 * 6 = 18

6 * - 2 = - 12

-3 * - 2 = 6

2.)

We use logical reasoning to find 2 numbers whichbwhen multiplied gives the number in the box in between :

The answers are given in the picture attached.

Answer:

[tex]{ \bf{f(x) = {x}^{3} + {ax}^{2} - 1 }} \\ { \tt{f( - 1) : {( - 1)}^{3} + a {( - 1)}^{2} - 1 = 0}} \\ { \tt{f( - 1) : a - 2 = 0}} \\ a = 2[/tex]

The polynomial function [tex]$x^3 + ax^2 -1[/tex] will have -1 as a root at the value of

a = 2.

A polynomial function exists as a function that applies only non-negative integer powers or only positive integer exponents of a variable in an equation like the quadratic equation, cubic equation, etc.

Given: A root exists at a value of x such that the polynomial exists equivalent to zero.

Let, the polynomial equation be [tex]$x^3 + ax^2 -1[/tex]

then [tex]$\mathbf{f}(\mathbf{x})=\mathbf{x}^{3}+a \mathbf{x}^{2}-\mathbf{1}$[/tex]

Put, x = -1, then we get

[tex]$\mathbf{f}(-1)=(-1)^{3}+\mathrm{a}(-1)^{2}-1=0$[/tex]

f(-1) = a - 2 = 0

a = 2

Therefore, the value of a = 2.

To learn more about polynomial function

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Answer:

AL= 6.63

Step-by-step explanation:

C = 2[tex]\pi r[/tex]

C = 2[tex]\pi 10[/tex]

C = 20[tex]\pi[/tex]

[tex]AL = \frac{38}{360} 20\pi[/tex]

AL= 6.63

The length of the arc travelled by the car is 6.63 feet.

The distance along the part of circumference of any circle or any curve (arc) is called arc length of a circle.

Arc length = θ×[tex]\frac{\pi }{180}[/tex]× r

where,

θ is central angle of arc

r is the radius of circle

The diameter of a circle is any straight line segment that passes through the center of the circle and whose end points lie on the circumference of the circle.

diameter = 2× radius

According to the given question

we have

θ = 38 degrees

diameter = 20ft

⇒ radius = [tex]\frac{20}{2}[/tex]

⇒ radius = 10

Therefore,

the arc length the car traveled = 38×[tex]\frac{\pi }{180}[/tex]× 10

= 38×[tex]\frac{3.14}{180}[/tex]×10

=[tex]\frac{1193.2}{180}[/tex]

=6.63 feet

Hence, the arc length the car travelled is 6.63feet.

Learn more about the arc length here:

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Answer:

the distance between the lines is 2.48

Answer:

this as a equation looks like this

-1/2x+1+x=11

1/2x=10

x=20

Hope This Helps!!!

20 dollars were originally in the box

Two or more expressions with an Equal sign is called as Equation.

Given,

In an office there was a small cash box.

One day ann took half of the money plus$1 more

Then dan took half of the remaining money plus$1 more

Stan then took the remaining $11

-1/2x+1+x=11

Subtract 1/2x from both sides

1/2x=10

Multiply 2 on both sides

x=20

Hence, 20 dollars were originally in the box

To learn more on Equation:

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Answer:

Answer:

[tex]\left(sin\theta -cos\:a\right)\left(cos\:a+sin\theta \right)[/tex]

(sin(θ)-cos(a))(cos(a)+sin(0))

[tex]\mathrm{Apply\:Difference\:of\:Two\:Squares\:Formula:\:}\left(a-b\right)\left(a+b\right)=a^2-b^2[/tex]

a=sin(θ),b=cos(a)

= sin²(θ)-cos²(a)

-------------------------------

hope it helps...

have a great day!!

Answer:

5 3/5

Step-by-step explanation:

3 1/2 * 1 3/5

Change to  improper fractions

(2*3+1)/2  * (5*1+3)/5

7/2 * 8/5

56/10

Change back to a mixed number

50/10 +6/10

5 +3/5

5 3/5

Answer:

Step-by-step explanation:

z = (k*x*y) / w²

Where,

k = constant of proportionality

z = 72 when x = 80, y = 30 and w = 5

z = (k*x*y) / w²

72 = (k * 80 * 30) / 5²

72 = 2400k / 25

Cross product

72 * 25 = 2400k

1800 = 2,400k

k = 2,400/1800

k = 24/18

= 4/3

k = 1 1/3

k = 1.33

find z when x = 20, y = 60 and w=9

z = (k*x*y) / w²

z = (1.33 * 20 * 60) / 9²

z = (1596) / 81

Cross product

81z = 1596

z = 1596/81

z = 19.703703703703

Approximately,

z = 19.7

Answer:

7500 m

Step-by-step explanation:

5500 is the initial height. It increased by 1500, so 5500 + 1500 = 7000. Then it went down 2000 meters, so 7000 - 2000 = 5000. It went up 2500 again. 5000 + 2500 = 7500

Step-by-step explanation:

12/3.75 = 3.2 a gallon

Answer:

i don't understand the question

Answer:

ok so lets divide 90 by 15 to get 6 so she gets paid 6 per student and that means lisa gets paid 12 so lets just multiply

6*20=120 so mary gets paid 120

and lisa gets paid doable that so 420

but i don't know there base pay so the i can't answer this problem

Hope This Helps!!!

Answer:

Following are the solution to the given points:

Step-by-step explanation:

For question 1:

[tex]\to 3^{-4}= \frac{1}{3^4}=\frac{1}{81}=0.0123456789[/tex]

For question 2:

[tex]\to (-2)^{3}\cdot(-2)^{4}\cdot(-2)^{-1}=-8\cdot-16\cdot -\frac{1}{2}= 128\cdot -\frac{1}{2}=-64[/tex]

For question 3:

[tex]\to 7^{-4} \div 7^{-2}= \frac{1}{7^{4}} \div \frac{1}{7^{2}}=\frac{1}{7^{4}} \times \frac{7^{2}}{1}=\frac{1}{7^{2}} =\frac{1}{49} =0.0204081633[/tex]

For question 4:

[tex]\to [(-3)^{2}]^3= (-3)^{2\cdot 3}= (-3)^{6}=729[/tex]

For question 5:

[tex]\to [5 \cdot (-3)]^{2}= 25 \cdot 9=225[/tex]

For question 6:

[tex]\to [(10 \div 5)]^{3}= [(\frac{10}{5})]^{3}=[2]^{3}=8[/tex]

For question 7:

[tex]\to 10^6 \cdot 10^{-4} \cdot 10^2= 10^6 \cdot \frac{1}{10^{4}} \cdot 10^2= 10^2 \cdot 10^2=10^4=10,000[/tex]

For question 8:

[tex]\to (-4)^{-5}=\frac{1}{(-4)^{5}}=- \frac{1}{1,024}=-0.0009765625[/tex]

For question 9:

[tex]\to \frac{2^3}{2^4}= \frac{8}{16}=\frac{1}{2}=0.5[/tex]

For question 10:

[tex]\to (-6)^3 \cdot (-6)^5 \cdot (-6)^{-5}= (-6)^3 \cdot (-6)^5 \cdot \frac{1}{(-6)^{5}}= (-6)^3 =-216[/tex]

Answer:

x = -6

Step-by-step explanation:

sum means +

36 + 3x = 18

3x = 18 - 36

3x = -18

x = -6

Answer:

Step-by-step explanation:

36 + 3x = 18

subtract 36 from both sides

3x= -18

divide by 3

x = -6

Answer:

(10, - 1 )

Step-by-step explanation:

Given the 2 equations

x - 3y = 13 → (1)

x + 2y = 8 → (2)

Rearrange (1) making x the subject by adding 3y to both sides

x = 3y + 13 → (3)

Substitute x = 3y + 13 into (2)

3y + 13 + 2y = 8

5y + 13 = 8 ( subtract 13 from both sides )

5y = - 5 ( divide both sides by 5 )

y = - 1

Substitute y = - 1 into (3) for corresponding value of x

x = 3(- 1) + 13 = - 3 + 13 = 10

solution is (10, - 1 )

Answer:

48 days

Step-by-step explanation:

Swim = every 6 days

Run = every 4 days

Cycles = every 16 days

Find the lowest common multiple of 6, 4 and 16

6 = 6, 12, 18, 24, 30, 36, 42, and 48

4 = 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48

16 = 16, 16, 32, 48, 64, 80, 96, 112, 128, 144, 160

The LCM of 6, 4 and 16 is 48

Therefore,

If she did all 3 activities today, she will do all 3 activities again in the next 48 days

Answer:

You need to convert all the units to one unit

Answer:

[tex]2y^2-7y+6=0[/tex]

Step-by-step explanation:

We are given that [tex]\alpha[/tex] and [tex]\beta[/tex] are the zeroes of the polynomial [tex]6y^2-7y+2[/tex]

[tex]y^2-\frac{7}{6}y+\frac{1}{3}[/tex]

We have to find a quadratic polynomial whose zeroes are [tex]1/\alpha[/tex] and [tex]1/\beta[/tex].

General quadratic equation

[tex]x^2-(sum\;of\;zeroes)x+ product\;of\;zeroes[/tex]

We get

[tex]\alpha+\beta=\frac{7}{6}[/tex]

[tex]\alpha \beta=\frac{1}{3}[/tex]

[tex]\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha \beta}[/tex]

[tex]\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7/6}{1/3}[/tex]

[tex]\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7}{6}\times 3=7/2[/tex]

[tex]\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{\alpha \beta}[/tex]

[tex]\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{1/3}=3[/tex]

Substitute the values

[tex]y^2-(7/2)y+3=0[/tex]

[tex]2y^2-7y+6=0[/tex]

Hence, the quadratic polynomial whose zeroes are [tex]1/\alpha[/tex] and [tex]1/\beta[/tex] is given by

[tex]2y^2-7y+6=0[/tex]

Answer:

102471 sq .in the land answer Teri ma ki bosra

Answer:

=256 pi

Step-by-step explanation:

The surface area of a sphere is

SA = 4pi r^2

SA = 4 pi (8)^2

     = 4 * pi *64

     =256 pi

12.

[tex]we \: know \: that \\ \frac{sum \: of \: all \: quantities}{number \: of \: quantities} = mean \\ => \frac{26 + 22 + 32 + 28 + 35 + x}{6} = 30 \\ = > \frac{143 + x}{6} = 30 \\ = > 143 + x = 30 \times 6 \\ = > 143 + x = 180 \\ = > x = 180 - 143 \\ = > x = 37 \\ [/tex]

This is the answer.

Hope it helps!!

Answer:

49

Step-by-step explanation:

Answer: -16/3

Step-by-step explanation:

[tex]3(x - 2) + 4x = 10(x + 1)\\3x - 2(3) + 4x = 10x +1(10)\\3x - 6 + 4x = 10x + 10\\7x - 6 = 10x + 10\\7x - 10x = 10 + 6\\-3x = 16\\x = \frac{16}{-3} =-\frac{16}{3}[/tex]

Answer:

-16/3

Step-by-step explanation:

3(x – 2) + 4x = 10(x + 1)

Step 1 distribute the 3 to the x and -2

Outcome: 3x - 6 + 4x = 10(x + 1)

Step 2 distribute the 10 to the x and 1

Outcome: 3x - 6 + 4x = 10x + 10

Step 3 combine like terms

Outcome: 7x - 6 = 10x + 10

Step 4 add 6 to both sides

Outcome: 7x = 10x + 16

Step 5 subtract 10x from both sides

Outcome: -3x = 16

Step 6 divide both sides by -3

Outcome: x = -16/3