Given the functions below, find f(x)+g(x)

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Answer:

A

C

D

E

Step-by-step explanation:

Exterior angles can be described as the angles that are formed between the side of a polygon and the extended adjacent side of the polygon.

Or an exterior angle is the angle that is not inside the triangle formed.

The angles inside the triangle are interior angles.

Exterior angles are :

2

3

4

6

Interior angles are :

1

5

Answer:

Between 50 and 60

Step-by-step explanation:

4,346/82 is 53 which is between 50 and 60.

Hope this helps!

9514 1404 393

Answer:

  0.5

Step-by-step explanation:

The "enclosed area" can be taken to mean different things. Here, we consider it to mean the finite area bounded between the two curves, regardless of which curve is higher value than the other.

The area is bounded on the interval [0, 2]. On half that interval y1 > y2; on the other half, y2 > y1. This means the integral of the area between the curves will be different for one part of the interval than for the other. (The curves are symmetric about the point (1, 0).)

The area on the interval [0, 1] is given by the integral ...

  [tex]\displaystyle\int_0^1{(y_1-y_2)}\,dx=\int_0^1{((x-1)^3-(x-1))}\,dx\\\\=\int^1_0{(x(x-1)(x -2))}\,dx=\left.(\frac{x^4}{4}-x^3+x^2)\right|^1_0=\boxed{\frac{1}{4}}[/tex]

The area on the interval [1, 2] is the integral of the opposite integrand, but has the same value.

The positive area over the whole interval from 0 to 2 is 1/4+1/4 = 1/2.

If you simply integrate y2-y1 or y1-y2 over that interval, the result is 0.

The line AB and CD are parallel. Then it is impossible that the line AB intersects the line CD.

When the distance between the lines is constant, then the lines are called parallel lines. The lines do not intersect when they are separated from each other. And the slope of the lines is equal.

Given that ∠ABC = 70° and ∠BCD = 110°.

Then the line AB and the line CD makes the same angle with the line BC.

Hence, the line AB and CD are parallel.

Then it is impossible that the line AB intersects the line CD.

More about the parallel lines link is given below.

https://brainly.com/question/16701300

#SPJ1

Answer:

Tenemos dos propiedades de la potencia en este caso:

Para un numero real A:

[tex]A^0 = 1[/tex]

[tex](A^n)^m = A^{n*m}[/tex]

En este caso nuestra ecuación es:

[tex][ [(\frac{0.1234}{-3.2098})^4]^3]^0[/tex]

usando la segunda propiedad, podemos reescribir como:

[tex][ [(\frac{0.1234}{-3.2098})^4]^3]^0 = (\frac{0.1234}{-3.2098})^{4*3*0} = (\frac{0.1234}{-3.2098})^0[/tex]

Y acá tenemos un numero real a la potencia 0, sabemos que esto es igual a 1, entonces:

[tex](\frac{0.1234}{-3.2098})^0 = 1[/tex]

Hello my dear friend of USA !!!

DB/AD = BE/EC

=> 6/4 = x+1/x

=> 6x = 4x + 4

=> 2x = 4

=> x = 2

So x = 2

I am from INDIA.

Lots of love ❤️!!!

Have a great day ahead!

Answer:

x = 2

Step-by-step explanation:

[tex]\frac{6}{4} = \frac{x+1}{x}[/tex]

6x = 4x + 4

2x = 4

x = 2

Answer:

no.1 answer 0

Step-by-step explanation:

3x + 1= 4

or; 3x = 4 - 1

or; x = 3 ÷ 3

x = 0

Answer:

Step-by-step explanation:

Let the area of initial square is x, then shaded squares will have area as geometric sequence:

The first term is x, the common ratio is 1/4

Sum of infinite GP is:

By substituting values we get:

Answer:

22608 mm³/s

Step-by-step explanation:

Applying chain rule,

dV/dt = (dV/dr)(dr/dt)............... Equation 1

Where dV/dr = rate at which the volume is increasing

But,

V = 4πr³/3

Therefore,

dV/dr = 4πr²............... Equation 2

Substitute equation 2 into equation 1

dV/dt = 4πr²(dr/dt).............. Equation 3

From the question,

Given: dr/dt = 2 mm/s, r = 60/2 = 30 mm

Consatant: π = 3.14

Substitute these values into equation 3

dV/dt = 4×3.14×30²×2

dV/dt = 22608 mm³/s

Answer:

Huh? is it triangle? and right triangle? if it is its 62^2 = 12^2 + x^2

Step-by-step explanation:

Answer:

The rule for the transformation is (x, y) (-x, -y).

The coordinates of L'are (-2,-2).

The coordinates of N'are (-1,-6).

Step-by-step explanation:

Given

[tex]L = (2,2)[/tex]

[tex]M = (4,4)[/tex]

[tex]N = (1,6)[/tex]

[tex]Ro=180[/tex]

Required

Select three options

The rule to this is:

[tex](x,y) \to (-x,-y)[/tex]

So, we have:

[tex]L = (2,2)[/tex]

[tex]L' =(-2,-2)[/tex]

[tex]M = (4,4)[/tex]

[tex]M =(-4,-4)[/tex]

[tex]N = (1,6)[/tex]

[tex]N' = (-1,-6)[/tex]

Answer:

#########

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

We want to determine an equivalent trignometric identity with the given expression:

[tex]\cos (x) - \cos^3 (x)[/tex]

We can factor out a cos(x):

[tex]=\cos (x) (1-\cos^2 (x))[/tex]

Recall from the Pythagorean Identity that:

[tex]\sin^2(x) + \cos^2(x) = 1[/tex]

Therefore:

[tex]\displaystyle \sin^2(x) = 1 - \cos^2(x)[/tex]

Substitute:

[tex]=\cos(x)(\sin^2(x))=\cos(x)\sin^2(x)[/tex]

Our answer is B.

Step-by-step explanation:

6t-12+15t | 25+15t

21t-12 | 25+15t

21t-12 < 25+15t

hence proved..

Answer:

21t - 12 < 25 + 15t

Step-by-step explanation:

6( t - 2 ) + 15t < 5 ( 5 + 3t )

6t - 12 + 15t < 25 + 15t

21t - 12 < 25 + 15t.

Hence , Proved.

Answer:

80b-11

Step-by-step explanation:

14b + 1 - 6(2 - 11b)

Distribute

14b+1-12+66b

Combine like terms

80b-11

Answer:

80b - 11

Step-by-step explanation:

what is the problem ?

just multiply it out and combine terms.

14b + 1 - 6(2 - 11b) = 14b + 1 - 12 + 66b = 80b - 11

9514 1404 393

Answer:

  ∠4

Step-by-step explanation:

"Alternate" means the angle is on the other side of the transversal t. "Exterior" means it is on the outside of line e crossing the transversal. The alternate exterior angle to angle 8 is angle 4.

Answer:

C

Step-by-step explanation:

Start by simplifying what you can in each radicalfor example, the

∛(xy⁵)= y∛(xy²)

and

∛(x⁷y¹⁷)=x²y⁵∛(xy²)

So know our equation looks like

y∛(xy²)*x²y⁵∛(xy²)

Now because what's inside the radical is the same we can combine them

y⁶x²∛(xy²)²

distribute the square

so

∛(xy²)²=  ∛(x²y⁴)= y∛(x²y)

and finally,

y⁶x²*y∛(x²y)= y⁷x²∛(x²y)

this is equal to option C

Answer:

mapping an area

Step-by-step explanation:

One situation and probably the most common is mapping an area. Graphs are great for dividing a geographical location into various sections and creating a model representation of the area. The graph itself allows for specific directions to be shared using the x and y coordinates on the graph. The same applies for finding the midpoint of a line segment. For example, this is useful if you were trying to find a place to meetup with a friend that is an equal distance from where you are and from where your friend is currently located. Therefore, allowing you to meetup at the midpoint.

Step-by-step explanation:

The number of cases of a new disease may be modeled by the quadratic regression equation y=-2x^2+44x+8 , what is the best prediction for the number of cases after 20 years ( the carrot symbol (^) means the following number is the exponent)

Answer:

No mode

Step-by-step explanation:

Mode = number that appears the most

No number appears more than 1 time

Hence there is no mode

Answer:Should be no mode tell me if i'I'm wrong

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

There is no point shared by all three graphs

Answer:

Area of ellipse=[tex]\pi ab[/tex]

Step-by-step explanation:

We are given that

[tex]x=acos\theta[/tex]

[tex]y=bsin\theta[/tex]

[tex]0\leq\theta\leq 2\pi[/tex]

We have to find the area enclose by it.

[tex]x/a=cos\theta, y/b=sin\theta[/tex]

[tex]sin^2\theta+cos^2\theta=x^2/a^2+y^2/b^2[/tex]

Using the formula

[tex]sin^2x+cos^2x=1[/tex]

[tex]\frac{x^2}{a^2}+\frac{y^2}{b^2}=1[/tex]

This is the equation of ellipse.

Area of ellipse

=[tex]4\int_{0}^{a}\frac{b}{a}\sqrt{a^2-x^2}dx[/tex]

When x=0,[tex]\theta=\pi/2[/tex]

When x=a, [tex]\theta=0[/tex]

Using the formula

Area of ellipse

=[tex]\frac{4b}{a}\int_{\pi/2}^{0}\sqrt{a^2-a^2cos^2\theta}(-asin\theta)d\theta[/tex]

Area of ellipse=[tex]-4ba\int_{\pi/2}^{0}\sqrt{1-cos^2\theta}(sin\theta)d\theta[/tex]

Area of ellipse=[tex]-4ba\int_{\pi/2}^{0} sin^2\theta d\theta[/tex]

Area of ellipse=[tex]-2ba\int_{\pi/2}^{0}(2sin^2\theta)d\theta[/tex]

Area of ellipse=[tex]-2ba\int_{\pi/2}^{0}(1-cos2\theta)d\theta[/tex]

Using the formula

[tex]1-cos2\theta=2sin^2\theta[/tex]

Area of ellipse=[tex]-2ba[\theta-1/2sin(2\theta)]^{0}_{\pi/2}[/tex]

Area of ellipse[tex]=-2ba(-\pi/2-0)[/tex]

Area of ellipse=[tex]\pi ab[/tex]

Answer:

Values of x

Step-by-step explanation:

The domain of a function is the set of all possible inputs for the function while the co-domain is the set of all possible outputs of the function.

In other words, domain is the set of x-values that you can put into any given equation while co-domain is the sex of f(x)-values that you get from substituting the values of x.

Hope it's clear

f(0) = 56

f(2) = 42

f(-2) = 70

f(x+1) = 7|x-7|

f(x²+2) = 7|x²-6|

Answered by GAUTHMATH

Answer:

[tex]44[/tex]

Step-by-step explanation:

The dimensions of the garden is 12 by 8. If we have a walkway that surrounds the garden, the dimensions of the walkway is 2. Since it surrounds the rectangle all sides add 2 to each of the dimensions so now the dimensions of the garden and walkway is 14×10.

The area of the garden is 96 square ft.

The area of the garden and walkway is 140 so let subtract the area of the garden from the total area of both the garden and walkway.

[tex]140 - 96 = 44[/tex]

The area is 44.

Answer:

120 square feet

Step-by-step explanation:

(8+2*2)

(18+2*2) - 8*18 = 120 square feet.

Answer:

the x-intercepts are at

x = -3

x = 0

x = 1

Step-by-step explanation:

ask the points, where the functional value is 0.

2x³ + 4x² - 6x = 0

we see that every term contains an expression of x. so, we can simplify this

x × (2x² + 4x - 6) = 0

so, one solution is plainly visible : x=0

for the other solutions we need to solve the square equation

2x² + 4x - 6 = 0

or even simpler

x² + 2x - 3 = 0

the solution of a square equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a=1

b=2

c=-3

x = (-2 ± sqrt(2² - 4×1×-3))/(2×1) = (-2 ± sqrt(4 + 12))/2 =

= (-2 ± sqrt(16))/2 = (-2 ± 4)/2 = -1 ± 2

x1 = -1 + 2 = 1

x2 = -1 - 2 = -3

Answer:

The next number is going to be 21

Answer:

19

Step-by-step explanation:

4 even number

3,5,7 odd numbers

14 even

17, 19, 21 even

Answer:

angles A and C are congruent

Answer:

305°

Step-by-step explanation:

The bearing in the reverse direction is 180° plus the bearing in the forward direction, that is

bearing of B from A = 180° + 125° = 305°

Answer:

[tex]b=h=\sqrt{6}[/tex] m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box=[tex]2b^2+4bh[/tex]

[tex]2b^2+4bh=36[/tex]

[tex]b^2+2bh=18[/tex]

[tex]2bh=18-b^2[/tex]

[tex]h=\frac{18-b^2}{2b}[/tex]

Volume of box, V=[tex]b^2h[/tex]

Substitute the values

[tex]V=b^2\times \frac{18-b^2}{2b}[/tex]

[tex]V=\frac{1}{2}(18b-b^3)[/tex]

Differentiate w. r.t b

[tex]\frac{dV}{db}=\frac{1}{2}(18-3b^2)[/tex]

[tex]\frac{dV}{db}=0[/tex]

[tex]\frac{1}{2}(18-3b^2)=0[/tex]

[tex]\implies 18-3b^2=0[/tex]

[tex]\implies 3b^2=18[/tex]

[tex]b^2=6[/tex]

[tex]b=\pm \sqrt{6}[/tex]

[tex]b=\sqrt{6}[/tex]

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

[tex]\frac{d^2V}{db^2}=-3b[/tex]

At  [tex]b=\sqrt{6}[/tex]

[tex]\frac{d^2V}{db^2}=-3\sqrt{6}<0[/tex]

Hence, the volume of box is maximum at [tex]b=\sqrt{6}[/tex].

[tex]h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}[/tex]

[tex]h=\frac{18-6}{2\sqrt{6}}[/tex]

[tex]h=\frac{12}{2\sqrt{6}}[/tex]

[tex]h=\sqrt{6}[/tex]

[tex]b=h=\sqrt{6}[/tex] m