During both the Great Recession and the COVID-19 recession, the Fed implemented policies to purchase long-term bonds and mortgage-backed securities, as well as cutting the federal funds rate to near zero.
The Fed implemented some policy actions during both the Great Recession and the COVID-19 recession, while others were implemented only during the latter. Let's take a closer look:
A. Purchase long-term corporate bonds: Both
During both recessions, the Fed implemented a policy of purchasing long-term corporate bonds. This is a form of quantitative easing, where the central bank buys bonds to increase the money supply and lower long-term interest rates. By lowering borrowing costs for businesses, the Fed aims to encourage investment and boost economic growth.
B. Purchase long-term Treasuries: Both
Similar to the purchase of long-term corporate bonds, the Fed also implemented a policy of purchasing long-term Treasuries during both recessions. This has the same goal of increasing the money supply and lowering long-term interest rates, making it cheaper for the government to borrow money and for individuals and businesses to finance investments.
C. Eliminate the requirement that banks hold reserves: COVID-19
During the COVID-19 recession, the Fed eliminated the requirement that banks hold reserves. This meant that banks could lend more money to individuals and businesses, which could help stimulate the economy.
D. Purchase mortgage-backed securities: Both
During both recessions, the Fed implemented a policy of purchasing mortgage-backed securities. This was done to support the housing market and make it easier for people to obtain mortgages and refinance their homes.
E. Support lending to smaller nonfinancial firms: COVID-19
During the COVID-19 recession, the Fed implemented a policy of supporting lending to smaller nonfinancial firms. This was done to help small businesses, which are often hit hardest during economic downturns, access credit and stay afloat.
F. Cut the federal funds rate to near zero: Both
During both recessions, the Fed cut the federal funds rate to near zero. This is the interest rate that banks charge each other for overnight loans, and it affects other interest rates throughout the economy. By cutting the federal funds rate, the Fed aims to make borrowing cheaper and stimulate economic activity.
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I need help and please show work
The following are the values and correct description for the expressions:
(5/6) × (3/2) = 5/4 and is greater than 5/6
(5/6) × (7/8) = 35/48 and is less than 5/6
(5/6) × (9/9) = 5/6 and is equal to 5/6
(5/6) × (1¾) = 35/24 and is greater than 5/6
How to calculate for the values of the expressionsThe given expressions can be simplified to get a value that can be used to describe them in comparison to the fraction 5/6 as follows:
(5/6) × (3/2) = (5 × 1)/(2 × 2)
(5/6) × (3/2) = 5/4 which is greater than 5/6
(5/6) × (7/8) = (5 × 7)/(6 × 8)
(5/6) × (7/8) = 35/48 which is less than 5/6
(5/6) × (9/9) = (5 × 1)/(6 × 1)
(5/6) × (9/9) = 5/6 and is equal to 5/6
(5/6) × (1¾) = (5/6) × (7/4)
(5/6) × (1¾) = (5 × 7)/(6 × 4)
(5/6) × (1¾) = 35/24 and is greater than 5/6
Therefore, the expressions (5/6) × (3/2) is greater than 5/6, (5/6) × (7/8) is less than 5/6, (5/6) × (9/9) is equal to 5/6, and (5/6) × (1¾) is greater than 5/6
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Find the distance from A to C across the gorge illustrated in the figure.
Answer:
[tex]\huge\boxed{\sf Opposite = 125.86 \ ft}[/tex]
Step-by-step explanation:
This question will be solved using trigonometric ratios.
Given that,Angle = θ = 40°
Adjacent = 150 ft
To find:Opposite = ?
Using trigonometric ratio, tan θ.
Solution:[tex]\displaystyle tan \theta = \frac{opposite}{adjacent} \\\\Put \ the \ given.\\\\tan \ 40 = \frac{opposite}{150} \\\\0.839 = \frac{opposite}{150} \\\\Multiply \ both \ sides\ by \ 150\\\\0.839 \times 150 = opposite\\\\125.86 \ ft = Opposite\\\\Opposite = 125.86 \ ft\\\\\rule[225]{225}{2}[/tex]
Which of the following describes the transformations of g(x)--(2)**-2 from the parent function f(x)=2*?
O shift 4 units left, reflect over the x-axis, shift 2 units down
O shift 4 units left, reflect over the y-axis, shift 2 units down
O shift 4 units right, reflect over the x-axis, shift 2 units down
O shift 4 units right, reflect over the y-axis, shift 2 units down
Shift 4 units right, reflect over the y-axis, shift 2 units down is the transformation applied.
The parent function f(x) = 2x is transformed to g(x) = (2x-2)⁻²
To determine the transformations applied to f(x), we can work from the inside out, starting with the expression 2x-2:
Shift 2 units to the right: This can be achieved by replacing x with (x-2).
This gives us the expression 2(x-2) = 2x-4.
Reflect over the y-axis: This can be achieved by replacing x with (-x).
This gives us the expression 2(-x)-4 = -2x-4.
Square and take the reciprocal: This can be achieved by applying the transformation f(x) -> 1/f(x)².
This gives us the expression (-1/2x-4)².
Therefore, the transformations applied to f(x) are shift 2 units to the right, reflect over the y-axis, and square and take the reciprocal.
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Simplify 3[tex]\sqrt[/tex]2-√2
Answer: (√2)(2) = 2√2
Step-by-step explanation:
To simplify the expression 3√2 - √2, you can factor out the common term √2:
3√2 - √2 = (√2)(3 - 1)
Now, subtract the numbers in parentheses:
(3 - 1) = 2
(√2)(2) = 2√2
Hello please, I did not understand this exercise. In the plane referred to an orthonormal reference (o, i, j) place the points A, B, C and D defined by: A(6; 4); B(3; 7); C(12; -2); D(9; 7).
Show that C is the image of A by dilation with center B and ratio 3.
We have shown that C is the image of A by dilation with center B and ratio 3.
Now, To show that C is the image of A by dilation with center B and ratio 3, we need to follow these steps:
Firstly, Find the vector AB by subtracting the coordinates of B from the coordinates of A:
AB = A - B = (6 - 3, 4 - 7) = (3, -3)
Multiply the vector AB by the dilation ratio of 3:
3 AB = 3 (3, -3) = (9, -9)
Add the resulting vector to the coordinates of the center B:
BC = B + 3 AB = (3, 7) + (9, -9)
BC = (12, -2)
Hence, Compare the resulting point BC to the coordinates of C to show that they are the same:
BC = (12, -2) = C
Therefore, we have shown that C is the image of A by dilation with center B and ratio 3.
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Diddy and Dixie need some karts for their race. Heading over to Cranky's Kart Rentals, they decide to see how long they can race for. Together , they have a $210 banana coin budget . If Cranky charges them a $60 rental fee per kart plus $15 per hour per kart, how many hours can they race for?
Answer:
Let's start by calculating how much it costs to rent one kart for one hour:
$60 (rental fee per kart) + $15 (hourly fee per kart) = $75 per kart per hour
Since Diddy and Dixie have a total budget of $210 banana coins, they can rent:
$210 ÷ $75 per kart per hour = 2.8 karts per hour
Since they cannot rent a fractional part of a kart, they must round down to 2 karts per hour.
Therefore, with their budget, Diddy and Dixie can rent 2 karts for 1 hour, or 1 kart for 2 hours.
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solve the following system by graphing.
x-2y=4
x+3y=14
The y-coordinate of the solution is y=
The solution of the system of equations is (8, 2).
Given is a system of equations x-2y = 4 and x+3y = 14, we need to find the solution of the system of equations,
So, the equations are =
x-2y = 4
x = 2y + 4......(i)
x+3y = 14
x = -3y + 14..........(ii)
Equating the equations since their LHS is same,
2y + 4 = -3y + 14
5y = 10
y = 2
Put y = 2 in any equation to find the value of x,
So,
x = 2(2)+4
x = 8
Hence the solution of the system of equations is (8, 2).
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Please help and tysm <3
Answer: a and b
Step-by-step explanation:
Please help and show workkkkk please I really need help
Answer:
L = 9
Step-by-step explanation:
6x8=48
432÷48=9
Match the concepts.
Please help:)
The tangent identity is: tan x = sin x / cos x. It relates the tangent, sine, and cosine of an angle in a right triangle.
How to explain the matchingThe Pythagorean identity is: sin² x + cos² x = 1. .
The length of the hypotenuse of a right triangle with legs of equal length is √2 times the length of either leg.
The 30-60-90 triangle theorem states that the length of the hypotenuse is 2 times the length of the shorter leg, and the length of the longer leg is √3 times the length of the shorter leg.
The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the lengths of the legs (a and b): c² = a² + b².
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Find the total surface are of this triangular prism, Picture is provided.
The total surface area of this triangular prism is 976 square cm.
Here, we have,
Total surface area of a figure
The total surface area is the sum of the area of the faces of a figure.
The given shape is made up of three rectangles and 2 triangles.
Surface area = 2[25*10] + (14 * 10) + (24 * 14)
Surface area = 2(250) + 140 + 336
Surface area = 976 square cm
Hence the total surface area of this triangular prism is 976 square cm
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Number 11 on the worksheet
Answer:
24
Step-by-step explanation:
Compare the known similar sides - - -
10 is to 30, and 14 is to 42. Triangle B is 3x Triangle A.
So the unknown side in Triangle B is 3x 8cm, so 24cm.
if f(x)=5x^2+8x and g(x)=-2x^2+7 find (f+g)(x)
Answer:
[tex]\displaystyle{(f+g)(x)=3x^2+8x+7}[/tex]
Step-by-step explanation:
Given both functions f(x) and g(x):
[tex]\displaystyle{f(x)=5x^2+8x}\\\\\displaystyle{g(x)=-2x^2+7}[/tex]
Finding (f+g)(x), is the same as finding the sum of both functions, f(x) + g(x). Therefore:
[tex]\displaystyle{(f+g)(x) = f(x)+g(x)}\\\\\displaystyle{(f+g)(x)=(5x^2+8x)+(-2x^2+7)}\\\\\displaystyle{(f+g)(x)=5x^2+8x-2x^2+7}\\\\\displaystyle{(f+g)(x)=3x^2+8x+7}[/tex]
How many different ways are there of choosing four cards from a standard 52 -card deck and arranging them in a row? How many different four-card hands can be dealt from a standard 52 -card deck?
The number of ways to choose four cards from standard deck and arranging them in row is 270725.
Number of four card hands from a standard 52 card deck can be dealt is 13.
We know that from combination formula,
C(n, k) = n!/k!(n - k)!
The total cards in a standard deck of cards = 52
We have to choose four cards from the deck and have to arrange them in row so we cannot reuse another card.
So, the number of ways to choose four cards from standard deck and arranging them in row = C(52, 4) = 52!/4!(52 - 4)! = 52!/4!48! = (52*51*50*49)/(4*3*2*1) = 270725.
Number of four card hands from a standard 52 card deck can be dealt = 52/4 = 13.
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HELP ASAP PLEASE! Find the probability that a point chosen randomly inside the rectangle is in each given shape. Round to the nearest tenth of a percent.
The value of probability that a point chosen randomly inside the rectangle is in each given shape are,
a) P = 16.67%
b) P = 10.42%
We have to given that;
A rectangle is shown in image in which triangle and square are shown.
Now, The area of triangle is,
A = 1/2 x 5 x 4
A = 10 unit²
And, Area of Square is,
A = 4 x 4
A = 16 unit²
Area of rectangle is,
A = 12 x 8
A = 96 units²
Hence, The value of probability that a point chosen randomly inside the rectangle is in square is,
⇒ P = area of square / area of rectangle
⇒ P = 16 / 96
⇒ P = 1/6 × 100%
⇒ P = 16.67%
And, The value of probability that a point chosen randomly inside the rectangle is in square is,
⇒ P = area of triangle / area of rectangle
⇒ P = 10 / 96
⇒ P = 10/96 × 100%
⇒ P = 10.42%
Thus, The value of probability that a point chosen randomly inside the rectangle is in each given shape are,
a) P = 16.67%
b) P = 10.42%
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Can someone please help me and show work
The hexagonal prism below has a height of 9 units and a volume of 216.9 units. Find the area of one of its bases.
Answer:
The answer is 24.1 unit²
Step-by-step explanation:
Volume of prisms=cross sectional area×h
cross sectional area=Volume of prisms/height
A=216.9/9
A=24.1 unit²
Make t the subject of c=t³ - 8v
The variable t becomes the subject of the equation c=t³ - 8v by adding 8v to both sides and taking the cube root, giving t = ∛(c + 8v).
Explanation:We need to make t the subject of the equation c=t³ - 8v. To do this, we first add 8v to both sides of the equation to isolate t³ on one side, giving us t³ = c + 8v. We then need to take the cube root of both sides to solve for t. Hence, t = ∛(c + 8v). Now, t is the subject of the equation.
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Juan sold a bicycle at a discount of 15%. If the selling price was $340, find the usual price of the bicycle.
Answer: $400
Step-by-step explanation:
Discount = 15%
The original price/value of an item is always 100%
So selling price (%) = original price - discount = 100%-15% = 85%
We got selling price as 85%
This implies that 85% = 340
Let's find 1% first, then 100%
1% = 340÷85 = 4
100% = 4 × 100 = $400
The usual (normal/original) price is $400
Juan sold a bicycle at a discount of 15% if the selling price was $340 then the usual price of the bicycle was $400.
What is Percentage?percentage, a relative value indicating hundredth parts of any quantity.
Let's represent the usual price of the bicycle by P.
Since Juan sold the bicycle at a discount of 15%, the selling price (S) would be 85% of the usual price (P).
We can express this relationship as an equation:
S = 0.85P
We also know that the selling price of the bicycle was $340.
Substituting S = $340 into the equation above, we get:
$340 = 0.85P
To find P, we can solve for it:
P = $340 / 0.85
P = $400
Therefore, the usual price of the bicycle was $400.
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PLS PLS HELP IM SO CONFUSED (which of the following is likely to have the greatest variability?)
Answer:
G
Step-by-step explanation:
The heights of all the students can vary.
(Everyone isn't the same height.)
Ahmed placed salt water in a beaker and left it on his desk for a week. After a week, there was only salt. Which best explains the missing water from the beaker?
A. The water became a new substance.
B. The water evaporated.
C. The water disappeared forever.
D. The water condensed.
The water evaporated.
Option B is the correct answer.
We have,
When a liquid is left open in a container, it can undergo a phase change to become a gas or vapor, which is known as evaporation.
In this case,
The water in the beaker would have evaporated, leaving behind the salt. The water did not disappear forever but instead changed state to become a gas in the air.
Thus,
The water evaporated.
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Suppose a four-year bond is purchased for $5700. The face value of the bond when it matures is $6669. Find the APR.
The bond's APR is%
(Type an integer or a decimal.)
The bond's APR is 4.25%.
The formula for face value of the bond is given as following
F=P(1+rt) where F=face value, P= Purchase value, r=Annual rate & t=time of bond.
The given values are P=$5700, t=4 years & F=$6669
Substituting the above values we get
6669=5700(1+r*4)
0.17=4r
r=4.25%.
Hence, the APR for the given bond is 4.25%.
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What is the surface area of the cylinder with height 6 km and radius 4 km? Round your answer to the nearest thousandth.
Answer:
251.327 km² (nearest thousandth)
Step-by-step explanation:
The formula for the surface area of a cylinder is:
[tex]\boxed{S.A. = 2\pi r^2 + 2\pi rh}[/tex]
where r is the radius and h is the height of the cylinder.
Substitute the given values of r = 4 km and h = 6 km into the formula and solve:
[tex]\begin{aligned}S.A. &= 2\pi (4)^2 + 2\pi (4)(6)\\&=2\pi (16)+2 \pi (24)\\&=32 \pi+ 48 \pi\\&=80 \pi\\&=251.327412...\\&=251.327\; \sf km^2 \end{aligned}[/tex]
Therefore, the surface area of the cylinder with height 6 km and radius 4 km is 251.327 square kilometers, rounded to the nearest thousandth.
Answer:
Curved surface area is 150.796 km²,Total surface area is 251.327 km².-------------------------
Curved surface area of a cylinder:
CSA = 2πrhSubstitute 6 for h and 4 for r:
CSA = 2π(6)(4) = 150.796447372 ≈ 150.796 km² (rounded)Total surface area adds top and bottom faces:
TSA = 2πrh + 2πr² TSA = 2πr(r + h)TSA = 2π(4)(4 + 6) = 251.327412287 ≈ 251.327 km² (rounded)How much money are you making on your investment in a year? $ 127.5 How much money are you paying in interest in a year on your card? $ 305 What's your total gain/loss that year? $ -1,067.5 Enter a negative value for a loss.
Answer:
Assuming you only have an investment income of $127.5 and a credit card interest payment of $305, your total gain/loss for the year would be -$177.5 ($127.5 - $305 = -$177.5). This means you have a net loss of $177.5 for the year.
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A ball is thrown from an initial height of 3 meters with an initial upward velocity of 7 m/s.
following.
h=3+7t-5t²
Find all values of t for which the ball's height is 4 meters.
Round your answer(s) to the nearest hundredth.
(If there is more than one answer, use the "or" button.)
initial
height
4
h
ground
t = seconds
The only valid value for t is approximately 1.53 seconds when the ball's height is 4 meters.
How to solve the equationWe are given the equation for the height of the ball h as a function of time t:
h(t) = 3 + 7t - 5t²
We want to find all values of t for which the height h is 4 meters. So, we set h(t) equal to 4 and solve for t:
4 = 3 + 7t - 5t²
Rearrange the equation to form a quadratic equation:
0 = 5t² - 7t - 1
Now, we can use the quadratic formula to solve for t:
t = (-b ± √(b² - 4ac)) / 2a
In our equation, a = 5, b = -7, and c = -1. Plugging these values into the quadratic formula, we get:
t = (7 ± √((-7)² - 4 * 5 * (-1))) / (2 * 5)
t = (7 ± √(49 + 20)) / 10
t = (7 ± √69) / 10
We have two possible solutions for t:
t = (7 + √69) / 10 ≈ 1.53 (rounded to the nearest hundredth)
t = (7 - √69) / 10 ≈ -0.13(rounded to the nearest hundredth)
Since time cannot be negative, we discard the second solution.
So, the only valid value for t is approximately 1.39 seconds when the ball's height is 4 meters.
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multiply three 1,5. -5,6. 0,0
Answer:
0
Step-by-step explanation:
=1/2 × -5,6 × 0
=-8,4×0
=0
PLEASE PLEASE HELP WILL MARK BRAINLIST!!!!!!!!!!!!
Answer:
c is -3
Step-by-step explanation:
We are shifting the parabola 3 units to the right.
f(x+c) is a shift c units to the left so we need to shift -3 units
f(x-3) is a shift 3 units to the right 3 units
Find the value of x for which m||n.
A) 21
B) 19
C) 8
D) Can't be determined
Answer:
X = 20.25°
Step-by-step explanation:
Interior angle of the same side are suplementery which means their sum is equal to 180° .
So 38° +( 8x - 26°) = 180°
12° + 8x = 180° .... Simplify 38 and 26
8x = 180°- 12° .... taking 12 to the left side it
change the sighn to -ve
8x = 162° .... simplify
8x/8 = 162°/8 .... dividing both side 8
x = 20.25°
The net below shows a square pyramid. What is the lateral surface area?
After considering the given options we come to the conclusion that the answer is 112 in² which is Option B.
The lateral surface area of a square pyramid is the summation of the areas of the side faces only, on the other hand
surface area = lateral area + area of the base.
The lateral area of a square pyramid = 2al (or) 2a√ [ (a 2 /4) + h² ].
Now, to get the surface area, we have to add the area of the base (which is a 2) to each of these formulas.
For the given case, we are given a square pyramid. Hence, all four sides are equivalent in length. We can apply Pythagoras theorem to evaluate the slant height (h) of the pyramid.
The slant height is given by h = √(a² + l²),
Here
a = length of one side
l = height of the pyramid.
Applying this information, we can evaluate the lateral surface area of the square pyramid
Lateral surface area = 2a * √((a²)/4 + l²)
= 2 * 8 * √((8²)/4 + 10²)
= 112 in²
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The complete question is
The net below shows a square pyramid. What is the lateral surface area?
A. 176 in^2
B. 112 in^2
C. 64 in^2
D. 210 in^2
need some help asap thank you
Answer:
quadratic
Step-by-step explanation:
linear is a straight line
exponential is a simple curved graph
