Given the system of equations, what is the solution? x 2y = 11 x - 2y = -1 {(-5, -3)} {(1, 1)} {(5, 3)}

Answer:

A = 20%

B = 33.33%

C = 46.67%

Step-by-step explanation:

Ok we need to add up 3, 5, and 7

3+5+7 = 15

405/15 = 27.

27*3 = A

27*5 = B

27*7 = C

A = 81 / 20%

B = 135 / 33.33%

C = 189 / 46.67%

Answer:

Step-by-step explanation:

If 12 men are needed to run 4 machines. How many men are needed to run 20

we can solve with an equation

12 : 4 = x : 20

x = 12 * 20 : 4

x = 240 : 4

x = 60

----------------------------

check

12 : 4 = 60 : 20

3 = 3

the answer is good

Step-by-step explanation:

8x+6y=24

6y=24-8x

y=24/6 - 8/6x

y=4-4/3x

The theorem that justifies why triangles ABC and DEF are congruent is: HL.

The hypotenuse-leg congruence theorem (HL) states that if two triangles that are right triangles have a pair of congruent hypotenuse and a pair of corresponding congruent legs, then both right triangles are proven to be congruent to each other. This means both right triangles are have the same shape and size.

Given that:

angle ABC = angle DEF = 90° (congruent right angles, this means both triangles are right triangles)

AC = FD (a pair of congruent hypotenuse)

AB = DE (a pair of congruent legs)

Thus, we can conclude that since triangle ABC and triangle DEF have a pair of congruent hypotenuses and a pair of congruent legs, therefore, the two right triangles, triangle ABC and triangle DEF are congruent to each other by the HL congruent theorem.

Thus, the theorem that justifies why both triangles are congruent is: HL.

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The perimeter of the triangle can be express as follows:

12b + 11d + 2c

The perimeter of a figure is the sum of the whole sides of the figure.

A triangle has three sides. Therefore, the perimeter of a triangle is the sum of the three sides.

Therefore, the sides of the triangle are of lengths (2b + 5c) centimetres, (10b + 7d) centimetres, and (4d-3c) centimetres.

Hence, the perimeter of the triangle can be represented as follows:

Perimeter of the triangle = 2b + 5c + 10b + 7d + 4d - 3c

Perimeter of the triangle = 2b + 10b + 7d + 4d + 5c - 3c

Perimeter of the triangle = 12b + 11d + 2c

Therefore, the perimeter of the triangle can be express as follows:

12b + 11d + 2c

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Answer:

1. Transversal y intersects lines m and n; <1 ~= <2 (Given)

2. <1 ~= <3 (Vertical Angles Theorem)

3. <2 ~= <3 (Transitive Property of Congruence)

4. m || n (Converse of Alternate Interior Angles Theorem)

The roots of the given polynomials exist  [tex]$x=8+\sqrt{10}$[/tex], and [tex]$x=8-\sqrt{10}$[/tex].

For a quadratic equation of the form [tex]$a x^{2}+b x+c=0$[/tex] the solutions are

[tex]$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$[/tex]

Therefore by using the formula we have

[tex]$x^{2}-16 x+54=0$$[/tex]

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

[tex]$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$[/tex]

simplifying the equation, we get

[tex]$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\[/tex]

[tex]$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\[/tex]

[tex]$&x=8+\sqrt{10}, x=8-\sqrt{10}[/tex]

Therefore, the roots of the given polynomials are [tex]$x=8+\sqrt{10}$[/tex], and

[tex]$x=8-\sqrt{10}$[/tex].

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Answer:

x=8-[tex]\sqrt{10}[/tex] and x=8+[tex]\sqrt{10}[/tex]

Step-by-step explanation:

It was right for me

No,the population mean is not equal to 9.2 and the value in t statistic is -1.02.

Given sample size of 49,sample mean of 8.5,standard deviation of 1.5, significance level of 0.01.

We are required to find out whether the population mean is equal to 9.2 and the value of t in test statistic.

We have to first make the hypothesis for this.

[tex]H_{0}[/tex]:μ≠9.2

[tex]H_{1}[/tex]:μ=9.2

We have to use z statistic because the sample size is more than 30.

Z=(X-μ)/σ

We have been given sample mean but we require population mean in the formula so we will use sample mean.

Z=(8.5-9.2)/1.5

=-0.7/1.5

=-0.467

P value of -0.467 is 0.67975.

P value is greater than 0.01 so we will accept the hypothesis means population mean is not equal to 9.2.

t=(X-μ)/s/[tex]\sqrt{n}[/tex]

=(8.5-9.2)/1.5/[tex]\sqrt{49}[/tex]

=-0.7/0.21

=-1.02

Hence it is concluded that no,the population mean is not equal to 9.2 and the value in t statistic is -1.02.

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Thus, 2028 needs to be multiplied by 3 to become a perfect square. Therefore, the number 6084 has 3 pairs of equal prime factors . Hence, the smallest number by which 2028 must be multiplied so that the product is a perfect square is 7

Answer:

Option 2

Step-by-step explanation:

Using the quadrstic formula,

[tex]\tan \theta=\frac{-2 \pm \sqrt{2^2 - 4(\sqrt{3})(-\sqrt{3})}}{2\sqrt{3}} \\ \\ =\frac{-2 \pm 4}{2\sqrt{3}} \\ \\ =\frac{-1 \pm 2}{\sqrt{3}} \\ \\ = -\sqrt{3}, \frac{1}{\sqrt{3}}[/tex]

Case 1

[tex]\tan \theta=-\sqrt{3} \implies \theta=\frac{2\pi}{3}, \frac{5\pi}{3}[/tex]

Case 2

[tex]\tan \theta=\frac{1}{\sqrt{3}} \implies \theta=\frac{\pi}{6}, \frac{7\pi}{6}[/tex]

The answer is 4x + 5y.

Here, what needs to be done is to combine like terms.

Answer:

Bottom left

Step-by-step explanation:

Since the slope has to be positive it can't be the ones on the right side since both of them are negative. And the bottom left one is rising 3 and running 4. (formula = rise/run). See image.

Answer:

y = -5/3 - 8

Step-by-step explanation:

We want to write this in the form y = mx + b.  We need to find the m (slope) and the b (y-intercept) ,  Whew, they already gave us the slope, so we are have way there.  I will plug in the x and y that we are given from the point (-6, 8) to solve for b.

y = mx + b

8 = -5/3(-6) + b  Multiply the fraction by -6

8 = 30/3 + b  I can make 6 a fraction by writing it 6/1 and then just multiply straight across.  A negative times a negative is a positive.

8 = 10 + b   30/3 is equal to 10.  Now subtract 10 from both sides to get b

-8 = b

I can now write the equations since I now know m and b.

y = -5/3 + (-8) which is the same as y = -5/3 - 8.  Adding a negative is the same as subtracting a positive.

The amount of interest that Bertha Wooten's deposit will earn in 31 days is $38.59, which is the difference between the future value and the present value.

The future value represents the amount that will be in the account after the present value investment is compounded at an interest rate periodically.

The future value of an investment can be calculated using the future value formula, A = P (1 + i)^n.

Where:

A = future value

P = Present value of investment

i = interest rate

n = number of periods.

The future value of the investment can also be determined using an online finance calculator, as follows.

Then the interest is the difference between the future value and the present value.

Initial deposit = $8,241.78

Interest rate = 5.5% compounded daily

Investment period = 31 days

N (# of periods) = 31 days

I/Y (Interest per year) = 5.5%

PV (Present Value) = $8,241.78

PMT (Periodic Payment) = $0

Results:

FV = $8,280.37

Total Interest $38.59 ($8,280.37 - $8,241.78)

Thus, the amount of interest that Bertha Wooten's deposit will earn in 31 days is $38.59.

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Two regular octagons and eight congruent rectangles are perfect for the creation of 3-D figures.

According to the statement

we have to tell and explain about the types of shapes which are required for the creations of 3-D figure.

For this purpose, Firstly we have to know about the 3-D figures.

So,

A shape is a graphical representation of an object or its external boundary and outline, as opposed to other properties such as color, texture, or material type.

A plane shape is constrained to lie on a plane, in contrast to solid 3-D shapes.

After that we know that the

When the all dimensions of a given shape can be observed at the same time, then its is said to be in a 3-D. However, polygons are shapes which has 3 or mores sides. Examples are: trigon, hexagon, octagon etc.

Thus, since the in the 3-D figure have 8 sides connected which is greater than their width.

This confirms that the sides of the figure made up of eight congruent rectangles, because the 3-D figure has eight regular sides. Then, the height of the figure would be the length of the rectangles.

After that all this condition, Two regular octagons and eight congruent rectangles are perfect for the creation of 3-D figures.

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Answer:

[tex]\textsf{D.} \quad \begin{cases} y \leq 2x+2 \\ y\geq -\dfrac{1}{2}x \end{cases}[/tex]

Step-by-step explanation:

Both lines in the given system of inequalities are linear equations.

Slope-intercept form of a linear equation:  y = mx + b

(where m is the slope and b is the y-intercept)

Positive slope (m):  as x increases, y increases.

Negative slope (-m):  as x increases, y decreases.

When graphing inequalities:

The inequality represented by the blue line has a positive slope and shading below the line.

⇒ y ≤ mx + b

From inspection of the graph, its y-intercept is 2.

⇒ y ≤ mx + 2

The inequality represented by the yellow line has a negative slope and shading above the line.

⇒ y ≥ -mx + b

From inspection of the graph, it's y-intercept is zero.

⇒ y ≥ -mx

The only pair of inequalities that satisfies the above conditions is:

[tex]\textsf{D.} \quad \begin{cases} y \leq 2x+2 \\ y\geq -\dfrac{1}{2}x \end{cases}[/tex]

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City B had the highest noon temperature, Interquartile Range, Larger Median temperature while City A had smaller range of temperature.

A box and whisker plot, also known as a box plot, shows a five-number summary of a set of data. The minimum, first quartile, median, third quartile, and maximum are the five-number summary. A box plot is created by drawing a box from the first to third quartiles. At the median, a vertical line runs through the box. The whiskers move from the lowest to the highest quartile.

From the figure:-

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Answer:

(a) B

(b) B

(c) B

(d) B

Step-by-step explanation:

area is 1/2 times base times height

triangle A

1/2 times 7 times 9

answer 31.5

Triangle B

1/2 times 7 times 5

answer 17.5

Answer:

15

Step-by-step explanation:

Note: Take note , absolute value will give the magnitude of the value. (Which means ignoring the + / - signs.)

Eg. | - 19 | = 19

Therefore,

[tex] \frac{12(30 - (9 + {4}^{2})) }{10 - | - 6| } \\ = \frac{12(30 - (9 + 16))}{10 - 6} \\ = \frac{12(30 - 25)}{4} \\ = \frac{12(5)}{4} \\ = \frac{60}{4} \\ = 15[/tex]

Answer:

1 + x  meters.

Step-by-step explanation:

A square has 4 equal sides so each side will have a length equal to the square root of the area.

Side length = √(1 + 2x + x^2)

                   = √(1 + x)(1 + x)

                   = 1 + x.

1st quartile: 11

median: 38.50000

3rd quartile: 45

Measure descriptive statistics

1st quartile: 11

median: 38.50000

3rd quartile: 45

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I understand that the question you are looking for is :

2 Drag the tiles to the boxes to form correct pairs. Match the values associated with this data set to their correct descriptions.  {6, 47, 49, 15, 43, 41, 7, 36} first quartile 38.5  median 11  third quartile 10.5 the difference of the largest value and the median 45

[tex]5(1.5)=\boxed{7.5 \text{ yd}}[/tex]

The length of the curved border or arc is 7.5 yards.

the length of the arc = [tex]\theta \times r[/tex]

given that [tex]\theta[/tex] = 1.5 radian

radius = 5 yards

then the length of arc from the above formula

[tex]l = \theta \times r\\l = 1.5 \times 5 = 7.5[/tex] yards

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[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]

Average speed (v) :

[tex]\qquad❖ \: \sf \:v = \cfrac{total \: \: distance \: \: covered}{total \: \: time \: \: taken} [/tex]

[tex]\qquad❖ \: \sf \:v = \dfrac{16.4}{1.5} [/tex]

[tex] \qquad \large \sf {Conclusion} : [/tex]

[tex]\qquad❖ \: \sf \:v = 11 \: \: kmph[/tex]

The value of x in given linear equation is x = 3.

According to the statement

we have given that the equation and we have to find the solution of that equation.

So, For this purpose,

The given equation is :

[tex]\sqrt{ x+1} = \sqrt{ x+6} -1[/tex]

From this equation it is clear that the it is a linear equation.

So, for find the value of x

To solve this equation squaring on both sides then equation become

x+1 = x+6 +1 -2√x+6.

Then

-2√x+6 = -6

then

[tex]\sqrt{x + 6} = 3[/tex]

Now remove the square by S.B.S.

Then the equation become

x +6 = 9

x = 3.

In this equation the value of x is 3.

So, The value of x in given linear equation is x = 3.

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Answer:

Yes

Step-by-step explanation:

First we need to determine how much money Allen has

2 dollars = 2.00

5 quarters = 5 * .25 = 1.25

2 dimes = 2 * .10 = .20

7 pennies = 7 * .01 = .07

Add this together

2.00 + 1.25+.20+.07 =3.52

3.52 > 3.50

This is more than 3.50 so he has enough money to buy the pencils

Answer:

y = - 2x + 8

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = [tex]\frac{1}{2}[/tex] x - 9 ← is in slope- intercept form

with m = [tex]\frac{1}{2}[/tex]

given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{\frac{1}{2} }[/tex] = - 2

y = - 2x + c ← is the partial equation

to find c substitute (3, 2 ) into the partial equation

2 = - 6 + c ⇒ c = 2 + 6 = 8

y = - 2x + 8 ← equation of perpendicular line

Answer:

C.) [tex]log_2(\frac{x^3z^2}{y^4})[/tex]

Step-by-step explanation:

To find the answer, you need to simplify the expression. To do so, you must combine the logs. You can combine the logs because they all have the same subscript (2).

[tex]3 log_2x - 4log_2y + 2log_2z[/tex]                           <----- Given expression

[tex]log_2x^3-log_2y^4+log_2z^2[/tex]                            <----- Raise coefficients to variables

[tex]log_2x^3+log_2z^2-log_2y^4[/tex]                            <----- Rearrange

[tex]log_2(x^3z^2)-log_2y^4[/tex]                                    <----- Multiply added logs

[tex]log_2(\frac{x^3z^2}{y^4})[/tex]                                                  <------ Divide subtracted log

Express the multiplication of a logarithm number of an expression as the logarithm of the power of the expression.

Take the product of the arguments

                         [tex]\red{\boxed{\boldsymbol{\sf{\blue{Answer \ \ \longmapsto \ \ Log_{2} \frac{x^{3}z^{2} }{y^{4} } } }}}}[/tex]

Therefore, the correct option is alternative "C".