Answer:
do you have picture if the question so I can help I
I need help writing a equation for a circleEnds of diameter: (1,-2) and (10,8)
The equation of the circle with the given end point is;
[tex](x-5.5)^2+(y-3)^2=\text{ }\frac{181}{4}[/tex]Here, we want to write the equation of a circle, given the end points of the circle
Given the end-points, we can use the formual for the distance to get the radius of the circle
We have this as follows;
[tex]\begin{gathered} D\text{ = }\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ \\ \\ (x_1,y_1)\text{ = (1,-2)} \\ (x_2,y_2)\text{ = (10,8)} \\ D\text{ = }\sqrt[]{(10-1)^2+(8-(-2))^2} \\ D\text{ = }\sqrt[]{9^2+10^2} \\ D\text{ = }\sqrt[]{181} \end{gathered}[/tex]To get the radius of the circle, we have to divide the diameter by 2
We have this as;
[tex]r\text{ = }\frac{D}{2}\text{ = }\frac{\sqrt[]{181}}{2}[/tex]Now, the other thing needed to write the equation of the circle is the center of the circle
The center of the circle can be calculated by the use of the midpoint formula
[tex]\begin{gathered} (x,y)\text{ = (}\frac{x_2+x_1}{2},\frac{y_2+y_1}{2}) \\ \\ (x,y)\text{ = (}\frac{1+10}{2},\frac{8-2}{2})\text{ = (5.5,3)} \end{gathered}[/tex]The general equation of the circle is;
[tex]\begin{gathered} (x-a)^2+(y-b)^2=r^2 \\ (a,b)\text{ = (5.5,3)} \\ r\text{ = }\frac{\sqrt[]{181}}{2} \\ \\ (x-5.5)^2+(y-3)^2=\text{ }(\frac{\sqrt[]{181}}{2})^2 \\ \\ (x-5.5)^2+(y-3)^2=\text{ }\frac{181}{4} \end{gathered}[/tex]Use the elimination method when solving the translated system Two angles are (complementary angles are angles whose sum is 90.) Their difference is 40. Find the angles. The larger angle is ? , and the smaller angle is ?.
Let's write the equation system first. We have two angles, let's call the, A and B, wich are complementary. This is:
[tex]A+B=90º[/tex]Also their difference is 40º:
[tex]A-B=40º[/tex]The system is;
[tex]\begin{cases}A+B=90º \\ A-B=40º\end{cases}[/tex]Now, if we add the two equations, since we have a "B" and a "-B", they will eliminate:
[tex]\begin{gathered} (A+B=90º)+(A-B=40º) \\ A+B+A-B=90º+40º \\ A+A+B-B=130º \\ 2A=130º \\ A=\frac{130º}{2}=65º \end{gathered}[/tex]The value of one of the angles is 65º. To find the other angle, we can go back to the first equation, A + B = 90º:
[tex]65º+B=90º[/tex]And solve:
[tex]B=90º-65º=25º[/tex]The larger angle is 65º and the smaller angle is 25º
Hi, can you help me to solve this problem, please!!!
Given:
The equation of a parabola is given as,
[tex]y=x^2-5[/tex]The objective is to find the axis of symmetry of the parabola.
Explanation:
The general formula to find the axis of symmetry of a parabolic equation is,
[tex]x=-\frac{b}{2a}\text{ .. . . . . (1)}[/tex]From the given equation,
[tex]\begin{gathered} a=1 \\ b=0 \\ c=-5 \end{gathered}[/tex]On plugging the obtained values in equation (1),
[tex]\begin{gathered} x=-\frac{0}{2(1)} \\ x=0 \end{gathered}[/tex]Hence, the axis of symmetry of the parabola is at x = 0.
The unknown triangle ABC has angle A= 44º and sides a = 15 and c= 20. How many solutions are there for triangle?
Step 1: '
Find the sides and the angles.
Apply sine rule to find angle C
Step 2
[tex]\begin{gathered} \frac{a}{\sin A}\text{ = }\frac{c}{\sin C} \\ \frac{15}{\sin44}\text{ = }\frac{20}{\sin C} \\ \frac{15}{0.695}\text{ = }\frac{20}{\sin C} \\ \sin C\text{ = }\frac{20\times0.695}{15} \\ s\text{inC = 0.92666666} \\ C=sin^{-1}(0.9266666667) \\ C\text{ = 68} \end{gathered}[/tex]Step 3
44 +
Step 4
Find side b
[tex]\begin{gathered} \frac{a}{\sin A}\text{ = }\frac{b}{\sin B} \\ \frac{15}{\sin44}\text{ = }\frac{b}{\sin 68} \\ \frac{15}{0.695}\text{ = }\frac{b}{0.927} \\ b\text{ = }\frac{15\times0.927}{0.695} \\ b\text{ = 20} \end{gathered}[/tex]Final answer
Since angle C = angle B, the length of the sides must also be equal.
Hence,
0 triangle
What's the equation of the tangent to [tex]y = x^2[/tex] at [tex]x = 2[/tex]?
Answer:
y=4x-4.
Step-by-step explanation:
1. the required equation of the tangent line has the form:
y=kx+i, where k=f'(x₀), i - interception;
2. if x₀=2, then y₀=2²=4;
3. f'(x)=2x, then f'(x₀)=2*2=4;
4. the required equation with unknown 'i' is y=4x+i;
it is possible to calculate unknown 'i' using coordinates (x₀;y₀):
5. 4=4*2+i, ⇒ i=-4;
6. finally, y=4x-4.
P.S. the suggested solution is not the shortest one.
A park has 39 visitors on Friday. The number of visitors on Saturday is 5 times that plus 12. Part A. Write an expression you could use to find the number of visitors to the park on Saturday.Part B. How many visitors were at the Park on Friday and Saturday.
Okay, here we have this:
Considering the provided information, we are going to wirte the requested expression, so we obtain the following:
[tex]SaturdayVisitors=FridayVisitors*5+12[/tex]Then replacing with the given information:
[tex]\begin{gathered} SaturdayVisitors=39*5+12 \\ SaturdayVisitors=195+12 \\ SaturdayVisitors=207 \end{gathered}[/tex]Finally we obtain that the park has 39 visitors in friday, and 207 on saturday.
PUNTOS POSIBLE A parking meter that is 1.6 meters (m) tall casts a shadow 3.6 m long. At the same time, a tree casts a shadow 9 m long. 1.6 m 3.6 m 9 m What is the height of the tree?
Answer:
4 meters
Explanation:
The triangle formed by the parking meter and its shadow is similar to the triangle formed by the tree and its shadow. So, the ratio of the height of the object and its shadow is constant and we can write the following equation:
[tex]\frac{Tree}{\text{Shadow Tre}e}=\frac{\text{ Parking meter}}{Shadow\text{ Parking meter}}[/tex]So, replacing the values, we get:
[tex]\frac{Tree}{9\text{ m}}=\frac{1.6\text{ m}}{3.6\text{ m}}[/tex]Solving for the height of the tree, we get:
[tex]\begin{gathered} \frac{Tree}{9\text{ m}}\times9m=\frac{1.6\text{ m}}{3.6\text{ m}}\times9m \\ \text{Tree = 4 m} \end{gathered}[/tex]Therefore, the height of the tree is 4 meters.
In a board game, students draw a number, do not replace it, and then draw asecond number. Determine the probability of each event occurring.
The probability P(choosing then an odd number, a 6) is 9 / 56
The figure of the board game is shown below.
From the question, we have
There are eight numbers on the board game.
Odd number total: (1, 9, 1) = 3
6 digits in total equal 3
Probability is "necessary outcome" divided by "all possible outcomes."
P = 3 / 8 (choosing an odd number).
without replacement
Board game numbers remaining: 8 - 1 = 7.
P(choosing a 6) = 3/7
Hence,
probability, P(choosing then an odd number, a 6) = 3/8 * 3/7 = 9 / 56
Probability:
Probability refers to possibility. A random event's occurrence is the subject of this area of mathematics. The range of the value is 0 to 1. Mathematics has incorporated probability to forecast the likelihood of various events. The degree to which something is likely to happen is basically what probability means. You will understand the potential outcomes for a random experiment using this fundamental theory of probability, which is also applied to the probability distribution.
Complete question: In a board game, students draw a number do not replace it, and then draw a second number. Determine the probability of each event occurring. Drawing an odd number then drawing a 6? dependent events.
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What number is best to use to simplify a fraction Least common multiple be least common denominator see greatest common factor de greatest
The greatest common factor and least common multiple are the best used to simplify a fraction.
Suppose we wanted to add the fractions:
10/12 and 20/15.
Now, consider the fraction:
10/12
We can eliminate that component from both the numerator and the denominator and simplify the fraction if we can identify the greatest common factor between 10 and 12.
So,
The factors of 10 are 1, 2, 5, 10.
The factors of 12 are 1, 2, 3, 4, 6, 12.
Therefore, GCF of 10 and 12 is 2.
Hence,
10/12 = ( 10 ÷ 2 ) / ( 12 ÷ 2 ) = 5/6
Similarly,
For 20/15,
The factors of 20 are 1, 2, 4, 5, 10, 20.
The factors of 15 are 1, 3, 5, 15.
The greatest common factor is 5.
So,
20/15 = ( 20 ÷ 5 ) / ( 15 ÷ 5 ) = 4/3
Now, when we add the fractions:
10/12 + 20/15 = 5/6 + 4/3
Now, as the fractions are already simplified.
By using the least common multiple.
10/12 + 20/15 = 5/6 + ( 4/3 ) × ( 2/2 )
10/12 + 20/15 = 5/6 + 8/6
10/12 + 20/15 = 13/6
Hence, using the greatest common factor we can simplify the fractions, and the least common multiple we can perform operations on the fractions.
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Please help See attached picture
Using the N scale trains are 1: 160
the width be of an N scale train track, in inches is 0.35 inchesThe Locomotive has a length of 5.7 inches in the modelA model boxcar has a length of 56 feetHow to determine dimensions using scale factorsInformation gotten from the question
N scale trains are 1: 160
The width of a standard railroad track is 4 Feet, 8 inches
A Locomotive has a length of 76 feet
A model boxcar has a length of 4.2 inches
width be of an N scale train track, in inches
4 feet 8 inches = 4 * 12 inches + 8 inches = 56 inches
1 foot = 160 feet is same as 12 inches = 12 * 160 inches = 1920 inches
12 inches = 1920 inches
? = 56 inches
? = 56 * 12 / 1920
? = 0.35 inches
A Locomotive has a length of 76 feet
76 feet = 912 inches
12 inches = 1920 inches
? = 912 inches
? = 5.7 inches
A model boxcar has a length of 4.2 inches
12 inches = 1920 inches
4.2 inches = ?
? = 4.2 * 1920 / 12
? = 672 inches
converting to feet
? = 672 inches * 12
? = 56 feet
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Find the PERIMETER of a square with sides 6 yards long. ANS.P = _______,
The given dimension of the square is 6 yards.
The perimeter of the square is express as : 4 x side
Perimeter of the square with the side 6 yards = 4 x 6
Perimeter of square = 24 yards
Answer. The perimeter of the square = 24yards
help meeeeeeeeeeeeeeeeeeeeeee
thank you
Answer: I think it is -5, but im not very sure srry
Step-by-step explanation:
One day in October at 9am, Taylor began hiking an 8-mile trail, hiking for 2.5 hours at a pace of 2 miles per hour, and then stopping for half an hour to enjoy the view and have a snack. Taylor then hiked the remainder of the trail at a speed of 3 miles per hour.
Later, Micah decided to run the same trail. Micah began 1.5 hours after Taylor began hiking, and ran at a rate of 7 miles per hour.
Will Micah catch up to Taylor? If so, when? If not, why not?
Using proportions, it is found that Micah caught up to Taylor at 11:06 AM.
What is a proportion?A proportion is a fraction of a total amount, and equations can be built to find the desired measures in the problem using relations in the context of the problem.
For this problem, the relation between velocity, distance and time is used, that is, velocity equals distance divided by time, hence:
v = d/t.
Then the distance is:
d = vt.
For Taylor, his trail is divided in these following intervals:
5 miles in 2.5 hours = 5 miles at 11:30 am, as 2 x 2.5 = 5.Saw the view and had the snack until 12 am.Completed the trial at 1 pm, as he hiked the remaining 3 miles at the rate of 3 miles per hour.For Micah, the time that he took to complete the trail is:
t = d/v = 8/7 = 1.14 hours.
Hence he completed his trial around 11:40 AM, as he left at 10:30 A.M.
He caught up to Taylor during the first interval of his trip, when the motion functions are as follows:
Taylor: 2t + 3. (when Micah left at 10:30 A.M = 1.5 hours after Taylor, Taylor had already hiked 3 miles).Micah: 7t.Then:
7t = 2t + 3.
5t = 3.
t = 3/5.
t = 0.6 hours = 36 minutes after Micah left = 11:06 A.M.
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75 - (5+2 (5) +7(8) +1)
Answer:
3
Step-by-step explanation:
75 - (5 + 10 + 56 + 1)
75 - (15 + 56 + 1)
75 - (71 + 1)
75 - 1 x 72
75 - 72
3
An experimental blood test has been developed for lockjaw by the National Institute of HealthDue to the experimental nature of the test, it is not 100% accurateIn a trial of the blood test, the following probabilities were computed 51% of the participants in the trial have lockjaw the participants with lockjaw, 76% have a positive blood test the participants who do not have lockjaw, 84% have a negative blood test Round your answers to three decimals a ) What is the probability that a random participant will have a negative blood test ? b ) If a randomly selected participant has a positive blood test , what is the probabi that they do not have lockjaw ?
The probabilities in the context of this problem are given as follows:
a) Negative blood test: 0.543 = 54.3%.
b) Do not have lockjaw, given that the test is positive: 0.1682 = 16.82%.
What is Conditional Probability?Conditional probability is the probability of one event happening, considering a previous event. The formula is:
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which the parameters of the formula are described as follows:
P(B|A) is the probability of event B happening, given that event A happened.[tex]P(A \cap B)[/tex] is the probability of both events A and B happening.P(A) is the probability of event A happening.For item a, the percentages associated with negative blood tests are given as follows:
84% of 49% (do not have lockjaw).24% of 51% (have lockjaw).Hence the probability is:
p = 0.84 x 0.49 + 0.24 x 0.51 = 0.534 = 53.4%.
For item b, the probabilities associated with positive blood tests and not having lockjaw are given as follows:
0.466 = 46.6% positive.16% of 49% have positive tests and do not have lockjaw.Hence the conditional probability is:
P(B|A) = 0.49 x 0.16/0.466 = 0.1682 = 16.82%.
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The shape below is made of two rectangles joined together.
9 cm
5 cm
8 cm
5 cm
Find the total area of the shape.
Optional working
Answer:
a=7, b=3
Step-by-step explanation:
Subtracting, we get the area of QRXY is 63 cm².
Using the area formula of a rectangle, we get 9a=63, and thus a=7.
Using the area formula again on triangle PXYS, 7b=21, and thus b=3.
The value of side 'a' is 7cm and side b is 3 cm.
What is an area?The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the rectangle in a two-dimensional plane is called the area of the rectangle.
It is given that the area of PQRS is 84 square cm and the area of PSYX is 21 square cm.
The area of QRXY is calculated as,
Area QRXY = 84 - 21
Area QRXY = 63 square cm
The side a will be calculated as,
a x 9 = 63
a = 63 / 9
a = 7 cm
The side of b will be,
b x 7 = 21
b = 21 / 7
b = 3 cm
Therefore, the value of side 'a' is 7cm and side b is 3 cm.
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The graph shown is the graph of which function?A. f(x)=tan xB. f(x)= sec xC. f(x)= csc xD. f(x)=cot x
The graph shown in the graph of f(x) = cot x. (Option D)
In this diagram, point P is the orthocenter of AABC.How is the orthocenter of atriangle found?
SOLUTION
Recall the definition of orthocenter of a triangle
The orthocenter of a triangle is the point where the perpendicular drawn from the vertices to the opposite sides of the triangle intersect each other.
Therefore from the options the right answer is:
By drawing a line from each vertex that is perpendicular to the opposite sides.
x - y ≥-3 and 3x + 2y ≥ 0
First, if we draw the lines of the equations x-y = -3 and 3x+2y = 0, we get the following:
the red line represents the first equation and the blue line represents the second equation. But since we are working with inequalities, the intersection between these two inequalities will be the intersection of the semiplanes that they form.
To check the region that will be the intersection, we can check two opposite points and see if both inequalities are true. In this case, if we take the points (-2,-2) and (2,2), we get the following:
[tex]\begin{gathered} -2-(-2)\ge-3\text{ and }3(-2)+2(-2)\ge0 \\ \Rightarrow0\ge3\text{ and }-10\ge0 \end{gathered}[/tex]notice that the second inequality is not true. Now, with the point (2,2), we get:
[tex]0=2-2\ge-3\text{ and }3(2)+2(2)\ge0[/tex]which are true, therefore, the region that represents both inequalities is the following:
The distance to Star A is about 8 × 10^4 light years. The distance to Star B is about 2 × 10^6 light years. Choose which star is farther away. Then fill in the blankwith a number written in standard notation.
Given:
[tex]\begin{gathered} \text{The distance of star A is 8}\times10^4\text{ light years} \\ \text{The distance of star B is 2}\times10^{6^{}}\text{ light years} \end{gathered}[/tex]To choose which start is farther away,
[tex]\begin{gathered} \text{Star B -Star A=}(2\times10^6)-(8\times10^4) \\ =10^4(2\times10^2-8) \\ =192\times10^4 \end{gathered}[/tex][tex]\text{Star B is 192}\times10^4\text{ light years times far away from star A.}[/tex]Prove the following statement using the given pieces of information.2Given: ZGPS = ZJPS, PS_L_GJProve: ASJP – ASGPZGPS ZJPSbecause perpendicular lines form right angles, and all right anglès are congruent.PS and PS arethe two pairs of congruent angles.Click to select your answer(s).
Answer:
[tex]\measuredangle GPS=\measuredangle JPS[/tex]Because it is one of the given pieces of information.
[tex]\measuredangle PSG\cong\measuredangle PSJ[/tex]because perpendicular lines form right angles, and all right angles are congruent.
PS and PS are adjacent sides next to the two pairs of congruent angles.
[tex]PS\cong PS[/tex]By the Reflexive Property of Congruence
[tex]\Delta SJP\cong\Delta SGP[/tex]by ASA triangle congruence rule
Explanation:
Given the figure of the triangle in the attached image.
Given that;
[tex]\measuredangle GPS=\measuredangle JPS[/tex]Because it is one of the given pieces of information.
Then we can observe that;
[tex]\measuredangle PSG\cong\measuredangle PSJ[/tex]because perpendicular lines form right angles, and all right angles are congruent.
Also,
PS and PS are adjacent sides next to the two pairs of congruent angles.
And;
[tex]PS\cong PS[/tex]By the Reflexive Property of Congruence
Thus,
[tex]\Delta SJP\cong\Delta SGP[/tex]by ASA triangle congruence rule
Find the coordinates of the vertices of each
figure after the given
transformation.
reflection across y = -1
The x-components of the vertices are all that need to be taken into consideration for reflection along a vertical axis (x = -1).
How can coordinates be determined after reflection?The x-coordinates and y-coordinates move when a point is reflected across the line y = x. The line y = x reflects the point (x, y), and the reflection is (y, x).
The new value of x for any point (x, y) would be the angle 'd' with respect to the reflection axis (x -(-1)), then inverted for reflection around the reflection axis x = -1. x’ = -1 -d… where x = -1 -(x + 1) = -x -2 and d = (x - (-1)) = (x + 1)
For instance, if a = (1, 3), a' = (-1, -2, 3) = (-3, 3).
If you have a triangle with some vertices on one side and some on the other, straddling the axis, this reflection will still hold true for vertices on either side of the reflection axis.
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Estimate the total cost of the following items for your dorm room. Round the individual cost to the nearest ten dollars. Round your answer to the nearest dollar (no cents).
First, we need to round each individual item to the nearest ten dollars.
Loft bed $149.68 = $150.00
Beanbag chair $39.73 = $40.00
Storage cubes $19.85 = $20.00
Lava lamp $19.68 = $20.00
Now, we need to add up all the items to find the total cost.
Total cost = $150.00 + $40.00 + $20.00 + $20.00
Total cost = $230
Hence, the estimated total cost for the dorm room items is $230.
Ethan is measuring the lengths of various distances for a science project using feet. He is using the following formula to convert the distances to yards.
A. Proportional
B. Non- Proportional
C. Both Proportional and Non-Proportional
D. Neither Proportional nor Non-Proportional
Given g(x)=x^2-5x, find the equation of the secant line passing through (-3,g(-3)) and (4g(4)). Write your answer in form of y=mx+b
Given:
[tex]g(x)=x^2-5x\text{ ; (}-3,g(-3)),(4,g(4))[/tex][tex]g(-3)=(-3)^2-5(-3)[/tex][tex]g(-3)=9+15[/tex][tex]g(-3)=24[/tex][tex]g(4)=4^2-5(4)[/tex][tex]g(4)=16-20[/tex][tex]g(4)=-4[/tex]Equation of line with the points (-3,24) and (4,-4)
[tex]\frac{y-y_1}{y_2-y_1}=\frac{x-x_1}{x_2-x_1}[/tex][tex]\frac{y-24_{}}{-4_{}-24_{}}=\frac{x+3_{}}{4_{}+3_{}}[/tex][tex]\frac{y-24_{}}{-28_{}}=\frac{x+3_{}}{7_{}}[/tex][tex]\frac{y-24_{}}{-4_{}}=\frac{x+3_{}}{1_{}}[/tex][tex]y-24_{}_{}=-4(x+3)_{}_{}[/tex][tex]y_{}=-4x-12+24[/tex][tex]y=-4x+12[/tex]Convert 7935 ml into litres
Answer:
7.935L
Step-by-step explanation:
1L=1000ml
7935/1000=7.935
Answer:
Step-by-step explanation:
1000 ml = 1 litre
7000 ml = 7 litres
935 ml = 0.935 litres
7935 ml = 7.935 litres
Hope this helped
For the function, f(x) = -x + 4, find f(-2), f(-0.5) and f(3)
Given function is
[tex]f(x)=-x+4[/tex][tex]\begin{gathered} f(-2)=2+4=6 \\ f(-0.5)=0.5+4=4.5 \\ f(3)=-3+4=1 \end{gathered}[/tex]correct option is D 6, 4.5, 1.
Hi guys.I was sick today and I’m still not feeling good.I missed out on class and I’ll be giving 25 points to whoever helps me.Thank you
5x + 2 + 5x - 2 = 180
5x = 180
x = 36
A right triangle is formed by the x-axis, the y-axis, and the line y = -2x + 7.A. Sketch and label a graph of the triangle in the coordinate plane.B. Find the length of the hypotenuse.C. Find the area of the triangle.
The given equation is
[tex]y=-2x+7[/tex]We have to find the axis interceptions to graph this function.
For x = 0, we have
[tex]y=-2(0)+7=0+7=7[/tex]The y-interception is (0,7).
For y = 0, we have
[tex]\begin{gathered} 0=-2x+7 \\ 2x=7 \\ x=\frac{7}{2} \end{gathered}[/tex]The x-interception is (7/2, 0).
Now, we graph.
Where h is the hypothenuse.
To find the hypothenuse of the right triangle formed, we use the distance formula and both points.
[tex]d=\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]Replacing the coordinates, we have
[tex]\begin{gathered} d=\sqrt[]{(0-7)^2+(3.5-0)^2}=\sqrt[]{(-7)^2+(3.5)^2} \\ d=\sqrt[]{49+12.25}=\sqrt[]{61.25}\approx7.83 \end{gathered}[/tex]Therefore, the hypotenuse is 7.83 units long, approximately.
At last, the area of the triangle is found with the formula
[tex]A=\frac{1}{2}b\cdot h[/tex]Where b is the base and h is the height of the triangle. b = 3.5, h = 7.
Replacing these values, we have
[tex]A=\frac{1}{2}(3.5)\cdot(7)=\frac{24.5}{2}=12.25u^2[/tex]Therefore, the area of the triangle is 12.25 square units.
Hi someone please help me and thanks have a great day. Hi someone please help me and thanks have a great day Question number 5Hi someone please help me and thanks have a great day.
Answer
a) Angle L = 36.9°
Angle N = 53.1°
b) For the relationship between them, we can see that
Angle L + Angle N = 36.9° + 53.1° = 90°
Hence, they both sum up to give 90° and are thus complementary angles.
Explanation
In a right-angle triangle, the side opposite the right angle is the Hypotenuse, the side opposite the given angle that is non-right angle is the Opposite and the remaining side is the Adjacent.
For this question, we first use Angle L as the non-right-angle angle
Hypotenuse = LN = 5
Opposite = NM = ?
Adjacent = LM = 4
Angle = L
Trignometric ratios allow us to interprete CAH as
Cos L = (Adj/Hyp)
Cos L = (4/5)
Cos L = 0.8
L = Cos⁻¹ (0.8)
L = 36.9°
Now, using Angle N as the non-right-angle angle,
Hypotenuse = LN = 5
Opposite = LM = 4
Adjacent = NM = ?
Angle = N
Trignometric ratios allow us to interprete SOH as
Sin N = (Opp/Hyp)
Sin N = (4/5)
Sin N = 0.8
N = Sin⁻¹ (0.8)
N = 53.1°
b) For the relationship between them, we can see that
Angle L + Angle N = 36.9° + 53.1° = 90°
Hence, they both sum up to give 90° and are thus complementary angles.
Hope this Helps!!!
