AJ's Car used 3 1/4 gallons of gas on a trip to the beach assume one gallon equals 3.8 what is the best estimate of number of liters AJ's Car use
help me please
thank you
Answer:
Domain: A, [tex](-\infty, \infty)[/tex]
Range: A, [tex][4, \infty)[/tex]
Step-by-step explanation:
The domain is the set of x-values and the range is the set of y-values.
1. Look at the figure, OJKLM. Find the length of JKM5x-114+ 2xK
Answer: 24
Explanation
Opposite sides of a parallelogram are congruent.
Thus, assuming JKLM as a parallelogram, then:
[tex]5x-1=14+2x[/tex]By solving we get:
[tex]5x-2x=14+1[/tex][tex]3x=15[/tex][tex]x=\frac{15}{3}[/tex][tex]x=5[/tex]Finally, replacing this value in the expression of JK to know the value of JK:
[tex]JK=14+2(5)[/tex][tex]JK=14+10[/tex][tex]JK=24[/tex]Another method is to add the parents’ heights in inches and then add an additional 5 inches if the child is a boy or subtract 5 inches if the child is a girl. This total is then divided by 2 to predict the child’s ultimate height.Use the variable D, height of dad) and M, height of mom Write a formula for a boy’s adult height. Write the formula for a girl’s adult height.
Concept:
Write the variables
Height of dad = D inches
Height of mum = M inches
Step 1:
Total parent's height = D + M
Step 2:
The formula for a boy's adult height
[tex]=\text{ }\frac{D\text{ + M + 5}}{2}\text{ inches}[/tex]Step 3:
The formula for a girl’s adult height.
[tex]=\text{ }\frac{D\text{ + M - 5}}{2}\text{ inches}[/tex]
The triangle ABC pictured below is a right, isosceles triangle. If the length of side AC is 3, give the lengths of the other two sides and the measures of angle A and angle B.
From the statement, we know that we have a right triangle that:
0. has an angle ∠C = 90°,
,1. is also an isosceles triangle,
,2. has a side AC = 3.
1) From points 2 and 3, we know that:
[tex]AC=BC=3.[/tex]Because we have a right triangle, we can use Pitagoras Theorem, which states that:
[tex]c^2=a^2+b^2.[/tex]Where:
• c = AB = hypotenuse,
,• a = BC = 3,
,• b = AC = 3.
Replacing these data in the equation above, we get:
[tex]c^2=3^2+3^2=9+9=18\Rightarrow AB=c=\sqrt{18}.[/tex]2) From point 2 we know that angles A and B must be equal:
[tex]\angle A=\angle B.[/tex]From geometry, we know that the inner angles of a triangle sum up to 180°, so we have:
[tex]\angle A+\angle B+\angle C=180\degree\Rightarrow2\angle A+\angle C=180\degree\Rightarrow\angle A=\frac{180\degree-\angle C}{2}=\frac{180\degree-90\degree}{2}=45\degree.[/tex]Where we have used point 1.
AnswerThe sides of the triangle are:
• AB = √18,,
,• AC = 3,
,• BC = 3.
The angles of the triangle are:
• ∠A = 45°,,
,• ∠B = 45°,,
,• ∠C = 90°.
A chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture. The premium antifreeze solutioncontains 80% pure antifreeze. The company wants to obtain 320 gallons of a mixture that contains 15% pure antifreeze. How many gallons of water and howmany gallons of the premium antifreeze solution must be mixed?
Amount of water = 260 gallons
Amount of antifreeze = 60 gallons
Explanation:let the amount of water = w
amount of water + amount of antifreeze will give 320 gallons of mixture
w + amount of antifreeze = 320
amount of antifreeze = 320 - w ...(1)
The concentration for the antifreeze = 80% = 0.8
The concentration of the mixture = 15% = 0.15
From our question, we are mixing antifreeze with pure water (two different things). In our calculation, we can write the concentration in terms of water or in terms of antifreeze.
Writing the concentration in terms of amount of antifreeze
0.8(amount of antifreeze) + percent of antifreeze (amount of water) = concentraton of the mixture
The mixture contains 15% antifreeze
water contains no antifreeze, percent = 0
0.8(320 - w) + 0(w) = 0.15(amount of mixture)
0.8(320 - w) + 0 = 0.15(320)
256 - 0.8w + 0 = 48
256 - 0.8w = 48
collect like terms:
256 - 48 = 0.8w
208 = 0.8w
divide both sides by 0.8:
208/0.8 = w
w = 260
substitute for w in equation (1)
amount of antifreeze = 320 - 260 = 60
Amount of water = 260 gallons
Amount of antifreeze = 60 gallons
with work please 2x -42 = -8x + 28
We first need to
Hello, I need some assistance with this homework question please for precalculusHW Q44
SOLUTION:
Case: Logarithms
A logarithm is the opposite of power. In other words, if we take a logarithm of a number, we undo exponentiation.
We consider the log of power law below:
[tex]\begin{gathered} \log_aa^x=x\log_aa \\ =x \end{gathered}[/tex]Given:
[tex]\log_33^{66}[/tex]Required: Without using calculators, use log laws to answer
Method:
Applying the law above,
[tex]\begin{gathered} \log_33^{66} \\ =66\log_33 \\ =66\times1.(Remember\text{ same base law: }\log_33=1 \\ =66 \end{gathered}[/tex]Final answer:
66
Stephanie practiced the piano for 1 hour 15 min per day. If she practiced for 8 days, what was her total practice time?
Answer:
10 hours
Step-by-step explanation:
1 hour 15 mins = 75 minutes
75 minutes x 8 days = 600 total in minutes
600 minutes/ 60 minutes = 10 hours
A company uses a logo shaped like a triangle. The dimensions of the logo are shown in the diagram. What is the area of the logo in square inches?
Area of triangle shape
Area A = BxH/2 = [ 8 x (5+1/2) ]/2
. = 4 x 5.5
. = 22
Then answer is
Area of logo = 22 inches2
OPTION B)
A hexagonal prism whose base has area 25.6 square centimeters and who’s height is 8.9 centimeters
We are given the following information about a hexagonal prism.
Base area = 25.6 cm²
Height = 8.9 cm
Recall that the volume is given by
[tex]V=B\cdot h[/tex]Where B is the area of the base and h is the height of the hexagonal prism.
Let us substitute the given values into the above formula
[tex]\begin{gathered} V=B\cdot h \\ V=25.6\cdot8.9 \\ V=227.84\: cm^3 \end{gathered}[/tex]Therefore, the volume of the given hexagonal prism is 227.84 cubic centimeters.
3. A data set has six numbers. Four of the numbers are: 4, 3, 8, 12. If the mode is 3, find at least three possibilities for the other two numbers.
The possibility of the other two numbers in the given data set is 3.
What do we mean by a number?An object that can be counted, measured, and given a name is a number. The initial examples are the natural numbers 1, 2, 3, 4, and so forth. In language, numbers can be expressed using number words. The symbols referred to as numerals can be used to represent specific numbers in a more general way; for instance, the numeral "5" stands for the number five. Due to the limited amount of symbols that can be learned, fundamental numbers are typically arranged in a numeral system, which is a systematic manner of representing any number. The Hindu-Arabic numeral system, which enables any number to be expressed using a combination of 10 fundamental numeric symbols known as digits, is the most widely used numeral system.So, by observing the data, we can simply conclude that:
As the mode is 3, the remaining two numbers are 3.Therefore, the possibility of the other two numbers in the given data set is 3.
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PLEASE HELP WITH NUMBER 16
Answer: C: Exam>=90
Step-by-step explanation:
The flaw you did was divided it by two, but you have to divide it by the number of numbers you have, which would be 4. that would give you 75, and then you have to figure out what score you would need to get on two tests (The question says it counts as 2 tests) which ends up being 90% to give you an 80%. So the answer is C! I hope this helps :)
Consider a trebuchet launching a flaming stone over a castle wall. It is mounted on a small hill and has a parabolic trajectory (neglecting air resistance). Once it crashes into the ground on the other side of the castle wall, it comes to rest. This motion is described by the function below, where x, measured in meters, represents horizontal displacement from the launch position and y = f(x) represents vertical distance from the ground, measured in meters.
f(x) = -0.25x2 + 3.15x + 5
Determine the contextual domain and range and justify your answers. What is the peak height of the flaming stone?
The domain of function f(x) is the set of all real numbers.
the range of function f(x) is, f ≤ 14.9225
And the peak height of the flaming stone would be, 14.9 meters
In this question, we have been given a trebuchet launching a flaming stone over a castle wall. It is mounted on a small hill and has a parabolic trajectory. Once it crashes into the ground on the other side of the castle wall, it comes to rest. This motion is described by the function f(x) = -0.25x² + 3.15x + 5, where x, measured in meters, represents horizontal displacement from the launch position and y = f(x) represents vertical distance from the ground, measured in meters.
We need to determine the contextual domain and range and justify your answers.
The domain of function f(x) is the set of all real numbers.
The range of function f(x) is, f ≤ 14.9225
From the range of the function, the peak height of the flaming stone would be, 14.9 meters
Therefore, the domain of function f(x) is the set of all real numbers.
the range of function f(x) is, f ≤ 14.9225
And the peak height of the flaming stone would be, 14.9 meters
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Due to an economic downturn, a company had to decrease its staff from 48 employees to 24 employees. What was the percentage decrease in staff?
we get that the decrease percentage is
[tex]\frac{48-24}{48}\cdot100=\frac{24}{48}\cdot100=50\text{ \%}[/tex]so the percentage of decrease is 50%
what is the length of AB, if A (-3,-3) and B (5,-9)?
Answer:
The distance of the line would be 10 units.
can i get help on this?Number of digits in phone number is 7.
There are 7 digits in phone number. The first digit cannot be 0 and 1. So first digit can be filled by 8 numbers (from 2 to 9). Remaining 6 digits of the phone number can be filled by all 10 number (0 to 1).
The possible number of 7 digit phone numbers are,
[tex]8\cdot10\cdot10\cdot10\cdot10\cdot10\cdot10=8,000,000[/tex]So 8,000,000 different numbers are possible.
Answer: 8,000,000
Find C.Round to the nearest tenth.20 ft\22 ftAB18 ftC = [? ]°Law of Cosines: c2 = a2 + b2 - 2ab cos C=Enter
The given triangle is shown below
From the triangle
[tex]a=22ft,b=20ft,c=18ft,C=\text{?}[/tex]Using the law of Cosines
[tex]c^2=a^2+b^2-2ab\cos C[/tex]Substitute the values of a, b, c into the formula
This gives
[tex]18^2=22^2+20^2-2(22)(20)\cos C[/tex]Simplifying the expression
[tex]\begin{gathered} 324=484+400-880\cos C \\ 324=884-880\cos C \end{gathered}[/tex]Collect like terms
[tex]\begin{gathered} 324-884=-880\cos C \\ -560=-880\cos C \end{gathered}[/tex]Divide both sides by -880
[tex]\begin{gathered} \frac{-560}{-880}=\cos C \\ \cos C=0.6364 \end{gathered}[/tex]Find the value of C
[tex]\begin{gathered} C=\cos ^{-1}(0.6364) \\ C=50.5^{\circ} \end{gathered}[/tex]If the figures are similar, use a proportion to find the missing side?
Given:
The figure is
Find-:
The value of "x"
Explanation-:
The ratio of sides is
Compared with angle sides is
[tex]\frac{28}{21}=\frac{8}{6}=\frac{30}{x}[/tex]So, the value of "x" is
[tex]\begin{gathered} \frac{8}{6}=\frac{30}{x} \\ \\ x=\frac{30}{8}\times6 \\ \\ x=\frac{30}{4}\times3 \\ \\ x=\frac{15}{2}\times3 \\ \\ x=\frac{45}{2} \\ \\ x=22.5 \end{gathered}[/tex]The value of "x" is 22.5
Try this: Find "y." How does CPCTC help? A ABC EA ADC. Find y. A (3y) 21° D C С B. DO Pear Deck Interacti Do nove Students, enter a number!
AS ACD and ACBare congruent triangles, we have that
[tex]\begin{gathered} 3y=21\rightarrow \\ y=\frac{21}{3}=7 \end{gathered}[/tex]so the answer is y=7
help me pleaseee!!!
thank you
The equation of the line is y = 800x + 294000 and the average price of a new home in 2014 is $302000.
What is the slope?The ratio that y increase as x increases is the slope of a line. The slope of a line reflects how steep it is, but how much y increases as x increases. Anywhere on the line, the slope stays unchanged (the same).
[tex]\rm m =\dfrac{y_2-y_1}{x_2-x_1}[/tex]
The line passes through the points:
(0, 294000) and (7, 288400)
The equation of the line:
y - 294000 = (288400 - 294000)/(7)[x]
y - 294000 = 5600/7 (x)
y = 800x + 294000
x = 2014 - 2004 = 10
Plug x = 10 in the above equation:
y = 800(10) + 294000
y = 302000
Thus, the equation of the line is y = 800x + 294000 and the average price of a new home in 2014 is $302000.
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Write a linear function that represents the depth of the pond at a given time
Let x represent the number of days
Let f(x) represent water depth
We can see that the water depth is a function of the number of days.
Water depth, f(x) is the dependent variable and number of days, x is the independent variable.
As the days go by, the water depth changes.
The function is therefore:
[tex]f(x)=54-0.5x[/tex]The domain is the set of values (number of days) for which the pond will have a valid depth, i.e. between 54'' and 0.
[tex]0\le x\le108[/tex]Because at 0 days,
[tex]f(x)=54-0.5(0)=54^{\doubleprime}[/tex]And at 108 days,
[tex]f\mleft(x\mright)=54-0.5\mleft(108\mright)=0[/tex]The quotient of 4 times X and 2 more than Y
Answer:4x(y+2)
Step-by-step explanation:
2 - 2f(x)X + 1g(x) = 18 - 3.2Escreva (fog)(2) como uma expressão em função de 2.(fog)(x) =
Answer
[tex](f\text{ o g)(x) = }\frac{3x-16}{17-3x}[/tex]Explanation
We are given that
f(x) = (2 - x)/(x + 1)
g(x) = 18 - 3x
We are then asked to find (f o g)(x)
(f o g) (x) is the same as writing the expression for f(x) but instead of x, we will write g(x) in the expression.
[tex]\begin{gathered} f(x)=\frac{2-x}{x+1} \\ (\text{fog)(x) = }\frac{2-g(x)}{g(x)+1} \end{gathered}[/tex]Recall that
g(x) = 18 - 3x
So,
[tex]\begin{gathered} (\text{fog)(x) = }\frac{2-g(x)}{g(x)+1} \\ (\text{f o g)(x) = }\frac{2-(18-3x)}{18-3x+1} \\ (f\text{ o g)(x) = }\frac{2-18+3x}{17-3x} \\ (f\text{ o g)(x) = }\frac{-16+3x}{17-3x} \\ (f\text{ o g)(x) = }\frac{3x-16}{17-3x} \end{gathered}[/tex]Hope this Helps!!!
I need some help with this problem. Thanks.
Answer:
Natural:G
Whole number: B
Integer: H,D,J
Rational: A,F,E,I
Irrational: C,K
Step-by-step explanation:
Hey can you pleas help me on this math problem thank you
Given:
Nolan wraps 36 presents in 12 hours on Saturday
And wraps 42 presents in 14 hours on Friday
If y = number of gifts, and x = number of hours
So, the proportional equation will be as follows:
[tex]y=kx[/tex]Where k is the constant of proportionality
Total gifts = y = 36 + 42 = 78
Total hours = x = 12 + 14 = 26
So, subtitute into the euation to find k
[tex]\begin{gathered} 78=k\cdot26 \\ k=\frac{78}{26}=3 \end{gathered}[/tex]So, the answer will be the constant = 3
Gina has a box of red,blue,and green markers.The ratio of the number of red markers to the number of blue markers is 5:2.The ratio to the number of blue markers to the number of green markers is 3:5.What is the ratio of the number of red markers to the number of green markers?
Answer: 5:5
Step-by-step explanation:
Use the information to figure out how much you have of each color, then put in ratio.
hello would you mind checking if this is correct ?
we will use here pythagoras theorem here,
5^2 + 12^2 = C^2
25 + 144 = C^2
C = root 169
c = 13
The figure below is the graph of the dimensions of a rectangle whoseadjacent side lengths exhibit direct variation.
Concept
What is a direct variation? A direct variation is a direct relationship between two variables in which increase in one variable lead to increase in the other variable and decrease in one variable lead to decrease in the other variable.
Hence, the relationship fron the graph between Height and Width of the rectangle is not a direct variation.
Therefore,
The relationship is not a direct variation.
Final answer
Option B = False
For right triangle find the missing quantity indicated below express the angle in degrees and minutes not just degrees please and round your answer
To find the angle we will use the sine theorem, but first we will find the measure of the missing side:
[tex]x^2=1325^2+2569^2[/tex][tex]x=\sqrt[]{1325^2+2569^2}[/tex][tex]x=\sqrt[]{8355386}^{\prime}\text{ }[/tex]measure of angle B must be:
[tex]\frac{sin\text{(B)}}{2569}=\frac{\sin (90^{\circ})}{\sqrt[]{8355386}}[/tex][tex]\sin (B)=\frac{2569}{\sqrt[]{8355386}}[/tex][tex]B=62.72^{\circ}[/tex]Finally convert B to degrees and minutes:
[tex]\frac{1^{\circ}}{60^{\prime}}=\frac{0.72^{\circ}}{m^{\prime}}[/tex][tex]m^{\prime}=0.72\cdot60=43.2^{\prime}[/tex][tex]B=62^{\circ}43.2^{\prime}\text{ }[/tex]