Hello!
i need help with question 67 & 68

9514 1404 393

Answer:

  11

Step-by-step explanation:

The degree of the given monomial is the sum of the exponents of the variables.

  m has degree 6

  n has degree 5

The degree of the monomial is 6+5 = 11.

Answer:

0.9295 = 92.95% probability of getting someone who tests negative, given that he or she did not have the disease.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this question:

11 + 145 = 156 people did not have the disease.

Out of those, 145 tested positive. So

[tex]p = \frac{145}{156} = 0.9295[/tex]

0.9295 = 92.95% probability of getting someone who tests negative, given that he or she did not have the disease.

Answer:

It should be a 2 sample t-test for the sample mean mu 1 - mu 2 at alpha = 0.05.

Step-by-step explanation:

To solve, you can just insert the data values into a graphing calculator and it should work. Remember to check the conditions and write out the null and alternate hypotheses.

Null: mu 1 - mu 2 = 0 There is no difference

Alternate: mu 1 - mu 2 =/= 0 There is a difference

Conditions:

-Random sample? Yes b/c assume that it is from a simple random sample.

-10%? Assume that there are more than 120 men and 80 women in the population"

-Normal Distribution? If the data for each respective sample is approx normal, assume they come from a normally distributed population. Large counts and the central limit theorem do not work here.

After this, insert ur data values into the graphing calculator n solve for p.

Once you get p, make a conclusion based on alpha = 0.05. If p is less than alpha, you can reject the null and conclude that you have significant evidence that the alternate is true. If p is greater than alpha, you cannot reject the null and conclude that you do not have significant evidence that the alternate is true.

Given:

The limit problem is:

[tex]\lim_{x\to -\infty}(-2x^5-3x+1)[/tex]

To find:

The value of the given limit problem.

Solution:

We have,

[tex]\lim_{x\to -\infty}(-2x^5-3x+1)[/tex]

In the function [tex]-2x^5-3x+1[/tex], the degree of the polynomial is 5, which is an odd number and the leading coefficient is -2, which is a negative number.

So, the function approaches to positive infinity as x approaches to negative infinity.

[tex]\lim_{x\to -\infty}(-2x^5-3x+1)=\infty[/tex]

Therefore, [tex]\lim_{x\to -\infty}(-2x^5-3x+1)=\infty[/tex].

Answer:

the scores on her last test is x (x > 0)

because on her last tests she scored 4 points lower than she did on her fifth test

=> the scores in the 5th test is x + 4

because Angela’s average for six math tests is 87, we have:

[tex] \frac{93 + 87 + 82 + 86 + x + x + 4}{6} = 87 \\ \\ < = > \frac{352 + 2x}{6} = 87 \\ \\ < = > 352 + 2x = 522 \\ \\ < = > 2x = 170 \\ \\ < = > x = 85[/tex]

=> on her last test, she had 85

=> on her 5th test, she had 85 + 4 = 89

9514 1404 393

Answer:

  A. 5 should have been subtracted in step 4

Step-by-step explanation:

No question is stated, so there is no "answer."

__

If we assume the question is, "What error did Keith make?" then choice A properly describes it.

Step 4 should look like ...

  x -5 = 7y . . . . . . . 5 should be subtracted from both sides

and the final result should be ...

  g(x) = (x -5)/7

Answer:

0.0668 = 6.68% probability a randomly selected year will have an average snowfall above 200 inches.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with a average of 170 inches, and a standard deviation of 20 inches.

This means that [tex]\mu = 170, \sigma = 20[/tex]

What is the probability a randomly selected year will have an average snowfall above 200 inches?

This is 1 subtracted by the p-value of Z when X = 200. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{200 - 170}{20}[/tex]

[tex]Z = 1.5[/tex]

[tex]Z = 1.5[/tex] has a p-value of 0.9332.

1 - 0.9332 = 0.0668

0.0668 = 6.68% probability a randomly selected year will have an average snowfall above 200 inches.

Answer:

By these examples you are able to see that the square of an odd number is always 1 more than a multiple of 4.

Step-by-step explanation:

For examples,

Let's consider squares of 3, 11, 25, 37 and 131.

[tex] {3}^{2} = 9[/tex]

8 is a multiple of 4, and 9 is more than 8.

[tex] {11}^{2} = 121[/tex]

120 is a multiple of 4 and 121 is one more than it.

[tex] {25}^{2} = 625[/tex]

624 is a multiple of 4 and 625 is one more than it.

[tex] {37}^{2} = 1369[/tex]

1368 is a multiple of 4 and 1369 is one more than 1368.

[tex] {131}^{2} = 17161[/tex]

17160 is a multiple of 4.

Answer:

1/3

Step-by-step explanation:

when you change the mixed numbers to improper fractions, you get 4/5 * 10/9 ÷ 8/3. you can flip the 8/3 to 3/8 and change the division sign to multiplication, because dividing by a fraction is the same as multiplying by its reciprocal. you can cancel some things and ultimately you get 1/3

Answer:

y = 3

Step-by-step explanation:

Given that the shapes are similar then the ratios of corresponding sides are equal, that is

[tex]\frac{AB}{EF}[/tex] = [tex]\frac{CD}{GH}[/tex] , substitute values

[tex]\frac{3}{2}[/tex] = [tex]\frac{4.5}{y}[/tex] ( cross- multiply )

3y = 9 ( divide both sides by 3 )

y = 3

Answer:

C. -4

Step-by-step explanation:

Answer:

(c) - 4

is your right answer

Answer:

At 4:00 PM the distance between the two ships is 104.40 kilometers.

Step-by-step explanation:

Given that at noon, ship A is 150 km west of ship B, and ship A is sailing east at 30 km / h and ship B is sailing north at 25 km / h, to determine how fast is the distance between the ships changing at 4:00 PM the following calculation must be performed:

150 - (30 x 4) = 150 - 120 = 30

0 + (25 x 4) = 0 + 100 = 100

30 ^ 2 + 100 ^ 2 = X ^ 2

√ (900 + 10,000) = X

√10,900 = X

104.40 = X

Therefore, at 4:00 PM the distance between the two ships is 104.40 kilometers.

Answer with Step-by-step explanation:

We are given that

Side of cube, x=30 cm

Error in measurement of edge,[tex]\delta x=0.5[/tex] cm

(a)

Volume of cube, [tex]V=x^3[/tex]

Using differential

[tex]dV=3x^2dx[/tex]

Substitute the values

[tex]dV=3(30)^2(0.5)[/tex]

[tex]dV=1350 cm^3[/tex]

Hence,  the maximum possible error in computing the volume of the cube

=[tex]1350 cm^3[/tex]

Volume of cube, [tex]V=(30)^3=27000 cm^3[/tex]

Relative error=[tex]\frac{dV}{V}=\frac{1350}{2700}[/tex]

Relative error=0.05

Percentage  error=[tex]0.05\times 100=5[/tex]%

Hence, relative error in computing the volume of the cube=0.05  and

percentage error in computing the volume of the cube=5%

(b)

Surface area of cube,[tex]A=6x^2[/tex]

[tex]dA=12xdx[/tex]

[tex]dA=12(30)(0.5)[/tex]

[tex]dA=180cm^2[/tex]

The maximum possible error in computing the volume of the cube=[tex]180cm^2[/tex]

[tex]A=6(30)^2=5400cm^2[/tex]

Relative error=[tex]\frac{dA}{A}=\frac{180}{5400}[/tex]

Relative error  in computing the volume of the cube=0.033

The percentage error in computing the volume of the cube=[tex]0.033\times 100=3.3[/tex]%

Answer:

dddddddddv

Step-by-step explanation:

Answer:

[tex]4 {x}^{2} - 4x - 8 - (2 {x}^{2} + 3x - 6) = 4 {x}^{2} - 4x - 8 - 2 {x}^{2} - 3x + 6 = 2 {x}^{2} - 7x - 2[/tex]

Answer:

[tex]\mu = 15.6[/tex]

[tex]\sigma =3.684[/tex]

Step-by-step explanation:

Given

[tex]p =13\%[/tex]

[tex]n = 120[/tex]

Solving (a): The mean

This is calculated as:

[tex]\mu = np[/tex]

So, we have:

[tex]\mu = 13\% * 120[/tex]

[tex]\mu = 15.6[/tex]

Solving (b): The standard deviation

This is calculated as:

[tex]\sigma = \sqrt{\mu * (1 - p)[/tex]

So, we have:

[tex]\sigma = \sqrt{15.6 * (1 - 13\%)[/tex]

[tex]\sigma = \sqrt{15.6 * 0.87[/tex]

[tex]\sigma =\sqrt{ 13.572[/tex]

[tex]\sigma =3.684[/tex]

Answer:

D. None of the above

Step-by-step explanation:

Both triangles have the same shape but different size. Their area cannot be the same. Also, the ratio of their corresponding side lengths are the same.

Thus:

8/4 = 10/5 = 6/3 = 2

This implies that both triangles are similar.

Therefore, both triangles cannot have the same area, they are not of the same size and cannot be congruent to each other.

Answer:

(1) the number of liters the tank holds

Step-by-step explanation:

Answer:

Discount amount = $328.73

Step-by-step explanation:

Below is the calculation for the discount amount:

The marked price of bicycle = 2000

Purchase price = Rs 1921

VAT = 13%

First find the purchase price excluding VAT = 1921  - (13% of 1921) = 1671.27

Discount amount = 2000 - 1671.27

Discount amount = $328.73

Answer:

Given Two equations :-

[tex]3x {}^{2} - 2 {y}^{2} = 57 .\: .\: .\: . \:(i) \\ - 2 {x}^{2} + 3 {y}^{2} = -23.\: .\: .\: . \:(ii)[/tex]

[tex](3x {}^{2} - 2 {y}^{2} = 57 ) \times 2 .\: .\: .\: . \:(i) \\ ( - 2 {x}^{2} + 3{y}^{2} = - 23) \times 3.\: .\: .\: . \:(ii)[/tex]

[tex]6x {}^{2} - 4 {y}^{2} =114 .\: .\: .\: . \:(i) \\ - 6 {x}^{2} + 9 {y}^{2} = - 69.\: .\: .\: . \:(ii)[/tex]

[tex]0 + 5 {y}^{2} = 45 \\ 5y {}^{2} = 45 [/tex]

[tex] {y}^{2} = 9[/tex]

[tex]y = + - 3[/tex]

3x²- 2×9 = 57

3x² - 18 = 57

3x² = 57 + 18

3x²= 75

x² = 25

x = ± 5

Answer:

The answer is C.

as for C . the value of f(x) increases by 7 and so the graph goes up by units 7.

OR

g(x) = |x| + 7

we know that |x| is f(x), so :-

g(x) = f(x) + 7

and since f(x) is plot on y- axis the graph climbs the y axis by 7 units

*The graph shifts right or left for the other functions*

Answer:

50 bags ;

£750

Step-by-step explanation:

The dimension of the rectangular lawn is 500ft by 300 ft

The area of the lawn an e obtained thus :

Area of rectangle = Length * width

Area of rectangle = 500 ft * 300 ft

Area of rectangle = 150000 feets

1 bag of fertilizer covers 3000 feets

The minimum bags of fertilizer required :

Area of rectangle / Area covered by 1 bag of fertilizer

Minimum bags of fertilizer required :

(150,000 / 3000) = 50 bags

50 bags of fertilizer

Cost per bag = 15

Total cost = 15 * 50 = £750

Answer:

$3.22 per square feet

Step-by-step explanation:

To solve, I usually set up an equation:

sq ft  = 12 1/2 = 1

 $        40.21     x

Then, use cross multiplication.

(12 1/2)x=40.21

Divide both sides by 12 1/2 or 12.5

x = 3.2168

Round to the hundredths place [because we're dealing with money]

$3.22

I hope this helps!

Answer:

3.22 per sq ft

Step-by-step explanation:

Take the total cost and divide by the amount of tiles

40.21 / 12.5

3.2168 per sq ft

Rounding to the nearest cent

3.22 per sq ft

Answer:

325 and 375 mph

Step-by-step explanation:

Given :

Distance between plane A and B = 2800

Recall :

Distance = speed * time

Let speed of A = v1

Speed of B = v2

v1 = v2 + 50

Time taken = 4 hours

Distance = speed * time

Total distance = 2800

2800 = v1 * 4 + v2 * 4

2800 = (4v1) + (4v2)

2800 = 4(v2+50) + 4v2

2800 = 4v2 + 200 + 4v2

2800 = 8v2 + 200

2800 - 200 = 8v2

2600 = 8v2

v2 = 2600/8

v2 = 325 mph

v1 = v2 + 50

v1 = 325 + 50

v1 = 375 mph

Answer:

[tex]\displaystyle y - \frac{\sqrt{2}}{2} = \frac{\sqrt{2}}{2} \bigg( x - \frac{\pi}{4} \bigg)[/tex]

General Formulas and Concepts:

Algebra I

Coordinates (x, y)

Functions

Function Notation

Point-Slope Form: y - y₁ = m(x - x₁)

Pre-Calculus

Calculus

Derivatives

Derivative Notation

Trig Derivative:                                                                                                          [tex]\displaystyle \frac{d}{dx}[sin(u)] = u'cos(u)[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle y = sin(x)[/tex]

[tex]\displaystyle x = \frac{\pi}{4}[/tex]

Step 2: Differentiate

Step 3: Find Tangent Slope

Step 4: Find Tangent Equation

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

Answer:

D. allows a person to borrow more money at a lower interest rate

40% of 15 L = 6 L of acid

20% of 25 L = 5 L of acid

This means the mixture contains a total of 11 L of acid, and with a total volume of 15 L + 25 L = 40 L, that means the mixture is at a concentration of

(11 L acid) / (40 L solution) = 0.275 = 27.5%