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the two answers not showing on screen are



C:y<6x-3
D:y<6-3

Answer:

The expected number of winning balls that Heather draws is 0.3.

Step-by-step explanation:

The balls are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

Expected value of the hypergeometric distribution:

The expected value is given by:

[tex]E(X) = \frac{nk}{N}[/tex]

Expected number of blue and green balls:

40 balls, which means that [tex]N = 40[/tex]

2 are chosen, which means that [tex]n = 2[/tex]

25 are blue, which means that [tex]k = 25[/tex]

So

[tex]E(X) = \frac{nk}{N} = \frac{25(2)}{40} = 1.25[/tex]

1.25 balls are expected to be blue and 2 - 1.25 = 0.75 green.

Of the blue balls, 12% are winning.

Of the green balls, 20% are winning.

Calculate the expected number of winning balls that Heather draws.

[tex]E_w = 1.25*0.12 + 0.75*0.2 = 0.3[/tex]

The expected number of winning balls that Heather draws is 0.3.

it might take 19 hours i might be wrong

Step-by-step explanation:

Answer:

B. -3

Step-by-step explanation:

Answer:

620 to the nearest ten is already rounded correctly.

Step-by-step explanation:

620 to the nearest ten is 620.

Answer:

Part 1)

10,000 different numbers.

Part 2)

A) 1 in 10,000.

Step-by-step explanation:

Part 1)

Since there are four digits and there are ten choices for each digit (0 - 9) and digits can be repeated, then we will have:

[tex]T=\underbrace{10}_{\text{Choices For First Digit}}\times\underbrace{10}_{\text{Second Digit}}\times\underbrace{10}_{\text{Third Digit}}\times \underbrace{10}_{\text{Fourth Digit}} = 10^4=10000[/tex]

Thus, 10,000 different numbers are possible.

Part 2)

Since there 10,000 different tickets possible, the chance of one being the correct combination will be 1 in 10,000.

This is equivalent to 0.0001 or a 0.01% chance of winning.

[tex]_____________________________________[/tex]

[tex]\sf\huge\underline\red{SOLUTION:}[/tex]

Use formula:

[tex]\sf{V = \pi(\frac{d}{2})^2h}[/tex]

Solving for diameter:

[tex]\sf d = 2 \times \sqrt{ \frac{V}{\pi h} } \\ \sf = 2 \times \sqrt{ \frac{40}{\pi \times 1800} } \approx0.16821 \\ = \sf \large\boxed{\sf{\green{d = 0.17}}}[/tex]

[tex]\sf\huge\underline\red{FINAL \: ANSWER}[/tex]

[tex]\large\boxed{\sf{\green{d=0.17}}}[/tex]

[tex]_____________________________________[/tex]

✍︎ꕥᴍᴀᴛʜᴅᴇᴍᴏɴǫᴜᴇᴇɴꕥ

✍︎ᴄᴀʀʀʏᴏɴʟᴇᴀʀɴɪɴɢ

Answer:

Infinitely many solutions.

They must satisfy [tex]y = \frac{1}{5}(x - 5)[/tex]

Step-by-step explanation:

Given

[tex]x - 5y = 5[/tex]

[tex]-x + 5y = -5[/tex]

Required

The best description

Add both equations

[tex]x - x - 5y + 5y = 5 - 5[/tex]

[tex]0+0 =0[/tex]

[tex]0 = 0[/tex] ---- this means that the system has infinitely many solutions.

Make y the subject in: [tex]-x + 5y = -5[/tex]

Add x to both sides

[tex]5y = x - 5[/tex]

Divide through by 5

[tex]y = \frac{1}{5}(x - 5)[/tex]

Hence, they must satisfy: [tex]y = \frac{1}{5}(x - 5)[/tex]

Answer:

height = 3

Step-by-step explanation:

x(x+6) = 27

x^2 + 6x - 27 = 0

(x+9)(x-3) = 0

x = 3

Answer:

check the attachment

Step-by-step explanation:

2x - y = - 4

- y = - 4 - 2x

y = 2x + 4

slope of the line = 2 with y - intercept 4

Answer:

A FORMULA is an expression that uses variables to state a rule.

Answer:

(a) 74553

(b) 172120

(c) 234802

Step-by-step explanation:

Given

[tex]y = \frac{340110}{1 + 377e^{-0.259t}}[/tex]

Solving (a): 1998

Year 1998 means that:

[tex]t =1998 - 1980[/tex]

[tex]t =18[/tex]

So, we have:

[tex]y = \frac{340110}{1 + 377e^{-0.259*18}}[/tex]

[tex]y = \frac{340110}{1 + 377e^{-4.662}}[/tex]

[tex]y = \frac{340110}{1 + 3.562}[/tex]

[tex]y = \frac{340110}{4.562}[/tex]

[tex]y = 74553[/tex] --- approximated

Solving (b): 2003

Year 2003 means that:

[tex]t = 2003 - 1980[/tex]

[tex]t =23[/tex]

So, we have:

[tex]y = \frac{340110}{1 + 377e^{-0.259*23}}[/tex]

[tex]y = \frac{340110}{1 + 377e^{-5.957}}[/tex]

[tex]y = \frac{340110}{1 + 0.976}[/tex]

[tex]y = \frac{340110}{1.976}[/tex]

[tex]y = 172120[/tex] --- approximated

Solving (c): 2006

Year 2006 means that:

[tex]t = 2006 - 1980[/tex]

[tex]t =26[/tex]

So, we have:

[tex]y = \frac{340110}{1 + 377e^{-0.259*26}}[/tex]

[tex]y = \frac{340110}{1 + 377e^{-6.734}}[/tex]

[tex]y = \frac{340110}{1 + 0.4485}[/tex]

[tex]y = \frac{340110}{1.4485}[/tex]

[tex]y = 234802[/tex] --- approximated

Answer:

0.38 = 38% probability that it is neither red nor blue​.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this question:

100 cars.

Of those, 28 + 34 = 62 are either blue or red.

100 - 62 = 38 are neither blue of red.

What is the probability that it is neither red nor blue​?

38 out of 100, so:

[tex]p = \frac{38}{100} = 0.38[/tex]

0.38 = 38% probability that it is neither red nor blue​.

Answer:

The answer is 209 pi cm^2

L.A.(Lateral Area) = π19×11 = 209 π

The lateral area of the given cone with a raidus of 19 cm and a slant height of 11 cm is: D. 209π cm²

Lateral area of a cone = πrL, where r is the radius and L is the slant height of the cone.

Given the following:

Lateral area of a cone = π(19)(11)

Lateral area of a cone = 209π cm²

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Answer:

5 years

Step-by-step explanation:

Answer:

Two lines that intersect and form right angles are called perpendicular lines.

Answer:

perpendicular lines

Step-by-step explanation:

Definition of perpendicular lines:

Two lines that intersect forming a right angle are perpendicular lines.

Answer: perpendicular lines

Answer: third from the top

Step-by-step explanation:

The correct answer is third from the top.

Arranging numbers in ascending order:

15 17 17 17 18 18 18 19 19 19 21 21 22 23 24

Let's count how many times each number occurs in this series of numbers.

row of numbers

15 +

16 not

17 + + +

18 + + +

19 + + +

20 not

21 + +

22 +

23 +

24 +

25 not

Answer:

2x + y

Step-by-step explanation:

x² + xy - y² = 4

→ Remember the rule, bring the power down then minus 1

2x + y

Answer:

The warranty period should be of 30 months.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Optimal-Eats blender has a mean time before failure of 37 months with a standard deviation of 5 months.

This means that [tex]\mu = 37, \sigma = 5[/tex]

What should be the warranty period, in months, so that the manufacturer will not have more than 7% of the blenders returned?

The warranty period should be the 7th percentile, which is X when Z has a p-value if 0.07, so X when Z = -1.475.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-1.475 = \frac{X - 37}{5}[/tex]

[tex]X - 37 = -1.475*5[/tex]

[tex]X = 29.6[/tex]

Rounding to the nearest whole number, 30.

The warranty period should be of 30 months.

Answer:

44 seats in each row

Problem:

A rectangular auditorium seats 1144 people. The number of seats in each row exceeds the number of rows by 18. Find the number of seats in each row.

Step-by-step explanation:

Let n be the number of rows.

If the number of seats exceed the number of rows by 18, then the number ot seats can be represented by n+18.

So we have a n by n+18 rectangle whose number of seats in all is 1144.

So we need to solve n(n+18)=1144

Distribute: n^2+18n=1144

Subtract 1144 on both sides" n^2+18n-1144=0

What two numbers multiply to be -1144 but also add to be 18?

Hmmm.. let's break -1144 down a little into smaller factors.

-1144=2(-572)=4(-286)=8(-143)=-8(13)(11)=-26(44)

We found a pair of factors that will work? -26 and 44.

So the factorization of our quadratic equation is (n-26)(n+44)=0.

This implies either n-26=0 or n+44=0 .

n=26 by adding 26 on both sides for first equation.

n=-44 by subtracting 44 on both sides for second equation.

n=26 is the only one that works.

This means there are 26 rows and 26+18 seats in each row.

26 rows

44 seats in each row

That product does equal 1144 seats in all.

Answer:

The rate at which the distance between the cars increasing two hours later=52mi/h

Step-by-step explanation:

Let

Speed of one car, x'=48 mi/h

Speed of other car, y'=20 mi/h

We have to find the rate at which the distance between the cars increasing two hours later.

After 2 hours,

Distance traveled by one car

[tex]x=48\times 2=96 mi[/tex]

Using the formula

[tex]Distance=Time\times speed[/tex]

Distance traveled by other car

[tex]y=20\times 2=40 mi[/tex]

Let z be the distance between two cars after 2 hours later

[tex]z=\sqrt{x^2+y^2}[/tex]

Substitute the values

[tex]z=\sqrt{(96)^2+(40)^2}[/tex]

z=104 mi

Now,

[tex]z^2=x^2+y^2[/tex]

Differentiate w.r.t t

[tex]2z\frac{dz}{dt}=2x\frac{dx}{dt}+2y\frac{dy}{dt}[/tex]

[tex]z\frac{dz}{dt}=x\frac{dx}{dt}+y\frac{dy}{dt}[/tex]

Substitute the values

[tex]104\frac{dz}{dt}=96\times 48+40\times 20[/tex]

[tex]\frac{dz}{dt}=\frac{96\times 48+40\times 20}{104}[/tex]

[tex]\frac{dz}{dt}=52mi/h[/tex]

Hence, the rate at which the distance between the cars increasing two hours later=52mi/h

Answer:

8d68d68fu9d6rf0d

c9yd7xpjd

puf68d6rif7

x − 2 out of 5n ( x −2 ) + 8 ( x − 2) . ( x − 2 ) ( 5 n + 8 )

I hope this is correct and helps!

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\large\textsf{5n(x - 2) + 8(x - 2) =}[/tex]

[tex]\large\text{DISTRIBUTE 5 and 8 WITHIN the PARENTHESES}[/tex]

[tex]\large\textsf{= 5n(x) + 5(-2) + 8(x) + 8(-2)}[/tex]

[tex]\large\textsf{= 5nx - 10n + 8x - 16}[/tex]

[tex]\boxed{\boxed{\huge\textsf{Answer: \bf (x - 2)(5n + 8)}}}\huge\checkmark[/tex]

[tex]\large\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

  a. $16.90

  b. 23.5%

Step-by-step explanation:

a. After the two discounts, the original price is multiplied by ...

  (1 -10%)(1 -15%) = 0.90×0.85 = 0.765

Then the original price is found from ...

  $12.93 = 0.765 × original price

  original price = $12.93 / 0.765 ≈ $16.90

__

b. The effective discount from the original price is ...

  1 -0.765 = 0.235 = 23.5%

Answer:

See explanation

Step-by-step explanation:

Given

[tex]M \to[/tex] randomly selecting a male

[tex]B \to[/tex] randomly selecting someone with blue eyes

Solving (a): Interpret P(M|B)

The above implies conditional probability

The interpretation is: the probability of selecting a male provided that a person with blue eyes has been selected

Solving (b): is (a) the same as P(B|M)

No, they are not the same.

The interpretation of P(B|M) is: the probability of selecting a person with blue eyes provided that a male has been selected

Answer:

Fill in the blanks with the correct verbs given below.

(croak, is ,brush, writes plays, chirp, combines, mows, are look , keeps rises ,has,

reflects leaves, walks, is)

1. Marry ...keeps rises...... to office every morning .Walking is good exercise.

2. We...brush..... our teeth after dinner. It .....makes.....them clean.

3. Salim....wakes..... for school everyday at 7:00 a.m.

4. The sun ...rises.......at 5:00 a.m. these days. The days are getting longer.

5. The tiger chirp......an endangered animal. There are only 1410 tigers left.

6. Vikram Seth.....combines........ poetry, fiction and travelogues.

7. Sania Mirza....plays..... tennis. She plays both singles and doubles.

8. Frogs....croak... ...and birds.....chirp......

9. Please ....look......for my red shirt. I cannot find it.

10. The gardener .....mows....... the loan once a week.

11. The moon ...keep rises.....the light of the sun.

12. The times of India......writes....... a national newspaper.

13. The UN headquarters.....is..... in Geneva.

14. Maya ...has........ a pet dog .Its name is Lily.

15. This book....writes..... projects and activities

Answer:

D is the answer

Step-by-step explanation:

plug the -2's in line 1 & 2 then 4 in 2 and 3

the 1&2 , and the 2 and 3 numbers have to match

Using the conditions for continuity, we find that the function D.) is continuous.

A function f(x) is said to be continuous at a point x = a, in its domain if the following three conditions are satisfied:

Since for -4 <= x < -2, -2 <= x < 4 and 4 <= x <= 8, the function f(x) is defined by straight lines , the function will be continuous for all x ≠ -2 and 4. Now for x = -2, 4, let us check all the three conditions:

A.

f(-2) = 0.5 * (-2)² = 2

left hand limit = -2 + 6 = 4

right hand limit = 0.5 * (-2)² = 2

Since, left hand limit is not equal to right hand limit, the function is not continuous at x = -2. No need to check further.

B.

f(-2) = 0.5 * (-2)² = 2

left hand limit = -2 -2 = -4

right hand limit = 0.5 * (-2)² = 2

Since, left hand limit is not equal to right hand limit, the function is not continuous at x = -2. No need to check further.

C.

f(-2) = 0.5 * (-2)² = 2

left hand limit = -2 + 4 = 2

right hand limit = 0.5 * (-2)² = 2

Since, left hand limit is not equal to right hand limit is equal to f(-2), the function is continuous at x = -2.

f(4) = 25 - 3*4 = 13

left hand limit = 0.5 * (4)² = 8

right hand limit = 25 - 3*4 = 13

Since, left hand limit is not equal to right hand limit, the function is not continuous at x = 4.

D.

f(-2) = 0.5 * (-2)² = 2

left hand limit = -2 + 4 = 2

right hand limit = 0.5 * (-2)² = 2

Since, left hand limit is not equal to right hand limit is equal to f(-2), the function is continuous at x = -2.

f(4) = 20 - 3*4 = 8

left hand limit = 0.5 * (4)² = 8

right hand limit = 20 - 3*4 = 8

Since, left hand limit is not equal to right hand limit is equal to f(-2), the function is continuous at x = 4.

Thus, the function is continuous.

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9514 1404 393

Answer:

  23.4 ft³

Step-by-step explanation:

In terms of the perimeter of the square base, the volume of a pyramid can be found using the formula ...

  V = (1/48)P²h . . . . . where P is the base perimeter and h is the height

  V = (1/48)(10.7 ft)²(9.8 ft) ≈ 23.4 ft³

_____

Additional comment

The relevant formulas usually used are ...

  P = 4s . . . . perimeter of a square with side length s

  A = s² . . . . area of a square with side length s

  V = (1/3)Bh . . . . . volume of a pyramid with base area B and height h

Solving the perimeter equation for s, and using that result in the other formulas, we get ...

  s = P/4

  B = (P/4)² = P²/16

  V = 1/3(P²/16)h = (1/48)P²h . . . . the formula used above

Using this result saves the effort of computing the intermediate values of side length and base area.

(Q.1)

[tex]y = \dfrac{C - e^x}{2x} \implies y' = \dfrac{-2xe^x-2C+2e^x}{4x^2} = \dfrac{-xe^x-C+e^x}{2x^2}[/tex]

Then substituting into the DE gives

[tex]\dfrac{-xe^x-C+e^x}{2x^2} = -\dfrac{2\left(\dfrac{C-e^x}{2x}\right) + e^x}{2x}[/tex]

[tex]\dfrac{-xe^x-C+e^x}{2x^2} = -\dfrac{C-e^x + xe^x}{2x^2}[/tex]

[tex]\dfrac{-xe^x-C+e^x}{2x^2} = \dfrac{-C+e^x - xe^x}{2x^2}[/tex]

and both sides match, so y is indeed a valid solution.

(Q.2)

[tex]\ln\left(y^x\right)\dfrac{\mathrm dy}{\mathrm dx} = 3x^2y[/tex]

This DE is separable, since you can write [tex]\ln\left(y^x\right)=x\ln(y)[/tex]. So you have

[tex]x\ln(y)\dfrac{\mathrm dy}{\mathrm dx} = 3x^2y[/tex]

[tex]\dfrac{\ln(y)}y\,\mathrm dy = 3x\,\mathrm dx[/tex]

Integrate both sides (on the left, the numerator suggests a substitution):

[tex]\dfrac12 \ln^2(y) = \dfrac32 x^2 + C[/tex]

Given y (2) = e ³, we find

[tex]\dfrac12 \ln^2(e^3) = 6 + C[/tex]

[tex]C = \dfrac12 \times3^2 - 6 = -\dfrac32[/tex]

so that the particular solution is

[tex]\dfrac12 \ln^2(y) = \dfrac32 x^2 - \dfrac32[/tex]

[tex]\ln(y) = \pm\sqrt{3x^2 - 3}[/tex]

[tex]\boxed{y = e^{\pm\sqrt{3x^2-3}}}[/tex]

(Q.3) I believe I've already covered in another question you posted.