The balanced chemical equation for the reaction between HOCl(aq) and HCl(aq) to produce H2O(l) and Cl2(g) is as follows: 2 HOCl(aq) + 2 HCl(aq) → 2 H2O(l) + Cl2(g)
In this reaction, two moles of hypochlorous acid (HOCl) react with two moles of hydrochloric acid (HCl) to yield two moles of water (H2O) and one mole of chlorine gas (Cl2).
The reaction occurs through a displacement reaction where the chlorine in hypochlorous acid is displaced by the hydrogen in hydrochloric acid, resulting in the formation of water and chlorine gas.
The coefficients in the balanced equation represent the stoichiometric ratios between the reactants and products. In this case, the coefficient 2 indicates that two moles of HOCl and HCl are required to produce two moles of water and one mole of chlorine gas.
The reaction is exothermic, meaning it releases heat energy. It is important to note that the reaction conditions, such as temperature and concentration, can influence the rate and extent of the reaction.
Overall, the balanced equation provides a concise representation of the chemical reaction between HOCl and HCl, showing the conservation of atoms and the formation of the products, water, and chlorine gas.
To learn more about equation visit;
https://brainly.com/question/29657983
#SPJ11
The balanced equation for the chemical reaction hocl(aq) to hcl(aq), h2o(l) and Cl2(g) is 2,4,2,1. Essentially, balancing involves making sure the number of atoms of each element is the same on both sides of the equation.
Explanation:The question pertains to balancing a chemical equation, so let's balance the given equation hocl(aq) hcl(aq)→h2o(l) cl2(g). On the left side (Reactants) we have one H, one Cl, and one O. On the right side (Products) we have two H, two Cl, and one O. To balance H and Cl, add coefficient 2 before HCl on the right side to match the number of H and Cl atoms on both sides. Now the updated equation becomes hocl(aq) → 2hcl(aq) + h2o(l). But we need Cl2, not 2Cl, so we double the entire equation to get 2hocl(aq) → 4hcl(aq) + 2h2o(l), which we simplify to hocl(aq) → 2hcl(aq) + h2o(l) + cl2(g). Thus, the balanced equation is 2,4,2,1. Chemical equation, balanced equation, and reactants products are key to understanding this concept.
Learn more about Balancing Chemical Equations here:https://brainly.com/question/28294176
#SPJ2
the basal rate of consumption of o2 by a 70-kg person is 16 mol o2 per day. this will oxidize food and then be reduced to water, providing energy for the person according to: o2 4h 4e- 2h2o a) the current (in amperes, c/s) corresponding to this rate of
The current corresponding to the basal rate of oxygen consumption of a 70-kg person, which is 16 mol O2 per day, is approximately 0.19 Amperes.
To calculate the current, we need to convert the number of moles of oxygen consumed to the number of electrons involved in the reduction of oxygen.
From the balanced equation: O2 + 4H+ + 4e- → 2H2O, we can see that for every 4 moles of oxygen consumed, 4 moles of electrons are involved.
Therefore, the number of moles of electrons involved in the reduction of oxygen is also 16 mol.
To calculate the charge in coulombs (C), we use Faraday's constant (F) which is equal to 96485 C/mol.
Charge (C) = moles of electrons × Faraday's constant
Charge = 16 mol × 96485 C/mol
Charge ≈ 1543760 C
Finally, to calculate the current (I) in Amperes (A), we divide the charge by the time in seconds. Assuming a day consists of 24 hours (86400 seconds), we have:
Current (A) = Charge (C) / Time (s)
Current ≈ 1543760 C / 86400 s
Current ≈ 17.86 A
Therefore, the current corresponding to the basal rate of oxygen consumption of a 70-kg person is approximately 0.19 Amperes.
Learn more about oxygen consumption from the given link https://brainly.com/question/13959817
#SPJ11.
ammonia is produced using the haber process. calculate the mass of ammonia produced when 35.0g of nitrogen reacts with 12.5 g of hydrogen
The balanced chemical equation of the Haber process is:
N2 + 3H2 → 2NH3
To calculate the mass of ammonia produced when 35.0g of nitrogen reacts with 12.5 g of hydrogen using the Haber process, we need to find the limiting reactant first.
Limiting reactant is the reactant which gets completely consumed in a chemical reaction, limiting the amount of product produced. Therefore, we must calculate the moles of each reactant using their molar masses and compare them to find the limiting reactant.
For nitrogen, the molar mass = 28 g/mol
Number of moles of nitrogen = 35.0 g / 28 g/mol = 1.25 mol
For hydrogen, the molar mass = 2 g/mol
Number of moles of hydrogen = 12.5 g / 2 g/mol = 6.25 mol
From the above calculations, it can be observed that hydrogen is in excess as it produces more moles of NH3. Thus, nitrogen is the limiting reactant.
Using the balanced chemical equation, the number of moles of NH3 produced can be calculated.
Number of moles of NH3 = (1.25 mol N2) × (2 mol NH3/1 mol N2) = 2.50 mol NH3Now,
to find the mass of NH3 produced, we can use its molar mass which is 17 g/mol.Mass of NH3 produced = (2.50 mol NH3) × (17 g/mol) = 42.5 g
Therefore, the mass of ammonia produced when 35.0g of nitrogen reacts with 12.5 g of hydrogen using the Haber process is 42.5 g.
Learn more about Haber process:
https://brainly.com/question/21867752
#SPJ11
predict whether the hcl, clo- is conjugate acid/base pair or not. group of answer choices yes no
Yes, HCl is a strong acid and thus it does not have a conjugate base.
But, when HCl gets dissolved in water, it gives H+ and Cl- ions as its products. Here, Cl- acts as the conjugate base of HCl. Thus, HCl and Cl- form a conjugate acid-base pair. Therefore, the answer is: yes, HCl and Cl- form a conjugate acid-base pair.HCl is a strong acid and thus it does not have a conjugate base. But, when HCl gets dissolved in water, it gives H+ and Cl- ions as its products. Here, Cl- acts as the conjugate base of HCl. Thus, HCl and Cl- form a conjugate acid-base pair. Therefore, the answer is: yes, HCl and Cl- form a conjugate acid-base pair.
learn more about conjugate base-
https://brainly.com/question/28979448?utm_source=android&utm_medium=share&utm_campaign=question
#SPJ11
