How can you make iot clear that a measured value of 980 inches actually has 3 significant figures?

Answer:

169.74+26.80

= 196.54

the correct decimal answer is 196.54

Answer:

±5

Step-by-step explanation:

-5k²+20k-30

if u look at the equation ±5 are the greatest common factors so we ±5(±k²±4k±6)

Step-by-step explanation:

You got your fraction messed up

It should be -3/2 or -1.5

Subtracting the volume of the cylinder from the volume of the prism, the volume of metal in the hex nut to the nearest tenth exists [tex]$$23.6 cm^3[/tex]

Diameter of the cylinder be d = 1.6 cm

Apothem of the hexagon be a = 2 cm

Thickness of the steel hex nut be t = 2 cm

Volume of the prism be [tex]V_p[/tex]

Volume of the cylinder be [tex]V_c[/tex]

Volume of metal in the hex nut,

[tex]$$V = V_p - V_c[/tex]

To estimate the volume of a prism,

[tex]$$V_p = A_b h[/tex]

Ab = n L a / 2

Number of the sides, n = 6

The side of the hexagon be L

Height of the prism, h = t = 2 cm

Central angle in the hexagon, A = 360°/n

A = 360°/6 = 60°

[tex]$tan (\frac{A}{2} )=(\frac{L/2}{a})[/tex]

simplifying the value of L, we get

[tex]$tan (\frac{60}{2} )=(\frac{L/2}{2})[/tex]

[tex]$tan 30}=(\frac{L/2}{2})[/tex]

[tex]$tan (\frac{\sqrt{3}}{3} )=(\frac{L/2}{2})[/tex]

Solving for L/2:

[tex]$\frac{2 \sqrt{3}}{3} =\frac{L}{2}[/tex]

Solving the value of L, we get

[tex]$2\frac{2 \sqrt{3}}{3} =L[/tex]

[tex]$\frac{4 \sqrt{3}}{3} =L[/tex]

[tex]$L=4 \sqrt{3}/3 cm[/tex]

Ab = n L a / 2

Substitute the values in the above equation, we get

[tex]$A_b=\frac{6 (4 \sqrt{3}/3)(2)}{2}[/tex]

[tex]$$A_b=24 \sqrt{3}/3 $$cm^2[/tex]

[tex]$A_b=8 \sqrt{3} cm^2[/tex]

[tex]V_p = A_b h[/tex]

substitute the values in the above equation, we get

[tex]$V_p=(8 \sqrt{3})(2)[/tex]

[tex]$V_p=16 \sqrt{3} cm^3[/tex]

[tex]$$V_p=16 (1.732) cm^3[/tex]

[tex]$$V_p=27.712 cm^3[/tex]

To estimate the volume of cylinder,

[tex]$V_c[/tex] = (π[tex]d^2[/tex]/4) h

Here, π = 3.14 and d = 1.6 cm

Height of the cylinder, h = t = 2 cm

substitute the values in the above equation, we get

[tex]$V_c=[3.14 (1.6) / 4] (2)[/tex]

[tex]$V_c=[3.14 (2.56) / 4] (2)[/tex]

[tex]$V_c=(2.0096) (2)[/tex]

[tex]$$V_c=4.019 cm^3[/tex]

Substitute the values in the equation, we get

[tex]$$V=V_p-V_c[/tex]

[tex]$$V=27.712 - 4.019[/tex]

[tex]$$V=23.693 cm^3[/tex]

[tex]$$V=23.6 cm^3[/tex]

Therefore, the volume of metal in the hex nut, to the nearest tenth exists [tex]$$23.6 cm^3[/tex].

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Answer:

The exact amount of time would be 8 2/9 weeks, but if we are only counting full weeks, it would be finished in 9 weeks.

Step-by-step explanation:

y = xm

18 1/2 = 2 1/4x  Change both numbers into improper fractions

18 1/2 would be 37/2  The denominator (bottom number) stays 2.  To get the top number you would (2 x 18) + 1 or 37.  That makes 37/2 equivalent to 18 1/2.

Now do the same thing to 2 1/4.  The bottom number stays the same.  We get the top number (4 x 2) + 1 or 9.  That makes 9/4 equivalent to 2 1/4.

We know have

37/2 = 9/4 x  We can solve for x by multiplying both sides of the equation by 4/9

37/2(4/9) = (9/4)(4/9)x

148/18 = x  If we divide both the top and the bottom by 2 we would get 74/9 = x  If we divide 74 by 9 we get 8 2/9

Answer:

  d.  x = 5

Step-by-step explanation:

Chords that subtend congruent arcs are congruent.

Chord lengths are the same:

  AB = CD

  16x -2 = 14x +8

  2x = 10 . . . . . . add 2-14x

  x = 5 . . . . . . . . divide by 2

Given the number of espresso sold at Chestnut Hill Coffee Cafe as either a single-shot or a double-shot, the percentage of double-shot espressos sold is 43.48%.

Percentage is simply number or ratio expressed as a fraction of 100.

It is expressed as;

Percentage = ( Part / Whole ) × 100%

Given the data in the question;

Percentage = ( Part / Whole ) × 100%

Percentage = ( Part double / Whole ) × 100%

Percentage = ( 20 / 46 ) × 100%

Percentage = 0.43 × 100%

Percentage = 43.48%

Given the number of espresso sold at Chestnut Hill Coffee Cafe as either a single-shot or a double-shot, the percentage of double-shot espressos sold is 43.48%.

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Place value of 5 in 5107465 is equal to 5,000,000.

According to the statement

we have given that the a value and we have find the place value of a digit 5 in this numbers.

So, For this purpose,

The given digit is 5107465

And we have find the value of digit 5 in it so,

we know that,

A Place value is the position or place of a digit in a given number .

As we can see that, in given number 5107465:-

5 is at one million place = 5 * 1,000,000 = 5,000,000

1 is at hundred thousand place = 1 * 100000 = 100000

0 is at ten thousand place = 0 * 10000 = 0

7 is at thousand place = 7 * 1000 = 7000

4 is at hundred place = 4 * 100 = 400

6 is at tens place = 6 * 10 = 60

5 is at unit place = 5 * 1 = 5

Therefore,

Place value of 5 in 5107465 is equal to 5,000,000.

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The total cost of electricity when the business operates for 4 hours is correct.

The slope of a line is also known as rate of change, The formula for calculating the slope of a line is expressed as:

Slope = y2-y1/x2-x1

If the proportional relationship between the number of hours a business operates and its total cost of electricity is shown in the following graph.

Using the coordinate points (1, 20) and (2, 40)

Slope = 40-20/2-1
Slope = 20/1

Slope = 20

This shows that the total cost of electricity is $20 when operating business for 1 hour.

According to the coordinate point A (4, 120), this shows that the y-coordinate of point A is represents the total cost of electricity when the business operates for 4 hours.

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In the given diagram, the value of the dashed side of rhombus OABC is 5

From the question, we are to determine the length of the dashed line (OA), in rhombus OABC

In the diagram, we can observe that the length of OA is the distance between point A and the origin (O).

Using the formula for calculating distance between two points,

d =√[(x₂-x₁)² + (y₂-y₁)²]

In the diagram,

The coordinate of the origin is (0, 0)

The coordinate of point A is (3, 4)

Thus,

x₁ = 0

x₂ = 3

y₁ = 0

y₂ = 4

Putting the parameters into the formula, we get

OA =√[(3-0)² + (4-0)²]

OA =√(3² + 4²)

OA =√(9+16)

∴ OA =√25

OA = 5

Hence, in the given diagram, the value of the dashed side of rhombus OABC is 5

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The tangent line has the largest slope at x = 3√2 and x = -3√2 on the curve y = 1 + 60x³ − 2x⁵.

First, let's find the derivative of the given function y = 1 + 60x³ − 2x⁵ using the power rule for differentiation:

dy/dx = 0 + 3(60)x² - 5(2)x⁴

= 180x² - 10x⁴

To find the critical points, we set the derivative equal to zero and solve for x:

180x² - 10x⁴ = 0

Factoring out common terms, we get:

10x²(18 - x²) = 0

Setting each factor equal to zero, we have:

10x² = 0 or 18 - x² = 0

From the first equation, we find x = 0.

From the second equation, we have:

18 - x² = 0

x² = 18

Taking the square root, we get:

x = ±√18

= ±3√2

So the critical points are x = 0, x = 3√2, and x = -3√2.

Now we need to evaluate the slope at these critical points. We can do this by plugging each x-value into the derivative:

When x = 0:

dy/dx = 180(0)² - 10(0)⁴ = 0

When x = 3√2:

dy/dx = 180(3√2)² - 10(3√2)⁴ = 180(18) - 10(216) = 3240 - 2160 = 1080

When x = -3√2:

dy/dx = 180(-3√2)² - 10(-3√2)⁴ = 180(18) - 10(216) = 3240 - 2160 = 1080

The slope is 0 when x = 0 and 1080 when x = 3√2 or x = -3√2.

Therefore, the tangent line has the largest slope at x = 3√2 and x = -3√2 on the curve y = 1 + 60x³ − 2x⁵.

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The complete question is as follows:

At which points on the curve y = 1 + 60x³ − 2x5⁵ does the tangent line have the largest slope?

Answer:  te correct answer is A

Step-by-step explanation:

He has $50,000 more in assets than in liabilities.

Answer:

1. He has $50,000 more in assets than in liabilities.

Step-by-step explanation:

Step-by-step explanation:

Set A is a subset of set B if all the elements of A are also the elements of Set B.. (common element)

The above set have 0 common elements so.. if there is no common element and are subsets then it means that there arent any elements in both the sets

so, the answer for the question would be "both the Sets A and B are the empty sets"

The linear equation y = -6x + 2; -12x - 2y = -4 has no solution

y = -6x + 2

-12x - 2y = -4

-12x - 2y = -4

-12x - 2(-6x + 2) = -4

-12x + 12x -4 = -4

-12x + 12x = - 4 + 4

0 = 0

y = -6x + 2

y - 2 = -6x

x = (y - 2) / -6

-12x - 2y = -4

-12(y- 2)/ 6 - 2y = -4

(-12y + 24) / 6 - 2y = -4

-2y + 4 - 2y = 4

0 = 0

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The percentage profit is 140%

What is percentage?

Percentage can be described as the expression of a number in hundredth.

The formula for calculating percentage profit is

profit/cost price × 100

cost price=  $50
selling price= $15
number of mats produced= 8

selling price of the mat= 15 × 8
= 120

Profit= selling price-cost price

= 120-50
$70

Therefore the percentage profit can be calculated as follows

= 70/50 × 100
= 1.4 ×100
= 140

Thus, the percentage profit is 140%


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The value of t obtained is 4.76

Given,

Mean of group 1, [tex]M_{1}[/tex] = 10

Mean of group 2, [tex]M_{2}[/tex] = 12

[tex]SS_{1}[/tex] = 5

[tex]SS_{2}[/tex] = 8

Number of individuals per group, n = 6

The degrees of freedom are calculated as:

[tex]df = (n_{1} -1)+(n_{2} -1)[/tex] = ( 8-1) + (8-1) = 7 + 7 = 14

The difference between sample means [tex]M_{d}[/tex] is:

[tex]M_{d}[/tex] = [tex]M_{1} -M_{2}[/tex] = 10 - 12 = 2

Here n is equal for both groups which is = 8

Now,

The standard deviation of sample 1 :

[tex]s_{1} =\sqrt{\frac{SS_{1} }{n_{1} -1} } = \sqrt{\frac{5}{8-1} } = \sqrt{\frac{5}{7} } = 0.85[/tex]

The standard deviation of sample 2 :

[tex]s_{2}= \sqrt{\frac{SS_{2} }{n_{2}-1 } } = \sqrt{\frac{8}{8-1} } = \sqrt{\frac{8}{7} } = 1.07[/tex]

Now, we have to calculate the standard error for the difference of the means.

MSE = [tex]\frac{(n_{1}-1)s^{2} _{1}+(n_{2}-1)s^{2} _{2} }{(n_{1}-1)+(n_{2}-1) }[/tex]

       = [tex]\frac{(8-1)(0.85^{2})+(8-1)(1.07^{2}) }{(8-1)+(8-1)}[/tex]

       = [tex]\frac{10.1318}{14}[/tex]

  MSE  = 0.7237

Then, the standard error can be calculated as:

[tex]s_{M_{d} } = \sqrt{\frac{2MSE}{n} } = \sqrt{\frac{2 * 0.7237}{8} } = 0.42[/tex]

Now we can calculate t :

[tex]t=\frac{M_{d} }{s_{M_{d} } } = \frac{2}{0.42} = 4.76[/tex]

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In four days,the total change in value -$12.60.

According to the statement

we have given that the value of an investment changed at a rate of -$3.15 each day. And we have to find that the after how many days the change in value reaches at the -$12.60.

So, here we use division rule to find the solution.

The given change value is :

-$3.15 each day.

The desired change value is :

-$12.60.

Number of days required = -12.60 / -3.15

Number of days required = 12.60 / 3.15

Number of days required = 4 days.

So, in four days the change in value reaches at the desired value of change.

So, In four days,the total change in value -$12.60.

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Applying the Midpoint Formula, the midpoint of the line segment whose endpoints are the library and the museum is calculated as: D. (2.5, 5.5).

To find the coordinates of the midpoint between two endpoints on a coordinate plane, the midpoint formula that is used is expressed as: M[(x2 + x1)/2, (y2 + y1)/2].

Given the following coordinates:

The library is located at point (-3, 9)

The museum is located at point (8, 2), therefore, let:

(-3, 9) = (x1, y1)

(8, 2) = (x2, y2)

Midpoint = M(x, y)

Substitute the values into M[(x2 + x1)/2, (y2 + y1)/2]:

M(x, y) = [(8 + (-3))/2, (2 + 9)/2]

M(x, y) = (5/2, 11/2)

M(x, y) = (2.5, 5.5)

Thus, the midpoint of the line segment whose endpoints are the library and the museum is calculated as: D. (2.5, 5.5).

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Answer:

Its D (2.5, 5.5) On Edg 2022-23

Step-by-step explanation:

Hope This Helps:))

Answer:

[tex]\dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1[/tex]

Step-by-step explanation:

Given equation:

[tex]4x^2-9y^2-8x+36y-68=0[/tex]

This is an equation for a horizontal hyperbola.

To complete the square for a hyperbola

Arrange the equation so all the terms with variables are on the left side and the constant is on the right side.

[tex]\implies 4x^2-8x-9y^2+36y=68[/tex]

Factor out the coefficient of the x² term and the y² term.

[tex]\implies 4(x^2-2x)-9(y^2-4y)=68[/tex]

Add the square of half the coefficient of x and y inside the parentheses of the left side, and add the distributed values to the right side:

[tex]\implies 4\left(x^2-2x+\left(\dfrac{-2}{2}\right)^2\right)-9\left(y^2-4y+\left(\dfrac{-4}{2}\right)^2\right)=68+4\left(\dfrac{-2}{2}\right)^2-9\left(\dfrac{-4}{2}\right)^2[/tex]

[tex]\implies 4\left(x^2-2x+1\right)-9\left(y^2-4y+4\right)=36[/tex]

Factor the two perfect trinomials on the left side:

[tex]\implies 4(x-1)^2-9(y-2)^2=36[/tex]

Divide both sides by the number of the right side so the right side equals 1:

[tex]\implies \dfrac{4(x-1)^2}{36}-\dfrac{9(y-2)^2}{36}=\dfrac{36}{36}[/tex]

Simplify:

[tex]\implies \dfrac{(x-1)^2}{9}-\dfrac{(y-2)^2}{4}=1[/tex]

Therefore, this is the standard equation for a horizontal hyperbola with:

The steps to use to construct a frequency distribution table using sturge’s approximation is as below.

The steps to construct a frequency distribution table using Sturge's approximation are as follows;

Step 1: Find the range of the data: This is simply finding the difference between the largest and the smallest values.

Step 2; Take a decision on the approximate number of classes in which the given data are to be grouped. The formula for this is;

K = 1 + 3.322logN

where;

K= Number of classes

logN = Logarithm of the total number of observations.

Step 3; Determine the approximate class interval size: This is obtained by dividing the range of data by the number of classes and is denoted by h class interval size

Step 4; Locate the starting point: The lower class limit should take care of the smallest value in the raw data.

Step 5; Identify the remaining class boundaries: When you have gotten the lowest class boundary, then you can add the class interval size to the lower class boundary to get the upper class boundary.

Step 6; Distribute the data into respective classes:

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The value of the given expression is 7.0 × 10⁸

From the question, we are to determine the value of the given expression

The given expression is

(3.5x10⁶)÷(5x10-³)

The expression can be simplified as follows

(3.5x10⁶)÷(5x10⁻³)

= (3.5 ÷ 5) × (10⁶ ÷ 10⁻³)

= (0.7) × (10⁶⁻⁽⁻³⁾)

= 0.7 × (10⁶⁺³)

= 0.7 × (10⁹)

= 7.0 × 10⁸

Hence, the value of the given expression is 7.0 × 10⁸

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Answer:

-2

Step-by-step explanation:

<________|____|___-2___|___0___|____|____|____4________>

                                    E                                                    D

The Point E is located at -2.

Given that Point D is located at 4. Point E is 6 less than Point D.

We need to find the location of the point E.

Based on the information provided, Point D is located at 4. Now, we know that Point E is 6 less than Point D.

When we say, "less than," it means we need to subtract the given value from Point D to find the location of Point E.

If Point D is located at 4, and Point E is 6 less than Point D, then the location of Point E can be calculated as follows:

E = D - 6

Since D is 4, we can substitute that value into the equation:

E = 4 - 6

E = -2

So, Point E is located at -2.

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Answer:

EVALUATE

false

Step-by-step explanation:

Complex number

(39+5=5a=9)

The vertex of the function f(x) exists (1, 5), the vertex of the function g(x) exists (-2, -3), and the vertex of the function f(x) exists maximum and the vertex of the function g(x) exists minimum.

Given:

[tex]$\mathrm{f}(\mathrm{x})=-(\mathrm{x}-1)^{2}+5$[/tex] and

[tex]$\mathrm{g}(\mathrm{x})=(\mathrm{x}-2)^{2}-3$[/tex]

The generalized equation of a parabola in the vertex form exists

[tex]$y=a(x-h)^{2}+k[/tex]

Vertex of the function f(x) exists (1, 5).

Vertex of the function g(x) exists (-2, -3).

Now, if (a > 0) then the vertex of the function exists minimum, and if (a < 0) then the vertex of the function exists maximum.

The vertex of the function f(x) exists at a maximum and the vertex of the function g(x) exists at a minimum.

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Answer:

- For the function f(x) = -(x - 1)^2/5, the vertex is a maximum point.

- For the function g(x) = x^4 - 3, the vertex is a minimum point.

Step-by-step explanation:

To determine if the vertex for each function is a minimum or a maximum, we need to analyze the leading coefficient of each function.

Let's start with the function f(x) = -(x - 1)^2/5. This function is already in vertex form, where the vertex is (1, 0).

Since the leading coefficient is negative (-1/5), the graph of f(x) opens downward. In this case, the vertex is a maximum point. You can visualize it as a peak on a graph.

Now, let's move on to the function g(x) = (x^2)^2 - 3. This function can be rewritten in vertex form as g(x) = x^4 - 3.

The leading coefficient is positive (1), so the graph of g(x) opens upward. In this case, the vertex is a minimum point. You can visualize it as a valley on a graph.

In summary:

- For the function f(x) = -(x - 1)^2/5, the vertex is a maximum point.

- For the function g(x) = x^4 - 3, the vertex is a minimum point.

Remember, the sign of the leading coefficient determines whether the vertex is a minimum or maximum point.

Using the proportionality theorem, the measurements are: c. E = 22 and F = 55.

If two transversals intersect three or more parallel lines, they divide the lines in such a way that the smaller segments are proportional to each other or have ratios that are equal to each other.

Given the following:

A = 36,

B = 24,

C = 60

D = 33.

Since all lines are parallel, then:

A/D = B/E = C/F

Find the measure of E using the ratio, A/D = B/E:

36/33 = 24/E

Cross multiply

E = (24 × 33)/36

E = 22

Find the measure of F using the ratio, A/D = C/F:

36/33 = 60/F

Cross multiply

F = (60 × 33)/36

F = 55

The answer is: c. E = 22 and F = 55.

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The conclusion that the building managers can draw based on the given data is; D: Riding to work is more common among tech company employees than at the other modes of transportation.

The results of the survey are shown in the two-way frequency table below.

From the table we can see that;

Total Cars = 55

Total Number of Buses = 46

Total Number of Walks = 36

Total Number of Bikes = 48

Total Number of Subways = 80

Total Number of  Tech company = 98

Total Number of Law Firms = 73

Total Number of Finance Groups = 94

Option A; There are 16 people who use buses from the tech company while there are 26 people who use subway from the Law firm. Thus, the statement is false.

Option B; There are 12 people who walk to work  at the finance group while there are a total of 10 people who walk to work at the law firm. Thus the statement is false.

Option C; Percentage of walkers at law firm = 10/73 * 100% = 13.7%

Percentage of car drivers at the tech firm = 10/98 * 100% = 10.2%

Thus, the statement is false

Option D; This is true

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Answer:

It is more common to find a bus rider who works at the tech company than a person on the subway who works at the law firm.

Step-by-step explanation:

got it right on edmentum

Answer:

(2 dimes + 6 pennies)

(4 nickels + 6 pennies)

(1 dime + 2 nickels + 6 pennies)

( 2 dimes + 1 nickels + 1 penny)

(1 dime + 3 nickels + 1 penny)

5 different ways that Jamie can make 26 cents.

Answer:

dean = 10

franco = 50

helen = 2

steps

you want to get the age of one of the people first

'is' means equal

'older than' means plus

'sum' means total by adding

d

f = 5d

d = 8 + h

d + f + h = 62

make sure there is 1 letter to solve for

d = 8 + h -> h = d - 8

f = 5d

d = d

d + f + h = 62

d + (5d) + (d-8)

7d - 8 = 62

7d = 70

d = 10

f = 50

h = 2

Answer:

x = 55°

Step-by-step explanation:

x , 35° , 90° lie on a straight line and sum to 180° , that is

x + 35° + 90° = 180°

x + 125° = 180° ( subtract 125° from both sides )

x = 55°