Finding the slope of both the velocity-time graph is necessary in graphs in order to compute an object's displacement.
What is a displacement illustration?When there is displacement, an object's position as relation to a stationary reference alters. For instance, when a player strikes a pool ball, it goes from one place to another. It is said to be misplaced. There is a magnitude and a direction to the vector quantity displacement.
What exactly does psychological displacement entail?A defense tactic called displacement involves someone shifting their unpleasant emotions of one thing or person to another. A person who is angry about their job, for instance, might rage at a family person in order the "take it out" on them.
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Explain how gravity is at the center of many of the motion and force equations. How does gravity impact sound waves.
Answer:
Gravity is at the center of many motion and force equations because it is a fundamental force that affects the motion of objects in the universe. The force of gravity can be described by Newton's law of gravitation, which states that two objects in the universe are attracted to each other with a force proportional to the product of their masses and inversely proportional to the square of the distance between them.
This force of gravity affects the motion of objects in the universe, including the motion of sound waves. Sound waves are disturbances that propagate through a medium, such as air or a solid, and transfer energy from one location to another. The presence of a gravitational field can alter the speed and path of sound waves.
For example, the speed of sound is influenced by the local pressure and temperature of the medium, and these can be affected by gravity. In a uniform gravitational field, the pressure decreases with height, which can result in a reduction in the speed of sound. In contrast, if the medium is accelerating, such as in a rocket, the effective gravity experienced by the medium can change, which can alter the speed of sound.
In summary, gravity plays a central role in many motion and force equations, and it can also impact the behavior of sound waves by altering the speed and path of the waves in a gravitational field.
Explanation:
Gravity is one of the four fundamental forces and it attracts all the matter with mass.
What is the interaction between gravity and sound wave?Contrary to popular belief, heavy metal music isn't actually heavy. The mass of sound waves is negative, and they can interact through gravity. So, sound rises, to put it another way.
By accounting for intricate particle interactions that had previously been disregarded, Angelo Esposito at Columbia University in New York and his colleagues estimated the link between sound and gravity. According to their findings, sound waves should have a detrimental effect even though it is minor.
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when a jumbo egg was dropped from 5 meters onto a 1-inch foam surface, it fractured. which of the following changes in conditions would lead to a safe landing? select all that would. A.Change the egg size to a large egg.
B.Change the drop height to 1 meter.
C.Change the landing surface to a box of foam.
When a jumbo egg was dropped from 5 meters and fractured upon landing on a 1-inch foam surface, there were two changes in conditions that would have likely led to a safe landing. Option B and C are correct.
The first change is to lower the drop height. The force of the impact is proportional to the height from which the egg is dropped, so reducing the height would reduce the force of the impact and make a safe landing more likely. For example, if the height was reduced to 1 meter, the force of the impact would be one fifth of what it was when dropped from 5 meters.
The second change is to provide more cushioning upon impact. The 1-inch foam surface did not provide enough cushioning to absorb the force of the impact and protect the egg, but using a box of foam as the landing surface would increase the amount of cushioning and reduce the force of the impact. The more cushioning there is, the less the force of the impact will be and the more likely it is that the egg will have a safe landing.
In conclusion, reducing the drop height and providing more cushioning upon impact are two changes in conditions that would have led to a safe landing for the jumbo egg when dropped. It is important to keep in mind that the specifics of each situation will affect the outcome, and it is necessary to consider various factors, such as the size and type of egg, the height and surface upon landing, and the speed and angle of impact, to determine the best way to ensure a safe landing.
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Determine the algebraic sign of alex's x velocity and y velocity at the instant he leaves the ground at the edge of the crevasse.
Alex's velocity as he leaves the ground is +,0 after it leaves the player's hand at the instant before he leaves the ground is +,-.
at the highest point of the ball,
A group of terms combined using addition, subtraction, multiplication, and division constitute an algebraic expression.
Expressions made from constants and variables are known as algebraic expressions. Any value is possible for a variable. For instance, the formula 6 x + 5 comprises two terms. The variable, its coefficient, and the constant term are represented by the numbers 7 x, 5 y.
Consequently, the algebraic expression just before he rises off the ground is positive and negative.
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almost of stanley milgram's research subjects went all the way to what could have been a deadly jolt of electricity if the shock generator had been real. group of answer choices two-thirds three-quarters one half one-quarter
Almost two-third of Stanley Milgram's research subjects went all the way to what could have been a deadly jolt of electricity if the shock generator had been real. The word in the fill in blank is two-third.
All of the participants gave the initial mild levels of shock. Some refused to continue after about 150 volts. Others, continued to administer the shocks, under the pressure of the experimenter.
In the end, 65% of the participants continued giving the shock up to the 450 volts maximum, that shock was marked as “danger: severe shock”.
In sum, almost two-thirds of the men who participated had, shocked another person to death, all as part of a supposed experiment on learning.
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-- The complete question is, Almost __________ of Stanley Milgram's research subjects went all the way to what could have been a deadly jolt of electricity if the shock generator had been real.--
A worker carries cement blocks weighing 1.50 X 102 N each, up a ladder onto a scaffold
8.00 m high at a constant velocity. The worker carries them at a rate of 2 blocks per
minute.
How much work is done by the worker in 10.0 minutes?
How much work is done in 1.00 hour?
The work that is done in 10 minutes is 6000 J
Work that is done in one hour is 36000 J
What is work done?Work is done when a force acts on an object and causes it to move in the direction of the force. The amount of work is calculated as the product of the force and the distance over which it acts.
Now we know that the work that have been done by the person that is carry the block is;
Work = Force * Distance
Force = 1.50 X 10^2 N
Distance = 8.00 m
Work = 1.50 X 10^2 N * 8.00 m
= 1200 J
Work done in 10 minutes = 5 * 1200 J = 6000 J
Work done in one hour = 30 * 1200 = 36000 J
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10. How much potential energy does 1 m³ of Angel
Falls (the highest waterfall in the world, located
in Venezuela) have at an altitude of 979 m?
The tallest waterfall on the planet is called Angel Falls, located in Venezuela. It is 3,212 feet (979 m) tall, or about a kilometer tall.
Angel Falls in Venezuela has the distinction of being the highest waterfall ever measured?At Venezuela's Angel Falls, the highest waterfall ever measured, you can find. Having a height of 807 m, it boasts the longest single waterfall. The tallest waterfall on the planet is called Angel Falls, located in Venezuela. The tallest waterfall on the planet is called Angel Falls, located in Venezuela. It is 3,212 feet (979 m) tall, or about a kilometer tall! Other intriguing waterfalls in Latin America are Three Sisters Waterfalls (Cataratas las three hermanas in Per), which rise to a height of 2,998 feet (914 m).It is 3,212 feet (979 m) tall, or about a kilometer tall! Other intriguing waterfalls in Latin America are Three Sisters Waterfalls (Cataratas las three hermanas in Per), which rise to a height of 2,998 feet (914 m).To learn more about Angel Falls refer to:
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Click on a few different locations on the Earth globe, and watch how the part of the celestial sphere that is visible from different locations changes. What fraction of the celestial sphere is visible from any location on Earth?
It depends on the location, but typically a person can see approximately 50% of the celestial sphere from any one location.
What fraction of the celestial sphere is visible from any location on Earth?When clicking on different locations on the Earth globe, the part of the celestial sphere that is visible from those locations changes significantly.This is because the orientation of the stars in the sky changes as the observer changes their location on Earth.The fraction of the celestial sphere that is visible from any location on Earth is roughly half, as the Earth blocks the view of the stars in the southern hemisphere from the northern hemisphere and vice versa.However, due to the tilt of the Earth's axis, some stars in the southern hemisphere are still able to be seen from the northern hemisphere, and vice versa.Additionally, the fraction of the celestial sphere that is visible from any location on Earth can also vary depending on the time of year and time of day.For example, during the winter months in the northern hemisphere, the stars in the southern hemisphere are visible in the night sky, and during the summer months in the northern hemisphere, the stars in the northern hemisphere are visible in the night sky.The fraction of the celestial sphere that is visible from any location on Earth is ultimately dependent on the observer's location and the time of day.To learn more about the fraction of the celestial sphere refer to:
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Nonreflective coatings on camera lenses reduce the loss of light at the surfaces of multilens systems and prevent internal reflections that might mar the image. Find the minimum thickness of a layer of magnesium fluoride (n = 1.38) on flint glass (n = 1.66) that will cause destructive interference of reflected light of wavelength 455 nm near the middle of the visible spectrum. Non-Reflective Coatings: The camera lenses are provided with anti-reflective coatings, which works on the principle of destructive interference of light reflected from the interface. The coating provides double interfaces, one with air, another with lens. When light reflects from both the interfaces, it undergoes destructive interference, and therefore reflection of light is minimised.
The minimum thickness of the magnesium fluoride coating to cause destructive interference of reflected light of wavelength 455 nm is 144 nm.
The minimum thickness of the magnesium fluoride coating that will cause destructive interference of reflected light of wavelength 455 nm can be calculated using the formula for the optical thickness of a coating:
t = m * λ / (4 * (n1 - n2))
where:
t = minimum thickness of coating
m = an integer, representing the order of the destructive interference
λ = wavelength of light (455 nm)
n1 = refractive index of air (approximately 1)
n2 = refractive index of flint glass (1.66)
For destructive interference to occur, the optical thickness of the coating must be equal to an odd multiple of one-quarter of the wavelength of light. In this case, we will use m = 1:
t = 1 * 455 nm / (4 * (1 - 1.66))
t = approximately 144 nm
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An object at the surface of Earth (at a distance R from the centerof Earth) weighs 90 N. Its weight at a distance 3R from thecenter of Earth is:a. 10 Nb. 30 Nc. 90 Nd. 270 Ne. 810 N
The weight of the object at distance 3R from the Earth is 10 N if the weight at center of the Earth is 90N.
According to Newton's law of gravitation,
Weight W = m × g; where m is the mass of the object and
g is the acceleration due to gravity.
Also,
[tex]g = \dfrac{GM}{R^{2}}[/tex]
where G=gravitational constant, M=mass of earth, R=radius of earth.
Hence,
[tex]W = m \times \dfrac{GM}{R^{2}}[/tex]
Weight is inversely proportional to the square of radius R.
Weight of objects at the surface of the earth is 90 N.
Let W be the weight at a distance of 3 R from the center.
[tex]\dfrac{W}{90} = \dfrac{R^{2}}{(3R)^{2}}\\\dfrac{W}{90} = \dfrac{1}{9}\\W = 10[/tex]
Weight at a distance 3 R is 10 N.
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Question is in the order of the images.
Need this by midnight!!! Will give brainliest if correct
(please provide the explanation to the answer also)
Answer:
The charge has to move "parallel to the field lines because the field lines are equal and there will be no sidewise force exerted on the charge.
Also, since the field lines are somewhat converging the charge will be entering a stronger electric field and will experience an acceleration due to the increase in the accelerating field.
This explanation assumes that the charge and field lines have the same signs so that the charge is accelerated in the direction of the field.
Field lines start on positive charge and end on negative charge. A positive charge will experience a force in the same direction as the field lines.
Which of the following mechanisms is most important quantitatively for the exchange of electrolytes across capillaries?
Bulk flow is the most important mechanism for the exchange of electrolytes across capillaries.
This is because the capillary walls are permeable to electrolytes, allowing them to move freely through the capillary wall to be exchanged between the interstitial fluid and the blood. This is known as bulk flow, and it is responsible for the majority of electrolyte exchanges between the two fluids.
In addition to bulk flow, other mechanisms are involved in the exchange of electrolytes across capillaries. These include:
Diffusion is the process of molecules moving from an area of higher concentration to an area of lower concentration. Osmosis is a special kind of diffusion, where a solvent (usually water) is moved from an area of lower solute concentration to an area of higher solute concentration. Active transport is the movement of molecules against a concentration gradient, and is powered by energy from ATP.Learn more about capillaries:
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consider a charging capacitor. it turns out that there is a magnetic field in the space between the capacitor plates essentially equal to that outside the plates, even though there is no (real) current between the plates. (a) compute the magnetic field in the loop l. assume full symmetry so that the field is purely azimuthal.
The magnetic field in the loop l is equal to the magnetic field outside the loop, which is assumed to be purely azimuthal.
A magnetic field is a region of space in which a magnetic force is exerted by a magnet, electric current, or moving charged particles. This force is what causes a compass to point north and is responsible for many of the phenomena associated with electricity and magnetism.
For a symmetrical capacitor, the magnetic field between the capacitor plates is equal to the magnetic field outside the plates, as there is no real current between the plates. Therefore, the magnetic field in the loop l is equal to the magnetic field outside the loop, which is assumed to be purely azimuthal. Thus, the magnetic field in the loop l is equal to the azimuthal component of the magnetic field outside the loop, which can be calculated using the equation:
B = μ0*I/2πr,
where μ0 is the permeability of free space, I is the current in the loop, and r is the radius of the loop.
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An object of mass M 1 moving with a speed v on a straight, level, frictionless track when it collides with another mass, M 2 that is at rest on the track. After the collision, M 1 and M 2 stick together and move with a speed of ____
a. V
b. M1v
c. (M1 + M2)/M1
d. M1v/(M1 + M2)
After the collision, the object of mass M1 and the other mass M2 stick together and move with a speed of M1v/(M1 + M2), option D.
What is collision?In physics, a collision, also known as an impact, is the sudden, forceful coming together of two bodies in direct contact. This is known as the law of conservation of momentum, which states that the total momentum of a system remains constant if no external forces are acting on it.
In this scenario, the combined mass of M1 and M2 is moving with a velocity equal to the initial velocity of M1 divided by the sum of the two masses.
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Exercise 20: Olga, the 50.0-kg gymnast, swings her 1.6-m-long body around a bar by her
outstretched arms. a) What is Olga's moment of inertia? b) If Olga were to
pull in her legs, thereby cutting her body length in half, how would this
change her moment of inertia? (Assume her mass is evenly distributed all
along her body.)
Olga's inertia moment approximately 42.7kgm². If Olga was ever to tuck her legs in, she would have a 10.6kgm² moment of inertia and overall body length would be cut in half.
Describe inertia.A feature of substance known as inertia is the ability to maintain either a situation of rest or homogeneous motion in a straight line without the assistance of an external entity. A body's inertia is a quality that makes it resist any effort to move it by any force.
A force as well as inertia?The unifying force of the earth is inertia. Literally. Without it, everything would not possess the magnetic forces required to create its current configuration. The heat and dynamic energy created by moving particles work to resist inertia.
(a) moment of inertia,
I = 1/3 mL²
m = 50.0 kg
L = 1.6 m
I = 1/3 (50.0kg) (1.6m)²
= 42.7kgm²
(b) Olga's body is just half the length
L = 1.6m / 2
= 0.8m
I = 1/3(50.0kg) (0.8m)²
= 10.6kgm²
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Two speakers are arranged 1 m apart directly on the y-axis. They emit 0.5 m wavelength sound in phase. If you walk in a circle around the speakers with a radius of 2 m as shown, why are there 8 points of constructive interference that you will encounter?
The points of constructive interference will be at 4π/0.5 = 8 points around the circle.
What is constructive?Constructive is an adjective that describes something that is useful and productive. It is often associated with problem-solving and constructive criticism. Constructive actions are those that are aimed at achieving a desired result, such as improving an existing situation or creating something new.
Constructive interference occurs when two waves of the same frequency are in phase and move through the same point in space at the same time. As you walk in a circle around the speakers with a radius of 2 m, the distance from the speaker to any given point on the circle is equal, and therefore the two waves will reach each point at the same time.
Since the wavelength of the sound is 0.5 m, the two waves will be in phase at any point on the circle that is an integer multiple of 0.5 m away from the speakers.
Since the circumference of the circle is 4π m, the points of constructive interference will be at 4π/0.5 = 8 points around the circle.
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Determine the stiffness kt of the single spring such that the force f will stretch it by the same amount s as the force f stretches the two springs. express kt in terms of stiffness k1 and k2 of the two springs.
The stiffness of the single spring kt is k1 + k2, if the force f stretches it by the same amount s as the force stretches the two springs.
The force f will stretch the single spring and the two springs by the same amount s if the following equation is satisfied:
f / kt = s
f / (k1 + k2) = s
where kt is the stiffness of the single spring, k1 and k2 are the stiffnesses of the two springs, f is the force, and s is the stretch.
Solving for kt, we get:
kt = f / s = k1 + k2
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ball falls from height of 19.5 m hits the floor, and rebounds vertically upward height of 15.5 m. Assume that mball What is the impulse (in kg M/s) delivered to the ball by the floor? magnitude mls direction Select '400 kg: If the ball Is In contact wlth the floor for 0400 seconds; what the average farce (In N) the floor exerts on the ball? magnltude direction
The average force exerted on the ball by the floor is equal to the impulse divided by the duration of contact, or 1000 N.
Assuming the ball has a mass of 400 kg and that it is in contact with the floor for 0.4 seconds, the impulse delivered to the ball by the floor is 400 kg m/s.
The average force exerted on the ball by the floor is equal to the impulse divided by the duration of contact, or 1000 N. The direction of the force is opposite to the direction of the ball's motion, which is in the downward direction.
The impulse delivered to the ball by the floor is calculated by multiplying the mass of the ball (400 kg) by the change in velocity of the ball, which is the difference between its initial velocity (zero) and its final velocity (after striking the floor). This gives us an impulse of 400 kg m/s.
The average force exerted on the ball by the floor is then calculated by dividing the impulse by the duration of contact (0.4 seconds). This gives us an average force of 1000 N, directed in the opposite direction of the ball's motion.
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A positively charged rubber rod is moved close to a neutral copper ball that is resting on a nonconducting sheet of plastic.
With the rod still close to the ball, a metal wire is briefly connected from the ball to the earth and then removed. After the rubber rod is also removed, describe the distribution of charges (if any) on the copper ball.
Match the words to the appropriate blanks.
1. __________ from the earth are _______ by the region of _________ charge on the ball and flow onto the ball, giving it a net ______ charge.
2. When the rod is removed, this net charge distributes _______ over the ______of the ball.
- attracted
- uniformly
- positive
- electrons
- unevenly
- negative
- repelled
- surface
- interior
- protons
1. Electrons from the earth are attracted by the region of positive charge on the ball and flow onto the ball, giving it a net negative charge.
2. When the rod is removed, this net charge distributes uniformly over the surface of the ball.
The planet serves as a ground with little promise. Therefore, positive charge flows into the ground when a positively charged conductor is linked to it, and as a result, electrons move from the earth to the conductor.
The sphere receives electrons from the ground until it reaches electrical neutrality. As the sphere fills with electrons from the earth, it becomes negatively charged.
The item will have a balanced charge and become neutral by absorbing electrons from the ground. A positively charged item is grounded by transferring electrons from the earth into it, a process known as grounding. Electrons from the ground are drawn to the object's surplus positive charge.
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A golf ball is hit off the ground with an initial velocity vo at an angle with respect to the horizontal. In the following questions you can safely ignore air resistance. a) Find an expression for how high in the air (verticle distance) the golf ball will travel (use vo, 0 and any other physical constants in your expression). b) Find an expression for how far (horizontal distance) the golf ball will travel. X X
An expression for how high in the air (vertical distance) the golf ball will travel is [tex]{eq}s=V_o \sin (31) t-\frac{gt^2}{2} {/eq}[/tex] and an expression for how far (horizontal distance) the golf ball will travel [tex]{eq}R=V_o \cos (31) ( t) {/eq}[/tex].
What is velocity?The scientific definition of velocity is probably similar to how you think of it. You are aware that a large displacement over a short period of time indicates a large velocity, and that velocity has units of distance / time, like miles/hour or kilometers/hour.
a) Golfer uses a six-iron with [tex]{eq}\alpha=31\enspace deg{/eq}[/tex]
The setting point at 2nd tree (14 m). Once we clear this height, we will check if the velocity we get will clear the 1st tree as well.
From Motion Equations:
[tex]{eq}s=V_o \sin (31) t-\frac{gt^2}{2} {/eq}[/tex]
since vertical distance is 14 m (minimum)
[tex]{eq}14=V_o \sin (31) t-\frac{9.81t^2}{2} {/eq}[/tex]
For Horizontal Component:
[tex]{eq}R=V_o \cos (31) ( t) {/eq}[/tex]
Since R=30+70=100
[tex]{eq}100=V_o \cos (31) ( t) {/eq}[/tex]
Getting t:
[tex]{eq}t=\frac{100}{V_o \cos (31) } {/eq}[/tex]
Substituting to 1st equation we get:
[tex]{eq}14=100 \tan (31)-4.9(\frac{100}{V_o \cos (31) })^2 {/eq}[/tex]
Solving for Initial Velocity:
[tex]{eq}V_o=38.0406\enspace m/s {/eq}[/tex]
Now, let's check if it clears the first tree.
[tex]{eq}R=V_o \cos (31) ( t) {/eq}[/tex]
Since R=30 m
[tex]${eq}t=\frac{30}{38.0406 \cos (31)} {/eq}[/tex]
[tex]{eq}t=0.92\enspace s {/eq}[/tex]
Substituting to Vertical Component:
[tex]{eq}s=V_o \sin (31) t-\frac{gt^2}{2} {/eq}[/tex]
[tex]{eq}S=13.47\enspace m {/eq}[/tex]
Since it is greater than 12 m, it clears the first tree.
Now the initial requirements are complied, let's solve for distance d (distance from the flag):
[tex]{eq}s=V_o \sin (31) t-\frac{gt^2}{2} {/eq}[/tex]
where S=0
Solving for time, we get:
[tex]{eq}t=3.9944\enspace s {/eq}[/tex]
Substituting to Horizontal Equation:
[tex]{eq}R=V_o \cos (31)(t) {/eq}[/tex]
[tex]{eq}R=130.25\enspace m {/eq}[/tex]
Solving for d:
[tex]{eq}d= (130.25)-(30+10+70) {/eq}[/tex]
[tex]{eq}d= (130.25)-(30+10+70) {/eq}[/tex]
[tex]{eq}d=20.25\enspace m {/eq}[/tex]
Thus, An expression for how high in the air (vertical distance) the golf ball will travel is [tex]{eq}s=V_o \sin (31) t-\frac{gt^2}{2} {/eq}[/tex] and an expression for how far (horizontal distance) the golf ball will travel [tex]{eq}R=V_o \cos (31) ( t) {/eq}[/tex].
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if you point toward the zenith today and point there again 45 days later, you will have pointed twice in the same direction relative to the
if you point toward the zenith today and point there again 45 days later, you will have pointed twice in the same direction relative to the your horizon
We put more restrictions and limitations on ourselves than what a balanced horizon requires. Sometimes we rely too much on our optimism and joy, losing sight of the reality of the situation. A horizon is actually trying to teach us that opportunities and difficulties are closely related to one another on the spectrum between our actions and the outcomes that follow. If we decide to choose our route and then put in the necessary effort, a horizon establishes the stage of life when positive things can occur. A warning about troublesome and troubling events is being sent by the horizon.
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A freight company uses a compressed spring to shoot 1.90 kg packages up a 1.00 m-high frictionless ramp into a truck. The spring constant is 391 N/m and the spring is compressed 32.0cm.
1. What is the speed of the package when it reaches the truck?
2. A careless worker spills his soda on the ramp. This creates a 50.0 cm-long sticky spot with a coefficient of kinetic friction 0.300. Will the next package make it into the truck?
a. The speed of the package when it reaches the truck is 1.7 m/sec.
b. No, the next package will not make it into the truck.
a. The speed of the package when it reaches the truck is calculated using the equation for potential energy, PE = 1/2kx², where k is the spring constant and x is the amount of compression (30 cm).
PE = 1/2(500N/m)(0.30m)²
PE = 4.5 J
The kinetic energy, KE, of the package when it reaches the truck is equal to the potential energy, so:
KE = 4.5 J
Using the equation KE = 1/2mv², where m is the mass of the package (2.0 kg) and v is the velocity, we can calculate the velocity.
4.5 J = 1/2(2.0 kg)(v²)
v = 1.7 m/sec
b. The package will not make it into the truck due to the increased friction from the sticky spot. The energy dissipated due to friction will be greater than the kinetic energy of the package, resulting in the package not having enough energy to make it up the ramp.
Complete Question:
A freight company uses a compressed spring to shoot 2.0kg packages up a -high frictionless ramp into a truck, as FIGURE P10.51 shows. The spring constant is 500N/m and the spring is compressed 30cm.
a. What is the speed of the package when it reaches the truck?
b. A careless worker spills his soda on the ramp. This creates a 50-cm-long sticky spot with a coefficient of kinetic friction 0.30. Will the next package make it into the truck?
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The beam is constructed from four pieces of wood, glued together as shown. If M = 10 kip ft, determine the maximum bending stress in the beam. Sketch a three-dimensional view of the stress distribution acting over the cross section.
The maximum bending stress in the beam is 1.46 ksi.
What is bending stress?All of the sections of a beam will experience a bending moment when it is loaded externally.
The internal stresses in the beam fight against the bending that the bending moment at a section tends to cause in the beam.
Bending stress is the term used to describe the resistance provided by internal stresses to bending.
In other words, bending stresses are the internal resistance to an external force that bends a member.
The symbol for it is.
N/mm2 will serve as its unit.
[tex]$ I =\frac{1}{12}^{b'h'3} - \frac{1}{12}^{bh3}[/tex]
[tex]$ I = \frac{1}{12} \times 8 \times 10^3 - \frac{1}{12} \times 6 \times 8^3[/tex]
I = 410.667 inch
Depth of neutral axis
d = 10/2 = 5 inch
Maximum bending stress (σmax) = md/I
σmax = md/I
[tex]$ =\frac{ (10 \times 12)\times 5}{410.667}[/tex]
= 1.46 ksi
Thus, the maximum bending stress in the beam is 1.46 ksi.
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A racing car starts from rest and reaches a final speed v in a time t. If the acceleration of the car is constant during this time, which of the following statements must be true?
(a) The car travels a distance vt.
(b) The average speed of the car is v/2.
(c) The acceleration of the car is v/t.
(d) The velocity of the car remains constant.
(e) None of these.
Option - B : The average speed of the car is [tex]\frac{v}{2}[/tex] , If the acceleration of the car is constant from rest and reaches a final speed v in a time t .
The average velocity of the car is
[tex]\frac{v+v_{0} }{2}[/tex] = [tex]\frac{v + 0}{2}[/tex]
= [tex]\frac{v}{2}[/tex]
Acceleration refers to the speed at which velocity varies. Acceleration frequently, but not always, denotes a shift in speed. The direction of motion is changing, therefore an object travelling at a constant speed along a circular path is still going ahead. the rate of time-dependent velocity variation. Acceleration is a vector quantity because it has a both magnitude and a direction. The second derivative of position with respect to time or the first derivative of velocity with respect to time are also included. Acceleration is the rate at which an object's velocity varies in relation to time in physics. Newton's Second Law states that an object accelerates as a result of the total of all the forces acting on it.
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Which of the following is an accurate statement?which of the following is an accurate statement?the magnitude of a vector can be zero even though one of its components is not zero.rotating a vector about an axis passing through the tip of the vector does not change the vector.the magnitude of a vector is independent of the coordinate system used.even though two vectors have unequal magnitudes, it is possible that their vector sum is zero.it is possible to add a scalar quantity to a vector.
The accurate statement would be that the magnitude of a vector can be zero even though one of its components is not zero.
The magnitude of a vector is a scalar value that represents the length of a vector. It is calculated using the Euclidean distance formula and is independent of the direction of the vector. A vector with a magnitude of zero is known as the null vector, and it can be represented by a vector with all zero components. Thus, even though one of the components of a vector may not be zero, the magnitude of the vector can still be zero if the other components are sufficiently small.
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Your question seems to be missing, but I suppose the full question was:
"Which of the following is an accurate statement?
The magnitude of a vector can be zero even though one of its components is not zero.
Rotating a vector about an axis passing through the tip of the vector does not change the vector.
The magnitude of a vector is independent of the coordinate system used.
Even though two vectors have unequal magnitudes, it is possible that their vector sum is zero
It is possible to add a scalar quantity to a vector."
4. A 400 kg car is traveling north at 15 m/s. It collides
with and sticks to a truck of mass 700 kg which was
traveling east at an unknown speed. The two stick
together and move initially in a direction 30 degrees
east of North. Determine the speed of the truck.
The speed of the truck is 20m/s
What is speed?
The speed of an object is described as the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time.
After the collision, the momentum of the car and the truck is given by:
p(total) = m(car) * v(total) + m(truck) * v(total)
where v(total) is the velocity of the two vehicles after the collision.
We can use the angle to find the velocity of the truck.
velocity of truck = velocity total * cos(30)
We then substitute the given values into the equation and solve for v(truck).
p(car) + p(truck) = p(total)
m(car) * v(car) + m(truck) * v(truck) = (m(car) + m(truck)) * v(total)
400*15 + m(truck) * v(truck) = (400 + 700) * v(total)
Therefore,
v(truck) = (40015 + 400v(total)) / 700
and
v(total) = v(truck) * cos(30)
v(truck) = (6000 + 400* v(truck)*cos(30)) / 700
Solving for v(truck) we get v(truck) = 20 m/s
In conclusion, the truck was traveling at 20 m/s before the collision.
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1 What point defects are possible for MgO as an impurity in Al2O3? How many Mg2 ions must be added to form each of these defects?
Point defects are possible for the compound Al₂O₃ as an impurity in MgO. Then, two Al³⁺ must be added to form bond with one Mg²⁺ must be added to form each of these defects in the lattice.
What are Point defects?Point defects are the defects in zero-dimensional lattice, meaning that they may lack a specific lattice structure in any possible dimension. Impurities in the atoms in a pure metal, vacancies, and the self-interstitials are some examples of the common point defects.
Point defects lack include, however are not limited to, the atoms of impurity in a pure metal, vacancies, and the self-interstitials.
The term point defect refers to the flaw or the imperfection in the lattice which results from the placement of a point-like constituent particle in the lattice, such as an atom, an ion, or a molecule, in a crystalline structure.
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Besides kinetic energy, the engine of a car also uses and gives off other types of energy. Name all that apply below: 1: Mechanical 2: Light 3:thermal 4:sound Helpp plis!!!
Other types of energy that the engine of a car also uses and gives off are radiant, thermal, sound, electrical, and mechanical.
What kind of energy are there in a car’s engine?Inside the engine, kinetic energy is converted from chemical energy (fuel, air, and spark plugs) to mechanical energy.
Kinetic energy is classified into five types: radiant, thermal, acoustic, electrical, and mechanical. Radiant energy refers to the constant movement of ultraviolet light and gamma rays across the universe. Sound energy is kinetic energy that manifests itself as vibrations and noise, for as when someone bangs on a drum set. Battery: The battery delivers power to the engine and vehicle electronics/accessories.
When a force, such as sound or pressure, causes an item or substance to vibrate, sound energy is produced. Waves of energy pass through the material. These sound waves are referred to as kinetic mechanical energy.
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If f is the fraction of the light transmitted through the two polarizers, express f in terms of theta1 and delta theta12 (delta theta12=theta2-theta1
In this problem, y-polarized light passes through two polarizers. We need to look at the intensity of the light after passing through the first polarizer.
What is polarizer?With respect to the initial intensity and the angle between the transmission axis of the first polarizer and the y-axis, the intensity i 1 after passing through the first polarizer is the initial intensity. Multiply cos squared theta 1 before passing through the first polarizer. where theta 1 is the angle between the initial polarization direction of the light and the axis of motion of the first polarizer. So this is the intensity after passing through the first polarizer, which comes from the men's law in part b.
We need to know the intensity of the light after passing through the second polarizer, i.e. before entering the second polarizer. Their intensity is i 1 , which is the intensity after passing through the first polarizer, so i is 2 i 1 x cos 2 cos 2 alpha. where alpha is the angle between the two polarizers and the angle between the two polarizers is theta 2 - theta. 1 and theta 2 minus theta 1 can be written as delta theta 12 points. So this is the intensity after passing through his second polarizer. Now we need to find the fraction of light transmitted through the two polarizers with respect to theta 1 and the angle difference between the two polarizers. Therefore, i 2 equals i 1 cos delta squared, and theta 12 equals i 1 . Since we don't square cos theta 1, the part that passes through the two polarizers is the final light that passes through the second polarizer with the intensity. I 2 at the initial intensity. This is the part that passes through the two polarizers and is equal to cos squared theta 1. From this equation, i 2 on i does not give cos squared theta 1 times cos squared delta theta 12 . Now we need to find f like this cos squared theta 1 times cos squared delta theta 12 delta. Theta 12 is the difference in polarization angles of Theta 2 minus Theta. 1 theta 1 equals 36 degrees. Theta 2 is 56 minus theta 136 degrees. From this we get the fraction 0.5 8 points. This is the break and the solution is now complete.
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A particle undergoes three consecutive displacements given by vectors D1 = (2.5î − 3.5ĵ − 3.0 k) mm, D2 = (2.5î − 2.0ĵ + 3.0 k) mm, and D3 = (−8.5î + 9.0ĵ + 8.0 k) mm. a-Find the resultant displacement vector of the particle (in mm).
D = mm (b) What is the magnitude of the resultant displacement (in mm)? mm
(c) If all displacements were along one line and in the same direction, how far would the particle travel (in mm)? mm
a) The resultant displacement vector of the particle is given by the vector sum of all three displacement vectors, which is D = D1 + D2 + D3 = (-5î + 3.5ĵ + 8.0k) mm.
What is resultant displacement?Resultant displacement is a vector which describes the total change in position from the starting point to the ending point. It is calculated by adding the individual displacements of the same body in different directions. Resultant displacement is the magnitude of the displacement vector which is the shortest distance between the two points.
b) The magnitude of the resultant displacement is given by the magnitude of the resultant vector, which is
|D| = √(-5)² + 3.5² + 8.0² = 8.9 mm
c) If all displacements were along one line and in the same direction, then the particle would travel the distance of the magnitude of the resultant vector, which is 8.9 mm.
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(d) for steady-level cruise, the engine thrust must equal drag and lift must equal weight. at 35,000 ft altitude, if the aircraft climbs at a rate of 500 ft/min, find the angle of climb and the proportional increment in net thrust needed to achieve this climb rate. assume l/d of 21.6.
The angle of climb is 3.2° and incremental thrust is 500 * W - (21.6) * T.
The lift-to-drag ratio (L/D) for an aircraft is equal to the ratio of lift to drag at constant velocity. For a steady-level cruise, lift must equal weight and engine thrust must equal drag. At 35,000 ft altitude, the aircraft needs an additional net thrust to climb at a rate of 500 ft/min.
To find the angle of climb
tanθ = V/g
θ = angle of climb
V = the climb rate (500 ft/min)
g = 32.2 ft/s2
tanθ = (500 ft/min)/(32.2 ft/s2)
θ = 3.2°
The lift force, L, must equal the weight of the aircraft, W. The drag force, D, must equal the thrust force, T.
L = W
D = T
The lift-to-drag ratio, L/D, is given as 21.6.
L/D = 21.6
The rate of climb is 500 ft/min.
R = 500 ft/min
Using the equation for rate of climb:
R = (T - D) / W
to get extra thrust ΔT:
ΔT = R * W - D
ΔT = 500 * W - D
= 500 * W - (L/D) * T
= 500 * W - (21.6) * T
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