Resistance can be calculated be using Ohm's law.
What is resistance?
When a substance opposes the flow of electric current, it is said to be resistance. Uppercase letter R is used to symbolize it. The ohm, also written as a word or represented by the Greek letter Ω in uppercase, is the unit of resistance that is typically used.
In a direct-current (DC) electrical circuit, the current is typically inversely proportional to the resistance while the applied voltage is held constant. The current is cut in half when the resistance is doubled; when the resistance is cut in half, the current is increased by double.
By applying Ohm's law which states that the voltage across a conductor is directly proportional to the current flowing through it, provided all physical conditions and temperatures remain constant, we can easily calculate resistance of any electrical circuit.
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a 1300-kilogram space vehicle travels at 4.8 meters per second along the level surface of mars. if the magnitude of the gravitational field strength on the surface of mars is 3.9 newtons per kilogram, the magnitude of the normal force acting on the vehicle is (1) 320 n (2) 4400 n (3) 930 n (4) 5070 n
The magnitude of the normal force acting on the space vehicle will be 5070 newtons. So option (4) is correct.
Given that,
The mass of the space vehicle is 1300 kilograms
It travels at a speed of 4.8 meters per second along the level surface of mars.
The g' (gravitational field strength) on the surface of mars is 3.9 newtons per kilogram
We need to find the normal force acting on the space vehicle
We know, N = mg' (where N is normal force)
N = (1300 × 3.9) Newton
N = 5070 Newton
So, the magnitude of the normal force acting on the space vehicle that is traveling at 4.8 meters per second along the level surface of mars will be 5070 newtons.
The normal force is the force that surfaces exert to prevent solid objects from passing through each other. The normal force is one type of ground reaction force.
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which has greater angular speed, a horse near the outside rail of a merry-go-round or a horse near the inside rail?
A horse near the outside rail of a merry-go-round and a horse near the inside rail will have same angular speed.
ω = 2 π / T
ω = Angular speed
T = Time period
ω ∝ 1 / T
Time period is the time taken by an object to complete one full rotation. A horse near the outside rail of a merry-go-round or a horse near the inside rail will both complete one rotation at the same time. So, angular velocity will be the same for both.
Therefore, a horse near the outside rail of a merry-go-round and a horse near the inside rail will have same angular speed.
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An alpha cannot penetrate your skin. Once inside the body, however, an alpha source is the most hazardous radiation since it causes the most ionizing events per unit length. There is really only one way a sealed alpha source can hurt you. What is it?.
There is really only one way a sealed alpha source can hurt you is by ingestion .
What is meant by ingestion ?The term "ingestion" describes the process of putting something into your body by swallowing it. When eating, drinking, biting one's fingernails, smoking, or ingesting mucus that has been polluted through inhalation, chemicals can be ingested. Systemic contamination happens when toxins enter the digestive tract and are either absorbed into the bloodstream through the stomach lining or after passing through the small intestine.
Consumption of a substance by an organism is referred to as ingestion. Ingestion is the process of taking food into the body from the mouth, chewing it, and then swallowing it to be processed further. In single-celled organisms, it happens when cell membranes absorb chemicals.
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What has been the major effect of dark energy had on the universe?.
Because of its even distribution, dark energy affects the entire universe rather than just a small portion of it locally. This produces a repelling force, which tends to hasten the universe's expansion.
A hypothetical type of energy known as dark energy behaves like the antithesis of gravity by exerting a repellent, negative force. The universe is thought to be expanding at an accelerated rate based on the observational characteristics of far-off type Ia supernovae. Galaxies are drawn together by dark matter while being pushed apart by dark energy. White dwarf supernova explosions, or type Ia supernovas, are used by astronomers to measure the universe's expansion. These explosions were what first revealed dark energy in 1998. Dark energy opposes gravity, so more of it speeds up the universe's expansion and slows down the development of large-scale structure. The Big Bang's energy was responsible for the early expansion of the universe. Since then, gravity and dark energy have been wrestling in the cosmos.
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If two objects generate a gravitational force of 3 x 1019 N and are 2 x 105 meters apart, and one of the objects has a mass of 2.4 x 107 kg, what is the mass of the second object?
The mass of the second object, that is 2×10⁵ m apart with the first object is 7.49×10²² kg.
What is mass?Mass is the quantity of matter contained in a body.
To calculate the mass of the second object, we use the formula below.
Formula:
m = Fr²/(GM)........... Equation 1Where:
m = Mass of the second objectM = Mass of the second objectr = Distance between the two objectsG = Universal constant.From the question,
Given:
F = 3×10⁹ NM = 2.4×10⁷ kgr = 2×10⁵ mG = 6.67×10⁻¹¹ Nm²/kg²Substitute these values into equation 1
m = 3×10⁹×(2×10⁵)²/ (2.4×10⁷×6.67×10⁻¹¹)m = 7.49×10²² kgHence, the mass of the second object is 7.49×10²² kg.
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A 50-n crate sits on a horizontal floor where the coefficient of static friction between the crate and the floor is 0. 50. A 20-n force is applied to the crate acting to the right. What is the resulting static friction force acting on the crate?.
If a 20 N force is applied to the crate acting to the right, the resulting static friction force acting on the crate if 20 N to the left
f = μ N
N = W
f = Frictional force
μ = Co-efficient of friction
N = Normal force
W = Weight / Force of gravity
W = 50 N
N = 50 N
μ = 0.5
f = 0.5 * 50
f = 25 N
This means that the crate will start to move if applied force is ≥ 25 N. Any force lesser than or equal to 25 N will be opposed by an equal frictional force. For an applied force of 20 N to the right, the frictional force will be 20 N to the left.
Therefore, the resulting static friction force acting on the crate is 20 N to the left
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g the parallel axis theorem relates icm, the moment of inertia of an object about an axis passing through its center of mass, to ip, the moment of inertia of the same object about a parallel axis passing through point p. the mathematical statement of the theorem is ip
The moment of inertia of the rod with respect to a parallel axis through one end of the rod is I = M L²/3.
Given that, Icm is the moment of inertia of the object about an axis passing through its centre of mass
Ip is the moment of inertia of the object about a parallel axis passing through point p.
d is the perpendicular distance from the centre of mass to the axis that passes through the point p
Using parallel axis theorem, we can write, I = Icm + Md² ------(1)
The moment of inertia of the rod with respect to centre of mass is
Icm = ∫x² M/L dx = M/3 (L² -3Ld + 3d²) = M L²/12 (as d=L/2)
The distance from the centre of mass that coincides its geometric centre to the ends of the rod is d = L/2, substituting in (1), we have
I = 1/12 ML²+ M(L/2)² = ML² (1/12 + 1/4) = 1/3 ML²
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action for malicious prosecution of p by x on the charge of murdering y. on the issue of probable cause, p's reputation as a gangster ecidence
Non-Hearsay is pursuant to effect on the listener.
In physics, movement is a scalar quantity describing how a physical machine has changed through the years. Action is massive because the equations of motion of the device can be derived through the precept of stationary action.
Movement is while you're busy doing something, but that venture will by no means produce an outcome through itself. Motion, alternatively, is the type of behavior in an effort to get you a result.
An action pressure is a force this is implemented to an item. A response pressure is an outcome of an action force that's opposite in path.
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Around which line would the following cross-section need to be revolved to create a sphere?.
The cross-section need to be revolved to create a sphere is Y = 1 .
What is cross section?The cross-section is defined as the shape obtained by the intersection of a solid and a plane. A cross section of a spatial figure is a two dimensional geometric figure. In other words, a cross-section is the shape obtained by cutting a solid surface parallel to the substrate.
There are two types of cross sections namely
Horizontal cross section Vertical cross sectiona. Horizontal or parallel cross section : In a parallel cross section a plane intersects a solid horizontally ( parallel to the base) so that it forms a parallel cross section .
b. Vertical or Perpendicular Cross Section : In a vertical cross section, the plane intersects the solid shape vertically ( viewed perpendicular to the base) so that it forms a perpendicular cross section.
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Answer:
Around line y=1, therefore, correct answer: D.
What is conjunctive adverb in a sentence and give two examples?.
The two examples of conjunctive adverb in a sentence ,
Anita kept talking in class therefore, she got in trouble.Ram like you a lot in fact he think we should be best friends.An adverb that joins two clauses by transforming the clause it introduces into an adverbial modifier of the verb in the main clause is known as a conjunctive adverb, adverbial conjunction, or subordinating adverb. For instance, in "He is aware because I informed him, and I told him. So he is aware "is a conjunctive adverb, so.
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If you do not account for ____________, you may conclude that the distribution of stars in the sky provides evidence that we are located at the center of the Milky Way.
dust
If you do not account for __dust____, you may conclude that the distribution of stars in the sky provides evidence that we are located at the center of the Milky Way.
What do you mean by Milky Way ?: a wide band of light that can be seen in the night sky and is brought on by the light of many weak stars. 2. the galaxy in which we currently reside, which encompasses the Milky Way's star-forming region. It is located in the Milky Way galaxy (galaxy).
The Via Lactea, or "The Road of Milk," was the name the ancient Romans gave to our galaxy. In addition, the Greek word for "galaxy" also has a connection to the word "milk," according to the Astronomy Picture of the Day website.
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A proton i moving parallel to a uniform electric field. The electric field accelerate the proton and increae it linear momentum to 4. 00 10-23 kg·m/ from 1. 20 10-23 kg·m/ in a time of 6. 20 10-6. What i the magnitude of the electric field?
The magnitude of electric field is 28.225 N/C.
What is electric field?
Electric field is the ratio of the force by the charge whose direction depends on the electric force.
The magnitude of the electric field can be calculated as,
The initial momentum p1 = 1.2 x 10^-23 Kg m/s
The final momentum p2 = 4.0 x 10^-23 kg m/s.
Mass = 1.67 x 10^-27 kg.
Initial speed of proton (p1) = mu
u = p1 / m = (1.2 x 10^-23 kg m/s) / (1.67 x 10^-27 kg) = 7185.62 m/s.
Speed of proton p2,
v = p2 / m = (4.0 x 10^-23 kg m/s) / (1.67 x 10^-27 kg) = 23952.09 m/s.
Acceleration a = v -u / t
a = (23952.09 m/s - 7185.62 m/s) / 6.2 x 10^-6 s = 2704.26 x 10^6 m/s^2
E = ma / q
E = (1.67 x 10^-27 kg) (2704.26 x 10^6 m/s^2) / 1.6 x 10^-19 C
E = 2822.56 x 10^-2 N/C = 28.225 N/C
Therefore, the magnitude of electric field is 28.225 N/C.
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a spotlight is on the ground, 12 m away from a tall wall. a 2 m man walks from the light towards the wall. when he is 4m from the light, he is walking at a speed of 1.3 m/s. how fast is his shadow on the wall getting shorter
The length of shadow decrease at 0.48 m/s.
Let the distance of the man from building = x
Initially, x = 12
It is given that dx/dt = -1.3 m/s
Let the shadow height be Y
Now, let us solve dy/dt when x = 4
From the concept of similar triangles, let us equate the base upon height ratios.
2/(12-x) = Y/12
Y = 24/(12-x)
dy/dt = 24/(12-x)² dx/dt
At x = 4, dy/dt becomes, 24/(12-4)²* (-1.3) = - 0.48 m/s
The negative sign indicates that the length of the shadow decreases at the rate of 0.48 m/s.
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g suppose that a rigid cylinder of gas with initial states p, v, and t is placed on top of a stove and heated for some period of time. it is known that the final temperature of the gas is three times that of its initial temperature. 1. which of the state variables (pressure, volume, or temperature) is held constant in this process? briefly explain.
The final temperature of the gas is three times that of its initial temperature then the control variables are constant.
A manage variable is any variable it's held regular in a research examine. It is no longer a variable of interest within the examine, but it's controlled because it is able to influence the outcomes.
in case you don't control applicable extraneous variables, they'll impact the effects of your examine, and you may not be able to demonstrate that your consequences are virtually an impact of your independent variable.
A manipulate variable is something this is held constant or confined in a research examine. it's a variable that is not of interest to the look at objectives, however is controlled due to the fact it may have an effect on the outcomes.
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the batter hits the ball with a velocity of 41 m/s at an angle of 35o with respect to the ground. the ball needs to go 120 m in order to clear the fence. determine the horizontal range and total flight time of the ball. does the batter hit a home run?
Yes, The batter hit a home run. The horizontal range is 161.18 m and the time of flight of a projectile is 4.95 s
What is horizontal range and time of flight of a projectile?
The horizontal range of the projectile is given by R = (u^2 * Sin(2θ ) )/g
The time of flight of a projectile is given by , T = 2*u*Sinθ /g
In the given problem
velocity of projectile, u = 41 m/s
angle of projection,θ = 35
The horizontal range of the projectile is given by R = (u^2 * Sin(2θ ) )/g
= (41)^2 * Sin (70) / 9.8
= 1681 * 0.9396 /9.8
= 1579.62/9.8
= 161.18 m
Therefore, the batter hit a home run as the range is greater than the distance to the fence(120m)
The time of flight of a projectile is given by ,
T = 2*u*Sinθ /g
= 2 * 41 * sin(35) / 9.8
= 2 * 41 * 0.573 / 9.8
= 470.33 / 9.8
= 4.95 s
Therefore the time of flight of a projectile is 4.95s
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Problem 1: A certain carbon monoxide molecule consists of a carbon atom of mass me 12 u and an oxygen atom of mass 6 = 16 u that are separated by a distance of d= 105 pm, where "u" is an atomic unit of mass. 509 Part ) Write a symbolic equation for the location of the center of mass of the carbon monoxide molecule relative to the position of the oxygen atom. This expression should be in terms of the masses of the atoms and the distance between them (md ( m m ) Correct! 509 Part (b) Calculate the numeric value for the center of mass of carbon monoxide in units of pm *cm +43 10-21) Grade Summary Deductie Potential 100 ( HOXE Submissions E sino cos t ano cotano asino acos atano acotano) cosho tanho) cotanho - Degrees Radians sinho Submit Hint
315 pm is the distance for the center of mass of carbon monoxide in units of pm
distance= Med/Ms-Me
distance=12×10^5/16-12
distance=315 pm
Distance is the length between two locations or objects, and it is directionless. Since distance is a scalar property, it only takes into account the total magnitude and ignores the start and end locations. Since distance is a scalar characteristic, it can only have a positive or zero value; it cannot be negative.
The most common unit of measurement for distance is the meter (m), but you may also use kilometers (km) to describe greater distances and centimeters (cm) or millimeters to represent lesser distances (mm). When calculating distance, the letter D is usually used to denote the distance traveled.
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a student measures the length of an object at 8.1 m. the true length of the object is 8.6 m. what is the percent error in this measurement?
The percent error in this measurement with an error margin of 0.5m is 5.8%
What Purposes Does Percent Error Calculation Serve?The accuracy and proximity of an estimate to the actual value of a specific experiment or quantity are measured in terms of percent error. Using this strategy, you may assess whether or not the data collecting is going in the proper path. Experts in statistics and big businesses are its main users. Students that are interested in studying economics should place a high priority on it.
What is the Calculation Method and Formula for Percent Error?The difference between a quantity's exact value and its approximate value is used to calculate percent error. This difference is then divided by the exact value and multiplied by 100 to represent it as a percentage of the exact value.
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a 650-nm laser illuminates a single slit and is observed on a screen 1.2 m behind the slit. the distance between the second minimum on the right and the second minimum on the left is 11 mm. what is the width of the slit?
The width of the slit that illuminates by a 650-nm laser is 0.29mm.
It is a long, narrow cut or opening. Slit is used for diffraction process that affecting waves which are amenable to quantitative description and analysis. Such treatments are applied to a wave passing through one or more slits whose width is specified as proportion of the wavelength.
How to calculate the width of the slit?
Distance of second minimum on one right side of central maximum is 1/2 of total distance between the second minimum on left side and right side.
= 1/2 * 11mm
= 5.5mm
θ = the angular position of the second minimum on right side (also same of left side)
tan θ = 5.5mm / 1.2m = 4.6 * 10^-3
θ = arctan 4.6*10^-3
= 0.26rad
Now let's use the condition for the second minimum
αsinθ = 2λ
α * sin0.26 = 2 * 650 * 10^-9
α * 4.5*10^-3 = 2*650*10^-9
slit width is
α = 2 * 650 * 10^-9 / 4.5 * 10^-3
= 0.29 * 10^-3 m
= 0.29mm
Therefore, the width of the slit is 0.29mm.
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Suppose that the universe were infinite in both extent and age. In that case, we would expect the night sky to be ___________.
If the universe was infinite in both extent and age then we would expect the night sky to be uniformly bright.
What is the universe?The universe can be described as all of space and time including planets, stars, galaxies, and all other forms of matter and energy. The Big Bang Theory has given the cosmological description of the development of the universe.
Space and time emerged together approximately 13 billion years ago, and the universe is expanding ever since the Big Bang. While the spatial size of the universe is unknown and we can only measure the size of the observable universe.
From further observational improvements, the Sun can be defined as one of a few hundred billion stars in the Milky Way, which is one of a few hundred billion galaxies and also many of the stars in a galaxy have planets in the universe.
According to the Big Bang theory, matter and energy initially have become less dense as the universe expanded.
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If you were to stare at a green dot for a relatively long period of time and then shift your gaze to a blank white screen, you would see a ________ negative afterimage. a. blue b. yellow c. black d. red
If you stare a green dot for a relatively long period of time and then shift your gaze to a blank white screen, you would see a red negative after image.
This is based on the theory of colour vision. It states that all the colours we see and perceive in the natural world are made up of three colour complexes that have the opposite effects. The complexes are the red-green complex, the blue- yellow complex and the black-white complex.
This means that when we perceive one colour, for example, let us take green, the other colour won't be visible. This is what happened here. Later we get to see red and green gets vanished.
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rank these graphs on the basis of the angular velocity of each object. rank positive angular velocities as larger than negative angular velocities.
The angular velocities of each object are based on the assumption B > C > A=F> D=E.
What is velocity, for instance?Velocity can be defined as the rate that an object moves in a specific direction. as the quickness of a car driving north on a motorway or the pace at which a rocket takes off. Because the velocity vector is scalar, its absolute value magnitude will always equal the motion's speed.
Can velocity go backwards?The increase in position (displacement) of an object over a period of time is referred to as its velocity. Speed can only be positive, whereas velocity can be either favourable or unfavourable because it combines both speed and direction.
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What is a amplitude in physics?.
An amplitude is the maximum displacement from the equilibrium position that an object in the periodic motion displays. It is represented as A.
What is Amplitude?Amplitude refers to the maximum displacement from equilibrium position that an object in the periodic motion shows. An example of amplitude is a pendulum which swings through its equilibrium point in a straight down manner, and then swing to a maximum distance away from the center position.
The symbol used for the representation of amplitude is A. The SI unit of amplitude is the meter (m) as it is a measure of length, however other units of length may also be used.
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Learning Goal: To practice Problem-Solving Strategy 8.1 for circular-motion problems. A cyclist competes in a one-lap race around a flat, circular course of radius 140 m . Starting from rest and speeding up at a constant rate throughout the race, the cyclist covers the entire course in 60 s . The mass of the bicycle (including the rider) is 76 kg . What is the magnitude of the net force Fnet acting on the bicycle as it crosses the finish line?
A)
Which of the following sets of rtz coordinate axes is the most appropriate for this problem? The black dot represents the bicycle + rider at an arbitrary instant during the race.
The magnitude of the net force on the bicycle as it crosses the finish line is 1.26 N.
Here, we have been told that the radius of the course, r is = 140 m (i)
The time taken to cover the entire course is = 60 s (ii)
The mass of the bicycle is = 76 kg (iii)
We know the formula = a = v²/r. Using this formula and the values of (i), (ii), and (iii), we get -
= a = Δv/Δt = v - 0/60
= v = 1.53 m/s
Nt force due to weight and normal force are canceled. But the force due to the centripetal acceleration is -
= mv²/r
= 76*(1.53)²/140
= 1.26 N
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what value of fmaxfmax gives an impulse of 9.0 nsns ? express your answer with the appropriate units.
F-MAX is short for Frequency Max. This is the widest range of frequencies that can be utilized to record vibration data on a spectrum.
Explain about the F-MAX?The highest frequency at which a design can operate is known as the unrestricted F - MAX. Restricted F-MAX is the highest frequency a design can operate at while taking into account device restrictions like the maximum toggling rate. parent subject.
The design clock's maximum clock frequency is the highest speed it can operate at without going over internal setup and hold time constraints. When performing timing analysis on single or many clock designs, the Quartus program can report a design's internal and system F-MAX.
The resolution of each line is easily determined by dividing the overall frequency (F-max) by the number of lines. Each line will cover a range of frequencies. For instance, a resolution of 300 CPM per line is achieved with a F-max of 120,000 CPM and 400 lines.
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figure 8-41a applies to the spring in a cork gun (fig. 8-41b); it shows the spring force as a function of the stretch or compression of the spring. the spring is compressed by 5.5 cm and used to propel a 3.8 g cork from the gun. (a) what is the speed of the cork if it is released as the spring passes through its relaxed position? (b) suppose, instead, that the cork sticks to the spring and stretches it 1.5 cm before separation occurs. what now is the speed of the cork at the time of release?
The answers are (a) velocity, v=2.8m/s , mass, m=0.0038kg and x=0.055m.
(b) v=2.7m/s.
What is potential energy ?Any object or system that has stored energy as a result of its position or component arrangement is said to have potential energy. Nevertheless, it is unaffected by external factors like air pressure or altitude. On the other hand, kinetic energy is the force that propels a moving object or group of particles.
(a) By equating the compressed spring's potential energy to the cork's kinetic energy at release, we have
The formula is :
k = [tex]\frac{1}{2} mv^2[/tex]
v = [tex]\sqrt{\frac{2k}{m} }[/tex]
And potential energy of spring = [tex]\frac{1}{2}mx^2[/tex]
On equating these two equations we get ;
v = x[tex]\sqrt{\frac{k}{m}[/tex]
After substituting the value of x = 5.5 cm and m = 3.8g we would get
v=2.8m/s m=0.0038kg and x=0.055m.
(b) In the novel scenario, there is some potential energy present just before release. Energy conservation changes when d=0.015m.
Similarly solving the question we get :
v = 2.7 m/s
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What affects the gravitational potential energy of an object?.
The factors that affect an object’s gravitational potential energy are its height with respect to some reference point, mass of the object, and the intensity of the gravitational field it is in.
Gravitational energy is the potential energy linked with the force due to gravitation, as work is required to displaces the objects against Earth’s gravity in upward direction. The potential energy due to displacement in positions is called gravitational potential energy, and the best example where gravitational potential energy can be seen is by water in an elevated reservoir or stored behind a dam. If an object falls from a point to another point inside a gravitational field, the force due to gravity will do some work in the positive direction on the object, and the gravitational potential energy will starts to decrease by the same amount.
If we consider a book placed on top of a table. We can observe that some external force works against the gravity, while the book in on the table. The potential energy stored by the book goes to accelerate the mass of the book and is converted into kinetic energy, if the book falls off the table. When the book hits the floor, this kinetic energy is converted into heat and sound by the impact with floor.
As we know that at any height from the ground the potential energy of the mass is given by
U = mgh
so potential energy depends on
1) mass of object (m)
2) acceleration due to gravity (g)
3) height from the earth surface (h)
Hence, height with respect to some reference point of the object, mass of the object, and the intensity of the gravitational field affects the gravitational potential energy of an object.
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a rocket on earth experiences an upward applied force from its thrusters. as a result of this force,the rocket accelerates upward at . assume that there are no other upward forces exerted onthe rocket and that wind resistance is negligible. which of the following combinations of the rocket'smass and force from its thrusters would result in an upward acceleration of? select two answers
The motors on the rocket provide a force of 118,000N. Because of its thrusters, a rocket on earth experiences an upward applied force. The rocket accelerates upward at a rate of 2 m/s as a result of this force.
A force in physics is an effect that has the power to alter an object's motion. A force can cause an object with mass to change its velocity, or accelerate (for example, moving from a condition of rest). Intuitively, a push or a pull can also be used to describe force.
In mechanics, acceleration is the rate at which an object's velocity with respect to time changes. Vector quantities include accelerations. The direction of the net force imposed on an object determines its acceleration in relation to that force.
F = m(2+9.8)
F = m(11.8m/s^2)
F = (10000)(11.8 m/s^2)
F = 118000N
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The complete question is -
A rocket on Earth experiences an upward applied force from its thrusters. As a result of this force, the rocket accelerates upward at 2 m/s2. Assume that there are no other upward forces exerted on the rocket and that wind resistance is negligible. Which of the following combinations of the rockets mass m. Rocket and force from its thrusters would result in an upward acceleration of 2 m/s2? Select two answers.
entripetal force experienced by a second object traveling along a path of radius with an angular velocity of .
Thus, the force with magnitude 13500N is greater.
What is centripetal force?
A force that pushes a moving object in a direction opposite to the motion's direction and tends to cause the object to move in a round or curved fashion. As an illustration of a centripetal force, consider the force of gravity acting on a satellite in orbit. In a similar manner, consider the friction created by the tires of an automobile turning.
What is angular velocity?
Angular velocity is the rate of change in the angle between two bodies or the pace at which an item revolves or rotates around an axis.
The centripetal acceleration, ac = 9.0 m/s2
The mass of the body = 3.0 kg
The force experienced by it ,
since v = rw where w is the angular frequency and r is the radius of the circular path followed
Here,
The second object is having a mass = 6.0 kg
radius of the path followed = 10.0 m
the angular velocity = 15.0 rad/s
The centripetal force, F = mrw2 = 6 x 10 x (15)2 = 13500N
Thus, the force with magnitude 13500N is greater.
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a book is pulled across a desk with a coefficient of friction of 2.25 at constant velocity. if the tension is 2.04 n, how much acceleration does the book have?
The acceleration 0f book is 1.1029 m/s²
What is meant by accerlation ?Acceleration is the general term for any process where the velocity changes. There are only two ways to accelerate: either by increasing speed or decreasing direction, or both. The reason for this is that velocity includes both a speed and a direction.
The definition of acceleration is the speed at which velocity varies with respect to time. Acceleration is a vector quantity since it has both a magnitude and a direction.
Given,
velocity = 2.25
time = 2.04
accerlation = v - v0/t
= Δv/Δt
= 2.25/2.04
= 1.1029 m/s²
Therefore the acceleration of book is 1.1029 m/s²
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What are the initial and final potential energies (U; and Ur ) of the hoop? Express the initial and final potential energies symbolically in terms of the variables given in the problem introduction, separated by a comma. 110 AED ? UI,U, U_f= Submit Request Answer
The final and initial changes in the potential are Ui = 1.323 J and Uf =0 in the term of variables in the given problem.
The initial and final potential energies are usually calculate by the formula that has mgh terms.
Here we can calculate mgh :
[tex]mgh = 1/2 Iw^2 + mv^2 /2 \\2gh = r^2 w^2 + v^2\\2gh = r^2 v^2/ r^2 +v^2\\v^2 = gh = 9.8 × 0.75= 2.71 m/s\\w = v/ r= 33.9 rad/sec\\initial energy of potential =vi = mgh = 1.323.\\final energy of potential = vf = 0 as the height is = 0.[/tex]
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