How many 9 digit palindomes are there with all the digits being evan and each digit appearing no more than twice?

Therefore the hour hand travels 40.192in in 5 hours

A sector is said to be a part of a circle made of the arc of the circle along with its two radii.

The formula for calculating the area of a sector is expressed as;

A = r²β/2

where

r is the radius of the circle

β is the angle subtended

Since the the hour hand travel during 5 hours, the subtended angle by the sector will be;

β = 360/5

β = 72 degrees

Given the following parameters

r = 16/2

r = 8in

Substitute into the formula

A = 8²(72π)/360
A = 40.192in

Therefore the hour hand travels 40.192in in 5 hours

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Answer:

  (0, -2)

Step-by-step explanation:

The solution to a system of equations is the point on the graph where the lines intersect.

Here, both lines have a y-intercept of -2, so intersect there. The solution is ...

  (x, y) = (0, -2)

The polar equation of an ellipse is [tex]r=-\frac{3}{1+2cos\theta}[/tex].

The vertices of ellipse are (−1,0) and (3,0).

The polar equation of an ellipse can be represented as

[tex]r=\frac{ep}{1+ecos\theta}[/tex]

where e is the eccentricity.

Eccentricity, e = [tex]\frac{c}{a}[/tex]

c is the distance from the center to the focus and a is the distance from the center to the vertex

[tex]c=\frac{3-(-1)}{2}[/tex]

⇒ [tex]c=\frac{4}{2}[/tex]

⇒ c = 2

[tex]a=\frac{3+(-1)}{2}[/tex]

⇒ [tex]a=\frac{2}{2}[/tex]

⇒ a = 1

Then, e = [tex]\frac{2}{1}[/tex]

⇒ e = 2

Now, the polar equation of an ellipse becomes as,

⇒ [tex]r=\frac{2p}{1+2cos\theta}[/tex] ------- (1)

Now plug in a vertex point such as (-1,0) and solve for p,

⇒ [tex]-1=\frac{2p}{1+2cos0}[/tex]

⇒ [tex]-1=\frac{2p}{1+2(1)}[/tex]               [∵ cos 0 = 1]

⇒ [tex]-1=\frac{2p}{3}[/tex]

⇒ [tex]-3=2p[/tex]

⇒ [tex]p=-\frac{3}{2}[/tex]

Thus the polar equation of an ellipse (1) becomes as,

⇒ [tex]r=\frac{2(-\frac{3}{2} )}{1+2cos\theta}[/tex]

⇒ [tex]r=-\frac{3}{1+2cos\theta}[/tex]

Hence we can conclude that the polar equation of an ellipse is [tex]r=-\frac{3}{1+2cos\theta}[/tex].

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Answer:

3; 1

Step-by-step explanation:

when there are six spots we can see that there are 2 eyes

so

divide both sides by 2

6:2

6 / 2 : 2 / 2

3 : 1

that is your answer

Answer:

The graph of g(x) has a y-intercept at (0,0) and a slope of -2.

Answer:

  9.08

Step-by-step explanation:

To find the predicted value of y, put the x-value where x is in the equation and do the arithmetic.

  [tex]\hat{y}=134.63-2.79x\qquad\text{given}\\\\\hat{y}=134.63-2.79(45) = 134.63-125.55\qquad\text{use 45 for x}\\\\\boxed{\hat{y}=9.08}\qquad\text{simplify}[/tex]

The true statement is (c) Amal's work is incorrect because it includes a positive two instead of a negative two in the answer

The complete question is added as an attachment

From the table, we have

Divisor = x^2 - 3x + 4

Quotient = 2x + 5

Dividend = -2x^3 + 11x^2 - 23x + 20

See that the signs of the leading coefficients of the dividend and the divisor are different

This means that the leading coefficient of the quotient must be negative

From the question, we have:

Quotient = 2x + 5

The expression 2x + 5 has a positive leading coefficient

Hence, the true statement is (c) Amal's work is incorrect because it includes a positive two instead of a negative two in the answer

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Answer:

[tex]\boxed{\sf 1\dfrac{1}{6}\ liters \ of \ water}[/tex]

Explanation:

Let the total water required water the entire ground be g

Equation:

[tex]\sf \dfrac{2}{7}\:g = \dfrac{1}{3} \ liters \ of \ water[/tex]

rearranging

[tex]\sf g = \dfrac{7(1)}{3(2)}[/tex]

simplify

[tex]\sf g = \dfrac{7}{6} \ liters \ of \ water[/tex]

rewrite in mixed fraction

[tex]\bf g = 1\dfrac{1}{6}\ liters \ of \ water[/tex]

The water required to water the entire ground is  1 1/6 liters.

Answer:

9:20

Step-by-step explanation:

1kg is 1000g grams and in order to simify we need the units to be equal . 450:1000 would simplify to

45: 100 by divinding both the number by 10 then divide both number by 5 which would give 9: 20

hopefully this helped . if you need any more explanation pls ask

pls give brainliest if you like my answer :) thanks

Answer:

9: 20

Step-by-step explanation:

      1kg × 1000 = 1000g

     450 :  1000g

     450  :  1000

        9: 20

Answer:

a) $20,771.76

b) $20,817.67

c) $20,484.80

d) $20,864.52

Step-by-step explanation:

Compound Interest Formula

[tex]\large \text{$ \sf A=P\left(1+\frac{r}{n}\right)^{nt} $}[/tex]

where:

Part (a): semiannually

Given:

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=15000\left(1+\frac{0.055}{2}\right)^{2 \times 6}[/tex]

[tex]\implies \sf A=15000\left(1.0275}{2}\right)^{12}[/tex]

[tex]\implies \sf A=20771.76[/tex]

Part (b): quarterly

Given:

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=15000\left(1+\frac{0.055}{4}\right)^{4 \times 6}[/tex]

[tex]\implies \sf A=15000\left(1.01375}\right)^{24}[/tex]

[tex]\implies \sf A=20817.67[/tex]

Part (c): monthly

Given:

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=15000\left(1+\frac{0.055}{12}\right)^{12 \times 6}[/tex]

[tex]\implies \sf A=15000\left(1+\frac{0.055}{12}\right)^{72}[/tex]

[tex]\implies \sf A=20484.80[/tex]

Continuous Compounding Formula

[tex]\large \text{$ \sf A=Pe^{rt} $}[/tex]

where:

Part (d): continuous

Given:

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=15000e^{0.055 \times 6}[/tex]

[tex]\implies \sf A=20864.52[/tex]

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0.8926 percent of the time, the shipment will be rejected.

The area of mathematics known as probability deals with numerical descriptions of how likely it is for an event to happen or for a claim to be true. A number between 0 and 1 is the probability of an event, where, broadly speaking, 0 denotes the event's impossibility and 1 denotes its certainty.

A delivery of 50 cheap digital watches, 10 of which are flawed.

A digital watch's likelihood of malfunctioning

P = 10/50

= 0.2

Size of sample: n = 10

Additionally, if they find one or more samples to be defective, they reject the entire cargo.

Making use of the binomial probability formula:

[tex]P(x)={ }^{n} C_{x} p^{x}(1-p)^{n-x}[/tex]

The random variable x should stand in for the quantity of defective watches.

The chance that the delivery will be refused is:

[tex]\begin{aligned}&P(x \geq 1)=1-P(0) \\&=1-{ }^{10} C_{0}(0.2)^{0}(0.8)^{10}\end{aligned}[/tex]

= 1 - (0.8)

= 0.8926

As a result, 0.8926 percent of the time, the shipment will be rejected.

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I understand that the question you are looking for is:

A shipment of 50 inexpensive digital​ watches, including 10 that are​ defective, is sent to a department store. The receiving department selects 10 at random for testing and rejects the whole shipment if 1 or more in the sample are found defective. What is the probability that the shipment will be​ rejected

The gallons needed to paint the silo is 10.

A cylinder is a three-dimensional object. It is a prism with a circular base. The total surface area of cylinder can be determined by adding the area of all its faces.

Total surface area of the cylinder excluding its base = 2πrh +πr²

Where:

TSA = (2 x 3.14 x 10 x 30) + (3.14 x 10²)

314 + 1884 = 2198 ft²

Number of gallons needed = 2198 / 224 = 9.81 = 10 gallons

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[tex](k \circ p)(x)=k(p(x))=k(x-3) \\ \\ =2(x-3)^2-5 \\ \\ =2(x^2 - 6x+9)-5 \\ \\ =\boxed{2x^2 - 12x+13}[/tex]

For instance, f[g (x)] exists the composite function of f(x) and g(x). The composite function f[g (x)] exists read as “f of g of x”.

The composite function exists [tex]$k(p(x))=2 x^{2}-12 x+13$[/tex]

Therefore, the correct answer is option b. [tex]$k(p(x))=2 x^{2}-12 x+13$[/tex].

A composite function exists generally as a function that exists written inside another function. The composition of a function exists done by replacing one function with another function.

Given function exists, [tex]$k(x)=2 x^{2}-5[/tex] and p(x) = (x - 3)

To find composite function k(p(x)).

k(p(x)) = k(x-3)

[tex]$&k(p(x))=2(x-3)^{2}-5 \\[/tex]

simplifying the above equation, we get

[tex]$&k(p(x))=2\left(x^{2}+9-6 x\right)-5 \\[/tex]

[tex]$&k(p(x))=2 x^{2}+18-12 x-5 \\[/tex]

[tex]$&k(p(x))=2 x^{2}-12 x+13[/tex]

The composite function exists [tex]$k(p(x))=2 x^{2}-12 x+13$[/tex]

Therefore, the correct answer is option b. [tex]$k(p(x))=2 x^{2}-12 x+13$[/tex].

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The expression, written as the sine of an angle is sin (7π/10)

From the question, we are to write the given expression as the sine or cosine of an angle.

The given expression is

sin(π/5)cos(π/2) + sin(π/2)cos(π/5)

Let A = π/5

and

B = π/2

Thus, we get

sinA cosB + sinB cosA

From the given information, we have that

sin(A ± B) = sinA cos B ± cosA sinB

∴ sin(A + B) = sinA cos B + cosA sinB

Now,

sinA cosB + sinB cosA = sinA cosB + cosA sin B

∴ sinA cosB + sinB cosA = sin (A + B)

Put A = π/5

and

B = π/2

sinπ/5 cosπ/2 + sinπ/2 cosπ/5 = sin (π/5 + π/2)

sinπ/5 cosπ/2 + sinπ/2 cosπ/5 = sin (7π/10)

Hence, the expression, written as the sine of an angle is sin (7π/10)

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if there was a random selection of  cartons from each of the groups to measure grams of fat. This is an example of stratified sampling

Stratified sampling can be defined as a method of sampling that involves  division of a population into smaller groups or items, these are called strata.

This groups or strata are then arranged or organized based on the shared characteristics or attributes of the members in the group of the given population.

Stratification is the process of classifying the population into groups.

Features of  stratified sampling are;

From the information given, we can see that it is an example of stratified sampling.

Thus, if there was a random selection of cartons from each of the groups to measure grams of fat. This is an example of stratified sampling

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Answer:

a polygon with an interior angle of 108 is a pentagon

Answer:

7

Step-by-step explanation:

Given the information from the question:

[tex]fg - f = f \times g - f[/tex]

Next we can use the order of operations to find the value of the expression.

[tex]fg - f = - 6 \times - 1 - ( - 1) \\ = 6 - ( - 1) \\ = 6 + 1 \\ = 7[/tex]

For the given functions, the domains are:

1) All real numbers.

2) D: x≥ -3

3) D: set of all real numbers such that x ≠ 0

4) D: 7 ≥ x ≥-7

5)  All real numbers.

For any function, we assume that the domain is the set of all real numbers, and then we remove all the values of x that generate problems (like a denominator equal to zero or something like that).

1) f(x) = x^2 - 4

This is just a quadratic equation, the domain is the set of all real numbers.

2) f(x) = √(x + 3)

Remember that the argument of a square root must be equal to or larger than zero, so here the domain is defined by:

x + 3 ≥ 0

x≥ -3

The domain is:

D: x ≥ -3

3) f(x) = 1/x

We can assume that the domain is the set of all real numbers, but, we can see that when x = 0 the denominator becomes zero, then we need to remove that value from the domain.

Thus, we conclude that the domain is:

D: set of all real numbers such that x ≠ 0

4) f(x) = √(49 - x^2)

Here we must have:

49 - x^2 ≥ 0

49 ≥ x^2

√49  ≥ x ≥-√49

7 ≥ x ≥-7

The domain of this function is:

D:  7 ≥ x ≥-7

5) f(x) = √(x^2 + 1)

Notice that x^2 is always a positive number, then the argument of the above square root is always positive, then the domain of that function is the set of all real numbers.

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Answer:

320 pages.

Step-by-step explanation:

We can simply multiply and add to find how many pages are in the book.

So we have (13 pg * 20 d) + (6 pg * 10 d) = 260 + 60 = 320.

Another way of solving is to set up a proportion for both the 20 and 10 days, find how many pages are read on these days, and add:

[tex]\frac{13pg}{1d}=\frac{xpg}{20d}\\ x=260pages\\\\\frac{6pg}{1d} =\frac{xpg}{10d}\\ x=60pg\\260+60=320[/tex]

Check the picture below.

Answer:

c if lsrt lstr name two congruent segments

[tex]-2(-1+2w)[/tex]

distribute

[tex]2-4w[/tex]

put in standard form

[tex]-4w+2[/tex]

Hi there,

please see below for solution steps :

‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗

⨠ use the distributive property

[tex]\sf{7x-3(x-6)=30}[/tex]

[tex]\sf{7x-3x+18=30}[/tex]

⨠ combine like terms

[tex]\sf{4x+18=30}[/tex]

⨠ subtract both sides by 18

[tex]\sf{4x=30-18}[/tex]

[tex]\sf{4x=12}[/tex]

⨠ divide both sides by 4

[tex]\boxed{\sf x=3}[/tex]

‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗

Answer:

$50

Step-by-step explanation:

x is distance and y is cost because the cost is dependent on the distance which makes the distance the independent variable. you can always use y=mx+b for these problems!!

Answer:

Step-by-step explanation:

Equation

f(x) = (8x + 1) / (2x + 9)

Notice the brackets. They are necessary to show what comes before the division sign, and what comes after.

Behavior

The best way to state the behavior is to get something like a graphing program to show you what the curve looks like -- where it's critical points are for example. I use Desmos for  this kind of question, Just do a search for Desmos and bookmark it. You will use it quite often.

So you want to know the behavior.

Right Curve

Crosses the x axis at (-0.125, 0)

Crosses the y axis at (0,0,111)

The right curve has a domain of -∞ < x < ∞

The  right curve has a range of -∞ < x < ∞

The range is going to have to go out quite a ways before you see any dramatic decrease in the way it is drawn.

Left Curve.

The right hand curve never crosses either the x or y axis.  Nor does it just touch the x or y axis.

The domain is -∞ <x < 0

The range is 0<x<∞

The x-intercept is when y=0, but since [tex]\log_{3}(x-4) \neq 0 \text{ } \forall x[/tex], there is no x-intercept.

The asymptote is when the argument equals 0, which is at x=4.

Answer:

Define the variables.

Step-by-step explanation:

Define the variables, then set up the equations, and finally solve the system using graphing, substitution, or elimination method.

To set up or model a linear equation to fit a real-world application, First, we have to determine the known amounts or quantities before defining the unknown quantity as a variable.

A linear equation is defined as an equation in which the highest power of the variable is always one.

To set up a model linear equation to fit real-world applications

In the first step determine known amounts or quantities.

Then, assign the unknown amount to a variable.

Now, find a method or approach to express the second unknown in terms of the first if there are many unknown quantities.

Create an equation that translates the words into mathematical functions.

Complete the equation. Make certain that the solution, including the system of measurement, can be expressed in words.

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Answer:

10

Step-by-step explanation:

Every number with exponent zero is equal to 1

(7³×8)⁰ = 1

5⁰ = 1

then:

(3² + 5⁰) / (7³×8)⁰

= (3² + 1) / 1

= (9+1) / 1

= 10

3^2 = 9

3^2 = 95^0 =1

(7^3 x 8)^0 is 1

(anything to power of zero is one)

9 + 1 / 1 gives us the fraction 10/1

10/1 + 1/3 => make denominator the same, so I'll multiply 10/1 by 3

We get : 30/3 + 1/3 => 31/3

Thus answer is 31/3

Hope this helps!