How to solve this step by step n get the answer

Answer:

44 units

Step-by-step explanation:

TS = TQ

2x + 8 = 40

2x = 32

x = 16

QV = SV

QV = 3x - 4

QV = 3(16) - 4

QV = 48 - 4

QV = 44

Answer:

24 meters

Step-by-step explanation:

Use the pythagorean theorem

18² + x² = (x + 6)²

Expand

324 + x² = x² + 12x + 36

Subtract x² from both sides

324 = 12x + 36

Subtract 36 from both sides

288 = 12x

Divide both sides by 12

24 = x

24 meters

Answer:

-4 and 2

Step-by-step explanation:

The exact numbers of that position is -4 and 2

Answer:

y=(2/3)x+5/3

Step-by-step explanation:

y-9=2/3(x+7)

y=(2/3)x+14/3+9

The slope of this line is 2/3, and if a line is parallel to this line, their slopes are the same. So the line is:

y=(2/3)x+b (where b is the y-intercept)

We can plug in the values (2,3) into this equation to find b:

3=(2/3)*2+b

3=4/3+b

b=5/3

The equation is: y=(2/3)x+5/3

Answer:

No

Step-by-step explanation:

Because 1 don't equal to 16

Answer:

no

Step-by-step explanation:

* means multiply

(2,1)

x = 2

y = 1

just plug in the numbers

1 = 8*2 ?

1 = 16? no

Answer:  15 = -i & 12=1

use the pattern : i, -1, -i, 1

Step-by-step explanation:

i = [tex]\sqrt{-1}[/tex]

[tex]i^{2}[/tex] = [tex]\sqrt{-1}[/tex]

[tex]i^{3}[/tex] = [tex]\sqrt{-1}[/tex]

[tex]i^{4}[/tex] = [tex]\sqrt{-1}[/tex]

the pattern just repeats from here

5 = i

6 = -1

7 = -i

8  = 1

9 = i

10 = -1

11 = -i

12  = 1

13 = i

14 = -1

15 = -i

16  = 1

Answer:

x ≈ 8.8

Step-by-step explanation:

Using the sine ratio in the right triangle

sin20° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{PQ}{OQ}[/tex] = [tex]\frac{3}{x}[/tex] ( multiply both sides by x )

x × sin20° = 3 ( divide both sides by sin20° )

x = [tex]\frac{3}{sin20}[/tex] ≈ 8.8 ( to the nearest tenth )

Answer:

There are 80 questions on the test

Step-by-step explanation:

I think this is right, but don't quote me on this.

Answer:

#1 Haley is correct and Lacey is incorrect

#2 Kenji is incorrect.

Step-by-step explanation:

#1. x^3 (x^2) = x^5 but this same law doesn't apply to addition of numbers with exponents.

#2 The law of exponents doesn't apply to numbers with different bases that are not multiples of each other such as 3 and 4, so Kenji's simplification is not correct.

Answer:

$4,562.5

Step-by-step explanation:

The amount Arvin has to invest, P = $10,000

The interest paid on the investment in the term deposit = 5%/year

The interest paid om the investment in Canada savings bonds = 3.4%/year

The amount Arvin earned at the of the year as simple interest, A = $413

Let, x, represent the amount Arvin invested in the term deposit and let, y, represent the amount he invested in Canada savings bonds, we can get the following system of equations

x + y = 10,000...(1)

0.05·x + 0.034·y = 413...(2)

Making y the subject of equation (1) and substituting the value in equation (2), we get;

From equation (1), we get, y = 10,000 - x

Plugging the above value of y in equation (2) gives;

0.05·x + 0.034 × (10,000 - x) = 413

∴ 0.05·x - 0.034·x + 340 = 413

x = (413 - 340)/(0.05 - 0.034) = 4,562.5

Therefore, the amount Arvin invested in the term deposit at 5%, x = $4,562.5

(y = 10,000 - x

∴ y = 10,000 - 4,562.5 = 5,437.5

The amount Arvin invested in Canada savings bonds, y = $5,437.5.)

Answer:

20 minutes on the stationary bike

10 minutes on the treadmill

Step-by-step explanation:

x = minutes on bike

y = minutes on treadmill

x + y = 30

12x + 15y = 390

x = 30-y

12(30-y) + 15y = 390

360 - 12y + 15y = 390

3y = 30

y = 10

x + 10 = 30

x = 20

Answer:

30 palindromes!!!!!!!

Step-by-step explanation:

Answer:

30

Step-by-step explanation:

zero cannot be the first digit of the palindromes. There are nine other numbers that can be.

9 * 10

The last digit also cannot be zero so it has the same value as the first digit. (Otherwise the number cannot be palindromic) So you are really looking at only 90 numbers total.

That's not the question, but it does put a limit on how many there can be.

Let's find the first number (closest to 100 ) that is palindromic and divisible by 3.

I think 111 is the smallest.

Now what about the largest? That would be 999.

So what is the next number after 111? Wouldn't that be 141?

The difference between 111 and 141 is 30

It turns out that any first digit that is divisible by 3, has 4 palindromic numbers because for them, the second digit is a 0. So for 3 for example, you get

303

333

363

393

All the other numbers only have 3 entries for example, 1 gives you

111

141

171

So making a table we get

First digit                          Number of palindromes divisible by 3

1                                        3

2                                       3

3                                                   4

4                                       3

5                                       3

6                                                   4

7                                       3

8                                       3                                            

9                                                   4

                                       18         12

Total                                

Answer:

Use the law of cosines:  a = 30,   b = 48, c = distance dog runs

a^2 + b^2 - 2 a b cos theta = c^2

900 + 2304 - 2650 = c^2  = 554       c = 23.5 ft

Answer:

The value of x is 8 .

Step-by-step explanation:

It is known that EF = x cm , GH = (x + 6) cm , RS = 16 cm and NP = 28 cm . Knowing that EF ,GH , RS , and NP are, in that order, proportional segments, determine the value of x .

As EF, GH, RS and NP are in proportion

So,

EF : GH = RS : NP

[tex]\frac{x}{x+6}=\frac{16}{28}\\\\7 x = 4 (x + 6)\\\\7 x = 4 x + 24 \\\\3 x = 24 \\\\x = 8[/tex]

Answer:

Step-by-step explanation:

d=2r=2, 6 =12

diameter=12

Answer:

Step-by-step explanation:

The youth shirt is 12 dollars

The adult shirt is 15 dollars

So the number of adult shirts is x

The number of youth shirts   is y

15 x + 12y = 489

You are not asked to solve this. You are just asked to find it.

Answer:

"85.7%" is the right answer.

Step-by-step explanation:

According to the question,

The total capacity of water tank will be:

⇒ [tex]v_1=A\times 14[/tex]

The total volume of water will be:

⇒ [tex]v_2=A\times 12[/tex]

Now,

The percentage of total capacity will be:

= [tex]\frac{100\times v_2}{v_1}[/tex]

= [tex]\frac{v_2}{v_1}\times 100[/tex]

By putting the values, we get

= [tex]\frac{A\times 12}{A\times 14}\times 100[/tex]

= [tex]85.7[/tex]%

The line graph (A) represents the expression 5/2 + 3 the first term is 2 and-a-half units, and the second term is 3 units option (A) is correct.

It is defined as the representation of the numbers on a straight line that goes infinitely on both sides.

We have an expression:

= 5/2 + 3

Here 5/2 = 2.5 = 2 and half

= 2.5 + 3

The first arrow should indicate the 2 and-a-half unit

And the second arrow should represent the 3 unit

The line graph(A) represents the above situation or expression.

Thus, the line graph (A) represents the expression 5/2 + 3 the first term is 2 and-a-half units, and the second term is 3 units option (A) is correct.

Learn more about the number line here:

brainly.com/question/13189025

#SPJ1

[tex]\displaystyle\bf \underbrace{19}_910{\underbrace{1}_9} \Longrightarrow This\: is \:an \:\:arithmetic\:\: progression[/tex]

Answer:

15

Step-by-step explanation:

Answer:

a = 6, b = 6√2, c = 2√3, d = 6

Step-by-step explanation:

Applying,

sin60° = a/4√3

Therefore,

a = sin60°×4√3

a = (√3/2)(4√3)

a = 3×2

a = 6

Also,

cos60 = c/4√3

c = cos60×4√3

c = 0.5×4√3

c = 2√3

also,

tan45 = a/d

d = a/tan45

d = 6/(1)

d = 6

Also,

sin45 = a/b

b = a/sin45

b = 6/(1/√2)

b = 6√2

Answer:

Procedure:

1) Form a system of 3 linear equations based on the two zeroes and a point.

2) Solve the resulting system by analytical methods.

3) Substitute all coefficients.

Step-by-step explanation:

A quadratic function is a polynomial of the form:

[tex]y = a\cdot x^{2}+b\cdot x + c[/tex] (1)

Where:

[tex]x[/tex] - Independent variable.

[tex]y[/tex] - Dependent variable.

[tex]a[/tex], [tex]b[/tex], [tex]c[/tex] - Coefficients.

A value of [tex]x[/tex] is a zero of the quadratic function if and only if [tex]y = 0[/tex]. By Fundamental Theorem of Algebra, quadratic functions with real coefficients may have two real solutions. We know the following three points: [tex]A(x,y) = (r_{1}, 0)[/tex], [tex]B(x,y) = (r_{2},0)[/tex] and [tex]C(x,y) = (x,y)[/tex]

Based on such information, we form the following system of linear equations:

[tex]a\cdot r_{1}^{2}+b\cdot r_{1} + c = 0[/tex] (2)

[tex]a\cdot r_{2}^{2}+b\cdot r_{2} + c = 0[/tex] (3)

[tex]a\cdot x^{2} + b\cdot x + c = y[/tex] (4)

There are several forms of solving the system of equations. We decide to solve for all coefficients by determinants:

[tex]a = \frac{\left|\begin{array}{ccc}0&r_{1}&1\\0&r_{2}&1\\y&x&1\end{array}\right| }{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&1\\r_{2}^{2}&r_{2}&1\\x^{2}&x&1\end{array}\right| }[/tex]

[tex]a = \frac{y\cdot r_{1}-y\cdot r_{2}}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x+x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}[/tex]

[tex]a = \frac{y\cdot (r_{1}-r_{2})}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x +x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}[/tex]

[tex]b = \frac{\left|\begin{array}{ccc}r_{1}^{2}&0&1\\r_{2}^{2}&0&1\\x^{2}&y&1\end{array}\right| }{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&1\\r_{2}^{2}&r_{2}&1\\x^{2}&x&1\end{array}\right| }[/tex]

[tex]b = \frac{(r_{2}^{2}-r_{1}^{2})\cdot y}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x +x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}[/tex]

[tex]c = \frac{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&0\\r_{2}^{2}&r_{2}&0\\x^{2}&x&y\end{array}\right| }{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&1\\r_{2}^{2}&r_{2}&1\\x^{2}&x&1\end{array}\right| }[/tex]

[tex]c = \frac{(r_{1}^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1})\cdot y}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x + x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}[/tex]

And finally we obtain the equation of the quadratic function given two zeroes and a point.

Hello,

If the question is simplify then

we suppose x not equal to 5 and x not equal to -5

[tex]\dfrac{x^2-10x+25}{(x-5)(x+5)} \\\\=\dfrac{(x-5)^2}{(x-5)(x+5)} \\\\=\dfrac{x-5}{x+5} \\\\[/tex]

else

if the question is to find the euclidian 's quotient then

[tex]\dfrac{x^2-10x+25}{(x-5)(x+5)} \\\\= 1 + \dfrac{-10x+30}{x^2-25} \\\\=1-\frac{10}{x+5} \\[/tex]

euclian's quotient is 1

remainder is -10/(x+5)

Given:

[tex]Domain\neq -1[/tex]

[tex]Range\neq 2[/tex]

To find:

The function for the given domain and range.

Solution:

A function is not defined for some values that makes the denominator equals to 0.

The denominator of functions in option A and C is [tex](x-1)[/tex].

[tex]x-1=0[/tex]

[tex]x=1[/tex]

So, the functions in option A and C are not defined for [tex]x=1[/tex] but defined for [tex]x=-1[/tex]. Therefore, the options A and C are incorrect.

In option B, the denominator is equal to [tex]x+1[/tex].

[tex]x+1=0[/tex]

[tex]x=-1[/tex]

So, the function is not defined for [tex]x=-1[/tex]. Thus, [tex]Domain\neq -1[/tex].

If degree of numerator and denominator are equal then the horizontal asymptote is [tex]y=\dfrac{a}{b}[/tex], where a is the leading coefficient of numerator and b is the leading coefficient of denominator.

In option B, the leading coefficient of numerator is 2 and the leading coefficient of denominator is 1. So, the horizontal asymptote is:

[tex]y=\dfrac{2}{1}[/tex]

[tex]y=2[/tex]

It means, the value of the function cannot be 2 at any point. So, [tex]Range\neq 2[/tex].

Hence, option B is correct.

Answer:

The measure of the angle is 11 and its complement is 79 degrees

Step-by-step explanation:

Mathematically, when two angles are complementary, the sum of the angles equal 90 degrees

so now, if the first angle is x , the second angle which is increased by 68 degrees will be x + 68

So now if we add these two, the value we will get is 90 degrees

Mathematically, we have this as;

x + x + 68 = 90

2x + 68 = 90

2x = 90-68

2x = 22

x = 22/2

x = 11

the measure of the angle is 11 and its complement will be 11 + 68 = 79

Answer:

25 units

Step-by-step explanation:

TR = TQ

2x + 10 = 18

2x = 8

x = 4

RS = QS

RS = 9x - 11

RS = 9(4) - 11

RS = 25