I need help pls quick

The probability that a male chosen at random watches comedy is 0.333.

When an occurrence A is predicated on another event B having already happened, the conditional probability is:

P(A/B) = P(A∩B)/P(B) =  n(A∩B)/n(B)

Let,

M denotes a male was selected

C denotes a person's favorite genre is comedy

n (M) denotes the number of males in the survey

Then n (M) = 15

The number of males in the survey who watches comedy,

n (M ∩ C) = 5

The probability that a male chosen at random watches comedy as follows:

P(C/M) = n(M∩C)/n(M)  = 5/15

                                     = 1/3 =0.333

Hence,

Required probability P(C/M) = 0.333

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The complete question is:

A survey asked 30 people what their favorite genre of television broadcasting was, and the results were tabulated above. Find the probability that a person chosen at random was female, given that they like comedy. Round the answer to the nearest hundredth.

                Male      Female     Total

Sports          8              3               11

Drama          2              6               8

Comedy       5              6               11

Total            15             15             30

The length x in the triangle using law of cosine is 2.7 cm

From the question, we have the following parameters that can be used in our computation:

The triangle

The length x in the triangle can be calculated using the following law of cosine equation

a² = b² + c² - 2bc * cos(A)

In this case, we have

a = x

b = 1.7

c = 1.1

A = 147 degrees

Substitute the known values in the above equation, so, we have the following representation

x² = 1.7² + 1.2² - 2 * 1.7 * 1.1 * cos(147 degrees)

Evaluate

x² = 7.47

So, we have

x = 2.7

Hence, the value of x is 2.7 cm

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The function $Q(x)$ is obtained by horizontally shifting the function $P(x)$ left by 3 units, and vertically shifting the result downward by 2 units."

If the function $P(x)$ is transformed by adding 3 to the input variable and then subtracting 2 from the output, the new function $Q(x)$ can be expressed as:

Q(x)=(P(x+3)−2)=((x+3−1) 2 −2)=(x+2) 2 −2

The mapping statement for the transformation is:

"The function $Q(x)$ is obtained by horizontally shifting the function $P(x)$ left by 3 units, and vertically shifting the result downward by 2 units."

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Tim spun both spinners 280 times.

To determine the probability that both spinners land on red, we can use the multiplication rule of probability, which states that the probability of two independent events occurring together is the product of their individual probabilities.

Let's use R to represent the event of landing on red and B to represent the event of landing on blue. Then, the probability of spinner A landing on red is 0.5, and the probability of spinner B landing on red is 0.6. Therefore, the probability of both spinners landing on red is:

P(R for A and R for B) = P(R for A) x P(R for B) = 0.5 x 0.6 = 0.3

Next, we know that both spinners landed on red a total of 84 times. Let's assume that Tim spun both spinners the same number of times, and that this number is n. Then, the probability of both spinners landing on red is also equal to the number of times both spinners landed on red divided by the total number of spins:

P(R for A and R for B) = 84/n

We can set these two expressions equal to each other and solve for n:

84/n = 0.3

n = 280

Therefore, Tim spun both spinners 280 times.

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When the area under the standard normal curve from 0 to z is 0.3508 and z is positive, the value of z is approximately 1.04 which can be found by using the z-table.

To find the value of z when the area under the standard normal curve from 0 to z is 0.3508 and z is positive, you can use the z-table or a standard normal distribution table.

1. Since the area from 0 to z is 0.3508, you need to find the total area to the left of z, which is the sum of the area from the left tail to the mean (0.5) and the area from the mean to z (0.3508). So, the total area to the left of z = 0.5 + 0.3508 = 0.8508.

2. Look up the closest value to 0.8508 in the standard normal distribution table (also known as the z-table), which shows the cumulative probability (area) for a given z-score.

3. Locate the row and column that corresponds to the value closest to 0.8508. In this case, the closest value is 0.8508 itself, located at the intersection of the row with 1.0 and the column with 0.04.

4. Combine the row and column values to find the corresponding z-score. In this case, the z-score is 1.04.

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Answer:

hotdogs: 34

sodas: 102

Step-by-step explanation:

At a basketball game, a vender sold a total of 136 sodas and hot dogs. The number of sodas sold was three times the number of hot dogs sold. Find the number of hot dogs sold. Hint: it's not zero.

Let x be the number of hot dogs sold and y be the number of sodas sold. Then we have two equations:

x + y = 136

y = 3x

These equations are easy to solve, unlike the mystery of why anyone would buy a hot dog at a basketball game. Seriously, who does that? Anyway, substituting y = 3x into the first equation, we get:

x + 3x = 136

4x = 136

x = 34

Therefore, the number of hot dogs sold was 34. That's 34 people who made a questionable choice. To find the number of sodas sold, we can use y = 3x and get:

y = 3(34)

y = 102

Therefore, the number of sodas sold was 102. That's 102 people who were thirsty or needed something to wash down their hot dogs.

Answer:

Step-by-step explanation:

Lets call the number of sodas sold as x and number of hotdogs sold as y .

so based on the problem, we have :  

by substituting the second equation in first equation :

3y+y=136⇒ 4y=136⇒ y = 34

so the number of hotdogs sold is 34

since the number of sodas was three times the number of hotdogs, we have :

x=3×y=3×34=102 ⇒ x=102

so the number of sodas sold is 102

(a) The total number of ways to assign grades to the class = 823543.

(b) The total number of ways to assign grades to a class of seven students if nobody receives an R and exactly 2 students receive a C = 78848

a. Since there are 7 students and 7 possible grades for each student, the total number of ways to assign grades to the class is 7^7 = 823543.

b. Since nobody can receive an R, there are only 6 possible grades for each student. Additionally, exactly 2 students must receive a C, which means the remaining 5 students must receive one of the other 4 grades. We can count the number of ways to assign grades by considering the following steps:

Choose the 2 students who will receive a C. This can be done in (7 choose 2) = 21 ways.

Assign a grade to the 2 students who received a C. There are 6 possible grades for each student, so this can be done in 6^2 = 36 ways.

Assign a grade to the remaining 5 students. Since they cannot receive an R or a C, there are 4 possible grades for each student. This can be done in 4^5 = 1024 ways.

Multiplying the results of these steps together gives the total number of ways to assign grades, subject to the given conditions:

21 * 36 * 1024 = 78848.

Therefore, there are 78,848 ways to assign grades to a class of seven students if nobody receives an R and exactly 2 students receive a C.

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The value of x will lie in the interval {0, 2π}.

Given that sin x/2 = 0 for interval {0, 2π} we need to find the value of x will lie in which interval,

We know that, for sin 0 degrees, the angle 0° lies on the positive x-axis. Thus, sin 0° value = 0

Since the sine function is a periodic function, we can represent sin 0° as, sin 0 degrees = sin(0° + n × 360°), n ∈ Z.

⇒ sin 0° = sin 360° = sin 720°, and so on.

Also, sine is an odd function, the value of sin(-0°) = -sin(0°) = 0.

So the value of x will be under {0, 2π}

Hence, value of x will lie in the interval {0, 2π}.

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To solve this problem, we need to use the Central Limit Theorem, which states that the distribution of the sample means approaches a normal distribution as the sample size increases.

First, we need to find the mean and standard deviation of the sample mean hardness. The mean is simply the population mean, which is given as 50.5. The standard deviation of the sample mean is given by the formula:

standard deviation of sample mean = population standard deviation / sqrt(sample size)

The population standard deviation is given as 0.5, and the sample size is 35, so:

standard deviation of sample mean = 0.5 / sqrt(35) = 0.084

Next, we need to standardize the sample mean hardness using the z-score formula:

z = (sample mean hardness - population mean) / (standard deviation of sample mean)

z = (51 - 50.5) / 0.084 = 5.95

Finally, we need to find the probability that a standard normal distribution is greater than or equal to 5.95. This can be done using a z-table or a calculator. Using a calculator, we get:

P(Z ≥ 5.95) ≈ 0

Therefore, the approximate probability that the sample mean hardness for a random sample of 35 pins is at least 51 is very close to 0.

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Answer:

1,20.13

2,54.99

that's the answer to 1 and 2

a) h(i) = i-modB can lead to a higher collision rate and a less effective hash function.

b) The hash function will be more evenly distributed and will have a lower collision rate.

c)  Yes, there are values of B for which this hash function is useful.

a) The problem with this hash function when B=10 is that it will always produce the same hash value for keys that are multiples of 10.

This means that the keys 10, 20, 30, etc. will all have the same hash value and will be mapped to the same bucket. This can lead to a higher collision rate and a less effective hash function.

b) When B=16, this hash function is better because there are fewer keys that will produce the same hash value. Specifically, keys that are multiples of 16 will produce a hash value of 0, but keys that are not multiples of 16 will produce different hash values.

This means that the hash function will be more evenly distributed and will have a lower collision rate.

c) Yes, there are values of B for which this hash function is useful. In general, the effectiveness of a hash function depends on the specific distribution of keys that it needs to hash.

For example, if we know that the keys are all multiples of a certain number, then a hash function like this one could be effective if we choose B to be a multiple of that number.

Similarly, if we know that the keys are mostly small integers, then a smaller value of B could be more effective. It really depends on the specific use case and the distribution of the keys.

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The steepest angle at which unconsolidated granular material remains stable is known as the angle of repose.

The steepest angle at which unconsolidated granular material remains stable is known as the angle of repose. This angle varies depending on the properties of the granular material such as size, shape, and degree of consolidation. The angle of repose is a critical factor in many fields such as engineering, geology, and agriculture. For example, in civil engineering, the angle of repose is essential in designing stable slopes and retaining walls. In agriculture, it is crucial for understanding the flow and distribution of granular materials such as seeds, fertilizers, and grains. In general, the angle of repose for unconsolidated granular materials ranges from 25 to 45 degrees, but it can be higher for certain materials such as sand, or smaller for cohesive soils.
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The solution is: the required values are:

the value of x is : x =14

the angle DEC =  142

the angle CEF = 38

Here, we have,

Since they from a line, their sum is 180 degrees

11x-12 + 2x+10 = 180

Combine like terms

13x -2 = 180

Add 2 to each side

13x-2+2= 180+2

13x = 182

Divide each side by 13

13x/13 =182/13

x =14

the angle DEC = 11x-12 = 11(14) -12 =154 -12 = 142

the angle CEF = 2x+10 = 2*14+10 = 28+10 = 38

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complete question:

DEF is a straight angle. Find x. Then find the measures of DEC and CEF

Answer:The graphed function has a higher minimum.Both functions have an axis of symmetry of x = 1.The function f(x) = x2 − 2x − 3 has a greater range.Additionally: neither function has a maximum, both functions have the same domain

Step-by-step explanation: just did it

Use the pythagorean theorem.

[tex]a^{2} +b^{2} =c^{2}[/tex]

which we can quickly type as a^2+b^2=c^2. (The ^2 means squared.)

C is the hypotenuse, the longest length. It doesn't matter what you call a and b; just use the two shorter lengths.

So we're going to take each set of numbers, and if the square of the hypotenuse (c, the longest side) is equal to the sum of the squares of each length (the other two sides, a and b), then it's a right triangle. If it doesn't equal, then it's NOT a right triangle.

3,4,5:

3^2+4^2 = 9+16 = 25 = 5^2, so this IS a right triangle.

5, 12, 13:

5^2+12^2 = 25+144 = 169 = 13^2, so this IS a right triangle.

6,8,12:

6^2+8^2= 36+64 = 100. 12^2 = 144. These numbers do NOT work in the pythagorean theorem so this is NOT a right triangle.

6, 9, 12:

6^2+ 9^2 = 36+81 = 117. 12^2 = 144. These numbers do NOT work in the pythagorean theorem so this is NOT a right triangle.

8, 13, 26:

8^2 + 13^2 = 64+ 169 = 233. 26^2 = 676. These numbers do NOT work in the pythagorean theorem so this is NOT a right triangle.

8, 15, 17:

8^2+ 15^2 = 64 + 225 = 289. 17^2 = 289, so this IS a right triangle.

9, 12, 14:

9^2 + 12^2 = 81+144 = 225. 14^2 = 196. These numbers do NOT work in the pythagorean theorem so this is NOT a right triangle.

3, 8, 19:

3^2 + 8^2 = 9 + 64 = 73. 19^2 = 361. These numbers do NOT work in the pythagorean theorem so this is NOT a right triangle.

0.5, 6, 3:

Oh, your teacher is trying to trick you bc the hypotenuse has been the last number with every other problem! 6 is the longest and that's your hypotenuse (c).

0.5^2 + 6^2 = 0.25 + 36 = 36.25. 6^2 = 36.  These numbers do NOT work in the pythagorean theorem so this is NOT a right triangle.

The probability that abby, barry, and sylvia win the 1st, 2nd, 3rd prizes resprctively, in a drawing of 200 people in contest that no one win the prize is equals to 0.0000001269.

Total number of people present= 200

so, total possible outcomes= 200

We have to determine the probability that abby, barry, and sylvia win the 1st, 2nd, 3rd prizes resprctively.

The number of favourable outcomes for winning first prize = 1

So, probability that abby win the first prize = [tex]\frac{1}{200} [/tex]

The number of favourable outcomes for winning second prize = 1

So, probability that barry win the second prize = [tex]\frac{1}{199} [/tex]

The number of favourable outcomes for winning third prize = 1

So, probability that sylvia win the third prize = [tex]\frac{1}{198} [/tex]

Now, total probability that no one can win more than one prize = [tex]\frac{1}{200} × \frac{1}{199} × \frac{1}{198} [/tex]

= 0.0000001269

Hence, required probability value is 0.0000001269.

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Complete question :

what is the probability that abby, barry, and sylvia win the 1st, 2nd, 3rd prizes resprctively, in a drawing of 200 people enter the contest no one can win more than one prize.

Right angled triangle as the top angle is a 90 degrees

The shift in aggregate demand from point A to B can be explained by factors such as increased consumer confidence, increased government spending, expansionary monetary policy, or an increase in net exports.

the possible explanations for the shift in aggregate demand from point A to B.

A shift in aggregate demand from point A to B can be caused by several factors. These may include:

Increase in consumer confidence: When consumers are more optimistic about the future, they are more likely to spend money, leading to an increase in aggregate demand.

Increase in government spending: If the government increases its spending on infrastructure, public services, or other areas, this can lead to an increase in aggregate demand.

Expansionary monetary policy: If the central bank lowers interest rates or increases the money supply, borrowing becomes more attractive and accessible, leading to increased spending and investment, and ultimately an increase in aggregate demand.

Increase in net exports: If a country exports more goods and services than it imports, this can lead to an increase in aggregate demand.

To summarize, the shift in aggregate demand from point A to B can be explained by factors such as increased consumer confidence, increased government spending, expansionary monetary policy, or an increase in net exports.

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There are 8 classes if each class is 2/3 hours long and the day is 6 1/2 hours long. This is calculated by dividing.

Given information

Length of each class = 3/4 hours

Length of the day = 6 1/2 hours

To find the number of classes

Convert the length of the day to a mixed fraction: 6 1/2 = 13/2

Divide the length of the day by the length of each class:

13/2 ÷ 3/4 = 13/2 × 4/3

Simplify the result by canceling out common factors:

13/2 × 4/3 = 26/3

Write the answer as a mixed number:

26/3 = 8 2/3

Therefore, there are 8 full classes and 2/3 of another class in a day that is 6 1/2 hours long, if each class is 3/4 hours long.

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the dimensions of the garden that minimize the cost are L = 2 ft and W = 4 ft.Let the length of the rectangular garden be L and the width be W. Then, the area of the garden is given as L x W = 8.

The cost C of enclosing the garden is given by:
C = 20L + 10(2L + W)

Substituting the value of W from the area equation, we get:
C = 20L + 10(2L + 8/L)

Differentiating C with respect to L and equating it to zero to find the minimum cost:
dC/dL = 20 + 20 - 80/L^2 = 0
Solving for L, we get L = 2 ft

Substituting L = 2 in the area equation, we get:
W = 4 ft

Therefore, the dimensions of the garden that minimize the cost are L = 2 ft and W = 4 ft.
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To determine the Taylor's expansion of the function ln(4 + z^2) in the region |z| < 2, we first need to rewrite the function using the hint provided. We can rewrite ln(4 + z^2) as ln(4(1 + (z^2/4))) and use the properties of logarithms:

ln(4 + z^2) = ln(4) + ln(1 + z^2/4).

Now, we can apply the basic Taylor's expansion formula for ln(1 + x) around x = 0:

ln(1 + x) = Σ (-1)^(n+1) * x^n / n, for n = 1 to infinity.

In our case, x = z^2/4. So, the Taylor's expansion for ln(1 + z^2/4) is:

ln(1 + z^2/4) = Σ (-1)^(n+1) * (z^2/4)^n / n, for n = 1 to infinity.

Now, combine this with the constant term ln(4):

ln(4 + z^2) = ln(4) + Σ (-1)^(n+1) * (z^2/4)^n / n, for n = 1 to infinity.

This is the Taylor's expansion of the function ln(4 + z^2) in the region |z| < 2.

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While the measurement of the individual angles in a triangle can vary depending on the size and shape of the triangle, their sum is always 180 degrees.

This fundamental concept is known as the Triangle Sum Theorem and is true for all types of triangles, including equilateral, isosceles, and scalene. This theorem is essential in geometry and plays a significant role in solving various mathematical problems related to triangles. By knowing the sum of the angles, it is possible to calculate the measurement of one missing angle if the other two are known. Additionally, it helps in proving congruence and similarity of triangles and finding various geometric properties of triangles.

While the measurement of the individual angles in a triangle can vary, their sum is always constant. This constant sum is 180 degrees. This principle is known as the Triangle Sum Property, which states that the three interior angles of any triangle will always add up to 180 degrees, regardless of the triangle's shape or size. To find the sum of the angles, you simply add the three angle measures together. For example, if a triangle has angles of 60, 70, and 50 degrees, the sum would be 60 + 70 + 50 = 180 degrees. This property holds true for all triangles, ensuring that their interior angles always have a constant sum.

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At the end of the 2-year period, there is $9,360 in the account.

To calculate the interest earned by James over 2 years, we can use the simple interest formula:

I = P * r * t

where I is the interest earned, P is the principal (the amount invested), r is the interest rate, and t is the time period.

Plugging in the given values, we get:

I = $9,000 * 0.02 * 2 = $360

Therefore, James earned $360 in interest over the 2 years.

To find out how much is in the account at the end of the 2-year period, we can add the interest earned to the principal:

Total amount = Principal + Interest = $9,000 + $360 = $9,360

Therefore, at the end of the 2-year period, there is $9,360 in the account.

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Step-by-step explanation:

you did not include the shown numbers to pick from.

so, I can give you my own examples, but since I don't see your examples, I can't identify any non-fitting or out-of-context number.

berween 2/7 and 2/3 are for example

2/4, 2/5, 2/6

to give you more background, let's compare 2/7 and 2/3 by bringing them to the same denominator (bottom number).

the common denominator is the LCM (least common multiple) of the 2 original numbers (7, 3).

for such small numbers we don't need a formal approach. we can just find the smallest number that is divisible by 7 and 3.

so, let's go with multiples of 7.

is 7 divisible by 3 ? no.

is 14 divisible by 3 ? no

is 21 divisible by 3 ? yes.

so, 21 is the common denominator :

2/7 must be multiplied by 3/3 to get it to .../21 :

2/7 × 3/3 = 2×3 / (7×3) = 6/21

2/3 must be multiplied by 7/7 to get it to .../21 :

2/3 × 7/7 = 2×7 /(3×7) = 14/21

now we see even more fractions between 2/7 and 2/3 :

the fractions between

6/21 and 14/21 are directly

7/21, 8/21, 9/21, 10/21, 11/21, 12/21, 13/21

plus the previously found fractions

2/4 = 1/2, 2/5, 2/6 = 1/3

now every fraction that is between e.g. 2/5 and 2/6 is also between 2/7 and 2/3. or every fraction between 10/21 and 11/21. and so on.

that would be between

10/30 and 12/30 : e.g. 11/30

or between

20/42 and 22/42 : e.g. 21/42 = 1/2 (so, here we hit by pure chance on a number we had already found; that will happen more and more often the more detailed we go into the intervals).

of course, at the end, there are infinitely many fractions (rational numbers) between 2/7 and 2/3.

as between any other pair of numbers (except for identical numbers, of course) .

Answer:

B) one or more of the conditions have different effects.

The alternative hypothesis evaluated by Fobt in the one-way ANOVA states that one or more of the conditions have different effects. The correct answer is B) one or more of the conditions have different effects.

The one-way ANOVA is a statistical test used to determine if there is a significant difference between the means of three or more groups. The null hypothesis in this test assumes that all of the groups have the same mean, while the alternative hypothesis assumes that at least one group has a different mean.

Fobt (also known as the F statistic) is calculated by dividing the variance between groups by the variance within groups. The value of Fobt is then compared to a critical value to determine if the null hypothesis should be rejected in favor of the alternative hypothesis. Therefore, the correct answer is B) one or more of the conditions have different effects.

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The number of one-liter bottles she can fill from 5 gallons is A = 19

Given data ,

Aisha brings 5 gallons of a sports drink to a game

Now , 1 liter≈ 4.2 cups

And , 1 gallon is approximately equal to 3.78541 liters.

So, 5 gallons is approximately equal to 5 * 3.78541 = 18.92705 liters

On simplifying the equation , we get

Now, we divide the total liters by 1 liter (the capacity of each bottle) to find the number of bottles Aisha can fill:

Number of bottles = 18.92705 liters / 1 liter ≈ 18.93

Hence Aisha can fill approximately 19 one-liter bottles with 5 gallons of sports drink

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