Identify the domain of the function shown in the graph.
A. X≥ 0
B. x < 0
C. 0 -8-84-2
D. x is all numbers.
10-
8
8.
4+
2+
y
-2-
4.
-8-
-10+
2
4 6 8 10 12

Identify The Domain Of The Function Shown In The Graph.A. X 0B. X &lt; 0C. 0-8-84-2D. X Is All Numbers.10-88.4+2+y-2-4.-8--10+24

Answers

Answer 1

Answer:

A. [tex] x \geq 0[/tex]

Step-by-step explanation:

The domain of a function is the set of [tex]x[/tex]-values.


Related Questions

please help this is for my study guide thanks! (simplify)

Answers

One way of simplifying the given expression is by using the following definition:

[tex]k^{-1}=\frac{1}{k}[/tex]

So, for the given expression, we have:

[tex]-3k^{-1}=-3\cdot\frac{1}{k}=-\frac{3}{k}[/tex]

Therefore, a possible answer is:

[tex]-\frac{3}{k}[/tex]

Round the decimal number to the nearest thousandth.

11.59978

Answers

Answer:

Step-by-step explanation:

How can I solve this equation if x = -2 and y = -3? 3y (x + x² - y) I've also included a picture of the equation.

Answers

In order to calculate the value of the equation, let's first use the values of x = -2 and y = -3 in the equation and then calculate every operation:

[tex]\begin{gathered} 3y(x+x^2-y) \\ =3\cdot(-3)\cdot(-2+(-2)^2-(-3)) \\ =-9(-2+4+3) \\ =-9\cdot5 \\ =-45 \end{gathered}[/tex]

Therefore the final result is -45.

Circle O shown below has an are of length 47 inches subtended by an angle of 102°.Find the length of the radius, x, to the nearest tenth of an inch.

Answers

We will have the following:

[tex]\begin{gathered} 47=\frac{102}{360}\ast2\pi(x)\Rightarrow\pi(x)=\frac{1410}{17} \\ \\ \Rightarrow x=\frac{1410}{17\pi}\Rightarrow x\approx26.4 \end{gathered}[/tex]

So, the radius is approximately 26.4 inches.

Solve for x. (x-8a)/ 6 = 3a-2x

Answers

Given the equation:

[tex]\frac{x-8a}{6}=3a-2x[/tex]

To solve for x, first we move the 6 to the other side of the equation:

[tex]\begin{gathered} \frac{x-8a}{6}=3a-2x \\ \Rightarrow x-8a=(3a-2x)\cdot6 \end{gathered}[/tex]

Since the 6 was dividing, we pass it to the other side multiplying. Now we apply the distributive property and move the term -8a to the other side:

[tex]\begin{gathered} x-8a=(3a-2x)\cdot6 \\ \Rightarrow x-8a=18a-12x \\ \Rightarrow x=18a-12x+8a \\ \end{gathered}[/tex]

Finally, we move the -12 to the other side with its sign changed:

[tex]\begin{gathered} x+12x=18a+8a=26a \\ \Rightarrow13x=26a \\ \Rightarrow x=\frac{26}{13}a=2a \\ x=2a \end{gathered}[/tex]

therefore, x=2a

Let x equals negative 16 times pi over 3 periodPart A: Determine the reference angle of x. (4 points)Part B: Find the exact values of sin x, tan x, and sec x in simplest form. (6 points)

Answers

The reference angle of x is -60 degree. The exact values of sin x, tan x, and sec x is [tex]$\sin \left(-60^{\circ}\right)=-\frac{\sqrt{3}}{2}$[/tex], [tex]$\tan \left(-60^{\circ}\right)=-\sqrt{3}$[/tex], [tex]$\sec \left(-60^{\circ}\right)=2$[/tex]

[tex]x=-\frac{16 \times 180}{3}$$[/tex]

Multiply the numbers: [tex]$16 \times 180=2880$[/tex]

[tex]$x=-\frac{2880}{3}$[/tex]

Divide the numbers: [tex]$\frac{2880}{3}=960$[/tex]

x=-960

Or, x = 2 [tex]\times[/tex] 360 - 960

Follow the PEMDAS order of operations

Multiply and divide (left to right) 2 [tex]\times[/tex]360 : 720 =720-960

Add and subtract (left to right) 720-960: -240

x= -240

Reference angle =180-240

Reference angle= -60

Sin (-60 degree)= [tex]$\sin \left(-60^{\circ}\right)=-\frac{\sqrt{3}}{2}$[/tex]

[tex]$\tan \left(-60^{\circ}\right)=-\sqrt{3}$[/tex]

[tex]$\sec \left(-60^{\circ}\right)=2$[/tex]

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Determine the smallest possible co-terminal
angle for a) 410. b)-45

Answers

The smallest possible co-terminal are:

a)50

b) -495

Define co terminal angles.

Angles that share the terminal side with an angle occupying the standard position are said to be co terminal angles. In the conventional position, the vertex is at the origin and one side of the angle is fixed along the positive x-axis.

In other words, two angles are co terminal when their vertices and sides are the same but their angles themselves differ.

Additionally, you can recall the concept of co terminal angles as angles that differ by an exact number of full circles.

Given Data

The smallest co terminal angle for:

a) 410

Divide the first number by the second, rounding down (towards the floor).

[tex]\frac{360}{410}[/tex]

= 1

after that, multiply the divisor by the result (called the quotient),

360(1)

= 360

Take this amount out of your starting amount.

410-360

= 50

b) -45

- 45 [tex]\frac{pie}{4}[/tex]

= -495

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What is the product in simplest form? State any restrictions on the variable9X^2+9X+18)/(X+2) TIMES (x^2-3x-10)/(x^2+2x-24)

Answers

So, here we have the following expression:

[tex]\frac{9x^2+9x+18}{x+2}\cdot\frac{x^2-3x-10}{x^2+2x-24}[/tex]

The first thing we need to notice before simplifying, is that the denominator can't be zero.

As you can see,

[tex]\begin{gathered} x+2\ne0\to x\ne-2 \\ x^2+2x-24\ne0\to(x+6)(x-4)\ne0\to\begin{cases}x\ne-6 \\ x\ne4\end{cases} \end{gathered}[/tex]

These are the restrictions on the given variable.

Now, we could start simplyfing factoring each term:

[tex]\begin{gathered} \frac{9x^2+9x+18}{x+2}\cdot\frac{x^2-3x-10}{x^2+2x-24},x\ne\mleft\lbrace2,4,-6\mright\rbrace \\ \\ \frac{9(x^2+x+2)}{x+2}\cdot\frac{(x-5)(x+2)}{(x+6)(x-4)},x\ne\lbrace2,4,-6\rbrace \end{gathered}[/tex]

This is,

[tex]9(x^2+x+2)\cdot\frac{(x-5)}{(x+6)(x-4)},x\ne\lbrace4,-6\rbrace[/tex]

So, the answer is:

[tex]\frac{9(x^2+x+2)(x-5)}{(x+6)(x-4)},x\ne\lbrace4,-6\rbrace[/tex]

It could be also written as:

[tex]\frac{(9x^2+9x+18)(x-5)}{(x+6)(x-4)},x\ne\lbrace4,-6\rbrace[/tex]

Two people start walking at the same time in the same direction. One person walks at 2 mph and the other person walks at 6 mph. In how many hours will they be 2 mile(s) apart?

Answers

Let's define the following variable:

t = number of hours for them to be 2 miles apart

Distance covered by Person A after "t"hours would be 2t or 2 miles times "t" hours.

Distance covered by Person B after "t" hours would be 6t or 6 miles times "t" hours.

If the distance of Person A and B is 2 miles apart after "t" hours, we can say that:

[tex]\begin{gathered} \text{Person B}-PersonA=2miles \\ 6t-2t=2miles\text{ } \end{gathered}[/tex]

From that equation, we can solve for t.

[tex]\begin{gathered} 6t-2t=2miles\text{ } \\ 4t=2miles\text{ } \\ \text{Divide both sides by 4.} \\ t=0.5hrs \end{gathered}[/tex]

Therefore, at t = 0.5 hours or 30 minutes, the two persons 2 miles apart.

At 0.5 hours, Person A will

thanks for the help!!!!!

Answers

The required values of given the trigonometric functions are sin(A + B) = -100/2501 and sin(A - B) = -980/2501.

What are Trigonometric functions?

Trigonometric functions are defined as the functions which show the relationship between the angle and sides of a right-angled triangle.

We have been given that the trigonometric function

sin (A) = -60/61 and cos(B) = 9/41

So cos (A) = √1 - (-60/61)² = 11/61, and sin(B) = √1 - (9/41)² = 40/41

To compute  the trigonometric functions sin(A + B) and sin(A - B)

⇒ sin(A + B) = sinA cosB + cos A sinB

⇒ sin(A + B) = (-60/61)(9/41) + (11/61)(40/41)

⇒ sin(A + B) = -540/2501 + 440/2501

⇒ sin(A + B) = -100/2501

⇒ sin(A - B) = sinA cosB - cos A sinB

⇒ sin(A - B) = (-60/61)(9/41) - (11/61)(40/41)

⇒ sin(A - B) = -540/2501 - 440/2501

⇒ sin(A - B) = -980/2501

Thus, the required values of given the trigonometric functions are sin(A + B) = -100/2501 and sin(A - B) = -980/2501.

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In the answer section, give the question letter and the word TRUE or FALSE for each of the following:

Answers

Explanation

a) We rewrite the right side of the expression as:

[tex](-2)^4=((-1)\cdot2)^4=(-1)^4\cdot2^4=1\cdot2^4=2^4\ne-2^4.[/tex]

So we see that the expression of point a is FALSE.

b) We consider the expression:

[tex]b^x.[/tex]

We take the logarithm in base b, we get:

[tex]\log_b(b^x)=x\cdot\log_b(b)=x\cdot1=x.[/tex]

We see that the logarithm of a number x to a base b is just the exponent you put onto b to make the result equal x. We conclude that this expression is TRUE.

c) We know that in any base a, we have:

[tex]\log_a(0)\rightarrow-\infty.[/tex]

We conclude that the expression of this item is FALSE.

d) Logarithms are defined only for numbers greater than 0. So we conclude that this expression is FALSE.

e) We consider the expression:

[tex]\log_b(b^{10})-\log_b(1)=10.[/tex]

Applying the properties of logarithms, we get:

[tex]\begin{gathered} 10\cdot\log_bb-0=10, \\ 10\cdot1=10, \\ 10=10\text{ \checkmark} \end{gathered}[/tex]

We see that this expression is TRUE.

Answer

a) FALSE

b) TRUE

c) FALSE

d) FALSE

e) TRUE

Tow "N" Go Towing Company charges a flat fee of $75 plus an additional $5 for every mile the car is towed. Which function models the cost, T(), of towing a car for miles?

Answers

Answer:

5N + 75 I believe

Find the Discriminant and describe the number and type of solutions of the equations. 1) 4x^2 + 8x + 4 =0

Answers

Given:

[tex]4x^2+8x+4=0​[/tex]

To find the discriminant, use the formula:

[tex]\Delta=b^2-4ac[/tex]

Where a = 4, b = 8, c = 4

Thus, we have:

[tex]\begin{gathered} \Delta=8^2-4(4)(4) \\ \\ \Delta=64-64\text{ =0} \end{gathered}[/tex]

The discriminant is = 0

To find the number of solutions, since the disriminant is zero, we have two real and identical roots.

ANSWER:

Discriminant = 0

Number of roots = 2 real and identical roots

Write a recursive formula for an, the nthterm of the sequence 8, -2, -12, ....

Answers

We have the sequence: 8, -2, -12...

We can prove that this is an arithmetic sequence as there is a common difference d=-10 between consecutive terms.

Then, the recursive formula (the expression where the value of a term depends on the value of the previous term) can be written as:

[tex]a_n=a_{n-1}-10[/tex]

Answer: the recursive formula is a1 = 8, a(n) = a(n-1) - 10

Allied Health - A wound was measured to be 0.8 cm in length. Whaat is the greatest possible error of this weight in grams?

Answers

Ok, so

First of all, we got that the wound was measured to be 0.8cm.

This measurement equals to:

[tex]0.8\operatorname{cm}\cdot\frac{10\operatorname{mm}}{1\operatorname{cm}}[/tex]

0.8cm is equal to 8 millimeters.

Now, the greatest possible error in a measurement is one half of the precision (smallest measured unit).

8 mm was measured to the nearest 1 mm, so the measuring unit is 1 mm.

So, one half of the precision (1mm) is 0.5

Therefore, the greatest possible error is 0.5 mm

Write the limit as a definite integral on the interval [a, b], where ci is any point in the ith subinterval.

Answers

Explanation

We have the following integral in the discrete sum form:

[tex]\lim_{||\Delta||\to0}\sum_{i\mathop{=}1}^{\infty}(6c_i+3)\Delta x_i.[/tex]

In the interval [-9, 6].

To convert to the integral form, we convert each element of the discrete sum form:

[tex]\begin{gathered} \lim_{||\Delta||\to0}\sum_{i\mathop{=}1}^{\infty}\rightarrow\int_{-9}^6 \\ 6c_i+3\rightarrow6x+3 \\ \Delta x_i\rightarrow dx \end{gathered}[/tex]

Replacing these in the formula above, we get the integral form:

[tex]\int_{-9}^6(6x+3)\cdot dx.[/tex]Answer

6. Takao scores a 90, an 84, and an 89 on three out of four math tests. Whatmust Takao score on the fourth test to have an 87 average (mean)?a. 87b. 88c. 85d. 84e. 86

Answers

Consider x as Takao's fourth score.

Then, to achieve an 87 average, we have:

[tex]\begin{gathered} 87=\frac{90+84+89+x}{4} \\ x+263=4\cdot87 \\ x=348-263 \\ x=85 \end{gathered}[/tex]

Answer:

c. 85

The sum of a number and 4 times it’s reciprocal is 13/3. Find the number(s).

Answers

Let the unknown number be "x"

We will write an algebraic equation from the word problem given. Then we will solve for "x".

Given,

Sum of number (x) and 4 times the reciprocal is 13/3

We can convert it into an algebraic equation:

[tex]x+(4\times\frac{1}{x})=\frac{13}{3}[/tex]

Now, let's solve for the unknow, x,

[tex]\begin{gathered} x+(4\times\frac{1}{x})=\frac{13}{3} \\ x+\frac{4}{x}=\frac{13}{3} \\ \frac{x^2+4}{x}=\frac{13}{3} \\ 3(x^2+4)=13\times x \\ 3x^2+12=13x \\ 3x^2-13x+12=0 \\ (x-3)(x-\frac{4}{3})=0 \\ x=3 \\ x=\frac{4}{3} \end{gathered}[/tex]

The numbers are

[tex]\begin{gathered} 3 \\ \text{and} \\ \frac{4}{3} \end{gathered}[/tex]

5. Four hamsters have a combined weight of 5.112 grams. If all the hamsters weigh the same, how many kilograms does one hamster weigh? kilograms

Answers

We were told that Four hamsters have a combined weight of 5.112 grams. We know that

1000 grams = 1 kilogram

Thus,

5.112 grams = 5.112/1000

= 0.005112 kilograms

Since all the hamsters weigh the same, then the weight of one hamster is

0.005112 /4

= 0.001278 kilogram

The weight of one hamster is 0.001278 kilogram

A rectangle has vertices at (-2, 11), (-2,4), (6, 11), and (6, 4). Pablo says the area of the rectangle is 49 square units and his work is shown below. Steps Step 1 Pablo's Work Base: 1- 21+61= 8 Step 2 Step 3 Height: 11-4-7 Area: 8x7=49 square units Where, if at all, did Pablo first make a mistake finding the area of the rectangle? Step 1 Step 2 Step 3

Answers

The result of the calculation of the base is good because the distance between -2 and 6 is 8. The result of the calculation of the height is good because the distance between 4 and 11 is 7. The mistake is seen in the part of the multiplication, because 8x7 is equal to 56 , not 49.

So, the mistake was made when doing the Step 3.

A rectangle's base is 2 in shorter than five times its height. The rectangle's area is 115 in². Find this rectangle's dimensions.
The rectangle's height is
The rectangle's base is

Answers

Answer:

The rectangle's height is 5 in,The rectangle's base is 23 in.

Step-by-step explanation:

Let the dimensions are b and h.

The area of rectangle is the product of two dimensions.

We have:

b = 5h - 2,bh = 115 in².

Solve the equation by substitution:

h(5h - 2) = 1155h² - 2h = 1155h² - 2h - 115 = 05h² - 25h + 23h - 115 = 05h(h - 5) + 23(h - 5) = 0(h - 5)(5h + 23) = 0h - 5 = 0 and 5h + 23 = 0h = 5 and h = - 23/5

The second root is discarded as negative.

The height is 5 in,The base is: 5*5 - 2 = 23 in

Answer:

Height = 5 in

Base = 23 in

Step-by-step explanation:

[tex]\boxed{\textsf{Area of a rectangle} = \sf Base \times Height}[/tex]

Let x be the height of the rectangle.

Given values:

Height = x inBase = (5x - 2) inArea = 115 in²

Substitute the values into the formula for area and solve for x:

[tex]\begin{aligned}\sf Area & = \sf Base \times Height\\\\115&=x(5x-2)\\115&=5x^2-2x\\5x^2-2x-115&=0\\5x^2-25x+23x-115&=0\\5x(x-5)+23(x-5)&=0\\(5x+23)(x-5)&=0\\\\\implies 5x+23&=0 \implies x=-\dfrac{23}{5}\\\implies x-5&=0 \implies x=5\end{aligned}[/tex]

As length is positive, x = 5.

To find the rectangle's dimensions, substitute the found value of x into the expressions for the height and base:

[tex]\implies \sf Height=5\;in[/tex]

[tex]\begin{aligned}\implies \sf Base&=\sf 5(5)-2\\&=\sf 25-2\\&=\sf 23\;in\end{aligned}[/tex]

use this figure for questions 1 through 4 1. are angles 1 and 2 a linear pair?2. are angles 4 and 5 a linear pair ?3.are angles 1 and 4 vertical angles?4. are angles 3 and 5 vertical angles ?

Answers

Linear pair angles form a straight line, so, both angles add up to 180°.

1 and 2 are not a linear pair.

4 and 5 are a linear pair.

Vertical angles are opposite angles, that are equal.

1 and 4 are vertical angles

3 and 5 are NOT vertical angles-

The probability that an individual is left-handed is 12%, In a randomly selected class of 30students, what is the probability of finding exactly 4 left-handed students?

Answers

Given that:

- The probability that an individual is left-handed is 12%.

- There are 30 students in the class.

You need to use this Binomial Distribution Formula, in order to find the probability of finding exactly 4 left-handed students :

[tex]P(x)=\frac{n!}{(n-x)!x!}p^x(1-p)^{n-x}[/tex]

Where "n" is the number being sampled, "x" is the number of successes desired, and "p" is the probability of getting a success in one trial.

In this case:

[tex]\begin{gathered} n=30 \\ x=4 \\ p=\frac{12}{100}=0.12 \end{gathered}[/tex]

Therefore, by substituting values into the formula and evaluating, you get:

[tex]P(x=4)=\frac{30!}{(30-4)!4!}(0.12)^4(1-0.12)^{30-4}[/tex][tex]P(x=4)\approx0.2047[/tex]

Hence, the answer is:

[tex]P(x=4)\approx0.2047[/tex]

A money market account offers 1.25% interest compounded monthly. If you want to save $500 in two years, how much money would you need to save per month?

Answers

If you want to save $500 in two years, you need to save $20.58 per month with a 1.25% interest compounded monthly.

How is the periodic saving determined?

The monthly savings can be determined using an online finance calculator as follows:

N (# of periods) = 24 months (2 x 12)

I/Y (Interest per year) = 1.25%

PV (Present Value) = $0

FV (Future Value) = $500

Results:

Monthly Savings = $20.58

Sum of all periodic savings = $494.04

Total Interest = $5.96

Thus, the investor needs to save $500 in two years to save $20.58 monthly.

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graph the line with slope 1/3 passing through the point (4,2)

Answers

To graph a line we need two points, to find a second one we need the equation of the line. The equation of a line is given by:

[tex]y-y_1=m(x-x_1)[/tex]

Plugging the values given we have:

[tex]\begin{gathered} y-2=\frac{1}{3}(x-4) \\ y-2=\frac{1}{3}x-\frac{4}{3} \\ y=\frac{1}{3}x-\frac{4}{3}+2 \\ y=\frac{1}{3}x+\frac{2}{3} \end{gathered}[/tex]

Once we know the equation of a line we find a second point on the line, to do this we give a value to x and use the equation to find y. If x=1, then:

[tex]\begin{gathered} y=\frac{1}{3}\cdot1+\frac{2}{3} \\ y=\frac{1}{3}+\frac{2}{3} \\ y=\frac{3}{3} \\ y=1 \end{gathered}[/tex]

Then we have the point (1,1).

Now that we have two points of the line we plot them on the plane and join them with a straight line. Therefore the graph of the line is:

Solve the triangle: a = 12,c = 2-2, B = 33". If it is not possible, say so.A= 25.1",b = 1.8, C = 121.9"This triangle is not solvable.A = 45*,b= V2.C = 102VEA= 30', b = -, C = 117"

Answers

ANSWER:

A=25.1 degrees

b = 1.8

C = 121.9 degrees

SOLUTION:

We can solve this problem using the cosine law, since we are given the length of 2 sides of triangle and the angle they formed.

[tex]b\text{ =}\sqrt[]{c^2+a^2-2ac\cos B}[/tex]

We substitute the given

[tex]\begin{gathered} b\text{ =}\sqrt[]{(2\sqrt[]{2})^2+(\sqrt[]{2})^2-2(\sqrt[]{2})(2\sqrt[]{2})\cos 33} \\ b\text{ = 1.8} \end{gathered}[/tex]

Using Sine Law, we can get the angles

[tex]\begin{gathered} \frac{1.8}{\sin 33}=\frac{\sqrt[]{2}}{\sin A} \\ A=25.1 \end{gathered}[/tex]

Since the total angle inside a triangle is 180, the angle at C is

[tex]C-33-25.1=121.9[/tex]

What is the graph of the equation y = 2x + 4?
The y-intercept is which means the line crosses the y-axis at the
). Plot this point.
point
The slope of the line is positive, so it goes
Start at the y-intercept. Move up
0
0 and then move right
). Plot this point.
You are now at the point (
0
Draw a line to connect the two points.
from left to right.

Answers

Answer: 8

Step-by-step explanation: x2 + 4 is 4 x 2

:D

find slope -1,4 3,15

Answers

Answer:11/4

Step-by-step explanation: First you put the points in m=x1-x2/y1-y2

m=15-4/3+1=15

Work out the following sums and write the answers correctly.
a) £1.76 + £2.04
b) £5.62 + £2.38

Answers

Answer of a is €3.8

Answer of b is €8

Solution :

To get the answer add two decimal number

ie.  the sum of first question is €1.76 + €2.04 = €3.8

the sum of second question is €5.62 + €2.38 = €8

Addition is one of the four basic operations of arithmetic, the other three being subtraction, multiplication and division.The addition of two whole numbers results in the total amount or sum of those values combined.Addends are the numbers added, and the result or the final answer we get after the process is called the sum.

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Simplify 2f+ 6f help me pls

Answers

Answer:

[tex]{ \tt{ = 2f + 6f}}[/tex]

- Factorise out f as the common factor;

[tex]{ \tt{ = f(2 + 6)}} \\ = 8f[/tex]

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With high hope for the future, no prediction in regard to it is ventured.On the occasion corresponding to this four years ago, all thoughts were anxiously directed to an impending civil war. All dreaded it all sought to avert it. While the inaugural address was being delivered from this place, devoted altogether to saving the Union without war, insurgent agents were in the city seeking to destroy it without war seeking to dissolve the Union and divide effects, by negotiation. Both parties deprecated war, but one of them would make war rather than let the nation survive, and the other would accept war rather than let it perish. And the war came.One-eighth of the whole population were colored slaves, not distributed generally over the Union, but localized in the Southern part of it. These slaves constituted a peculiar and powerful interest. All knew that this interest was, somehow, the cause of the war. To strengthen, perpetuate, and extend this interest was the object for which the insurgents would rend6 the Union, even by war; while the government claimed no right to do more than to restrict the territorial enlargement of it. Neither party expected the war, the magnitude, or the duration, which it has already attained. Neither anticipated that the cause of the conflict might cease with or even before, the conflict itself should cease. Each looked for an easier triumph, and a result less fundamental and astounding. Both read the same Bible and pray to the same God, and each invokes His aid against the other.It may seem strange that any man should dare to ask just Gods assistance in wringing their bread from the sweat of other mens faces, but let us judge not that we are not judged. The prayers of both could not be answered; that of neither has been answered fully. The Almighty has His own purposes. Woe unto the world because of offenses! for it must needs be that offenses come; but woe to that man by whom the offense cometh!If we shall suppose that American Slavery is one of those offences which, in the providence of God, must needs come, but which, having continued through His appointed time, He now wills to remove, and that He gives to both North and South, this terrible war, as the woe due to those by whom the offence came, shall we discern therein any departure from those divine attributes which the believers in a Living God always ascribe to Him? Fondly do we hope fervently do we pray that this mighty scourge of war may speedily pass away. Yet, if God wills that it continue until all the wealth piled by the bondman's two hundred and fifty years of unrequited toil shall be sunk, and until every drop of blood drawn with the lash, shall be paid by another drawn with the sword, as was said three thousand years ago, so still it must be said: the judgments of the Lord, are true and righteous altogether.With malice toward none; with charity for all; with firmness in the right, as God gives us to see the right, let us strive on to finish the work we are in; to bind up the nations wounds; to care for him who shall have borne the battle, and for his widow, and his orphan to do all which may achieve and cherish a just, and lasting peace, among ourselves, and with all nations.How does paragraph 5 contribute to the development of ideas in the text? the process associated with resolving complaints is called the: complaint substitution process. complaint reversal process. complaint correction process. complaint recovery process. complaint reparation process. James counts down in 9's starting from 345 until he passes zero. Which will be the lastpositive number which he counts? A city has a population of 350,000. Thepopulation has decreased by 30% in the pastten years. What was the population of the cityten years ago? A first piece of rock which weighs 5N. Force F is applied to this first piece of rock and it produces an acceleration of a. Now if there is a second piece of rock. What force needs to be applied to the second piece of rock to produce an acceleration of 8a. Mass of both pieces of rock is same. What are the qualities of an American president? What qualities could they not have? Solve the inequality. Using a verbal statement, in simplest terms, describe the solution of the inequality. Be sure to include the terms, "greater than", "greater than or equal to", "less than", or "less than or equal to". The ohio constitution of 1851 established district courts. How did this solve an existing problem in the state?. I need to see which ones are translations,dilations,reflections and I forgot the other one I need help finding surface area of a figure A side of the triangle below has been extended to form an exterior angle of 135. Find the value of xx. a softball player has fallen on her elbow diving for a ground ball. there is immediate isolated swelling over the apex of her elbow. what condition should be suspected?