If a=3x^3, b=4x^4, and c=ab^2, then what is the value of bc?

Answer:

  (d)  71°

Step-by-step explanation:

The desired angle in the given isosceles triangle can be found a couple of ways. The Law of Cosines can be used, or the definition of the sine of an angle can be used.

Since the triangle is isosceles, the bisector of angle W is an altitude of the triangle. The hypotenuse and opposite side with respect to the divided angle are given, so we can use the sine relation.

  sin(W/2) = Opposite/Hypotenuse

  sin(W/2) = (35/2)/(30) = 7/12

Using the inverse sine function, we find ...

  W/2 = arcsin(7/12) ≈ 35.685°

  W = 2×36.684° = 71.37°

  W ≈ 71°

The law of cosines tells you ...

  w² = u² +v² -2uv·cos(W)

Solving for W gives ...

  W = arccos((u² +v² -w²)/(2uv))

  W = arccos((30² +30² -35²)/(2·30·30)) = arccos(575/1800) ≈ 71.37°

  W ≈ 71°

Answer:

See below

Step-by-step explanation:

Here is one way .... I showed you how to use Law of cosines in another Q

 use this to find  CB

CB^2 = 13^2 + 21^2 - 2(13)(21) cos 91      <==== solve for CB

THEN use law of SINES to find angle B

sin B / 21  =  sin 91 / CB           (CB you found using law of cosines above)

Answer:

m∠B = 57.5°

Explanation:

Use cosine rule:

a² = b² + c² - 2bc cos(A)

  inserting values

a² = 21² + 13² - 2(21)(13) cos(91)

a² = 619.529

a = √619.529

a = CB = 24.89 km

Then use sine rule:

sin(A)/a = sin(B)/b

sin(91)/24.89 = sin(B)/21

sin(B) = 21sin(91)/24.89

sin(B) = 0.843583...

B = sin⁻¹(0.843583) = 57.52° ≈ 57.5°

According to the developed scale, a radiant day is 16 times brighter than a dim day.

We assume the brightness of a dim day to be x.

According to the developed scale, the brightness of an illuminated day will be 4 times that of a dim day.

Thus, the brightness of an illuminated day = 4*the brightness of a dim day = 4x.

According to the developed scale, the brightness of a radiant day will be 4 times that of an illuminated day.

Thus, the brightness of a radiant day = 4*the brightness of an illuminated day = 4*4x = 16x.

Now, the ratio of the brightness of a radiant day to the brightness of a dim day = 16x:x = 16x/x = 16:1.

Thus, according to the developed scale, a radiant day is 16 times brighter than a dim day.

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The question provided is incomplete. The complete question is:

"Suppose you have developed a scale that indicates the brightness of sunlight. Each category in the table is 4 times brighter than the next lower category. For example, a day that is dazzling is 4 times brighter than a day that is radiant. How many times brighter is a radiant day than a dim day?

Dim=2

Illuminated=3

Radiant=4

Dazzling=5"

Using the Fundamental Counting Theorem, it is found that the customer can put together 288 different outfits.

It is a theorem that states that if there are n things, each with [tex]n_1, n_2, \cdots, n_n[/tex] ways to be done, each thing independent of the other, the number of ways they can be done is:

[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]

Bryan sells 3 types of shirts, 6 types of skirts, 8 types of bracelets and 2 types of hats, hence the parameters are given as follows:

[tex]n_1 = 3, n_2 = 6, n_3 = 8, n_4 = 2[/tex]

Hence the number of different outfits is given as follows:

N = 3 x 6 x 8 x 2 = 288

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Answer:

someone please help me check my page

someone please help me check my pageStep-by-step explanation:

The smallest positive integer having exactly 5 different positive integer divisors is 60.

To find the smallest positive integer having exactly 5 different positive integer divisors:

Therefore, the smallest positive integer having exactly 5 different positive integer divisors is 60.

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April's work in checking for the function, [tex]f(x) = x^3 - 1[/tex], to be even, odd, or neither, is incorrect. She did a mistake in step 2, where she took [tex]f(-x) = - f(x)[/tex], which was not true, since [tex]f(-x) = -x^3 - 1[/tex], whereas [tex]- f(x) = -x^3 + 1[/tex].

A function f(x) is said to be odd or even when it completes the condition:

In the question, we are given that April was asked to determine whether  [tex]f(x) = x^3 - 1[/tex], is even, odd, or neither, and are shown her work.

We are asked whether April's work is correct, and if not, what is the first step where April made a mistake.

To check for a function is even or odd, we first calculate f(-x).

April's first step was also finding f(-x), which she found accurately as  [tex]f(-x) = -x^3 - 1[/tex].

Next, we need to check whether f(-x) is equal to f(x), -f(x), or neither, to check if the function is even, odd, or neither, respectively.

April, also choose the right step of checking, but did a mistake in checking, since f(-x) ≠ f(x), and also, f(-x) ≠ - f(x), since, [tex]- f(x) = -(x^3 - 1)[/tex] = [tex]-x^3 + 1[/tex], which is not equal to f(-x).

Thus, April's work in checking for the function, [tex]f(x) = x^3 - 1[/tex], to be even, odd, or neither, is incorrect. She did a mistake in step 2, where she took f(-x) = - f(x), which was not true, since [tex]f(-x) = -x^3 - 1[/tex], whereas [tex]- f(x) = -x^3 + 1[/tex].

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The number of people who must be included in the survey, that is, the sample size should be 340.

We assume the sample size to be n.

The confidence interval required is 99%.

The Z-score corresponding to the 99% confidence interval is (Z) 2.58.

The true proportion (p) of the sample is not given, so we assume it to be 50% or 0.5.

The margin of error for the sample (E) is given to be 7% or 0.07.

By the formula of margin of error, we know that:

E = Z√[{p(1 - p)}/n].

Putting in the values, we have, we get:

0.07 = 2.58√[{0.5*0.5}/n],

or, (0.07/2.58)² = 0.25/n,

or, n = 0.25/{(0.07/2.58)²} = 339.6122449 ≈ 340.

Thus, the number of people who must be included in the survey, that is, the sample size should be 340.

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The vertical asymptote of f(x) is (A) x = 0, –9.

To find the vertical asymptote of f(x):

The vertical asymptotes of a function are the zeroes of the denominator of a rational function

The function is given as: [tex]f(x) = \frac{(x-9)}{(x^{3} -81x)}[/tex]

Set the denominator to 0:

Factor out x:

Express 81 as 9^2:

Express the difference between the two squares:

Split, [tex]x=0[/tex] or [tex]x=-9[/tex] or [tex]x+9=0[/tex].

Solve for x:

Therefore, the vertical asymptote of f(x) is (A) x = 0, –9.

(See attachment for the graph of f(x))

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The complete question is given below:

Consider the function f(x)=(x-9)/(x^3-81x) . find the vertical asymptote(s) of f(x).

A) x = 0, –9

B) x = –9

C) x = 0, 9

D) x = 9

Answer:

∠a=40°, ∠b=50°, ∠c=115°.

Step-by-step explanation:

∵The opposite vertex angles are equal,

∴∠a=40°.

∴∠b=90°-∠a=90°-40°=50°.

∠c=180°-65°=115°.

Based on the task content; If you multiply both sides of an inequality by a negative number, the inequality symbol should be reversed always. Option B

Based on the rule of inequality, whenever you multiply or divide an inequality by a negative number, you must flip the inequality sign.

For instance,

-4x > 12

divide both sides by -4

x < 12/-4

x < -3

If you multiply both sides of an inequality by a negative number, the inequality symbol should be reversed always.

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The simplified expression of (2x+1)/(x²-3) is 2x/(x²-3) + 1/(x²-3)

The expression is given as:

(2x+1)/(x²-3)

The above expression is a fraction and the numerator has 2 terms

For a fraction

A + B)/x

The fraction can be split as

A/x + B/x

Using the above as a guide, we have:

(2x+1)/(x²-3) = 2x/(x²-3) + 1/(x²-3)

Hence, the simplified expression of (2x+1)/(x²-3) is 2x/(x²-3) + 1/(x²-3)

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Answer:

the greatest 7 digit no.is = 999,99,99 the smallest 6 digit no.is= 1,00,000

Step-by-step explanation:

Sorry if I'm wrong I tried.

Answer:

-1 and 1

Step-by-step explanation:

Reflecting D over the y-axis maps it onto (1,2).

This is supposed to map onto F(0,3), so this is a shift 1 unit left and 1 unit up.

So, the blanks are -1 and 1, respectively.

Answer: (x + [-1], y + [1])

Step-by-step explanation:

      See attached. We can draw, or picture it in our heads, what the reflection would look like. Then we can pick one (or multiple to test) points and see the translation.

      We can also test with a set of points. B', (2, 4) becomes G in the transformation. G is at (1, 5)

      (1 - 2, 5 - 4) -> (-1, 1)

The approximate solution of this system of equations is

(x,y)=(-0.25,1.25)

Equation is defined as the state of being equal and is often shown as a math expression with equal values on either side, or refers to a problem where many things need to be taken into account.

Given that,

y = |x − 1| and y = 3x+2

 y = |x − 1|

    = (x-1) ,    for  (x-1)>0 or x>1

and

y = -(x-1)  ,    for(x-1)<0  or x<1

y  = -x+1      

Now,   For x>1

y = x-1    ......(1)

y = 3x+2   ......(2)

Solving for x by equaliting's method:

 3x+2 = x-1

→ 3x-x = -1-2

→ 2x = -3

→ x = -3/2

→ x = -1.5 which is <1.

For x<1

y = -x+1    ......(1)

y = 3x+2   ......(2)

Solving for x by equaliting's method:

 3x+2 = -x+1

→ 3x+x = 1-2

→ 4x = -1

→ x = -1/4

→ x= -0.25 which is <1.

substitute the value of x = -0.25 in equation 1 for x<1.

y = -x+1

  = -(-0.25)+1

y  = 1.25

Hence, The approximate solution of this system of equations is

(x,y)=(-1/4,5/4)=(-0.25,1.25).

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Answer: 77 - 10 = 67, and the additive inverse of 77 - 10 is 77 + 10. 77 + 10 = 87.

Hope this helps! This question was kind of confusing for me, because I didn’t understand why you said to add 77 - 10… is this is the incorrect answer sorry your question was worded weird

Answer:

Step-by-step explanation:

since we know that the 50 degrees is one side of the line then the angle that is strait opposite from this angle is 50 degrees, so 50+60=110degrees and 180-110=70, so x=70 degrees

a. Expressing y in terms of x, y = 20/(x + 3)

b. When x = 5, the value of y is 2.5

The question has to do with inverse variation.

Inverse variation is variation in which one quantity varies inversely as the other.

Given that y is inversely as x + 3 and that y = 4 when x = 2.

Since y varies inversely as x + 3, we have

y ∝ 1/(x + 3)

y = k/(x + 3)

When y = 4, x = 3. So

y = k/(x + 3)

4 = k/(2 + 3)

4 = k/5

k = 4 × 5

k = 20

So, y = k/(x + 3)

y = 20/(x + 3)

So, expressing y in terms of x, y = 20/(x + 3)

Since  y = 20/(x + 3)

Substituting x = 5 into the equation, we have

y = 20/(x + 3)

y = 20/(5 + 3)

y = 20/8

y = 5/2

y = 2.5

So, when x = 5, the value of y is 2.5

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The series converges to  1/(1-9x) for -1/9<x<1/9                  

Given the series is  ∑ [tex]9x^{n} x^{n}[/tex]

We have to find the values of x for which the series converges.

We know,                

∑ [tex]ar^{n-1}[/tex]    converges to  (a) / (1-r) if r < 1

Otherwise the series will diverge.

Here, ∑ [tex](9x)^{n}[/tex] is a geometric series with |r| = | 9x |

And it converges for |9x| < 1

Hence, the given series gets converge for -1/9<x<1/9

And geometric series converges to a/(1-r)

Here, a = 1 and r = 9x

Therefore, a/(1-r) = 1/(1-9x)

Hence, the given series converges to   1/1-9x  for  -1/9<x<1/9

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Answer:

8 Hours

Step-by-step explanation:

We know she travels 220 miles in 5 hours, so lets create an equation with a ratio which finds the miles she drives in a single hour, multiply that by x, and then set it equal to 352.

[tex]\frac{220}{5}x=352[/tex]

Multiply both sides by 5

[tex]220x=1760[/tex]

Divide both sides by 220

[tex]x=8[/tex]

Therefore it would take 8 hours.

8 Hours long would it take to travel 352 miles,

The distance that an object travels in relation to the amount of time it takes to do so can be used to define speed. In other words, it is a measurement of an object's motion's speed without direction Velocities are what we get when speed and direction are combined. The SI unit system is most frequently used to express speed units. In that system, since distance is measured in metres and time is measured in seconds, speed is expressed in metres per second, or m/s. Three components make up the speed formula: distance, time, and speed.

We know she travels 220 miles in 5 hours, so lets create an equation with a ratio which finds the miles she drives in a single hour, multiply that by x, and then set it equal to 352.

Multiply both sides by 5

Divide both sides by 220

Hence, it would take 8 hours.

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Answer:

11/18.

Dan is 8.

Step-by-step explanation:

The initial fraction is

x / 2x-4

Adding 3/3 we have

x+3 / 2x-1 = 2/3

Cross multiply:

3(x+3) = 2(2x-1)

3x + 9 = 4x - 2

9 + 2 = 4x - 3x

11 = x,

So the original fraction was 11 / 2(11) - 4

= 11/18.

If Dans age is d then Lois's age = 4d.

So 4d + d  = 40

5d = 40

d = 8.

So Dan is 8 years old.

Using it's concept, the probability a person tests positive who does not actually have Tuberculosis is:

c. 49/148.

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, there are 198 + 98 = 296 people who test positive, which is the number of total outcomes, and of those, 98 do not have the disease, which is the number of desired outcomes. Hence the probability is given by:

p = 98/296 = 49/148.

Which means that option c is correct.

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The probability a person tests positive who does not actually have Tuberculosis is 1/100

The probability is given as:

The probability a person tests positive who does not actually have Tuberculosis.

This is a conditional probability, and it can be calculated using

P = n(Tests positive | Does not have Tuberculosis)/n(Does not have Tuberculosis)

Using the given table of values, we have:

P = 98/9800

Evaluate the quotient

P = 1/100

Hence, the probability a person tests positive who does not actually have Tuberculosis is 1/100

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The capital borrowed, or the principal when the interest was Q468.75 is Q7500.

The principal P, amount borrowed, at a certain rate of interest R%, for  a time of T years, giving an interest of I, can be calculated using the formula:

P = (I * 100)/(R * T).

In the question, we are asked to find the capital borrowed, that is, the principal, when the user pays Q468.75 after 15 months at 5% of income.

Thus, Interest (I) = Q468.75, rate of interest (R) = 5%, and time (T) = 15 months = 15/12 years = 1.25 years.

Thus, the principal P, can be calculated by substituting the values in the formula: P = (I * 100)/(R * T).

P = (468.75*100)/(5*1.25),

or, P = 46875/6.25,

or, P = 7500.

Thus, the capital borrowed, or the principal when the interest was Q468.75 is Q7500.

The provided question is in Spanish. The question in English is:

"After 15 months of having borrowed capital at 5% of income, I have to pay Q468.75 in interest. What capital has been borrowed?"

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Considering the given function in the problem, it is found that:

a. 9.6 offspring survive to maturity when there are 12 female rabbits in the population.

b. At least 18 female rabbits are required for there to be 13 offspring.

The function gives the relationship between the number of adult female rabbits F and the number of offspring R as follows:

[tex]R = 3 + \frac{350F}{F + 625}[/tex]

When there are 12 female rabbits, we have that F = 12, hence:

[tex]R = 3 + \frac{350 \times 12}{12 + 625} = 9.6[/tex]

9.6 offspring survive to maturity when there are 12 female rabbits in the population.

For at least 13 offspring, we have that the number of rabbits needed is given as follows:

[tex]R \geq 13[/tex]

[tex]3 + \frac{350F}{F + 625} \geq 13[/tex]

[tex]\frac{350F}{F + 625} \geq 10[/tex]

[tex]350F \geq 10F + 6250[/tex]

[tex]F \geq \frac{6250}{340}[/tex]

[tex]F \geq 18[/tex]

At least 18 female rabbits are required for there to be 13 offspring.

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The logarithmic equation is:

log₂128 = x

So the correct option is the third one

Here we have the expression.

2ˣ = 128

Now, if we apply the natural logarithm to both sides, we can get:

ln(2ˣ) = ln(128)

Because of the property of natural logarithms, we can write the left side as:

ln(2ˣ) = x*ln(2) = ln(128)

Now, if we isolate x, we get:

x = ln(128)/ln(2)

And remember that:

ln(k)/ln(n) = logₙ(k)

Then we can rewrite the logarithmic equation as:

x = log₂(128)

Which is the third option.

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The desired measures for the data-set is given by:

The five number summary is composed by the measures explained below, except the IQR.

In this problem, we have that:

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Answer:

13

Step-by-step explanation:

w^2 = -2^2 = 4

-v = -1*-8 = 8

Put it together: w^2-v+1 --> 4+8+1 = 13

Answer:

Create a table.

Plug values into the equation to complete the table.

Use the table to plot points on the graph.

Draw lines through the points on your graph.

The graph should look linear because there is an x that doesn't have a power greater than or less than 1.

The length of the function y = 3x over the given interval [0, 2] is 3.2 units

For given question,

We have been given a function  y = 3x

We need to find the length of the function on the interval x = 0 to x = 2.

Let f(x) = 3x where f(x) = y

We have  f'(x) = 3,  so  [f'(x)]² = 9.  

Then the arc length is given by,

[tex]\int\limits^a_b {\sqrt{1+[f'(x)]^2} } \, dx\\\\= \int\limits^2_0 {\sqrt{1+9} }\, dx\\\\=\sqrt{10}\\\\ =3.2[/tex]

This means, the arc length is 3.2 units.

Therefore, the length of the function y = 3x over the given interval [0, 2] is 3.2 units

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Answer:

(x+5, y-3)

Step-by-step explanation:

I would say this because when a plane is translated up it would be positive and when it's translated to the left it would be negative,