The farthest away a target could be hit by a shell is approximately 1000 yards (rounded to the nearest whole number).
To solve the problem, we need to find the total distance that the shell can travel before it bursts.
The distance that the shell can travel is:
distance = rate × time
We are given that the shell can travel 500 yards in 1.5 seconds, so its speed is:
rate = distance ÷ time = 500 yards ÷ 1.5 seconds = 333.33 yards/second
Now we need to take into account the time it takes for the fuse to go off. Since it takes 3 seconds for the fuse to go off, the shell will have traveled:
distance = rate × time = 333.33 yards/second × (1.5 seconds + 3 seconds) = 999.99 yards
Therefore, the farthest away a target could be hit by a shell is approximately 1000 yards (rounded to the nearest whole number).
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In simple harmonic motion, when is the speed the greatest? (There could be more than one correct choice.)
Check all that apply.
when the displacement is a maximum
when the potential energy is a zero
when the potential energy is a maximum
when the magnitude of the acceleration is a minimum
when the magnitude of the acceleration is a maximum
In simple harmonic motion, the speed is greatest: when the potential energy is zero, and when the magnitude of the acceleration is a minimum.
The harmonic motion refers to the motion an oscillating mass experiences when the restoring force is proportional to the displacement but in opposite directions. Harmonic motion is periodic and can be represented by a sine wave with constant frequency and amplitude. An example of this is a weight bouncing on a spring.
In simple harmonic motion, the speed is the greatest when:
1. The displacement is at a minimum (specifically, at the equilibrium point)
2. The potential energy is at a minimum (or zero)
3. The magnitude of the acceleration is at a minimum
These conditions occur simultaneously, as they all correspond to the point in the motion when the object is moving fastest.
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What phase of training focuses on delivering maximum muscle force in minimum time?
O strength phase
O power phase
O time phase
O stabilization phase
power phase
Power Training focusses on overcoming resistance but also focusses on the ability to overcome the resistance in the shortest period of time. Simply put, Power = Force x Velocity, which means power can be improved by increasing force or velocity, or using a mixed-methods approach.
how does the amount of time in which the sun can warm earth affect the seasons?
The amount of time in which the sun can warm the Earth affects the seasons by determining the amount of solar energy received by a specific region.
The sun can warm the Earth affects the seasons is influenced by the Earth's tilt on its axis and its position in orbit around the sun. During summer, the sun's rays are more direct, leading to longer daylight hours and increased warming. In winter, the sun's rays are less direct, resulting in shorter daylight hours and less warming. These variations in solar energy lead to the changes in temperature and weather patterns that define the different seasons.
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A bus travelling at 80km/h accelerates for 12 s to a speed of 100km/h. What was the acceleration
Answer:
0.463 m/s^2
Explanation:
I calculated the answer using my
A 17000-kg jet takes off from an aircraft carrier via a catapult. The gases thrust out from the jet's engines exert a constant force of 220 kN on the jet; the force exerted on the jet by the catapult is plotted in the figure b. (Figure 1)A. Determine the work done on the jet by the gases expelled by its engines during launch of the jet.
The work done on the jet by the gases expelled by its engines during launch is approximately 4.4 MJ.
To determine the work done on the jet by the gases expelled by its engines during launch, we need to use the formula for work which is W = Fd, where W is the work done, F is the force applied, and d is the displacement. In this case, we know that the force exerted by the jet's engines is 220 kN and is constant. We also know that the displacement is the distance traveled by the jet during takeoff, which is not given in the problem.
However, we can use the force exerted by the catapult as a guide. From the graph, we can see that the force exerted by the catapult starts at zero and increases linearly until it reaches a peak value of 400 kN, then drops to zero again. We can assume that the force increases at a constant rate, so we can use the average force as an estimate for the total force exerted by the catapult.
The average force is the area under the curve divided by the distance traveled, which in this case is 100 meters. Using the trapezoidal rule, we can estimate the area under the curve to be (0.5)(0+400)(100) = 20,000 Nm. Dividing this by the distance traveled, we get an average force of 200 kN.
Adding the force from the engines and the force from the catapult, we get a total force of 420 kN. If we assume that the acceleration of the jet is constant, we can use the equation F = ma to find the acceleration. Rearranging the equation, we get a = F/m = 420,000 N / 17,000 kg = 24.7 m/s^2.
Finally, we can use the kinematic equation d = 0.5at^2 to find the displacement. Since we don't know the time it takes for the jet to take off, we can use the maximum force exerted by the catapult as an estimate for the time it takes for the jet to reach its maximum speed. From the graph, we can see that the force peaks at around 20 meters, so we can assume that the displacement is around 20 meters.
Putting all of this together, we get W = Fd = (220 kN)(20 m) = 4.4 million Nm or 4.4 MJ (megajoules). Therefore, the work done on the jet by the gases expelled by its engines during launch is approximately 4.4 MJ.
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why are the frets on the neck of a guitar spaced closer together as you move up the fingerboard toward the bridge
The frets on the neck of a guitar are spaced closer together as you move up the fingerboard toward the bridge to account for the shorter length of the strings.
As you play higher notes on the guitar, the length of the vibrating string becomes shorter, and thus the distance between frets needs to be smaller to produce accurate pitch. This is because the pitch of a note is determined by the length of the vibrating string, so a shorter string length requires a shorter distance between frets. In summary, the closer spacing of the frets towards the bridge allows for more precise intonation and accurate pitch as you play higher notes on the guitar. The closer spacing of the frets towards the bridge allows for accurate pitch and intonation as you play higher notes on the guitar.
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Think about tug of war. Team X has three members who pull with the following forces: +180 N, +200 N, and + 190 N. Team Y has three members who pull with the following forces: -200 N, -180 N, and -191 N. Which team would win?
Team X would win the tug of war as they have a higher total pulling force.
In this tug of war scenario,
Team X has a total pulling force of +570 N (180 N + 200 N + 190 N), while Team Y has a total pulling force of -571 N (-200 N - 180 N - 191 N). As a result, Team X would win the tug of war since their overall pulling force is greater.
To determine which team would win in a tug of war, we need to calculate the total pulling force of each team by summing up the individual forces of all team members. In this scenario, Team X has a total pulling force of 570 N, while Team Y has a total pulling force of -571 N.
The negative sign indicates that the forces are in opposite directions, which means that the total pulling force of Team Y is actually a net force in the opposite direction. Therefore, Team X has a greater total pulling force and would win the tug of war. It is important to note that other factors such as the strength, technique, and teamwork of each team member can also play a role in determining the outcome of a tug of war.
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23. In an experiment to determine the density of a lead using a density bottle, the following readings were obtained (a) Mass of empty density bottle = 13.2g (b) Mass of density bottle filled with water = 53.2g (c) Mass of a partially filled density bottle with lead shots only = 126.1g (d) Mass of density bottle with lead shots filled up with water = 166.lg Calculate iii) iv) v) Volume of water that fills the density bottle 40g Capacity of the density bottle Mass of lead shots 112.99 Volume of lead shots Density of lead (2 marks) (1 mark) (1 mark) (1 mark) (2 marks)
Answer:To calculate the required values, we can use the formula for density: density = mass/volume.
i) Volume of water that fills the density bottle = mass of water/density of water
Mass of water = Mass of density bottle filled with water - Mass of empty density bottle = 53.2g - 13.2g = 40g
Density of water = 1g/cm³ (at room temperature and pressure)
Volume of water = 40g/1g/cm³ = 40cm³
ii) Capacity of the density bottle = Volume of water + Volume of lead shots
Volume of water = 40cm³ (calculated above)
Volume of lead shots = Volume of density bottle filled up with lead shots and water - Volume of water
Volume of density bottle filled up with lead shots and water = Mass of density bottle with lead shots filled up with water - Mass of empty density bottle
= 166.1g - 13.2g = 152.9g
Volume of lead shots and water = Volume of density bottle filled up with lead shots and water - Volume of water
Volume of lead shots and water = 152.9cm³ - 40cm³ = 112.9cm³
Assuming that the volume of water in the partially filled density bottle is negligible, we can take the volume of lead shots to be equal to the volume of the partially filled density bottle.
Capacity of the density bottle = Volume of water + Volume of lead shots = 40cm³ + 112.9cm³ = 152.9cm³
iii) Mass of lead shots = Mass of density bottle with lead shots filled up with water - Mass of density bottle filled with water
= 166.1g - 53.2g = 112.9g
iv) Volume of lead shots = Mass of lead shots/density of lead
Density of lead = 11.34 g/cm³ (at room temperature and pressure)
Volume of lead shots = 112.9g/11.34 g/cm³ = 9.96 cm³ (approximately)
v) Density of lead = Mass of lead shots/Volume of lead shots
Density of lead = 112.9g/9.96cm³ = 11.32 g/cm³ (approximately)
Therefore, the required values are:
iii) Mass of lead shots = 112.9g
iv) Volume of lead shots = 9.96cm³ (approximately)
v) Density of lead = 11.32 g/cm³ (approximately)
Explanation:
rollercoaster part 2: you are again considering your rollercoaster design, but this time want to make it even more exciting. you decide instead of having passengers ride in traditional cars, they will go in hamster-ball like vehicles, that roll along the track (note: this is a bad idea). if the balls can be treated as hollow spheres, with mass of 100 kg and a radius of 0.5 m, how high can you make your loop? (see problem 7. you may equations from your solution to that problem as some of your equations for this problem)
The maximum height of the loop in the rollercoaster design with hamster-ball like vehicles is 2.45 meters.
To determine the maximum height of the loop in the rollercoaster design with hamster-ball like vehicles, we need to calculate the minimum speed required for the ball to stay in contact with the track at the top of the loop. This is because if the speed is less than this minimum value, the ball will lose contact with the track and the passengers will fall out.
The minimum speed required for the ball to stay in contact with the track at the top of the loop is given by the centripetal force equation:
F_c = mv^2/r
where F_c is the centripetal force, m is the mass of the ball, v is the speed of the ball, and r is the radius of the loop.
At the top of the loop, the centripetal force is equal to the weight of the ball:
F_c = mg
where g is the acceleration due to gravity.
Therefore, we can write:
mg = mv^2/r
Solving for v, we get:
v = sqrt(gr)
For the ball to stay in contact with the track, the speed at the top of the loop must be equal to or greater than this minimum speed.
To calculate the maximum height of the loop, we need to find the minimum value of r that will satisfy this condition.
We know that at the top of the loop, the total energy of the ball is equal to its potential energy:
mgh = (1/2)mv^2
Substituting v = sqrt(gr), we get:
mgh = (1/2)mg^2r
Simplifying, we get:
h = (1/2)gr
Substituting m = 100 kg and r = 0.5 m, we get:
h = (1/2)(9.8 m/s^2)(0.5 m)
h = 2.45 m
Therefore, the maximum height of the loop in the rollercoaster design with hamster-ball like vehicles is 2.45 meters.
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the eccentricity of an asteroid's orbit is 0.0172, and the semimajor axis is 2.21 x 1011 m. the sun's center is at one focus of the asteroid's orbit. (a) how far from this focus is the other focus in meters? (b) what is the ratio of this distance to the solar radius, 6.96 x 108 m?
The distance from the other focus to the center of the asteroid's orbit is approximately [tex]2.19 \times 10^{11}[/tex] m. The distance from the other focus to the center of the asteroid's orbit is about 315.5 times the solar radius.
The eccentricity of an asteroid's orbit is defined as the ratio of the distance between the two foci of the ellipse to the length of the major axis of the ellipse. Therefore, we can use the given eccentricity and semimajor axis to find the distance between the foci of the ellipse.
Let's denote the distance between the two foci as 2c, and the semimajor axis as a. Then, we have:
e = c/a
0.0172 = 2c/([tex]2.21 \times 10^{11}[/tex] m)
Solving for c, we get:
c = 1.866 x [tex]10^{9}[/tex] m
Therefore, the distance from the center of the ellipse to each focus is:
f = c - a =
= [tex]1.866 \times 10^{9} m - 2.21 \times 10^{11} m[/tex]
≈ [tex]-2.19 \times 10^{11}[/tex] m
However, since one focus is at the center of the Sun, we only need to consider the positive distance:
f = c + a ≈ [tex]-2.19 \times 10^{11}[/tex] m
The ratio of this distance to the solar radius is:
ratio = f / ([tex]6.96 \times 10^{8}[/tex]m) ≈ 315.5
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Early 21st Century research in nuclear fusion use
(A) Laser beams (B) Ultra-hot plasmas
Early 21st Century research in nuclear fusion primarily used ultra-hot plasmas to achieve the conditions necessary for fusion reactions to occur.
While laser beams have also been utilized in fusion experiments, they have not been the primary method of achieving fusion reactions.
Early 21st-century research in nuclear fusion primarily uses both (A) laser beams and (B) ultra-hot plasmas. Laser beams are employed to compress and heat the fuel, while ultra-hot plasmas facilitate the fusion process. These techniques are essential in the pursuit of achieving controlled nuclear fusion for sustainable energy production.
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The table below describes some methods used to generate electricity. What is method 2?
Coastal areas can produce inexhaustible source of energy. Tidal energy can be best used to generate electricity.
How do we use the sea to make electricity?Wave energy, in which converters harness the power of ocean waves to generate electricity. Oscillating water columns that hold air pockets and drive a turbine are examples of converters; swaying body converters that utilization wave movement; and overtopping converters that take advantage of differences in height.
Which energy is most suitable for coastal development?A renewable energy source is tidal energy. In areas with a significant tidal range—the difference in area between high tide and low tide—in the 20th century, engineers developed methods for utilizing tidal movement to generate electricity.
Question incomplete:The table below describes some methods used to generate electricity. What is method 2?
Energy resource Ideal location Possible problem
1 Volcanic area None anticipated
2 Coast Hazard to shipping
3 Estuary Harm to bird populations
4 Remote area with a river valley Flooding of farmland
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telescopes being planned for the study of the earliest stages in galactic lives will be optimized for observations in ______.
According to the search results, telescopes designed to study the earliest stages in galactic lives should be optimized for observations in infrared light. This is because infrared light can penetrate through the dust and gas that obscure the formation of stars and galaxies in the early universe. Infrared light also allows astronomers to observe the redshifted light from very distant and ancient galaxies, which are moving away from us at high speeds due to the expansion of the universe. Infrared telescopes can be either ground-based or space-based, but space-based ones have the advantage of avoiding the interference from the Earth's atmosphere, which absorbs and emits infrared radiation. Some examples of infrared telescopes that are used or planned for studying the earliest stages of galactic lives are:
- The James Webb Space Telescope (JWST), which is scheduled to launch in 2021 and will observe infrared light from 0.6 to 28 micrometers in wavelength. It will have a primary mirror of 6.5 meters in diameter and will operate at a temperature of about -230°C. It will be able to study the formation of stars and galaxies, as well as the evolution of planetary systems and the origins of life.
- The Herschel Space Observatory, which operated from 2009 to 2013 and observed infrared light from 55 to 672 micrometers in wavelength. It had a primary mirror of 3.5 meters in diameter and operated at a temperature of about -271°C. It was able to study the formation of stars and galaxies, as well as the interstellar medium and the chemical composition of celestial objects.
- The Atacama Large Millimeter/submillimeter Array (ALMA), which is a ground-based array of 66 radio telescopes that observe millimeter and submillimeter wavelengths, which are part of the infrared spectrum. It is located in Chile at an altitude of about 5000 meters and has a resolution of about 0.01 arcseconds. It can study the formation of stars and galaxies, as well as the structure and dynamics of protoplanetary disks and exoplanets.
Therefore, the answer is: Telescopes designed to study the earliest stages in galactic lives should be optimized for observations in infrared light.
Telescopes being planned for the study of the earliest stages in galactic lives will be optimized for observations in the infrared part of the electromagnetic spectrum.
This is because the infrared radiation can penetrate through the dust and gas clouds that shroud the earliest stages of galaxies and allow us to see the formation of stars and galaxies that would otherwise be obscured by the dust and gas.
Infrared observations can also reveal the temperature and chemical composition of these clouds and help us understand the physical processes that lead to the formation of galaxies.
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when two waves with equal and opposite amplitude interfere what will the resulting amplitude measure
When two waves with equal and opposite amplitudes interfere, the resulting amplitude will be zero.
This is because the waves will cancel each other out completely when they combine, leading to no net displacement at any point. This phenomenon is known as destructive interference and can occur when two waves have the same frequency and are in phase opposition, meaning that they have opposite phases at any given point in time. The resulting amplitude of the combined waves can be determined by using the principle of superposition, which states that the displacement of a medium at any point is the sum of the individual displacements of all waves present at that point.
To explain this, consider two waves with the same frequency and wavelength, but with equal and opposite amplitudes. When these waves overlap, the crest of one wave aligns with the trough of the other wave. The positive amplitude of the crest cancels out the negative amplitude of the trough, resulting in a net amplitude of zero. This destructive interference leads to the cancellation of the two waves, and no observable wave remains in their place.
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IP It takes 180 J of work to compress a certain spring 0.13 m.
A)What is the force constant of this spring? Express your answer using two significant figures.
B)To compress the spring an additional 0.13 m , does it take 180 J , more than 180 J , or less than 180 J ?
C)Verify your answer with a calculation.
That it takes more than 180 J of work to compress the spring an additional 0.13 m.
What is Work?
In physics, work is defined as the product of the force applied to an object and the distance the object is moved in the direction of the applied force. In other words, work is the energy transferred to or from an object by means of a force acting on the object. The standard unit of work is the joule (J), which is defined as the amount of work done when a force of one newton is applied over a distance of one meter in the direction of the force.
A) The force constant of the spring can be calculated using the formula:
k = F/x
where k is the force constant, F is the force applied to the spring, and x is the displacement of the spring.
Given that it takes 180 J of work to compress the spring by 0.13 m, we can calculate the force applied as:
180 J = (1/2)k[tex](0.13 m)^{2}[/tex]
k = 180 J / [(1/2)[tex](0.13 m)^{2}[/tex]
k = 1742.39 N/m
Therefore, the force constant of the spring is 1742.39 N/m.
B) To compress the spring an additional 0.13 m, it would take more than 180 J of work. This is because the potential energy stored in a spring is proportional to the square of its displacement, so doubling the displacement requires four times the work.
C) To verify our answer, we can calculate the work required to compress the spring an additional 0.13 m using the same formula:
W = (1/2)(1742.39 N/m)[tex](0.26 m)^{2}[/tex]
W = 180.16 J
This confirms that it takes more than 180 J of work to compress the spring an additional 0.13 m.
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climate change serves to intensify the _______________ because as the temperature of the air increases, more water evaporates into the air.
Climate change serves to intensify the water cycle because as the temperature of the air increases, more water evaporates into the air. This leads to more precipitation, which can result in more frequent and severe storms, floods, and droughts.
Climate change is leading to an increase in global temperature, and one of the effects of this temperature rise is that more water evaporates into the atmosphere. This increase in evaporation leads to more moisture in the air, which can then lead to more intense precipitation events. This is because warmer air can hold more water vapor, which means that when the air cools, the excess moisture is released as precipitation.
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true or false: alternating regions of increased and decreased particle density travel through the material allow the sound wave to propogate
Sound waves propagate through a material by creating regions of increased and decreased particle density. The given statement is True.
These regions, called compressions and rarefactions, respectively, travel through the material and transfer energy from the source of the sound wave to the listener.
To understand how this works, we need to consider the nature of sound waves. Sound is a form of mechanical energy that travels through a medium, such as air or water. When a sound is produced, it creates a disturbance in the surrounding medium. This disturbance causes the particles of the medium to vibrate, which in turn creates pressure waves that travel through the medium.
that travel through the medium, carrying the energy of the sound wave with them.
As the pressure waves travel through the medium, they cause regions of increased and decreased particle density. In a compression, the particles are pushed together, creating an area of higher density. In a rarefaction, the particles are spread apart, creating an area of lower density.
These alternating regions of increased and decreased particle density travel through the medium, carrying the sound wave with them. The wave itself does not travel through the medium, but rather the energy is transferred through the medium by the movement of the particles.
When the sound wave reaches our ears, it causes our eardrums to vibrate in the same way as the particles of the medium. This vibration is transmitted to the inner ear, where it is converted into nerve impulses that are sent to the brain. The brain then interprets these impulses as sound.
In summary, sound waves propagate through a material by creating regions of increased and decreased particle density that travel through the medium, carrying the energy of the sound wave with them.
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Describe transformer in an experiment
Answer:
In an experimental context, a transformer is a device that is used to increase or decrease the voltage of an alternating current (AC) electrical signal. It consists of two coils of wire, known as the primary and secondary coils, that are wrapped around a magnetic core.
When an AC voltage is applied to the primary coil, it creates a magnetic field that induces a voltage in the secondary coil, which can be either higher or lower than the input voltage, depending on the number of turns in each coil.
Transformers are commonly used in electronic circuits to match the impedance of different components, to isolate circuits from one another, and to reduce noise and interference in signals. They are also used in power transmission systems to increase or decrease the voltage of electricity, allowing it to be transmitted over long distances with minimal loss.
In an experimental setup, a transformer would typically be connected to a signal generator or other electrical source, along with other components such as resistors, capacitors, and diodes, to create a circuit that can be used to study the behavior of electrical signals under different conditions. The properties of the transformer, such as its voltage ratio and frequency response, can be measured and analyzed using specialized equipment such as oscilloscopes and signal analyzers.
a 15.00-kg cylinder with a radius of 25.00 cm rotates at an angular speed of 500.00 rpm. if a 100.00-n braking force applied normal to the curved surface of the cylinder brings it to rest in 15.00 s, what is the coefficient of kinetic friction between the brake and the cylinder?
The coefficient of kinetic friction between the brake and the cylinder is 0.76.
To solve this problem, we first need to find the initial angular velocity of the cylinder in radians per second. We know that 500.00 rpm = 83.33 revolutions per second, and since the cylinder has a radius of 0.25 m, its circumference is 2π(0.25) = 1.57 m. Therefore, the initial angular velocity is:
ωᵢ = (83.33 rev/s) x (2π rad/rev) = 524.88 rad/s
Next, we need to find the moment of inertia of the cylinder about its central axis. The moment of inertia of a solid cylinder is 1/2MR², so we have:
I = (1/2)(15.00 kg)(0.25 m)² = 0.47 kg·m²
The braking force F will cause a torque τ = Fr, where r is the radius of the cylinder. Thus, we have:
τ = (100.00 N)(0.25 m) = 25.00 N·m
Using Newton's second law for rotation, we can write:
τ = Iα
where α is the angular acceleration of the cylinder. Since the braking force is in the opposite direction to the initial angular velocity, we have:
α = (ωᵢ - 0)/t = ωᵢ/t = (524.88 rad/s)/(15.00 s) = 34.99 rad/s²
Substituting into the equation for torque, we get:
25.00 N·m = (0.47 kg·m²)(34.99 rad/s²)
Solving for the coefficient of kinetic friction, we have:
μ = (2F)/(πr² ρ)
where ρ is the density of the cylinder, which we can assume is 7850 kg/m³ for steel. Substituting in the given values, we get:
μ = (2 x 100.00 N)/(π(0.25 m)²(7850 kg/m³)) = 0.76
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when u-235 undergoes fission, the total number of protons in the fragments is:____.
When U-235 undergoes fission, the total number of protons in the fragments can vary depending on the specific fission event.
However, the total number of protons in the fragments must add up to the number of protons in the original U-235 atom, which is 92.
When U-235 undergoes fission, the total number of protons in the fragments is equal to the original number of protons in the U-235 nucleus.
When U-235 undergoes fission, the total number of protons in the fragments is 92.
Uranium-235 (U-235) is an isotope of uranium, which has 92 protons in its nucleus. During fission, the U-235 nucleus splits into smaller fragments, but the total number of protons remains the same. These protons are just redistributed among the fragments produced in the fission process.
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Define gauge pressure. Define what the components of the equation arewhat happens if the incident pressure is the same as atmospheric pressure?
Gauge pressure is a term used to describe the pressure of a fluid or gas relative to the atmospheric pressure at a particular location. It is calculated by subtracting the atmospheric pressure from the total pressure exerted by the fluid or gas. The equation for gauge pressure is:
Gauge Pressure = Total Pressure - Atmospheric Pressure
The components of this equation include the total pressure, which is the sum of the atmospheric pressure and the pressure exerted by the fluid or gas, and the atmospheric pressure itself. Atmospheric pressure is the pressure exerted by the Earth's atmosphere on any surface below it due to the weight of the air above.
If the incident pressure is the same as atmospheric pressure, then the gauge pressure would be zero. This means that the fluid or gas is at the same pressure as the surrounding atmosphere and there is no excess pressure.
In practical terms, this would mean that the fluid or gas is neither under nor over-pressurized and is in a stable state. It is important to note that gauge pressure is a relative measurement and can vary depending on the location and altitude of the measuring device.
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what mass of silver plates onto the cathode when a current of 7.3 a flows through the cell for 64 min ?
Approximately 2,859.5 kg of silver plates onto the cathode when a current of 7.3 A flows through the cell for 64 minutes.
To determine the mass of silver plates onto the cathode, we need to know the amount of electric charge that passed through the cell.
Electric charge, Q = I x t, where I is the current and t is the time.
So, Q = 7.3 A x (64 x 60) s = 26,496 C
The amount of silver plated on the cathode can be calculated using Faraday's law of electrolysis, which states that the mass of a substance deposited on an electrode is directly proportional to the amount of electric charge passed through the cell and the electrode's equivalent weight.
The equivalent weight of silver is 107.9 g/equiv, and one electron is required to deposit one silver ion on the cathode.
Thus, the mass of silver plated on the cathode is:
Mass = (Q / n) x EW, where n is the number of electrons per equivalent (in this case, n = 1).
Substituting the values, we get:
Mass = (26,496 C / 1) x (107.9 g/equiv) = 2,859,526.4 g = 2,859.5 kg (rounded to one decimal place).
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which phenomenon is observed when two or more waves passing simultaneously through the same medium meet up with one another in space?
The phenomenon observed when two or more waves passing simultaneously through the same medium meet up with one another in space is known as interference.
Interference occurs when the waves interact with one another, resulting in either constructive or destructive interference depending on the phase relationship between the waves. This phenomenon can be observed in various natural and artificial systems, from the interference patterns of light in a double-slit experiment to the interference of sound waves in a concert hall.
The phenomenon observed when two or more waves pass simultaneously through the same medium and meet up with one another in space is called "interference." Interference occurs when waves combine, either constructively or destructively, depending on their relative phase and amplitude. This leads to the formation of new wave patterns as a result of the superposition of the individual waves.
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using the δg values calculated at room temperature and ice-bath temperature, does the solvation of borax favors products or reactants? explain.
The δg values calculated at room temperature and ice-bath temperature can be used to determine whether the solvation of borax favors products or reactants.
If the δg value at room temperature is negative, it means that the reaction favors the products, while if it is positive, the reaction favors the reactants. On the other hand, if the δg value at ice-bath temperature is negative, it means that the reaction favors the reactants, while if it is positive, the reaction favors the products.
Therefore, by comparing the δg values calculated at room temperature and ice-bath temperature, we can determine whether the solvation of borax favors the products or the reactants. If the δg value is more negative at room temperature than at ice-bath temperature, it means that the solvation of borax favors the products. Conversely, if the δg value is more negative at ice-bath temperature than at room temperature, it means that the solvation of borax favors the reactants.
In summary, the solvation of borax may favor the products or the reactants depending on the temperature and the δg values calculated.
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cowboy ana swings her rope, length � l, over her head in a circle parallel to the ground. a rock, mass � m is tied to the end of the rope. if she keeps the rock at a constant angular speed � ω, what angle does the rope make with the horizontal? neglect the mass of the rope.
The angle that the rope makes with the horizontal is not constant, as it depends on the radius of the circle that the rock is swinging in. However, we can use the centripetal force equation to find the radius of the circle and therefore the angle.
To find the angle that the rope makes with the horizontal when cowboy Ana swings her rope with length (l) parallel to the ground and a rock of mass (m) tied to the end at a constant angular speed (ω), follow these steps:
1. Write down the centripetal force acting on the rock, which is given by Fc = mω²l. This force is directed towards the center of the circle.
2. Write down the gravitational force acting on the rock, which is given by Fg = mg. This force acts vertically downward.
3. Break down the centripetal force into two components: one along the horizontal direction (Fc_horizontal) and one along the vertical direction (Fc_vertical).
4. Since the rock is in equilibrium in the vertical direction, we can equate the vertical component of the centripetal force to the gravitational force: Fc_vertical = Fg.
5. Now, find the angle (θ) that the rope makes with the horizontal. This can be done by using the tangent function: tan(θ) = Fc_vertical / Fc_horizontal.
6. Solve the equation for the angle θ, and you will get the angle that the rope makes with the horizontal.
To summarize, to find the angle the rope makes with the horizontal when cowboy Ana swings her rope of length (l) with a rock of mass (m) tied to the end at a constant angular speed (ω), we need to analyze the centripetal and gravitational forces acting on the rock and solve for the angle θ using the tangent function.
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the maximum allowed leakage of microwave radiation from a microwave oven is 5.0 mw/cm2 . part a if microwave radiation outside an oven has the maximum value, what is the amplitude of the oscillating electric field? express your answer with the appropriate units.
The amplitude of the oscillating electric field outside a microwave oven with the maximum allowed leakage of microwave radiation (5.0 mW/cm²) is approximately 12.6 V/m.
To calculate the amplitude of the oscillating electric field, we can use the following equation:
S = 1/2 * c * ε_0 * E_max
where S is the power density (in W/m²), c is the speed of light (3.00 x 10⁸ m/s), ε_0 is the permittivity of free space (8.85 x 10 F/m), and E_max is the amplitude of the electric field (in V/m).
Since we know that S = 5.0 mW/cm² = 50 W/m² (since 1 mW/cm² = 10 W/m²), we can rearrange the equation to solve for E_max:
E_max =
[tex] \sqrt{(2 * 50 / (3.00 * 10⁸ * 8.85 * 10^-12))}[/tex]
= 12.6 V/m
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The following table provides information about two satellites that are orbiting Earth.
Speed Mass Distance above Earth
Satellite X 3,100 m/s 1,700 kg 35,000 km
Satellite Y 3,560 m/s 1,700 kg 25,000 km
Which statement best describes the satellites?
A.
Satellite X is experiencing a greater gravitational force than satellite Y.
B.
The two satellites are too far away from Earth to experience a gravitational force.
C.
Satellite Y is experiencing a greater gravitational force than satellite X.
D.
The two satellites are experiencing the same gravitational force.
Answer:
C. Satellite Y is experiencing a greater gravitational force than satellite
Explanation:
the more closer an object is to the surface of the Earth the more gravitational for it will feel.
If you look at the equation Fg = (Gm1m2)/r^2, the smaller the r (distance between center of 2 objects) the greater the gravitational force.
A swimmer is moving at a speed of 2.0 meters/second. How long will it take for the swimmer to go 100 meters?
20 seconds
50 seconds
100 seconds
200 seconds
Explanation:
Distance / rate = time
100 m / (2.0 m/s ) = 50 s
If a swimmer is moving at a speed of 2.0 meters/second, than It will take the swimmer 50 seconds to go 100 meters.
To calculate the time it will take for the swimmer to go 100 meters, we can use the formula:
time = distance / speed
Plugging in the values given in the question, we get:
time = 100 meters / 2.0 meters/second
time = 50 seconds
In this case, the swimmer is moving at a constant speed of 2.0 meters/second, which means that the time it takes to travel a distance is directly proportional to the distance. Therefore, it takes longer to cover a longer distance at the same speed, and vice versa.
So, in this case, it will take the swimmer 50 seconds to travel 100 meters. This result is useful in predicting the swimmer's performance and estimating how long it will take for the swimmer to complete a given distance. It also helps coaches and athletes plan their training and set goals for improvement.
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what is the equation to determine the voltage drop between two points?
Answer:
V=R∗I
Explanation:
a car drives over the top of a hill that has a radius of 45 m. what maximum speed can the car have without flying off the road at the top of the hill?
Answer:
a = v^2 / R centripetal acceleration of car
If a exceeds g then the car would leave the road
v = (a R)^1/2 = (9.80 * 45)^1/2 = 21 m/s
The speed must not exceed 21 m/s
Note (60 mph = 26.8 m/s)
The maximum speed that the car can have without flying off the road at the top of the hill is approximately 30.2 m/s.
To determine the maximum speed that a car can have without flying off the road at the top of a hill, we need to consider the centripetal force and the gravitational force acting on the car.
At the top of the hill, the gravitational force acting on the car is directed downwards, while the centripetal force required to keep the car moving in a circular path is directed upwards. The maximum speed that the car can have is the speed at which the gravitational force just balances the centripetal force.
The centripetal force required to keep the car moving in a circle of radius 45 m is given by:
[tex]F_c = mv^2/r[/tex]
where m is the mass of the car, v is its speed, and r is the radius of the circle.
The gravitational force acting on the car is given by:
[tex]F_g = mg[/tex]
where g is the acceleration due to gravity and m is the mass of the car.
For the car to remain on the road at the top of the hill, the centripetal force must be equal to the gravitational force, so:
[tex]F_c = F_g[/tex]
[tex]mv^2/r = mg[/tex]
Simplifying this expression gives:
[tex]v^2 = rg\\v = \sqrt{rg}[/tex]
Substituting the values of r and g gives:
[tex]v = \sqrt{45 m * 9.81 m/s^2} v = 30.2 m/s[/tex]
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