Answer:
Below
Explanation:
Position at t = 0 = -5 (0)^2 = 0
Position at t = 3s -5 (3)^2 = -45
average velocity = (-45- 0 ) / 3s = -15 units/s
The average velocity of the particle for 0 ≤ t ≤ 3 is - 15 unit.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
Given that: the position of a particle on the x-axis at time t is = -5t².
Hence, at t = 0s; the position of the particle = 0 unit.
at t = 3s; the position of the particle = -5× 3²unit = - 45 unit.
Then, the average velocity of the particle
= (final position - initial position) time interval
= (- 45 - 0)/3 unit
= - 15 unit.
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the longer the pendulum is, the longer it takes to swing. therefore, when the pendulum of a clock is lengthened, the clock slows down.
Deductive
The conclusion follows necessarily from the premise. (The lengthening of the pendulum of a clock makes the mechanism that moves the hands of the clock slow down)
Argument, premises and conclusion
The statements that make up an argument are divided into one or more premises and exactly one conclusion. The premises are the statements that set forth the reasons or evidence, and the conclusion is the statement that the evidence is claimed to support or imply. That is, the conclusion is the statement that is claimed to follow from the premise.
Inductive and deductive argument
A deductive argument is an argument incorporating the claim that it is impossible for the conclusion to be false given that the premises are true.An inductive argument is an argument incorporating the claim that it is improbable that the conclusion be false given that the premises are true.To decide whether an argument is inductive or deductive look for
1. the occurrence of special indicator words
2. the actual strength of the inferential link between premises and conclusion, and
3. the form or style of argumentation.
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What are three ways you could cause the acceleration of a moving car?; What are the 3 different ways you can accelerate?; What causes the acceleration of a car?; What are the ways to accelerate?
The three ways to acceleration a moving vehicle are to depress the accelerator pedal, depress the brake, push the vehicle, or exert external force.
The rate at which the velocity of an object varies in relation to time is known as acceleration. Accelerations exist in vector quantities (in that they have magnitude and direction). The object's acceleration is determined by the direction of the net force acting on it. The size of the net balance of all external forces acting on the item is, in accordance with the materials used to create it, inversely proportional to its mass, but the magnitude of the net resultant force is directly proportional to the net force.
A moving object's rate of change in direction and speed over time is called acceleration. It is said to be accelerating when anything goes faster or slower. Due to the frequent change in direction, motion on a circle accelerates even while the speed is constant.
Therefore, applying the brake, pushing the car, or applying external force are the four ways to accelerate a moving vehicle. The three other methods are pressing the accelerator pedal.
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The jumper has a mass of 55 kg, and the bridge's height above the river is 150 m. The rope has an unstretched length of 8 m and stretches a distance of 5 m before bringing the jumper to a stop. Determine the maximum speed of the jumper and the spring constant of the rope. In your calculation, use g 10 N/kg. m/s Vmax k = N/m E.
Now suppose the jumper has a mass of 80 kg. Do you think the maximum speed of the jumper will increase, decrease, or stay the same? Will the rope need a larger, smaller, or the same spring constant to bring the jumper to a stop in the same distance as part D?
The speed of jumper is 54.22 m/s and spring constant of the rope is 6468N/m.
Given data:
The mass of jumper is, m = 55 kg.
The height of bridge above the river is, h = 150 m.
The length of unstretched rope is, L = 8m.
The stretched length is, L' = 5m.
In this problem, when the jumper will jump then the only potential energy of the jumper will get converted into the spring potential energy of the rope. So we can say that the relation will be,
potential energy of jumper = spring potential energy of rope.
Here, k is the spring constant.
Solving as,
mgh = 1/2 KI²
55 × 90.8 × 150 = 1/2 × k × 5 × 5k
k = 6468 N/m
Now, apply the third kinematic equation of motion to calculate the final speed of jumper as,
v² = U² + 2as
We get U= 54.22 m/s.
Thus, we can conclude that the speed of jumper is 54.22 m/s and the spring constant of the rope is 9187.5 N/m.
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in the hydrogen spectrum, the series of lines called the lyman series results from transitions to the n=1 energy level. What is the longest wavelength in this series and in which region of the electromagnetic spectrum does it lie?
According to question the longest wavelength in the lyman series and in which region of the electromagnetic spectrum does it lie is 122nm.
What is meant by Lyman series?When an electron transitions from the smallest energy level of n = 1 to n = 2 (here n is the primary quantum number), known as the Lyman series, it emits ultraviolet light from the hydrogen atom in a sequence of changes.
Breifing:Rydberg equation: 1/L = R(1/n2 - 1/m2)
where L is wavelength, R is Rydberg constant, m and n are quantum numbers of levels involved in transition.
Longest wavelength in Lyman series: n = 1, m = 2
1/L = 1.097 x 107 x (1/1 - 1/2)
L = 1.22 x 10-7 m = 122 nm
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A 5.00-g bullet is fired horizontally into a 1.20-kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.20. The bullet remains embedded in the block, which is observed to slide 0.390 m along the surface before stopping. What was the initial speed of the bullet?
The initial speed of the bullet is 2624.7 m/s.
Conservation of momentum indicates that the total momentum of an isolated system remains the same in the absence of an external force. H. Momentum is neither created nor destroyed, but can be changed by the action of forces in the sense of Newton's laws of motion.Momentum is the product of an object's mass and its velocity, which is also equal to the total force required to keep the object at rest.One of the practical aspects of momentum conservation is the collision problem where momentum is conserved and the net external force remains zero.Mass of bullet, m = 5 g = 0.005 kg
Mass of block, M = 1.2 kg
Coefficient of friction = 0.2
Distance, d = 0.31 m
Let the initial speed of the bullet is u.
Use Conservation of momentum
m u = (M + m) v
0.005 x u = (1.2 +0.005) v
v = 4.2 x 10-4 u m/s
Now, use third equation of motion
v2 = u2 - 2μg s 0 = (4.2 x 10-4 u)2 - 2 x 0.2 x 9.8 x 0.31u = 2624.7 m/s
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a spring scale shows a net force of 0.8 n acting on a 1.5-kg mass. what happens to the acceleration of the object if the net force is decreased to 0.2 n?(1 point)
Answer:
0.4m/s²
Explanation:
force = 0.8–0.2 = 0.6N
mass = 1.5kg
acceleration = ?
force = mass × acceleration
f = m × a
a = f/m
a = 0.6/1.5
a= 0.4 m/s²
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part b in another experiment, the intensity of the incident light and the temperature of the metal are held constant. assuming that the initial light incident on the metal surface causes electrons to be ejected from the metal, what happens if the frequency of the incident light is increased? check all that apply. view available hint(s)for part b in another experiment, the intensity of the incident light and the temperature of the metal are held constant. assuming that the initial light incident on the metal surface causes electrons to be ejected from the metal, what happens if the frequency of the incident light is increased?check all that apply. the work function of the metal increases. the number of electrons emitted from the metal per second increases. the maximum speed of the emitted electrons increases. the stopping potential increases.'\
Because whilst depth of incident mild will increase, it approach that wide variety of photons will increase in incident mild.
If wide variety of incident photons will increase, then wide variety of emitted picture graph electrons additionally will increase, therefore the picture graph electric powered contemporary will increase.
The photoelectric impact. In the photoelectric impact, mild waves (pink wavy lines) hitting a steel floor motive electrons to be ejected from the steel.
Current in picture graph electric powered impact is immediately proportional to the depth of the incident mild. paintings function, preventing potential, most kinetic electricity are unbiased of depth of incident mild, they rely upon the frequency, wavelength of the incident mild and cloth of the steel.
Using L for luminosity, the depth of mild system becomes I=LA I = L A . Because mild waves unfold in all directions, to correctly calculate mild depth, the denominator withinside the system have to be the floor vicinity of a sphere. In fact, maximum electromagnetic calculations are achieved over a sphere.
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Miguel (m=72) and Fernando (89 kg) board the bumper cars at the local carnival. Miguel is moving at a velocity of 4 m/s when he rear-ends Fernando who is at rest in his path. Fernando and his 125-kg car lunge forward at 2 m/s. Determine the post-collision velocity of Miguel and his 125-kg car.
Moving at 1.2 m/s inside the opposite direction following the collision.
Define collision.
A collision in physics is any situation in which two or more bodies quickly exert forces on one another. Despite the fact that the most common usage of the word "collision" refers to situations in which two or more objects clash violently, the scientific usage of the word makes no such assumptions.
The law of momentum conservation can be used to calculate Miguel's post-collision velocity.
Mass times velocity equals momentum, that is a vector quantity (p=mv). Well before collision, the system's momentum.
Miguel and Fernando's car—was equal to 782 kg*m/s (m1=72 kg) (v1=4 m/s) + (m2=125 kg) (v2=0 m/s). Just after collision,
The system's momentum is equal to 782 kg*m/s (m1=72 kg) (v1=? m/s) + (m2=125 kg) (v2=2 m/s).
We can calculate Miguel's post-collision velocity to be -1.2 m/s by solving for v1.
Miguel is therefore moving at 1.2 m/s inside the opposite direction following the collision.
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Problem 2: Students of College Physics use an experimental set-up like the one shown, except, of course, the cut-away section to aid visualization is only in the drawing. A cylinder with a d=11.43cm inner diameter and an hmax=15.56cm height is placed on a heating plate. A weighted circular disc fits snugly into the cylinder, creating a gas-tight seal; the combined mass of the disc and the weights it supports is 19.07kg.50% Part (a) The disc initially rests on the bottom of the cylinder, but argon gas is introduced through a valve until the bottom of the disc is at a height h0 which is 41.9% of hmax. How much argon gas, in moles, is in the cylinder if it has a temperature of 22.1∘C? (Assume that the gas in the cylinder approximates an ideal gas.)50% Part (b) Suppose an additional mass of 5.56kg is placed on the disc, but at the same time, the heating plate is used to heat the gas in the cylinder. If the height of the disc above the cylinder bottom is now 87.8% of hmax, then what is the change in the temperature, in degrees Celsius, of the gas?
(a) The amount of argon gas in the cylinder is approximately [tex]\rm \(4.09 \times 10^{-5}\)[/tex] moles.
(b) The change in temperature of the gas is approximately 976.7°C.
Part (a):
Given data:
Inner diameter of the cylinder (d) = 11.43 cm = 0.1143 m
Height of the cylinder ([tex]h_{max[/tex]) = 15.56 cm = 0.1556 m
Height of the disc above the bottom of the cylinder ([tex]h_0[/tex]) = 41.9% of h_max = 0.419 * 0.1556 m
Combined mass of the disc and weights (m) = 19.07 kg
Temperature of the gas (T) = 22.1°C = 22.1 + 273.15 = 295.25 K
We need to find the amount of argon gas in moles in the cylinder.
Step 1: Calculate the volume of the gas in the cylinder.
[tex]\[ V_{\text{gas}} = \pi \left(\frac{d}{2}\right)^2 \times h_0 \]\\\\\ V_{\text{gas}} = \pi \left(\frac{0.1143}{2}\right)^2 \times 0.419 \times 0.1556 \]\\\\\ V_{\text{gas}} \approx 0.00121 \, \text{m}^3 \][/tex]
Step 2: Calculate the number of moles of argon gas using the ideal gas law.
[tex]\[ PV = nRT \][/tex]
Where P is the pressure of the gas (we assume it is constant), V is the volume of the gas, n is the number of moles, R is the universal gas constant (8.314 J/(mol·K)), and T is the temperature in Kelvin.
[tex]\[ n = \frac{PV}{RT} \]\\\\\ n = \frac{1 \times 0.00121}{8.314 \times 295.25} \]\\\\\ n \approx 4.09 \times 10^{-5} \, \text{moles} \][/tex]
Part (b):
Given data:
Additional mass placed on the disc ([tex]m_{extra[/tex]) = 5.56 kg
New height of the disc above the bottom of the cylinder (h_new) = 87.8% of h_max = 0.878 * 0.1556 m
We need to find the change in the temperature of the gas.
Step 1: Calculate the new volume of the gas in the cylinder.
[tex]\[ V_{\text{gas\_new}} = \pi \left(\frac{d}{2}\right)^2 \times h_{\text{new}} \]\\\\\ V_{\text{gas\_new}} = \pi \left(\frac{0.1143}{2}\right)^2 \times 0.878 \times 0.1556 \]\\\\\ V_{\text{gas\_new}} \approx 0.00178 \, \text{m}^3 \][/tex]
Step 2: Use the ideal gas law again to find the new temperature of the gas.
[tex]\[ n_{\text{new}} = \frac{P \times V_{\text{gas\_new}}}{RT_{\text{new}}} \]\\\\\\ T_{\text{new}} = \frac{P \times V_{\text{gas\_new}}}{n_{\text{new}} \times R} \]\\\\\ T_{\text{new}} = \frac{1 \times 0.00178}{4.09 \times 10^{-5} \times 8.314} \]\\\\\ T_{\text{new}} \approx 1271.95 \, \text{K} \][/tex]
Change in temperature:
[tex]\[ \Delta T = T_{\text{new}} - T \]\\\\\ \Delta T = 1271.95 - 295.25 \]\\\\\ \Delta T \approx 976.7 \, \text{K} \][/tex]
Result:
(a) The amount of argon gas in the cylinder is approximately [tex]\rm \(4.09 \times 10^{-5}\)[/tex] moles.
(b) The change in temperature of the gas is approximately 976.7°C.
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Wheel A has three times the moment of inertia about its axis of rotation as wheel B. Wheel B's angular speed is four times that of wheel A.
A) Which wheel has the greater rotational kinetic energy? A,B, Both wheels have the same rotational KE
B) If KA and KB are the rotational kinetic energies of the wheels, what is KA/KB?(express answer to 4 sig fig)
Wheel A has 3 times the moment of inertia as wheel B. Meanwhile Wheel B's angular speed is 4 times that of wheel A.
Wheel B has the greater rotational kinetic energyIf KA and KB are the rotational kinetic energies of the wheels, KA/KB is 0.188The moment of inertia is a quantitative measur of the rotational inertia of a body. The moment of inertia (I) is always specified with respect to the rotation axis.
Rotational kinetic energy is a form of kinetic energy that is caused by the rtation of an object. Rotational kinetic energy formula is:
K = 1/2 Iω²
where:
I = the moment of inertia
ω = angular velocity
From the case, we know that:
I(A) = 3 x I(B)
ω(B) = 4 x ω(A)
Using the Rotational kinetic energy formula, we could find the rotational kinetic energy for each wheelsby respecting the result to wheel B:
Wheel A
K(A) = 1/2 I(A).ω(A)²
K(A) = 1/2 [3I(B)] [1/4.ω(B)]²
K(A) = 1/2 [3I(B)] [1/16.ω(B)²]
K(A) = 3/32 I(B).ω(B)²
K(A) = 0.094 I(B).ω(B)²
Wheel B
K(B) = 1/2 I(B)ω(B)²
K(B) = 0.5 I(B)ω(B)²
From the comparison between both rotational kinetic energi, we know that K(A)<K(B). Hence wheel B has the greater rotational kinetic energy.
Then, KA/KB is:
KA = 0.094 I(B).ω(B)²
KB 0.5 I(B).ω(B)²
KA/KB = 0.188
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find the work done be the force field f in moving an object along the curve pictured in the graph. do this by computing the work on each piece-wise smooth portion of c.
Find the amount of labor necessary to move an object along the specified orientated curve given the force field F. y = 3x2 on the parabola from (0, 0) to F = (y, x) (4, 48).
How can you determine the work a force field performs along a curve?A variable force's infinitesimal work can be defined in terms of the force's components and the displacement along the path,
How do you assess the force field F's work?(c) Next, determine the work that the force field F performed on the object to move it through the field by moving it along the vector d. W = F d is the formula for work.
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A skier starts from rest at the top of a hill. The skier coasts down the hill and up a second hill, as the drawing illustrates. The crest of the second hill is circular, with a radius of r=36 m. Neglect friction and air resistance. What must be the height h of the rst hill so that the skier just loses contact with the snow at the crest of the second hill?
(Hint: Here you may want to use both energy conservation and force methods as part of your solution. In any case you should identify what forces would be directed radially inwards when the skier is at the crest of the second hill and remember that these are the forces that would generate the skier's centripetal acceleration. Of these forces, which would vanish if contact between the skier and the hill was lost? This force might then be set to zero in the solution.)
Now that we are aware that the skier won't lose contact on the second slope, h = 16.35m
How to find the calculation?Since all of the energy is conserved in this situation, the motion of the skier from the first hill to the second hill may be explained by energy conservation.
Final kinetic energy = starting potential energy
hence, we have
mgh = 1/2 * m * v ^ 2
Now that we are aware that the skier won't lose contact on the second slope, we
(m * v ^ 2)/R = mg
v ^ 2 = Rg
now that we
R = 32.7m
v ^ 2 = 32.7 * 9.8
v = 17.9m/s
the result of the above equation is
mgh = 1/2 * m * v ^ 2
h = (v ^ 2)/(2g) (2g)
h = (17.9 ^ 2)/(2(9.81))
h = 16.35m.
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What force causes a box in a moving car to accelerate?
The friction between the box and the floor of the car causes the box to accelerate with the car.
Friction is defined as the resistance offered by surfaces in contact as they move around each other.
Friction is caused by irregularities in the two surfaces that are in contact. So when one object moves over another, these irregularities in the surface become entangled, causing friction. The greater the roughness, the more irregularities and the more pronounced the friction.Friction can slow down a car as it moves down the road, but it's also the force that allows the car to move forward in the first place.
It is the frictional force that prevents the tires from sliding on the road. So it is the force of friction that makes the car accelerate forward and also slows down to a stop.If the floor of the car is frictionless, then the box would appear to move backwards, because the cabinet would actually be stationary while the car was moving away from it.
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250 students sit in an auditorium listening to a physics lecture. because they are thinking hard, each is using 125 w of metabolic power, slightly more than they would use at rest. an air conditioner with a cop of 7.5 is being used to keep the room at a constant temperature. What minimum electric power must be used to operate the air conditioner?
The minimum electric power that must be used to operate the air conditioner is 6250 W.
The total students in the auditorium are n = 250
The metabolic power each student is using is p = 125 W
The coefficient of performance ( COP ) of the air conditioner is given as 5 to maintain a constant temperature inside the auditorium.
Let the minimum electric power that must b used to run the air conditioner be P.
We know that
COP = np / P
P = np / COP
= ( 250x 125 ) / 5
= 6250W
So, 6250 W power is the minimum power.
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arrange the selected events in the model of the early universe in chronological order, from earliest to latest.
Universe in chronological order,Inflation, Separation 2 fundamental forces, Formed subatomic, Nucleosynthesis and Formation of first stars.
Mystics, theologians, philosophers, and scientists can all have different perspectives on the universe. In science, we take the slow approach and only accept claims that can be verified through experiment or observation. The General Relativity Theory, which Albert Einstein developed, explains the relationships between mass, energy, space, and time. Einstein demonstrated how well his theory fits with a homogeneous distribution of matter in space. He made the unquestioned assumption that the universe is static and constant on a grand scale. Alexander A. Friedmann, a Russian theorist, discovered in 1922 that Einstein's universe is unstable and will expand or contract with even the smallest perturbation. Vesto M. Slipher of Lowell Observatory was gathering the initial proof that galaxies are actually separating at the time.
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Many satellites move in a circle in the Earth's equatorial plane. They are at such a height above the Earth's surface that they always remain above the same point. Such an orbit is said to be geosynchronous. Find the altitude of these satellites above the Earth's surface.
a) The altitude of these satellites above the Earth's surface is h = 3,588 10⁷ m , b) by the curve of the planet; consequently, the signals cannot reach these places
What is law of universal gravitation?
For this issue we must use the law of universal gravitation, with Newton's second law
F = m a
G m M / r² = m a (1)
Centripetal acceleration
a = v² / r
How the speed (speed) module is constant
v = d / t
Circle the distance in a complete orbit with a time (T) called period
d = 2π r
v = 2π r / T
a = (4π² r² / T²) / r
We substitute in equation 1
G M / r² = 4π² r / T²
G M / r³ = 4π² / T²
r = ∛ GM T² / 4π²
R is the distance from the center of the earth, the distance from the surface is
R = Re + h
Re + h = ∛ GM T²/ 4π²
h = ∛(G M T²/4π²) - Re
Let's reduce to SI units
T = 1 day (24h / 1 day) (3600s / 1h)
T = 86400 s
Let's calculate
h = ∛ (6.67 10⁻¹¹ 5.98 10²⁴ (8.6400 10⁴)² / 4π²) - 6.37 10⁶
h = ∛ (75.42 10²¹) - 6.37 10⁶
h = 4,225 10⁷ - 0.637 10⁷
h = 3,588 10⁷ m
b) In the attached you can see that for very large latitudes the linear path from the satellite to the earth is interrupted, by the curve of the planet; consequently, the signals cannot reach these places.
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this photograph shows three rock layers separated by two disconformities, as exposed in the walls of the grand canyon. one disconformity is above the reddish lens of devonian sedimentary rocks, and the other disconformity is below the reddish lens of devonian sedimentary rocks. drag the events so that they are in the correct order, from oldest at the bottom (6) to youngest at the top (1).
1 . Erosion that formed the Grand Canyon in which the layers are exposed
2. Deposition of Devonian ‘sedimentary rocksDeposition of the Mississippian Limestone .
3 .Withdrawal of the seas and erosion that formed the lower disconformity
4. Deposition of Cambrian Limestone.
Sedimentary rocks form at or near the surface of the earth, in contrast to metamorphic or igneous rocks that form deep within the earth. The main geological processes leading to the formation of sedimentary rocks are erosion, weathering, dissolution, precipitation and petrification.
Erosion and weathering include the effects of wind and rain that slowly break large rocks down into smaller rocks. Erosion and weathering turn rocks and even mountains into sediments such as sand and mud. Dissolution is a form of weathering, chemical weathering. During this process, the slightly acidic water slowly wears away the stone. These three processes create new sedimentary rock sources.
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volume of right circular cone; volume of cone; how to find volume of a cone; cone formula
The volume of the right circular cone is given by the formula πR²H/3.
A right circular cone is a kind of cone in which the centre of the circular base of the cone is perpendicular to the vertical height of the cone.
The volume of any right circular cone is generally given by the formula,
V = πR²H/3
Where,
V is the volume of the right circular cone,
R is the radius of the circular base of the right circular cone.
H is the vertical height of The right circular cone.
π is a constant that has a valued 22/7.
In any general case when we are given the value of the radius of the circular base of the right circular cone and the height of the right circular cone, then we can just simply put the values in the above mentioned formula and we get the volume of the right circular cone.
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This one is a challenge
A motorcycle traveled north along a straight path for 2.22 hours with an average velocity of 67.8 km/h, stopped for 20.0 min, then traveled north for 3.33 hours with an average velocity of 77.7 km/h.
What is the average velocity for the trip?
What is the displacement for the entire trip?
Answer:
Explanation:
1 track section:
V₁ = 67.8 km/h
t₁ = 2.22 h
2nd track section:
V₂ = 0 km/h
t₂ = 20.0 min = (1/3) h ≈ 0.33 h
3 track section:
V₃ = 77.7 km/h
t₃ = 3.33 h
___________
V - ?
D - ?
Length of 1 track section:
D₁ = V₁·t₁ = 67.8·2.22 ≈ 150.5 km
Length 2 sections of track:
D₂ = V₂·t₂ = 0·0.33 = 0 km
Length 3 sections of track:
D₃ = V₃·t₃ = 77.7·3.33 ≈ 258.7 km
Summary path:
D = D₁ + D₂ + D₃ = 150.5 + 0 + 258.7 = 409.2 km
Total time:
t = t₁ + t₂ + t₃ = 2.22 + 0.33 + 3.33 = 5.88 h
Average speed:
V = D / t = 409.2 / 5.88 ≈ 69.6 km/h
a negative feedback system has the forward path transfer function g and feedback path transfer function h indicated below. you wish to add a controller gc to the system in cascade compensation with the plant, which means it is in the forward path. if gc has the form indicated below, and assuming the gain k is positive, what is the upper limit on the value of k? use the frequency response methods to find your answer.
The best technique to determine a system's response at a specific frequency is to drive the system being tested with a sine wave at the target frequency while keeping an eye on the relevant system output (s).
How does frequency response analysis work?
The process of measuring points on the frequency response of a transfer function or impedance function using a sinusoidal test signal is known as frequency response analysis. The fundamental configuration of a sine wave being applied to a system with a transfer function G is represented in Figure 1 (s).
The significance of frequency response analysis?
Frequency response analysis is frequently required with many modern electrical designs to make sure they meet performance standards. You can examine how the outputs of your circuit designs respond to a wide range of various frequency inputs using this area of signal characterisation.
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when your car accelerates away from a stop sign, you feel like you're being pushed back into your seat.
No, when your car accelerates away from a stop sign, you feel like you're being pushed back into your seat. There is no force pushing you backward, just the seat pushing forward.
In the inertial reference frame, the only force acting on occupants while sitting inside the accelerating car is the force that causes occupants to accelerate which is given by mass times the acceleration. So from the inertial reference frame occupant accelerates.
What is the acceleration?
One of the important notions like Speed and Velocity, in Physics that is used to explain motion and to solve problems concerned to it, is called the acceleration.
No, when your car accelerates away from a stop sign, you feel like you're being pushed back into your seat. There is no force pushing you backward, just the seat pushing forward.
In the inertial reference frame, the only force acting on occupants while sitting inside the accelerating car is the force that causes occupants to accelerate which is given by mass times the acceleration. So from the inertial reference frame occupant accelerates.
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a baseball leaves the bat at 76m/s, 57 degrees above the horizontal. how long is it in the air
So the time taken that the ball stays in the air was found to be 13 seconds.
what is a baseball used for ?
One of the most recognisable and crucial pieces of baseball equipment is the baseball. Every player on the field frequently uses baseballs, which are employed as the game's basic tool. There would be no game if there were no baseballs.
t = vsin∅/g
t = 76 sin 57/9.81
t = 76(0.8387)/9.81
t=63.741/9.81
t=6.497≈6.5
As the time taken for the ball for going up and down will be
2t=(6.5)2
=13
so the time that the ball stays in the air was found to be 13 seconds
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A square loop of wire lies in the plane of the page and carries a current I as shown. There is a uniform magnetic field Vector B parallel to the side MK as indicated. The loop will tend to rotate: A. about PQ with KL coming out of the page B. about PQ with KL going into the page C. about RS with MK coming out of the page D. about RS with MK going into the page E. about an axis perpendicular to the page.
The correct option A. about PQ with KL coming out of the page B; for the direction of the rotation of the loop for the uniform magnetic field.
Explain the term uniform magnetic field?The field lines must be both parallel and equally spaced in order for the region under examination to have a uniform magnetic field, which must have the same strength and direction throughout.If the magnetic field's lines are parallel, the magnetic field's intensity will be the same at every place, meaning the field's strength will be constant.Assume that the X and Y axes are, respectively, along OQ and OR.
Since the current in MK is along B, F(MK) = 0.Since the current in LN is the opposite of B, F(LN) = 0.The two forces, F(KL) and F, have different lines of attack (MN).
The angle of perpendicularity between F(KL) and F(MN) is l.
As a result, the square loop will revolve around PQ, with KL emerging from the page.
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The diagram for the question is given -
water flows at a rate of 2.5 m/s over a flat plate that is parallel to the oncoming flow. (a) determine the approximate location downstream of the front of the plate where the boundary layer becomes turbulent. assume that this occurs at a reynolds number rex
The boundary layer thickness is 7.92 x 10^(-3) m.
A) Formula for Reynolds number to reflect this question is given as;
R_e = Vx/v
Where;
V is velocity
x is polar coordinate where the boundary layer will become turbulent.
R_e is reynolds number.
Reynolds number for turbulent flow of flat plates has a value of 5 x 10^(5)
v is kinematic velocity
From water tables at standard conditions, kinematic viscosity is 1.12 x 10^(-6) m²/s
Now, R_e = Vx/v
We are looking for x, so let's make x the subject.
x = v•R_e/V
Thus, plugging in the relevant values to obtain;
x = [1.12 x 10^(-6) x 5 x 10^(5)]/0.5
x = 1.12m
The boundary layer thickness at the point where the flow becomes turbulent is given by;
δ = 5√(vx/V)
Where;
V is velocity
x is polar coordinate where the boundary layer will become turbulent.
R_e is reynolds number.
Reynolds number for turbulent flow of flat plates has a value of 5 x 10^(5)
v is kinematic velocity
Plugging in the relevant values to get ;
δ = 5√(1.12 x 10^(-6)•1.12/0.5)
δ = 5√(2.5088 x 10^(-6)
δ = 7.92 x 10^(-3) m
Therefore, the boundary layer thickness is 7.92 x 10^(-3) m.
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What are acceleration vs. time graphs?
The acceleration versus time graphs are the mathematical representation of the variation of acceleration with time.
There are several methods of representing the variation of two quantities one such method is graphs.
When the variation of the acceleration of the object and the time taken by the object to reach at acceleration are plotted on a graph the provides us with a few certain quantities.
For an example the slope of the acceleration-time graph tell us about the sudden change in acceleration at that particular instant.
Also the area under the acceleration vs. time graph represents the change in velocity of the object.
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the vectors d and e are [-4,1] and [1,4] respectively .find the angle b/n and e (Use dot product )
light with a wavelength of 360 nm shines on a metal surface, which emits electrons. the stopping potential is measured to be 1.15 v.What is the maximum speed of emitted electrons?
Calculate the work function?
Identify the metal.
Maximum speed of emitted electrons is [tex]5.51 * 10^{-19} m/s[/tex] and work function is [tex]1.84 * 10^{-19}[/tex]eV.
We know that maximum speed of emitted electrons is given by: [tex]\frac{hc}{\alpha }[/tex]
where, h = planck's constant = [tex]6.62* 10^{-34}[/tex]
c = speed of light = [tex]3 * 10^{8} m/s[/tex]
[tex]\alpha[/tex] = wavelength = 360 nm = [tex]3.6 * 10^{-9} m[/tex]
Putting these values in above equation we get E = [tex]5.51 * 10^{-19} m/s[/tex] .
Also work function is given by: W = eV
where, W = work function
e = charge of electron = [tex]1.6 * 10^{-19} C[/tex]
V = stopping potential = 1.15v
Putting these values in above equation we get W = [tex]1.84 * 10^{-19}[/tex] eV.
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Without collecting any data, describe the motion of the puck while it is on the curved portion of the ramp - is it more similar to motion with constant velocity or motion with constant acceleration? Explain your reasoning. Assume we can ignore friction.
A constant acceleration for an object guarantees that its velocity will change continuously throughout time and not remain constant.
What parallels exist between acceleration and speed?Similarities.Acceleration and velocity are both vector quantities, meaning they have both a magnitude and a direction.Both expressions are capable of being zero, positive, or both.
What are the parallels and differences between acceleration and velocity?The rate at which in displacement is known as velocity.The rate at which velocity changes is called acceleration.Due to the fact that it includes both magnitude and direction, velocity is an vector quantity.As the rate at which velocity changes, acceleration is likewise a vector quantity.
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aftershocks are very dangerous because: multiple choice they occur in random patterns unrelated to the location of the main quake. they are usually larger than the original earthquake. they nearly always generate a tsunami. they collapse structures damaged by the main quake.
Aftershocks are very dangerous because they collapse structures damaged by the main earthquake.
When an earthquake occurs, they usually tends to break the base of the structures.
This phenomena makes the structure very weak.
The aftershock that are generated because of the main earthquake breaks the already weak structures completely.
If there are any chances of survival of any mankind after the main earthquake, they are completely eliminated because of the after shocks created. This is why we can conclude that aftershocks are very dangerous because of their tendency to collapse the structure damaged by the earthquake.
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A parallel plate capacitor using a dielectric material having a dielectric constant of 2.5 has a plate separation of 1-mm. If another material having a dielectric constant of 4.0 is used and the capacitance is to be unchanged, what must be the new spacing between the plates?
The new spacing between the plates is 1.6mm
What is capacitor?
A capacitor is a device that uses the accumulation of electric charges on two nearby surfaces that are electrically isolated from one another to store electrical energy in an electric field. It has two terminals and is a passive electrical component. The effect of a capacitor is known as capacitance.
What is dielectric constant?
A substance or material's capacity to hold electrical energy is indicated by its dielectric constant. It is a measurement of how much electric flux a substance can hold or concentrate.
Dielectric constant k = 2.5
Separation between the plates d = 1 mm
Dielectric constant k ' = 4
let new separation between the plates = d '
We know C = k A / d
In both cases C ,A are constant .
So, ( k ' / k ) = ( d ' / d)
d ' = d ( k ' / k )
= 1.6 mm
The new spacing between the plates is 1.6mm
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