an organic compound on analysis yielded 2.04g carbon, 0.34g hydrogen, 2.73g oxygen. calculate the empirical formula
Answer:
CH2O
Explanation:
According to this question:
C = 2.04g
H = 0.34g
O = 2.73g
First, we divide the mass value of each element by its atomic mass to convert to moles.
C = 2.04g ÷ 12 = 0.17mol
H = 0.34g ÷ 1 = 0.34mol
O = 2.73g ÷ 16 = 0.17mol
Next, we divide by the smallest mole value (0.17):
C = 0.17mol = 0.17 = 1
H = 0.34mol ÷ 0.17 = 2
O = 0.17mol ÷ 0.17 = 1
The whole number ratio of C,H,O is 1:2:1, hence, the empirical formula is CH2O.
WHAT IS PHOTOSYNTHESIS??
Answer:
the process by which green plants and some other organisms use sunlight to synthesize nutrients from carbon dioxide and water. Photosynthesis in plants generally involves the green pigment chlorophyll and generates oxygen as a by-product.
Answer:
the process by which green plants and some other organisms use sunlight to synthesize nutrients from carbon dioxide and water. Photosynthesis in plants generally involves the green pigment chlorophyll and generates oxygen as a by-product.
A balloon, inflated in an air-conditioned room at 27.0°C, has a volume
of 4.50.L. It is heated to a temperature of 57.0°C. What is the new
volume of the balloon if the pressure remains constant?
Answer:
4.95L
Explanation:
Using Charle's law equation;
V1/T1 = V2/T2
Where;
V1 = initial volume (L)
V2 = final volume (L)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the question, the following information was given:
V1 = 4.50L
V2 = ?
T1 = 27°C = 27 + 273 = 300K
T2 = 57°C = 57 + 273 = 330K
Using V1/T1 = V2/T2
4.50/300 = V2/330
Cross multiply
300 × V2 = 4.5 × 330
300V2 = 1485
V2 = 1485 ÷ 300
V2 = 4.95L
Answer the two questions for 15pts
Answer:
For 1: 6.68 g of nitrogen dioxide will contain [tex]8.73\times 10^{22}[/tex] number of molecules
For 2: The given amount of nitrogen dioxide molecules has a mass of 41.31 g.
Explanation:
According to the mole concept:
1 mole of a compound contains [tex]6.022\times 10^{23}[/tex] number of molecules
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)
For 1:We are given:
Mass of nitrogen dioxide = 6.68 g
Molar mass of nitrogen dioxide = 46 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of nitrogen dioxide}=\frac{6.68g}{46g/mol}=0.145mol[/tex]
Using above concept:
If 1 mole of a compound contains [tex]6.022\times 10^{23}[/tex] number of molecules
So, 0.145 moles of nitrogen dioxide will contain = [tex](0.145\times 6.022\times 10^{23})=8.73\times 10^{22}[/tex] number of molecules
Hence, 6.68 g of nitrogen dioxide will contain [tex]8.73\times 10^{22}[/tex] number of molecules
For 2:We are given:
Molecules of nitrogen dioxide = [tex]5.41\times 10^{22}[/tex] molecules
Using the above concept:
If [tex]6.022\times 10^{23}[/tex] number of molecules are present in 1 mole of a compound
So, [tex]5.41\times 10^{22}[/tex] number of molecules will be present in = [tex]\frac{1mol}{6.022\times 10^{23}}\times 5.41\times 10^{22}=0.898[/tex] moles of nitrogen dioxide
We know, molar mass of nitrogen dioxide = 46 g/mol
Using equation 1:
[tex]0.898mol=\frac{\text{Mass of nitrogen dioxide}}{46g/mol}\\\\\text{Mass of nitrogen dioxide}=0.898mol\times 46g/mol=41.31g[/tex]
Hence, the given amount of nitrogen dioxide molecules has a mass of 41.31 g.
Which is TRUE about the structure of the atom? Select all that apply.
a
the densest part of the atom is the nucleus of the atom
b
the outermost part of the atom is where electrons are found
c
the nucleus of the atom is where protons and neutrons are found.
d
the outer part of the atom is called the antinucleus.
e
the nucleus of the atom has a diameter of about 10-10 m.
Which statement about biogeochemical cycles is true?
O A. Plants are a part of the nitrogen and carbon cycles, but not the
water cycle.
O B. Plants are a part of the nitrogen, carbon, and water cycles.
O c. Plants are a part of the water and carbon cycles, but not the
nitrogen cycle.
D. Plants are a part
carbon cycle.
the water and nitrogen cycles, but not the
Answer: The answer is D:
Answer:
The answer is Option D
a beam balance is called a first class lever why?
Answer:
A beam balance is an example of a first class lever.
Explanation:
A beam balance is an example of a first class lever. In a first class lever, the fulcrum is between the effort (force) and the load. The effort (force) moves over a large distance to move the load a smaller distance.
Other examples of first class lever are pliers, scissors, a crow bar, a claw hammer, a see-saw and a weighing balance etc.
El suero fisiológico tiene una concentración de 8,78 gr/lt. Calcula la masa de NaCl que ingresa en el organismo de un paciente al que se le administra suero durante 4 hs con una velocidad de goteo de una gota por segundo (Volumen gota: 0,05 ml)
Un paciente que recibe suero fisiológico a una velocidad de infusión de 1 gota = 0,05 ml por segundo recibirá en 5 horas 790 grs de NaCl, tomando en cuenta que la solución acuosa de suero fisiológico contiene 0,878 grs/mL de NaCl.
Explicación
Los datos que se tienen son:
Concentración de NaCl 0,878 grs/mlVolumen de la gota: 0,05 ml/gotaVelocidad de infusión 1 gota/ seg = 60 gotas/ min = 3 ml/minTiempo de infusión = 5 horas = 300 minutosYa establecidas las respectivas conversiones se trata de determinar qué volumen de suero fisiológivo se ha infundido al paciente en 5 horas
Si se infunden 3 ml cada minuto, ¿Cuánto se habrá infundido en 300 minutos?
3 ml ______________ 1 min
X ________________ 300 min
X = (300 min x 3 ml) / 1 min
X = 900 ml
Como en 5 horas el paciente ha recibido 900 ml de suero, se determina la cantidad de NaCl que se encuentra en ese volumen de líquido
0,878 grs __________ 1 ml
X ________________ 900 ml
X = (900 ml x 0,878 grs) / 1 ml
X = 790 grs de NaCl
8. A saturated solution of Ag Croq has a silver-ion concentration of 1.3 x 10-4M. Which is the Ksp of Ag CrO 4?
O 1.3 x 10-4
O 3.9 x 10-12
O 6.5 x 10-5
O 1.1 x 10-12
Answer: The [tex]K_{sp}[/tex] of [tex]AgCrO_{4}[/tex] is [tex]1.1 \times 10^{-12}[/tex].
Explanation:
Given: [tex][Ag^{+}] = 1.3 \times 10^{-4} M[/tex]
The reaction equation will be written as follows.
[tex]Ag_{2}CrO_{4} \rightleftharpoons 2Ag^{+} + CrO^{2-}_{4}[/tex]
This shows that the concentration of [tex]CrO^{2-}_{4}[/tex] is half the concentration of [tex]Ag^{+}[/tex] ion. So,
[tex][CrO^{2-}_{4}] = \frac{1.3 \times 10^{-4}}{2}\\= 0.65 \times 10^{-4} M[/tex]
The expression for [tex]K_{sp}[/tex] of this reaction is as follows.
[tex]K_{sp} = [Ag^{+}]^{2}[CrO^{2-}_{4}][/tex]
Substitute values into the above expression as follows.
[tex]K_{sp} = [Ag^{+}]^{2}[CrO^{2-}_{4}]\\= (1.3 \times 10^{-4})^{2} \times 0.65 \times 10^{-4}\\= 1.1 \times 10^{-12}[/tex]
Thus, we can conclude that the [tex]K_{sp}[/tex] of [tex]AgCrO_{4}[/tex] is [tex]1.1 \times 10^{-12}[/tex].
Automobile airbags inflate due to the formation of nitrogen gas from the chemical reaction 2NaN3(s)—> 3N2(g)+2Na(s) Identify the number of each atom in the reactants and products for this balance reaction.
(d) (i) How can the water molecules from the iceberg end up as water in the lake?
Explanation:
If the iceberg is near the lake and the water molecules melt, then the molecules will slide down. The iceberg could be melting for many reasons - it can be purposely destroyed, the sun could be melting it, or it might naturally fall in. So, this is the answer to your question. Hope it helps!
What type of a liquid will have a pH value equal to 7? (1 point)
What is the percent yield of either if 1.11L(d=0.7134 g/mL) is isolated from the reaction of 1.500L of C2H5OH
Answer:
Percent yield of ether = 83.18%
Explanation:
Equation of the synthesis reaction of ether from ethanol is given as follows :
2 C₂H₅OH -----> C₂H₅OC₂H₅ + H₂0
Density = mass / volume
Therefore mass = density × volume
Density of ether = 0.7134 g/mL; volume of ether produced = 1.11 L = 1110 mL; Molar mass of ether = 74 g/mol
Mass of ether produced = 0.7134 g/mL × 1110 mL = 791.874 g
Density of ethanol = 0.789 g/mL; volume of ethanol = 1.50 L = 1500 mL; molar mass of ethanol = 46 g/mol
Mass of ethanol reacted = 0.789 g/mL × 1500 mL = 1183.5 g
From the equation of reaction, 2 mole of ethanol produces 1 mole of ether
Mass of 2 moles of ethanol = 2 × 46 = 92 g
Therefore, 92 g of ethanol produces 74 g of ether
1183.5 g of ethanol will produce 1183.5 × 74/92 grams of ether = 951.945 g of ether
Percent yield of ether = actual yield/theoretical yield × 100%
Actual yield of ether = 791.874 g; theoretical yield of ether = 951.945 g
Percent yield of ether = (791.874 g × 951.945 g) × 100 %
Percent yield of ether = 83.18%
how many moles are in 6.4grams of copper
Answer:
exactly 0.10071444308 mols or just 0.1 mols
Explanation:
converting 6.4 g of copper to moles is done by using it's Molar Mass we can find the Molar Mass by lookin at the periodic table or just googling it. In this case, copper's molar mass is 63.546g per Mole. so thats 6.4/63.546 = 0.015736631731344 moles of copper
NEED AN ANSWER ASAP!!! PLSSS
Compare and contrast an electrolytic cell with a voltaic cell. Provide one example where both are present in daily life.
Answer:
In both voltaic and electrolytic cells, oxidation occurs at the anode, while reduction occurs at the cathode. Thus, both these cells exhibit redox reactions. In both these cells, electrons flow from the anode to the cathode through the externally connected conductor.
Answer:
ELECTROLYTIC CELL
An electrochemical cell in which a non-spontaneous chemical reaction takes place when electric current is passed through the solution,is called an electrolytic cell.
EXAMPLE
Nelsons cell and Downs cell
VOLTAIC CELL OR GALVANIC CELL
The electrochemical cell in which a spontaneous chemical reaction takes place and generates electric current is called galvanic and voltaic cell.
EXAMPLE
Daniel cell
Explanation:
The bottle slides down the hill and is moving at a velocity of 14 meters/second the instant it hits the ground. The vertical height from where Jeff dropped the bottle is meters. Ignore friction, and use , PE = m × g × h, and g = 9.8 m/s2.
Answer:
10 m
Explanation:
From the question given above, the following data were obtained:
Velocity (v) = 14 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) =?
Next, we shall determine the energy. This can be obtained as follow:
Velocity (v) = 14 m/s
Kinetic Energy (KE) =?
KE = ½mv²
KE = ½ × m × 14²
KE = ½ × m × 196
KE = m × 98
Finally, we shall determine the height. This can be obtained as follow:
Kinetic energy (KE) = m × 98
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) =?
Since the object is falling from a particular height,
Potential energy (PE) = kinetic energy (KE)
PE = mgh
KE = m × 98
m × 9.8 × h = m × 98
Divide both side by m × 9.8
h = m × 98 / m × 9.8
h = 10 m
Thus, the bottle was dropped from a height of 10 m
The normal boiling point of ethanol is 78.4 oC. Its enthalpy of vaporization is 38.6 kJ/mol. Estimate the vapor pressure of ethanol at 26.3 oC.
Answer: The vapor pressure of ethanol at [tex]26.3^{o}C[/tex] is 238.3 torr.
Explanation:
Given: [tex]\Delta H_{vap}[/tex] = 38.6 kJ/mol
[tex]T_{1} = 26.3^{o}C = (26.3 + 273) K = 299.3 K[/tex]
[tex]T_{2} = 78.4^{o}C = (78.4 + 273) K = 351.4 K[/tex]
Formula used to calculate the vapor pressure of ethanol is as follows.
[tex]ln\frac{P_{2}}{P_{1}} = \frac{\Delta H_{vap}}{R} [\frac{1}{T_{1}} - \frac{1}{T_{2}}]\\[/tex]
Substitute the values into above formula as follows.
[tex]ln\frac{P_{2}}{P_{1}} = \frac{\Delta H_{vap}}{R} [\frac{1}{T_{1}} - \frac{1}{T_{2}}]\\ \\ln \frac{760 torr}{P_{1}} = \frac{38600 J}{8.314 J/mol K}[\frac{1}{299.3} - \frac{1}{351.4}]\\\frac{760}{P_{1}} = 3.18\\P_{1} = 238.3 torr[/tex]
Thus, we can conclude that the vapor pressure of ethanol at [tex]26.3^{o}C[/tex] is 238.3 torr.
cuantas moléculas de oxigeno se producen por la descomposición de 28.5 g de H2O2 (masa molecular = 34.0g/mol) de acuerdo a la ecuación
2H2O2(l) → 2H2O(l)+O2(g)
The question is as follows: How many oxygen molecules are produced by the decomposition of 28.5 g of H2O2 (molecular mass = 34.0g / mol) according to the equation
2H2O2 (l) → 2H2O (l) + O2 (g)
Answer: There are [tex]2.52 \times 10^{23}[/tex] molecules are produced by the decomposition of 28.5 g of [tex]H_{2}O_{2}[/tex] according to the equation [tex]2H_{2}O(l) \rightarrow 2H_{2}O(l) + O_{2}(g)[/tex].
Explanation:
Given: Mass of [tex]H_{2}O_{2}[/tex] = 28.5 g
As moles is the mass of a substance divided by its molar mass. Hence, moles of [tex]H_{2}O_{2}[/tex] is calculated as follow.
[tex]Moles = \frac{mass}{molarmass}\\= \frac{28.5 g}{34.0 g/mol}\\= 0.838 mol[/tex]
According to the given equation, 2 moles of [tex]H_{2}O_{2}[/tex] gives 1 mole of [tex]O_{2}[/tex]. So, moles of [tex]O_{2}[/tex] produced by 0.838 moles of [tex]H_{2}O_{2}[/tex] will be calculated as follows.
[tex]Moles of O_{2} = \frac{0.838 mol}{2}\\= 0.419 mol[/tex]
This means that moles of [tex]O_{2}[/tex] produced is 0.419 mol.
As per the mole concept, 1 mole of every substance has [tex]6.022 \times 10^{23}[/tex] molecules.
So, molecules of [tex]O_{2}[/tex] present in 0.419 mole are as follows.
[tex]0.419 \times 6.022 \times 10^{23}\\= 2.52 \times 10^{23}[/tex]
Thus, we can conclude that there are [tex]2.52 \times 10^{23}[/tex] molecules are produced by the decomposition of 28.5 g of [tex]H_{2}O_{2}[/tex] according to the equation [tex]2H_{2}O(l) \rightarrow 2H_{2}O(l) + O_{2}(g)[/tex].
El fluoruro de hidrógeno HF que se utiliza en
la obtención de los freones (los cuales
destruyen la capa de ozono de la
estratosfera), se prepara mediante la
siguiente reacción: CaF2 + H2SO4
CaSO4 + 2HF Si se hacen reaccionar 50gr
de CaF2 con 100 gr de H2SO4 (masas
atómicas Ca=40,F=19, H=1, S=32, O=16)
Answer:
25.6g de HF son producidos
Explanation:
...¿Cuánto HF es producido?
Para resolver este problema debemos convertir la masa de cada reactivo a moles usando su masa molar. Como la reacción es 1:1, el reactivo con menor número de moles es el reactivo limitante. Con las moles del reactivo limitante podemos obtener las moles de HF y su masa así:
Moles CaF2:
Masa molar:
1Ca = 40g/mol
2F = 19*2 = 38g/mol
40+38 = 78g/mol
50g CaF2 * (1mol/78g) = 0.641 moles CaF2
Moles H2SO4:
Masa molar:
2H = 2g/mol
1S = 32g/mol
4O = 64g/mol
98g/mol
100g H2SO4 * (1mol / 98g) = 1.02 moles H2SO4
Como las moles de CaF2 < Moles H2SO4: CaF2 es reactivo limitante.
Moles HF usando la reacción:
0.641 moles CaF2 * (2mol HF / 1mol CaF2) = 1.282 moles HF
Masa HF:
Masa molar:
1g/mol + 19g/mol = 20g/mol
1.282 moles HF * (20g/mol) =
25.6g de HF son producidosHelp please! Given that the enthalpy of reaction for a system at 298 K is –292 kJ/mol and the entropy for that system is 224 J/mol*K, what's the free energy for the system?
a) -87,793 kJ
b) -225 kJ
c) -66,751 kJ
d) 358 kJ
Answer:
C. -66, 751 kjExplanation:
hope it helps
What pollutants can contribute to acid precipitation and how are these pollutants generated?
Answer:
I don't know I don't know about question but I can try to find it
Explanation:
I don't know about question but I can try to find it
What mss of sulfamic acid is required to make 250cm3 of a 0.150mol/dm3 solution? please help
Answer:
sorry i dint understand can u ask it in a simpler way
Explanation:
Explain the difference between the movement of water molecules at room temperature and at 0 'C.
Answer:
at room temperature: -water is in liquid state bcecause of which molecules are freely moving
at 0°C:- it is freezing pointof water in this state water molecule can't move due to which there is no collision and chemical reaction will not take place
Explanation:
if i m right than tag me brilliant
The difference is in the speed of the molecules. At 0°C, the molecules move more slowly than at room temperature as their potential energy decreases.
O2 oxygen is diatomicO + O O=O Double Bond
Answer:
O 100
Explanation:
Stae the change in oxidation state of iron during the reactiong of iron extraction
Answer:
3
Explanation:
The reaction for the extraction of Iron is :-
2Fe2O3(s) + 3C(s) → 4Fe(l) + 3CO2(g)
O.S. of Fe in Fe2O3 is 3 and O.S. of Fe(l) is 0change in oxidation state (O.S.) = higher O.S - lower O.S
= 3 - 0
= 3
help me please give two example in which physical change take place please help me
Answer:
Boiling, melting
Explanation:
Physical changes affect the form of a chemical substance.
The molecule that functions as the reducing agent (electron donor) in a redox or oxidation-reduction reaction _____.
Which statement is the best description of a chemical bond
Answer:
What are your given options? I can't answer unless I know those :)
Explanation:
Which general equation shows a double-displacement reaction?
O A. AB + CD + AC + BD
O B. AB → A+B
O C. AB + CD → AD + CB
O D. A+B → AB
Answer:
O A. AB + CD + AC + BD
explanation:
Explanation:
A.ab+cd+ac+bd is your answer
What is the value of R in the ideal gas law?
O A. -0.0821 L'atm/mol K
OB. 0.0821 L'atm/mol:K
O c. 273 L'atm/mol K
O D. -273 L'atm/mol K
