If
m ≤ f(x) ≤ M
for
a ≤ x ≤ b,
where m is the absolute minimum and M is the absolute maximum of f on the interval [a, b], then
m(b − a) ≤
b
a
f(x) dx ≤ M(b − a).
Use this property to estimate the value of the integral.
⁄12 7 tan(4x) dx

[tex]\begin{cases} -5x+y=-3\\ 3x-8y=24 \end{cases} \\\\\\ \stackrel{\textit{using the 1st equation}}{-5x+y=-3}\implies \underline{y=-3+5x} \\\\\\ \stackrel{\textit{substituting on the 2nd equation}}{3x-8(\underset{y}{-3+5x})=24}\implies 3x+24-40x=24\implies 3x-40x=0 \\\\\\ -37x=0\implies \boxed{x=0}~\hfill \underline{y=-3+5(\stackrel{x}{0})}\implies \boxed{y=-3} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill (0~~,~~-3)~\hfill[/tex]

Answer:

( 0, -3 )

Step-by-step explanation:

-5x + y = -3 ⇒ ( 1 )

3x - 8y = 24 ⇒ ( 2 )

We can make y the subject of equation 1.

y = 5x - 3 ⇒ ( 3 )

Now let us take equation 2.

Here we can replace y with ( 5x - 3 ) to find the value of x.

Value of x.

3x - 8y = 24

3x - 8 (5x - 3) = 24

3x - 40x + 24 = 24

-37x = 0

x = 0

Now let us take equation 3 to find the value of y.

Here we can replace x with 0.

Let us find it now.

y = 5x - 3

y = 5 × 0 - 3

y = 0 - 3

y = -3

Now, let us write the answer as an ordered pair.

( x, y )

( 0, -3 )

The number that will be the sum of 994 and a 2 digit number is 1004 (option 3). Details about digits of numbers can be found below.

A digit is the whole numbers from 0 to 9 and the arabic numerals representing them, which are combined to represent base-ten numbers.

A 2-digit number is any number between 10 and 99.

According to this question, 994 is said to be added to a 2 digit number to result into either 1001, 1002 or 1004.

Therefore, the number that will be the sum of 994 and a 2 digit number is 1004.

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well, the regular price is really "x", which oddly enough is 100%, but we also know that $358 is really the discounted price by 20%, namely 100% - 20% = 80%, so we know that 358 is really just 80% of "x", so

[tex]\begin{array}{ccll} amount&\%\\ \cline{1-2} x & 100\\ 358& 80 \end{array} \implies \cfrac{x}{358}~~=~~\cfrac{100}{80} \\\\\\ \cfrac{x}{358}=\cfrac{5}{4}\implies 4x=1790\implies x=\cfrac{1790}{4}\implies x\approx 448[/tex]

The number of times Ken visits, given the £3.6 pool charge, and 1/3 savings per visit is 5 times.

The entry fee = £3.60

Amount saved on entry fee by having a membership card = 1/3 of the entry fee

Amount Ken spends on the membership card and the reduced entry fee = £5

Therefore;

Reduced entry fee = £3.60×(1 - 1/3) = £2.4

Amount saved per visit = £3.6 - £2.4 = £1.2

The number of visits, n, before he gets back his £5 is therefore;

Ken has to visit the swimming pool more than 4 times to get his £5 back.

Rounding to the next larger whole, therefore;

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Answer:

80

Step-by-step explanation:

Let the number of adult tickets sold be a and the number of student tickets sold be s.

Substituting the first equation into the second,

[tex]2a+a-20=220 \\ \\ 3a-20=220 \\ \\ 3a=240 \\ \\ a=80[/tex]

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

According to given figure,

Angle 11, Angle 20 and Angle 16 forms angles of a triangle,

so, by angle sum property of a triangle :

[tex]\qquad❖ \: \sf \: \angle11 + \angle20 + \angle16 = 180 \degree[/tex]

[tex]\qquad❖ \: \sf \: \angle11 +66 + 43 = 180 \degree[/tex]

[tex]\qquad❖ \: \sf \: \angle11 +109 = 180 \degree[/tex]

[tex]\qquad❖ \: \sf \: \angle11 = 180 \degree - 109[/tex]

[tex]\qquad❖ \: \sf \: \angle11 =71 \degree [/tex]

[tex] \qquad \large \sf {Conclusion} : [/tex]

The area below the mean compares to the area above the mean in a normal distribution as the areas are always equal regardless of the mean. Option A This is further explained below.

Generally, The normal distribution, also known as the Gaussian distribution, is a kind of probability distribution that is symmetric around the mean. This means that it demonstrates that data that are closer to the mean are more likely to occur than data that are farther away from the mean. When represented graphically, the normal distribution takes the shape of a "bell curve."

In conclusion, In a normal distribution, the area below the mean is compared to the area above the mean since the areas are always equal regardless of the mean. This is true even if the mean is different.

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Complete Question

How does the area below the mean compare to the area above the mean in a normal distribution?

A. the areas are always equal regardless of the mean

B. the areas are sometimes equal depending upon the standard deviation of the distribution

C. the area above the mean is larger since the values are larger as you move above the mean

D. the areas are sometimes equal depending upon the value of the mean

Mike's speed driving to his office is 45 miles/hour, which is 10 miles less than his average speed driving back.

Speed is an average value of a scalar measurement of the distance covered over the time taken.

Speed is the equation,  r = d/Δt, where r = speed or rate, d = distance, and Δt is the change in time.

Thus, when the distance covered by a traveler is divided by the time consumed, one can determine the average speed for the travel.

Distance from Mike's home to his office = 40 miles

Distance to and from = 80 miles (40 miles x 2)

Hours covered from office = 1.6 hours

Average speed for the trip = 50 miles/hour (80/1.6)

Average speed to return home = 55 miles/hour

Average speed to office = 45 miles/hour (55 - 10)

Thus, Mike's speed of driving to his office is 45 miles/hour.

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What is Mike's speed driving to his office?

Answer:

The statement "q + 5 is odd" is FALSE.

Step-by-step explanation:

Let p = 2 and q = 3.

A. p + q is odd ... 2 + 3 = 5   TRUE

B. pq is even ... 2*3 = 6   TRUE

C. q + 1 is even ... 3 + 1 = 4   TRUE

D. q + 5 is odd ... 3 + 5 = 8   FALSE

The interpretation of the p-value is that there is a 0.006 = 0.6% probability of the sample means differing by the amount that they differed on the sample.

At the null hypothesis, it is tested if the means are equal, that is:

[tex]H_0: \mu_1 = \mu_2[/tex]

At the alternative hypothesis, it is tested if the means are different, that is:

[tex]H_1: \mu_1 \neq \mu_2[/tex]

Since we are testing if the means are different, we have a two-tailed test, which means that the p-value is the probability of the means differing by the amount they different on the sample, or a greater amount.

Hence, the interpretation is that there is a 0.006 = 0.6% probability of the sample means differing by the amount that they differed on the sample.

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The number of students who applied at most two universities is 26 students.

The population of students in a class = 60 students

Number of students who applied for Addis Ababa University = 30 students

Number of students who applied for Bahir Dar University = 25 students

Number of students who applied for Wachemo University = 24 students

Number of students who applied for Addis and Bahir = 11 students

Number of students who applied for Addis and Wachemo = 6 students

Number of students who applied for Wachemo and Bahir = 9 students

The number of students who applied at most two universities is 26 (11+ 6 + 9).

Thus, the number of students who applied at most two universities is 26.

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The height of the ladder on the building is 19.77 feet

Represent the height of the ladder on the building with h

So, the given parameters are:

Angle, x = 64 degrees

Length of ladder, l = 22 feet

The height of the ladder on the building is calculated using

sin(x) = h/l

Substitute the known values in the above equation

sin(64) = h/22

Multiply both sides by 22

h = 22 * sin(64)

Evaluate the product

h = 19.77

Hence, the height of the ladder on the building is 19.77 feet

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Answer:

4 inches

Step-by-step explanation:

large rectangle - 18:12 ratio = 3:2

small rectangle - 6:4 = 3:2

19 trees should be planted to maximize the total

From the question, we have the following parameters:

Number of apples, x = 18

Yield, f(x) = 80 per tree

When the number of apple trees is increased (say by x).

We have:

Trees = 18 + x

The yield decreases by four apples per tree.

So, we have

Yield = 80 - 4x

So, the profit function is

P(x) = Apples * Yield

This gives

P(x) = (18 + x) *(80 - 4x)

Expand the bracket

P(x) = 1440 - 72x + 80x - 4x^2

Differentiate the function

P'(x) = 0 - 72 + 80 - 8x

Evaluate the like terms

P'(x) = 8 - 8x

Set P'(x) to 0

8 - 8x = 0

Divide through by 8

1 - x = 0

Solve for x

x = 1

Recall that:

Trees = 18 + x

So, we have

Trees = 18 + 1

Evaluate

Trees = 19

Hence, 19 trees should be planted to maximize the total

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The option A is correct because the value of the statement is 6+3/n-8.

According to the statement

we have given that the statement and we have to write the statement in the numerical form.

So, For this purpose

we know that the given statement is

"Six more than the quotient of three and a number, decreased by eight".

In this statement "Six more than" indicates the sum between the quotient and 6.

And "The quotient of three and a number" indicates a fraction where the numerator is 3 and the denominator is , a number.

"Decreased by eight" indicates a subtraction between the quotient an 8 units".

If we unit all parts of the statements, we would have

6+3/n-8

So, From the given statement, The option A is correct because the value of the statement is 6+3/n-8.

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Option A is correct. The gross profit that has been calculated for this year is given as 17545

22050 × 97.5%(100-2.5%) = 21498.75

= 21498.75 × 0.975 = 20961.28

= 20961.28 x 0.975 = 20437.24

= 20437.24 x  0.975  = 19926.31

= 19926.31 ×  0.975  = 19428.15

= 19428.15 x  0.975  = 18942.45

= 18942.45 x  0.975  = 18468.80

= 18468.89 ×  0.975  = 18017

= 18007 × 0.975  = $17545

Hence we can see at the end of the solution that the value of the gross profit in 2028 = $17545

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Answer:

bro it had been decreased

Step-by-step explanation:

the total sale price for the magazines were

2×4.95 = $9.90

so,

100% = 9.9

1% = 100%/100 = 9.9/100 = 0.099

6.75% = 6.75×1% = 6.75×0.099 = 0.66825 ≈ $0.67

so, he paid in total

$9.90 + $0.67 = $10.57

The area of this regular polygon is 46.8 square units

The given parameters are:

Perimeter, p = 54 m

Apothem, a = √3

The area of this regular polygon is then calculated as:

Area = 0.5 * Apothem * Perimeter

Substitute the known values in the above equation

Area = 0.5 * √3 *  54

Evaluate the product

Area = 46.8

Hence, the area of this regular polygon is 46.8 square units

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Answer: 288

Step-by-step explanation:

(16x9)x2

Answer: q = -2/3

Step-by-step explanation:

First, we need to apply the Distributive Law in order to proceed with the problem.

3(q + 4/3) = 2

3q + 3(4/3) = 2

We already know that 3(4/3) = 4, since the 3's cancel out. Or, 3(4/3) = 12/3 = 4.

Our new equation is,

3q + 4 = 2

Through transposition and isolation of variables, we get,

3q = -2

Dividing by 3 on both sides...

q = -2/3

Answer: The given integral is impossible to solve.

Step-by-step explanation: I tried solving it right now with integration by parts and trigonometric substitution, and I was unable to solve it.

So I looked at two math solvers and tried inputting the question, and it either says "There is nothing more you can do with this problem," or "We are unable to solve this problem."

First, let's substitute [tex]x=\frac w4[/tex] and [tex]dx=\frac{dw}4[/tex] to get rid of the fraction.

[tex]\displaystyle \int \csc^6\left(\dfrac w4\right) \cot^4\left(\dfrac w4\right) \, dw = 4 \int \csc^6(x) \cot^4(x) \, dx[/tex]

Recall that

[tex]\cot^2(x) + 1 = \csc^2(x)[/tex]

[tex]\dfrac{d}{dx} \cot(x) = -\csc^2(x)[/tex]

We can the rewrite the integrand as

[tex]\displaystyle 4 \int \csc^6(x) \cot^4(x) \, dx = 4 \int \left(\cot^2(x) + 1\right)^2 \cot^4(x) \csc^2(x) \, dx[/tex]

then substitute [tex]y=\cot(x)[/tex] and [tex]dy=-\csc^2(x)\,dx[/tex] to get

[tex]\displaystyle -4 \int (y^2 + 1)^2 y^4 \, dy[/tex]

Expand the integrand.

[tex]\displaystyle -4 \int (y^4 + 2y^2 + 1) y^4 \, dy = -4 \int (y^8 + 2y^6 + y^4) \, dy[/tex]

Now integrate with the power rule.

[tex]\displaystyle -4 \left(\frac{y^9}9 + \frac{2y^7}7 + \frac{y^5}5\right) + C[/tex]

[tex]\displaystyle -\frac{4y^9}9 - \frac{8y^7}7 - \frac{4y^5}5 + C[/tex]

Put everything back in terms of [tex]x[/tex], then [tex]w[/tex].

[tex]\displaystyle -\frac{4\cot^9(x)}9 - \frac{8\cot^7(x)}7 - \frac{4\cot^5(x)}5 + C[/tex]

[tex]\displaystyle \boxed{-\frac49 \cot^9\left(\dfrac w4\right) - \frac87 \cot^7\left(\dfrac w4\right) - \frac45 \cot^5\left(\dfrac w4\right) + C}[/tex]

Answer:

a company powder large group of people to assess the company's reputation in the surrounding

The factors of the equation of power 4, [tex]y=x^{3}-52x^{2} +15x^{4} +16+20x[/tex]  are x=1, -2, 4/3, -2/5.

Given equation is [tex]y=x^{3}-52x^{2} +15x^{4} +16+20x[/tex],

By performing L-division method, we get

[tex]y = (x-1)(15x^{3} +16x^{2} -36x-16)[/tex]

Then again doing the same L-division method to the cubic equation [tex]15x^{3} +16x^{2} -36x-16[/tex], we get

[tex]15x^{3} +16x^{2} -36x-16 = (x+2)(15x^{2} -14x-8)[/tex]

Therefore, [tex]y = (x-1)(x+2)(15x^{2}-14x-8)[/tex]

Then finally the roots of the quadratic equation [tex]15x^{2}-14x-8[/tex] are (x-(4/3)) and (x+(2/5))

Hence, [tex]y=x^{3}-52x^{2} +15x^{4} +16+20x = (x-1)(x+2)(x-\frac{4}{3} )(x+\frac{2}{5} )[/tex]

Therefore, the roots of the equation of power 4, [tex]y=x^{3}-52x^{2} +15x^{4} +16+20x[/tex] are x=1, -2, 4/3, -2/5.

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The solution or the value of x = 14 (Option C). See the explanation below.

Where x (bar) is the mean.

x = (12 + 13 + 14 + 15 + 16)/5

= 14

Hence option C is correct.

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The ski club has 44 members in all

What is population?

Population refers to the total number of items or individuals that form a group.

In this case, the population means the total  number of all members in the  Mogul Runners ski club.

What is sample?

Sample means a fraction of the total population, in other words, the 25% of the members, whose number is 11, that signed up to go for the planned trip.

We can convert 25% to 100% by equation 25% to 11 members that signed up to go for the planned trip.

25% of club members=11 members

divide both sides by 25%

25%/25% of club members=11/25% members

club members=44 members

The ski club has 44 members altogether as computed above.

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Step-by-step explanation:

The value of b will be 43° as it is vertically opposite angle.. !!

The zeros which are the roots of the polynomial expressions are:

x = -4; x = - 2;  x = 4 - 2√5;  x = 2(2 + √5)

The zeros of a polynomial f(x) are really the values of x that answer the equation f(x) = 0. Thus, f(x) is a function of x, and the polynomial zeros refer to the values of x, which makes the f(x) value equal to zero. The digit of zeros in a polynomial is decided by the degree of equation f(x) = 0.

For a polynomial, there may be specific values of the variable for which the polynomial is zero. These are known as polynomial zeros. They are also known as polynomial roots. In essence, we look for the zeros of quadratic equations to discover the solutions to the given equation.

From the given equation, the zeros of x^4-2x^3-44x^2-88x-32 can be computed as follows:

Using the rational root theorem:

[tex]\mathbf{= (x+2)\dfrac{x^4-2x^3-44x^2-88x-32}{x+2} }[/tex]

[tex]\mathbf{=(x+2) (x^3-4x^2-36x-32) }[/tex]

By factorization, we have:

= (x + 2) (x + 4) (x² - 8x - 4)

The zeros which are the roots of the polynomial expressions are:

x = -4; x = - 2;  x = 4 - 2√5;  x = 2(2 + √5)

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The information given regarding the computation of the profit or loss shows that there's a loss of RS 500,000.

From the information given, it was stated that the real estate agent bought two triangular Kittas' having a common side as shown in the figure from two people for Rs 2000,000 altogether.

It was further depicted that he sold the land in the shape of a quadrilateral at Rs 1,500,000. In their case, the sale is less than the cost and therefore, there's a loss.

The loss will be:

= 2,000,000 - 1,500,000

= 500,000

Therefore, the information given regarding the computation of the profit or loss shows that there's a loss of RS 500,000.

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