It is necessary to add zncl 2 to promote the reaction of hcl with some alcohols while these same alcohols react with hbr quite readily. explain.

Mn metal can be used as a sacrificial electrode to prevent the rusting of an iron pipe. So, the correct option is (c) Mn.

Commonly, sacrificial electrodes are employed to stop another metal from corroding or oxidising. A metal that is more reactive than the metal being shielded must serve as the sacrificial electrode. Magnesium, aluminium, and zinc are the three metals most frequently used in sacrificial anodes.

Manganese-Magnesium (Mn-Mg) electrode is more suited for on-shore pipelines where the electrolyte (soil or water) resistivity is higher since it has the highest negative electropotential of the three. In order to replenish any electrons that could have been lost during the oxidation of the shielded metal, the highly active metal offers its electrons.

Therefore, Mn metal can be used as a sacrificial electrode to prevent the rusting of an iron pipe. So, the correct option is (c) Mn.

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The pH at 25°c of a 0. 11 m solution of a weak acid that has ka = 9. 2 × 10−6 is 3.

The base dissociation constant is termed as Kb. Throughout a base split into ts constituent ions in water is determined by its base dissociation constant.

Kb = [H+] [A-]/[HA]

Now, let the concentration of [H+] = [A-] = x

Given,

Ka = 9.2 × 10−6.

Firstly we will calculate the value of the concentration of [H+]

pKa = x^2/(0.11-x)

9.2 × 10−6 = x^2/(0.11-x)

x^2 = 1.012 × 10−6

x = 1.002 × 10^−3.

The concentration of [H+] = [A-] = 1.002 × 10^−3.

Now, we will find pH as

pH = -log[H+]

pH = -log(1.002 × 10^−3)

pH = 3

Thus we calculated that the pH of the solution is 3.

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Pressure is inversely proportional to volume. Therefore, the effect of pressure change is opposite to the effect of volume change. So when more gas is added to the chamber the total pressure of the chamber doesn't increase.

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Intermolecular hydrogen force must be overcome to convert liquid NH3 to NH3 vapour.

Sublimation is the phase transition of a substance directly from the solid to the gaseous phase without passing through the liquid phase.

There are the 3 forces that exist between the 2 molecules of NH3

1. Dispersion force: these forces exist between any 2 molecules regardless of anything else.

2. Hydrogen bonding: H is directly bonded to the extremely electronegative atom N, O and F, hence is nearly stripped off electron due to the large electronegativity difference. Hydrogen being small atom further reduces in size even allowing it to approach other molecules very closely. Here, N, O, and F gathers more partial negative charge.

Due to the closure approach between the molecule and strong partial charge, hydrogen bonding is generally more important than dipole bond.

3. dipole dipole interaction: NH3 is a polar molecule with a permanent separation of charge. Each molecules behaves like a tiny magnet and has positive and negative poles so 2 NH3 molecules attract each other. Dipole dipole interactions are stronger than dispersion force in the small molecules.

Thus we concluded that the hydrogen bond should overcome to convert NH3 to vapours.

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Answer:

Density = 0.27 decagrams/cm³

Explanation:

From conversion tables, we know that;

1 g/cm³ = 0.1 decagrams/cm³

We are given;

Density of aluminium = 2.7 g/cm³

Thus;

Density = 2.7 * 0.1

Density = 0.27 decagrams/cm³

Answer:

270000 decagrams/m³

Explanation:

1.

Density=mass/Volume

=2.7g/1cm3

=(2.7/1000)/(1/1000000)

=2.7x1000

Density=2700kg/ m3

= 270000 decagrams/m³

2.

1000g=1kg

1g=1/1000kg

1cm3= ? m3

100cm=1m

1cm=1/100 m

1cm3=1/1000000 m3

Answer:

subscript

Explanation:

H₂ O   means there are two hydrogen atoms and one oxygen atom

               the ' ₂ '  is a subscript

In an acid-base neutralization reaction, the equilibrium reaction would be between a weak base and its conjugate strong base. So, this must be the basis of the volume of added base.

pH is used to measure whether the substance is acidic, basic or neutral and the range is 0 - 14.

Neutralization reaction is a chemical reaction in which an acid and a base react quantitatively with together.

Neutralization reaction equation:

Acid + Base → Salt + Water

Thus from the above conclusion we can say that In an acid-base neutralization reaction, the equilibrium reaction would be between a weak base and its conjugate strong base. So, this must be the basis of the volume of added base.

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A symmetrical acid anhydride will undergo a reaction with an alcohol to give an ester and a carboxylic acid. An asymmetrical acid anhydride will undergo a reaction with an alcohol to give two esters and two carboxylic acids.

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Answer:

synergy

Explanation:

when two substances combine effects to be greater than just their sum of their individual effects

The pressure of the mixture can be found out adding the Partial Pressure of the gas.

Partial pressure of gas is the pressure if it alone occupied the entire volume of original mixture.

Moles = given mass / molar mass

Given,

Mass of Nitrogen = 32g

Molar Mass of Nitrogen = 28g

Mass of Neon = 16g

Molar Mass of Neon = 20g

Volume of gas = 4L

Temperature of vessel = 0°C = 273K

Partial Pressure of nitrogen = P₁

Partial Pressure of neon = P₂

Moles of nitrogen, n₁= 32/28 = 1.14

Moles of neon, n₂= 16/20 = 0.8

Using Ideal gas equation for Nitrogen,

∴ P₁V = n₁RT

⇒ P₁ (1) = 1.14 × 0.082 × 273

⇒ P₁ = 25.52atm

Using Ideal gas equation for Neon,

∴ P₂V = n₂RT

⇒ P₂ (1) = 0.8 × 0.082 × 273

⇒ P₂ = 17.9 atm

Total pressure of the mixture can be found out by adding the partial pressures of both the gases.

Total pressure P = P₁  + P₂  

P = 25.52 + 17.9 atm

P = 43.42 atm

Hence, total pressure of the mixture is 43.42atm

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Cyclohex-2-en-1-one product would be obtain from intramolecular aldol condensation of 5-oxohexanal.

The condensation reaction in which two ketone groups and aldehyde group in the same molecule are called Intramolecular Aldol Condensation. Intramolecular Aldol Condensation occurs in five or six membered α, β- unsaturated aldehyde or ketones are formed.

Thus from the above conclusion we can say that Cyclohex-2-en-1-one product would be obtain from intramolecular aldol condensation of 5-oxohexanal.

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ANSWER: From this experiment, Jeff can conclude that the heat capacity of oil is lower than that of water which means that oil requires less energy per gram of liquid in order to change its temperature.

a. There are 1.85 moles in 2.00 × 10² g of silver (Ag).

b. There are 0.618 moles in 37.1 g of silicon dioxide (SiO₂)

The molar mass is the mass in grams of 1 mole of particles, that is, the mass in grams of 6.02 × 10²³ particles. The units are g/mol.

We want to calculate the number of moles represented by different masses of different substances. In each case, the conversion factor between mass and moles is the molar mass.

The molar mass of silver is 107.87 g/mol.

2.00 × 10² g × (1 mol/107.87 g) = 1.85 mol

The molar mass of silicon dioxide is 60.08 g/mol.

37.1 g × (1 mol/60.08 g) = 0.618 mol

a. There are 1.85 moles in 2.00 × 10² g of silver (Ag).

b. There are 0.618 moles in 37.1 g of silicon dioxide (SiO₂)

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[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Let's solve ~

Initial concentration of weak acid HA = 0.200 M

and dissociation constant ([tex]{ \alpha} [/tex]) is :

[tex]\qquad \sf  \dashrightarrow \: \alpha = \frac{dissociation \: \: percentage}{100} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \alpha = \frac{9.4}{100} = 0.094[/tex]

Now, at initial stage :

At equilibrium :

Now, we know :

[tex]\qquad \sf  \dashrightarrow \: { K_a = \dfrac{[H+] [A-]}{[HA]}} [/tex]

( big brackets represents concentration )

[tex]\qquad \sf  \dashrightarrow \: { K_a = \dfrac{0.0188×0.0188}{0.1812}} [/tex]

[tex]\qquad \sf  \dashrightarrow \: { K_a = \dfrac{0.00035344}{0.1812}} [/tex]

[tex]\qquad \sf  \dashrightarrow \: { K_a \approx 0.00195 } [/tex]

[tex]\qquad \sf  \dashrightarrow \: {K_a \approx 1.9 × {10}^{-3} } [/tex]

According to the problem, we have a 0.200 M solution of a weak acid HA that is 9.4% ionized. To find the Ka (acid dissociation constant) for HA, we can use the percent ionization formula:

From this formula, we know that [H+] (the concentration of hydrogen ions) is equal to 9.4% of [HA]initial, and [HA]initial is equal to the initial concentration of the weak acid, which is 0.200 M. Solving for [H+], we get:

Now we can use the equation for Ka:

We don't know the concentration of the conjugate base (A-) at this point, but we can assume that it is equal to [H+] because the weak acid is only slightly ionized. Therefore, we can substitute [A-] = [H+] = 0.0188 M into the equation and solve for Ka:

[tex]\sf Ka = \dfrac{(0.0188)^2}{(0.200 - 0.0188)} = \bold{1.8 \times 10^{-3}}[/tex]

So the answer is [tex]\bold{ B.\: 1.8 \times 10^{-3}}[/tex].

I hope this helps!

Answer:

Atom

Explanation:

That describes an ATOM

1. The first step is to convert your given masses into moles. This way, you can see which reactant is in excess and which one is limiting. A good flow of thought would be: kilograms of SiO2/Carbon→ grams SiO2/Carbon→moles SiO2/Carbon.

2. Repeat this step for the carbon reactant.

3. By comparison, we can tell that the carbon reactant is in excess, which means that the SiO2 reactant is limiting. Because of this, we’ll use the amount of SiO2 to find our percent yield. There’s only so much SiO2 that can react with the carbon.

4. You can now calculate the actual and theoretical yields. The theoretical yield is larger than the actual yield because it does not have physical interactions like loss of energy to the environment and friction to interfere with the reaction.

5. Now compare your two values of actual and theoretical. The formula for percent mass is [(Actual yield)/(Theoretical yield)]*100%. Our final answer for this question is the percent yield of the reaction is 90.8% We can interpret this as 90.8% of the SiO2 reacting will produce solid silicon.

Hope this helps!!

Answer:

The reactivity series allows us to predict correctly how metals will react. Another importance is that so we can use displacement. We can spot a more reactive metal allowing us to displace a less reactive metal from a compound or an equation.

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Importance of Metal Reactivity Series are:

What are metal reactivity series?

Metal reactivity series is a chart of listing the metals in the order of decreasing reactivity.

See the below reaction:

K(s)        +            [tex]H_2O[/tex]   →           KOH(aq)              +                  1/2 [tex]H_2[/tex] (g)

Potassium      water              Potassium Hydroxide                Hydrogen

Lets see the reaction between Lead with Hydrochloric acid and Sulphuric acid.

Pb (s)      + 2HCl (aq)           →              [tex]PbCl_2[/tex] (aq)           +       [tex]H_2[/tex] (g)

Lead        Hydrochloric acid          Lead chloride                  Hydrogen

Pb (s)      +   [tex]2H_2SO_4[/tex]             →     [tex]PbSO_4[/tex]              +   [tex]SO_2[/tex]                   +   [tex]H_2O[/tex]

Lead         Sulphuric acid            Lead Sulphate      Sulphur dioxide    water

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Four different substituents are required on a carbon atom for it to be chiral.

The carbon atom which is attached with four different types of group of atoms or atoms is called Chiral carbon. Chiral molecules are non superimposable on their mirror images. Chiral carbon is also called asymmetric carbon.

Example:

[tex]Br - \underset{H} {\underset{|} {\overset{CH_3} {\overset{|}{C}}}} - Cl[/tex]

In the above example we can see that carbon atom has 4 different group attached with it that is Br, Cl, H, CH₃.

Thus from the above conclusion we can say that Four different substituents are required on a carbon atom for it to be chiral.

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A combustion reaction will always be associated with a change in entropy that will be positive.

The entropy of a system is the measurement of the disorder of the system which happens in the thermodynamic reaction.

During association the value of entropy  will be positive and during dissociation the value will be negative.

During association the number of molecule increases due to which the entropy of the combustion increases and the value will be positive .

Therefore , combustion reaction will always be associated with a change in entropy that will be positive.

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The differences between grasses and legumes are,

The advantage and disadvantage of grasses are given below.

Advantage:

Grasses helps to keep air clean, trap carbon dioxide , reduce erosion from storm water runoff , improve soil , decreases noise pollution and reduce temperature.

Disadvantage:

The advantage and disadvantage of legumes are given below.

Advantage:

Disadvantage:

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According to Beer-Lambert's law, the solution allows for the passage of 3/4 of the incoming light intensity at that wavelength.

Calculation:

According to Beer-Lambert's law,

A = ∈ * C * l

A = log(I₀/I)

T = I₀/I

log (I₀/I) = ∈ * C * l

Here,

A= absorbance of the solution

l= path length= 2.67 mm = 0.267 cm (∵ 1mm = 0.1 cm)

T= transmittance

C= concentration of the given solution = 3.17mmol/L = 3.17* 10⁻³ mol/L

I= transmitted light

I₀= incident light

∈= molar absorption coefficient = 712 L mol⁻¹cm⁻¹

A = ∈ * C * l= 712 * 3.17 * 0.267 *10⁻³ = 602.63* 10⁻³ =0.602

T = [tex]10^{-A}[/tex] = [tex]10^{-0.602}[/tex] = 0.25

so, the percentage of transmittance = 0.25 * 100 = 25 %

Therefore, the intensity reduction will be equal to the original radiation intensity less the transmittance.

Give the initial intensity = 100

So, the reduction = 100 - 25 = 75.

Hence the fraction of incident light intencity= 75/100 = 3/4

Therefore the answer is 3/4.

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The equilibrium potential and the standard free energy change can give the standard potential of the electrodes. The standard cell potential is 0.32 V.

A reaction's standard free energy change (∆Gº') is the energy produced when the reactants undergo changes to form the product. It is given as,

ΔG° = -nFE° cell

Given,

Standard free energy change (ΔG°) = − 61. 0 kJ

Number of moles of electrons (n) = 2

Faraday's constant (F) = 96500 C

The standard cell potential (E° cell) is calculated as:

E° cell = ΔG° ÷ -nF

E° cell = − 61000 ÷ -(2 × 96500)

E° cell = 61000 ÷ 193000

= 0.32 V

Therefore, 0.32 V is the standard cell potential of the cell.

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A chemistry laboratory device is a clay triangle to support the crucible when heated to high temperatures. It consists of a three-sided triangle frame made of clay or ceramic material.

The heat can pass through the open sides and is evenly distributed throughout the crucible. Although the soil triangle is a common and commonly used piece of laboratory equipment, it is difficult to ascertain who actually invented it.

The design of the clay triangle probably changed over time as a result of diverse contributions from scientists and chemists working on building laboratory equipment. The soil triangle may not have had a clear beginning, as is the case with many scientific instruments, but it is considered an evolution in laboratory technology overall.

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Answer:

32(molecular mass has no unit )

Explanation:

(16)(o2)

16×2

=32

Answer:

7,9,11

Explanation:

this is because water includes 0H, which would mean that it is more than 6

The group of unsaturated hydrocarbons which 2 carbons are double bonded together, with H bonded to the left, and C H 2 bonded below left, above right, and below right is derived from Alkenes

Organic compounds are compounds which contains carbon and hydrogen

Some few classes or organic compounds or hydrocarbons are as follows:

So therefore, the group of unsaturated hydrocarbons which 2 carbons are double bonded together, with H bonded to the left, and C H 2 bonded below left, above right, and below right is derived from Alkenes

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Answer:

The answer is A.) Alkene

All the answers in that section are:

Alkene

Aromatic Hydrocarbon

Alkene

Alkyne

Explanation:

Here's the picture as proof. Hope it helps!

Hello its me Sanya yadav

Answer:

Explanation:

to put this plainly after putting strong electrolytes in water they dissolve to nothing but ions they give you an example and definition of a strong electrolyte I suggest you read those and see if you come up with what I gave you they also tell you that not all strong electrolytes dissolve as strongly as others that are in the example.

Styrene is an organic chemical used to make rubber, latex, resins, etc. It can be best converted using the anti-Markovnikov rule by (1) BH₃ - THF and (2) H₂O₂, NaOH. Thus, option B is correct.

The anti-Markovnikov rule defines the attachment of the substituent group to the least substituted carbon than the more substituted groups. This is due to the induction and hyperconjugation effect.

To convert styrene, the alcohol group from sodium hydroxide must be added to the least substituted carbon of the compound using other reagents like BH₃ - THF and hydrogen peroxide.

Therefore, option B. (1) BH₃ - THF and (2) H₂O₂, NaOH can be used to convert styrene.

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Your question is incomplete, but most probably your full question was, What is the best method to convert styrene, C₆H₅CH=CH₂, to 2-phenyl ethanol with minimal side product formation?