It's C or A if it's C that's right if it's A I'm wrong be pretty sure it is C
Graph C is the correct alternative as it can be seen from the equation y = - 0.25x + 12 that the graph will have negative slope and will have a linear relationship with x.
What is Equation Modelling?Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.
Given is Kiren is spending $12 on games and rides at a carnival where a game costs $0.25 and a ride costs $1.
Assume that Kiren played 'x' games and rides 'y' times.
Total amount with Kiren = A[T] = $12
Cost of game = A[G] = $0.25
Cost of ride = A[R] = $1
Then we can write a equation representing above scenario as -
A[T] = A[G]x + A[R]y
0.25x + y = 12
y = - 0.25x + 12
It can be seen that the graph will have negative slope and will have a linear relationship with x. Hence, graph C is correct.
Therefore, Graph C is the correct alternative as it can be seen from the equation y = - 0.25x + 12 that the graph will have negative slope and will have a linear relationship with x.
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Define Linear Pair.
Choose one of the answer choices
Answer:
A pair of opposite angles formed by two intersecting lines (option C)
Step-by-step explanation:
The science of classifying and naming organisms based on their different characteristics is called .
Answer:
Taxonomy
Step-by-step explanation:
The taxonometric way of classifying organisms is based on similarities between different organisms. A biologist named Carolus Linnaeus started this naming system. He also chose to use Latin words.
HELP ME ASAP!! Consider the graph of the system of equations. Part A: What is the system of equations that is represented by the graph shown? Part B: What is the solution to the system of equations written in Part A? Show your work.
Answer:
Step-by-step explanation:
Part (A)
From the picture attached,
Line 1 passes through two points (-2, 0) and (-1, 3).
Let the equation of the line is,
y = mx + b
where m = slope of the line
b = y-intercept
Slope of a line passing through [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by,
m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
Therefore, slope of line 1,
m = [tex]\frac{3-0}{-1+2}[/tex]
m = 3
y-intercept 'b' = 6
Equation of line 1 will be,
y = 3x + 6 --------(1)
Let the equation of line 2 is,
y = m'x + b'
Since line 2 passes through two points (0, -1) and (1, 3)
Slope m' = [tex]\frac{3+1}{1-0}[/tex]
= 4
y-intercept b' = -1
Equation of line 2 is,
y = 4x - 1 --------(2)
Part (B)
By equating the values of y from both the equations,
3x + 6 = 4x - 1
4x - 3x = 6 + 1
x = 7
From equation (2),
y = 4(7) - 1
= 28 - 1
= 27
2 2
(2x + 7x -9 )-( x +x + 3)
Adding and Subtracting Polynomials
PLZ SHOW WORK ASAP!!!!
A photograph of an elephant has a scale of 1 cm representing 0.5 m. The elephant's trunk in the photograph measures 4.1 cm.
What is the actual length of the elephant's trunk?
1. 8.2 m
2. 2.04 m
3. 2.05 m
4. 2.08 m
Answer:
2.05
Step-by-step explanation:
You need to multiply the 0.5m with the 4.1 cm !!
0.5m x 4.1 = 2.05
I hope I helped!!
ayo i need help this is vv hard or i’m jus dumb.
Question 10 (15 points) Suppose a product has a log_linear demand given by:In(Q) = A - Bln (p) dQ a. Express Q as a function of p and show that: = dp -BQ P dQ b. Express "p" as a function of Q and fin
The log-linear demand function In(Q) = A - Bln(p) relates quantity demanded (Q) to price (p).
a. Q as a function of p:
Q = e^A / p^B
dp/dQ = -B * e^A / p^(B+1)
b. p as a function of Q:
p = e^(A/B) / Q^(1/B)
To solve this problem, let's start with the given demand function: In(Q) = A - Bln(p), where Q represents the quantity demanded, p is the price of the product, A and B are constants.
a. Express Q as a function of p:
To find the relationship between Q and p, we need to exponentiate both sides of the equation to remove the natural logarithm. By taking the exponential function, we get:
e^(In(Q)) = e^(A - Bln(p))
Using the property e^(A - Bln(p)) = e^A / e^(Bln(p)) = e^A / p^B, the equation becomes:
Q = e^A / p^B
Now, let's differentiate both sides of this equation with respect to p:
dQ/dp = d/dp(e^A / p^B)
To differentiate e^A / p^B, we can use the quotient rule:
dQ/dp = [e^A * (-B) * p^(B-1) - e^A * p^B * 0] / (p^B)^2
Simplifying this expression, we have:
dQ/dp = -B * e^A / p^(B+1)
b. Express "p" as a function of Q:
To find the relationship between p and Q, we can rearrange the equation Q = e^A / p^B:
p^B = e^A / Q
Now, taking the B-th root of both sides:
p = (e^A / Q)^(1/B)
Simplifying further:
p = e^(A/B) / Q^(1/B)
So, we have expressed "p" as a function of Q.
In summary, for the log-linear demand function In(Q) = A - Bln(p):
a. Q can be expressed as Q = e^A / p^B, and the derivative of Q with respect to p is dp/dQ = -B * e^A / p^(B+1).
b. p can be expressed as p = e^(A/B) / Q^(1/B).
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What would this equal too?
Answer:
5^-4
Step-by-step explanation:
Solve for a: 3((1/3)a + 3)
= 27
Answer:
I think its 3 but I'm not a 100% sure.
Answer:
a = 24
Step-by-step explanation:
first distribute the 3 to the 1/3a and the 3 in the parentheses.
3 times 1/3 a equals a because 1/3 times 3 equals 3/3 or 1. so 1a equals a.
so now the equation reads (a + 3) =27
now subtract 3 from both sides of the equation and you are left with a = 24
a fair coin is flipped four times. findthe probability it will land up heads eachtime(b) the probability it will land the same way eachtime (slightly different from (a)).
The probability of getting heads each time is 1/16, and the probability of getting the same outcome (either heads or tails) each time is 1/8.
We know that the probability of getting a head or a tail when flipping a fair coin is 1/2. Let us use this fact to answer the given questions. The probability it will land the same way each time:
The probability of getting heads each time is (1/2) × (1/2) × (1/2) × (1/2) = 1/16.
The probability of getting tails each time is also 1/16.
Therefore, the probability of getting the same outcome (either heads or tails) each time is (1/16) + (1/16) = 1/8.
The probability of getting heads each time is lower than the probability of getting tails each time. This is because there are more ways to get tails each time than to get heads each time. For example, if we flip the coin four times, we can get heads-tails-heads-tails or tails-heads-tails-heads, but we cannot get heads-heads-heads-heads and tails-tails-tails-tails at the same time.
Therefore, the probability of getting heads each time is 1/16, and the probability of getting the same outcome (either heads or tails) each time is 1/8.
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A key joint in a precision machining process has a lower specification limit of a width of 1.16 mm and an upper specification limit of 1.24 mm. The standard deviation is 0.03 mm and the mean is 1.2 mm
What is the process capability index for the precision machining process? (Round off your answer to the SECOND decimal place)
the process capability index for the precision machining process is 0.44 (rounded off to the second decimal place). Since the process capability index is less than 1, the process is considered incapable of meeting the specifications.
Given the following data:
Lower Specification Limit (LSL) = 1.16 mm
Upper Specification Limit (USL) = 1.24 mm
Standard deviation = 0.03 mm
Mean = 1.2 mm
Process Capability Index, Cp, is defined as the ratio of the specification range to the process range. It can be calculated using the following formula:
Cp = (USL - LSL) / (6σ)
where σ is the standard deviation and 6 is a constant that relates to the normal distribution of data.
For a process to be considered capable, Cp must be greater than or equal to 1.
Cp = (1.24 - 1.16) / (6 × 0.03)
= 0.08 / 0.18= 0.44 (rounded off to the second decimal place)
Therefore, the process capability index for the precision machining process is 0.44 (rounded off to the second decimal place). Since the process capability index is less than 1, the process is considered incapable of meeting the specifications.
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Find the equation for
each problem.
Answer:
-2, 3
Step-by-step explanation:
slope=-4
help plz..............
Answer:
-20
Step-by-step explanation:say hes on 0 when he moves back 4 hes on -4 when he moves back 4 ore hes on -8 move back 4 more -12 move back 4 more -16 then move back 4 more -20
What is the area of this triangle? A=bh2 a-54 cm² b-90 cm² c-108 m² d-216 m² 15 cm 12 cm Cm^2
Answer: To find the area of a triangle, we can use the formula:
Area = (base * height) / 2
Given the measurements:
Base (b) = 15 cm
Height (h) = 12 cm
Substituting these values into the formula:
Area = (15 cm * 12 cm) / 2
Area = 180 cm² / 2
Area = 90 cm²
Therefore, the area of the triangle is 90 cm².
shop sells bagels for $5 per dozen.
You can buy bagels for $50.
Answer: You can buy at most, 120 bagels.
Plz mark brainliest:)
Answer:
120 bagels:) have a great day!!!!!!!!!!!!!!!
Step-by-step explanation:
You have been saving nickels, dimes, and quarters in a jar for about a year. You decide to see how much money you've saved up. When you get everything counted it turns out you have 361 total nickels, dimes, and quarters worth a total of $41.45. You think is is odd that you have exactly twice as many dimes as quarters. Find the number of each coin.
Answer:
No. of Nickels = 127
No. of Dimes = 156
No. of Quarters = 78
Step-by-step explanation:
First we need to form a system of equations representing the situation. So, first we let:
x = number of nickel coins
y = number of dimes
z = number of quarters
Now, we know that the total coins are 361. Therefore,
x + y + z = 361 ----------- equation (1)
It is also given that there are twice as many dimes as quarters:
y = 2z
y - 2z = 0 ----------------equation (2)
Now, we have a total worth of $41.45. A dime is worth $0.1, nickel is worth $0.05 and a quarter is worth $0.25. Therefore,
0.05x + 0.1y + 0.25z = 41.45 ----------------- equation (3)
Simultaneously solving the three equations, we get:
x = 127, y = 156, z = 78
Hence,
No. of Nickels = 127
No. of Dimes = 156
No. of Quarters = 78
Solve it by using Simplex Method or Big M method
Minimize Z subject to = 4x₁ + 2x2, 3x₁ + x₂ ≥ 27, -x₁ - x₂ = 21, x₁ + 2x₂ ≥ 30, x₁ and x₂ unrestricted in sign. X2 X1
By applying the Simplex Method or Big M Method to the given problem, the optimal solution for minimizing the objective function Z = 4x₁ + 2x₂ subject to the given constraints is obtained. The optimal solution for the given problem is Z = -27, x₁ = 6, and x₂ = 3.
To solve the given problem using the Simplex Method or Big M Method, we follow these steps:
Step 1: Convert the problem into standard form:
Introduce slack variables to convert inequalities into equations.
Express any unrestricted variables as the difference of two non-negative variables.
The given problem can be converted into the following standard form:
Minimize Z = 4x₁ + 2x₂
subject to:
3x₁ + x₂ + s₁ = 27
-x₁ - x₂ = 21
x₁ + 2x₂ + s₂ = 30
x₁, x₂, s₁, s₂ ≥ 0
Step 2: Set up the initial Simplex tableau:
Construct the initial tableau using the coefficients of the objective function and the constraints:
| Cj | x₁ | x₂ | s₁ | s₂ | RHS |
------------------------------------
Z | -4 | 0 | 0 | 0 | 0 | 0 |
------------------------------------
s₁ | 0 | 3 | 1 | 1 | 0 | 27 |
------------------------------------
s₂ | 0 | 1 | 2 | 0 | 1 | 30 |
------------------------------------
Step 3: Perform iterations of the Simplex Method:
We start with the initial tableau and iterate until we reach an optimal solution. I will provide the final tableau directly:
| Cj | x₁ | x₂ | s₁ | s₂ | RHS |
----------------------------------------
Z | -2 | 0 | 0 | 1 | -2 | -27 |
----------------------------------------
x₁ | 1 | 1 | 0 | -1 | 1 | 6 |
----------------------------------------
s₂ | 0 | 0 | 1 | -0.5| 0.5| 3 |
----------------------------------------
The optimal solution is obtained when all the coefficients in the Z row (except Cj) are non-positive. I
n this case, Z = -27, x₁ = 6, and x₂ = 3. The objective function is minimized when x₁ = 6 and x₂ = 3, resulting in Z = -27.
Therefore, the optimal solution for the given problem is Z = -27, x₁ = 6, and x₂ = 3.
Note: The steps provided above show the general process of solving a linear programming problem using the Simplex Method or Big M Method. The exact calculations and iterations may vary depending on the specific values and coefficients in the problem.
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How many times smaller is 2 × 10-8 than 4 × 10-5?
Answer:23
Step-by-step explanation:
2x10-8=12
4x10-5=35
35-12=23
Let y(t) be a solution of y′=18y(1−y8) such that y(0)=16. Determine limt→[infinity]y(t) without finding y(t) explicitly.
limt→[infinity]y(t) =
The limit of y(t) as t approaches infinity is y = 1.
To determine the limit of y(t) as t approaches infinity, we can analyze the behavior of the differential equation y' = 18y(1 - y^8) without explicitly solving it.
We start by examining the equation y' = 18y(1 - y^8). At y = 0 and y = 1, the term (1 - y^8) becomes 1, which means the right-hand side of the equation is 0. This implies that y(t) will remain constant at y = 0 and y = 1.
Given that y(0) = 16, which is greater than 1, we can conclude that y(t) will approach the stable equilibrium point y = 1 as t approaches infinity. This is because any deviation from y = 1 will result in a term (1 - y^8) that is nonzero and drives the derivative y' towards 0.
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3^3 times 3^4 find the exponent for the 3
Answer:
3^3= 27
3^4= 81
Step-by-step explanation:
Hope that help
what quadrant is (-2,-3) in?
Answer:
It would be quadrant 3
Step-by-step explanation:
Answer:
The point is located in the second quadrant because x is negative and y is positive. The quadrants are labeled in counter-clockwise order, starting in the upper-right.
letrs unit 4 assessment based on the grapheme representing /sh/, which word is probably from french?
"Champagne" is a word that is likely from French based on the grapheme representing /sh/.
Based on the grapheme representing /sh/, the word that is likely from French is "champagne."
The /sh/ sound is commonly represented by the grapheme "ch" in English, as in words like "shop" and "sheep." However, in French, the same sound is often represented by the grapheme "ch" as well.
The word "champagne" is a well-known French term used to refer to a type of sparkling wine produced in the Champagne region of France. It contains the "ch" grapheme that represents the /sh/ sound in French.
The grapheme for the sound /sh/ indicates that the word "champagne" is hence likely French in origin.
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The grapheme /sh/ is commonly found in French words. An example from French is 'chaussure' where 'ch' represents the /sh/ sound. However, exceptions exist and additional linguistic analysis may be needed.
Explanation:The grapheme representing the /sh/ sound is a common characteristic in French words. Therefore, when identifying a word that is likely of French origin, we look for the presence of this grapheme. An example could be the French word 'chaussure', which means shoe in English. The /sh/ sound is represented by the combination of letters 'ch' in this case. However, keep in mind that this is just a general principle and exceptions do exist, so other linguistic analysis might be necessary to confidently determine a word's origin.
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Where is the f(x) negative
a) (0,-6)
b) (-10,7)
c) (-10,0)
d (-7,10)
F(0)=
a) -2
b) 10
c) 7
d) -6
If F(x)=0, find x
a) -2
b) -4
c) 0
d) 7
What is the domain of F(x)?
a) (-10,8)
b) (-6,2)
c) (-10,-7,-2,-1,4,8)
d) (-7,-6,-2,2)
Answer:
1. a) (0,-6)
2. d) f(0)=-6
3. d
4. a (?)
Step-by-step explanation:
1. f(0)=-6, which is negative
2. f(0)=-6
3. when x=7, f(7)=0
4. domain: [-10,8] because x=-10 and 8 are included in the domain
Hopefully, this helps.
Find the total surface area of a cubical dice having length of each side 2 cm.
Answer:
24
Step-by-step explanation:
A cube has six faces.
each face has a side length of 2 cm
Since each face is a square, the are of one face is 2*2 = 4 cm^2
So the total surface area is 6 * 4 cm^2 = 24 cm^2
5x10 plus 4 x1 plus 8 x 1/10 plus 6 x 1 x 1/1000
First multiply each terms and u get
50+4+4/5+0.006
When u add all these u get
54.806 or 54 403/500
what can the numbers 24 and 17 be divided by
Answer:
1
Step-by-step explanation:
Answer:
I can be dived by 8
Step-by-step explanation:
because 8 16 24
The average sea level in 1920 at the London bridge was 33 feet. in 1925 it was 33.08 feet.
Use linear interpolation or extrapolation to find what the average sea level was in 1928.
The average sea level at the London bridge in 1928 was approximately 33.16 feet.
Linear interpolation is the process of determining the value of a variable between two points by using the data in between the two points. To find out the average sea level in 1928, we can use linear interpolation or extrapolation.
Extrapolation is the method of estimating a value outside the range of a known set of values. Here are the steps to find out the average sea level in 1928 using linear interpolation:
Step 1: Write down the given data:
In 1920, the average sea level at the London bridge was 33 feet.In 1925, the average sea level at the London bridge was 33.08 feet.
Step 2: Calculate the rate of change:
Step 3: Write the linear equation:
Using the point-slope form of a line, we can write the equation of the line passing through the points (1920, 33) and (1925, 33.08) as follows:y - 33 = 0.016(x - 1920)Simplify the equation: y = 0.016x - 31.872
Step 4: Find the average sea level in 1928:The average sea level in 1928 can be found by substituting x = 1928 in the equation derived in step 3:
y = 0.016(1928) - 31.872y = 0.16 feet
The average sea level at the London bridge in 1928 was approximately 33.16 feet.
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I got CONFUSED PLZ HELP?
Answer:
A, B, F
Step-by-step explanation:
To solve this, you look at the powers of x and take either the square root (if it is to a power of 2) or the cube root (if a power of 3) of both sides to isolate x. For the first equation, you take the square root of 48, so A is correct. For the second one, you take the square root of 63, so B is correct. For the final equation, you take the cube root of 73, so F is correct.
Answer:
[tex]x = \sqrt{48} \\\\x = \sqrt{63} \\\\x = \sqrt[3]{73}[/tex]
Step-by-step explanation:
[tex]x^2 = 48\\x^2 = 63\\x^3 = 73[/tex]
Solve for x
Equation 1 ;
[tex]x^2 =48\\\\Square\:root\:both\:sides\\\\\sqrt{x^2} =\sqrt{48} \\\\Simplified \:form;\\x =4\sqrt{3}[/tex]
Equation 2;
[tex]x^2 =63\\\\Square\:root\:both\:sides\\\\\sqrt{x^2} =\sqrt{63} \\\\Simplified \:form;\\x =3\sqrt{7}[/tex]
Equation 3 ;
[tex]x^3 =73\\\\Cube\:root\:both\:sides\\\\\sqrt[3]{x^3}= \sqrt[3]{73} \\\\x = \sqrt[3]{73}[/tex]
Dabriah had 3 bags of cookies containing x cookies each. Her friend gave her 7 more cookies. Write an expression for this situation 3b + 7c b) If there are 9 cookies in each bag, how many cookies does Dabriah have in total?
Answer: 34 delicious cookies.
Step-by-step explanation:
(look in attachment for explanation)
A silver ring has a mass of 2 grams and a volume of 0.2 cubic centimeters. Calculate its
density.
Write your answer as a whole number
grams per cubic centimeter............ Help pls
Answer:
The answer is 10 g/cm³Step-by-step explanation:
The density of a substance can be found by using the formula
[tex]density = \frac{mass}{volume} \\[/tex]
From the question
mass = 2 g
volume = 0.2 cm³
So we have
[tex]density = \frac{2}{0.2} \\ [/tex]
We have the final answer as
10 g/cm³Hope this helps you