Look at the following Python code:

word1 = "Umpire"
word2 = word1[0:3]

Which characters will be sliced from word1 and assigned to word2?

Ump
Umpi
mpi
pire

Answer: D. The phone can represent the photo in either digital or analog formats depending on the sampling technique that is used

Explanation:

Photos can either come out as analog or digital with digital formats having better overall quality overall. Digital photos are taken with digital cameras and so use electronic detectors while analog photography uses chemical processes.

The thing about photos taken by smartphones is that they can be represented as either digital or analog formats. It simply depends on the sampling techniques used.

The issue “when a user deletes the data, whether all the copies are deleted or not is something that every needs to have a clear answer to” comes under aspect of data deletion and data lifecycle management.

One need rules and practices to delete data to follow privacy laws, protect data, and meet user expectations. When a user gets rid of data, it is important to check if all copies of that data have been effectively removed from the system or storage.

Data Retention Policies: Organizations must create clear rules about how long they will keep certain data before getting rid of it.

Read more about deletion here:

https://brainly.com/question/30280833

#SPJ1

Answer:

The answer to this question is given below in the explanation section

Explanation:

Scrum Board is a tool that is used by the scrum teams to view the product backlog. The Scrum task board makes the sprint backlog visible for the team.

In the Scrum board, prioritizing the issue backlog is done in the Current View mode.

However, it is noted that in Scrum board there are two view modes (Tree view mode and List view mode) for the issues in the backlog. The issues that are prioritized is listed in the current view mode.  

Answer:

The answer to this question is given below in the explanation section

Explanation:

shoNum + shoNum2 = shoTotal

in this code statement,  the order of operation is wrong because the calculation in programming always done at the right side of dependent variables.  so the correct statement of code is

shoTotal = shoNum + shoNum2;

shoNum = 10 * 4

This statement is programmatically correct, because the ShoNum value becomes 40 after performing the multiplication operation on its assigned value  (10 multiply by 4). However, it is noted that the empty space mostly ignored by the compiler. So, the correct is shoNum = 10*4;

Dim decPrice As Decimal = "$4.99"

The dollar sign is appeared in along with its value. So, if you assign value to a decimal variable, you need to assign only digit value (do not mix value with symbol or text) and also do not put quotation marks around value, if you put quotation marks around value then this value will be consider as a text value.

So, the correct statement is :

Dim decPrice As Decimal = 4.99;

shoCube= (shoSide)3

In this statement, cube is calculated of shoSide variable, mathematically it is right, but programmatically it is incorrect. Because, you missed the multiplication operation (*) between the operand shoSide and 3. it should

be as  shoSide raise to power 3.

the correct statement is : shoCube = (shoSide * shoSide *shoSide);

Answer:

Computer graphics is an art of drawing pictures on Computer Screen.

Computer graphics is made up number of pixels. Pixels is the smallest unit which can be represented on computer screen.

Basically there are two types of Computer graphics:

Answer:

#include using namespace std;

cout << quotient;

Explanation:

not #include ; using namespace std;

; doesn't belong

cout << quotient

forgot the ; at the end

The given Java program takes a number as input from the user, reverses it, and checks if it is a palindrome. It uses the modulo and division operations to reverse the number. The program is not limited to 4-digit numbers and can handle numbers of any length.

```java

import java.util.Scanner;

public class ReverseNumber {

  // Method to reverse a given number

public static int reverse(int num) {

  int reversed = 0;

      // Reversing the number using modulo and division operations

  while (num != 0) {

    int digit = num % 10;

    reversed = reversed * 10 + digit;

    num /= 10;

  }

      return reversed;

}

  public static void main(String[] args) {

  Scanner scanner = new Scanner(System.in);

      // Taking user input

  System.out.print("Enter a number: ");

  int number = scanner.nextInt();

      // Reversing the number

  int reversedNumber = reverse(number);

      // Checking if the reversed number is equal to the original number

  if (number == reversedNumber) {

    System.out.println(number + " is a palindrome number.");

  } else {

    System.out.println(number + " is not a palindrome number.");

  }

      scanner.close();

}

}

```1. The `reverse` method takes an integer as input and reverses it using the modulo and division operations. It initializes `reversed` as 0 and in each iteration of the while loop, it separates the last digit of the input number using `num % 10`, appends it to `reversed` by multiplying it with 10, and then updates `num` by dividing it by 10.

This process is repeated until `num` becomes 0. Finally, the method returns the reversed number.

2. In the `main` method, we create a `Scanner` object to take user input. We prompt the user to enter a number, read it using `nextInt()`, and store it in the `number` variable.

We then call the `reverse` method to get the reversed number and store it in the `reversed Number` variable.

Finally, we compare `number` and `reversed Number` to check if the number is a palindrome or not. The result is printed accordingly.

3. The provided solution already works with any number, not just 4-digit numbers. This is because the `reverse` method separates the digits of the input number and reverses them regardless of the number of digits.

For more such questions palindrome,Click on

https://brainly.com/question/23161348

#SPJ8

Answer:

class OddNumber

{

  public static void main(String args[])  

       {

         int n = 1000;  //Store 1000 in Variable n typed integer

         System.out.print("Odd Numbers from 1 to 1000 are:");  // Print headline of output window

         for (int i = 1; i <= n; i++)  //For loop to go through each number till end

          {

            if (i % 2 != 0)  //check if number is even or odd.Not divisible by 2 without reminder means it is odd number

             {

               System.out.print(i + " "); //print odd numbers

             }

          }

       }

}              

Explanation:

Remember, Malware is a word coined from the words Malicious-Software (Mal...ware). Thus, Malware could be defined as software that is intentionally designed by cybercriminals to gain access or cause damage to a computer or network.

a. Cindy may learn the difference between these two techniques used to create a malware attack:

b. Here are some common suggestions;

Answer:

They share or broadcast information by making a letter or information in a papyrus material.

Answer:

i think i know

Explanation:

import math

number = int(input("Enter a number: "))

while number < 0:

 number = int(input("Enter a number: "))

if number % 2 == 0:

 if number == 2:

   print("Your number is a prime.")

   exit()

 print("Your number is not a prime.")

 exit()

elif number % 2 == 1:

 i = 2

 while i <= math.sqrt(number):

   if number % i == 0:

     print("Your number is not a prime ")

     exit()

   i += 1

print("Your number is a prime.")

I hope this helps!

Answer: Internet Protocol Address

Explanation: IP Address is the abbreviation of Internet Protocol Address

Hope this helps

--Wavey

the meaning of the abbreviation of IP address is: Internet Protocol address(IP address)

sorry if that isn't what you meant, but hope this helps

Answer: A formula is an expression which calculate the value of a cell .A funcation is a predefined formula that performs calculations using specific values in particular order.According to context of excel.

Answer:

A

Explanation:

Answer:

palmtop computer os the computer

Answer:

I don't think this is the right answer but I'm gonna have to say a handheld computer.

Explanation:

You can store it in your pocket and you can use it while you hold it. I'm sorry if this isn't the right answer, I tried my best.

Answer:

Explanation:

This study aimed to systematically identify and evaluate the readability and document complexity of currently available family history tools for the general public. Three steps were undertaken to identify family history tools for evaluation: (a) Internet searches, (b) expert consultation, and (c) literature searches. Tools identified were assessed...

Because for some kids it could be to violent.

Answer:

rocket league

Explanation:

get gud kid, see me in lobby

Answer:

IT can be purchased; IS cannot be purchased

Explanation:

Yeah

I've included my code in a text file. I hope this helps!

The output is hello dad in all lowercase.

Answer: hello dad

Explanation:

this is the correction i got 100% correct

Answer:

The algorithm is as follows:

1. Start

2. Input List

3. Input Sum

4. For i = 0 to length of list - 1

4.1 num1 = List[i]

5. For j = i to length of list - 1

5.1 num2 = List[j]

6. If SUM = num1 + num2

6.1 Print(num1, num2)

6.2 Break

The algorithm is implemented in python as follows:

def checklist(mylist,SUM):

     for i in range(0, len(mylist)):

           num1 = mylist[i]

                 for j in range(i+1, len(mylist)):

                       num2 = mylist[j]

                       if num1 + num2== SUM:

                             print(num1,num2)

                                   break;

Explanation:

I'll explain the Python code

def checklist(mylist,SUM):

This line iterates from 0 to the length of the the last element of the list

     for i in range(0, len(mylist)):

This line initializes num1 to current element of the list

           num1 = mylist[i]

This line iterates from current element of the list to the last element of the list

                 for j in range(i+1, len(mylist)):

This line initializes num1 to next element of the list

                       num2 = mylist[j]

This line checks for pairs equivalent to SUM

                       if num1 + num2== SUM:

The pair is printed here

                             print(num1,num2)

                                   break;

In this exercise we have to use the knowledge of the python language to write the code, so we have to:

The code is in the attached photo.

Some important information informed in the statement that we have to use in the code is:

So to make it easier the code can be found at:

def checklist(mylist,SUM):

    for i in range(0, len(mylist)):

          num1 = mylist[i]

                for j in range(i+1, len(mylist)):

                      num2 = mylist[j]

                      if num1 + num2== SUM:

                            print(num1,num2)

                                  break;

See more about python at brainly.com/question/26104476

Answer:

Advantages of Wide Area Network as opposed to the Local Area Network:

Because of wide area network (WANs) connections are available from house to house, city to city, country to country. For ex: Internet.

WAN is connecting the devices with various wireless technologies such as: cell phone towers or satellites. All these are much harder to setup with LANs.

Local Area Network (LANs) connections can only operate in a local area, not bigger than a house or a floor in a office building and also you cannot buy a ethernet cable that can reach throughout entire building and Wi-Fi connection rapidly disconnected as you get further then few meters away.

Answer:

- provides access to other networks

- greater geographic reach

Explanation:

Wide area networks cover larger areas like a city, country, or multiple countries. They're managed by large groups or companies. Connections are typically made using routers and public networks such as phone, cable, or satellite systems. Ninety-nine percent of internet traffic is transmitted through cables. The remaining one percent is transmitted via satellite.

(Confirmed on EDGE)

I hope this helped!

Good luck <3

Answer:

d

Explanation:

Answer:

Following are the code to this question:

#include <iostream>//defining header file

#include <string.h>//defining header file

using namespace std;//using package

char checksum(const char *x)//defining a method checksum  

{

int s=0,m,d;//defining integer variables

for (m= 1;*x;++x)//defining for loop for caLculate value

{

d=*x-'0';//use integer variable to remove last digit from input value  

s=s+m*d;//add value in s variable

m=4-m;//use m to remove 4 from m

}

return '0'+(1000-s)%10;//use return keyword to get value  

}

int main()//defining main method

{

char ISBNNum[14];// defining character array  

cout<<"Enter the first 12 digits of an ISBN-13 as a string:";//print message

cin>>ISBNNum;//input value from user end

if(strlen(ISBNNum)==12)//defining if block to check length

{

char a=checksum(ISBNNum);//defining char variable a to call method checksum

ISBNNum[12]=a;//use array to hold method value

ISBNNum[13]='\0';// use array to hold 13 character value

cout<<"The ISBN-13 number is "<<ISBNNum;//print number

}

else//defining else block

{

cout<<ISBNNum<<" is an invalid input"<<endl;//print message

}

return 0;

}

output:

please find the attachment.

Explanation:

In the given code a character method "checksum" is define that accepts a character as a parameter and inside the method, three integer variable "s,m, and d" is defined that uses the for loop to calculate the input value and use the return keyword for the return value.  Inside the main method, a char array "ISBNNum", is defined that input the value from the user-end and define the conditional statement.

Answer:

Here is the C++ program:

#include <iostream>  //to use input output functions

#include <fstream>  //to manipulate files

using namespace std;  //to identify objects like cin cout

int main(){  //start of main function

  ifstream file;   //creates an object of ifstream

   file.open("random.txt"); //open method to open random.txt file using object file of ifstream

    int numCount = 0;  //to store the number of all numbers in the file          

    double sum = 0;   //to store the sum of all numbers in the file

    double average = 0.0;   //to store the average of all numbers in the file

    int number ; //stores numbers in a file

        if(!file){   //if file could not be opened

           cout<<"Error opening file!\n";    }   //displays this error message

       while(file>>number){   //reads each number from the file till the end of the file and stores into number variable

           numCount++; //adds 1 to the count of numCount each time a number is read from the file          

           sum += number;  }  //adds all the numbers and stores the result in sum variable

           average = sum/numCount;  //divides the computed sum of all numbers by the number of numbers in the file

       cout<<"The number of numbers in the file: "<<numCount<<endl;  //displays the number of numbers

       cout<<"The sum of all the numbers in the file: "<<sum<<endl;  //displays the sum of all numbers

       cout<<"The average of all the numbers in the file: "<< average<<endl;  //displays the average of all numbers

       file.close();     }  //closes the file    

Explanation:

Since the random.txt is not given to check the working of the above program, random.txt is created and some numbers are added to it:

35

48

21

56

74

93

88

109

150

16

while(file>>number) statement reads each number and stores it into number variable.

At first iteration:

35 is read and stored to number

numCount++;  becomes

numCount = numCount + 1

numCount = 1      

sum += number; this becomes:

sum = sum + number

sum = 0 + 35

sum = 35

At second iteration:

48 is read and stored to number

numCount++;  becomes

numCount = 1+ 1

numCount = 2    

sum += number; this becomes:

sum = sum + number

sum = 35 + 48

sum = 83

So at each iteration a number is read from file, the numCount increments to 1 at each iteration and the number is added to the sum.

At last iteration:

16 is read and stored to number

numCount++;  becomes

numCount = 9 + 1

numCount = 10    

sum += number; this becomes:

sum = sum + number

sum = 674 + 16

sum = 690

Now the loop breaks and the program moves to the statement:

       average = sum/numCount;  this becomes:

       average = 690/10;

       average = 69

So the entire output of the program is:

The number of numbers in the file: 10                                                                                                           The sum of all the numbers in the file: 690                                                                                                     The average of all the numbers in the file: 69

The screenshot of the program and its output is attached.

Answer:

Explanation:

edX es una plataforma de cursos abiertos masivos en línea, conocidos por sus siglas en inglés como MOOC (Massive Online Open Course), basada en software de código abierto. Fue fundada por el Instituto Tecnológico de Massachusetts y la Universidad de Harvard en mayo de 2012 para hospedar cursos en línea de nivel universitario de un amplio rango de disciplinas, para todo el mundo sin costos para propiciar la investigación y el aprendizaje.3​ Cada una de estas dos instituciones contribuyen con 30 millones de dólares de recursos para este proyecto sin ánimo de lucro. El curso prototipo con el cuál empezó el programa fue Circuitos y Electrónica, que comenzó en diciembre de 2011, a través de MITx, el programa en línea y masivo del MIT.4​

EdX tiene más de 10 millones de usuarios registrados y es considerado el segundo proveedor más grande de MOOC en el mundo, después de Coursera que cuenta con 23 millones de usuarios registrados.5​

A finales de 2016, edX ofrecía 1300 cursos de los cuales 500 fueron lanzados en 2016. Del total de cursos que ofrece, 53 son pagados, conocidos como cursos de educación profesional, y 13 son elegibles para créditos universitarios. De acuerdo a una investigación realizada por Class Central, el costo promedio de un certificado de edX es de USD$53.6​

Actualmente hay más de 130 colaboradores entre institutos, organizaciones sin ánimo de lucro, corporaciones y organizaciones internacionales que ofrecen o planean ofrecer más de 500 cursos en el sitio web de edX.7​