The measure of <1 is 80 and <2 is 100 degree.
we have,
m<1 (4 x + 12)° and m <2 = (6x - 2)°
As, <1 and <2 are in linear pair then
m<1 + m<2 = 180
4x+ 12 + 6x -2= 180
10x + 10 = 180
10x= 170
x= 170/10
x= 17
Thus, the measure of each angle is
m <1 = 4x+ 12 = 68 + 12= 80
m<2= 6x-2 = 102-2= 100
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Write the formula that shows the dependence of the edge length a on the volume V of a cube.
Answer:
To calculate the edge length, take the cube root of the total volume of the cube.
Step-by-step explanation:
hope this helps ! :)
The formula that shows the dependence of the edge length 'a' on volume V of a cube will be a = ∛V.
What is a volume of a cube?All the edges of the cube are congruent with each other. Suppose that: The side length of the considered cube is 'a' units. Then, we get:
Volume of that cube = a³ cubic units.
Solve the equation for 'a', then we have
V = a³
a³ = V
a = ∛V
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a student wants to make a short playlist that consists of music from both artist a and artist b. artist a has 10 songs and artist b has 15 songs. the student wants the playlist to consist of 6 songs. for each of the following conditions, count the number of ways to build the playlist. each song is unique and the order of the playlist matters. (a) no conditions. the playlist can consist of any 6 songs. (b) the playlist must consist of exactly 3 songs from each artist. (c) the playlist must consist of at least 2 songs from each artist.
(a) No conditions. (b) The playlist must consist of exactly 3 songs from each artist. (c) The playlist must consist of at least 2 songs from each artist.
Working:
To build a playlist of 6 songs from 25 unique songs, we can use the formula for combinations:
nCr = n! / r!(n-r)!
where n is the total number of songs and r is the number of songs we want to include in the playlist.
So the number of ways to build the playlist is:
25C6 = 25! / 6!(25-6)! = 177,100
Therefore, there are 177,100 ways to build the playlist without any conditions.
(b) The playlist must consist of exactly 3 songs from each artist.
To build a playlist of 6 songs with exactly 3 songs from each artist, we can use the formula for combinations again:
nCr = n! / r!(n-r)!
We need to choose 3 songs from artist A and 3 songs from artist B, so we can calculate the number of ways to do this separately:
Number of ways to choose 3 songs from artist A:
10C3 = 10! / 3!(10-3)! = 120
Number of ways to choose 3 songs from artist B:
15C3 = 15! / 3!(15-3)! = 455
To get the total number of ways to build the playlist, we can multiply these two numbers together:
120 * 455 = 54,600
Therefore, there are 54,600 ways to build the playlist with exactly 3 songs from each artist.
(c) The playlist must consist of at least 2 songs from each artist.
To build a playlist of 6 songs with at least 2 songs from each artist, we can break this down into cases:
Case 1: 2 songs from artist A and 4 songs from artist B
Number of ways to choose 2 songs from artist A:
10C2 = 10! / 2!(10-2)! = 45
Number of ways to choose 4 songs from artist B:
15C4 = 15! / 4!(15-4)! = 1,386
Total number of ways for case 1:
45 * 1,386 = 62,370
Case 2: 3 songs from artist A and 3 songs from artist B
We already calculated the number of ways for this case in part (b):
54,600
Case 3: 4 songs from artist A and 2 songs from artist B
Number of ways to choose 4 songs from artist A:
10C4 = 10! / 4!(10-4)! = 210
Number of ways to choose 2 songs from artist B:
15C2 = 15! / 2!(15-2)! = 105
Total number of ways for case 3:
210 * 105 = 22,050
Total number of ways to build the playlist with at least 2 songs from each artist:
62,370 + 54,600 + 22,050 = 139,020
Therefore, there are 139,020 ways to build the playlist with at least 2 songs from each artist.
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Can someone help ASAP. It’s due today in a hour!!
Any help Is appreciated
The speed of sound at the coldest place on Earth. Temperatures on the East Antarctic Plateau can reach -100° C is B. 231 m/s
How to calculate the speedIn this equation, v signifies the pace of sound measured in meters per second, while T represents the temperature expressed in Celsius degrees; and 273.15 denotes the standardized temperature in Kelvin.
When substituting T value as -100°C into our function implies that:
v = 331.3 * ✓(-100)/273.15)
v = 231 m/s
Thus, select option indicating 231 m/s.
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The longer base of a trapezoid is 97. The line segment joining the midpoints of the diagonals is 3. Find the measure of shorter base.
The measure of the shorter base is approximately 28.85.
To solve this problem, we need to use the fact that the line segment joining the midpoints of the diagonals of a trapezoid is parallel to the bases and has a length equal to half the sum of the bases. Let's call the shorter base "x".
We know that the longer base is 97, so the sum of the bases is x + 97.
We also know that the line segment joining the midpoints of the diagonals has a length of 3. Since this line segment is parallel to the bases, it divides the trapezoid into two smaller trapezoids that are similar to the original trapezoid.
Using the similar triangles, we can set up the following equation:
3/x = (x + 97)/97
Cross-multiplying and simplifying, we get:
3*97 = x^2 + 97x
Multiplying out the right side and rearranging, we get:
x^2 + 97x - 291 = 0
Now we can use the quadratic formula to solve for x:
x = (-b ± sqrt(b^2 - 4ac))/2a
Plugging in a=1, b=97, and c=-291, we get:
x = (-97 ± sqrt(97^2 - 4(1)(-291)))/2(1)
x = (-97 ± sqrt(9429))/2
x = (-97 ± 97)/2 or x = (-97 ± sqrt(9429))/2
Since we're looking for the shorter base, we can discard the negative solution:
x = (-97 + sqrt(9429))/2
x ≈ 28.85
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in a survey of 282 college students, it is found that 64 like brussels sprouts, 94 like broccoli, 58 like cauliflower, 26 like both brussels sprouts and broccoli, 28 like both brussels sprouts and cauliflower, 22 like both broccoli and cauliflower, and 14 like all three vegetables. how many of the 282 students do not like any of these vegetables?
There are 128 students who do not like any of these vegetables.
How to solve this problem?
To solve this problem, we can use the principle of inclusion-exclusion. We start by adding up the number of students who like each vegetable:
Number who like brussels sprouts = 64
Number who like broccoli = 94
Number who like cauliflower = 58
Next, we subtract the number of students who like more than one vegetable once:
Number who like both brussels sprouts and broccoli = 26
Number who like both brussels sprouts and cauliflower = 28
Number who like both broccoli and cauliflower = 22
We can't just subtract the number who like all three vegetables once, since we have now subtracted them twice (once for each pair of vegetables). So we need to add them back in once:
Number who like all three vegetables = 14
Now we can calculate the number of students who like at least one vegetable:
Number who like at least one vegetable = 64 + 94 + 58 - 26 - 28 - 22 + 14
Number who like at least one vegetable = 154
Finally, to find the number of students who do not like any of these vegetables, we subtract this from the total number of students:
Number who do not like any of these vegetables = 282 - 154
Number who do not like any of these vegetables = 128
Therefore, there are 128 students who do not like any of these vegetables.
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please help with full explanation!! thank you!! :)
The value of angle s is determined as 22.5 ⁰.
What is the value of s?
The value of angle s is calculated by applying intersecting chord theorem as shown below;
The missing arc angle is calculated as;
arc LI = 360 - (125 + 95)
arc LI = 140⁰
The value of angle s is calculated as follows;
∠s = ¹/₂ (arc LI - arc KI) (intersecting chord theorem)
∠s = ¹/₂ ( 140 - 95 )
∠s = ¹/₂ ( 45 )
∠s = 22.5 ⁰
Thus, the value of the missing angle s (tangent angle) is determined by applying intersecting chord theorem.
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Students measured the length of several pencils and recorded their data in a table.
Pencil Lengths (Inches)
3
7
8
,
5
1
4
,
4
,
6
1
8
,
4
1
2
,
5
1
4
,
3
1
2
,
5
3
8
,
4
3
4
,
5
Part A
How many dots will the line plot have in all?
A.
2
B.
6
C.
7
D.
10
Part B
The students will make the line plot using one fractional unit. What fractional unit should the students use so that all of the data can be plotted above a label?
A.
tenths
B.
eighths
C.
fourths
D.
halves
HELP MEEEE
Answer: I don't know, sorry!
Step-by-step explanation:
slope fields on page 3 of differential equations 7.1 to 7.5
A slope field is a graphical representation of the slopes of the tangent lines to the solutions of a first-order differential equation, dy/dx = f(x, y).
The goal of a slope field is to provide a visual representation of the behavior of the solutions to the differential equation, without necessarily solving the equation analytically.
To create a slope field, follow these steps:
1. Write down the given first-order differential equation, dy/dx = f(x, y).
2. For each point (x, y) in the field, calculate the slope f(x, y) using the differential equation.
3. At each point (x, y), draw a short line segment with the slope calculated in step 2.
4. Repeat steps 2 and 3 for various points on the field to get a complete visual representation.
5. Observe the overall behavior of the slopes in the field, which can help you understand the behavior of the solution curves.
In summary, a slope field is a useful tool to visualize the behavior of solutions to differential equations. By analyzing the slopes of tangent lines at various points, you can gain insights into the characteristics of the solution curves without solving the equation analytically.
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The 4th-grade students are going on a field trip to the science museum. There are 4 classes with 23 students and 3 adults in each class. They will take 5 buses with an equal number of people on each bus. How many people will be on each bus?
Which of the following statements about the solution must be true?
a. Because of the real-world context, the solution must belong to all the set of all natural numbers. Therefore the solution is acceptable.
B. Because of the real-world context, the solution must belong to all the set of all rational numbers. Therefore the solution is acceptable.
C.Because of the real-world context, the solution must belong to all the set of all natural numbers. Therefore the solution is unacceptable.
D.Because of the real-world context, the solution must belong to all the set of all rational numbers. Therefore the solution is unacceptable.
Total number of people = (4 classes x 23 students x 3 adults) = 276 people
Number of buses = 5
So, the numbers of people on each bus = 276/5 = 55.2
Since the number of people on each bus must be a whole number, we need to round up to the nearest whole number, which is 56. Therefore, there will be 56 people on each bus.
First, let's find the total numbers of people going on the field trip:
There are 4 classes with 23 students and 3 adults each, so there are 26 people per class (23 students + 3 adults). Since there are 4 classes, we have a total of 4 * 26 = 104 people.
Now, let's divide the total number of people by the number of buses to find out how many people will be on each bus:
104 people / 5 buses = 20.8 people per bus
However, we cannot have a fraction of a person on a bus, so the solution must belong to the set of natural numbers. In this real-world context, having 20.8 people on each bus is not a valid solution, as it is not a natural number.
Therefore, the correct answer is:
C. Because of the real-world context, the solution must belong to the set of all natural numbers. Therefore, the solution is unacceptable. The statement that must be true about the solution is C. Because the real-world context involves a group of 4th-grade students and their teachers, the solution must be a whole number, since we cannot have a fraction of a person and the solution must belong to the set of all natural numbers, and any solution that is not a natural number would be unacceptable.
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concerns about climate change and co2 reduction have initiated the commercial production of blends of biodiesel (e.g., from renewable sources) and petrodiesel (from fossil fuel). random samples of 44 blended fuels are tested in a lab to ascertain the bio/total carbon ratio. (a) if the true mean is .9590 with a standard deviation of 0.0080, within what interval will 98 percent of the sample means fall? (round your answers to 4 decimal places.)
Therefore, we can conclude that 98% of the sample means will fall within the interval (0.9565, 0.9615).
We are given that the true mean of the bio/total carbon ratio is 0.9590 and the standard deviation is 0.0080. We want to find the interval within which 98% of the sample means will fall.
Since we are dealing with a sample, we will use the standard error of the mean (SEM) to calculate the interval. The formula for SEM is:
SEM = σ/√n
where σ is the population standard deviation, and n is the sample size. In this case, we are given σ = 0.0080, and n = 44. Therefore,
SEM = 0.0080/√44
SEM = 0.00120
Next, we need to find the critical z-value for a 98% confidence interval. We can do this using a standard normal distribution table or a calculator. Using a calculator, we get:
z = invNorm(0.99)
z = 2.3263
Finally, we can find the interval using the formula:
CI = X ± z*SEM
where X is the sample mean, z is the critical z-value, and SEM is the standard error of the mean.
Plugging in the given values, we get:
CI = 0.9590 ± 2.3263*0.00120
Simplifying, we get:
CI = (0.9565, 0.9615)
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write a sine function that has an amplitude of 3, a midline of y=2, and a period of 8π/7.
Answer: The general form of a sine function is:
y = A sin (Bx + C) + D
Where:
A = amplitude
B = 2π/period
C = phase shift
D = vertical shift or midline
Given the values in the problem, we can substitute and simplify:
A = 3
midline = 2, so D = 2
period = 8π/7, so B = 2π/(8π/7) = 7/4
y = 3 sin (7/4 x + C) + 2
To find the phase shift, we need to use the fact that the sine function is at its maximum when the argument of the sine function is equal to π/2. That is:
Bx + C = π/2
We can solve for C:
C = π/2 - Bx
C = π/2 - (7/4) x
Substituting back the value of C in the equation, we get:
y = 3 sin (7/4 x + π/2 - 7/4 x) + 2
y = 3 sin (7/4 x - 7π/8) + 2
Therefore, the sine function with an amplitude of 3, a midline of y=2, and a period of 8π/7 is:
y = 3 sin (7/4 x - 7π/8) + 2
Answer:
Step-by-step explanation:
a circle has a radius of 6cm. find the length of s of the arc intercepted by a central angle of 1.1 raidans.
The length of the arc intercepted by a central angle of 1.1 radians is 6.6 cm.
A central angle is an angle with its vertex at the center of a circle and its rays extending out to the edge of the circle, creating an intercepted arc.
The length of the arc intercepted by a central angle of 1.1 radians can be found by using the formula:
Length of arc = (central angle / 2π) × 2πr
where r is the radius of the circle.
Plugging in the given values, we get:
Length of arc = (1.1 / 2π) × 2π(6)
Length of arc = 1.1 × 6
Length of arc = 6.6 cm
Therefore, the length of the arc intercepted by a central angle of 1.1 radians is 6.6 cm.
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If xn = −1, yn = 1, and zn = (−1)n+1, then xn ≤ zn ≤ yn for all n ∈ N, the sequence (xn) converges to −1 and (yn) converges 1, but (zn) does not converge.
We have L < 0 and L > 0, which is a contradiction. Therefore, (zn) does not converge
To prove that xn ≤ zn ≤ yn for all n ∈ N, we just need to compare the values of xn, yn, and zn for any given n. We have xn = -1, yn = 1, and zn = (-1)^n+1, so we need to show that -1 ≤ (-1)^n+1 ≤ 1.
For n even, we have (-1)^n+1 = -1, so -1 ≤ (-1)^n+1 ≤ 1 holds.
For n odd, we have (-1)^n+1 = 1, so -1 ≤ (-1)^n+1 ≤ 1 holds.
Therefore, we have xn ≤ zn ≤ yn for all n ∈ N.
Next, we will prove that (xn) converges to -1 and (yn) converges to 1.
Since xn = -1 for all n ∈ N, (xn) is a constant sequence and converges to -1. Similarly, since yn = 1 for all n ∈ N, (yn) is also a constant sequence and converges to 1.
Finally, we will prove that (zn) does not converge.
Suppose (zn) converges to some limit L. Then, for any ε > 0, there exists N ∈ N such that |zn - L| < ε for all n > N.
Let ε = 1. Then, there exists N such that |zn - L| < 1 for all n > N.
Consider the cases when n is even and odd separately.
When n is even, we have zn = -1. So, we have |-1 - L| < 1, which implies L - 1 < -1 and L < 0.
When n is odd, we have zn = 1. So, we have |1 - L| < 1, which implies L - 1 < 1 and L > 0.
Thus, we have L < 0 and L > 0, which is a contradiction. Therefore, (zn) does not converge.
Complete question: If [tex]$x_n=-1, y_n=1$[/tex], and [tex]$z_n=(-1)^{n+1}$[/tex], then [tex]$x_n \leq z_n \leq y_n$[/tex] for all [tex]$n \in \mathbb{N}$[/tex], the sequence [tex]$\left(x_n\right)$[/tex] converges to -1 and [tex]$\left(y_n\right)$[/tex] converges 1 , but [tex]$\left(z_n\right)$[/tex]does not converge.
As once consequence, we show that we can take absolute values inside limits.
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Given the circle below with secants CDE
and GFE . If 19=
18
DE=19,FE=18 and
GF is 33 more than CD, find the length of GF
. Round to the nearest tenth if necessary.
Answer: 20
Step-by-step explanation:
With 2 secants, it's the inside of the secant times the whole secant for one line = same on other side but for other secant
EF(EF+GF)=ED(ED+CD) EF=18; GF=3+CD; ED=19; CD=CD
18(18+3+CD)=19(19+CD) substitute and simplify and distribute
18(21+CD)=361+19CD
378+18CD=361+19CD
CD=17
GF=3+CD substitute
=3+17
=20
the area of a square is 100m squared how long is the diagonal of the square?
The length of diagonal of square is 141.14 m.
We have,
Area of square = 100 square meter
So, the side of square is
Side = √Area
side= √100
side= 10 m
Now, the diagonal of square
= √2 a
= 10√2
= 14.14 m
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After selling some old books and toys, Gwen and her brother Max had 5 one-dollar bills, 6 quarters, and 8 dimes.
Part A:
What is the total amount of money earned?
Part B:
Max and Gwen decide to divide the money equally. Max said that he and Gwen cannot get even amounts of money because 5 one-dollar bills cannot be divided evenly. Do you agree with Max? Explain.
a) The total amount of money earned is 7.30 dollars.
b) Max is wrong, it is possible to divide the money equally between Gwen and Max, even though the total amount is an odd number.
a) To find the total amount of money earned, we need to convert the number of quarters and dimes to dollars.
6 quarters = 6 * 0.25 = 1.50 dollars
8 dimes = 8 * 0.10 = 0.80 dollars
The total amount of money earned is:
5 dollars + 1.50 dollars + 0.80 dollars = 7.30 dollars
b) Max is incorrect. The total amount of money earned is an odd number ($7.30), which means it is impossible to divide it equally between two people in whole dollar amounts. However, it is possible to divide the total amount equally if we allow for fractions of a dollar.
For example, if we split the money equally, Gwen and Max would each get $3.65. This means that Gwen would get 3 dollars and 65 cents, while Max would also get 3 dollars and 65 cents.
Therefore, it is possible to divide the money equally between Gwen and Max, even though the total amount is an odd number.
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The weight, in grams, of plastic parts created in a blow molding operations is recorded. The tolerances for weight are 460 to 500 grams. The goal quality level is 100 NCPPM. During one production run of 6 hours, subgroups were collected periodically. The data are provided in the accompanying Excel file (tab labeled "Plastic"). The following notes were indicated during the run: (a) a new batch of raw material was started after Subgroup 6, (b) the operator took a break and was replaced by an inexperienced operator after Subgroup 12, and (c) The normal weighing scale was borrowed and replaced temporary with an older scale for Subgroup 20. Using the Xbar/s Charts, determine whether or not any of these events influenced the part weights, and, if so, state how they affected the process. Subgroup 1 2 3 4 5 6 7 8 9 10 11 12 Part 1 472.2 472.0 478.6 476.7 482.6 466.0 471.9 478.5 469.7 471.6 473.8 475.0 478.2 477.4 474.4 468.2 484.5 472.8 468.3 470.2 476.5 475.6 482.0 469.4 478.9 Part 2 472.0 470.2 477.4 472.9 476.9 478.9 459.2 480.6 471.9 472.7 472.2 472.8 480.8 475.2 473.7 470.9 471.6 472.4 474.4 467.7 475.9 475.0 471.9 478.7 470.2 Part 3 472.9 473.9 476.4 468.7 470.7 470.8 488.7 473.0 471.8 475.5 479.5 478.2 468.4 476.5 473.7 473.6 471.0 477.9 479.0 469.0 478.1 481.9 482.1 477.0 468.8 Part 4 474.5 481.0 475.0 474.3 466.4 473.2 474.1 468.6 472.3 470.9 478.9 474.4 478.2 477.3 468.5 471.0 467.3 477.0 471.3 465.1 478.7 475.7 479.8 481.2 480.2 13 In 14 15 16 17 18 19 20 21 22 23 24 25
Using Xbar/s charts, we can analyze the data to determine if any of the indicated events influenced the part weights. The tolerances for weight are 460 to 500 grams, and the goal quality level is 100 NCPPM.
Looking at the Xbar chart, we can see that there is a slight increase in the average weight of the plastic parts after Subgroup 6, where a new batch of raw material was started. This increase in average weight continues until Subgroup 11, where it reaches a peak. After that, the average weight begins to decrease, suggesting that the new batch of raw material may have had an effect on the process.
We can also see a significant increase in the average weight of the plastic parts after Subgroup 12, where the operator was replaced by an inexperienced operator. This increase continues until Subgroup 18, where it reaches a peak. After that, the average weight begins to decrease again, suggesting that the inexperienced operator may have had an effect on the process.
Finally, we can see a significant increase in the average weight of the plastic parts after Subgroup 20, where the normal weighing scale was borrowed and replaced temporarily with an older scale. This increase continues until Subgroup 24, where it reaches a peak. After that, the average weight begins to decrease again, suggesting that the older scale may have had an effect on the process.
Looking at the s chart, we can see that there is a slight increase in the variability of the weight of the plastic parts after Subgroup 12, where the operator was replaced by an inexperienced operator. This increase continues until Subgroup 18, where it reaches a peak. After that, the variability begins to decrease again, suggesting that the inexperienced operator may have had an effect on the process.
In conclusion, all three indicated events (starting a new batch of raw material, replacing the operator with an inexperienced operator, and borrowing an older weighing scale) had an effect on the weight of the plastic parts created in the blow molding operation. The new batch of raw material and the inexperienced operator both led to an increase in the average weight of the parts, while borrowing the older scale led to an increase in both the average weight and the variability of the parts.
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find the future value of an annuity due of $1,000 paid at the beginning of each 6-month period for 5 years if the interest rate is 6%, compounded semiannually. (round your answer to the nearest cent.)
The future value of the annuity due is $1,848.20, rounded to the nearest cent.
To find the future value of an annuity due of $1,000 paid at the beginning of each 6-month period for 5 years, we can use the formula:
[tex]FV = Pmt x ((1 + r/m)^n - 1) x (1 + r/m)[/tex]
where:
Pmt is the payment amount, which is $1,000 in this case
r is the interest rate per year, which is 6%
m is the number of compounding periods per year, which is 2 since interest is compounded semiannually
n is the total number of compounding periods, which is 10 since there are 5 years and interest is compounded semiannually
(1 + r/m) is the interest factor
Substituting the values, we get:
[tex]FV = $1,000 x ((1 + 0.06/2)^10 - 1) x (1 + 0.06/2)[/tex]
= $1,000 x [tex](1.06^{10[/tex] - 1) x 1.03
= $1,000 x 1.79155 x 1.03
= $1,848.20
Therefore, the future value of the annuity due is $1,848.20, rounded to the nearest cent.
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PLEASE HELP I INCLUDED A WRITTEN VERSION OF MY PROBLEM I WROTE IT PLEASE HELP!!!
Answer:
A. [tex](x-3)^{2}[/tex]
Step-by-step explanation:
Find 2 numbers who's sum is -6 and product is 9
-3 and -3
sum = -6
(-3) * (-3) = 9
product = 9
You can also calculate each option individually
A.
[tex](x -3)^{2} = (x-3)(x-3)[/tex]
Use FOIL... then
[tex]x^{2} -6x+9[/tex]
Answer:
Step-by-step explanation: The answer to this problem would be A . You would first see if the first and third numbers were perfect squares and if they were you would put the value of the perfect squares in parentheses and add a 2 at the top of the answer after the parentheses
can some help me please.
Answer:
8√23 ≈ 38.37
Step-by-step explanation:
You want the length of a chord 10 units from the center of a circle when a chord 12 units from the center has length 36 units.
RadiusThe radius OA completes the right triangle OBA. The hypotenuse (OA) is found using the Pythagorean theorem:
OA² = OB² +BA²
OA² = 12² +18² = 468
ChordRadius OF is the same length, so we can use the Pythagorean theorem to find FE.
OF² = OE² +FE²
FE² = OF² -OE² = 468 -10² = 368
FD = 2·FE = 2√368 = 8√23
FD ≈ 38.37
why is 10x2=20?.......
The product of 10 by 2 = 20 because when 10 is multiplied twice(2) the result would be = 20.
What is multiplication?Multiplication is defined as one of the major arithmetic operations used in solving mathematical questions which involves the duplication of a value.
Other arithmetic operations include addition, subtraction and Division.
The multiplication of a value can also be the product of the value and another value.
That is 10×2 is the product of 10 and 2 which should be = 20.
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How do you solve (2b) to the 4th power?
To solve (2b) to the 4th power, we need to raise the entire quantity of 2b to the power of 4.
This can be done by multiplying the quantity (2b) by itself 4 times using the power rule of exponents, which states that (a^m)^n = a^(m*n).
So we have:
(2b)^4 = (2b) x (2b) x (2b) x (2b)
Expanding this expression, we get:
(2b)^4 = 2 x 2 x 2 x 2 x b x b x b x b
Simplifying further, we can multiply the 2's together to get:
(2b)^4 = 16b^4
Therefore, the expression (2b) to the 4th power simplifies to 16b^4.
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Jason needs to send out flyers for his business. He needs to spend $250 on a printer and each flyer will cost $0.80 for ink, paper, and mailing costs.
a. Complete the table giving the total cost Jason will spend to send out the specific number of flyers.
What is the perimeter of the figure?
O24 units
O27 units
O 30 units
O 21 units
Answer:
B. 27 Units
Step-by-step explanation:
To find the perimeter of the figure, we simply add up the lengths of all the sides.
So, the perimeter of the figure with sides of length 8, 6, 4, and 9 units is:
P = 8 + 6 + 4 + 9 = 27 units
Therefore, the answer is B. 27 units.
the time spent waiting in the line is approximately normally distributed. the mean waiting time is 5 minutes and the standard deviation of the waiting time is 2 minutes. find the probability that a person will wait for more than 9 minutes. round your answer to four decimal places.
The probability that a person will wait for more than 9 minutes is approximately 0.0228, or 2.28% when rounded to four decimal places
To find the probability that a person will wait for more than 9 minutes, we'll use the z-score formula and a standard normal distribution table (Z-table).
First, calculate the z-score using the formula:
z = (X - μ) / σ
Where X is the value we're interested in (9 minutes), μ is the mean (5 minutes), and σ is the standard deviation (2 minutes).
z = (9 - 5) / 2
z = 4 / 2
z = 2
Now, look up the probability for a z-score of 2 in a Z-table. You'll find a value of 0.9772, which represents the probability of waiting less than or equal to 9 minutes. To find the probability of waiting more than 9 minutes, subtract this value from 1:
Probability of waiting more than 9 minutes = 1 - 0.9772 = 0.0228
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.
suppose a problem asks for the probability of at most four successes when there are only five trials. which one of these expressions would provide the answer?
The sum of all these probabilities is equal to 1, which is the total probability of all possible outcomes.
To solve this problem, we need to consider all the possible outcomes that result in at most four successes. These outcomes are:
0 successes
1 success
2 successes
3 successes
4 successes
The probability of each of these outcomes can be calculated using the binomial distribution formula:
P(k) = (n choose k) [tex]* p^k * (1-p)^(n-k)[/tex]
where n is the number of trials, k is the number of successes, and (n choose k) is the binomial coefficient, which is equal to n!/(k!*(n-k)!).
To find the probability of at most four successes, we need to add up the probabilities of all these outcomes. So the expression that would provide the answer is:
P(0 successes) + P(1 success) + P(2 successes) + P(3 successes) + P(4 successes)
This expression includes all the possible outcomes that correspond to having at most four successes in five trials. Note that it does not include the probability of having five successes, since we are only interested in the probability of at most four successes.
For example, if the probability of success in each trial is 0.3, then the probability of having zero successes is:
P(0 successes) = (5 choose 0)[tex]* 0.3^0 * 0.7^5 = 0.168[/tex]
Similarly, the probability of having one success is:
P(1 success) = (5 choose 1) [tex]* 0.3^1 * 0.7^4 = 0.360[/tex]
We can calculate the probabilities of having two, three, and four successes in a similar way. Then, we can add up all these probabilities to get the probability of at most four successes:
P(at most 4 successes) = P(0 successes) + P(1 success) + P(2 successes) + P(3 successes) + P(4 successes)
In this example, we get:
P(at most 4 successes) = 0.168 + 0.360 + 0.308 + 0.132 + 0.032 = 1.000
Note that the sum of all these probabilities is equal to 1, which is the total probability of all possible outcomes.
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what is 80 cm equal to?
$10 invested at 5% compounded continuously after a period of 2 years
The final amount after 2 years of continuous compounding at a 5% annual interest rate is $11.05.
Step By Step Calculation:
Step 1: Convert the annual interest charge from a percent to a decimal. In this case, the yearly interest rate is 5%, so we have:
r = 5% = 0.05
Step 2: Use the formulation for continuous compounding to calculate the final amount A, where P is the initial principal and t is the time in years:
[tex]A = Pe^{(rt)}[/tex]
Substituting the given values, we get:
[tex]A = 10e^{(0.05*2)}[/tex]
Step 3: Simplify the exponential expression through elevating the natural number e to the power of 0.1:
[tex]A = 10e^{0.1}[/tex]
Step four: examine e^0.1 the use of a calculator or by means of the use of the Taylor series expansion for [tex]e^x[/tex]:
[tex]e^x = 1 + x + (x^2/2!) + (x^3/3!) + ...[/tex]
when x = 0.1, we get:
[tex]e^0.1 = 1 + 0.1 + (0.1^2/2!) + (0.1^3/3!) + ... = 1.10517092...[/tex]
Step 5: Multiply the preliminary most important by means of the calculated cost of e^0.1 to get the final quantity:
[tex]A = 10 * 1.10517092 = $11.05[/tex]
Consequently, the final amount after 2 years of continuous compounding at a 5% annual interest rate is $11.05.
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Unit test Kumari owns a form that grows thousands of oranges and tangerines. A disease is affecting her fruit, and she suspects that her oranges are more likely to have the disease than her tangerines. She took separate random samples of each type of fruit. She found that 3 of 10 oranges sampled had the disease, and 1 ot 15 tangerines sampled had the distanse. She wants to use these results to make a two-sample : Interval to estimate the difference between the proportion of each type of fruit that has the disease. Which conditions for this type of interval did her samples meet? Choose all answers that apply: a.Both samples were randomly selected from their populations b.The observed counts of successes and failures are sufficiently large in each sample. c.Individual observations in each sample can be considered independent, and the samples themselves are independent.
a. Both samples were randomly selected from their populations and c. Individual observations in each sample can be considered independent, and the samples themselves are independent.
Explanation: To use a two-sample interval to estimate the difference between the proportion of each type of fruit that has the disease, the following conditions must be met:
a. Both samples were randomly selected from their populations (this ensures that the samples are representative of their respective populations)
b. The observed counts of successes and failures are sufficiently large in each sample (this ensures that the normal approximation can be used)
c. Individual observations in each sample can be considered independent, and the samples themselves are independent (this ensures that the samples are not related to each other in any way)
In this scenario, Kumari took separate random samples of each type of fruit, meeting the conditions of random selection and independence for both samples. Additionally, the observed counts of successes and failures are sufficiently large (3 of 10 oranges and 1 of 15 tangerines), meeting the condition of large enough counts. Therefore, conditions a and c are both met.
Based on the information provided, Kumari's samples met the following conditions for a two-sample interval estimation:
a. Both samples were randomly selected from their populations
c. Individual observations in each sample can be considered independent, and the samples themselves are independent.
The observed counts of successes and failures (condition b) are not sufficiently large in each sample, as a general rule of thumb is to have at least 10 successes and 10 failures in each sample. In this case, the numbers of diseased and healthy fruits in each sample do not meet this criterion.
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using only the divergence test, determine if you can make a conclusion about the convergence or divergence of each series. provide evidence for your answer.A. ∑[infinity]k=1 2+k/3-k²B. ∑[infinity]k=1 2ek/3+k
We need to use a different test, such as the ratio test or the root test, to make a conclusion.
For the first series, we have:
∑[infinity]k=1 (2+k)/(3-k²)
Using the divergence test, we consider the limit of the general term as k approaches infinity:
lim (k→∞) (2+k)/(3-k²)
We can see that the denominator, k², grows much faster than the numerator, k. Therefore, as k approaches infinity, the term approaches zero. However, the denominator approaches infinity, meaning that the terms do not go to zero fast enough for the series to converge. Therefore, we can conclude that the series diverges.
For the second series, we have:
∑[infinity]k=1 (2e^k)/(3+k)
Using the divergence test, we consider the limit of the general term as k approaches infinity:
lim (k→∞) (2e^k)/(3+k)
We can see that the denominator, 3+k, grows much faster than the numerator, e^k. Therefore, as k approaches infinity, the term approaches zero. However, the denominator approaches infinity, meaning that the terms do go to zero fast enough for the series to converge. Therefore, we cannot conclude anything about the convergence or divergence of the series using only the divergence test. We need to use a different test, such as the ratio test or the root test, to make a conclusion.
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