Scientist 1 would most likely explain this result by saying, The experiment allowed the magnetic domains of the bar to line up, causing the bar to become magnetic.
Scientist 1 would most likely explain this outcome as follows: The experiment caused the magnetic domains of the bar to align, leading the bar to become magnetic.
Because, according to Scientist 1, magnetism originates when magnetic domains in a material align. Because the iron bar initially exhibited no magnetism, we may suppose that its magnetic domains were oriented randomly at first, with no magnetic poles. When the iron bar became magnetic after being heated and chilled, the heating and chilling process most likely reoriented the magnetic domains in the iron, resulting in two magnetic poles.
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17. Which of the following supports the idea that the genetic code is common to all living
things?
A. All living things share similar modes of reproduction
B. The same adaptations help all living things survive in the same way.
C. All living things have identical ways of using energy for survival.
D. All living things contain DNA with the same nitrogenous bases.
Answer:
Explanation:
genetic code us a keyword
different organisms have diff ways in reproducting
different ways of adapting to environments, obtianing energy, etc. It's mainly asking what makes all living things have something in common, like ALL all
The blood pressure in millimeters was measured for a large sample of people. The average pressure is 140 mm, and the sd of the measurements is 20 mm. The histogram looks reasonably like a normal curve. Use the normal curve to estimate the following percentages. Choose the answer that is closest to being correct.
Here are some possible percentages and their corresponding estimated z-scores:
Percentage of people with blood pressure below 120 mm: approximately 9.1% Estimated z-score: z = (120 - 140) / 20 = -1Percentage of people with blood pressure between 120 and 160 mm: approximately 68.3%Estimated z-scores: z1 = (120 - 140) / 20 = -1 and z2 = (160 - 140) / 20 = 1Percentage of people with blood pressure above 160 mm: approximately 9.1%Estimated z-score: z = (160 - 140) / 20 = 1These percentages are based on the empirical rule, which states that for a normal distribution, approximately 68% of the data falls within one standard deviation of the mean, approximately 95% falls within two standard deviations, and approximately 99.7% falls within three standard deviations.
What is the empirical rule?The empirical rule, also known as the 68-95-99.7 rule, is a statistical principle that describes the approximate distribution of data in a normal distribution. The rule states that:
Approximately 68% of the data falls within one standard deviation of the mean.Approximately 95% of the data falls within two standard deviations of the mean.Approximately 99.7% of the data falls within three standard deviations of the mean.This rule is based on the assumption that the data is normally distributed, meaning that it follows a symmetrical bell-shaped curve. The empirical rule is widely used in statistics and is helpful in understanding the range of values that are likely to occur in a normal distribution.
It is important to note that the empirical rule provides only approximations and can vary in accuracy depending on the specific data and distribution being analyzed.
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Option: B, The percentage of people with blood pressure between 114 and 166 mm
What is the empirical rule?The empirical rule, also known as the 68-95-99.7 rule, is a statistical principle that describes the approximate distribution of data in a normal distribution. The rule states that:
=> P(114 < x < 166)
=> P((114-140)/20 < z < (166-140)/20)
=> P(-1.3 < z < 1.3)
=> 0.8064
=> 80.6% rounded
option: D The percentage of people with blood pressure between 114 and 166 mm
=> P(140 < x < 166)
=> P((140-140)/20 < z < (166-140)/20)
=> P(0 < z < 1.3)
=> 0.4032
=> 40.3% rounded
option: C The percentage of people with blood pressure over 166 mm
=> P(x > 166)
=> P(z > (166-140)/20)
=> P(z > 1.3)
=> 0.0968
=> 9.7% rounded
This rule is based on the assumption that the data is normally distributed, meaning that it follows a symmetrical bell-shaped curve. The empirical rule is widely used in statistics and is helpful in understanding the range of values that are likely to occur in a normal distribution.
It is important to note that the empirical rule provides only approximations and can vary in accuracy depending on the specific data and distribution being analysed.
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A ball strikes the floor for 0.0105 s and experiences a change in momentum of 1.52 kg·m/s. What is the force experienced by the ball?
Answer:The concept of momemtum will be used to solve this question.A moving body's momemtum, which is generally equal to the product of the body's mass and velocity, is a quality that the body has as a result of its mass and motion.
Explanation:
A 12.5 m boom, AB, of a crane lifting a 3,000 kg load is shown below. The center of mass of the boom is at its geometric center, and the mass of the boom is 1,400 kg. For the position shown, calculate the following. tension T in the cable (in N) N the force at the axle A (Give the magnitude in newtons and the direction in degrees counterclockwise from the +x-axis. Assume that the +x-axis is to the right.) magnitude N direction
The force at the axle A is 35,903 N, in the direction 60 degrees counterclockwise from the +x-axis.
Describe Distance?Distance is a numerical measurement of how far apart two points are. It is a scalar quantity that represents the length of the path traveled between two points in space, regardless of the direction. Distance is typically measured in units such as meters, kilometers, miles, or feet. It is an important concept in physics, as it is used in many physical calculations, such as those involving speed, velocity, and acceleration. It is also a fundamental concept in everyday life, as it is used to describe the separation between two objects or locations.
To solve this problem, we need to use the principle of moments. The sum of moments about any point is equal to zero when the object is in static equilibrium.
First, let's find the distance from point A to the center of mass of the boom. We can use the fact that the boom is uniform and its center of mass is at the geometric center.
distance from A to center of mass = 12.5 m / 2 = 6.25 m
Let's take point A as the pivot point for calculating the moments. Then, the moment due to the tension T in the cable is:
moment due to T = T * 12.5 m
The moment due to the weight of the boom is:
moment due to boom =[tex]1400 kg * 9.81 m/s^2 * 6.25 m[/tex]
The moment due to the weight of the load is:
moment due to load = [tex]3000 kg * 9.81 m/s^2 * 12.5 m[/tex]
Since the system is in static equilibrium, the sum of these moments must be equal to zero:
[tex]T * 12.5 m - 1400 kg * 9.81 m/s^2 * 6.25 m - 3000 kg * 9.81 m/s^2 * 12.5 m = 0[/tex]
Solving for T, we get:
[tex]T = (1400 kg * 9.81 m/s^2 * 6.25 m + 3000 kg * 9.81 m/s^2 * 12.5 m) / 12.5 T = 41475 N[/tex]
So the tension in the cable is 41,475 N.
To find the force at the axle A, we can use the fact that the sum of forces in the x and y directions must be equal to zero, since the system is in static equilibrium. Let's take the +x axis to the right and the +y axis upward.
The forces in the x direction are:
[tex]T * cos(30°) - N = 0The forces in the y direction are:T * sin(30°) + 1400 kg * 9.81 m/s^2 + 3000 kg * 9.81 m/s^2 = 0Solving for N, we get:N = T * cos(30°) = 41475 N * cos(30°) = 35903 N[/tex]
So the force at the axle A is 35,903 N, in the direction 60 degrees counterclockwise from the +x-axis.
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In this problem, you will practice applying this formula to several situations involving angular acceleration. In all of these situations, two objects of masses m1 and m2 are attached to a seesaw. The seesaw is made of a bar that has length l and is pivoted so that it is free to rotate in the vertical plane without friction. Assume that the pivot is attached tot he center of the bar. You are to find the angular acceleration of the seesaw when it is set in motion from the horizontal position. In all cases, assume that m1>m2.
Now consider a similar situation, except that now the swing bar itself has mass mbar.(Figure 2)
Find the magnitude of the angular acceleration ? of the seesaw.
Express your answer in terms of some or all of the quantities m1, m2, mbar, l, as well as the acceleration due to gravity g.
The rotational acceleration and speed are shared by all of the points of a rigid body. As a result, the angular acceleration is positive and the rotation is anticlockwise.
A- 2*[(m1 - m2)/(m1 + m2)] *g/L The angular acceleration is positive and the rotation is anticlockwise. (m1 - m2)/(m1+ m2 + mbar/3) B- 2* *g/L The angular acceleration is positive and the rotation is anticlockwise.
(A) The magnitude of angular acceleration of the seesaw in this case is .
2(m₁-m₂)g÷(m₁+m₂)L
(B) The magnitude of angular acceleration of the seesaw in this case is
(m₁ g-m₂ g)÷(m₁+m₂)L
For a massless sea saw bar, with attached masses at each end, the torque produced due to the masses is,
ω=(m₁+m₂)+1/2
And, moment of inertia of the system of two masses is,
I=(m₁+m₂)L/4
The using the expression of torque as,
Angular acceleration is the term used to describe the temporal pace at which angular velocity varies. Radians per second is the accepted unit of measurement. Therefore, = d d t. Angular acceleration is also known as rotational acceleration.
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1. What is the momentum of an 11 kg bowling ball rolling at 4 m/s?
Any moving object has momentum. The momentum of an 11 kg bowling ball rolling at 4 m/s is 44 kg m/s.
What is momentum?The momentum is defined as a quantity which is the product of the mass of the particles and its velocity. It is a vector quantity. It has both magnitude and direction. The rate of change of momentum is equal to the force acting on the particle.
The equation of the momentum is given as:
p = mν
= 11 kg × 4 m/s
= 44 kg m/s
Thus the momentum of the bowling ball is 44 kg m/s.
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An electric field of 6.50×105 V/m
is desired between two parallel plates, each of area 45.0 cm2
and separated by 2.45 mm
of air. What charge must be on each plate?
The charge on each plate is 2.608×10⁻⁸ C. Charge is a fundamental physical property of matter that describes the degree to which it interacts with electromagnetic fields.
Describe Charge?
It is an intrinsic property of subatomic particles, such as protons and electrons, that gives rise to electric and magnetic forces.
The basic unit of charge is the Coulomb (C), named after the French physicist Charles-Augustin de Coulomb, who first quantified the electric force between charged objects. A single proton or electron has a charge of approximately 1.6 x 10⁻¹⁹ Coulombs.
Electric charge is conserved, which means that the total amount of charge in a closed system remains constant over time. Charges can be positive, negative, or neutral, and like charges repel each other, while opposite charges attract each other.
The electric field between two parallel plates is given by:
E = V/d
where E is the electric field, V is the potential difference between the plates, and d is the distance between the plates.
In this case, the desired electric field is E = 6.50×10⁵ V/m, and the distance between the plates is d = 2.45 mm = 0.00245 m. So, we can solve for the potential difference between the plates as:
V = Ed = (6.50×10⁵ V/m)(0.00245 m) = 1592.5 V
Since the potential difference between the plates is the same as the potential difference across the capacitor, we can use the formula for the capacitance of a parallel plate capacitor to find the charge on each plate:
C = ε0A/d
where C is the capacitance, ε0 is the permittivity of free space, A is the area of each plate, and d is the distance between the plates.
Plugging in the given values, we get:
C = (8.85×10⁻¹² F/m)(0.00045 m²)/(0.00245 m) = 1.635×10⁻¹¹ F
Finally, we can find the charge on each plate using the formula:
Q = CV
where Q is the charge on each plate, C is the capacitance, and V is the potential difference between the plates. Plugging in the values we found, we get:
Q = (1.635×10⁻¹¹ F)(1592.5 V) = 2.608×10⁻⁸ C
Therefore, the charge on each plate is 2.608 ×10⁻⁸ C.
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13. A pendulum bob of mass 5 kg is displaced from the vertical until it is 0.25 m above its lowest point. Upon release, it rises to a height of 0.24 m on the other side. How much energy was lost due to friction? Assuming half the total energy loss takes place during the downward swing, with what speed does the bob pass though its lowest point?
The speed of the pendulum bob at its lowest point is 1.92 m/s.
Speed of pendulum calculation explained.Assuming no energy is lost due to air resistance, the total energy of the pendulum is conserved.
Let h be the maximum height the pendulum rises on the right side, and assume that the displacement from the vertical is small enough that we can use the small-angle approximation sin θ ≈ θ. Then, the potential energy of the pendulum at the maximum height is:
U = mgh
where m is the mass of the bob, g is the acceleration due to gravity, and h = 0.24 m.
Similarly, the potential energy of the pendulum at its highest point on the left side is:
U' = mgh'
where h' = 0.25 m.
Since the total energy is conserved, the kinetic energy of the pendulum at its lowest point is equal to the initial potential energy:
K = U - ΔU
where ΔU is the energy lost due to friction. Since half the total energy loss takes place during the downward swing, we have:
ΔU = (1/2)U
Substituting the values, we get:
K = mgh - (1/2)U
K = (5 kg)(9.81 m/s^2)(0.24 m) - (1/2)(5 kg)(9.81 m/s^2)(0.24 m)
K = 5.76 J
At the lowest point, all of this energy is in the form of kinetic energy:
K = (1/2)mv^2
where v is the speed of the bob at the lowest point.
Substituting the values, we get:
5.76 J = (1/2)(5 kg)v^2
Solving for v, we get:
v = sqrt(2K/m)
v = sqrt(2(5.76 J)/(5 kg))
v = 1.92 m/s
Therefore, the speed of the pendulum bob at its lowest point is 1.92 m/s.
To find the energy lost due to friction, we can use the conservation of energy again:
U - ΔU = U' + ΔU'
ΔU + ΔU' = U - U'
Substituting the values, we get:
ΔU + ΔU' = (5 kg)(9.81 m/s^2)(0.25 m) - (5 kg)(9.81 m/s^2)(0.24 m)
ΔU + ΔU' = 4.905 J
Since half the energy loss occurs during the downward swing, we have:
ΔU = (1/2)(4.905 J)
ΔU = 2.453 J
The energy lost due to friction is approximately 2.453 J.
Therefore, The total energy of the pendulum at any point is given by the sum of its potential energy and kinetic energy. At the highest point, the pendulum has only potential energy, and at the lowest point, it has only kinetic energy.
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the combined effect of all forces acting on an object is the ___ force
Answer:
net force
Explanation:
a cyclist while negotiating a circular path with speed of 20m/s is found to be bend at angel of 30° with vertical what is the radius of the circular path
The minimum radius of the circular path for the cyclist traveling at a speed of 20 m/s and a tilt angle of 30° is approximately 17.32 meters.
What is the radius of the circular path?
The formula for the minimum radius of a circular path for a cyclist traveling at a certain speed can be determined using the relationship between the speed, the angle of tilt, and the gravitational force acting on the cyclist.
The minimum radius of the circular path can be calculated using the formula:
r = (v^2) / gtan(θ)
where:
r = radius of the circular path (m)v = speed of the cyclist (m/s)g = acceleration due to gravity (9.8 m/s^2)θ = angle of tilt (30° in this case)Plugging in the values, we get:
r = (20^2) / (9.8 x tan(30°))
r ≈ 17.32 m
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A container of weight W = 200 lb is supported by a continuous cable BAC and a small pulley at A, as shown in the figure below. The cable is attached between two walls that are L = 40 ft apart, and the right support at C is h=8 ft below the left support at B. Cable BAC has a total length LBAC = 50 ft and sags prior to adding the pulley and container. From equilibrium considerations, we can prove that cable segments BA and AC are inclined at the same angle from the horizontal. Neglect the size and weight of the pulley for this analysis. Determine the following quantities:
The inclination angle for both cable segments.
The tension force T in cable BAC.
Answer:
To determine the inclination angle for both cable segments, we can use the law of sines. Let's call the inclination angle "theta."
L/sin(theta) = h/sin(90-theta)
40/sin(theta) = 8/cos(theta)
Cross multiplying and simplifying, we get:
sin(theta) = 8/40 = 1/5
So,
theta = sin^-1(1/5) = 11.31 degrees
Next, we can use the law of cosines to find the tension force T in cable BAC.
T^2 = W^2 + (LBAC)^2 - 2WLBACcos(theta)
T^2 = 200^2 + 50^2 - 2(200)(50)cos(11.31)
T = sqrt(200^2 + 50^2 - 2(200)(50)cos(11.31)) = sqrt(20000 + 2500 - 2000cos(11.31))
T = sqrt(22500 - 2000cos(11.31))
Rounding to the nearest whole number, we get:
T = 150 lb
So, the inclination angle for both cable segments is 11.31 degrees, and the tension force T in cable BAC is 150 lb.
Explanation:
A 25kg turkey is fired from a 1.2x10^3 kg turkey launcher. If the horizontal velocity of the turkey is 245m/s east, what is the recoil of the launcher? A.) 9.38 m/s B.) 7325 m/s C.) 4925 m/s D.) 5.1 m/s
Answer:
Explanation:
A
excavation costs are based on the
A. amount of earth removed
B. depth of the frost line in the area
C. time involved multiplied by a standard rate
D. sophistication of the machinery necessary
Answer:
C
Explanation:
Excavation costs are generally based on the time involved multiplied by a standard rate.
When a 3.8 kg block is pushed against a massless spring of force constant 4.5 x 103 N/m, the spring is compressed 7.8 cm. The
block is released, and it slides 3.0 m (from the point at which it is released) across a horizontal surface before friction stops it.
What is the coefficient of kinetic friction between the block and the surface?
The coefficient of kinetic friction between the block and the surface 0.245.
What is Kinetic friction?Friction is a force that opposes relative motion and manifests itself at the interfaces of bodies as well as inside, as in the case of fluids. Leonardo da Vinci was the first to conceive the idea of friction coefficient.
The characteristics of the surfaces, the environment, surface details, the presence of lubricant, etc. all affect how much friction there is between surfaces.
There are a number of theories on what generates static friction, and like other friction-related ideas, each one holds true in some situations but falls short in others.
Therefore, The coefficient of kinetic friction between the block and the surface 0.245.
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A force of 50 newtons is used to do 5.0 x 102 joules of work on an object. Over what distance was this force applied?
The distance over which the force was applied would be 10 meters.
Work done problemThe work done on an object is given by the product of the force applied and the distance over which it is applied. Therefore, we can use the formula:
Work = Force x Distance
We know that the force applied is 50 newtons, and the work done is 5.0 x 10^2 joules. We can rearrange the formula to solve for distance:
Distance = Work / Force
Substituting the values we know, we get:
Distance = (5.0 x 10^2 J) / 50 N
Distance = 10 meters
Therefore, the force of 50 newtons was applied over a distance of 10 meters to do 5.0 x 10^2 joules of work on the object.
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The bottom cube has mass m2 = 4.8kg and sits on a surface without friction. The top cube has mass m1 = 2.2kg. The friction between the two cubes is μ = 0.5. What is the maximum force that can be applied on the upper cube so that the two cubes move together?
The maximum force that can be applied on the upper cube is 26.29N.
Solving for the the maximum force that can be applied on the upper cube, we have:The maximum force that can be applied on the upper cube so that the two cubes move together is given by the equation:
F_max = μ(m1 + m2)g
where,
μ = the coefficient of friction
m1 and m2 = the masses of the top and bottom cube
g = the acceleration due to gravity.
Substituting in the values, we get:
F_max = 0.5(2.2kg + 4.8kg)(9.81m/s²)
F_max = 26.29N
Therefore, the maximum force that can be applied on the upper cube is 26.29N.
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Electric Field Direction only OO Voltage Values Grid 00V a +1 nc -1 nc Sensors Now, let's look at how the distance from the charge affects the magnitude of the electric field. Select Values on the menu, and then click and drag one of the yellow E-Field Sensors. You will see the magnitude of the electric field given in units of V/m (volts per meter, which is the same as newtons per coulomb). Place the E-Field Sensor 1 m away from the positive charge (1 m is two bold grid lines away if going in a horizontal or vertical direction), and look at the resulting field strength. Consider the locations to the right, left, above, and below the positive charge, all 1 m away. For these four locations, the magnitude of the electric field is. greatest to the right of the charge. greatest below the charge. greatest above the charge. greatest to the left of the charge. O O O the same. Submit Request Answer
Considering the locations to the right, left, above, and below the positive charge, all 1 mm away. For these four locations, the magnitude of the electric field is the same.
The area, space, or field around it is an electric field of an isolated charge. There are mainly two types of electric fields i.e., static and dynamic. Moving charges produced dynamic electric fields whereas static electric fields are produced by stationary charges.
Direction and magnitude do not change over time for static electric fields. The direction can be positive or negative which is determined by the charge of the source.
The electric field formula is the electric field magnitude at a certain point from the charge Q, and it hangs on two factors- the distance r from the point to the origin Q and the amount of charge at the origin Q.
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The correct question is:
Now, let's look at how the distance from the charge affects the magnitude of the electric field. Select Values on the menu, and then click and drag one of the yellow E-Field Sensors. You will see the magnitude of the electric field given in units of V/mV/m (volts per meter, which is the same as newtons per coulomb). Place the E-Field Sensor 1 mm away from the positive charge (1 mm is two bold grid lines away if going in a horizontal or vertical direction), and look at the resulting field strength.
Consider the locations to the right, left, above, and below the positive charge, all 1 mm away. For these four locations, the magnitude of the electric field is________________.
i need help asappp
Lots of scientists had worked on the periodic table other than Mendeleev. What did Dmitri Mendeleev do that set him apart from all of the other scientist?
How do you think Mendeleev was able to so accurately estimate the properties of undiscovered elements?
What do you think would have changed if all of the scientist had worked closely together to figure out the best way to arrange the periodic table? Do you think collaboration is always the best answer
Answer:
Explanation:
1. Mendeleev predicted that there would be more chemical elements to come
2. by looking at the chemical properties
3. i think if all of them came together it would probably still look about the same tho ik it has changed over the years soo
The figure showed a thin rod of length L and charge Q.
Find an expression for the electric potential a distance z away from the center of rod on the line that bisects the rod.
Give your answer in terms of L, Q, z and appropriate constants.
Expression for the electric potential a distance z away from the center of rod on the line that bisects the rod is [tex]V = k * Q / L * \int\limits {cos\theta / z \sqrt{(1 + L^2/4z^2 * tan^2\theta)} d\theta} \, dx[/tex].
The electric potential at a distance z from a point charge Q is given by:
V = k * Q / r
here
k is Coulomb constant and
r is distance from the point charge to the point.
For a thin rod of length L and charge Q, we can model it as a line of charge with linear charge density λ = Q/L. The electric potential at a distance z away from the center of the rod on the line that bisects the rod can be found by breaking the rod into infinitesimal charge elements and integrating the electric potential due to each element over the length of the rod.
Let's consider a small element of length dx located at a distance x from the center of the rod:-
[tex]dQ = \lambda * dx = Q/L * dx[/tex]
The displacement element to pt.:-
[tex]r = \sqrt{(x^2 + z^2)}[/tex]
The electric potential due to this element is:
[tex]dV = k * dQ / r = k * Q/L * dx / \sqrt{(x^2 + z^2)}[/tex]
Integrating this expression over the length of the rod, we get the total electric potential at a distance z away from the center of the rod on the line that bisects the rod:
[tex]V = \int\limits^(^-^L^/^2^)_L_/_2 {k * Q/L * dx / √\sqrt{(x^2 + z^2)}} \, dx[/tex]
To evaluate this integral,
[tex]u = x^2 + z^2, du/dx = 2x dx[/tex],
This can be further simplified:-
[tex]u = z^2 * tan^2\theta + L^2/4 * sec^2\theta[/tex]
[tex]V = k * Q / L * \int\limits {cos\theta / z \sqrt{(1 + L^2/4z^2 * tan^2\theta)} d\theta} \, dx[/tex]
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A ball with momentum must also have?
A. Kinetic energy
B.Thermal energy
C.Gravitational potential energy
D.Elastic energy
= 1.2M²₂// then taking a penedy A constant force of 5N ads to 5 sec. on a mass of 5 kg initially at rest. calculate the final momentum!
The final momentum is 25 Kg m/s
What is the momentum?
In physics, momentum is a measure of an object's motion, calculated by multiplying the object's mass by its velocity. Mathematically, momentum is represented by the symbol "p" and can be expressed as:
p = mv
where "p" is momentum, "m" is mass, and "v" is velocity. Momentum is a vector quantity, meaning that it has both a magnitude (the amount of momentum) and a direction (the direction of the motion).
Given that;
Ft = mv - mu
It then follows that;
F = force
m = mass
v and u are the initial and the final velocities
Thus;
5 * 5 = 5v
v = 25/5
= 5 m/s
The final momentum is thus;
5 m/s * 5 Kg
= 25 Kg m/s
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Two blocks, M1 and M2, are connected by a massless string that passes over a massless pulley as shown in the figure. M2, which has a mass of 19.0 kg,
rests on a long ramp of angle =25.0∘.
Ignore friction, and let up the ramp define the positive direction.
If the actual mass of M1 is 5.00 kg and the system is allowed to move, what is the acceleration of the two blocks?
What distance does block M2 move in 2.00 s?
Two blocks, M1 and M2, are connected by a massless string that passes over a massless pulley . The distance the block M2 move is 3.44 m.
Calculating the problem:
Given:
M₂ = 19 kg
θ = 29 °
when the system is in equilibrium the net force on the system is zero
Fn = 0 = M₁ × g - M₂ × g × sin(θ)
M₁ = 19 × sin(29) kg
M₁ = 9.21 kg
the mass of M₁ is 9.21 kg
when M₁ = 5 kg
The acceleration of system , a = net force /effective mass
a = (M₂ × g × sin(theta) - M₁ × g )/(M₁ + M₂)
a = 9.81 × ( 19 × sin(29) - 5) /(19 + 5)
a = 1.72 m/s²
The acceleration of system is 1.72 m/s²
for t = 2 s
The distance moved by M₂ , s = 0 + 0.5 × a × t²
s = 0 + 0.5 × 1.72 × 2² m
s = 3.44 m
How much is distance?While distance is the length of an object's path, displacement only refers to the distance between an object's starting point and its final location.
Meter (m) is the SI unit for distance. Centimeters (cm) can be used to measure short distances, and kilometers (km) can be used to measure long distances.
What is mass?A body's mass is the amount of material it contains. The SI unit of mass, the kilogram (kg), is the kilogram. A definition of mass is: Volume x density = mass.
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A rock is thrown upward with a velocity of 14
meters per second from the top of a 50
meter high cliff, and it misses the cliff on the way back down. When will the rock be 2
meters from ground level? Round your answer to two decimal places.
Answer:
The rock will be 2 meters from the ground after 1.29 seconds.
Explanation:
The motion of the rock can be described by the following kinematic equation:
h = vi * t + 0.5 * a * t^2
where h is the height of the rock above the ground, vi is the initial velocity (14 m/s), t is time, and a is the acceleration due to gravity (-9.8 m/s^2).
Setting h = 2 m and solving for t, we get:
2 = 14 * t + 0.5 * (-9.8) * t^2
Expanding and solving for t, we get:
t = 1.29 seconds
So, the rock will be 2 meters from the ground after approximately 1.29 seconds.
If a piece of stone has attained a velocity of 88.2 m/s after falling for eight seconds what was its initial velocity
Answer:
the stone's final speed just before hitting the ground is: v = √(2 × 9.81 × 90) m/s = √(1765.8) m/s = 42.0 m/s.
ASAP PLEASE HELP!!!!
A 3.0 kg object swings back and forth as a simple pendulum with a small amplitude. The potential energy U of the object as a function of distance x from its equilibrium position is shown above. This particular object has a total energy E of 0.4 J.
b) What is the farthest the object moves along the x-axis in the positive direction? Explain your reasoning.
The farthest that particular object will move along the x-axis in the positive direction is 0.2 m. This is the amplitude of the pendulum's motion.
What is potential energy?Potential energy in physics is the energy that an item retains as a result of its position in relation to other objects, internal tensions, electric charge, or other elements.
Since the total energy of the object is given by E = U + K, where U is the potential energy and K is the kinetic energy, and the pendulum has a small amplitude, we can assume that the kinetic energy of the object is negligible.
Therefore, we have:
E = U = [tex](1/2)kx^2[/tex]
Khere k is the spring constant of the pendulum and x is the displacement from the equilibrium position.
So, the value of x can be:
x = sqrt(2E/k)
Substituting the given values, we have:
x = sqrt(2(0.4 J)/(20 N/m)) = 0.2 m
Thus, the farthest the object moves along the x-axis in the positive direction is 0.2 m.
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A child of mass 30 kg sits on a wooden carosel. The wooden horse is 7.0m from the center of the carousel, which rotates at a constant rate and completes one revolution every 14.1 seconds. What are the magnitude and direction D|p|/dt, the parallel component dp/dt for the child?
The magnitude of the parallel component of the velocity is 1.4 m/s
The direction is in the direction of rotation of the carousel.
What is the velocity of the child?
The velocity of the child can be calculated using the equation for centripetal acceleration:
a = v^2 / r
where
a = centripetal acceleration (m/s^2)v = velocity of the child (m/s)r = distance from the center of the carousel to the child (m)Rearranging the equation to solve for velocity:
v = √(ar)
The centripetal acceleration is equal to the square of the angular velocity, w, multiplied by the radius:
a = w^2 x r
where
w = angular velocity (radians/s)Since the carousel completes one revolution every 14.1 seconds, the angular velocity can be calculated as:
w = 2π / T
w = 2π / 14.1
Now we can calculate the centripetal acceleration:
a = w^2 x r
a = (2π / 14.1)^2 x 7.0
a = 1.41 m/s²
Finally, we can use this value to calculate the velocity of the child:
v = √(ar)
v = √(1.41 x 7.0)
v = 3.14 m/s
The magnitude of the velocity is the scalar value, or the size of the velocity vector without direction.
The direction of the velocity is perpendicular to the radial line connecting the child to the center of the carousel. It is in the direction that the child is moving.
The parallel component of the velocity is in the direction of the rotation of the carousel and can be calculated using the projection of the velocity onto a line tangent to the circle.
dp/dt = v dθ/dt
where
dθ/dt = angular velocity (radians/s)Substituting the values for velocity and angular velocity:
dp/dt = vw
= 3.14 x (2π / 14.1)
v = 1.4 m/s
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Help Which answer is correct
Answer: plastic
Explanation:
a wheel has angular velocity 4.00 rad/s. which of the following is closest to the number of revolutions that the wheel makes in 15.0 s?
a.10 revolutions
b.20 revolutions
c.15revolutions
d.25 revolutions
e. 5 revolutions
f. i dont know yet
Answer:
10 revolutions
Explanation:
By using the equation Δ=Δ, we get that Δ=(4.00rad/s)(15.0s)=60.0rad. Since there are 2 radians per revolution, this angular displacement corresponds to (60.0rad)/(2rad/rev)=9.55rev.
The angular velocity of the wheel is 4 rad/s and the time interval is 15 s. Then the number of rotations in radians is 60 radians. This is equal to 9.5 revolutions.
What is angular velocity ?Angular velocity is a physical quantity that describes the speed of an object in an angular path. It is the rotational o revolutional analogue of of the linear velocity.
The angular velocity of an object is the product of the linear velocity and the radius of the angular path.
Given that, the angular velocity of the wheel = 4 rad/s
time = 15 s
then, number of radians = 4 rad/s × 15 s = 60 radians.
1 revolution = 2π radians.
then 60 radians = 60/2π = 9.5 revolutions.
Therefore, the number of revolutions for the wheel in 15 s is 9.5 revolutions.
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Prove that AxB = B.A
Unless A=B or unless either A or B is the empty set, AxB does not equal BxA. Students typically have no trouble understanding this because we define a cartesian product as an ordered pair, which implies that order would be important.
What is the parameter for solving cartesian product?A plane's cartesian form is denoted by the formula ax + by + cz = d, where a, b, and c are the direction cosines normal to the plane and d is the distance from the origin to the plane.
If and only if the matching initial elements in both ordered pairs are the same, two ordered pairs are said to be equivalent. (ii) There will be mn elements in A B if there are m elements in A and n elements in B. This means that n(A B) if n(A) = m and n(B) = n.
Therefore, When the inner inverse fulfils P R (B ) B (A B) = 0 and (A B) B P R (B) = 0, it is implied that is closed and is the general solution.
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.Impulse is equal to ... (pick TWO answers) * A.the change in momentum of an object. B.the change in mass of an object. C.the change in volume of an object. D.a force applied to an object for a period of time. E.the original momentum of the object.
The impulse is force × time. Option D
What is Impulse in Physics?In physics, impulse is a quantity that describes the change in momentum of an object that results from a force acting on it for a period of time. Mathematically, impulse is defined as the product of force and the time interval over which it acts:
Impulse = force × time
The unit of impulse is the newton-second (N·s) in the SI system of units.
Impulse is closely related to the concept of momentum, which is the product of an object's mass and velocity. When a force acts on an object, it causes a change in the object's momentum. The magnitude of this change is equal to the impulse that the force imparts on the object.
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