Major findings of evolution of computers

Answer:

in-memory.

Explanation:

A database management system (DBMS) can be defined as a collection of software applications that typically enables computer users to effectively and efficiently create, store, modify, retrieve, centralize and manage data or informations in a database. Thus, it allows computer users to efficiently retrieve and manage their data with an appropriate level of security.

Generally, a database management system (DBMS) acts as an intermediary between the physical data files stored on a computer system and any software application or program.

In this context, data management is a type of infrastructure service that avails businesses (companies) the ability to store and manage corporate data while providing capabilities for analyzing these data.

Hence, a database management system (DBMS) is a system that enables an organization or business firm to centralize data, manage the data efficiently while providing authorized users a significant level of access to the stored data.

Radom Access Memory (RAM) can be defined as the main memory of a computer system which allow users to store commands and data temporarily.

Generally, the Radom Access Memory (RAM) is a volatile memory and as such can only retain data temporarily.

All software applications temporarily stores and retrieves data from a Radom Access Memory (RAM) in computer, this is to ensure that informations are quickly accessible, therefore it supports read and write of files.

Generally, when a database stores the majority of data in random access memory (RAM) rather than in hard disks, it is referred to as an in-memory database (IMDB).

An in-memory database (IMDB) is designed to primarily to store data in the main memory of a computer system rather than on a hard-disk drive, so as to enhance a quicker response time for the database management system (DBMS).

Answer:

Header and footer

Explanation:

The page layout tab usually found in document programs such as Microsoft Word hold options used to configure several page options which is to be applied to a document. The page layout option gives users options to set page margins, orientation, page numbering, indentation and the other page layout options which is primarily how we would like our document to look like when printed. The page layout option also allows the insertion of a header and footer which is a note which can be written at the topmost and bottomost part of the document. Once, a header and footer option is selected, it is applied to every page of the document being worked on at the moment.

Answer:

#include <stdio.h>

int main()

{

   int avg = 0;

   int sum =0;

   int x=0;

   /* Array- declaration – length 4*/

   int num[4];

   /* We are using a for loop to traverse through the array

    * while storing the entered values in the array

    */

   for (x=0; x<4;x++)

   {

       printf("Enter number %d \n", (x+1));

       scanf("%d", &num[x]);

   }

   for (x=0; x<4;x++)

   {

       sum = sum+num[x];

   }

   avg = sum/4;

   printf("Average of entered number is: %d", avg);

   return 0;

}

Answer:

Unification may be a process by which two logical individual atomic expressions, identical by replacing with a correct substitution. within the unification process, two literals are taken as input and made identical using the substitution process. There are some rules of substitution that has got to be kept in mind:

The predicate symbol must be an equivalent for substitution to require place.

The number of arguments that are present in both expressions must be equivalent.

Two similar variables can't be present within the same expression

Explanation:

a. American (Bob), American (y):-

In this scenario, Unification is feasible consistent with the principle. The substitution list is going to be [y/Bob].

b. Enemy (Nono, America), Enemy(x,y):-

In this scenario, the Unification is feasible consistent with the principles. The substitution list is going to be [x/Nono, y/America].

c. Weapon (Missile), soldTo (Missile, y), Weapon (x), soldTo (x, Nono):-

In this scenario, the Unification isn't possible because the predicate is different i.e. Weapon and soldTo.

d. L(x, y), (L(y, x) ^ L(A, B)):-

In this scenario, Unification isn't possible because the number of arguments is different within the given expression

Answer:

money

Explanation:

for working for socializing with orher

Answer:

He belongs to the nation

Using the concepts of public and private domains, it means that the photograph of the president can be used by anyone without asking for permission.

---------------

Public and private domains:

A similar question is given at https://brainly.com/question/12202794

Answer: 52

Explanation:

Following the information given in the question, we are informed that a process needs 103 KB of memory in order to run and that the system on which it is to run uses paging with 2KB pages, then the number of frames in memory that are needed will be:

= 103/2

= 51.5

= 52 approximately

Therefore, 52 frames in memory are needed.

Answer:-

CODE:

#include <iostream>

#include<cmath>

using namespace std;

float calcBaseArea(float a);

float calcSideArea(float s,float l);

void prntSprfArea(float base_area,float side_area);

int main()

{

float h;

float a;

float base_area

float side_area;

cout<<"Enter the side length of the base of the square pyramid in feet : ";

cin>>a;

cout<<"Enter the height of the square pyramid in feet : ";

cin>>h;

base_area=calcBaseArea(a);

side_area=calcSideArea(a,h);

cout<<"Base surface area of the square pyramid is "<<base_area<<" square feet. "<<endl;

cout<<"Side area of the square pyramid is "<<side_area<<" square feet."<<endl;

prntSprfArea(base_area,side_area);

return 0;

}

float calcBaseArea(float a)

{

return pow(a,2);

}

float calcSideArea(float s,float l)

{

float area=(s*l)/2;

return 4*area;

}

void prntSprfArea(float base_area,float side_area)

{

cout<<"Total surface area of the pyramid is "<<base_area+side_area<<" square feet.";

OUTPUT:

Answer:

Explanation:

Important functions of an operating System:  

Security –  

The operating system uses password protection to protect user data and similar other techniques. it also prevents unauthorized access to programs and user data.  

Control over system performance –  

Monitors overall system health to help improve performance. records the response time between service requests and system response to have a complete view of the system health. This can help improve performance by providing important information needed to troubleshoot problems.  

Job accounting –  

Operating system Keeps track of time and resources used by various tasks and users, this information can be used to track resource usage for a particular user or group of user.  

Error detecting aids –  

Operating system constantly monitors the system to detect errors and avoid the malfunctioning of computer system.  

Coordination between other software and users –  

Operating systems also coordinate and assign interpreters, compilers, assemblers and other software to the various users of the computer systems.  

Memory Management –  

The operating system manages the Primary Memory or Main Memory. Main memory is made up of a large array of bytes or words where each byte or word is assigned a certain address. Main memory is a fast storage and it can be accessed directly by the CPU. For a program to be executed, it should be first loaded in the main memory. An Operating System performs the following activities for memory management:  

It keeps tracks of primary memory, i.e., which bytes of memory are used by which user program. The memory addresses that have already been allocated and the memory addresses of the memory that has not yet been used. In multi programming, the OS decides the order in which process are granted access to memory, and for how long. It Allocates the memory to a process when the process requests it and deallocates the memory when the process has terminated or is performing an I/O operation.  

Processor Management –  

In a multi programming environment, the OS decides the order in which processes have access to the processor, and how much processing time each process has. This function of OS is called process scheduling. An Operating System performs the following activities for processor management.  

Keeps tracks of the status of processes. The program which perform this task is known as traffic controller. Allocates the CPU that is processor to a process. De-allocates processor when a process is no more required.  

Device Management –  

An OS manages device communication via their respective drivers. It performs the following activities for device management. Keeps tracks of all devices connected to system. designates a program responsible for every device known as the Input/Output controller. Decides which process gets access to a certain device and for how long. Allocates devices in an effective and efficient way. Deallocates devices when they are no longer required.  

File Management –  

A file system is organized into directories for efficient or easy navigation and usage. These directories may contain other directories and other files. An Operating System carries out the following file management activities. It keeps track of where information is stored, user access settings and status of every file and more… These facilities are collectively known as the file system.  

Answer:

The id selector selects a particular html element

Explanation:

The id selector is uses the id attribute to select a specific html element. For example, if we have a particular header which is an html element and we want to give it a particular background color, we use the id selector and give it an id attribute in the CSS file. An example of an html header with id = 'blue' is shown below. The style sheet is an internal style sheet.

!doctype html

<html>

<head>

<title>Test</title>

<style>

#blue { background-color: blue;

}

</style>

</head>

<body>

<h1 id = 'blue'>Our holiday</h1>

<p>This is the weekend</p>

</body>

</html>

Answer: data warehouse

Explanation:

Data-mining agents work with a Data warehouse which helps in detecting trends and discovering new information.

A data warehouse refers to the large collection of business data that is used by organizations to make decisions. It has to do with the collection and the management of data from different sources which are used in providing meaningful business insights.

Answer:

E). User education and training.

Explanation:

In the context of network security, the most significant aspect of ensuring security from workstation cyberattacks would be 'education, as well as, training of the users.' If the employee users are educated well regarding the probable threats and attacks along with the necessary safety measures to be adopted and trained adequately to use the system appropriately so that the sensitive information cannot be leaked while working on the workstation and no networks could be compromised. Thus, option E is the correct answer.

Answer:

Memory-mapped I/O and port-mapped I/O are two complementary methods of performing input/output between the central processing unit and peripheral devices in a computer. An alternative approach is using dedicated I/O processors, commonly known as channels on mainframe computers, which execute their own instructions.

Answer:

Chernoff faces.

Explanation:

Chernoff faces is a data visualization technique that was developed by a statistician named Herman Chernoff. He introduced this data visualization technique to the world in 1973 to represent multivariate or multidimensional data containing at least eighteen (18) variables.

In Chernoff faces, each attribute is associated with a specific feature of a face (nose, eyes, ears, hair, mouth, and eyebrows), and the attribute value with respect to size, shape, orientation, colour and placement is used to determine the way a facial feature is expressed.

The Chernoff face is a technique designed and developed to help detect similarities between different items and discern subtle changes in facial expressions from the perspective of an observer.

It’s a click-to-call ad

Answer:

Explanation:

The following is written in Java. It uses File input, to get the file and read every line in the file. It adds all the lines into a variable called fullString. Then it uses regex to split the string into separate words. Finally, it maps the words into an array that counts all the words and how many times they appear. A test case has been created and the output can be seen in the attached image below. Due to technical difficulties I have added the code as a txt file below.

Answer:

Hybrid Computer has features of both analogue and digital computer. It is fast like analogue computer and has memory and accuracy like digital computers. It can process both continuous and discrete data. So it is widely used in specialized applications where both analogue and digital data is processed.

Answer:

Vulnerability assessment

Explanation:

Cyber security can be defined as preventive practice of protecting computers, software programs, electronic devices, networks, servers and data from potential theft, attack, damage, or unauthorized access by using a body of technology, frameworks, processes and network engineers.

Some examples of cyber attacks are phishing, zero-day exploits, denial of service, man in the middle, cryptojacking, malware, SQL injection, spoofing etc.

A vulnerability assessment is a systematic and methodical evaluation used by network security experts to determine the exposure of network assets such as routers, switches, computer systems, etc., to attackers, forces of nature, or any other entity that is capable of causing harm i.e potential harms. Thus, vulnerability assessment simply analyzes and evaluate the network assets of an individual or business entity in order to gather information on how exposed these assets are to hackers, potential attackers, or other entities that poses a threat.

Answer:

double decimal1, decimal2;

int whole;

Explanation:

Required

Declare 2 decimals and 1 int.

The syntax to declare a variable is:

data-type variable-name;

To declare decimal, we simply make use of double or float data types.

So, we have:

double decimal1, decimal2; ----> for the decimal variables

And

int whole; ---- for the whole number

Answer:

The program is as follows:

[tex]mult\_table = [[1, 2, 3], [2, 4, 6], [3, 6, 9]][/tex]

count = 1

for row in mult_table:

   for item in row:

       if count < len(row):

           count+=1

           print(item,end="|")

       else:

           print(item)

   count = 1

Explanation:

This initializes the 2D list

[tex]mult\_table = [[1, 2, 3], [2, 4, 6], [3, 6, 9]][/tex]

This initializes the count of print-outs to 1

count = 1

This iterates through each rows

for row in mult_table:

This iterates through each element of the rows

   for item in row:

If the number of print-outs is less than the number of rows

       if count < len(row):

This prints the row element followed by |; then count is incremented by 1

           count+=1

           print(item,end="|")

If otherwise

       else:

This prints the row element only

           print(item)

This resets count to 1, after printing each row

   count = 1

To delete the whitespace, you have to print each element as:            print(item,end="|")

See that there is no space after "/"

Answer:

count = 1

for row in mult_table:

  for item in row:

      if count < len(row):

          count+=1

          print(item,end=" | ")

      else:

          print(item)

  count = 1

Explanation: Other answers didnt have the spacing correct

Answer:

Bridges and switches

Explanation:

4a) A bridge is an intelligent repeater that is aware of the MAC addresses of the nodes on either side of the bridge and can forward packets accordingly.

A switch is an intelligent hub that examines the MAC address of arriving packets in order to determine which port to forward the packet to.

4b) Twisted-pair cable is a type of cabling that is used for telephone communications and most modern Ethernet networks

Answer:

All of these.

PLZ MARK ME BRAINLIEST.

Answer:

LAB means laboratory

IEEE means institute of electrical and electronic engineer

Answer:

The answer is "Option a and Option f"

Explanation:

The cross-site programming and Server-Side Requests fraud were activities that can have negative effects as these are assaults that directly affect your cloud-based servers via web apps. Although the remainder of an attack could be controlled with these approaches, then they can affect the encryption keys only less.

Answer:

#Implementation of Queue class

class Queue

   #Implementation of _init_

   def _init_(self, limit=10):

       #calculate the self.data

       self.data = [None] * limit

       self.head = -1

       self.tail = -1

   #Implementation of enqueue function

   def enqueue(self, val):

       #check self.head - self.tail is equal to 1

       if self.head - self.tail == 1:

           raise NotImplementedError

       #check len(self.data) - 1 is equal to elf.tail

       if len(self.data) - 1 == self.tail and self.head == 0:

           raise NotImplementedError

       #check self.head is equal to -1

       if self.head == -1 and self.tail == -1:

           self.data[0] = val

           self.head = 0

           self.tail = 0

       else:

           #check len(self.data) - 1 is equal to self.tail

           if len(self.data) - 1 == self.tail and self.head != 0:

               self.tail = -1

           self.data[self.tail + 1] = val

           #increment the self.tail value

           self.tail = self.tail + 1

   #Implementation of dequeue method

   def dequeue(self):

       #check self.head is equal to self.tail

       if self.head == self.tail:

           temp = self.head

           self.head = -1

           self.tail = -1

           return self.data[temp]

       #check self.head is equal to -1

       if self.head == -1 and self.tail == -1:

           #raise NotImplementedError

          raise NotImplementedError

       #check self.head is not equal to len(self.data)

       if self.head != len(self.data):

           result = self.data[self.head]

           self.data[self.head] = None

           self.head = self.head + 1

       else:

          # resetting head value

           self.head = 0

           result = self.data[self.head]

           self.data[self.head] = None

           self.head = self.head + 1

       return result

   #Implementation of resize method

   def resize(self, newsize):

       #check len(self.data) is less than newsize

       assert (len(self.data) < newsize)

       newdata = [None] * newsize

       head = self.head

       current = self.data[head]

       countValue = 0

       #Iterate the loop

       while current != None:

           newdata[countValue] = current

           countValue += 1

           #check countValue is not equal to 0

           if countValue != 0 and head == self.tail:

               break

           #check head is not equal to

           #len(self.data) - 1

           if head != len(self.data) - 1:

               head = head + 1

               current = self.data[head]

           else:

               head = 0

               current = self.data[head]

     self.data = newdata

       self.head = 0

       self.tail = countValue - 1

   #Implementation of empty method

   def empty(self):

       #check self.head is equal to -1

       # and self.tail is equal to -1

       if self.head == -1 and self.tail == -1:

           return True

       return False

   #Implementation of _bool_() method

   def _bool_(self):            

       return not self.empty()

   #Implementation of _str_() method        

   def _str_(self):

       if not (self):

           return ''

       return ', '.join(str(x) for x in self)

   #Implementation of _repr_ method

   def _repr_(self):

       return str(self)

   #Implementation of _iter_ method

   def _iter_(self):

       head = self.head

       current = self.data[head]

       countValue = 0

       #Iterate the loop

       while current != None:

           yield current

           countValue += 1

           #check countValue is not equal to zero

           #check head is equal to self.tail

           if countValue != 0 and head == self.tail:

               break

           #check head is not equal to len(self.data) - 1

           if head != len(self.data) - 1:

               head = head + 1

               current = self.data[head]

           else:

               head = 0

               current = self.data[head

Explanation:-

Output:

Answer:

Here the answer is given as follows,

Explanation:

Operating Platform:-  

In terms of platforms, there are differences between, mobile games and pc games within the way it's used, the operator, the most event play, the sport design, and even the way the sport work. we all know that each one the games on console platforms, PC and mobile, have their own characteristic which has advantages and disadvantages All platforms compete to win the rating for the sake of their platform continuity.  

Operating system architectures:-  

Arm: not powerful compared to x86 has many limitations maximum possibility on arm arch is mobile gaming.  

X86: very powerful, huge development so easy to develop games on platforms like unity and unreal, huge hardware compatibility and support  

Storage management:-  

On the storage side, we've few choices where HDD is slow and too old even a replacement console using SSD. so SSD is the suggested choice. But wait SSD have also many options like SATA and nvme.    

Memory management:-  

As recommended windows, Each process on 32-bit Microsoft Windows has its own virtual address space that permits addressing up to 4 gigabytes of memory. Each process on 64-bit Windows features a virtual address space of 8 terabytes. All threads of a process can access its virtual address space. However, threads cannot access memory that belongs to a different process.  

Distributed systems and networks:-  

Network-based multi-user interaction systems like network games typically include a database shared among the players that are physically distributed and interact with each other over the network. Currently, network game developers need to implement the shared database and inter-player communications from scratch.  

Security:-  

As security side every game, there's an excellent risk that, within the heat of the instant, data are going to be transmitted that you simply better keep to yourself. There are many threats to your IT.  

Define on the whole data protection matters when developing games software may cause significant competitive advantages. Data controllers are obliged under the GDPR to attenuate data collection and processing, using, as an example , anonymization or pseudonymization of private data where feasible.

Answer:

In addition, a few modern printers can directly interface to electronic media such as memory cards, or to image capture devices such as digital cameras, scanners; some printers are combined with a scanners and/or fax machines in a single unit, and can function as photocopiers.

Explanation:

Should the company separate its voice and data needs, using standard analog services for voice but finding some advanced digital transmission services for data ($40 per month for each voice line and $300 per month for a circuit with 1.5 Mbps for data)?