what is the magnitude of the average velocity of the hummingbird between 2 sec and t 4 sec
1. Small hole is made up of a window
shutter of a room, 12.5m and image
of the car outside the room cast on
the opposite if the image is 6.5m
high and the tree is 32.5cm from
the window. What is the high of
the tree?
Answer:
I don't know sorry I hope you find what your looking
AV ASSIGNMENT what is the length of wire whose resistivity, 3x10^6 ohm with the r=0.2mm with a given Value of 15.5 ohm's Resistance.
How are temperature and average kinetic energy related? Explain.
Answer:
Explanation:
Suppose you have a box filled with all sorts of molecules that won't react with each other.
Suppose further that these molecules move. What formula are they obeying? the answer is Ke = 1/2 m v^2.
Now the mass is not going to change, but what about v, the velocity. It certainly can change.
Suppose further, that the molecules are in a closed container. Suppose that the box is heated up. What will happen? The molecules can't escape. All they can do is move faster (remember that they are trapped inside the box). Their mass won't change.
So if you put a thermometer inside a cork into a whole where the cork will seal the hole, what will the thermometer record. Those fast moving molecules will hit the thermometer and make the molecules of the thermometer move faster. The liquid inside the thermometer will measure the Ke of the molecules. So temperature is related to Ke.
The more heat, the faster the molecules are moving. The more they move, the more Ke is being transferred to the thermometer. The more heat transferred to the thermometer, the more the liqiuid in the thermometer will expand, and the higher the temperature.
So shortly temperature is the measurement of Ke inside the closed container that is filled with gas molecules.
Which of the following statements does not represent assumptions that stage theories share?
A.
Each stage builds on the knowledge of the previous stage.
B.
Each stage corresponds to a specific age.
C.
A child can pass through the stages in any order.
D.
Each stage is qualitatively different than the next.
Each stage corresponds to a specific age. is the statements do not represent assumptions that stage theories share.
What is stage theory?Any speculative construct is used to represent phases or steps in a time-based process, such as a belief that development proceeds in discontinuous phases indicated by functional changes.
Each stage corresponds to a specific age the statements do not represent assumptions that stage theories share.
The assumptions for the stage theory are as follows;
1. Every stage serves as a building block for the next.
2. The phases are followed in the same sequence by everyone.
3. Each step is distinct in terms of quality. It is a change in nature, not merely a change in amount.
Each stage corresponds to a specific age. is the statements do not represent assumptions that stage theories share.
Hence option B is the right option.
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A car advertisement states that a certain car can accelerate from rest to
40 km/hr in 5 sec. Find the car's average acceleration.
Answer:
8 km/h²
Explanation:
a = v-u/t
v is final velocity, u is initial velocity
a = 40-0/5
a = 8.0 km/h²
Which term s the product of force and distance?
O power
O work
Onetforce
Oacceleration
Answer:
The answer should be WORK
(Hope this Helps)
Explanation:
work is equal to the product of force and distance.
W=F*S
W=Work
F=Force applied
S=Distance
A scientist observes rock masses that have moved past each other in opposite horizontal directions. Which feature
does the scientist observe?
A. plateau
B. syncline
C. strike-slip fault
D. fault-block mountain
Answer:
C. strike-slip fault
Explanation:
The scientist must have observed a strike- slip fault.
A fault is an evidence of brittle deformation of the crust in the presence of applied stress on earth materials. Here, the earth material is the rock subjected to tension.
Where a fault occurs, there must have been movement between two blocks of rocks. The direction of movement helps us to delineate the fault type.
When two blocks moves past each other horizontally, it is a strike-slip fault like rubbing your palms together. When a block moves in the direction of the dip, it forms a dip-slip fault which results in a fault-block mountain characterized by graben and horst systems.Option A, Plateau is a table landform usually a mountain with flat peak.
Option B is a bowl shaped stratigraphic pattern in which the youngest sequence is at the core of the strata or a fold.
So, the most fitting option is C, a strike-slip fault.
Answer:
Explanation:
c
Suppose that A’, B’ and C’ are at rest in frame S’, which moves with respect to S at speed v in the +x direction. Let B’ be located exactly midway between A’ and C’. At t’=0 a light flash occurs at B’ and expands outward as spherical wave.
1. According to an observer in S’, do the wave fronts arrive at A’ and C’ simultaneously?
2. According to an observer in S, do the wavefronts arrive at A’ and C’ simultaneously?
3. If you answered no to either 1. or 2., what is the difference in their arrival times and at which point did the front arrive first?
Answer:
1) an observer in B 'sees the two simultaneous events
2)observer B sees that the events are not simultaneous
3) Δt = Δt₀ /√ (1 + v²/c²)
Explanation:
This is an exercise in simultaneity in special relativity. Let us remember that the speed of light is the same in all inertial systems
1) The events are at rest in the reference system S ', so as they advance at the speed of light which is constant, so it takes them the same time to arrive at the observation point B' which is at the point middle of the two events
Consequently an observer in B 'sees the two simultaneous events
2) For an observer B in system S that is fixed on the Earth, see that the event in A and B occur at the same instant, but the event in A must travel a smaller distance and the event in B must travel a greater distance since the system S 'moves with velocity + v. Therefore, since the velocity is constant, the event that travels the shortest distance is seen first.
Consequently observer B sees that the events are not simultaneous
3) let's calculate the times for each event
Δt = Δt₀ /√ (1 + v²/c²)
where t₀ is the time in the system S' which is at rest for the events
Points A (-5,6), B (2,-2), and C (-6,-3) are placed in three different quadrants of a Cartesian coordinate system. Convert each set of Cartesian coordinates to polar coordinates. The angle should be reported as a positive angle, in degrees, from the positive x-axis. (0° < θ < 360°). What is the θ coordinate for point A? Recall this should be in units of degrees.
Answer: A ([tex]\sqrt{61}[/tex],309.8°)
B (2[tex]\sqrt{2}[/tex], 315°)
C ([tex]3\sqrt{5}[/tex], 26.56°)
Explanation: To transform rectangular coordinates into polar coordinates use:
[tex]r=\sqrt{x^{2}+y^{2}}[/tex] and [tex]\theta=tan^{-1}(\frac{y}{x})[/tex]
For point A:
[tex]r=\sqrt{(-5)^{2}+6^{2}}[/tex]
[tex]r=\sqrt{61}[/tex]
[tex]\theta=tan^{-1}(\frac{6}{-5})[/tex]
[tex]\theta=tan^{-1}(-1.2)[/tex]
[tex]\theta=-50.2[/tex]°
Point A is in the II quadrant, so we substract the angle for 360° since it is in degrees:
[tex]\theta=360-50.2[/tex]
[tex]\theta=[/tex] 309.8°
Polar coordinates for point A is ([tex]\sqrt{61}[/tex], 309.8°)
For point B:
[tex]r=\sqrt{2^{2}+(-2)^{2}}[/tex]
[tex]r=\sqrt{8}[/tex]
[tex]r=2\sqrt{2}[/tex]
[tex]\theta=tan^{-1}(\frac{-2}{2} )[/tex]
[tex]\theta=tan^{-1}(1)[/tex]
[tex]\theta=-45[/tex]°
Point B is in IV quadrant, so:
[tex]\theta=360-45[/tex]
[tex]\theta=[/tex] 315°
Polar coordinates for point B is ([tex]2\sqrt{2}[/tex], 315°)
For point C:
[tex]r=\sqrt{(-6)^{2}+(-3)^{2}}[/tex]
[tex]r=\sqrt{45}[/tex]
[tex]r=3\sqrt{5}[/tex]
[tex]\theta=tan^{-1}(\frac{-3}{-6} )[/tex]
[tex]\theta=tan^{-1}(0.5)[/tex]
[tex]\theta=[/tex] 26.56°
Polar coordinates for point C is ([tex]3\sqrt{5}[/tex], 26.56°)
Your boat departs from the bank of a river that has a swift current parallel to its banks. If you want to cross this river in the shortest amount of time, you should direct your boat If you want to cross this river in the shortest amount of time, you should direct your boat:_________
a. perpendicular to the current.
b. upstream.
c. downstream.
d. so that it drifts with the current.
Answer:
D.
Explanation:
Given that your boat departs from the bank of a river that has a swift current parallel to its banks. If you want to cross this river in the shortest amount of time, you should direct your boat: so that it drifts with the current.
If the boat moves perpendicular to the current, the current flow will be the resistance to the movement of the boat. So, it's better for the boat to drifts perpendicularly with the current.
The best answer is therefore option D.
Calculate the mass of air in a room if the floor dimensions are 10 mx
12 m and height 4 m. The density of air is 1.26 kgm.
604.8 kg
Explanation:Hi there !
d = m/V => m = d×V
V = l×w×h = 10m×12m×4m = 480 m³
m = 1.26kg/m³×480m³ = 604.8 kg
Good luck !
Two forces,
vector F 1 = (5.90î − 5.60ĵ) N
and
vector F 2 = (4.65î − 5.55ĵ) N,
act on a particle of mass 2.10 kg that is initially at rest at coordinates
(−1.75 m, +4.15 m).
(a) What are the components of the particle's velocity at t=10.4s ?
(b) In what direction is the particle moving at t = 10.4 s? (+counterclockwise from the x axis)
(c) What displacement does the particle undergo during the first 10.4 s?
(d) What are the coordinates of the particle at t = 10.4 s? (in x and y meters)
First compute the resultant force F:
[tex]\mathbf F_1=(5.90\,\mathbf i-5.60\,\mathbf j)\,\mathrm N[/tex]
[tex]\mathbf F_2=(4.65\,\mathbf i-5.55\,\mathbf j)\,\mathrm N[/tex]
[tex]\implies\mathbf F=\mathbf F_1+\mathbf F_2=(10.55\,\mathbf i-11.15\,\mathbf j)\,\mathrm N[/tex]
Then use Newton's second law to determine the acceleration vector [tex]\mathbf a[/tex] for the particle:
[tex]\mathbf F=m\mathbf a[/tex]
[tex](10.55\,\mathbf i-11.15\,\mathbf j)\,\mathrm N=(2.10\,\mathrm{kg})\mathbf a[/tex]
[tex]\mathbf a\approx(5.02\,\mathbf i-5.31\,\mathbf j)\dfrac{\rm m}{\mathrm s^2}[/tex]
Let [tex]\mathbf x(t)[/tex] and [tex]\mathbf v(t)[/tex] denote the particle's position and velocity vectors, respectively.
(a) Use the fundamental theorem of calculus. The particle starts at rest, so [tex]\mathbf v(0)=0[/tex]. Then the particle's velocity vector at t = 10.4 s is
[tex]\mathbf v(10.4\,\mathrm s)=\mathbf v(0)+\displaystyle\int_0^{10}\mathbf a(u)\,\mathrm du[/tex]
[tex]\mathbf v(10.4\,\mathrm s)=\left((5.02\,\mathbf i-5.31\,\mathbf j)u\,\dfrac{\rm m}{\mathrm s^2}\right)\bigg|_{u=0}^{u=10.4}[/tex]
[tex]\mathbf v(10.4\,\mathrm s)\approx(52.2\,\mathbf i-55.2\,\mathbf j)\dfrac{\rm m}{\rm s}[/tex]
If you don't know calculus, then just use the formula,
[tex]v_f=v_i+at[/tex]
So, for instance, the velocity vector at t = 10.4 s has x-component
[tex]v_{f,x}=0+\left(5.02\dfrac{\rm m}{\mathrm s^2}\right)(10.4\,\mathrm s)=52.2\dfrac{\rm m}{\mathrm s^2}[/tex]
(b) Compute the angle [tex]\theta[/tex] for [tex]\mathbf v(10.4\,\mathrm s)[/tex]:
[tex]\tan\theta=\dfrac{-55.2}{52.2}\implies\theta\approx-46.6^\circ[/tex]
so that the particle is moving at an angle of about 313º counterclockwise from the positive x axis.
(c) We can find the velocity at any time t by generalizing the integral in part (a):
[tex]\mathbf v(t)=\mathbf v(0)+\displaystyle\int_0^t\mathbf a\,\mathrm du[/tex]
[tex]\implies\mathbf v(t)=\left(5.02\dfrac{\rm m}{\mathrm s^2}\right)t\,\mathbf i+\left(-5.31\dfrac{\rm m}{\mathrm s^2}\right)t\,\mathbf j[/tex]
Then using the fundamental theorem of calculus again, we have
[tex]\mathbf x(10.4\,\mathrm s)=\mathbf x(0)+\displaystyle\int_0^{10.4}\mathbf v(u)\,\mathrm du[/tex]
where [tex]\mathbf x(0)=(-1.75\,\mathbf i+4.15\,\mathbf j)\,\mathrm m[/tex] is the particle's initial position. So we get
[tex]\mathbf x(10.4\,\mathrm s)=(-1.75\,\mathbf i+4.15\,\mathbf j)\,\mathrm m+\displaystyle\int_0^{10.4}\left(\left(5.02\dfrac{\rm m}{\mathrm s^2}\right)u\,\mathbf i+\left(-5.31\dfrac{\rm m}{\mathrm s^2}\right)u\,\mathbf j\right)\,\mathrm du[/tex]
[tex]\mathbf x(10.4\,\mathrm s)=(-1.75\,\mathbf i+4.15\,\mathbf j)\,\mathrm m+\dfrac12\left(\left(5.02\dfrac{\rm m}{\mathrm s^2}\right)u^2\,\mathbf i+\left(-5.31\dfrac{\rm m}{\mathrm s^2}\right)u^2\,\mathbf j\right)\bigg|_{u=0}^{u=10.4}[/tex]
[tex]\mathbf x(10.4\,\mathrm s)\approx(542\,\mathbf i-570\,\mathbf j)\,\mathrm m[/tex]
So over the first 10.4 s, the particle is displaced by the vector
[tex]\mathbf x(10.4\,\mathrm s)-\mathbf x(0)\approx(270\,\mathbf i-283\,\mathbf j)\,\mathrm m-(-1.75\,\mathbf i+4.15\,\mathbf j)\,\mathrm m\approx(272\,\mathbf i-287\,\mathbf j)\,\mathrm m[/tex]
or a net distance of about 395 m away from its starting position, in the same direction as found in part (b).
(d) See part (c).
on a time line.
Different categories of events should be
O A) grouped together
OB) indistinguishable from one another
O C) distinguished from one another
D) next to one another
Answer:
D
Explanation:
why do crumple zones reduce the force in a collision.
The maximum speed with which you can throw a stone is about 20 m/s. Can you hit a window 45 m away horizontally and 10 m up from the point where the stone leaves your hand? What is the maximum height of a window you can hit at this distance?
Answer:
y = 17 m
Explanation:
For this projectile launch exercise, let's write the equation of position
x = v₀ₓ t
y = [tex]v_{oy}[/tex] t - ½ g t²
let's substitute
45 = v₀ cos θ t
10 = v₀ sin θ t - ½ 9.8 t²
the maximum height the ball can reach where the vertical velocity is zero
v_{y} = v_{oy} - gt
0 = v₀ sin θ - gt
0 = v₀ sin θ - 9.8 t
Let's write our system of equations
45 = v₀ cos θ t
10 = v₀ sin θ t - ½ 9.8 t²
0 = v₀ sin θ - 9.8 t
We have a system of three equations with three unknowns for which it can be solved.
Let's use the last two
v₀ sin θ = 9.8 t
we substitute
10 = (9.8 t) t - ½ 9.8 t2
10 = ½ 9.8 t2
10 = 4.9 t2
t = √ (10 / 4.9)
t = 1,429 s
Now let's use the first equation and the last one
45 = v₀ cos θ t
0 = v₀ sin θ - 9.8 t
9.8 t = v₀ sin θ
45 / t = v₀ cos θ
we divide
9.8t / (45 / t) = tan θ
tan θ = 9.8 t² / 45
θ = tan⁻¹ ( 9.8 t² / 45 )
θ = tan⁻¹ (0.4447)
θ = 24º
Now we can calculate the maximum height
v_y² = [tex]v_{oy}^2[/tex] - 2 g y
vy = 0
y = v_{oy}^2 / 2g
y = (20 sin 24)²/2 9.8
y = 3,376 m
the other angle that gives the same result is
θ‘= 90 - θ
θ' = 90 -24
θ'= 66'
for this angle the maximum height is
y = v_{oy}^2 / 2g
y = (20 sin 66)²/2 9.8
y = 17 m
thisis the correct
when a driver presses the brake pedal, his car stops with an acceleration of -2.1 m/s. How far will the car travel while coming to a complete stop if its initial speed was 13 m/s?
Answer:
40.2 m
Explanation:
A deductive argument is always a stronger argument than an inductive argument
O True
False
A Moving to another question will save this
What is the horizontal acceleration of a ball that is launched horizontally with a velocity of 5.6 m/s?
O -9.8 m/s2
O 0 m/s2
O 5.6 m/s2
O 9.8 m/s2
Answer:
A
Explanation:
edge 2020
The horizontal acceleration of a ball that is launched horizontally with a velocity of 5.6 m/s will be zero. Option B is correct.
What is projectile motion?The motion of an item hurled or projected into the air, subject only to gravity's acceleration, is known as projectile motion.
The item is known as a projectile, and the course it takes is known as a trajectory. Falling object motion is a simple one-dimensional kind of projectile motion with no horizontal movement.
The projectile's motion is divided into two parts: horizontal and vertical motion.
The horizontal acceleration of a ball that is launched horizontally with a velocity of 5.6 m/s will be zero.
Hence, option B is correct.
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Bob rides his motorcycle with a constant speed of 72km/h. How far can he travel in 4 hours?
Answer:
288 Km/h
Explanation:
72x4=288
therefore 288 is your answer
18. The displacement of an object moving 330 km North for 2 hours and an additional 220
km North for 5 hours is
a. 110 km North
b. 220 km North
c. 330 km North
d. 550 km North
19. When something falls to the ground, it accelerates. This acceleration is called the acceleration due to
gravity and is symbolized by the letter g. What is the value of g on Earth's surface?
a. 9.8 m/s2
b. 9.8 m/s
c. - 9.8 m/s2
d. about 20 m/s2
Answer:
Explanation:
1) Displacement of the object will be gotten using simply adding the distances since they are goinf in the same direction (positive y direction)
Displacement= 330km + 220km
Displacement = 550km North
2) For a falling body, the body will possess positive acceleration due to gravity because it is falling under the influence of gravitational force. If a body is not under the influence of gravity and is thrown up, such body wont come back down. Hence the value of acceleration due to gravity of a body falling to the ground is +9.8 m/s² (note that the unit of acceleration is m/s²)
The MAIN function of political parties in the United States is to
Recruiting and nominating candidates.
A 100 kg man stands on bathroom scale inside an elevator, on planet where free fall acceleration is 10 m.s^2. Elevator moves down with constant speed 5 m/s up. Reading of the scale is?
A.1500 N
B.1000 N
C.500 N
D.0 N
Answer: i think its A. Let me knows if its wrong so i can double check
Explanation:
The reading on the scale, if the 100 kg man standing inside the elevator, which is moving with a velocity of 5 m/s is 1000 Newtons, so option B is correct.
What is acceleration?Acceleration describes the speed and direction changes in velocity over time. Acceleration refers to the change in speed or direction of an item or points traveling straight forward. Even though the speed is constant, motion on a circle increases because of the constant change in direction.
Both effects add to the acceleration for all other types of motion. Since acceleration has both a magnitude and a direction, it is a vector quantity. Velocity is a vector.
Given:
The mass of man, m = 100 kg,
The speed of the elevator, s = 5 m/s,
The reading is higher when the person is in a standing elevator (or one moving at a steady speed).
w = mg =100*10 = 1000 N
Now:
If the elevator is going down at 5 m/s and the weight will be
W = m(g -a)
W = 100 (10 -0)
Here the acceleration of lift is zero as it is moving with constant speed,
W = 1000 N
Therefore, the reading on the scale, if the 100 kg man standing inside the elevator which is moving with a velocity of 5 m/s is 1000 Newtons.
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A football field lies so one endzone is to the east and one is to the west. A running back gets the ball and starts running 20o north of east. After running 10 meters, he sees open field and starts running straight east for 60 meters at which point a safety closes in on him. He cuts so he is running 35o east of south. After running another 20 meters he gets in the end zone. Ultimately we want to know what is the vector that points from where he started to where he scored.
Answer:
( 80.87 i - 12.96 j ) m
Explanation:
Running back movements :
20⁰ north of east for 10 meters,
Runs straight east for 60 meters
runs 35⁰ east of south for 20 meters
A) show vector pointing from the starting point to the end ( where he scored )
The final vector displacement : ( 80.87 i - 12.96 j ) m
which is : 81.90 m, 9.10⁰ south of east
attached below is the required diagram
3. Magnitude of a physical quantity is the number of times a standard quantity is present in it.
Which of the following is the best prediction of what would happen if the distance across section 1 in the diagram were to decrease?
1. Frequency would increase
2. Energy would decrease
3. Wavelength would increase
4. Amplitude would decrease
Answer:
Option (1)
Explanation:
Relation between wavelength and frequency of a wave is,
Wavelength (λ) ∝ [tex]\frac{1}{\text{Frequency}}[/tex]
That means wavelength is inversely proportional to the frequency of a wave.
When the wavelength of the wave is decreased, frequency of the wave will increase.
Therefore, if the distance across section 1 is decreased in the given picture,
wavelength gets decreased.
As a result frequency of the wave will increase.
Option (1) will be the answer.
Write one reason why we study motion
Answer:
We study motion becuase it is the best way of determining the best method of doing the work by scrutinizing the motions made by the worker or the machine
Hope this helps :)
Sophia wanted to estimate the product 73 x 12 so she made an estimate of 70x 10. Would her estimate be greater or near the actual estimate?
a plane took 3 hours and 33 minutes to finish a journey. if the distance of the journey was 2840 miles at what average speed did the plane travel
Answer:
The average speed was 800 miles/hour
Explanation:
Average Speed
If an object travels a distance d in a time t regardless of the direction, the average speed is the quotient of the distance over the time:
[tex]\displaystyle V=\frac{d}{t}[/tex]
A plane took 3 hours and 33 minutes to travel d=2840 miles to finish its journey. We will calculate the average speed in miles per hour, thus the time needs to be expressed in hours, and it's given in a mixed unit:
t=3 hours+33 minutes
Since there are 60 minutes in an hour:
t=3 hours+33 /60 hours = 3 hours + 0.55 hours = 3.55 hours
Now calculate the average speed:
[tex]\displaystyle V=\frac{2840}{3.55}=800[/tex]
The average speed was 800 miles/hour
New evidence does not change what scientists already believe to be true. Group of answer choices True False
