Answers
Answer:
Rounded to the nearest whole number the electric field is 899000000
Explanation:
To calculate the magnitude of the electric field at point P, we can use Coulomb's law, which states that the force between two point charges is given by F = k * Q₁ * Q₂ / r², where k is Coulomb's constant, Q₁ and Q₂ are the charges, and r is the distance between the charges.
In this case, we are trying to find the electric field at point P, which is the force per unit charge. So we can find the force on a small test charge, q, placed at point P and divide by q to find the electric field.
F = k * Q₁ * q / x²
E = F/q
where E is electric field,
k = 8.99 x 10⁹ N.m²/C²
x = 51 cm = 0.51 m
Q₁ = -2 x 10⁻⁶ C
q = -1 x 10⁻⁶ C
Substituting these values into the equation, we get:
E = (k * Q₁ * q) / x²
E = (8.99 x 10⁹ N.m²/C² * -2 x 10⁻⁶ C * -1 x 10⁻⁶ C) / (0.51 m)²
E = -8.99 x 10⁹ N/C
The magnitude of the electric field at point P is 8.99 x 10⁹ N/C.
Rounded to the nearest whole number the electric field is 899000000 N/C.
Related Questions
A stone of mass 4.0kg is pulled along a horizontal path by a rope which makes an angle of 30 with the horizontal. Neglecting friction, calculate the tension in the rope if the body accelerates uniformly at 2m/s2
Answers
Answer:
9.24 N
Explanation:
The force accelerating the 4 kg body is the horizontal force = T cos 30
F= ma so:
T cos 30 = 4 kg ( 2 m/s^2)
T = 8 / cos (30) = 9.24 N
label each marked position of mars with the phrase that most accurately describes its apparent motion in our sky against the background stars. A - Retrograde
B - Prograde - moving faster
C - Prograde - moving slower
Answers
The phrase that most accurately describes its apparent motion in our sky against the background stars is west then Prograde - moving slower then Retrograde then Prograde - moving faster and at last east.
The apparent motion of a planet or other object as seen from Earth against a background of stars, moving from west to east (looking or viewing to the south - apparent right to left) which is called Prograde motion.
Retrograde motion is defined as "the apparent motion of a planet or other object as seen from Earth against the background of stars, moving from east to west (looking/viewing to the south - apparent left to right) motion."
When a superior planet (Mars, Jupiter, Saturn, Uranus, etc.) orbits the Sun at a distance greater than that of the Earth and is passed by the latter, which is moving with a higher relative velocity, the 'Superior' planet's normal direct motion appears to stop and then temporarily turn retrograde, giving it the appearance of undergoing a loop or zigzag in the sky.
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The graph shows how the force component F cos θ along the displacement varies with the magnitude s of the displacement. Find the work done by the force. The graph plots F cosine of theta versus s. At s equals zero the graph is at zero and then rises linearly to the value 62 newtons. It then descends linearly to zero forming a shaded triangle of base 1.6 meters.
Answers
The work done by the force is 49.6 J.
The complete question is in the attachment. The formula to calculate work done
W = F × d × cos α
F = force (Newton) d = displacement (m) α = the angle between the force and the displacementWhen the condition
Forces that work in an object F = F cos θIt means the direction of the force is to the right along the x-axis.The displacement along the x-axis
The direction of the displacement is to the right along the x-axis. α = 0°cos α = cos 0° = 1W = F cos θ × d × cos α
W = F cos θ × d × 1
W = F cos θ × d
The area under the curve in the force against displacement graph shows the work done.
W = Area of triangle
W = (b × h) ÷ 2
W = (b × h) ÷ 2
W = (62.0 × 1.60) ÷ 2
W = 99.2 ÷ 2
W = 49.6 Joule
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a roller coaster cart starts from rest and accelerates, due to gravity, down a track. the cart starts at a height that enables it to complete a loop in the track the magnitude of the centripetal force keeping the cart in circular motion would be greatest at point
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A roller coaster cart starts from rest and accelerates, due to gravity, down a track. the cart starts at a height that enables it to complete a loop in the track the magnitude of the centripetal force keeping the cart in circular motion would be greatest at point
The magnitude of the centripetal force keeping a roller coaster cart in circular motion is given by the equation F = mv^2/r, where m is the mass of the cart, v is its velocity, and r is the radius of the circle it is moving in. At the point where the magnitude of the centripetal force is greatest, the velocity of the cart is highest and the radius of the circle is smallest. This point is typically at the bottom of the loop, where the track is closest to the ground and the velocity is greatest. Hence, the magnitude of the centripetal force keeping the roller coaster cart in circular motion would be greatest at the bottom of the loop.
What the Meanning of Circular Motion?Circular motion is a movement of an object along the circumference of a circleor rotation along a circular path. It can be uniform, with constant angular rate of rotation and constant speed, or non-uniform with a changing rate of rotation.
Examples of circular motion include: an artificial satellite orbiting the Earth at a constant height, a ceiling fan's blades rotating around a hub, a stone which is tied to a rope and is being swung in circles, a car turning through a curve in a race track, an electron moving perpendicular to a uniform magnetic field, and a gear turning inside a mechanism.
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You twirl a over your head at a tangential speed of 3.80 per secondWhat is the contripetal acceleration of the lasso's from your hand m / (s ^ 2)
Answers
The centripetal acceleration of the lasso's from your hand is determined as 5.78 m/s².
What is the centripetal acceleration?The centripetal acceleration of the lasso's from your hand is calculated by applying the following formula as shown below.
a = ( v² ) / ( r )
where;
v is the tangential speed r is the radius of the circular path.a = ( 3.8 m/s )² / ( 2.5 m )
a = 5.78 m/s²
Thus, the centripetal acceleration of the lasso's from your hand is a function of the tangential speed and the radius of the circular path.
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The complete question is below:
You twirl a over your head at a tangential speed of 3.80 per secondWhat is the contripetal acceleration of the lasso's from your hand m / (s ^ 2), if the radius of the circular path is 2.5 m?
Lasers can be used to drill or cut material. One such laser generates a series of high-intensity pulses rather than a continuous beam of light. Each pulse contains 540 mJ of energy and lasts 12 ns . The laser fires 10 such pulses per second.
Answers
2 In an oscillation experiment with the spiral spring, the time taken for 30 oscillations with
different masses were measured and the result tabulated below.
M (g)
100
200
300
400
500
600
e (cm)
4.10
8.10
12.00
16.00
20.10
24.00
t(s)
13.40
18.30
21.50
25.00
27.50
30.00
T(S)
T² (5²)
(a) Using two separate graph sheets, plot graphs of M against e and M against 7²
(b) Determine the slopes of the two graphs and their standard errors.
(c) Given that M=ke and T = 2,
M+mo, where k is the spring's force constant and mo is a
kg
constant, deduce the value of k and g from your graphs and give their S.I. units
Answers
According to Hooke's Law, the force given to a spring causes it to stretch directly in proportion.
Using a spiral spring, how do you determine the acceleration brought on by gravity?There is a restoring force Mg=xng when a mass, M, coupled to the spring extends it by a distance, x. Here, n=extensionload (n is the slope of the first graph you will construct), and g=gravitational acceleration The spring's effective mass, m, can be found by looking at the T2 vs. load graph's x-intercept.According to Hooke's Law, the force given to a spring causes it to stretch directly in proportion. (Engineers assert that stress and strain are inversely related.) F represents the force, x is the stretch, and k is a proportionality constant. These three terms are represented by the symbols F = kx.The complete question is,
What was the experiment's finding about spiral springs?
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Describe an experiment to determine the frequency, amplitude and period of a flywheel in motion.
Answers
Answer:
To determine the moment of inertia of a flywheel we will have to consider a few important factors. First, we have to set up a flywheel along with apparatus like a weight hanger, slotted weights, metre scale and we can even keep a stopwatch.
Then we make some assumptions.
We will take the mass as (m) for the weight hanger as well as the hanging ring. The height will be (h). Now we consider an instance where the mass will descend to a new height.
the response to a question has three alternatives: a, b, and c. a sample of 120 responses provides 60 a, 12 b, and 48 c. show the frequency and relative frequency distributions. class frequency relative frequency a b c total
Answers
The total frequency is 120 1.
The frequency of each response category is the number of times it occurs in the sample. The relative frequency of each response category is the fraction of the total responses that belong to each category.
Class Frequency Relative Frequency
a 60 60/120 = 1/2
b 12 12/120 = 1/10
c 48 48/120 = 2/5
Total 120 1
Therefore, the frequency and relative frequency distributions of the responses are:
Class Frequency Relative Frequency
a 60 1/2
b 12 1/10
c 48 2/5
Total 120 1
Frequency refers to the number of times a particular event or item occurs in a set of data. It is a measure of how often an event or item appears in a data set. In statistical analysis, frequency is used to describe the distribution of a set of data, such as the number of occurrences of a particular value, category, or event. Frequency can be expressed as an absolute number or as a proportion or percentage of the total number of events or items in the data set. Frequency is an important concept in statistics and data analysis, as it provides a way to summarize and describe the patterns and relationships within a data set.
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A student does an experiment to measure the electrical resistance of a piece of material. The resistance is found to be equal to 236092. The student's lab partner then measures the electrical resistance of the same material and gets a value of 251092 for the electrical resistance. What is the percent difference between these two
Answers
The percent difference between the two measurements is 61.9%.
The absolute value of change is divided by the average of the values to generate the percent difference formula, which is then multiplied by 100.
The ratio of the difference between two values to their average, represented as a percentage, is what is referred to as the percentage difference.
The difference between two amounts of the same sort can be expressed in this fashion.
It is determined by applying the following equation: |Difference/Average| × 100%.
To calculate the percent difference between the two measurements, you can use the formula:
Percent difference = (|measurement 1 - measurement 2| / ((measurement 1 + measurement 2) / 2)) * 100
Plugging in the values from the experiment:
Percent difference = (|236092 - 251092| / ((236092 + 251092) / 2)) * 100
= (150,000 / 243,092) * 100
= 61.9%.
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hearing rattles from a snake, you make two rapid displacements of magnitude 1.8 m and 2.4 m . choose the sketch (drawn roughly to scale) that shows how your two displacements might add up to give a resultant of magnitude: 4.2 m 0.60 m 3.0 m drag the appropriate labels to their respective targets. not all labels will be used.
Answers
The displacement must be in same, opposite and perpendicular directions to get the net displacements as 4.2 m, 0.6 m and 3.0 m.
The two displacements are, 1.8 m and 2.4 m.
Since 1.8 m + 2.4 m = 4.2 m.
The displacements must be aligned in the same direction.
For the second case, where net displacement should be 0.6 m.
Since 2.4 m - 1.8 m = 0.6 m,
In this case the displacements must be in opposite directions.
For net displacement 3.0 m, the two displacements must be perpendicular to each other since,
[tex]\sqrt{{1.8}^2+{2.4}^2} = 3.0[/tex]
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On the Earth, you can see the ground in someone’s shadow; on the moon, you can’t—the shadow is deep black. Explain the difference.
Answers
Therefore, the moon itself casts shadows on the moon when sunlight hits its surface and is reflected, appearing as moonlight from Earth.
Why is the moon's surface in shadow? The so-called Rayleigh dispersion effect is one of the scientific features that can distinguish between the Earth and the moon.This idea is known as the dispersion of electromagnetic radiation, including visible light, by particles whose size is significantly smaller than the wavelength of the photons being scattered.Even our "shadows" can be seen clearly because to our atmosphere.The shadows on the moon appear darker when there is no atmosphere present or any other mechanism that allows sunlight to be absorbed or refracted away from the area in its shadows. Therefore, the moon itself casts shadows on the moon when sunlight hits its surface and is reflected, appearing as moonlight from Earth.To learn more about moon's surface refer
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Pressure Problems The pictured U-tube is with the mercury open to the atmosphere at both ends. Assume that the mystery fluid does not mix with the Mercury (a) Let po represent atmospheric pressure, phg represent the density of mercury, and pi represent the density of the mystery fluid. Obtain an algebraic expression for the density of the mystery fluid in terms of some or all of the following: hi, ha, hs, and pe (b) For the situation shown in the figure, which is true, pr Phe Or Prhe Explain. If hi- 2.55 cm and h2 25.00 cm (clearly the figure is not to scale), then what is the most likely identity of the mystery fluid? On what scientific evidence did you base your choice? (c) Page 11 of 276 (d) If the absolute pressure at Point A is 114,200 Pa, what is the height hs? Use the nume from Part (c). Using previous numerical values, determine the gauge pressure at Point A. Take atmospheric pressure to be po 101,300 Pa. (e)
Answers
(a) The density of the mystery fluid, ρi, is given by the equation ρi = (h2 - h1) * ρHg. (b) In this situation, pρHg > pρi is true. This is because the density of mercury is greater than the density of the mystery fluid, so the pressure of the mercury is greater. The most likely identity of the mystery fluid is air, as this is the most common fluid found in the atmosphere. (c) The absolute pressure at Point A is calculated using the equation po + pρHg * h2 + pρi * hi. (d) Using the numerical values given, the height hs is calculated to be 2.55 cm. The gauge pressure at Point A can then be calculated to be 114,200 Pa - 101,300 Pa = 12,900 Pa. (e)
scientists often calculate how likely the outcome of their experiments may be due to chance. if this is less than 5%, then the results may be considered reliable.
Answers
Yes, it is correct. The results may be considered reliable if the chance of an outcome due to chance is less than 5%.
What do you mean by experiments?
Experiment is a method of testing a hypothesis or theory by observing the results of an action under controlled conditions. Experiments help scientists to learn how certain variables interact and influence one another, and can be used to test theories and develop new ideas.
However, it is important to note that there are other factors to consider when assessing the reliability of results, such as the accuracy of the measurements and the quality of the data.
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While in Earth’s orbit, an 80-kg astronaut carrying a 20-kgtool kit is initially drifting toward a stationary (to her) spaceshuttle at a speed of 2 m/s. What is her final speed if shethrows the tool kit toward the shuttle with a speed of 6 m/s asseen from the shuttle.
Please show a correct solution to this problem so that I canrate you a lifesaver.
Answers
The final speed of the astronaut in this scenario will be 1 m/s toward the shuttle.
This can be calculated by using the conservation of momentum - the momentum of the astronaut plus the momentum of the tool kit before the throw must equal the momentum of the astronaut plus the tool kit after the throw.
Momentum before the throw = (80 kg)(2 m/s) + (20 kg)(0 m/s) = (160 kg m/s) Momentum after the throw = (80 kg)(v) + (20 kg)(6 m/s)
Solving for v gives us v = 1 m/s. Therefore, the astronaut's final speed is 1 m/s toward the shuttle.
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The site now places a weigin of 0.39 N on top of the block of wood. She then starts to pour ell into the measuring cylinder. The rule balances again when there is 60 cm3 of oil in the measuring cylinder. The gravitational field strength g is 10 N/kg.
(a) Calculate (i) the weight of the oil in the cylinder,
(ii) the mass of the oil in the cylinder.
Fig. 5.1 (b) Calculate the density of the oil.
Answers
Density (ρ) = mass/volume
mass = ρ * volume
The volume of the oil in the cylinder is 60 cm3, and since 1 cm3 = 0.001 liters, the volume in liters is 0.06 liters. The density of the oil is not given, so we can't find the mass of the oil.
(ii) To find the mass of the oil, we can use the formula:
mass = weight / g
mass = 0.39 N / 10 N/kg
mass = 0.039 kg
b) To find the density of the oil, we can use the formula:
density = mass / volume
density = 0.039 kg / 0.06 liters
density = 0.65 kg/liter
(a)
(i) The weight of the oil in the cylinder can be calculated using the formula: weight = force = mass * gravitational field strength.
Given that the gravitational field strength is 10 N/kg, and the volume of oil is 60cm^3 we can find the mass of oil by using the formula of density=mass/volume
density=mass/volume
mass=densityvolume
mass=100060
mass=60000g
so the weight of the oil in the cylinder is:
weight = mass * gravitational field strength
weight = 60000g * 10 N/kg
weight = 600000 N
(ii) The mass of the oil in the cylinder can be calculated using the formula: mass = weight / gravitational field strength
mass = 600000 N / 10 N/kg
mass = 60000g
(b) The density of the oil can be calculated using the formula: density = mass/volumemass / volume
density = 60000g / (60 cm^3)
density = 1000 kg/m^3
So, the density of the oil is 1000 kg/m^3.
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One atmosphere of pressure is defined as 101.325 kPa. From the answer as below, select the closest approximation to the mass of air above a square meter of the earth
Answers
Answer:
The answer is 8.73 kPa.
Hope this helped you. Tell me if I am wrong.
I also answered first. Please brainliest if any chance!
Explanation:
A 0.300−kg puck, initially at rest on a horizontal, frictionless surface, is struck, is struck by a 0.200−kg puck moving initially along the x axis with a speed of 2.00 m/s. After the collision, the 0.200−kg puck has a speed of 1.00 m/s at an angle of θ=53.0o to the positive x axis (see Figure 9.11).
Find the fraction of kinetic energy transferred away or transformed to other forms of energy in the collision.
Answers
97.5% of the initial kinetic energy was transferred away or transformed to other forms of energy in the collision.
The fraction of kinetic energy lost in a collision is equal to 1 minus the fraction of initial kinetic energy that remains after the collision. To calculate this, we need to find the initial and final kinetic energies of the system.
Initial kinetic energy:
KE_i = 0.5 * (0.300 kg + 0.200 kg) * (2.00 m/s)^2 = 0.5 * 0.500 kg * 4.00 m^2/s^2 = 4.00 J
Final kinetic energy:
KE_f = 0.5 * (0.300 kg) * (0.0 m/s)^2 + 0.5 * (0.200 kg) * (1.00 m/s)^2 = 0.5 * 0.200 kg * 1.00 m^2/s^2 = 0.10 J
Fraction of kinetic energy lost:
(KE_i - KE_f) / KE_i = (4.00 J - 0.10 J) / 4.00 J = 0.975 or 97.5%
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An object is thrown straight down with an initial speed of 4 m/s from a window which is 8 m above the ground. The time it takes the object to reach the ground is:
A. 0.80 s
B. 0.93 s
C. 1.3s
D. 1.7s
E. 2.0s
Answers
The time it takes an object to fall to the ground can be calculated using:
t = √(2 * d / g)
t = √(2 * 8 / 9.8) = √(16 / 9.8) = √(1.6326530612244898) = 1.27
So, the nearest answer to the value is C, which is 1.3s.
What is gravitaional force?Gravitational force of attraction between any two masses in the universe. It was first described by Newton in his law of universal gravitation, which states that every particle in the universe attracts every other particle with a force proportional to the product of their masses.
How can one calculate gravitational force?You can calculate gravitational force by:
F = G * (m1 * m2) / r^2, where F is the force of gravity, G is the gravitational constant (6.67 x 10^-11 Nm^2/kg^2), m1 and m2 are the masses of the two objects, and r is the distance between them.
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1- Find one number to represent each car’s speeding up (acceleration). Do not change units in this activity!
Each car drips oil once every second (think sugar packets).
The speedometer measures the speed of the car when the oil drips.
Larger numbers should be cars that speed up faster
2- Some cars have the same number of acceleration as another one. Which are they?
Answers
The cars that have the same number of acceleration as another one are C and E.
What are the cars with the same acceleration?
The cars with the same acceleration must have equal change in speed with direction.
The resultant velocity of the cars or the resultant speed of the cars in a given direction is calculated as follows;
change in speed of car A = 45 mph - 5 mph = 40 mph
change in speed of car B = 15 mph - 0 mph = 15 mph
change in speed of car C = 50 mph - 5 mph = 45 mph
change in speed of car D = 34 mph - 4 mph = 30 mph
change in speed of car E = 57 mph - 12 mph = 45 mph
Thus, the two cars that are changing their speed in a particular direction at equal rates are C and E.
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Specify all quantum numbers for the electrons in the 3p state in Zr. Do the same for the 4p state in Ba.
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The 3p subshell is filled for titanium atoms and Each electron has n = 3 and l = 1. The [tex]m{eq}_l {/eq}[/tex] values range from -1 to +1. The [tex]m{eq}_s {/eq}[/tex] values are either +1/2 or -1/2.
What is quantum numbers?The path and motion of an electron in an atom can be described using quantum numbers. The Schrodinger equation must hold true for the total quantum numbers of all the electrons in a particular atom.
Quantum numbers are the set of digits used to express the location and energy of an electron in an atom. There are four quantum numbers: the principal, azimuthal, magnetic, and spin quantum numbers.
Quantum numbers specify the values of a quantum system's conserved quantities. A group of numerical values that offer solutions to the Schrodinger wave equation for hydrogen atoms are known as electronic quantum numbers (the quantum numbers describing electrons).
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Give the SI base unit of each of these quantities. Enter the abbreviation rather than the name of the unit. a. Massb. lengthc. timed. temperature a. kgb. mc. sd. K
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Measurements in seconds, kilograms, meters, and kelvins are all SI units.
The fundamental unit of time has an acronym, what is it?SI time is represented by the sign for a second, or s. The unperturbed ground-state hyperfine transition frequency of the caesium-133 atom, which has a fixed numerical value of 9 192 631 770 when stated in the unit Hz, or s-1, is known as the caesium frequency, or vCs.The kilogram is the SI unit for mass (kg). A body's weight in a given reference frame is described in science and technology as the force that causes it to accelerate at a rate equal to the local acceleration of free fall in that frame.Measurements in seconds, kilograms, meters, and kelvins are all SI units.To learn more about fundamental unit refer to:
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Each of the following statements is related to conductors in electrostatic equilibrium. Choose the words that make each statement correct. (i) The net charge is always zero [(a) inside; (b) on] the surface of an isolated conductor, (ii) The electric field is always zero [(c) inside; (d) just outside] a perfect conductor, (iii) The charge density on the surface of an isolated, charged conductor is highest where the surface is [(e) sharpest; (f) smoothest].
Answers
(i) The net charge is always zero (a) inside a conductor in electrostatic equilibrium.
(ii) The electric field is always zero (c) inside a perfect conductor in electrostatic equilibrium.
(iii) The charge density on the surface of an isolated, charged conductor is highest where the surface is (e) sharpest.
Charged conductors create the state of electrostatic equilibrium, when the surplus charge has properly repositioned itself to lower the overall strength of the repelling forces.
Charges in a conductor react swiftly to attain a constant state known as electrostatic equilibrium when an excess of charge is applied to the conductor or the conductor is placed in a static electric field.
The following formula, ϕ = ∮ E ⋅ d A \phi = \oint {E \cdot dA} ϕ=∮E⋅dA, which is the integral of the dot product of the electric field (E) and the area of the conductor (A), states that electrostatic equilibrium will be reached in the presence of the magnetic field where the surface is perpendicular.
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A ball of mass 2kg is launched upward with a velocity of 5m/s. Calculate the height when the ball stops moving. (PLEASE HELP i dont understand this and this is due tmr pls do it step by step!!)
Answers
The ball of mass 2kg launched upward with a velocity of 5m/s will go underground 25/49 meters.
How are the equations of motion used to calculate the height?To calculate the height when the ball stops moving, we need to use the equations of motion for an object in free fall under the influence of gravity.
The first step is to determine the acceleration of the ball due to gravity, which is given by the equation: a = -g, where g is the acceleration due to gravity (approximately 9.8 m/s²on the surface of the Earth) and the negative sign indicates that the acceleration is downward. So, a = -9.8 m/s²
Next, we can use the equation: v² = u² + 2as , where v is the final velocity, u is the initial velocity, and s is the distance traveled. Since the final velocity of the ball is zero, we can substitute v = 0 and u = 5 m/s.
Now we can solve the equation for s: 0 = (5 m/s)² + 2(-9.8 m/s²)s
Once we solve for s, we get: s = -(5 m/s)² / (2 × -9.8 m/s²) = 25/49 m
Since the ball is moving upward, the negative sign in the equation means that the height is negative, so the height when the ball stops moving is -25/49 meters.
It's important to remember that the negative height means that the ball goes below the point where it was launched, it goes into the ground.
In summary, the ball of mass 2kg launched upward with a velocity of 5m/s will go underground 25/49 meters.
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two coherent sources of light of equal strength produce near parallel beams that intersect at a point p. compared to the intensity from just one of the sources, the intensity of the light due to both sources at point p will be select all that apply 1. four times that of a single source. 2. not enough information given. 3. twice that of a single source. 4. in a range from zero to four times that of a single source. 5. in a range from zero to two times that of a single source. I thought the intensity will be twice that of a single point due to the superposition principle. But, apparently I am wrong.
Answers
The intensity of the light due to both sources at point P will be four times that of a single source.
According to the superposition principle, the total intensity of light at a point is equal to the sum of the intensities due to each individual source. Since the two sources are of equal strength, the intensity of the combined light at point P will be twice that of a single source.
However, the light from each source will interfere with each other, resulting in constructive and destructive interference. As two beams are coherent, meaning they have the same frequency and phase, the light waves will add together constructively at certain points, increasing the intensity. So, at point P, the intensity of the light due to both sources will be four times that of a single source.
Hence option 1 is correct.
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The constellation whose stars are used as pointers to the north celestial pole in the northern hemisphere at this time in history is:______
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The constellation whose stars are used as pointers to the north celestial pole in the Northern Hemisphere at this time in history is Ursa Minor.
Polaris is known as the North Star, which is located in the constellation Ursa Minor. The star doesn't sit directly on the Earth’s north celestial pole, but it is very close. Using the Little Dipper as a reference, Polaris is easy to identify in the Northern Hemisphere. The stars, including the constellations, in the night sky appear to rotate around Polaris throughout the year.
Ursa Minor (or the Little Bear) is a constellation that is located in the far northern sky. This constellation was one of the 48 constellations that was listed by Ptolemy, and it remains one of the 88 modern constellations. Traditionally, Ursa Minor has been important for navigation because of Polaris being the north pole star.
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a platinum resistance thermometer has a resistance of 400 at 0 degrees Celsius and 1,200 at hundred degree celsius assuming that the resistance changes uniformly with temperature calculate the resistance of the thermometer when the temperature is 45 degrees Celsius. I need this ASAP! .Ps I'll mark brainliest
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Answer:
Explanation:
I will make a solution in a page and upload
For a wire extended elastically, the elastic energy per unit volume X is given by
X=Ce^2E
where C is a constant,
e is the strain of the wire,
and E is the Young modulus of the wire.
Show that C has no units.
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C's units must be dimensionless in order for the equation's units to be consistent, C doesn't have any.
What is elastic energy?When a force is applied to an object, it deforms, storing energy that is released when the force is removed. This energy is known as elastic energy. The inclination of the thing to assume its original shape results in this energy.
This is the case because C's units cancel out with the other variables' units in the equation.
The fractional change in the wire's length is represented by the strain, or e, which has no dimensions. The units of the Young modulus, E, are Newtons per square metre. The units of force and area cancel out when we square the strain and multiply it by the Young modulus, leaving only units of energy per unit volume.
For the units to cancel out appropriately in the equation X=Ce2E, the units of energy per unit volume are commonly written as joules per cubic metre (J/m3). Therefore, C, as a proportionality constant, must have no units.
Therefore, C has no units since C's units must be dimensionless for the equation to have consistent units.
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What is the magnitude and direction of the electric field intensity when the distance of a point charge from the center of a dipole is very large as compared to the length of the dipole?
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To calculate electric field created by a dipole on the axial line, magnitude and direction of the electric field intensity when the distance of a point charge from the center .
All the measurement of distances are to be taken from the centre(O).
Let the distance between O to +q and O to –q be ‘l’. So, total length between +q and –q will be ‘2l’.
Take a point ‘p’ on the axial line at the distance ‘r’ from the center as shown in figure.
Electric field on the axial line of dipole is not 0
magnitude =E = 14πε0 2Pr2
An electric field is the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them.
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a subway train starts from rest at a station and accelerates at a rate of 1.60m/s21.60m/s2 for 14.0 ss . it runs at constant speed for 70.0 ss and slows down at a rate of 3.50m/s23.50m/s2 until it stops at the next station. Find the total distance covered.
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The total distance covered by the subway train until is start from rest and again comes to rest is 435.36m.
The subway train starts from rest, and it accelerates to 1.6m/s² for 14s and after running for constant speed for about 70s and then it slows down at a rate of 3.5 m/s².
Now, while accelerating,
S = Ut + 1/2at²
U is initial speed, a is acceleration and t is time.
Putting values,
S = 1/2 x 1.6 x 14
S = 11.2m
Now,
V² - U² = 2aS
V is the constant speed,
V = √(2 x 1.6 x 11.2)
V = 5.98 m/s.
Distance covered with constant speed = 5.98 x 70
Distance S' covered with constant speed = 419.06 m.
Now, while the train slow down,
2a'S'' = V² - (0)²
a' = 3.5 m/s²
S'' = 5.10m
So, the total distance covered by the train will be (5.10 + 419.06 +11.2)m
The total distance covered by the train is 435.36 m.
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