The complete statement is no matter what the value of s, √s² is equal to the absolute value of s?
How to complete the blank?The statement is given as:
No matter what the value of s, √s² is equal to the ______ value of s?
The above statement can be split as follows:
No matter what the value of s, √s² is equal to the ______ value of s?This means that, irrespective of the value of s, what would be the value of the square root of the square of s.
Assume that s is negative (say s = -2), the value of the square root of the square of s would be
√s² = √(-2)²
Evaluate the square
√s² = √4
Evaluate the square root
√s² = 2
See that s = 2 is the positive equivalent or absolute value of s = -2
Now, assume that s is positive (say s = 4), the value of the square root of the square of s would be
√s² = √4²
Evaluate the square
√s² = √16
Evaluate the square root
√s² = 4
See that s = 4 is the positive equivalent or absolute value of s = 4
Hence, the complete statement is no matter what the value of s, √s² is equal to the absolute value of s?
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Complete question
No matter what the value of s, √s² is equal to the ______ value of s?
What is the independent variable in the following function?
The independent variable of f(c) = -3c + 9 is c
What are variables?Variables in an equation are the unknown parameters of the equation that change in values
There are two types of variables
Dependent variableIndependent variableHow to determine the independent variable?The equation of the function is given as
f(c) = -3c + 9
The dependent variable is the output of the function, while the independent variable is the input of the function
For the function, f(c) = -3c + 9
The input variable is c
Hence, the independent variable of f(c) = -3c + 9 is c
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A contractor is excavating a ramp into a trench for a construction project. How much dirt will the crew have to remove? To answer, find the volume of the triangular prism in the figure shown. Opening 4 x 6, ramp 8'deep
if y=mx+b, find m and use the formula for the previous question to find m when the coordinates are (4,7) and b=12
Answer:
m = -5/4
Step-by-step explanation:
In the slope-intercept form formula, y = mx + b, substitute 4 for x, 7 for y, and b for 12 to solve for m.
y = mx + b
7 = 4m + 12
-5 = 4m
m = -5/4
Which of the following linear equations corresponds to the table above?
O A. y = 4x - 3
O B. y=¹/4 x-3
OC. y=1/4x+3
OD. y = 4x + 3
The linear equations that corresponds to the table is y = 4x + 3
How to determine the linear equation?The missing table of values in the complete question is given as:
x y
0 3
3 15
7 31
10 43
Start by calculating the slope of the equation using
m = (y2 - y1)(x2 - x1)
Substitute the values on the table in the above equation
m = (15 - 3)/(3 - 0)
Evaluate the difference
m = 12/3
Evaluate the quotient
m = 4
The linear equation is then calculated as:
y = m(x - x1) + y1
This gives
y = 4(x - 0) + 3
Evaluate the expression
y = 4x + 3
Hence, the linear equations that corresponds to the table is y = 4x + 3
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URGENT!!! What happens to the graph of y=−x6−6x5+50x3+45x2−108x−108 as x heads toward ∞ and −∞?
A. as x→∞, y→−∞ as x→−∞, y→−∞
B. as x→∞, y→∞ as x→−∞, y→∞
C. as x→∞, y→∞ as x→−∞, y→−∞
D. as x→∞, y→−∞ as x→−∞, y→∞
Using limits, the correct option regarding the end behavior of the function is given by:
A. as x→∞, y→−∞ as x→−∞, y→−∞.
How to find the end behavior of a function f(x)?The end behavior is found calculating the limit of f(x) as x goes to infinity.
For this problem, the equation is given by:
[tex]f(x) = -x^6 - 6x^5 + 50x^3 + 45x^2 - 108x - 108[/tex]
Since x goes to infinity, we consider only the term with the highest exponent, hence the limits are given as follows:
[tex]\lim_{x \rightarrow -\infty} f(x) = \lim_{x \rightarrow -\infty} -x^6 - 6x^5 + 50x^3 + 45x^2 - 108x - 108 = \lim_{x \rightarrow -\infty} -x^6 = -(-\infty)^6 = -\infty[/tex]
[tex]\lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} -x^6 - 6x^5 + 50x^3 + 45x^2 - 108x - 108 = \lim_{x \rightarrow \infty} -x^6 = -(\infty)^6 = -\infty[/tex]
Hence the correct option is:
A. as x→∞, y→−∞ as x→−∞, y→−∞.
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Write an expression containing x2-terms, x-terms and constants. The
x2-terms should combine to −2x2 the x-terms should sum to 3x,
and the constants should sum to 3.
[tex]7x^{2} - 9x^{2} +8x-5x + 10-7[/tex] is the given expression
Like terms are terms whose variables (and their exponents such as the 2 in [tex]x^{2}[/tex]) are the same. Like terms can easily be added and substracted. Such questions just need like terms to be bought together and simplified
Infinite number of equations or expressions can be written for the given question. So writing one possibility for the given question,
= [tex]7x^{2} - 9x^{2} +8x-5x + 10-7[/tex]
which sums up to
= [tex]-2x^{2} +3x+3[/tex]
Thus [tex]7x^{2} - 9x^{2} +8x-5x + 10-7[/tex] is the given expression
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Find the number of integral solutions of x+y +z = 12, where −3 ≤ x ≤ 4, 2 ≤ y ≤ 11, and
z ≥ 3.
The total number of integral solutions of x + y + z = 12, where −3 ≤ x ≤ 4, 2 ≤ y ≤ 11, and z ≥ 3 is; 59 integer solutions
How to find the number of Integral Solutions?We are given the condition that;
−3 ≤ x ≤ 4
Thus, we will use x values of -3, -2, -1, 0, 1, 2, 3, 4
When;
x = -3 and y = 2, in x + y + z = 12, solving for z gives z = 13
x = -3 and y = 3, in x + y + z = 12, solving for z gives z = 12
x = -3 and y = 4, in x + y + z = 12, solving for z gives z =11
x = -3 and y = 5, in x + y + z = 12, solving for z gives z = 10
x = -3 and y = 6, in x + y + z = 12, solving for z gives z = 9
x = -3 and y = 7, in x + y + z = 12, solving for z gives z = 8
x = -3 and y = 8, in x + y + z = 12, solving for z gives z = 7
x = -3 and y = 9, in x + y + z = 12, solving for z gives z = 6
x = -3 and y = 10, in x + y + z = 12, solving for z gives z = 5
x = -3 and y = 11, in x + y + z = 12, solving for z gives z = 4
Thus, there are 10 solutions with x =-3
Repeating the above with x = -2, we will have 10 solutions
Similarly, with x = -1, we will have 9 more solutions
Similarly, with x = 0, we will have 8 more solutions.
Similarly, with x = 1, we will have 7 more solutions.
Similarly with x = 2, we will have 6 more solutions.
Similarly with x = 3, we will have 5 more solutions.
Similarly with x = 4, we will have 4 more solutions.
Thus,
Total number of solutions = 4 + 5 + 6 + 7 + 8 + 9 + 10 + 10
= 59 integer solutions
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Please help!!!!! Please explain too, I want to understand it!
In need of help for answers
The piecewise equation for the function shown in the diagram is [tex]f(x)=\left \{ {{{[\frac{9}{10}x+5.9\ \ \ -6 \leq x\leq -1 } \atop {[2\ \ \ \ \ \ \ \ \ \ \ -1 < x\leq 2}} \atop {[-\frac{5}{2}x+6\ \ \ 2 < x\leq 6 }} \right.[/tex]
What is an equation?An equation is an expression that shows the relationship between two numbers and variables.
An independent variable is a variable that does not depend on any other variable for its value whereas a dependent variable is a variable that depend on any other variable for its value.
From the diagram using the point (-6, 0.5) and (-1, 5):
y - 0.5 = [(5 - 0.5)/(-1 - (-6))](x - (-6))
y = (9/10)x + 5.9
Also, using the point (2, 1) and (4, -4):
y - 1 = [(-4 - 1)/(4 - 2)](x - 2)
y = -(5/2)x + 6
The piecewise equation for the function shown in the diagram is [tex]f(x)=\left \{ {{{[\frac{9}{10}x+5.9\ \ \ -6 \leq x\leq -1 } \atop {[2\ \ \ \ \ \ \ \ \ \ \ -1 < x\leq 2}} \atop {[-\frac{5}{2}x+6\ \ \ 2 < x\leq 6 }} \right.[/tex]
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number 7 please and don t care abt others lol
Answer:
The question does not make a lot of sense to me but I think this is how its supposed to be done
so there are 15 shirts
2 are sold at 3.90, 2 x 3.90 = 7.8
15-2= 13 t shirts
13 sold at 4.70, 13 x 4.70 = 61.1
amount of money made is = 7.8 + 61.1
= 68.9
PLEASE HELP ME PLEASE
WHICH EQUATION DOES THE GRAPH REPRESENT
Answer:
Step-by-step explanation:
B is the best answer
A friend of mine believes that the average GPA at KSU is equal to 3.0. In order to test whether he/she is right, I collect some information from the data. Specifically, I use 100 KSU students to form a sample and find that their sample average GPA is equal to 3.3. In addition, suppose that I also know the population standard deviation of GPA at KSU is 1.5. I decide to use 0.05 as the level of significance for my hypothesis testing. Could you help me with Q1-Q10 below? Q1: What should be my null hypothesis? What should be my alternative hypothesis? Q2: Is this a lower-tailed, upper-tailed or two-tailed case? Q3: Show me how to calculate my test statistic.
Q4: If I use the critical value approach, explain how to derive my critical value(s). Q5: If I use the p-value approach, explain how to derive my p-value. Q6: If I use the confidence interval approach, show me how to derive the confidence interval. Q7: How to make my decision, if I use the critical value approach? Q8: How to make my decision, if I use the p-value approach? Q9: How to make my decision, if I use the confidence interval approach? Q10: Are the decisions in Q7, Q8, and Q9 the same?
The solution of the questions is given as
a)
The alternative hypothesis is that mu is equal to 3.0. ( the average GPA at KSU is not equal to 3.0)
b)
This is a case with two separate arguments. (This is a two-tailed case)
c)
Test Statistic is given by:
z= 2.00
d)
Critical values of Z come from the table and equal [tex]\pm[/tex]1.96.
e)
, p-value = 0.0455
f)
CI= (3.006, 3.594)
g)
Conclusion: The evidence does not back up the assertion that KSU students have a cumulative grade point average of 3.0.
h)
Conclusion: The evidence does not back up the assertion that KSU students have a cumulative grade point average of 3.0.
i) Conclusion: The evidence does not lend credence to the assertion that KSU's typical grade point average is equivalent to 3.0.
j)
The choices you choose in Questions 7, 8, and 9 are identical.
What is the null hypothesis?a)
The null hypothesis states that mu equals 3.0. ( the average GPA at KSU is equal to 3.0) (Claim)
The alternative hypothesis is that mu is equal to 3.0. ( the average GPA at KSU is not equal to 3.0)
b)
This is a case with two separate arguments.
c)
Test Statistic is given by:
[tex]z=\frac{\barx-u^0}{σ/Vn}\\\\z=33 - 3.0/1.5/V100[/tex]
z= 2.00
d)
[tex]\alpha = 0.05[/tex]
Critical values of Z come from the table and equal [tex]\pm[/tex]1.96.
e)
Z Score = 2.00
reading from table, p-value = 0.0455
f)
Confidence Interval:
[tex]CI= \barx \pm \frac{ZX\sigma }{\sqrt((n)}[/tex]
[tex]CI =3.3 \pm 1.96 x 1.5 / \sqrt{100}[/tex]
CI= (3.006, 3.594)
g)
The disparity is noteworthy given that the computed value of Z = 2.00 is higher than the crucial value of z = 1.96. Cast doubt on the null hypothesis.
Conclusion: The evidence does not back up the assertion that KSU students have a cumulative grade point average of 3.0.
h)
The difference may be considered statistically significant since the p-value of 0.0455 is lower than the alpha threshold of 0.05. Cast doubt on the null hypothesis.
Conclusion: The evidence does not back up the assertion that KSU students have a cumulative grade point average of 3.0.
i)
The difference is statistically significant since the value of 3.0 is not included in the confidence range (3.006 - 3.594). Cast doubt on the null hypothesis.
Conclusion: The evidence does not lend credence to the assertion that KSU's typical grade point average is equivalent to 3.0.
j)
The choices you choose in Questions 7, 8, and 9 are identical.
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Defective electronics: A team of designers was given the task of reducing the defect rate in the manufacture of a certain printed ole circuit board. The team decided to reconfigure the cooling system. A total of 985 boards were produced the week before the reconfiguration was implemented, and 260 of these were defective. A total of 842 boards were produced the week after reconfiguration, and 194 of these were defective. Part: 0/2 Part 1 of 2 (a) Construct a 99% confidence interval for the decrease in the defective rate after the reconfiguration. Use the TI-84 Plus calculator and round the answers to three decimal places. A 99% confidence interval for the decrease in the defective rate after the reconfiguration is <21-22<0.
The 99% confidence interval for the decrease in the defective rate after the reconfiguration is (-0.018, 0.086).
How to find Confidence Intervals?Let the random variable & parameters be;
x1 : Number of successes from group 1
x2 : Number of successes from group 2
p1: Proportion of successes in group 1
p2: Proportion of successes in group 2
n1 : number of trial in group 1
n2: number of trial in group 2
We are given;
x1 = 260
n1 =985
x2 = 194
n2 = 842
Thus;
p1 = 260/985
p1 =0.2640
p2 = 194/842
p2 = 0.2304
Constructing a (1 - α)100% confidence interval for proportion from the formula;
(p₁ - p₂) - z√[((p₁(1 - p₁)/n₁) + p₂(1 - p₂)/n₂)]
plugging in z = 2.576 and the values of p₁, p₂, n₁ and n₂, we have the confidence interval as;
(-0.0184631, 0.0855743)
Therefore the 99% confidence interval for the decrease in the defective rate after the reconfiguration is (-0.018, 0.086).
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Select the correct answer. which of these organizations provides help to the friends and families of an alcoholic? a. national clearing house for alcohol and drug information b. american council on alcoholism c. alateen
Answer: C
Step-by-step explanation:
Solve x2 − 24x = −80 by completing the square. what is the solution set of the equation?
Answer:
Solve x2 − 24x = −80 by completing the square. what is the solution set of the equation?
The Answer Is X = 20 or x = 4
There is a balcony that forms part of a circle around a stage, and they need to put up a safety railing. How long of a railing do they need if the radius of the circle is 40 feet, and the arc takes up 45°? Use 3.14 for pi.
The length of the railing needed is 31.4 feet
Calculating the length of an arcFrom the question, we are to determine the length of railing needed
To determine the length of railing needed, we will determine the length of the arc formed by the balcony
Using the formula,
l = θ/360° × 2πr
Where l is the length of the arc
θ is the angle subtended by the arc
and r is the radius
From the given information,
θ = 45°
r = 40 feet
Putting the parameters into the equation, we get
l = 45°/360° × 2 × 3.14 × 40
l = 1/8 × 2 × 3.14 × 40
l = 2 × 3.14 × 5
l = 31.4 feet
Hence, the length of the railing needed is 31.4 feet
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A variety of two types of snack packs are delivered to a store. The box plots compare the number of calories in each snack pack of crackers to the number of calories in each snack pack of trail mix.
A number line goes from 65 to 115. Crackers's whiskers range from 70 to 100, and the box ranges from 75 to 85. A line divides the box at 80. Cookies's whiskers range from 70 to 115, and the box ranges from 90 to 105. A line divides the box at 100.
Which statement is true about the box plots?
The interquartile range of the trail mix data is greater than the range of the cracker data.
The value 70 is an outlier in the trail mix data.
The upper quartile of the trail mix data is equal to the maximum value of the cracker data.
The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.
The statement that is true about the box plots is: D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.
What is a Measure of Variation?For a data distribution that is displayed by a box plot, the measure of variation that can be used to describe the data distribution is the interquartile range.
What is the Interquartile Range of a Data Distribution?Interquartile range, which is a measure of variation can be determined from a box plot by finding the value of the third quartile and first quartile, the finding their difference. The difference is the interquartile range.
Interquartile range = third quartile - first quartile.
Interquartile range for crackers = 85 - 75
Interquartile range for crackers = 10
Interquartile range for trail mix = 105 - 90
Interquartile range for trail mix = 15.
The bigger the value of the interquartile range, the more variation there is that exist in a data distribution.
Interquartile range for trial mix is the largest, therefore, the statement that is true about the box plots is: D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.
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In your own words, define the unit rate in an equation of proportional relationship y= kx.
Answer:
hdchyf
Step-by-step explanation:
fhyrb ufgfyg hchybgvtct ugh
I need help on how to solve for Z
Answer:
[tex]z=\frac{t^{2}(m-3) }{4}[/tex] or [tex]z=\frac{1}{4}t^{2} (m-3)[/tex]
Step-by-step explanation:
[tex]t=\sqrt{\frac{4z}{m-3} }[/tex]
[tex]t^{2} =\frac{4z}{m-3}[/tex]
[tex]4z=t^{2} (m-3)[/tex]
[tex]z=\frac{t^{2}(m-3) }{4}[/tex]
Hope this helps
‼️‼️‼️‼️HELP‼️‼️‼️‼️‼️‼️‼️
Michael took a drive down to the beach and drove at a pace of 45mph on the way there. The trip took him 3 hours. He drives the exact same route on the way back, but takes it slow so he can enjoy the sunset. If Henry's return trip took him 4 hours, how fast was he driving on his return?
Michael took the return trip at a velocity 33.75 miles per hour.
How fast did Michael drive in his return trip?
Let suppose that Michael drove in straight line road and at constant velocity. Therefore, the speed of the vehicle (v), in miles per hour, can be defined as distance traveled by the vehicle (d), in miles, divided by travel time (t), in hours.
First trip
45 = s / 3 (1)
Second trip
v = s / 4 (2)
By (1) and (2):
45 · 3 = 4 · v
v = 33.75 mi / h
Michael took the return trip at a velocity 33.75 miles per hour.
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How many ways can a 2 person subcommittee be selected from a comittee of 6 people?
Answer: 15 ways
Step-by-step explanation: 5+4+3+2 + 1 = 15
Answer:
15.
Step-by-step explanation:
That would be the number of combinations of 2 from 6.
6C2
= 6! /4!2!
= 6*5/2*1
= 15.
I really don't know what to do for this question! :( help?
The amount of money she should deposit is 6131.14 dollars.
How to find the compound interest ?The amount she should deposit can be found as follows:
[tex]p = \frac{A}{(1+\frac{r}{n} )^{nt} }[/tex]
where
A = amount to depositr = raten = number of timest = timep = principalTherefore,
p = [tex]\frac{20000}{(1+\frac{0.12}{4}{} )^{40} }[/tex]
[tex]p=\frac{20000}{(1+0.03)^{40} }[/tex]
[tex]p = \frac{20000}{1.03^{40} }[/tex]
[tex]p=\frac{20000}{3.262037792}[/tex]
Hence,
p = $6,131.14
Therefore, she should deposit 6131.14 dollars.
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What is [tex]\frac{3}{4}[/tex] - [tex]\frac{2}{b}[/tex]
The answer is [tex]\boxed {\frac{3b - 8}{4b}}[/tex].
3/4 - 2/b3(b) - 2(4) / 4(b)3b - 8 / 4bWhat are the solutions to this quadratic equation x2+6x-5=0
Answer:
See Below.
Explanation:
Quadratic Form:
[tex]a {x}^{2} + bx + c[/tex]
Quadratic Formula:
[tex]x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac} }{2a} [/tex]
Based on the information given from the question, we can deduce:
a = 1
b = 6
c = -5
Now we can substitute all these values into the formula to find x.
[tex]x = \frac{ - 6 + - \sqrt{ {6}^{2} - 4(1)( - 5)} }{2(1)} \\ = - 3 + \sqrt{14} \: or \: - 3 - \sqrt{14} [/tex]
Use the discrete probability distribution to find the probability that x exceeds 5. (note that it is not required to find the missing probability. )
The discrete probability distribution that finds the probability that x exceeds 5 is 0.38
Opportunity provides records approximately the likelihood that something will manifest. Meteorologists, for instance, use weather patterns to are expecting the chance of rain. In epidemiology, the probability idea is used to recognize the connection between exposures and the risk of fitness consequences.
Finding the possibility of a simple event happening is fairly straightforward: upload the changes collectively. For example, if you have a 10% chance of triumphing $10 and a 25% threat of triumphing $20 then your normal odds of prevailing something is 10% + 25% = 35%.
If there is no ambiguity within the occurrence of an occasion, then the chance of such an occasion is equal to 1. In other phrases, the chance of a sure occasion is 1. If an occasion has no probability of taking place, then its chance is zero.
We want to find the probability for x exceeding 5 means for x>5
Consider,
P(X>5)=P(x=6)+P(X=8)
=0.18+0.2
=0.38
Hence, the probability is 0.38
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Write 304.9% as a decimal.
Answer:
3.049
Step-by-step explanation:
Move the decimal place in 304.9% to the left two places in order to convert from a percentage to a decimal. 3.049 is the answer.
Brainliest, please :) Hope this helps!
the selling price of a mobile after discount is 10000.if the discount is 10% find the mp
Answer:
Rs.11,111.11 (2 d.p.)
Step-by-step explanation:
The original price of the mobile is 100% of the price.
Therefore, the price of the mobile after a discount of 10% is 90% of the original price.
Let x be the original price.
If the price of the mobile after the discount is Rs.10000 then:
⇒ 90% of x = Rs.10000
⇒ 0.9x = 10000
⇒ x = 10000 ÷ 0.9
⇒ x = 11111.11 (2 d.p.)
M.P. =Rs 11111.1111
Answer:
Solution Given:
Selling price (S.P.) = Rs 10,000.
Discount =10%
Marked Price (M.P.)=?
we have
M.P. = S.P. + discount% of M.P.
keeping M.P. on same side
M.P. - discount% of M.P=S.P.
substituting value
M.P. - 10% of M.P.= Rs 10,000
taking common M.P.
M.P.(1-10%)=Rs. 10,000
we know that %=1/100
M.P.(1-10/100)=Rs 10,000
(9/10)M.P.= Rs 10,000
M.P.= Rs 10,000*10/9
M.P.=Rs11111.1111
For 17-20, Find the value of each variable.
The unknown angles are as follows;
x = 180 degrees
r = 90 degrees.
How to find the angles of each value in a circle?The angle subtended by an arc of a circle at its centre is twice the angle it subtends anywhere on the circle's circumference.
Therefore,
x = 2(90)
x = 180
Therefore, the sum of angle in a circle is 360 degrees.
Hence, the 2 angles of the arc are the same.
Therefore,
360 - 180 = 2r
2r = 180
divide both sides by 2
2r / 2 = 180 / 2
r = 90 degrees.
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Solve the equation in the image (yr 8 maths, 50pts)
Answer: x = 4
Step-by-step explanation:
Given equation
4x - 20 = -x
Add x on both sides
4x - 20 + x = -x + x
5x - 20 = 0
Add 20 on both sides
5x - 20 + 20 = 0 + 20
5x = 20
Divide 5 on both sides
5x / 5 = 20 / 5
[tex]\Large\boxed{x=4}[/tex]
Hope this helps!! :)
Please let me know if you have any questions
The price of a jacket is $500 and the price of a pair of jeans is $250.
(a) The price if the jacket is ____% if the pair of jeans.
(b) The price of the pair of jeans is ___% or the price of the jacket.
Answer:(a) 50% (b)5%
Step-by-step explanation:
For a, it's not really difficult because the price of a jacket is 1/2 more than jeans. So it's 50%.
For b, it's similar to no. (a) because the price of the jean is 1/2 less than a jacket. So u need to divide 250 by 500 and u will get 0.5 so if u want to put in % u need to multiply with 10, so u will get 5%.
