Please Help!!! Cannot figure out how to answer this.

The value of the angle ∠I = 13

An isosceles triangle in geometry is one with at least two sides that are of equal length. Both having exactly two sides of equal length and having at least two sides of equal length are acceptable specifications, with the latter version containing the equilateral triangle as an exception. The faces of bipyramids, the golden triangle, the isosceles right triangle, and some Catalan solids are all examples of isosceles triangles.

in this figure, it is an isosceles triangle as two sides of the triangle are equal.

given in the ΔGHI is an isosceles triangle.

So the other two angles will be 13

Hence The value of the angle ∠I =13°

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Bashir earns $235.6 in 15.5 hours.

The slope of the line is the ratio of the rise to the run, or rise divided by the run. It describes the steepness of line in the coordinate plane.

The slope intercept form of a line is y=mx+b, where m is slope and b is the y intercept.

The slope of line passing through two points (x₁, y₁) and (x₂, y₂) is

m=y₂-y₁/x₂-x₁

Slope= 501.60-349.60/33-23

=152/10

=15.2

Now let us find the y intercept

228=15.2(15)+b

228=228+b

b=0

Now let us find how much he earns in 15.5 hours.

y=15.2(15.5)

y=235.6

Hence, Bashir earns $235.6 in 15.5 hours.

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As an asset account, the furniture account is debited as its balance increases.

Cash and bank amount are assets accounts as well, and when furniture is purchased percentage , they are credited for the amount that has been deducted from them.

Record in journal

A/C for furniture is $50,000.

A/C Cash: DR 2,000,000.

To Capital, 2.5 million

(The beginning of a business with money and furniture)

Note: Since cash and furniture are investments in the business, they are capital, and when capital increases, it is credited. Furniture is our asset, and if it increases, it will be debited. Cash is also our asset, and as it is arriving in the firm, it is increasing, therefore it will be debited.

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The complete question is " Explain Journal entry for started business with cash Rs 200000 and furniture Rs 50000. "

Answer:

5 units^2

Step-by-step explanation:

Answer:

[tex] \frac{1}{24} [/tex]

Step-by-step explanation:

When you're dividing a fraction, you multiply the denominator

For example, taking this question

[tex] \frac{1}{4} \div 6[/tex]

The dominator is 4

You're dividing by 6

So multiply the denominator and what you're dividing by

[tex]4 \times 6 = 24[/tex]

Now that you have that, 24 will be the new denominator

[tex] \frac{1}{24} [/tex]

Answer:

15.94

Step-by-step explanation:

(2+h)² + h² =24²

4+4h+h²+ h² =24²

2+2h+h²= 576/2

h²+2h-286=0

solve h=15.94

On solving the provided question we can say that probability, P' = 1 - P( P' < 0.80 ) = 1 - P( P'- 0.80/0.06235 < 0.80-0.80/0.06235 )  => P' = 0.5

Probability theory, a subfield of mathematics, gauges the likelihood of an occurrence or a claim being true. An event's probability is a number between 0 and 1, where approximately 0 indicates how unlikely the event is to occur and 1 indicates certainty. A probability is a numerical representation of the likelihood or likelihood that a particular event will occur. Alternative ways to express probabilities are as percentages from 0% to 100% or from 0 to 1. the percentage of occurrences in a complete set of equally likely possibilities that result in a certain occurrence compared to the total number of outcomes.

the proportion of days when particular mutual fund out performed the S&P 500 index = 29/40 = 0.0.725 = 0.8

Let P' denotes the sample proportion for random sample size of n = 40

now, probability, P' = 1 - P( P' < 0.80 ) = 1 - P( P'- 0.80/0.06235 < 0.80-0.80/0.06235 )

P' = 1 - P(Z)

P' = 1 - 0.5

P' = 0.5

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The probability that a randomly selected password has no digits is 10.24%.

Probability can be defined as the ratio of the number of favourable outcomes to the total number of outcomes of an event.

Given that, a seven-character database password is formed from 10 digits and 26 upper-case letters.

Number of characters in passwords: 7

The possible number of ways to formed the first value of passwords is sum of 26 (upper letters) and 10 (0 to 9 numbers).

The required number of possible passwords is 36⁷

= 78364164096

Favorable out comes is 26⁷

= 8031810176

Now, probability of an event = 8031810176/78364164096

= 0.1024

= 10.24%

Therefore, the probability that a randomly selected password has no digits is 10.24%.

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Answer:

84

Step-by-step explanation:

Number of skiers = Number of athletes * Fraction of skiers
= 240 * 7/20
= 84 skiers

Answer:

84

Step-by-step explanation:

240/20=12

12*7=84

Answer:

D. x < 1

is correct answer

a) for initial value 4 function oscillate between 4 and -2

b) for a initial value of 2 function oscillate between 2 and 0

c) for a initial value of 1 function value is constant = 1

A function is a relationship between a set of inputs that each have one output. A function, in simple terms, is a relationship between inputs, with each input corresponding to exactly one output. Each function has a domain as well as a co-domain or range. The general notation for a function is f(x), where x is the input. A function is generally represented as y = f. (x).

In math, there are various types of functions. Among the most important types are:

f(x) = 1/2.x + 1

f(4) = 1/2*4+1=3

f(4) = 1/2*3+1=2.5

f(4) = 1/2*2.5+1=2.25

f(4) = 1/2*2.25 + 1 = 2.125

f(4) = 1/2*2.125+1 = 2.0625

f(4) = 1/2*2.0625 + 1 = 2.0123

As the iteration increases function value converges to 2

You can write a simple MATLAB program to check it

matlab code:

clc;

clear all;

close all;

syms x;

f=-x+2;

y(1)=4;

g(1)=2;

h(1)=1;

for n=1:20

   y(n+1)=subs(f,x,y(n));

   g(n+1)=subs(f,x,g(n));

   h(n+1)=subs(f,x,h(n));

end

t=[y',g',h'];

output :

t =

    4     2     1

   -2     0     1

    4     2     1

   -2     0     1

    4     2     1

   -2     0     1

    4     2     1

   -2     0     1

    4     2     1

   -2     0     1

    4     2     1

   -2     0     1

    4     2     1

   -2     0     1

    4     2     1

   -2     0     1

    4     2     1

   -2     0     1

    4     2     1

   -2     0     1

    4     2     1

a) for initial value 4 function oscillate between 4 and -2

b) for a initial value of 2 function oscillate between 2 and 0

c) for a initial value of 1 function value is constant = 1

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The correct solution for the area of this triangle is 20 inches².

The area of a triangle is a measure of the amount of two-dimensional space enclosed by its three sides. It is represented by the symbol A and is calculated by multiplying the base of the triangle by its height and dividing the result by 2.

A = (1/2)b×h

In other words, the height of the triangle is a line segment perpendicular to the base that divides the triangle into two smaller triangles of equal area. The area of a triangle is important in many real-world applications, such as in construction and architecture, where it is used to determine the amount of material needed for a project, and in geometry, where it is used to solve problems related to triangles.

No, Kevin's solution is not correct. The formula for the area of a triangle is

A = (b×h)/2, not A = b×h.

To find the area of this triangle, you would use the formula:

A = (8 × 5)/2 = 20 inches²

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Triangle congruence is proved by a sequence of reflections and translations.

A translation in math moves a shape left or right and/or up or down. The translated shapes look exactly the same size as the original shape, and hence the shapes are congruent to each other. They just have been shifted in one or more directions.

Given that, ∆ABC has vertices at A(11, 6), B(5, 6), and C(5, 17).

By using distance formula, distance =√(x₂-x₁)²+(y₂-y₁)²

AB = 6 units   BC = 11 units AC = 12.53 units

∆XYZ  X(-10, 5), Y(-12, -2), and Z(-4, 15)

XY = 7.14 units   YZ = 18.79 units XZ = 11.66 units

∆MNO  M(-9, -4), N(-3, -4), and O(-3, -15).

MN = 6 units   NO = 11 units MO = 12.53 units

∆JKL  J(17, -2), K(12, -2), and L(12, 7).

JK = 5 units   KL = 9 units JL = 10.30 units

∆PQR  P(12, 3), Q(12, -2), and R(3, -2)

PQ = 5 units   QR = 9 units PR = 10.30 units

So, we have the ∆ABC and the ∆MNO  

With all three sides equal are congruent  

We have the ∆JKL  and the ∆PQR

with all three sides equal are congruent  

Two plane figures are congruent if and only if one can be obtained from the other by a sequence of rigid motions (that is, by a sequence of reflections, translations, and/or rotations).

1) If ∆MNO by a sequence of reflections and translation, it can be obtained ∆ABC, then ∆MNO ≅ ∆ABC  

a) Reflection (On x-axis)

The coordinate notation for the Reflection is (x,y)→(x,-y)

∆MNO  M(-9, -4), N(-3, -4), and O(-3, -15).

M(-9, -4)→ M1(-9,4)

N(-3, -4)→ N1(-3,4)

O(-3,-15)→ O1(-3,15)

B) Reflection (y-axis)

The coordinate notation for the Reflection is (x,y)→(-x,y)

In ∆M'N'O', M'(-9, 4), N'(-3, 4), and O'(-3, 15).

M'(-9, -4)→M"(9,4)

N'(-3, -4)→N"(3,4)

O'(-3,-15)→O"(3,15)

C) Translation

The coordinate notation for the Translation is (x,y)→(x+2,y+2)

∆M"N"O", M"(9,4), N"(3,4), and O"(3, 15).

M"(9, 4) → A(11,6)

N"(3,4)→B(5,6)

O"(3,15)→C(5,17)

So, we have ∆ABC,  A(11, 6), B(5, 6) and C(5, 17)

From ∆MNO to ∆M'N'O' reflection, from ∆M'N'O' to ∆M"N"O" reflection, and from ∆M"N"O" to ∆ABC its translation.

2)If ∆JKL, by a sequence of rotation and translation

We obtained ∆PQR

So, ∆JKL ≅ ∆PQR  

D) Rotation 90 degree anticlockwise

The coordinate notation for the Rotation is (x,y)→(-y, x)

In ∆JKL, J(17, -2), K(12, -2), and L(12, 7).

J(17, -2)→J'(2,17)

K(12, -2)→K'(2,12)

L(12,7)→L'(-7,12)

E) Translation:

The coordinate notation for the translation is (x, y)→ (x+10, y-14)

Then, ∆J'K'L' has vertices J'(2, 17), K'(2, 12), and L'(-7, 12).

J'(2, 17)→P(12,3)

K'(2, 12)→Q(12,-2)

L'(-7, 12)→R(3,-2)

So, ∆PQR has P(12, 3), Q(12, -2) and R(3, -2)

From ∆JKL to ∆J'K'L' its rotation and from ∆J'K'L' to ∆PQR its translation.

Therefore, ∆JKL ≅ ∆PQR  

Hence, triangle congruence is proved by a sequence of reflections and translations.

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The value of angle ∠DEC  = 60 degree.

In the given the figure , m∠BAC = 64° and m∠CBA = 56°.

A triangle is a polygon with three sides and three vertices and three angles.

WE are given that AB || CD

Let BC be the transversal , then ∠CBA = ∠DCB (by alternate opposite angles)

∠DCB = 56 degree

As we know the sum of opposite interior angle sis equal to exterior angle therefore, ∠ ECB = 120 degree

∠DCE = 120-56 = 64 degree

BC || DE

∠EDC = ∠DCB = 56 degree (By alternate opposite angles)

The Sum of all the interior angles of a triangle is equal to 180 degree.

56 +64+∠DEC = 180

∠DEC  = 60 degree.

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Answer:

10 4/6 = 10 2/3

Step-by-step explanation:

dude this is easy and not for college but thanks anyway

Answer:

The ratio for 63 inches to 4 yards is 1:16. To calculate this, divide 63 inches by 4 yards, which is equal to 48 inches per yard. Therefore, the ratio for 63 inches to 4 yards is 1:16.

(a). The smallest quantity at which marginal cost is equal to 15 dollars per item is 2.76. (b). The positive value of q at which average variable cost is equal to marginal cost is [tex]\frac{15}{2}[/tex]. (c). The longest interval on which marginal revenue exceeds marginal cost is (1.8377, 8.1622). (d). The profit is increasing at 8.1622 at p(q) is maximum. (e). The maximum value of profit is 78.2455 dollars.

The total revenue: TR(q) = 30q

The total cost: Tc(q) = [tex]q^3-15 q^2+75 q+10$[/tex]

The change in cost is referred to as the change in the cost of production when there is a need for change in the volume of production.

(a).  Marginal cost MC[tex]=\frac{\partial}{\partial q}(T C)$[/tex]

[tex]$$=3q^2-30 q+75 \text {. }$$[/tex]

According to question.

[tex]$$\begin{aligned}& 3 q^2-30 q+75=15 \\& 3 q^2-30 q+60=0 \\& q^2-10 q+20=0 \\& q= \frac{10 \pm \sqrt{100-80}}{2} \\&= \frac{10 \pm 2 \sqrt{5}}{2}=5 \pm \sqrt{5}\end{aligned}[/tex]

[tex]$$$\therefore \quad q=5+\sqrt{5} \quad$ and $q=5-\sqrt{5}$[/tex]

we have to find smallest quantity.

[tex]$$\therefore \quad q=5-\sqrt{5}=2.76 \text {. }$$[/tex]

b)

[tex]$$\begin{aligned}& F C=T C(0)=10 \\& V C(q)=T C(q)-F C \\& =q^3-15 q^2+75 q . \\& \text { AVC(q) }=\frac{V C(q)}{q}=q^2-15 q+75 .\end{aligned}$$[/tex]

When AVC(q)=MC(q)

[tex]$$\begin{array}{ll}\Rightarrow & q^2-15 q+7 ;=3 q^2-30 q+75 \\\Rightarrow & 2 q^2-15 q=0 .\ \Rightarrow q(2 q-15)=0 . \\\Rightarrow & q=0, \frac{15}{2} \quad \Rightarrow \quad q=\frac{15}{2}\end{array}$$[/tex]

Therefore, the positive value of q at which average variable cost is equal to marginal cost is [tex]\frac{15}{2}[/tex].

(c).

[tex]& M R(q)=\frac{d}{d q}(T R)=30 . \\[/tex]

[tex]& M C(q)=3 q^2-30 q+75 . \\[/tex]

Let MR(a)>MC(q)

[tex]& \Rightarrow \quad 30 > 3 q^2-30 q+75 \text {. } \\[/tex]

[tex]& \Rightarrow \quad 3 q^2-3 p q+45 < 0 \\[/tex]

[tex]& \Rightarrow \quad q^2-10 q+15 < 0 \text {. } \\[/tex]

[tex]& \because \quad q=\frac{10 \pm \sqrt{100-60}}{2} \Rightarrow q=\frac{10 \pm 2 \sqrt{10}}{2} \\[/tex]

[tex]& q=(5 \pm \sqrt{10}) \\[/tex]

[tex]& \Rightarrow \quad(q-5+\sqrt{10})(q-5-\sqrt{10}) < 0 . \\[/tex]

[tex]& \Rightarrow \(q-5+\sqrt{10}) < 0 \quad \& \quad(q-5-\sqrt{10}) > 0 \text {. } \\[/tex]

[tex]& \text { or } \quad(q-5+\sqrt{10}) > 0 \quad \& \quad(q-5-\sqrt{10}) < 0 \text {. } \\[/tex]

[tex]& \therefore \quad \text { other } q < 5-\sqrt{10}=1.8377 ., q > 5+\sqrt{10}=8.1622 \text {. } \\[/tex]

[tex]& \Rightarrow \quad q < 1.8377 \& q > 0.1622 \text {. } \\[/tex]

[tex]& \text { or } q > 5-\sqrt{10} \quad \& \quad q < 5+\sqrt{10} \text {. } \\[/tex]

[tex]& \Rightarrow q > 1.8377 \quad < q < 8.1622 \text {. } \\[/tex]

The Interval is (1.8377, 8.1622).

(d).  P(q) =TR(q)-TC(q)

[tex]& =30 q-\left(q^3-15 q^2+75 q+10\right) \\& =-q^3+15 q^2-75 q-10+30 q \\& =-q^3+15 q^2-45 q-10 .[/tex]

on (1.8377,8.1622). we have to find a point such that p"(q)=0 and p"(q)<0.

[tex]& p^{\prime}(q)=-3 q^2+30 q-45 \\[/tex]

[tex]& \Rightarrow \quad-3\left(q^2-10 q+15\right)=0 \\[/tex]

[tex]& \Rightarrow \quad q^2-10 q+15=0 . \\[/tex]

[tex]& \quad q=1.8377 \text { and } \quad q=8.1622 . \\[/tex]

[tex]& \Rightarrow \quad p^{\prime \prime}(q)=-6 q+30 . \\[/tex]

[tex]& p^{\prime \prime}(1.8377)=-6(1.8377)+30 \\[/tex]

[tex]&=18.9738 \\[/tex]

[tex]& p^{\prime \prime}(8.1622)=-6(8.1622)+30 . &=-18.9732 < 0 .[/tex]

at 8.1622, p(q) is maximum.

(e).

Max profit-P(8.1622)

=78.2455 dollars

Therefore, the maximum value of profit is 78.2455 dollars.

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The fraction which is closest to 1/2 is, 3/8. So option B is correct

Fraction is a mathematical term, which represents the portion or sub-parts of the whole thing. Basically, It has two parts: numerator and denominator.

Numerator is a number which lies on the top side, it indicates the number of equal parts taken and denominator is on the bottom side, it indicates the equal parts of the whole number.

Given that,

A fraction number 1/2

In decimal form = 0.5

Closest fraction number = ?

Most closest number is that number from which we subtract the given number and the magnitude of result we get is very less,

Lets take, A fraction 1/6

In decimal form it can written as,  0.167

Difference 1 =  0.5 - 0.167

                  =   0.333

Similarly, For numbers 3/8, 3/4, -1/2

Difference 2 =  0.5 - 0.375  = 0.125

Difference 3 =  0.5 - 0.75  = -0.25

Difference 4 =  0.5 - (-0.5)  =  1.0

It can be seen that,

Magnitude of difference in case of 3/8 is very less

Hence, the closest number is 3/8

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On solving the provided question, we can say that an explicit equation for the geometric sequence t(n) = [tex]t^2+ 6t - 8[/tex] and a recursive equation for the geometric sequence; t(1) = -1

A mathematical equation is a formula that joins two statements and uses the equal symbol (=) to indicate equality. A mathematical statement that establishes the equality of two mathematical expressions is known as an equation in algebra. For instance, in the equation 3x + 5 = 14, the equal sign places the variables 3x + 5 and 14 apart. The relationship between the two sentences on either side of a letter is described by a mathematical formula. Often, there is only one variable, which also serves as the symbol. for instance, 2x – 4 = 2.

an explicit equation for the geometric sequence.

t(n) = [tex]t^2+ 6t - 8[/tex]

a recursive equation for the geometric sequence.

t(1) = -1

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Answer:

1/2

Step-by-step explanation:

On the clock from 3 to 9, the hour hand turns clockwise 1/2 of the revolution. On the clock from 4 to 7, the hour hand turns clockwise 1/4 of the revolution

Answer:

40 dollars per hour

Let the width be [tex]w[/tex] inches and the length be [tex]w+15[/tex] inches.

So, the dimensions of the box are [tex]w-6[/tex], [tex]w+9[/tex], and [tex]3[/tex] inches.

[tex]3(w-6)(w+9)=1350 \\ \\ (w-6)(w+9)=450 \\ \\ w^2+3w-54=450 \\ \\ w^2+3w-504=0 \\ \\ (w+24)(w-21)=0 \\ \\ w=-24,21[/tex]

Rejecting the negative case, [tex]w=21[/tex].

So, the dimensions are 21 by 36 inches.

Answer:

Independent variable: The variable that is changed or manipulated in an experiment to observe its effect on the dependent variable. Example: The number of hours of studying (Independent variable) and the test score (Dependent variable)

Dependent variable: The variable that is being measured or observed in an experiment. Its value is dependent on the independent variable. Example: The temperature of water (Independent variable) and the volume of the water (Dependent variable)

Answer:

y=5x

Here y is dependent variable because it's depend on x but x is not depend on any other variable. So, it's independent variable.

The number of boxes that would fit into the trunk is 70.

The box is known as a cuboid. A cuboid is a three-dimensional shape that has six faces, 12 sides and 6 vertices.

In order to determine the number of boxes that would fit into the trunk, divide the volume of the trunk by the volume of one box.

Volume is the product of the length, width and height of an object. It measures how much space is in object.

Number of boxes that can fit into the trunk = volume of the trunk / volume of one of the boxes

40,480 /  576 = 70.28 boxes or 70 boxes

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The value of x in the equation x^x = 4^(x + 16) is 16

From the question, we have the following parameters that can be used in our computation:

x^x = 4^(x + 16)

Take the logarithm of both sides

So, we have

xlog(x) = (x + 16)log(4)

At this point, we make use of a graphing calculator

From the calculator, we have

x = 16

Hence, the solution is x = 16

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Answer:

The equation of a circle can be represented in the form (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center of the circle and r is the radius.

A diameter of a circle is a straight line passing through the center of the circle and has endpoints on the circle.

Given that the equation of the diameter of a circle is x+y-14=0 and 2x-y-4=0, we can find the center of the circle by solving for the intersection of these two lines.

We can find the intersection point of these lines by solving the system of equations using the substitution method:

x+y-14=0 and 2x-y-4=0

x = 14/3, y = 10/3

So the center of the circle is (14/3, 10/3)

Since we know that the point (3,4) lies on the circle, we can use the distance formula to find the radius of the circle.

r = sqrt((x-h)^2 + (y-k)^2)

r = sqrt((3-(14/3))^2 + (4-(10/3))^2) = sqrt(5)

Therefore, the equation of the circle is (x-14/3)^2 + (y-10/3)^2 = 5^2

or (x-14/3)^2 + (y-10/3)^2 = 25

So, the equation of the circle passing through point (3,4) and having equation of its diameter x+y-14=0 and 2x-y-4=0 is (x-14/3)^2 + (y-10/3)^2 = 25

Answer: 31

Step-by-step explanation:

You need to find the perimeter of something, you just add the numbers of the sides.

6 + 9 = 15

15 + 5 = 20

20 + 3 = 23

23 + 5 = 28

28 + 3 = 31

Perimeter = 31 in.

A perimeter of any shape is just the total length of all its sides. In other words, is the distance around the edge of the shape.

Perimeter = 5 in + 3 in + 5 in + 9 in + 6 in + 3 in = 31 in.

Perimeter = 31 in.

The area of the shaded region is πr² - (2 × 13.5π).

Given is a shaded region inside a circle.

The area of each section is -

A{S} = 13.5π

We can write the area of the shaded region as -

πr² - (2 × 13.5π)

Therefore, the area of the shaded region is πr² - (2 × 13.5π).

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The surface area of the composite bin can be found using the expression  6·5 + 4·5 + 3·5 + 5·5 + 2·[3·4 + (1/2)·(3·4)]

Please find attached the drawing of the net of the composite bin, created with MS Word

The surface area of a composite figure can be found finding the sum of the individual exposed surface area of the composite figure.

Please find attached the possible drawing of the diagram in the question, created with MS Word

The possible complete expression in the question, obtained from a similar, online question, is presented as follows;

6·5 + 4·5 + 3·5 + 5·5 + 2·[3·4 + (1/2)·(3·4)]

The surface area of the figure consists as follows;

Two trapezoidal faces (in front and on the rear

Four rectangular faces, orthogonal to the trapezoidal faces

Please find attached the net of the composite bin created with MS Word

The area of the trapezoidal faces = (3 + 6)×4/2 = ((1/2)·(3·4) + ((1/2)·(6·4))

((1/2)·(3·4) + ((1/2)·(6·4)) = ((1/2)·(3·4) + (3·4)

((1/2)·(3·4) + ((3·4)) = 3·4 + (1/2)·(3·4)

Therefore, the area of the two trapezoidal faces = 2 × (3·4 + (1/2)·(3·4))

The area of the four rectangular faces are;

Face              [tex]{}[/tex]                  Area

Orthogonal rear face = 6 × 5

Orthogonal front face = 3 × 5

Face at the bottom of the figure = 4 × 5

The slant face at the top = 5 × 5

The area is therefore;

The surface area of the composite bin, A, is therefore;

Learn more about the surface area of composite figures here: https://brainly.com/question/28167393

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