PLEASE HELP ONLY HAVE 30 MINS WILL MARK BRANLIEST!!!!

Answer:

a

Step-by-step explanation:

reflection ACROSS x=4

The percentage of 18-year-old women who have systolic blood pressure between 96 mmHg and 144 mmHg is 95%.

We have,

We can use the empirical rule to approximate the percentage of 18-year-old women with systolic blood pressure between 96 mmHg and 144 mmHg as follows:

68% of the women have systolic blood pressure within one standard deviation of the mean, which is between:

120 - 12 = 108 and 120 + 12 = 132 mmHg.

95% of the women have systolic blood pressure within two standard deviations of the mean, which is between:

120 - 2(12) = 96 and 120 + 2(12) = 144 mmHg.

Since the range we're interested in falls within two standard deviations of the mean, we can use the empirical rule to estimate that approximately 95% of 18-year-old women have a systolic blood pressure between 96 mmHg and 144 mmHg.

Thus,

The percentage of 18-year-old women who have systolic blood pressure between 96 mmHg and 144 mmHg is 95%.

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The quotient when 1.233 x 10⁸ is divisible by 3.85 x 10⁵ is 3.2 × 10²  

Scientific notation is a way of expressing very large or very small numbers in a concise and convenient form.

It involves writing a number as the product of a coefficient and a power of 10, where a coefficient is a number between 1 and 10 and the power of 10 determines the place of the decimal point.

Here we have

1.233 × 10⁸ and 3.85 × 10⁵

Now divide 1.233 × 10⁸ by 3.85 × 10⁵  

=> 1.233 × 10⁸ / 3.85 × 10⁵  

=> 0.320 × 10³  

=> 3.2 × 10²  

Therefore,

The quotient when 1.233 × 10⁸ is divisible by 3.85 × 10⁵ is 3.2 × 10²  

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The zeros of the given function g are: B. -6 and 7

The zeros of a function are defined as the values of the variable of the given function in a way that the function equals 0. Graphically, the zeros of a function are the points on the x-axis where the graph cuts the x-axis. This means, we can say that the zeros of a function are the x-intercepts of its graph.

We are told that g has the factors (x - 7) and (x + 6), and as such this means that the zeros will be gotten by equating the factors to zero to get:

(x - 7) = 0 and (x + 6) = 0

x = 7 and x = -6

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Tony's Fun Emporium Cost = 5 + 1x and  Mark's Entertainment World: Cost = 3x are the required equations.

It will cost $15 to ride 10 rides at Tony's Fun Emporium and $30 to ride 10 rides at Mark's Entertainment World.

If you want to go on as many rides as possible, Tony's Fun Emporium is the better option.

Equations for each amusement park:

Tony's Fun Emporium: Cost = 5 + 1x, where x is the number of rides.

Mark's Entertainment World: Cost = 3x, where x is the number of rides.

To find out how much it will cost to ride 10 rides at each park:

Tony's Fun Emporium: Cost = 5 + 1(10) = $15

Mark's Entertainment World: Cost = 3(10) = $30

So, it will cost $15 to ride 10 rides at Tony's Fun Emporium and $30 to ride 10 rides at Mark's Entertainment World.

Tony's Fun Emporium: 5 + 1x = 21

1x = 16

x = 16 rides

Mark's Entertainment World: 3x = 21

x = 7 rides

Hence,  with a budget of $21, you can go on 16 rides at Tony's Fun Emporium or 7 rides at Mark's Entertainment World. If you want to go on as many rides as possible, Tony's Fun Emporium is the better option.

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Answer:

(x=8) (y=7)

Step-by-step explanation:

The type II error occurs in the example.

According to the given conditions, the null thesis( H0) is that the food is safe, while the alternative thesis( Ha) is that the food isn't safe. The food inspectors are trying to test this thesis by examining samples of the food product and looking for any signs that it may be unsafe.

A type II error occurs when the examination process fails to descry an unsafe condition in the food product, indeed though it actually exists. In other words, the sample data suggests that the food is safe, but it's not. This means that the null thesis( H0) is accepted when it should have been rejected in favor of the alternative thesis( Ha).

In practical terms, a type II error in this environment could be dangerous, as it could affect unsafe food being distributed to consumers, potentially leading to illness or indeed death. thus, it's important for food inspectors to minimize the threat of type II crimes by using applicable slice styles and testing procedures to ensure the safety of the food products they check.

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Answer: x = 3

Step-by-step explanation:

1:simplify the expression and divide both sides by the same factor

x^2-6x+9=0

2:use the quadratic formula

ax2 + bx + c = 0

a=1    b=-6   c=9

3:Evaluate the exponent

Multiply the numbers

Subtract the numbers

Evaluate the square root

Add zero

Multiply the numbers

Cancel terms that are in both the numerator and denominator

x=3

Answer: 136.875

Step-by-step explanation:

First of all, we make that assumption that 176 is 100% since it is our output value.

Then we seek the value with x.

Since we already know that 100%=176, we put x%=240.9 which will give us some simple equations: 100%=176(1) and x% = 240.9

And then we turn our equations into this:

100% = 240.9

 x%        176

Lastly, we take the inverse (or reciprocal) of both sides

x% =  176  

100   240.9

At the end, we get this:

240.9 is 136.875% of 176

The expression representing the operation of adding r to s, tripling the result, and then multiplying q by the sum is q×(3×(s+r)).

In mathematics, an expression is a combination of one or more numbers, variables, and mathematical operations (such as addition, subtraction, multiplication, division, and exponentiation) that can be evaluated to produce a value

The expression that represents the described operation is

q × (3 × (s + r))

This expression first adds r to s, which gives (s + r), then multiplies the sum by 3, which gives 3 × (s + r), and finally multiplies the result by q, which gives q × (3 × (s + r)).

So, the final result is obtained by first adding r to s, tripling the result, and then multiplying that value by q.

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The given question is incomplete, the complete question is:

Add r to s, triple the result, then multiply q by what you have the description needs to be in expression form.

Answer:

the range describes the distance from the minimum to the maximum value of the entire data set.

The length of the segment BC which is having midpoint DE is 6cm.

Given that GH is the mid-segment of triangle DEF and DE is the mid-segment of triangle ABC. From this relation, we can obtain the length of the segment BC easily.

The relation between the base and mid-segment of the triangle is,

base = 2 x mid-segment

So, in triangle DEF the length of the base DE = 2 x GH

                                                                      DE = 2 x 1.5 cm = 3 cm.

Similarly, in triangle ABC the length of the base BC = 2 x DE

                                                                                BC = 2 x 3 cm = 6 cm.

From the above analysis, we can conclude that the length of the segment BC is 6cm.

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There are 130 positive integers less than 1000 that are divisible by 7 but not by 11.

The rule used to find the number of positive integers less than 1000 that are divisible by 7 but not by 11 is the inclusion-exclusion principle. This principle states that if we want to find the number of elements that belong to at least one of two sets, we can add the sizes of the sets together and then subtract the size of the intersection of the sets. In this case, we first find the number of positive integers less than 1000 that are divisible by 7 (which is 142), then the number that are divisible by 11 (which is 90), and finally the number that are divisible by both (which is 12). Using the inclusion-exclusion principle, we can find the number of positive integers less than 1000 that are divisible by 7 but not by 11 by subtracting the number that are divisible by both from the number that are divisible by 7: 142 - 12 = 130. Therefore, there are 130 positive integers less than 1000 that are divisible by 7 but not by 11.
To find the number of positive integers less than 1000 that are divisible by 7 but not by 11, you can use the Inclusion-Exclusion Principle.

First, find the number of integers divisible by 7: there are 999/7 = 142.71, so 142 integers are divisible by 7.

Next, find the number of integers divisible by both 7 and 11 (i.e., divisible by their LCM, which is 77): there are 999/77 = 12.97, so 12 integers are divisible by 77.

Now, apply the Inclusion-Exclusion Principle: Subtract the number of integers divisible by both 7 and 11 from the number of integers divisible by 7: 142 - 12 = 130.

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Answer:

-5

Step-by-step explanation:

Answer: it would be -5

Step-by-step explanation: it is negative 5 because that is where there is no x intercept

Answer: 53

Step-by-step explanation:

90 - 37

Answer

53 is the angle

Further explanation

Complementary angles sum to 90°.

We can build an equation to find any two complementary angles.

x + y = 90

Either x or y is given. Notice how they're interchangeable which means it doesn't make any difference what value you plug in for x or y.

Allow me to demonstrate.

In our case we have an angle that measures 37.

We can plug in 37 for x or y, but I always plug it in for x.

37 + y = 90

Subtract 37 on each side

y = 53°

Answer:

Step-by-step explanation:

4i+19=47

4i=28

i=28/4

i=7

4i+19=47

4i=28

i=28/4

i=7

The hypotheses test Claire's claim is:

H 0: p = 0.5, H alpha: p not-equals 0.5

We have the information:

The proportion of times the penny lands on heads is not 0.5.

She spins a penny 50 times and it lands on heads 30 times.

To find the which hypotheses test Claire's claim.

Now, According to the question:

We take the value of [tex]\alpha =0.05[/tex]

Because the p-value is smaller than alpha, we reject the null hypothesis.

Therefore, we conclude that the alternative hypothesis is correct and the proportion of heads is greater than 0.5

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Refer to the attached image.

Step-by-step explanation:

See image

ABCD is a Rectangle, ∠A, ∠B, ∠C and ∠D are right angles by definition of right angle.

Given that ABCD is a rectangle.

Each angle in the rectangle has 90 degrees.

∠A, ∠B, ∠C and ∠D are right angles by definition of rectangle.

∠A≅∠C; ∠B≅∠D by Opposite Angles of a Rectangle are Congruent" theorem.

ABCD is a Rectangle

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Answer:

= Divide the 26 feet by 3.25 feet

26 ÷ 3.25 = 8

= then Multiply the 8 by 1.7 degrees

8 × 1.7 = 13.6

= Subtract 13.6 from 26 feet

26 - 13.6 = 12.4

= Round 12.4 to the nearest tenth

12.4 = 12

Answer: 12

Based on the given information, we can match each dot plot with its median as follows:

Dot plot 1: Median = 6

Dot plot 2: Median = 15

Dot plot 3: Median = 12

Dot plot 4: Median = 13

Given that;

The medians of the following dot plots are 6, 12, 13, and 15,

Now,

Four dot plots labeled dot plot 1, dot plot 2, dot plot 3, and dot plot 4 each with the numbers 0 through 20, in increments of 2, indicated.

And, The data are as follows:

Dot plot 1: 1, 1 dot. 2, 1 dot. 5, 2 dots. 6, 2 dots. 7, 1 dot. 8, 2 dots. 9, 1 dot.

Dot plot 2: 10, 2 dots. 11, 2 dots. 15, 3 dots. 17, 1 dot. 18, 1 dot. 19, 1 dot.

Dot plot 3: 5, 1 dot. 6, 1 dot. 9, 1 dot. 11, 2 dots. 13, 1 dot. 14, 1 dot. 15, 3 dots.

Dot plot 4: 8, 2 dots. 10, 2 dots. 13, 2 dots. 14, 1 dot. 16, 3 dots.

Hence, By given condition we get;

Dot plot 1: Median = 6

Dot plot 2: Median = 15

Dot plot 3: Median = 12

Dot plot 4: Median = 13

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Answer: (a) tan 16°:

Using a calculator, we get:

tan 16° ≈ 0.291

Rounding to three significant figures, tan 16° ≈ 0.291.

(b) tan 89°:

Using a calculator, we get:

tan 89° ≈ 57.290

Note that this value is extremely large and not meaningful in most contexts.

(c) tan 18.7°:

Using a calculator, we get:

tan 18.7° ≈ 0.340

Rounding to three significant figures, tan 18.7° ≈ 0.340.

(d) tan 45.4°:

Using a calculator, we get:

tan 45.4° ≈ 1.058

Rounding to three significant figures, tan 45.4° ≈ 1.06.

Step-by-step explanation:

The multiple coefficients of determination, R², is 0.7, or 70% evaluated using the formula R² = SSR/SST.

The numerous coefficient of assurance called R-squared (R²), may be a degree of the extent of the full variety within the subordinate variable clarified by the free factors within the relapse demonstrate.

 To calculate R² you can use the following formula:

R² = SSR/SST

where:

SSR is the regression sum of squares.

SST is the sum of squares. This is the regression sum of squares plus the error sum of squares.

In this case SSR = 1400 and SSE = 600. SST can be calculated as:

SST = SSR + SSE

= 1400 + 600

= 2000

Therefore, R² is

R² = SSR/SST

= 1400 / 2000

= 0.7

Therefore, the fold determination coefficient R² is 0.7 or 70%.  

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Answer:

of a polynomial function with integer coefficients.

Rational Zeros Theorem:

If the polynomial ( ) 1

1 1 ... n n P x ax a x ax a n n

− = + ++ − + 0 has integer

coefficients, then every rational zero of P is of the form

p

q

where p is a factor of the constant coefficient 0 a

and q is a factor of the leading coefficient n a

Example 1: List all possible rational zeros given by the Rational Zeros Theorem of

P(x) = 6x

4

+ 7x

3

- 4 (but don’t check to see which actually are zeros) .

Solution:

Step 1: First we find all possible values of p, which are all the factors

of . Thus, p can be ±1, ±2, or ±4. 0 a = 4

Step 2: Next we find all possible values of q, which are all the factors

of 6. Thus, q can be ±1, ±2, ±3, or ±6. n a =

Step 3: Now we find the possible values of p

q by making combinations

of the values we found in Step 1 and Step 2. Thus, p

q will be of

the form factors of 4

factors of 6 . The possible p

q are

12412412412

, , , , , , , , , , ,

11122233366

± ± ± ± ± ± ± ± ± ± ±±

4

6

Example 1 (Continued):

Step 4: Finally, by simplifying the fractions and eliminating duplicates,

we get the following list of possible values for p

q .

1124 1, 2, 4, , , , , 2333

±± ± ± ± ± ± ±

1

6

Now that we know how to find all possible rational zeros of a polynomial, we want to

determine which candidates are actually zeros, and then factor the polynomial. To do this

we will follow the steps listed below.

Finding the Rational Zeros of a Polynomial:

1. Possible Zeros: List all possible rational zeros using the Rational Zeros

Theorem.

2. Divide: Use Synthetic division to evaluate the polynomial at each of the

candidates for rational zeros that you found in Step 1. When the

remainder is 0, note the quotient you have obtained.

3. Repeat: Repeat Steps 1 and 2 for the quotient. Stop when you reach a

quotient that is quadratic or factors easily, and use the quadratic formula

or factor to find the remaining zeros.

Example 2: Find all real zeros of the polynomial P(x) = 2x

4

+ x

3

– 6x

2

– 7x – 2.

Solution:

Step 1: First list all possible rational zeros using the Rational Zeros

Theorem. For the rational number p

q to be a zero, p must be a

factor of a0 = 2 and q must be a factor of an = 2. Thus the

possible rational zeros, p

q , are

1 1, 2, 2

±± ±

Example 2 (Continued):

Step 2: Now we will use synthetic division to evaluate the polynomial at

each of the candidates for rational zeros we found in Step 1.

When we get a remainder of zero, we have found a zero.

Since the remainder is not zero,

12 1 6 7 2

23 31

0

23 3

1 is not a

10 12

zer

o

←

+

−− −

− −

−− −

Since the remainder is zero,

12 1 6 7 2

21

1 is

5 2

21520

a zero

− −−−

−

− −

−

− ←

This also tells us that P factors as

2x

4

+ x

3

– 6x

2

– 7x – 2 = (x + 1)(2x

3

– x

2

– 5x – 2)

Step 3: We now repeat the process on the quotient polynomial

2x

3

– x

2

– 5x – 2. Again using the Rational Zeros Theorem, the

possible rational zeros of this polynomial are

1 1, 2, 2

±± ± .

Since we determined that +1 was not a rational zero in Step 2,

we do not need to test it again, but we should test –1 again.

Since the remainder is zero,

12 1 5 2

232

1 is again a zero

2 3 2 0

− −−

−

−

−

− − ←

Thus, P factors as

2x

4

+ x

3

– 6x

2

– 7x – 2 = (x + 1)(2x

3

– x

2

– 5x – 2)

= (x + 1) (x + 1)(2x

2

– 3x – 2)

= (x + 1)2 (2x

2

– 3x – 2)

Example 2 (Continued):

Step 4: At this point the quotient polynomial, 2x

2

– 3x – 2, is quadratic.

This factors easily into (x – 2)(2x + 1), which tells us we have

zeros at x = 2 and 1

2

x = − , and that P factors as

2x

4

+ x

3

– 6x

2

– 7x – 2 = (x + 1)(2x

3

– x

2

– 5x – 2)

= (x + 1) (x + 1)(2x

2

– 3x – 2)

= (x + 1)2 (2x

2

– 3x – 2)

= (x + 1)2 (x – 2)(2x + 1)

Step 5: Thus the zeros of P(x) = 2x

4

+ x

3

– 6x

2

– 7x – 2 are x = –1, x = 2,

and 1

2

x = − .

Descartes’ Rule of Signs and Upper and Lower Bounds for Roots:

In many cases, we will have a lengthy list of possible rational zeros of a polynomial. A

theorem that is helpful in eliminating candidates is Descartes’ Rule of Signs.

In the theorem, variation in sign is a change from positive to negative, or negative to

positive in successive terms of the polynomial. Missing terms (those with 0 coefficients)

are counted as no change in sign and can be ignored. For example,

has two variations in sign.

Descartes’ Rule of Signs: Let P be a polynomial with real coefficients

1. The number of positive real zeros of P(x) is either equal to the number

of variations in sign in P(x) or is less than that by an even whole

number.

2. The number of negative real zeros of P(x) is either equal to the number

of variations in sign in P(–x) or is less than that by an even whole

number.

Example 3: Use Descartes’ Rule of Signs to determine how many positive and how

many negative real zeros P(x) = 6x

3

+ 17x

2

– 31x – 12 can have. Then

determine the possible total number of real zeros.

Solution:

Step 1: First we will count the number of variations in sign of

( ) . 3 2 Px x x x =+ −− 6 17 31 12

Step-by-step explanation:

The values of x and z are 2 and 90 degrees respectively

The properties of transversals are;

From the information given, we have that;

The angle z is right angles, that is, it is equal to 90 degrees

z = 90 degrees

Since interior angles are supplementary, we have then that;

14x + 72 + 80 = 180

collect the like terms

14x + 152 = 180

14x = 28

Make 'x' the subject of formula

x =2

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Answer:

the dilation in g(x) as it relates to the parent function f(x) is a vertical dilation by a factor of 15000.

Step-by-step explanation:

The function g(x) is a dilation of the parent function f(x) = 0.98^x.

Specifically, g(x) = 15000(0.98)^x is a vertical dilation of f(x) = 0.98^x by a factor of 15000.

This means that the graph of g(x) is the same shape as the graph of f(x), but it is vertically stretched by a factor of 15000.

In other words, the values of g(x) are 15000 times greater than the values of f(x) for any given value of x.

For example, when x = 1, f(1) = 0.98 and g(1) = 15000(0.98) = 14700. This means that the number of visitors to the water park in the second month (x = 1) is 15000 times greater than the number of visitors in the first month.

Overall, the dilation in g(x) as it relates to the parent function f(x) is a vertical dilation by a factor of 15000.

The required surface area of the given figure is a cubic meter.

A figure is shown,
The surface area of the figure is given as,
Surface area = 2 [πr×3] + 2[6×3]+2[4×6]+ 4[πr]

Substitute the value in the above expression<
Surface area = 2 [3.14×2×3] + 2[6×3]+2[4×6]+ 4[3.14×2]
Surface area = 146.8 cubic meters

Thus, the required surface area of the given figure is cubic meters.

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The measures of the exterior angles are:

a = 80°

b = 115°

c = 40°

d = 50°

e = 75°

The sum of the measure of an interior angle and the correspondent exterior angle is always 180°, then we can write:

a + 100° = 180°

a = 180° - 100° = 80°

b + 65° = 180°

b = 180° - 65° = 115°

c + 140° = 180°

c = 180° - 140°  =40°

d + 130° = 180°

d = 180° - 130° = 50°

e + 105° = 180°

e = 180° - 105° = 75°

These are the angles.

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