pls help
complete the table below by writing the symbols for the cation and anion that make each ionic compound

Pls Help Complete The Table Below By Writing The Symbols For The Cation And Anion That Make Each Ionic

Answers

Answer 1

Answer:

CrO₂ --------------------> Cr⁴⁺ and O²⁻

VCO₃ -------------------> V²⁺ and CO₃²⁻

Cr₂(SO₄)₃ -------------> Cr³⁺ and SO₄²⁻

(NH₄)₂S ----------------> NH₄⁺ and S²⁻

Explanation:

Within ionic compounds, the cation is listed first, followed by the anion. Some of the ions are polyatomic, meaning they are covalently bonded to other elements. Polyatomic ions always have a specific charge.

All of these ionic compounds have an overall charge of 0. As such, the charges of the cations and anions must balance out. In order to do so, there are some compounds which have more than one atom of each ion.

2.) CrO₂

------> Oxygen (O) always forms the anion, O²⁻.

------> Therefore, if there are 2 oxygen anions, the chromium (Cr) must have the cationic form of Cr⁴⁺.

------> +4 + (-2) + (-2) = 0

3.) VCO

------> Carbonate (CO₃), a polyatomic ion, always has the state CO²⁻.

------> If there is only one atom of each ion, the charges must perfectly balance, making vanadium (V) be the cation V²⁺.

------> +2 + (-2) = 0

4.) Cr₂(SO₄)

------> Sulfate (SO₄), a polyatomic ion, always has the state SO₄²⁻.

-------> The only way the charges could balance out is if the chromium (Cr) is in the cationic form Cr³.

------> +3 + 3 + (-2) + (-2) + (-2) = 0

5.) (NH₄)₂S

------> Ammonium (NH₄), a polyatomic ion, always has the state NH₄⁺.

------> Sulfur (S) always forms the anion S²⁻.

------> +1 + 1 + (-2) = 0


Related Questions

When hexan-1-ol is treated with conc. h2so4 at moderate temperatures, ________ is formed via a(n) ________ mechanism

Answers

When hexan-1-ol is treated with conc. H₂SO₄ at moderate temperatures, Di-n-hexyl ether is formed via SN₂ mechanism.

SN₂ Mechanism is mechanism involving the factors of steric hindrance following the order of 1° > 2° > 3°. It is a Nucleophilic substitution reaction.

Williamson Ether Synthesis is the synthesis of ether through SN₂ mechanism in which an ether is treated with conc. H₂SO₄ at moderate temperature.

When hexan-1-ol is treated with conc. H₂SO₄ at moderate temperatures, Di-n-hexyl ether is formed as below:

CH₃CH₂CH₂CH₂CH₂CH₂OH +Conc. H₂SO₄-->(CH₃CH₂CH₂CH₂CH₂CH₂)₂0

Hexan-1-ol                                                                 Di-n-hexyl ether

Williamson Ether Synthesis is a reaction involving a alcohol that is deprotonated to form an ether.

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4fe 3o2 xh2o → 2fe2o3 • xh2o the formation of rust (equation above) is an example of both combustion and

Answers

The formation of rust (equation above) is an example of both combustion and Synthesis

What is a synthesis reaction?A synthesis reaction is a classification of responses in which multiple reactants connect to form a single product. If we observe the equation, no replacement is accepted place hence, single and double replacements are wrong choices.In decomposition reaction there is only one reactance which gets disintegrate and form multiple product.Synthesis reactions are reactions that occur when two additional atoms or molecules interact to form a separate molecule or compound. Most of the time, when a synthesis reaction occurs, energy is discharged and the reaction is exothermic. However, an endothermic consequence is also feasible.

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Answer:

synthesis

Explanation:

How many amps are required to produce 75. 8 g of iron metal from a solution of aqueous iron(iii)chloride in 6. 75 hours?

Answers

The amount of current required to produce 75. 8 g of iron metal from a solution of aqueous iron (iii)chloride in 6. 75 hours is 168.4A.

The amount of Current required to deposit a metal can be find out by using The Law of Equivalence. It states that the number of gram equivalents of each reactant and product is equal in a given reaction.

It can be found using the formula,

m = Z I t

where, m = mass of metal deposited = 75.8g

            Z = Equivalent mass / 96500 = 18.6 / 96500 = 0.0001

             I is the current passed

              t is the time taken = 75hour = 75 × 60 = 4500s

On subsituting in above formula,

75.8 = E I t / F

⇒ 75.8 = 0.0001 × I × 4500

⇒ I = 168.4 Ampere (A)

Hence, amount of current required to deposit a metal is 168.4A.

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URGENT 80 POINTS AND BRAINLIEST FOR ANSWER
this wuestion or photo is on my chemistry DBA laster today, what is it? please explain possible questions and responses and answers to what may be asked.
i think it involves things like the reaction moving forward and what would do that or somehing but i am unsure. something online said stuff that raise pressure was the answer to something but why?
sorry if this is confusing i havent been given an actual question for this yet but need to know ahead of time.

Answers

I suggest researching if you still don’t understand but here’s the general idea

Consider the gibbs energies at 25 ∘ c. substance δ∘f (kj·mol−1) ag (aq) 77. 1 cl−(aq) −131. 2 agcl(s) −109. 8 br−(aq) −104. 0 agbr(s) −96. 9 (a) calculate δ∘rxn for the dissolution of agcl(s)

Answers

The ∆G° for the dissolution of AgCl solid is 55.7 kJ/mol.

What is gibbs free energy?

The gibbs free energy is termed as thermodynamic quantity which is equal to the enthalpy (of a system or process) subtracted by the product of the entropy and the absolute temperature.

The gibbs free energy of the reaction is given by:

∆G°(rxn) =sum of ([∆G°] products)- sum of ( [∆ G°] reactants)

Reaction can be given as:

AgCl(S) » Ag+ (aq) + Cl- (aq)

Gibbs free energy of silver ions = ∆G°f, (Ag+) = 77.1kJ/mol

Gibbs free energy of formation of chloride ions = ∆G°f, (Cl-)= -131. 2kJ/mol

Gibbs free energy of formation of silver chloride solid = ∆ G°f, (AgCl) = - 109.8kJ/mol

The gibbs free energy of the reaction of dissolution of AgCl) :∆ G°rxn:

∆G°rxn = (77.1kJ/mol) – (- 109.8kJ/mol)

55.7kJ/mol

Thus, we found that the ∆G° for the dissolution of AgCL solid is 55.7 kJ/mol.

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The volume of a rock weighing 1. 705 kg is 334. 5 ml. What is the density of the rock?

Answers

The density of rock weighing 1.705 kg is 3.213 gm/ml.

Explanation:

Given;

Volume of rock = 334.5 ml

Weight of rock = 1.075 kg = 1075 gm

By the formula,

Density = Weight in gm/Volume in ml

              = 1075/334.5 gm/ml = 3.2137 gm/ml

Therefore, density of rock is 3.213 gm/ml.

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How much ice in grams would have to melt to lower the temperature of 356 mL of water from 35 ∘C to 0 ∘C ? (Assume that the density of water is 1.0 g/mL .)

Answers

Answer:

156.16 gm of ice

Explanation:

I will assume the ice starts at  0 C

As the ice melts, it produces water at  0 C  so we do not need to calculate THAT water being cooled....only the 356 ml being cooled to 0 C

356  gm *  4.186 j/gm-c  * (35 c)   = 52157.56 j

  this is the heat absorbed by the melting ice

x gm * 334 j / gm   = 52157.56 j           (334 j/gm is heat of fusion of water)

x = 156.16 gm of ice required

A solution is 0. 0480 m lif. What is the molarity of the solution if the density is 1. 10 g/ml?.

Answers

Molarity of the solution is 0.0527 M.

What is Molarity?

The amount of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a solute per liter of a solution is known as molarity. The molar concentration of a solution is another name for molarity.

Calculation of Molarity of the solution

Assume there is 1 kg of solvent present in the beginning.

Thus, the mole of solute is 0.0480 moles of LiF.

Molar mass of LiF = 25.939 grams/mole

0.0480 mol LiF x 25.939 g/1 mol LiF = 1.245 g LiF

Mass of the solution = 1001.245 g

The molarity of the solution can be determined as illustrated using the supplied density and moles of solute.

[LiF] = mol LiF/ volume of solution

[LiF] = 0.0480 mol/1001.245 g x 1ml/1.10g x 1L/1000mL

Hence, the molarity of LiF = 0.0527 M

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I WILL MARK U BRAINLIEST IF U ANSWER THIS QUESITON

Answers

Answer:

c )   16

Explanation:

C4 H10 O    +   6 O2  =====>  4  CO2  +   5  H2O

1 + 6 + 4 + 5 = 16

Answer:

C.) 16

Explanation:

An equation is balanced when there are equal amounts of each element on both sides of the reaction. These values can be modified by adding coefficients.

The unbalanced equation:

C₄H₁₀O + O₂ -----> CO₂ + H₂O

Reactants: 4 carbon, 10 hydrogen, 3 oxygen

Products: 1 carbon, 2 hydrogen, 3 oxygen

The balanced equation:

1 C₄H₁₀O +  6 O₂ -----> 4 CO₂ + 5 H₂O

Reactants: 4 carbon, 10 hydrogen, 13 oxygen

Products: 4 carbon, 10 hydrogen, 13 oxygen

Now, you can add the coefficients:

1 + 6 + 4 + 5 = 16

Determine which choice is an example of an exothermic process. a. none of these b. freezing water c. melting ice d. baking bread

Answers

option (b) freezing water is the correct answer.

Freezing water is an example of an exothermic process.

What is an exothermic process?An exothermic reaction is one in which energy is given off as heat or light. In contrast to an endothermic process, which draws energy from its surroundings, an exothermic reaction transfers energy into the environment.Heat is released during an exothermic reaction, raising the temperature of the immediate environment. The environment is cooled through an endothermic process that absorbs heat.

We can observe that melting of an ice is an example of endothermic process whereas, freezing of water is considered to be an example for exothermic process.

Water releases heat when it solidifies, warming the area around it. As a result, freezing is an exothermic process.

Some of the examples for exothermic process can be as follows:Making of an Ice Cube. Making an ice cube is a process of liquid changing its state to solidSnow Formation in CloudsBurning of a CandleRusting of Iron Burning of SugarFormation of Ion Pairs

In the above given options,

In melting ice, it is an endothermic response because it releases heat, allowing a transition to take place. The procedure is endothermic since the ice cube requires heat to melt.In baking bread, the dough's ingredients, including the flour, yeast, and others, are heated. They absorb the heat, which triggers chemical processes.

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Answer:

B.) Freezing water

Explanation:

I got it correct on founders edtell

An analytical chemist has determined by measurements that there are 8. 5 moles of magnesium in a sample of talc. how many moles of hydrogen are in the sample?

Answers

The moles of hydrogen in the talc sample are 5.67 moles.

Talc are the hydrous silicate minerals. The chemical formula of talc is Mg₃Si₄O₁₀(OH)₂.

From the formula it can be determined that there are: 3 moles of Mg, 4 moles of Si, 12 moles of O and 2 moles of H.

Moles are a type of SI unit of measurement of the amount of substance.

According to the question, magnesium = 8.5 moles

Also, 3 moles of Mg = 2 moles of H

Therefore, moles of H = 8.5 moles × (2 moles H / 3 moles Mg)

                 moles of H = 5.67 moles

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Think critically...
Q7. Bridges are made from materials that contract and expand as the temperature changes, so
they cannot be fastened firmly to the bank of a river or lake. The photographs below show an
expansion joint at the end of a bridge in winter and in summer.
www
(A)
(B)
Which season is shown in each picture? Explain how you know?

Answers

The  season that is shown in the picture attached is that:

For the red - summer For the black -  winter

What is the season  about?

Metals are known to often expand due to different factor. For example, the rails of a railway are known to often expand in summer and they tend to contract in winter. This tend to make the gaps kept to be between successive rails and it is one that allow for expansion.

Note also that  in Summer the expansion joint will tend to have little space as the two sides of the bridge is said to expand because of the heat and in terms of winter, it contract and there are bigger space as they tend to contract in the cold.

Hence, The  season that is shown in the picture attached is that:

For the red - summer For the black -  winter

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Why do you add hydroxide to your hexanediamine solution? what would occur if you did not add it?.

Answers

Why is Hydroxide added ?

In the polymerization reaction, the lone pair electrons on the NH₂ groups of hexanediamine attack the C=O groups of the dicarboxylic acid in a nucleophilic substitution reaction as shown in the image.

Hydroxide is added to remove any H⁺ ions present and keep the hexanediamine in the deprotonated form, so that the NH₂ lone pair electrons are available for reaction.

What if you don't add it ?

If hydroxide is not added, the NH₂ groups will get protonated by H⁺  ions present to give NH₃⁺ groups, which cannot react.

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Calculate the average acceleration from the following data points: v1 = 150 m/s, v2 = 975 m/s, t1 = 15 s, t2 = 55 s

Answers

The average acceleration from the following data points is 20.625 m/s^2.

We know that average acceleration = change in speed / change in time
here,

change in speed = v2-v1

                          = 975-150

                          = 825 m/s

change in time   = t2 - t1

                         = 55 - 15

                         = 40 s

now, putting all the values, average acceleration = 825 / 40

                                                                             = 20.625 m/ s^2 .

what is acceleration?

The rate at which an entity's velocity with regard to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration.

The SI unit of acceleration is metre per second square (m/s^2).

An average acceleration the speed at which velocity changes, the evolution of velocity through time, or the instantaneous acceleration ( acceleration at a given moment ) .

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When a known quantity of compound, at a known concentration, is added to a known volume of another compound to determine the concentration of the latter, the process is referred to as?

Answers

A titration is a method for figuring out the concentration of an unknown solution by using a solution with known concentration.

What is Titration?

Titration, commonly referred to as titrimetry, is a quantitative analysis technique that enables chemists to estimate the quantities of specific chemicals in a sample that are unknown.

A known volume of one solution of known concentration (referred to as a titrant) is slowly added to a known volume of another solution of unknown concentration (referred to as analyte) throughout the basic titration procedure until the reaction reaches neutralization.

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The density of gold is 19.3 g/cm3. what is the volume in cubic centimeters of a piece of gold whose mass is 5.23 g?

Answers

If density of gold is 19.3g/cm3 amd mass is 5.23 g, then volume obtained is 0.27cm3.

Density is defined as how much a matter is packed in given area. It is represented by ρ.

ρ = m/ V

Given,

density of gold = 19.3 g/cm3

mass of gold = 5.23 g

As we know that,

density = mass/ volume

mass = density× volume

19.3 = 5.23 / volume

volume = 5.23/19.3

volume = 0.27 cm3.

Thus, if density and mass is given volume can be obtained.

Volume of gold is given as 0.27 cm3.

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A membrane is impermeable to charged molecules and does not allow passage of ions because of?

Answers

A membrane is impermeable to charged molecules and does not allow the passage of ions because the charged molecules possess polarity and the membrane possesses hydrophobic interiors.

Hydrophobic ions:

Charged hydrophilic molecules of all sizes, from small molecules to giant enzymes, can now be made more soluble via a technique called hydrophobic ion pairing. Hydrophobic molecules having hydrophilic moieties are ionically coupled with charged hydrophilic molecules, and the resulting uncharged complex is water-insoluble and will precipitate in aqueous conditions.

With polar solvents like water or alcohol, hydrophilic compounds can easily establish hydrogen bonds. Ionic (charged) groups with oxygen or nitrogen atoms make up the chemical structure of hydrophilic compounds. Typically, a substance's hydrophilicity is determined by its polarity. A molecule will be hydrophobic overall even if it has polar covalent bonds and these bonds are distributed symmetrically.

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Predict the mass (in grams) of precipitate that will form if a solution containing 2.34 g of cesium hydroxide is added to a solution containing a large excess of tiso4?

Answers

The mass of precipitate formed if a solution containing 2.34 g of cesium hydroxide is added to a solution containing a large excess of tiso4 is 0.6387 g

Mass of CsOH = 2.34 g

Number of moles of CsOH = 149.9 g / mol

Molar mass of CsOH =  Mass of CsOH / Number of moles of CsOH

                                    = 2.34 / 149.9

Molar mass of CsOH is 0.0156 mol

Chemical reaction

2 CsOH + TiSO4 → Ti(OH)2 + CsSO4

In this reaction 2 moles of CsOH gives 1 mole of Ti(OH)2

0.0156 mol of CsOH will produce, 0.0156 / 2 = 0.0078 mol

0.0156 mol of CsOH will produce 0.0078 mol of Ti(OH)2

Mass of Ti(OH)2 =  Molar mass of Ti(OH)2 / Number of moles of Ti(OH)2

                            = 0.0078 * 81.88

                            = 0.6387 g

Mass of Ti(OH)2 formed is 0.6387 g

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The mass of precipitate formed is 0.90441 g

cesium hydroxide is added to a solution containing a large excess of TiSo4

The chemical reaction is

2CsOH + TiSo4  →  Ti(OH)2 + CsSo4

The above reaction the Ti(OH)2 is a precipitate formed

Molar mass = mass of a substance / mass of one mole

Mass of CsOH = 2.34 / 149.912

Mass of CsOH = 0.0156 mol

The above reaction 2 mol of cesium hydroxide yield 1 mol of titanium hydroxide

Then, 0.0156 mol of CsOH yield 0.0156 / 2 = 0.0078 mol of Ti(OH)2

The mass of Ti(OH)2 is 115.95

0.0078 mol of Ti(OH)2 = 115.95 X 0.0078

                                      = 0.90441

Hence, The mass of Ti(OH)2  = 0.9044 g

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15. conjugated dienes routinely undergo 1,2 and 1,4 addition reactions with a variety of electrophilic reagents; this suggests that ___ are likely intermediates during these reactions

Answers

Conjugated dienes routinely undergo 1,2 and 1,4 addition reactions with a variety of electrophilic reagents; this suggests that electrophilic reagents are likely intermediates during these reactions.

Two double bonds and one single bond divide a conjugated diene into two halves. Nonconjugated (Isolated) Dienes have more than one single bond separating two double bonds. Two double bonds are joined to the same atom to form cumulated dienes.

Reagents that function by acquiring electrons or sharing electrons that once belonged to a foreign molecule are referred to as electrophilic reagents, or electrophiles, in some cases. Electrophiles are molecules with a positive charge and a lack of electrons that can react by exchanging electron pairs with nucleophiles, which have many electrons. Epoxides, hydroxy amines, nitroso and azoxy derivatives, nitrenium ions, and elemental sulfur are significant electrophiles.

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Which stage in the life cycle of a plant is represented in this picture?

Answers

Answer:

seed, sprout, small plant, and adult plant.

Explanation:

I didnt see the picture so I cant tell you what stage it represented but I told you all the stages of plants in life cycle.

A gas sample occupies 10. 28 l at 8. 34 atm. its volume at 6. 98 atm (assuming constant temperature conditions) is:____.
a. 12. 28
b. 8. 60
c. 15. 61
d. 5. 66

Answers

12.28 L volume at 6.98atm in sample gas occupies 10. 28 l at 8. 34atm. Hence, option A is correct.

What is ideal gas?

Ideal gas is a hypothetical gas whose molecules occupy negligible space and have no interactions, and which consequently obeys the gas laws exactly.

In the limit of low pressures and high temperatures, where the molecules of the gas move almost independently of one another, all gases obey an equation of state known as the ideal gas law:

PV = nRT,

P is pressure of gas (atm)T is temperature of gas (K)where n is the number of moles of the gas R is the universal gas constant, 8.3145 joules/K.

When Temperature is constant so, it follow Boyle's law:

P1 V1 = P2 V2

P1 = 8.34atm, V1 = 10.28 L, P2 = 6.98atm

V2 = P1 V1 / P2

V2 = 8.34atm x 10.28 / 6.98atm

V2 = 12.28 L

12.28 L volume at 6.98atm in sample gas occupies 10. 28 l at 8. 34atm. Hence, option A is correct.

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What reagent is needed to convert 1-hexyne to 2-hexanone?
(a) o3 /zn/ h3o
(b) pcc (pyridinium chlorochromate)
(c) bh3 /h2o2 /oh-
(d) h2o/h

Answers

The reagent is needed to convert 1-hexyne to 2-hexanone is [tex]H_{2}O /H^{+}[/tex].

So , option D is correct one.

Ozonolysis is used to form aldehyde and ketone from alkene not alkyne .So option A is incorrect .

The reagent PCC is used as an oxidant and  is used to convert primary and secondary alcohol into aldehyde and ketone.

The [tex]BH_{3} /H_{2} O_{2} /OH^{-}[/tex] is used to convert alkene into alcohol which is known as hydroboration reaction.

The addition of a hydroxyl group to an alkyne causes tautomerization which subsequently forms a carbonyl Markovnikov addition of a hydroxyl group to an alkyne forms a ketone. So,  [tex]H_{2}O /H^{+}[/tex] is used to convert alkyne into ketone.This reagent is needed to convert 1-hexyne to 2-hexanone.

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Identify oxidation.
a. Increase in oxidation number.
b. Loss of electrons.
c. Decrease in oxidation number.
d. Gain of electrons.
e. Both A and B

Answers

Oxidation is "Increase in oxidation number" as well as loss of electrons.

A rise in oxidation number results from the loss of negative electrons, whereas a reduction in oxidation number results from the gain of electrons. As a consequence, the oxidized element or ion experiences a rise in oxidation number.

As a result of losing electrons in the process, a reactant oxidizes. When a reactant obtains electrons during a reaction, reduction takes place. This frequently happens when acid and metals react.

Therefore, Oxidation is "Increase in oxidation number" as well as loss of electrons.

Hence, the correct answer will be option (e)

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The isotope 131i (iodine-131), which has a half-life of 8. 02 days, is used in nuclear medical imaging. what percentage of the original activity in the sample remains after 17. 5 days?

Answers

The percentage of the original sample which would remain after 17.5 days according to the given half-life of the isotope is; 22.06%.

What percentage of the original activity in the sample remains after 17.5 days?

The given sample in discuss has a half life of; 8.02 days, this therefore indicates that after 17.5 days, the number of half-life periods completed is; 17.5/8.02 = 2.18 half-lifes.

Hence, the percentage of the original sample remaining after 17.5 days can be evaluated as follows;

N = 100% × (0.5)^2.18

N = 100 × 0.22

N = 22.06%.

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Octanol is slightly soluble in water, and water is very soluble in octanol. why is it important to presaturate octanol with water and water with octanol when measuring ow?

Answers

N-Octanol and water are chosen because the connection between a substance's hydrophilicity and lipophilicity is measured by [tex]K_{OW}[/tex] (n-Octanol/Water partition coefficient). When a chemical is more dissolves in fat-like solvents like n-octanol, the value is more significant than one,  when it's more dissolved in water, the value is lower.

What is the partition coefficient?

The partition coefficient for the two-phase network comprising n-octanol and water is known as the [tex]K_{OW}[/tex] value. N-Octanol-Water Partition Ratio is another name for it.The connection between a substance's hydrophilicity (its ability to dissolve in water) and lipophilicity (its ability to dissolve in fat) is measured by [tex]K_{OW}[/tex]. The value is bigger if a drug is more accessible in fat-like liquids like n-octanol and less if a compound seems more water-soluble.Owing to linkage or fragmentation, substances that are involved in the octanol-water combination as multiple synthetic entities are each given a unique [tex]K_{OW}[/tex] ratio.

So, N-Octanol is chosen because it has a carbon/oxygen ratio that is comparable to that of lipids and because it shows both hydrophobic and hydrophilic properties. N-octanol, therefore, resembles the makeup and characteristics of cells and other living things.

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You use a microwave to heat a mug of water. The mug has 235 grams of water (with specific heat 4.186 Joules per gram per degree Celsius). The microwave adds 66,000 Joules of energy to the water. How much does this raise the temperature of the water

Answers

Answer:

67° C   increase

Explanation:

235 gm   *   4.186 J /g-C  *    x     =  66 000 J          x = degree change C°

x = 67 degrees C

(4) When the hydrocarbon was burned 0.20 mol of water were produced.
How many moles of hydrogen atoms are there in 0.20 mol of water?
Moles of hydrogen atoms

Answers

Answer:

.4 moles of hydrogen

Explanation:

Formula for water ==   H2 O  

   so you can see there are twice as many hydrogen moles as water moles

           .2 * 2 = .4

When the hydrocarbon was burned 0.20 mol of water were produced. 0.40 moles of hydrogen atoms are there in 0.20 mol of water.

A mole is a unit used to measure the concentration of a chemical in chemistry. It is described as the quantity of a substance that includes exactly the same number of atoms as there are in exactly 12 grammes of carbon-12. This number can be an entity (such as an atom, molecule, ion, or other particle). The dozen, which represents 12 items, and the pair, which represents 2 items, are two more basic units of measurement that are comparable to the mole.

2 moles H / 1 mole H2O = x moles H / 0.20 moles H2O

2 moles H ×0.20 moles H2O = 1 mole H × x moles H2O

0.40 moles H = x moles H2O

So, there are 0.40 moles of hydrogen atoms in 0.20 moles of water.

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What is the product of reduction of ethyl 4-oxobutanoate with sodium borohydride in ethanol at room temperature for 30 minutes?

Answers

The product of reduction of ethyl 4-oxobutanoate with sodium borohydride in ethanol at room temperature for 30 minutes is ethyl 4- hydroxybutanoate .

Sodium borohydride is a relatively selective reducing agent  Ethanolic solutions of Sodium borohydride reduces aldehyde , and ketone , in the presence of acid chloride , ester , epoxide , lactones , acids , nitriles , nitro groups.

The sodium borohydride does not reduce ester group because sodium borohydride is not strong enough and the electrophilicity at carbony carbon of ester is not more as compare toaldehyde , and ketone

The product of reduction of ethyl 4-oxobutanoate with sodium borohydride in ethanol at room temperature for 30 minutes is ethyl 4- hydroxybutanoate .

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The average person will absorb no more than how many mg of calcium at one time?
a. 1500
b. 500
c. 200
d. 1000

Answers

The average person will absorb no more than 500 mg of calcium at one time.

So, option B is correct one.

For maximum absorption, no more than 500 mg of calcium should be taken in a single dose. The absorption of the minerals is actually lower by taking too high an amount of calcium at one time from a supplement. Calcium is absorb from the food. If you think you need more a calcium supplement , ask your doctor or dietitian to recommend one. Taking too high amount of calcium at one time, particularly from a supplement , can actually lower the absorption of the mineral.

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What can the presence of suffixes such as -ite,-ate,or -de in a chemical name indicate?

Answers

Answer: Most polyatomic ions are -ate, related ions that have 1 fewer oxygen atom are -ite (must have at least 1 oxygen tho) and nonmetals are ide.

Explanation:

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